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I need answer to those questions please ASAP I\'m stuck D Question 12 0.5 pts After the first round of replication, Meselson and Stahl found that all the DNA were of intermediate density indicating that the DNA molecules were made up of a hybrid of N15 (aka 15-N, or heavy isotope of N) and N14 (aka 14-N, or light isotope of N). How did they determine that the correct model of DNA replication was semi- conservative and not dispersive? Recap of Meselson and Stahl\'s experiment: https utube.com/watch?V 4gdWOWiioBE 1799: H O Because if it had been the dispersive model, after the first round of replication half the DNA would have been heavy and half would have been light. O After the second round, half the DNA were of low density and half the DNAwas of intermediate density after the second round of replication, all the DNA were were of intermediate density O after the second round, half the DNA were of high density and half the DNA were of low density. Solution Question 12 How did they determine that the correct model of DNA replication was semi conservative and not dispersive? After the second round, half the DNA was of low density and half the DNA was of intermediate density Explanation After conducting the experiment, they came to a conclusion that After first generation, they obtained DNA molecules of intermediate density After second generation, they obtained DNA, in which half is intermediate and other half is light. This supports the fact the replication if of semi-conservative type. After first generation, when DNA labeled with 15N will act as template for the synthesis of new strands, the obtained two strands will have one strand of 15N and other strand of 14N, resulting in intermediate density. But in second generation, when these N15-14N strands act as template, you will get four double strands, 2 strands with 15N-14N, 2 strands with 14N-14N, giving you Question 14: Answer is B It will have two double-stranded DNA of intermediate density and two double-stranded DNA of light strands at the end of second generation. Question 15 DNA replication is dispersive That is the reason why one clump is regular whitish color, if the replication is semi conservative then this lump should be intermediate glowing green in color due to the present of altered form of nitrogen. Question 16 Answer is a The resulting strands will be light and heavy; you cannot find any intermediate strand as here the two newly synthesized strands after one round of replication will form double helix, whereas the old two strands will remain together as one double strand..
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questions. How did semiconservative and Stahl s experiments support .pdf
questions. How did semiconservative? and Stahl s experiments support the idea that DNA
replication is 2. A new form of DNA is discovered that appears to be able to replicate itself both
in the 3\' 5\' direct and in the sequence direction. If this is true, how would newly on replication
differ from DNA replication as we this discovered DNA know it? 3. Amazingly, an alien species
of cellular organism is found alive in the remains of a meteorite that landed in the Mojave
Desert. As a scientist, you are trying to determine whether this alien life-form uses DNA,
protein, or some other type of compound as its hereditary material a. What kinds of experiments
would you propose to determine what the hereditary material b. If the hereditary material tums
out to be similar to our DNA, describe the simplest experiments you could run to try to
determine if is double-stranded like our DNA, triple-stranded, or some other configuration.
Copyright 2014 Pearson Activity 15.3 Inc.
Solution
Answer to question 1
Nitrogen is one of the major constituent of DNA. 14N is by far the most abundant isotope of
nitrogen, but DNA with the heavier 15N isotope is also functional.
E. coli was grown for several generations in a medium containing NH4Cl with 15N. When DNA
is extracted from these cells and centrifuged on a salt density gradient, the DNA separates out at
the point at which its density equals that of the salt solution. The DNA of the cells grown in 15N
medium had a higher density than cells grown in normal 14N medium. After that, E. coli cells
with only 15N in their DNA were transferred to a 14N medium and were allowed to divide.
DNA was extracted periodically and was compared to pure 14N DNA and 15N DNA. After one
replication, the DNA was found to have intermediate density. Since conservative replication
would result in equal amounts of DNA of the higher and lower densities (but no DNA of an
intermediate density), conservative replication was excluded. However, this result was consistent
with both semiconservative and dispersive replication. Semiconservative replication would result
in double-stranded DNA with one strand of 15N DNA, and one of 14N DNA, while dispersive
replication would result in double-stranded DNA with both strands having mixtures of 15N and
14N DNA, either of which would have appeared as DNA of an intermediate density.
Meselson–Stahl continued to sample cells as replication continued. DNA from cells after two
replications had been completed was found to consist of equal amounts of DNA with two
different densities, one corresponding to the intermediate density of DNA of cells grown for only
one division in 14N medium, the other corresponding to DNA from cells grown exclusively in
14N medium. This was inconsistent with dispersive replication, which would have resulted in a
single density, lower than the intermediate density of the one-generation cells, but still higher
than cells grown only in 14N DNA medium, as the original 15N DNA would have be.
In prokaryotes, promoters are specific sequences of ______ that are r.pdf
In prokaryotes, promoters are specific sequences of ______ that are recognized by __________.
a DNA/RNA polymerase b. RNA/DNA polymerase c. DNA/sigma factor d. RNA/RNA
polymerase In the Meselson-Stahl experiment, cells were grown for one generation in growth
medium containing a relatively heavy nitrogen isotope, then transferred to new medium
containing a lighter nitrogen isotope. After another round of cell division, what is true of the
DNA in the cells? a. All DNA contains only the lighter nitrogen isotope. b. Half of the DNA
contains only the light nitrogen isotope. c. All DNA contains only the heavy nitrogen isotope d.
All DNA contains a hybrid of heavy and light nitrogen isotopes
Solution
C. DNA/sigma factor
Promoter is made of DNA sequence which is recognized by transcription protein sigma factor as
that goes and bind first at DNA then reads it and forms RNA which is called transcription .
D. All dna contains both heavy and light nitrogen isotopes
E. coli was grown for several generations in a medium containing NH4Cl with 15N. When DNA
is extracted from these cells and centrifuged on a salt density gradient, the DNA separates out at
the point at which its density equals that of the salt solution. The DNA of the cells grown in 15N
medium had a higher density than cells grown in normal 14N medium. After that, E. coli cells
with only 15N in their DNA were transferred to a 14N medium and were allowed to divide; the
progress of cell division was monitored by microscopic cell counts and by colony assay.
DNA was extracted periodically and was compared to pure 14N DNA and 15N DNA. After one
replication, the DNA was found to have intermediate density. Since conservative replication
would result in equal amounts of DNA of the higher and lower densities (but no DNA of an
intermediate density), conservative replication was excluded. However, this result was consistent
with both semiconservative and dispersive replication. Semiconservative replication would result
in double-stranded DNA with one strand of 15N DNA, and one of 14N DNA, while dispersive
replication would result in double-stranded DNA with both strands having mixtures of 15N and
14N DNA, either of which would have appeared as DNA of an intermediate density.
