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Jordanian Synchrotron Roof Truss
Prof. Dr. Yasser Al-Hunaiti
Contents
Project Description
Truss Analysis
Truss Design
Truss connections
Project Description
Synchrotron Project
• The structure consists of main three-dimensional spine truss and Ratt type
secondary trusses of 1.50m module to receive the roof purlins at the same
locations at 7.5m bays.
• The building is of 60x60m dimensions resting on reinforced concrete column
framing.
• All trusses are to be free in horizontal movement to prevent any secondary
trusses being developed by thermal or any other secondary effects.
• The buildings is to be equipped with an electrical over-head 10.0-ton crane
resting on 3-rails, one at either one of two alternative location on the spine truss
and the remote ends on concrete corbels to be cast as part of the concrete
columns.
Loads
• DL: Dead load is estimated as self-weight.
• SL: Snow load as alternate to the (Live Load) has been specified at
175kg/m2 (1.75kN/m2) for increased safety due to the importance of the
structure.
• CL: Crane load is taken as 10.0-ton (100kN) Payload capacity.
Truss Analysis
Analysis Procedure
• First of all, analysis of the secondary trusses was applied (secondary
trusses were taken as separated units considering connections with the
main truss are supports i.e. without the effect of the main truss); in order
to transfer forces from secondary trusses to the main truss through
connections (forces here are the external forces supported by these trusses
and members’ own weights). Action and reaction principle is applied.
• Through the analysis of the secondary trusses the following is applied:
1. Reactions were calculated by assuming sections for truss members and
sections for the purlins above (sections are assumed compared to the
previous design), in addition to the external loads (snow load) which are
considered as the loads that are supported by the columns (supports).
2. Members weights were transferred equally (1/2 of member weight.) to
each joints holding every member.
Analysis Procedure
3. Loads were multiplied by factors in order to achieve the ultimate
design loads (1.6 L.L and 1.2 D.L).
4. Reactions were calculated using structural analysis methods.
5. Connections between main and secondary trusses were considered to
be reactions.
• After the analysis of the secondary trusses was completed, analysis of the
main truss was performed considering instead-of-connections forces to be
the main forces affecting the main truss.
• Reactions must be calculated first to begin the analysis of the main truss
(using structural analysis methods). Here a computer program was used
to calculate them (Staad Pro software).
Analysis Example
𝑂𝑤𝑛 𝑊𝑒𝑖𝑔ℎ𝑡 = 5.8125 + 1.77 + 3.36 + 1.876 + 3.153 = 15.97𝑘𝑁
𝐷𝐿 = 1.2 ∗ 15.97 = 19.2𝑘𝑁
∑𝐹𝑦 = 0;
−456 − 19.2 + 1735.4 sin 51.3 + 𝐹53 ∗
6
6.7
= 0
𝐹53 = −981.5𝑘𝑁
∑𝐹𝑥 = 0;
1081 − 1318 + 1735.4 cos 51.3 ∗
3
4.8
+ 𝐹52 ∗
6
7.08
− 981.5
3
6.7
= 0
𝐹52 = −2𝑘𝑁
∑𝐹𝑍 = 0;
−2 ∗
3.75
7.08
+ 29.6 − 1735.4 cos 51.3 ∗
3.75
4.8
+ 𝐹54 = 0
𝐹54 = 819.2𝑘𝑁
Truss Design
Design Procedure
Design of Tension Members:
• The selection of members to support given tension loads is described. Although the
designer has considerable freedom in the selection the resulting members should
have the following properties:
1. Compactness.
2. Dimensions that fit into the structure with reasonable relation to the
dimensions of the other member of the structure.
3. Connections to as many parts of sections as possible to minimize shear lag.
• The type of connections used for the structure often affects the choice of member
type. Some steel section are not very convenient to bolt together with the required
gusset or connection plates, while the same section may be welded together with
little difficulty. Tension members consisting of angles, channels, and W and S
section will probably be used when the connections are made with bolts, while
plates channels, and structural tees might be used for welded structures.
