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Forms of Quadratic Functions
Give the different forms of
quadratic function, determine the
axis of symmetry, opening of the
parabola and the vertex; and
Identify the different forms of
quadratic functions.
The vertex is (h,k), and the axis of
symmetry is x = h which divides the
graph of quadratic function into two
equal parts. The value of a indicates
the opening of the graph. If the value
of a is positive, the graphs opens
upward. If the value of a is negative,
the graph opens downward.
To find the value of the vertex use the
formula of:
𝒉 =
−𝒃
𝟐𝒂
and 𝒌 =
𝟒𝒂𝒄−𝒃𝟐
𝟒𝒂
and the axis of
symmetry is x = h.
Examples:
1.y = 3x² - 4
2.y = - x² + 2x + 3
3.y = 5x²
4.y = 2x² + 8x + 16
Graphs of Quadratic
Functions
Learning Targets
 Draw the graphs of the quadratic
function;
 Analyze the effect of changing the
values of a, h and k in the equation
y = a(x-h)²+k of the quadratic function
on its graph.
GRAPHS OF QUADRATIC FUNCTION
All quadratic functions have graphs
similar to this graph. This U-shaped is
called a parabola. 𝑷𝒂𝒓𝒂𝒃𝒐𝒍𝒂
𝒗𝒆𝒓𝒕𝒆𝒙
( 0, -1 )
The “turning points” of the graph is
called the vertex of the parabola.
The parabola is symmetric with respect
to a line that passes through the vertex.
This line is called the axis of symmetry. It
divides the parabola into two parts so
that one part is a reflection of the other
part.
𝒂𝒙𝒊𝒔 𝒐𝒇 𝒔𝒚𝒎𝒎𝒆𝒕𝒓𝒚
EXAMPLE 1. Construct a table of values for the
quadratic function and identify at least five points of
the function.
𝑓 𝑥 = 1 − 2𝑥 − 𝑥2
𝒌 =
𝟒𝒂𝒄 − 𝒃𝟐
𝟒𝒂
𝒉 =
−𝒃
𝟐𝒂
𝒂 = −𝟏 𝒃 = −𝟐 𝒄 = 𝟏
𝑭𝒊𝒏𝒅 𝒕𝒉𝒆 𝒗𝒆𝒓𝒕𝒆𝒙.
𝒉 =
−(−𝟐)
𝟐(−𝟏)
𝒉 =
𝟐
−𝟐
𝒉 = −𝟏
𝒌 =
−𝟒 − 𝟒
−𝟒
𝒌 =
𝟒(−𝟏)(𝟏) − (−𝟐)𝟐
𝟒(−𝟏)
𝒌 =
−𝟖
−𝟒
𝒌 = 𝟐
𝑽𝒆𝒓𝒕𝒆𝒙: (−1, 2)
x
y
−𝟏
𝟐
−𝟐
−𝟑 0 𝟏
1
−𝟐 1 −𝟐
𝑓 𝑥 = 1 − 2(−2) − (−2)2
𝒙 = −𝟐
𝑓 𝑥 = 1 − 2𝑥 − 𝑥2
𝑓 𝑥 = 1
𝑓 𝑥 = 1 + 4 − 4
𝑓 𝑥 = 1 − 2(−3) − (−3)2
𝒙 = −𝟑
𝑓 𝑥 = −2
𝑓 𝑥 = 1 + 6 − 9
𝑓 𝑥 = 1 − 2(0) − (0)2
𝒙 = 𝟎
𝑓 𝑥 = 1
𝑓 𝑥 = 1 − 0 − 0
𝑓 𝑥 = 1 − 2(1) − (1)2
𝒙 = 𝟏
𝑓 𝑥 = −2
𝑓 𝑥 = 1 − 2 − 1
𝑽𝒆𝒓𝒕𝒆𝒙: (−1, 2)
x
y
−𝟏
(−𝟏, 𝟐)
−𝟐
−𝟑 0 𝟏
1
−𝟐 1 −𝟐
𝑓 𝑥 = 1 − 2𝑥 − 𝑥2
𝑣𝑒𝑟𝑡𝑒𝑥: (−1, 2)
𝟐
(−𝟐, 𝟏)
(−𝟑, −𝟐) (𝟏, −𝟐)
(𝟎, 𝟏)
𝐴𝑥𝑖𝑠 𝑜𝑓 𝑆𝑦𝑚𝑚𝑒𝑡𝑟𝑦: (−1)
𝑦 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: 1
𝑂𝑝𝑒𝑛𝑠 𝑑𝑜𝑤𝑛𝑤𝑎𝑟𝑑
𝑥 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: −2.5, 0.5
𝑅𝑎𝑛𝑔𝑒: 𝑦 𝑦 ≤ 2
𝐷𝑜𝑚𝑎𝑖𝑛: 𝑎𝑙𝑙 𝑟𝑒𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠
EXAMPLE 2. Draw the graph of the quadratic
function.
𝑦 = −𝑥2
− 2𝑥 + 3
𝒌 =
𝟒𝒂𝒄 − 𝒃𝟐
𝟒𝒂
𝒉 =
−𝒃
𝟐𝒂
𝒂 = −𝟏 𝒃 = −𝟐 𝒄 = 𝟑
𝑭𝒊𝒏𝒅 𝒕𝒉𝒆 𝒗𝒆𝒓𝒕𝒆𝒙.