The authors continued to sample cells as replication continued. DNA from cells after two
replications had been completed was found to consist of equal amounts of DNA with two
different densities, one corresponding to the intermediate density of DNA of cells grown for only
one division in 14N medium, the other corresponding to DNA from cells grown exclusively in
14N medium. This was inconsistent with dispersive replication, which would have resulted in a
single density, lower than the intermediate density of the one-generation cells, but still higher
than cells grown only in 14N DNA medium, as the original 15N DNA would have been split
evenly among all DNA strands. The result was consistent with the semiconservative replication
hypoth.
In the Meselson Stahl experiment, E. coli was grown for many generati.pdf
In the Meselson Stahl experiment, E. coli was grown for many generations in a medium
\"heavy\" nitrogen^15 N. Once the bacterial DNA was uniformly labeled, the bacteria were
transferred to a medium containing the \"light\" nitrogen, ^14N. After ONE round of replication,
DNA was extracted and subjected to density gradient centrifugation in cesium chloride. Upon
inspection, there was only a single band of intermediate density DNA in the gradient. This
proved that DNA replication CANNOT be conservative dispersive semiconservative
conservative of dispersive continuous.
Solution
Answer is Dispersive replication.
Dispersive replication would result in double-stranded DNA with both strands having mixtures
of 15N and 14N DNA, either of which would have appeared as DNA of an intermediate density..
PROKARYOTIC DNA REPLICATION
The genetic material must produce a large number of copies of itself during the life cycle of an organism. The process by which a DNA molecule makes its identical copies is called DNA replication. The DNA molecule that undergoes replication may be termed as ‘parent molecule or template molecule, while the two molecules produced by replication may be called progeny molecules or daughter molecules.
Recommended
questions. How did semiconservative and Stahl s experiments support .pdf
questions. How did semiconservative? and Stahl s experiments support the idea that DNA
replication is 2. A new form of DNA is discovered that appears to be able to replicate itself both
in the 3\' 5\' direct and in the sequence direction. If this is true, how would newly on replication
differ from DNA replication as we this discovered DNA know it? 3. Amazingly, an alien species
of cellular organism is found alive in the remains of a meteorite that landed in the Mojave
Desert. As a scientist, you are trying to determine whether this alien life-form uses DNA,
protein, or some other type of compound as its hereditary material a. What kinds of experiments
would you propose to determine what the hereditary material b. If the hereditary material tums
out to be similar to our DNA, describe the simplest experiments you could run to try to
determine if is double-stranded like our DNA, triple-stranded, or some other configuration.
Copyright 2014 Pearson Activity 15.3 Inc.
Solution
Answer to question 1
Nitrogen is one of the major constituent of DNA. 14N is by far the most abundant isotope of
nitrogen, but DNA with the heavier 15N isotope is also functional.
E. coli was grown for several generations in a medium containing NH4Cl with 15N. When DNA
is extracted from these cells and centrifuged on a salt density gradient, the DNA separates out at
the point at which its density equals that of the salt solution. The DNA of the cells grown in 15N
medium had a higher density than cells grown in normal 14N medium. After that, E. coli cells
with only 15N in their DNA were transferred to a 14N medium and were allowed to divide.
DNA was extracted periodically and was compared to pure 14N DNA and 15N DNA. After one
replication, the DNA was found to have intermediate density. Since conservative replication
would result in equal amounts of DNA of the higher and lower densities (but no DNA of an
intermediate density), conservative replication was excluded. However, this result was consistent
with both semiconservative and dispersive replication. Semiconservative replication would result
in double-stranded DNA with one strand of 15N DNA, and one of 14N DNA, while dispersive
replication would result in double-stranded DNA with both strands having mixtures of 15N and
14N DNA, either of which would have appeared as DNA of an intermediate density.
Meselson–Stahl continued to sample cells as replication continued. DNA from cells after two
replications had been completed was found to consist of equal amounts of DNA with two
different densities, one corresponding to the intermediate density of DNA of cells grown for only
one division in 14N medium, the other corresponding to DNA from cells grown exclusively in
14N medium. This was inconsistent with dispersive replication, which would have resulted in a
single density, lower than the intermediate density of the one-generation cells, but still higher
than cells grown only in 14N DNA medium, as the original 15N DNA would have be.
In prokaryotes, promoters are specific sequences of ______ that are r.pdf
In prokaryotes, promoters are specific sequences of ______ that are recognized by __________.
a DNA/RNA polymerase b. RNA/DNA polymerase c. DNA/sigma factor d. RNA/RNA
polymerase In the Meselson-Stahl experiment, cells were grown for one generation in growth
medium containing a relatively heavy nitrogen isotope, then transferred to new medium
containing a lighter nitrogen isotope. After another round of cell division, what is true of the
DNA in the cells? a. All DNA contains only the lighter nitrogen isotope. b. Half of the DNA
contains only the light nitrogen isotope. c. All DNA contains only the heavy nitrogen isotope d.
All DNA contains a hybrid of heavy and light nitrogen isotopes
Solution
C. DNA/sigma factor
Promoter is made of DNA sequence which is recognized by transcription protein sigma factor as
that goes and bind first at DNA then reads it and forms RNA which is called transcription .
D. All dna contains both heavy and light nitrogen isotopes
E. coli was grown for several generations in a medium containing NH4Cl with 15N. When DNA
is extracted from these cells and centrifuged on a salt density gradient, the DNA separates out at
the point at which its density equals that of the salt solution. The DNA of the cells grown in 15N
medium had a higher density than cells grown in normal 14N medium. After that, E. coli cells
with only 15N in their DNA were transferred to a 14N medium and were allowed to divide; the
progress of cell division was monitored by microscopic cell counts and by colony assay.
DNA was extracted periodically and was compared to pure 14N DNA and 15N DNA. After one
replication, the DNA was found to have intermediate density. Since conservative replication
would result in equal amounts of DNA of the higher and lower densities (but no DNA of an
intermediate density), conservative replication was excluded. However, this result was consistent
with both semiconservative and dispersive replication. Semiconservative replication would result
in double-stranded DNA with one strand of 15N DNA, and one of 14N DNA, while dispersive
replication would result in double-stranded DNA with both strands having mixtures of 15N and
14N DNA, either of which would have appeared as DNA of an intermediate density.