Design Procedure
Design of Tension Members:
• The slenderness ratio of a member is the ratio of its unsupported length to its
least radius of gyration. Steel specifications give preferable maximum values of
slenderness ratios for both tension and compression members. The purpose of such
limitations for tension members is to ensure the use of section with stiffness
sufficient to prevent undesirable lateral deflection or vibrations. Although tension
members are not subject to buckling under normal loads, stress reversal may
occur during shipping and erection and perhaps due to wind or earthquake loads.
Specifications usually recommend that slenderness ratios be kept below certain
maximum values in order that some minimum compressive strengths be provided
in the members. For tension members other than rods, the ASIC Specification does
not provide a maximum slenderness ratio for tension members, but Section D.1 of
the specification suggests that a maximum value of 300 be used.
Design Procedure
Design of Compression Members:
• The designs of several axially columns are presented. Included are the selections
of single shapes, W sections with cover plates, and built-up sections constructed
with channels. Also included are the designs of sections whose unbraced lengths in
the x and y directions are different, as well as the sizing of lacing and tie plates for
built-up sections with open sides. Another topic that is introduced is flexural
torsional buckling of sections.
• The design of columns by formulas involves a trial-and-error process. The LRFD
design stress ɸ F and the ASD allowable stress F/Ω are not known until a column
size is selected, and vice versa. A column size may be assumed, the R-values for
that section obtained from the Manual or calculated, and the design stress found
by substituting into the appropriate column formula. It may then be necessary to
try a larger or smaller section.
Design of Compression members Example
𝐹 𝑚𝑎𝑥 = 2174𝑘𝑁 = 488.73𝑘𝑖𝑝𝑠
𝐿 = 3.35𝑚 = 10.99𝑓𝑡 = 11𝑓𝑡
From AISC. table 4-1 select section (based on KL)
Try (𝑊14 × 53)
𝐾𝐿
𝑟
=
1 ∗ 11 ∗ 12
1.92
= 68.75 < 200 ⟹ 𝑂𝑘
From ASIC. table 4-22
𝜙𝐹𝑐𝑟 = 32.025𝑘𝑠𝑖
𝐴 𝑔 =
𝑃𝑢
𝜙𝐹𝑐𝑟
=
488.73
32.025
= 15.26𝑖𝑛2
< 15.6𝑖𝑛2
⟹ 𝑂𝑘
Weight Check:
𝑊𝑒𝑖𝑔ℎ𝑡 = 53
𝑘𝑖𝑝𝑠
1000𝑓𝑡
∗ 3.28
𝑓𝑡
𝑚
∗ 4.448
𝑘𝑁
𝑘𝑖𝑝𝑠
= 0.773
𝑘𝑁
𝑚
< 1.12
𝑘𝑁
𝑚
⟹ 𝑂𝑘
Use 𝑊14 × 53
𝑊14 ∗ 53
𝐴 𝑔 = 15.6𝑖𝑛2
𝐴 𝑒 = 11.7𝑖𝑛2
𝑟 𝑚𝑖𝑛 = 1.92
Design of Tension members Example
𝐹𝑚𝑎𝑥 = 2468𝑘𝑁 = 554𝑘𝑖𝑝𝑠
𝐿 = 7.69𝑚 = 25.23𝑓𝑡
𝐴𝑠𝑠𝑢𝑚𝑒 𝑏𝑜𝑙𝑡 𝑑𝑖𝑎𝑚𝑒𝑡𝑒𝑟 = 7/8𝑖𝑛
𝐴𝑠𝑠𝑢𝑚𝑒 𝐴 𝑒 = 0.75𝐴 𝑔
𝐴 𝑔 =
𝑃𝑢
0.9𝐹𝑦
=
554
0.9 ∗ 50
= 12.31𝑖𝑛2
All W14. Sections that have 𝐴 𝑔 = 12.31𝑖𝑛2 or more have
(𝑡𝑓 ≥ 0.530𝑖𝑛)
𝐴 𝑔−𝑚𝑖𝑛 =
𝑃𝑢
𝜙 ∗ 𝑈 ∗ 𝐹𝑦
+ 𝑒𝑠𝑡𝑖𝑚𝑎𝑡𝑒𝑑 𝑏𝑜𝑙𝑡𝑠 𝑎𝑟𝑒𝑎
=
554
0.75 ∗ 0.9 ∗ 65
+ 4 ∗
7
8
+
1
8
∗ 0.53 = 14.75𝑖𝑛2
⟹⟹ 𝐴 𝑔 = 14.75𝑖𝑛2
Design of Tension members Example
𝑊14 ∗ 53
𝐴 𝑔 = 15.6𝑖𝑛2
𝐴 𝑒 = 11.7𝑖𝑛2
𝑟 𝑚𝑖𝑛 = 1.92
From AISC. table 1-1 select section (based on gross area)
Try (𝑊14 ∗ 53)
Yielding Check:
𝜙𝑃𝑛 = 𝜙𝐹𝑦 𝐴 𝑔 = 0.9 ∗ 50 ∗ 15.6 = 702𝑘𝑖𝑝𝑠 > 554𝑘𝑖𝑝𝑠 ⟹ 𝑂𝑘
Rupture Check:
𝜙𝑃𝑛 = 𝜙𝐹𝑢 𝐴 𝑒 = 0.75 ∗ 65 ∗ 11.7 = 570.375𝑘𝑖𝑝𝑠 > 554𝑘𝑖𝑝𝑠
⟹ 𝑂𝑘
Slenderness Ratio Check:
𝐿
𝑟
=
25.23 ∗ 12
1.92
= 157.69 < 300 ⟹ 𝑂𝑘
Weight Check:
𝑊𝑒𝑖𝑔ℎ𝑡 = 53
𝑘𝑖𝑝𝑠
1000𝑓𝑡
∗ 3.28
𝑓𝑡
𝑚
∗ 4.448
𝑘𝑁
𝑘𝑖𝑝𝑠
= 0.773
𝑘𝑁
𝑚
< 1.12
𝑘𝑁
𝑚
⟹ 𝑂𝑘
Use 𝑊14 × 53
Truss Connections
Connection Procedure
• There are, in general, two types of connections, one is bearing type connection and
the second is slip critical connection.
• The design of a connection means both, to determine the number of bolts in that
connection and to determine the spacing between those bolts (bolt-to-bolt spacing
and edge spacing).
• To determine the number of bolts, one must first assume the diameter and the
type of bolts to be used.
• Based on the diameter and the type of bolts, the capacity of each bolt can be
determined in each shear, tension, and slipping.
• After that, number of bolts can be determined by dividing the maximum applied
force on the least capacity of the bolt i.e. shear, tension, and slipping capacities.
Connection Procedure
• When the number of the bolts is determined, the spacing can be determined based
on bearing capacity i.e. by choosing edge and bolt-to-bolt spacing to be between the
minimum and maximum spacing, then checking if those spacing will give the
required capacity to support the entire maximum applied load.
Minimum edge spacing Le-min (table J3-4 AISC code).
Maximum edge spacing Le-max = 12t or 6 inches whichever is less.
Minimum bolt-bolt spacing Smin = 2.667d but 3d is preferable
Maximum bolt-bolt spacing Smax = 24t or 12 inches whichever is less. (For
protective bolts)
• Bearing capacity /bolt -------- 𝜙𝑅 𝑛 = 𝜙1.2𝐿 𝑐 𝑡𝐹𝑢 or ϕ2.4dtF_u whichever is less.
Done By:
Ahmed Hammad Hamzeh Al-Khalailah
Qusai Al-Qudah Mohammad Al-Ghzawi

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Graduation project presentation

  • 1. Jordanian Synchrotron Roof Truss Prof. Dr. Yasser Al-Hunaiti
  • 4. Synchrotron Project • The structure consists of main three-dimensional spine truss and Ratt type secondary trusses of 1.50m module to receive the roof purlins at the same locations at 7.5m bays. • The building is of 60x60m dimensions resting on reinforced concrete column framing. • All trusses are to be free in horizontal movement to prevent any secondary trusses being developed by thermal or any other secondary effects. • The buildings is to be equipped with an electrical over-head 10.0-ton crane resting on 3-rails, one at either one of two alternative location on the spine truss and the remote ends on concrete corbels to be cast as part of the concrete columns.
  • 5.
  • 6. Loads • DL: Dead load is estimated as self-weight. • SL: Snow load as alternate to the (Live Load) has been specified at 175kg/m2 (1.75kN/m2) for increased safety due to the importance of the structure. • CL: Crane load is taken as 10.0-ton (100kN) Payload capacity.