𝒉 =
−(−𝟐)
𝟐(−𝟏)
𝒉 =
𝟐
−𝟐
𝒉 = −𝟏 𝒌 =
−𝟏𝟐 − 𝟒
−𝟒
𝒌 =
𝟒(−𝟏)(𝟑) − (−𝟐)𝟐
𝟒(−𝟏)
𝒌 =
−𝟏𝟔
−𝟒
𝒌 = 𝟒
𝑽𝒆𝒓𝒕𝒆𝒙: (−1, 4)
x
y
−𝟏
𝟒
−𝟐
−𝟑 0 𝟏
3
𝟎 3 𝟎
𝑓 𝑥 = −(0)2 − 2 0 + 3
𝒙 = −𝟐
𝑦 = −𝑥2
− 2𝑥 + 3
𝑓 𝑥 = 3
𝒙 = −𝟑
𝑓 𝑥 = 0
𝒙 = 𝟎
𝑓 𝑥 = 3
𝒙 = 𝟏
𝑓 𝑥 = 0
𝑓 𝑥 = 0 − 0 + 3
𝑓 𝑥 = −(−3)2
− 2 −3 + 3
𝑓 𝑥 = −9 + 6 + 3
𝑓 𝑥 = −(−2)2 − 2 −2 + 3
𝑓 𝑥 = −4 + 4 + 3
𝑓 𝑥 = −(1)2 − 2 1 + 3
𝑓 𝑥 = −1 − 2 + 3
x
y
−𝟏
(−𝟏, 𝟒)
−𝟐
−𝟑 0 𝟏
3
𝟎 3 𝟎
𝑦 = −𝑥2
− 2𝑥 + 3
𝑣𝑒𝑟𝑡𝑒𝑥: (−1, 4)
𝟒
(−𝟐, 𝟑)
(−𝟑, 𝟎) (𝟏, 𝟎)
(𝟎, 𝟑)
𝐴𝑥𝑖𝑠 𝑜𝑓 𝑆𝑦𝑚𝑚𝑒𝑡𝑟𝑦: (−1)
𝑦 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: 3
𝑂𝑝𝑒𝑛𝑠 𝑑𝑜𝑤𝑛𝑤𝑎𝑟𝑑
𝑥 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: −3 𝑎𝑛𝑑 1
𝑅𝑎𝑛𝑔𝑒: 𝑦 𝑦 ≤ 4
𝐷𝑜𝑚𝑎𝑖𝑛: 𝑎𝑙𝑙 𝑟𝑒𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠
EXAMPLE 3. Draw the graph of the quadratic
function.
𝑦 = (𝑥 − 2)2
− 4
𝑭𝒊𝒏𝒅 𝒕𝒉𝒆 𝒗𝒆𝒓𝒕𝒆𝒙.
𝒉 = 𝟐 𝒌 = −𝟒
𝑽𝒆𝒓𝒕𝒆𝒙: (2, −4)
𝒇 𝒙 = 𝒂(𝒙 − 𝒉)𝟐
+ 𝒌
𝑦 = (𝑥 − 2)2
− 4
x
y
2
−𝟒
1
0 3 𝟒
−3
𝟎 −3 𝟎
𝒙 = 𝟏
𝑦 = (−1)2
− 4
𝑓 𝑥 = −3
𝒙 = 𝟎
𝑓 𝑥 = 0
𝒙 = 𝟑
𝑓 𝑥 = −3
𝒙 = 𝟒
𝑓 𝑥 = 0
𝑦 = (𝑥 − 2)2
− 4
𝑦 = (1 − 2)2
− 4
𝑦 = (−2)2
− 4
𝑦 = (0 − 2)2
− 4
𝑦 = (1)2
− 4
𝑦 = (3 − 2)2
− 4
𝑦 = (2)2
− 4
𝑦 = (4 − 2)2
− 4
(𝟒, 𝟎)
𝑦 = (𝑥 − 2)2
− 4
𝑣𝑒𝑟𝑡𝑒𝑥: (2, −4)
(𝟏, −𝟑)
(𝟎, 𝟎)
(𝟑, −𝟑)
(𝟐, −𝟒)
𝐴𝑥𝑖𝑠 𝑜𝑓 𝑆𝑦𝑚𝑚𝑒𝑡𝑟𝑦: (2)
𝑦 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: 0
𝑂𝑝𝑒𝑛𝑠 𝑢𝑝𝑤𝑎𝑟𝑑
𝑥 − 𝑖𝑛𝑡𝑒𝑟𝑐𝑒𝑝𝑡: 0 𝑎𝑛𝑑 4
𝑅𝑎𝑛𝑔𝑒: 𝑦 𝑦 ≥ −4
𝐷𝑜𝑚𝑎𝑖𝑛: 𝑎𝑙𝑙 𝑟𝑒𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟𝑠
x
y
2
−𝟒
1
0 3 𝟒
−3
𝟎 −3 𝟎
Generate a table of values and graph each quadratic functions and
determine the vertex, axis of symmetry, y- and x- intercepts, maximum
or minimum value, opening of parabola, range, and domain.
NOTE: Use GRAPHING PAPER for your graph and other
paper for the table of values.
1. 𝒚 = 𝒙𝟐 + 𝒙 − 𝟒
2. 𝒚 = 𝒙𝟐
− 𝟑𝒙 − 𝟒
3. 𝒚 = 𝟐(𝒙 − 𝟏)𝟐 + 𝟑
4. 𝒚 = (𝒙 − 𝟑)𝟐 + 𝟐