The authors continued to sample cells as replication continued. DNA from cells after two
replications had been completed was found to consist of equal amounts of DNA with two
different densities, one corresponding to the intermediate density of DNA of cells grown for only
one division in 14N medium, the other corresponding to DNA from cells grown exclusively in
14N medium. This was inconsistent with dispersive replication, which would have resulted in a
single density, lower than the intermediate density of the one-generation cells, but still higher
than cells grown only in 14N DNA medium, as the original 15N DNA would have been split
evenly among all DNA strands. The result was consistent with the semiconservative replication
hypoth.
In the Meselson Stahl experiment, E. coli was grown for many generati.pdf
In the Meselson Stahl experiment, E. coli was grown for many generations in a medium
\"heavy\" nitrogen^15 N. Once the bacterial DNA was uniformly labeled, the bacteria were
transferred to a medium containing the \"light\" nitrogen, ^14N. After ONE round of replication,
DNA was extracted and subjected to density gradient centrifugation in cesium chloride. Upon
inspection, there was only a single band of intermediate density DNA in the gradient. This
proved that DNA replication CANNOT be conservative dispersive semiconservative
conservative of dispersive continuous.
Solution
Answer is Dispersive replication.
Dispersive replication would result in double-stranded DNA with both strands having mixtures
of 15N and 14N DNA, either of which would have appeared as DNA of an intermediate density..
PROKARYOTIC DNA REPLICATION
The genetic material must produce a large number of copies of itself during the life cycle of an organism. The process by which a DNA molecule makes its identical copies is called DNA replication. The DNA molecule that undergoes replication may be termed as ‘parent molecule or template molecule, while the two molecules produced by replication may be called progeny molecules or daughter molecules.
Nature structure and replication of genetic material
A complete ppt for a detailed explanation of genetic material and its replication in prokaryotes and eukaryotes
FORMS OF DNA
At this time; reading, listening or writing the word DNA doesn’t amaze us, we know that it is deoxyribonucleic acid. But it was not always like this. There was a time when it was a mystery; many of the scientists, researcher and workers spent their whole life in searching out what is DNA.
Identify each of the enzymes involved in DNA replication and whether.pdf
Identify each of the enzymes involved in DNA replication and whether they are used during
synthesis of the leading strand, lagging strand, or both
Solution
ANS:
REPLICATION:
Replication is a process of duplication of DNA .the replication had specific time in S
phase. All the cellular molecules had timing programed inside the cells, the time depends on
species. Replication occur during the S phase of eukaryotic cell cycle.it is highly accurate
process and involved the faithful transmission of the genetically information from parental DNA
to two daughter DNA duplexes.
Replication involves the polymerization of precursor of d NTPs (d ATP, d GTP, d CTP, d TTP).
B. ENZYMOLOGY IN REPLICATION:
Replication is a complex process the various enzymes/proteins are involved in this.
1. DNA polymerase:
It can polymerized the d NTP’s directed by template strand of DNA so called DNA
DEPENDENT DNA POLYMARASE.
In eukaryotes 5 different DNA polymerase are there (Pol Alfa, Pol Beta, Pol Gama, Pol Delta
and Pol Epsilon).
DNA Pol Alfa can initiate replication in both leading and lagging strands, it dual activity so often
called as Pol Alfa/ primase enzyme.
DNA pol Delta is a major replication enzyme involved in the replication of both leading and
lagging strands.
2. DNA A protein: also called initiation protein, it involved in recognition & binding to origin.
3. DNA HELICASE: 1st component in replisoma, it possess an ATPase activity, it separates the
2 parental strands of DNA, It always binds to lagging strand.
4. PRIMASE: Involved in synthesis of RNA primer, always binds to helicase results the
formation of primosome.
5. SSB protein: It prevents reannealing of DNA, it removes the secondary structure prevent in
DNA.
6. DNA Topoisomerase 1: Relaxes tension due to un coiling of dna.it binds downstream of
replication fork.
7. DNA Gyrase: It binds up stream of replication fork and introduces Negative supercoiling.
8. DNA LIGASE: It covalently seals the nick between the adjacent okazaki fragments.
9. Termination protein: Also called TUS protein, binds the TER sites results termination.
10. DNA Topoisomerase 4: Involved in decapitation of the 2 circular daughter DNA duplexes
obtained after replication.
Synthesis of the leading strand and lagging strand:
Semi –conservative mechanism:
In this the 2 strands of DNA separated from each other and each strand act as template for
synthesis of anew complimentary strand ,such daughter duplex contain 1 parental and 1 newly
synthesize strand.
Replication always began from fixed point called origin.as unwinding DNA produced a Y
shaped junction called REPLICATIONPORK. That represents origin of replication.
As the replication pork moved in one direction the DNA copies continuously in both strands.
Then the replication missionary should be able to synthesize in both 5\'-3\' and 3\'-5\' direction.
But the DNA polymerase involved in replication can added a new nucleotide only to 3\'end of
growingchain.so DNA always synthesized in 5\'-3\' .
molecular biology- Replication in Prokaryotes
Replication in Prokaryotes - molecular biology -assignment
DNA REPLICATION class XII Biology based NCERT Text book .pptx
DNA REPLICATION class XII Biology based NCERT Text book .
Prokaryotic DNA replication
Prokaryotic DNA replication : These slides contains basics of the prokaryotic DNA replication for S.Y.B.Sc and T.Y.B.Sc students of Microbiology and biotechnology
It covers topics like Enzymes used in replication, Semiconservative replication, Meselson and Stahl experiment, Termination of replication, modes of replication: theta and rolling circle, basic rules of replication
Blood typing is often used as evidence in paternity cases in court. .pdf
Blood typing is often used as evidence in paternity cases in court. In one case, the mother had
blood type B and the child had blood type O. Which of the following blood types could the
father NOT have?
KEY CROSS PUNNETT ANSWER
Solution
Answer: Father cannot have AB blood group
Genotype of Mother = BO
Genotype of the Baby = OO
Father must have an O allele = OO, AO or BO but not AB.