  • 7.
  • 9. Analysis Procedure • First of all, analysis of the secondary trusses was applied (secondary trusses were taken as separated units considering connections with the main truss are supports i.e. without the effect of the main truss); in order to transfer forces from secondary trusses to the main truss through connections (forces here are the external forces supported by these trusses and members’ own weights). Action and reaction principle is applied. • Through the analysis of the secondary trusses the following is applied: 1. Reactions were calculated by assuming sections for truss members and sections for the purlins above (sections are assumed compared to the previous design), in addition to the external loads (snow load) which are considered as the loads that are supported by the columns (supports). 2. Members weights were transferred equally (1/2 of member weight.) to each joints holding every member.
  • 10. Analysis Procedure 3. Loads were multiplied by factors in order to achieve the ultimate design loads (1.6 L.L and 1.2 D.L). 4. Reactions were calculated using structural analysis methods. 5. Connections between main and secondary trusses were considered to be reactions. • After the analysis of the secondary trusses was completed, analysis of the main truss was performed considering instead-of-connections forces to be the main forces affecting the main truss. • Reactions must be calculated first to begin the analysis of the main truss (using structural analysis methods). Here a computer program was used to calculate them (Staad Pro software).
  • 11. Analysis Example 𝑂𝑤𝑛 𝑊𝑒𝑖𝑔ℎ𝑡 = 5.8125 + 1.77 + 3.36 + 1.876 + 3.153 = 15.97𝑘𝑁 𝐷𝐿 = 1.2 ∗ 15.97 = 19.2𝑘𝑁 ∑𝐹𝑦 = 0; −456 − 19.2 + 1735.4 sin 51.3 + 𝐹53 ∗ 6 6.7 = 0 𝐹53 = −981.5𝑘𝑁 ∑𝐹𝑥 = 0; 1081 − 1318 + 1735.4 cos 51.3 ∗ 3 4.8 + 𝐹52 ∗ 6 7.08 − 981.5 3 6.7 = 0 𝐹52 = −2𝑘𝑁 ∑𝐹𝑍 = 0; −2 ∗ 3.75 7.08 + 29.6 − 1735.4 cos 51.3 ∗ 3.75 4.8 + 𝐹54 = 0 𝐹54 = 819.2𝑘𝑁
  • 13. Design Procedure Design of Tension Members: • The selection of members to support given tension loads is described. Although the designer has considerable freedom in the selection the resulting members should have the following properties: 1. Compactness. 2. Dimensions that fit into the structure with reasonable relation to the dimensions of the other member of the structure. 3. Connections to as many parts of sections as possible to minimize shear lag. • The type of connections used for the structure often affects the choice of member type. Some steel section are not very convenient to bolt together with the required gusset or connection plates, while the same section may be welded together with little difficulty. Tension members consisting of angles, channels, and W and S section will probably be used when the connections are made with bolts, while plates channels, and structural tees might be used for welded structures.
  • 14. Design Procedure Design of Tension Members: • The slenderness ratio of a member is the ratio of its unsupported length to its least radius of gyration. Steel specifications give preferable maximum values of slenderness ratios for both tension and compression members. The purpose of such limitations for tension members is to ensure the use of section with stiffness sufficient to prevent undesirable lateral deflection or vibrations. Although tension members are not subject to buckling under normal loads, stress reversal may occur during shipping and erection and perhaps due to wind or earthquake loads. Specifications usually recommend that slenderness ratios be kept below certain maximum values in order that some minimum compressive strengths be provided in the members. For tension members other than rods, the ASIC Specification does not provide a maximum slenderness ratio for tension members, but Section D.1 of the specification suggests that a maximum value of 300 be used.
  • 15. Design Procedure Design of Compression Members: • The designs of several axially columns are presented. Included are the selections of single shapes, W sections with cover plates, and built-up sections constructed with channels. Also included are the designs of sections whose unbraced lengths in the x and y directions are different, as well as the sizing of lacing and tie plates for built-up sections with open sides. Another topic that is introduced is flexural torsional buckling of sections. • The design of columns by formulas involves a trial-and-error process. The LRFD design stress ɸ F and the ASD allowable stress F/Ω are not known until a column size is selected, and vice versa. A column size may be assumed, the R-values for that section obtained from the Manual or calculated, and the design stress found by substituting into the appropriate column formula. It may then be necessary to try a larger or smaller section.