Write a very simple Note taking using JavaFX ( adding three function.pdf
Write a very simple Note taking using JavaFX ( adding three functionaning buttons - new -
delete - save )
Solution
JavaFX is a set of grapics and media packages that enables developers to design, create, test,
debug and deploy client applications that operate on diverse platforms.It is a java library that
contains classes and interfaces that are written in native code. There are many features involved
in JavaFX like UI controls, webview, Canvas API, Multitouch support mainly used for android
applications, Swing interoperability etc..
Buttons can also be created by using this JavaFX and we can do changes to those buttons like
applying shadow effect, image for button etc...
Button btn=new Button(\"new\");
Button btn1 =new Button(\"Delete\");
Button btn2=new Button(\"Save\");
// Here three buttons have been created and now we can assign the actions to these buttons by
using //setOnAction() method availabel in javaFX
btn1.setOnAction( new EventHandler () {
@override public void handle(ActionEvent e){
FileChooser file=new FileChooser();
File selected=file.showOpenDialog(stage);
if(selected !=NULL)
openFile(selected);
}
});
btn2.setOnAction(new EventHandler() {
@override private handle(ActionEvent e){
file.showSaveDialog(stage);
}
});
These buttons are used to open a new file and save the file using javaFX.
More Related Content
Similar to I need answer to those questions please ASAP Im stuck D Question 1.pdf
Nature structure and replication of genetic material
A complete ppt for a detailed explanation of genetic material and its replication in prokaryotes and eukaryotes
FORMS OF DNA
At this time; reading, listening or writing the word DNA doesn’t amaze us, we know that it is deoxyribonucleic acid. But it was not always like this. There was a time when it was a mystery; many of the scientists, researcher and workers spent their whole life in searching out what is DNA.
Identify each of the enzymes involved in DNA replication and whether.pdf
Identify each of the enzymes involved in DNA replication and whether they are used during
synthesis of the leading strand, lagging strand, or both
Solution
ANS:
REPLICATION:
Replication is a process of duplication of DNA .the replication had specific time in S
phase. All the cellular molecules had timing programed inside the cells, the time depends on
species. Replication occur during the S phase of eukaryotic cell cycle.it is highly accurate
process and involved the faithful transmission of the genetically information from parental DNA
to two daughter DNA duplexes.
Replication involves the polymerization of precursor of d NTPs (d ATP, d GTP, d CTP, d TTP).
B. ENZYMOLOGY IN REPLICATION:
Replication is a complex process the various enzymes/proteins are involved in this.
1. DNA polymerase:
It can polymerized the d NTP’s directed by template strand of DNA so called DNA
DEPENDENT DNA POLYMARASE.
In eukaryotes 5 different DNA polymerase are there (Pol Alfa, Pol Beta, Pol Gama, Pol Delta
and Pol Epsilon).
DNA Pol Alfa can initiate replication in both leading and lagging strands, it dual activity so often
called as Pol Alfa/ primase enzyme.
DNA pol Delta is a major replication enzyme involved in the replication of both leading and
lagging strands.
2. DNA A protein: also called initiation protein, it involved in recognition & binding to origin.
3. DNA HELICASE: 1st component in replisoma, it possess an ATPase activity, it separates the
2 parental strands of DNA, It always binds to lagging strand.
4. PRIMASE: Involved in synthesis of RNA primer, always binds to helicase results the
formation of primosome.
5. SSB protein: It prevents reannealing of DNA, it removes the secondary structure prevent in
DNA.
6. DNA Topoisomerase 1: Relaxes tension due to un coiling of dna.it binds downstream of
replication fork.
7. DNA Gyrase: It binds up stream of replication fork and introduces Negative supercoiling.
8. DNA LIGASE: It covalently seals the nick between the adjacent okazaki fragments.
9. Termination protein: Also called TUS protein, binds the TER sites results termination.
10. DNA Topoisomerase 4: Involved in decapitation of the 2 circular daughter DNA duplexes
obtained after replication.
Synthesis of the leading strand and lagging strand:
Semi –conservative mechanism:
In this the 2 strands of DNA separated from each other and each strand act as template for
synthesis of anew complimentary strand ,such daughter duplex contain 1 parental and 1 newly
synthesize strand.
Replication always began from fixed point called origin.as unwinding DNA produced a Y
shaped junction called REPLICATIONPORK. That represents origin of replication.
As the replication pork moved in one direction the DNA copies continuously in both strands.
Then the replication missionary should be able to synthesize in both 5\'-3\' and 3\'-5\' direction.
But the DNA polymerase involved in replication can added a new nucleotide only to 3\'end of
growingchain.so DNA always synthesized in 5\'-3\' .
molecular biology- Replication in Prokaryotes
Replication in Prokaryotes - molecular biology -assignment
DNA REPLICATION class XII Biology based NCERT Text book .pptx
DNA REPLICATION class XII Biology based NCERT Text book .
Prokaryotic DNA replication
Prokaryotic DNA replication : These slides contains basics of the prokaryotic DNA replication for S.Y.B.Sc and T.Y.B.Sc students of Microbiology and biotechnology
It covers topics like Enzymes used in replication, Semiconservative replication, Meselson and Stahl experiment, Termination of replication, modes of replication: theta and rolling circle, basic rules of replication
Similar to I need answer to those questions please ASAP Im stuck D Question 1.pdf (20)
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centraldogmaofmolecularbiology-130608212246-phpapp01.pdf
Nature structure and replication of genetic material
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Blood typing is often used as evidence in paternity cases in court. .pdf
Blood typing is often used as evidence in paternity cases in court. In one case, the mother had
blood type B and the child had blood type O. Which of the following blood types could the
father NOT have?
KEY CROSS PUNNETT ANSWER
Solution
Answer: Father cannot have AB blood group
Genotype of Mother = BO
Genotype of the Baby = OO
Father must have an O allele = OO, AO or BO but not AB.
Write a very simple Note taking using JavaFX ( adding three function.pdf
Write a very simple Note taking using JavaFX ( adding three functionaning buttons - new -
delete - save )
Solution
JavaFX is a set of grapics and media packages that enables developers to design, create, test,
debug and deploy client applications that operate on diverse platforms.It is a java library that
contains classes and interfaces that are written in native code. There are many features involved
in JavaFX like UI controls, webview, Canvas API, Multitouch support mainly used for android
applications, Swing interoperability etc..
Buttons can also be created by using this JavaFX and we can do changes to those buttons like
applying shadow effect, image for button etc...
Button btn=new Button(\"new\");
Button btn1 =new Button(\"Delete\");
Button btn2=new Button(\"Save\");
// Here three buttons have been created and now we can assign the actions to these buttons by
using //setOnAction() method availabel in javaFX
btn1.setOnAction( new EventHandler () {
@override public void handle(ActionEvent e){
FileChooser file=new FileChooser();
File selected=file.showOpenDialog(stage);
if(selected !=NULL)
openFile(selected);
}
});
btn2.setOnAction(new EventHandler() {
@override private handle(ActionEvent e){
file.showSaveDialog(stage);
}
});
These buttons are used to open a new file and save the file using javaFX.
Write a JAVA program that reads a stream of integers from a file and.pdf
Write a JAVA program that reads a stream of integers from a file and prints to the screen the
range of integers in the file (i.e. [lowest, highest]). You should first prompt the user to provide
the file name. You should then read all the integers from the file, keeping track of the lowest and
highest values seen in the entire file, and only print out the range of values after the entire file
has been read. Importantly, unlike the previous problem, you can make no assumptions about the
contents of the file. If your program cannot read the file, opens an empty file, or encounters a
non- integer while reading the file, your program should output that the file is invalid.
You have been supplied JUnit tests for several invalid files (e.g. non-existent, empty, non-
integer) as well as files that contain only integer values.
Solution
ReadFileNumbers.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadFileNumbers {
public static void main(String[] args) throws FileNotFoundException {
Scanner scan = new Scanner(System.in);
System.out.print(\"Enter the file name: \");
String fileName = scan.next();
File file = new File(fileName);
int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
if(file.exists()){
try{
Scanner scan1 = new Scanner(file);
if(scan1.hasNext()){
while(scan1.hasNext()){
int n= scan1.nextInt();
if(min > n){
min = n;
}
if(max < n){
max = n;
}
}
System.out.println(\"highest number is \"+max);
System.out.println(\"lowest number is \"+min);
}
else{
System.out.println(\"File is an empty\");
}
}
catch(Exception e){
System.out.println(\"File is invalid. File has a a non-integers.\");
}
}
else{
System.out.println(\"File does not exist\");
}
}
}
Output:
Enter the file name: D:\\\ umbers.txt
highest number is 9
lowest number is -17
numbers.txt
3
4
2
-1
1
5
7
-11
-12
-17
6
9
8.
What two difficulties arise in taking simplicity straightforwardly a.pdf
What two difficulties arise in taking simplicity straightforwardly as a guide in choosing one
hypothesis over another?
Solution
Answer:
Theories with the fewest assumptions are often preferred to those positing more, a heuristic often
called “Occam’s razor.” This kind of argument has been used on both sides of the creationism vs.
evolution debate.
Simple theories have many advantages: they are often falsifiable or motivate various predictions,
and can be easily communicated as well as widely understood.
But there are numerous reasons to suspect that this simple “theory of theories” is itself
fundamentally misguided. Nowhere is this more apparent than in physics, the science attempting
to uncover the fundamental laws giving rise to reality. The history of physics is like a trip down
the rabbit hole: the elegance and simplicity of Newtonian physics has been incrementally
replaced by more and more complex theories.
And it is in the life sciences where Occam’s razor cuts most sharply in the wrong direction and
posing difficulties in taking simplicity straightforwardly
1) First, life itself is a fascinating example of nature’s penchant for complexity. Parsimony can
apply anywhere but not here.
2) Second, evolution doesn’t design organisms as an engineer might, instead, organisms carry
their evolutionary history along with them, advantages and disadvantages alike (appendix is the
price an individual pays for all his inherited immunity to disease). Thus, life appears to result
from a cascading complexifying process, an understanding of organisms at the macroscale will
be anything but simple.
3) Third, we know that the even the simplest rules of life can give rise to intractable complexity.
Unless an individual is a biophysicist, the mechanisms at the preferred level of analysis are likely
to be incredibly heterogenous and complex, even at the simplest..
what is true about assetsSolutionAssets are those which are u.pdf
what is true about assets?
Solution
Assets are those which are used as an economic resource for generating revenues. Assets may be
of Tangibles or Intangibles. Tangible assets are those which can be seen and toouch physcially.
Intangible assets are those which cannot be seen in physical but they get generate revenues..
What happens if the dividing zygote accidental separates into two A.pdf
What happens if the dividing zygote accidental separates into two? After fertilizations, how
long does it take for the blastocyst to arrive in the uterus? What risk does the blastocyst face
after it attaches to the uterus? What is gastrulation? What will the lower layer of cells
(endoderm) develop into? What will the middle layer of cells (mesoderm) develop into? What
will the outer layer of cells (ectoderm) develop into? What does a gene do when it has been
turned on? What do the following proteins do? a. Collagen: b. Crystallin: c. Actin and Myosin:
d. Hemoglobin: How do cells communicate with each other? How is the Y chromosome
different from the X chromosome? Where specifically does the baby get its nutrients from? Do
the baby\'s and mother\'s blood ever mix? How old is the fetus when it gains the ability to hear
sounds? Why is birth more dangerous for humans than other animals?
Solution
Q.No 17
A single-celled zygote will undergo multiple rounds of cleavage, or cell division, to be able to
produced a ball of cells, called a blastula, accompanied by a fluid-filled cavity to use center,
termed as blastocoel.
Q.No 18
Blastocyst formation begins about 5 days after fertilization, if your fluid-filled cavity uncovers in
the morula, a ball consisting of some dozen cells. The blastocyst possesses a diameter of 0.1-0.2
mm and comprises 200-300 cells following rapid cleavage (cell division). After about 1 day (5–6
days post-fertilization), which it\'s time usually required to contact the uterus, the blastocyst sets
out to embed itself into the endometrium of the uterine wall where it may undergo later
developmental processes, including gastrulation.
Q.No 19
Approximately 5–6 days after fertilization the blastomeres of one\'s blastula set out to undergo
cell differentiation and it is structure changes in becoming the blastocyst. With the uterus the
zona pellucida of one\'s blastocyst breaks down allowing it to implant straight into the uterine
wall approximately 6 days after fertilization. Implantation marks the conclusion of the germinal
stage of embryogenesis.
Q.No 20
During gastrulation, the blastula folds in on itself to three germ layers, the ectoderm, the
mesoderm, and the endoderm, that give rise to the internal structures of one\'s organism. Is it
doesn\'t stage of embryo development at which a gastrula is made from your blastula via the
inward migration of cells.
Q.No 21
The endoderm is among the most germ layers formed during animal embryogenesis. Cells
migrating inward across the archenteron form the inner layer of one\'s gastrula, which develops
into the endoderm.The endoderm consists at firstly flattened cells, which subsequently become
columnar. It forms the epithelial lining of one\'s whole of one\'s digestive tube except an area of
the mouth and pharynx along with the terminal an area of the rectum
Q.No 22
The mesoderm germ layer forms in the embryos of triploblastic animals.During gastrulation, a
few of the cells migrating inward b.
What are stored in the Autodesk Inventor History Tree When extrudin.pdf
What are stored in the Autodesk Inventor History Tree? When extruding, what is the difference
between Distance and Through All? Describe the history-based part modification approach.
What determines how a model reacts when other features in the model change?
Solution
1. The Autodesk Inventor History Tree has all features, which includes Boolean relations,
construction steps, the rules defining the design intent of each construction operation. A history
tree is sequential record of the features used to create the part.
2. DISTANCE option extrudes in one specific direction only. This option in INVENTOR is By
Default for creating extrusions. During this option extrusion distance is given input in input
box.There are some direction controls with distance option( 1. Direction, 2. Symmetric, and 3.
Asymmetric) as per desired extrusion.
THROUGH ALL is used to extrude the profile through all features and sketches is a desired
direction.
3. HISTORY BASED PART MODIFICATION is used in Inventor, this enables us to perform
modifications in appropriate features and relink the the history tree without reconstructing the
model same as in history. By this we can keep watch on steps performed in creating a part. This
feature has advantage that we can mofidy any feature that has been created.
4. The paresnt/child relationships determine how a model reacts when other features in model
change..
What are three factors contributing to resistanceCharacterize car.pdf
What are three factors contributing to resistance?
Characterize cardiomyocytes?
An EKG correlates to which events in the cardiac cycle?
Solution
Resistance is the ability of any bacteria and other microorganisms to resist the effects of any
antibiotic to which they were sensitive before.
Factors contributing to resistance are - Overuse of antibiotics, Mutation or gene transfer and
agricultural use of drugs..
Alan Homes serves on the board of directors of Flynn Company. The pr.pdf
Alan Homes serves on the board of directors of Flynn Company. The president of Flynn told him
that in three weeks the corporation would announce a 25% increase in dividends. Alan called his
neighbor to tell him to buy some stock. The neighbor told his friend about the stock, and that
friend told him that Alan was acting unethically. The neighbor called Alan back, and Alan told
him that no one would know the difference, that in business this happens all the time, and that he
shouldn\'t be left out. Do you think Alan\'s behavior is appropriate? Write down your
recommendation to Allen\'s neighbor.
Solution
My recommendation to Allen\'s neighbor is not to buy the stock and reasons for this are given
below:-
1- If a company 25% increase in dividend that does not gaurantee of company\'s growth in terms
of funds and share
value.
2- The dividend paid to customers can not be utilized for growth of the business.
3- After paying high dividends Flynn has minimum money to growth the funds.
4- Investors will have to pay the tax on 25% dividend value received because dividends are
taxable article.
5- Dividends are not gauranteed income forever although it can be stopped any time by Flynn
company.
6- Dividends always have a broad effect on equity rates if any time dividends are cancelled then
share price will
increase at a higher rate and investors will definately loose his/her shares due to minimum
dividend pay out.
7- Only focusing on high dividend paying comapnies like Flynn will cut the maximum chances
of additional new
investment in market in terms of profit gaining.
Conclusion:- In my opinion Allen\'s behavior is not appropriate because of not
thinking/Analysing about profitability,overall debt management, liquidity ratios, asset
management, cash flow( in last 5 years) and long term investment plans of Flynn Company. All
these things mentioned above are very important for any investor to gain long term benefits from
Dividends..
Two genes (A and B) are located 10cM apart on the X chromosome. A wom.pdf
Two genes (A and B) are located 10cM apart on the X chromosome. A woman is homozygous
for recessive mutant alleles for both genes. She has children with a wild-type man who is
homozygous for both genes. What proportion of their children are expected to show wild-type
phenotype for both genes? 100% 95% 0% 5% 50%
Solution
D.5%
Homozygous dominant = p2 = 0.25
Homozygous dominant = q2 = 0.25
children 2pq = 0.5
Now the homozygous make up 2/3 of the surviving population, so the recessive allele makes up
1/3 of the total alleles in the population. 2pq = 0.5 or 5%.
q2.4) Listed are elements of the financial statements discussed in t.pdf
q2.4) Listed are elements of the financial statements discussed in this chapter. Match each
element with the descriptions (use each as many times as necessary) (Click the icon to view the
elements.) Debts of the company Economic resources with future benefit Elements V Inflows of
assets from delivering or producing goods or services | Things of value a company owns VThe
residual interest in the assets of an entity that remains after deducting its liabilities | The
difference between what the company has and what the company owes V The owners\' interest in
the company | outflows or using up of assets from delivering or producing goods and services 3
4 a. Assets b. Liabilities c. Shareholders\' equity d. Revenues e. Expenses Costs that have no
future value PrintDone 10. The amount the company owes | Sales
Solution
Debts of a company
Liabilities
Economic resources with future value
Assets
inflows of asset from delivering products or services
Revenue
Things of value a company owns
Assets
A residential interest in the assets of the entity that remains after deducting its liabilities
Shareholders equity
The difference between what company has and what company owes
Shareholders equity
The owners interest in the company
Shareholders equity
Outflows or using up of assets from delivering or producing goods and services
Expenses
Costs that have no future value
Expenses
The amount the company owes
Liabilities
Sales
Revenues
Debts of a company
Liabilities
Economic resources with future value
Assets
inflows of asset from delivering products or services
Revenue
Things of value a company owns
Assets
A residential interest in the assets of the entity that remains after deducting its liabilities
Shareholders equity
The difference between what company has and what company owes
Shareholders equity
The owners interest in the company
Shareholders equity
Outflows or using up of assets from delivering or producing goods and services
Expenses
Costs that have no future value
Expenses
The amount the company owes
Liabilities
Sales
Revenues.
Programming code in C must be C loops reque.pdf
Programming code in C ***************** must be C *****
loops requesting information about patients and inserting the information into a linked list:
call a function responsible for allocating the memory for the new item, requesting the following
information for each patient: first name, last name, and patientid (an integer), and putting the
information into the new item
the function mentioned in part a should return a pointer to the new item
call a function to insert the new item into the linked list
new patients should be added so that the list is in alphabetical order by the last name
leave the loop when the patient id is set to 0
displays the patient information in alphabetical order by the last name once all data has been
provided. The first and last name and patient id for each patient should be displayed
After the data has been input and displayed, enter another loop that asks for a patient’s last name
and then displays the information for that patient:
Write a function to search for the patient in the linked list and return a pointer to the item if it is
found. If it is not found return null
If the patient is found, display the patient’s full name and id number.
If the patient is not found, display a message saying the patient was not found.
Leave the loop if the person enters a zero for the person’s last name.
Solution
#include
#include
#include
//-------------------------------------------------
struct node
{
int pid;
char fname[10];
char sname[10];
struct node *next;
};
//------------------------------------------------------------
struct node *start=NULL;
struct node *create(struct node *);
struct node *display(struct node*);
struct node *sort(struct node*);
struct node *create(struct node *start)
{
struct node *new_node ,*ptr;
int num;
char ch;
do
{
new_node=(struct node *)malloc(sizeof(struct node));
printf(\"Enter Patient ID: \");
scanf(\"%d\",&new_node->pid);
printf(\"Enter Patient First name: \");
scanf(\"%s\",&new_node->fname);
printf(\"Enter Patient Second name: \");
scanf(\"%s\",&new_node->sname);
new_node->next=NULL;
if(start==NULL)
{
new_node->next=NULL;
start=new_node;
}
else
{
ptr=start;
while(ptr->next!=NULL)
ptr=ptr->next;
ptr->next=new_node;
new_node->next=NULL;
}
printf(\"\ Do you want to create another : \");
ch=getche();
}while(ch!=\'n\');
return start;
}
//------------------------------------------------------------------
struct node* display(struct node* start)
{
struct node *new_node;
printf(\"\ The Linked List : \");
new_node=start;
while(new_node!=NULL){
printf(\"\ %d\",new_node->pid);
printf(\"\\t%s\", new_node->fname);
printf(\"\\t%s\",new_node->sname);
new_node=new_node->next;
}
return start;
}
struct node* sort(struct node* start){
struct node *ptr1,*ptr2;
char temp[10];
int i;
while(ptr1->next!=NULL){
ptr2=ptr1->next;
while(ptr2!=NULL){
if(ptr1->sname[0]>ptr2->sname[0]){
for (i=0;i<2;i++)
temp[i]=ptr1->sname[i];
for (i=0;i<2;i++)
ptr1->sname[i]=ptr2->sname[i];
for (i=0;i<2;i++)
ptr2->sname[i]=temp[i];
}.
Please find the solution. Thanks 4. As the value of increases fro.pdf
Please find the solution. Thanks 4. As the value of increases from r-ito,.4,1he value offa)
increases by 50% M4> is how many limes as large as
Solution
given as value of x increases from x =1 to x =4, the value of f(x) increases by 50%
[f(4)-f(1)]/f(1)=50%
f(4)-f(1)=50%f(1)
f(4)-f(1)=0.5f(1)
f(4)=0.5f(1)+f(1)
f(4)=1.5 f(1)
f(4) is 1.5 times f(1).
Please help! Both answers must be in long paragraph form1. Explain.pdf
Please help! Both answers must be in long paragraph form
1. Explain in detail Where did the chloroplast organelle come from, what is it\'s \"origin story\",
what evidence supports this idea originally developed by Lynn Margulis?
2. Explain in detail What is the importance of chloroplasts to living things other than plants?
What are products they make, and how did one of the waste products generated change the
history of the planet earth?
Solution
Ans 1: Chloroplast Origin: The credit for discovery of this organelle goes to Julius Von Sachs. In
Year 1837, German botanist Hugo von Mohl provided the first definitive description of the
chloroplast, which is descrite bodies within the green plant cell. Later, The name was changed to
plastid by A.F. W Schimper in 1883. By the end of 19th century chloroplast name was accepted
in scientfic community worldwide to the cell- organelle which is green color found in plant
tisuue. One major discovery was also found by schimper that chloroplast are capable of division.
He suggest that origin of green pant was possibly by symbiotic relationship between chlorophyll
containing and colorless organism. Another important observation was made by A. meyer in
1883 that chloroplast contain grana. Chloroplast are only found in green plant,algae etc. Green
Color present in plant is only due to chloroplast.
Lynn Margulis was a evolutionist, she suggest that photosynthesis process which occur in plant
due to symbiosis relationship between plant cell and bacteria,which reside permanently there, by
which chloroplast capture sunlight energy undergoes biochemical reaction including
combination of water and carbon di oxide to make organic matter. Margulis symbisis thought of
evolution of eukaryotic cell was published in \" The Origin of Eukaryotic Cells.\"
Ans 2 : Importance of chloroplast is in the process of photosynthesis take place in algae, which is
also eukayotes. Many are unicellular, but sometimes they can live in large colonies that may
even look like plants.
Cynobacteria are prokaryotes contain double outer membrane and thylakoid membrane system
for the process of photosyntheis. Cyanobacteria also use the Calvin cycle to fix carbon dioxide in
the same way as plants and algae. Both of the above organism perform oxygenic photosynthesis.
similar way green sulphur, green non sulphur and heliobacteria use choloroplast for the process
of photosynthesis.
Two and a half billion years ago, single-celled organisms called cyanobacteria harnessed
sunlight to split water molecules, producing energy to power their cells and releasing oxygen
into an atmosphere that had previously had none. These early environmental engineers are
responsible for the life we see around us today. Oxygen which is one of the waste product
generated during photosynthesis change the history of the planet earth and all the higher level
living organism are able to live their life easily..
Life is easy to recognize but difficult to define. According to .pdf
\"Life\" is easy to recognize but difficult to define. According to one popular biology text, living
things:
1- are highly organized compared to natural inanimate objects
2- display homeostasis, maintaining a relatively constant internal environment
3- reproduce themselves
4- grow and develop from simple beginnings
5- take energy and matter from the environment and transform it
6- Respond to stimuli
7- Show adaptation to their environment
Score a person, a vacuum cleaner, and a potato with respect to these characteristics
Solution
Vacuum cleaner is an inanimate object. It is highly organized when compared to natural
inanimate objects.
Potato is natural life containing object that takes energy and matter from environment and
transform it. It grow and develop from simple beginnings. It reproduces and show adaptation to
the environment.
Person displays homeostasis, maintaining a relatively constant internal environment, reproduce
themselves, take energy and matter from the environment and transform it, respond to stimuli
and show adaptation to their environment.
Person is highly ranked than potato. Potato is highly ranked than inanimate object.
Let I, J be ideals in a ring R. Prove that I J is also an ideal of R.pdf
Let I, J be ideals in a ring R. Prove that I J is also an ideal of R.
Solution
Answer :
Let I and J be two ideals of a ring R.
Then I J is an additive subgroup because intersections of sub-groups are subgroups.
If f I J and x R then xf I because f I and I is an ideal and so xf J for the same reason, so xf I
J.
Thus , I J is an ideal of R..
Imagine that one of the segments in Drosophila is T2, which will for.pdf
Imagine that one of the segments in Drosophila is T2, which will form the wing, and that two of
the cells in that segment will become the wing disk, and form the entire wing during pupation.
Which two cells must this be? Describe them in terms of their gene expression: are they cells that
express \"engrailed + hedgehog only\", \"patched only\", or \"patched + wingless only\"?
Solution
Answer:
The effects of a total lack of engrailed function in the wing has revealed three different
requirements for engrailed during wing development.
1. It has a late role in patterning the wing margin, which includes cells within the anterior
compartment.
2. it is involved in the cell-cell interactions that maintain the expression of the decapentaplegic
gene along the antero-posterior compartment boundary. Decapentaplegic, in turn, controls
growth through a mechanism that depends on the activity of the gene hedgehog, and the
maintenance of the compartment boundary depends on these cell-cell interactions.
3. Finally, there is a global requirement for engrailed in the control of growth through a
hedgehog-independent mechanism.
Thus, they appears to be cells which express engrailed and hedgehog only..
If the Social Security retirement system was a private retirement sy.pdf
If the Social Security retirement system was a private retirement system, it would be declared
bankrupt. Discuss why this is so and why the Social Security system can continue to pay benefits
despite the fact that it can be considered bankrupt. Discuss why the Social Security tax rate has
increased so much in recent years. What measures could be taken to reduce the Social Security
payroll tax rate?
Solution
Social Security System Definition-
A system of federally funded services and payments to help support the needy ,the aged and the
temporarily unemployed as well as providing support for needy, dependent, disabled ,or
neglected children, rehabilitation for the disabled ,and a host of other social services. The system
was established as part of the new Deal and is funded by payroll taxes paid by workers and
employers.
Social Security is funded through payroll taxes called Federal insurance contributions Act
Tax(FICA) or self employed contributions Act(SECA).Tax deposits are collected by the internal
revenue service(IRS) and are formally entrusted to the Federal Old –Age and survivors insurance
Trust Fund,the Federal Disability insurance Trust Fund,the Federal Hospital insurance trust
Fund,or the fedral supplementary medical insurance trustFund which make up the social Security
Trust Funds.with a few exceptions ,all salaried income ,up to an amount specifically determined
by law has a FICA or SECA tax collected on it .All income over said amount is not taxed ,for
2015 the maximum amount of taxable earning is $118,500
Social Security\'s financial situation hasn\'t changed much since last year, according to the
annual Trustee\'s Report released last week.
· There is enough money in the Social Security trust fund to pay full retirement benefits
through 2033. After that, payroll taxes at current levels will bring in about 75 percent of the
money required to pay Social Security\'s obligations.
What measures could be taken to reduce the Social Security payroll tax rate?
America\'s Social Security system is in serious trouble. Payroll tax rates have been increased 17
times in the past 40 years, yet promised benefits exceed projected revenues by trillions of dollars.
Moreover, Social Security has become an increasingly bad deal for American workers who must
pay record high taxes to a system that provides only meager levels of income for their retirement
years. Even worse, there is no way to fix the current system to remedy these problems.
Additional payroll taxes or benefit reductions would address the massive long-term deficit, but
only by making the system an even poorer investment for working Americans; and raising
benefits or cutting taxes, both of which could improve the rate of return for workers, would
catapult Social Security into bankruptcy even sooner.
The only answer to these seemingly intractable problems is to privatize the Social Security
system. Countries around the world, including Chile, Australia, Mexico, Singapore, and Great
Britai.
Identify the following reaction Glucose + Fructose rightarrow Sucros.pdf
Identify the following reaction: Glucose + Fructose rightarrow Sucrose + Water dehydration
synthesis reaction hydrolysis reaction exchange reaction reversible reaction ionic reaction
Solution
Identify the following reaction: Glucose + Fructose Sucrose + Water
A) Dehydration synthesis reaction --------answer
B) Hydrolysis reaction
C) Exchange reaction
D) Reversible reaction
E) Ionic reaction
explanation:
Dehydration synthesis : it is the process joining two particles, or mixes, together after the
evacuation of water. the word dehydration, the primary thing that may come out is \'losing
water\' or \'lacking water.\'.
identify the developmental genes that influence macroevolutionSo.pdf
identify the developmental genes that influence macroevolution
Solution
Developmental genes are the regulatory genes that regulate hundreds of genes of development
and even a small genetic change in these genes leads to major structural changes in the
organisms. These are the genes that distinguish one species from other species. These genes
regulate the shape, pattern and type and location of organs of animal body. For ex: Hox genes
serve to regulate the formation of particular regions of the body by encoding the related
transcription factors and thereby regulate the fate of regions of body. Homeotic genes determine
the future development of segments on the basis of the pattern of expression of the segmentation
genes before them. Mutation in these genes leds to development of that segment to an adjacent
segment, usually anterior to it. These genes are also called memory genes as they regulate
developmental fate of a segment which is followed from one cell division to the next..
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Life is easy to recognize but difficult to define. According to .pdf
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Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
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Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
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Reverse Pharmacology.
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