  • 16. Design of Compression members Example 𝐹 𝑚𝑎𝑥 = 2174𝑘𝑁 = 488.73𝑘𝑖𝑝𝑠 𝐿 = 3.35𝑚 = 10.99𝑓𝑡 = 11𝑓𝑡 From AISC. table 4-1 select section (based on KL) Try (𝑊14 × 53) 𝐾𝐿 𝑟 = 1 ∗ 11 ∗ 12 1.92 = 68.75 < 200 ⟹ 𝑂𝑘 From ASIC. table 4-22 𝜙𝐹𝑐𝑟 = 32.025𝑘𝑠𝑖 𝐴 𝑔 = 𝑃𝑢 𝜙𝐹𝑐𝑟 = 488.73 32.025 = 15.26𝑖𝑛2 < 15.6𝑖𝑛2 ⟹ 𝑂𝑘 Weight Check: 𝑊𝑒𝑖𝑔ℎ𝑡 = 53 𝑘𝑖𝑝𝑠 1000𝑓𝑡 ∗ 3.28 𝑓𝑡 𝑚 ∗ 4.448 𝑘𝑁 𝑘𝑖𝑝𝑠 = 0.773 𝑘𝑁 𝑚 < 1.12 𝑘𝑁 𝑚 ⟹ 𝑂𝑘 Use 𝑊14 × 53 𝑊14 ∗ 53 𝐴 𝑔 = 15.6𝑖𝑛2 𝐴 𝑒 = 11.7𝑖𝑛2 𝑟 𝑚𝑖𝑛 = 1.92
  • 17. Design of Tension members Example 𝐹𝑚𝑎𝑥 = 2468𝑘𝑁 = 554𝑘𝑖𝑝𝑠 𝐿 = 7.69𝑚 = 25.23𝑓𝑡 𝐴𝑠𝑠𝑢𝑚𝑒 𝑏𝑜𝑙𝑡 𝑑𝑖𝑎𝑚𝑒𝑡𝑒𝑟 = 7/8𝑖𝑛 𝐴𝑠𝑠𝑢𝑚𝑒 𝐴 𝑒 = 0.75𝐴 𝑔 𝐴 𝑔 = 𝑃𝑢 0.9𝐹𝑦 = 554 0.9 ∗ 50 = 12.31𝑖𝑛2 All W14. Sections that have 𝐴 𝑔 = 12.31𝑖𝑛2 or more have (𝑡𝑓 ≥ 0.530𝑖𝑛) 𝐴 𝑔−𝑚𝑖𝑛 = 𝑃𝑢 𝜙 ∗ 𝑈 ∗ 𝐹𝑦 + 𝑒𝑠𝑡𝑖𝑚𝑎𝑡𝑒𝑑 𝑏𝑜𝑙𝑡𝑠 𝑎𝑟𝑒𝑎 = 554 0.75 ∗ 0.9 ∗ 65 + 4 ∗ 7 8 + 1 8 ∗ 0.53 = 14.75𝑖𝑛2 ⟹⟹ 𝐴 𝑔 = 14.75𝑖𝑛2
  • 18. Design of Tension members Example 𝑊14 ∗ 53 𝐴 𝑔 = 15.6𝑖𝑛2 𝐴 𝑒 = 11.7𝑖𝑛2 𝑟 𝑚𝑖𝑛 = 1.92 From AISC. table 1-1 select section (based on gross area) Try (𝑊14 ∗ 53) Yielding Check: 𝜙𝑃𝑛 = 𝜙𝐹𝑦 𝐴 𝑔 = 0.9 ∗ 50 ∗ 15.6 = 702𝑘𝑖𝑝𝑠 > 554𝑘𝑖𝑝𝑠 ⟹ 𝑂𝑘 Rupture Check: 𝜙𝑃𝑛 = 𝜙𝐹𝑢 𝐴 𝑒 = 0.75 ∗ 65 ∗ 11.7 = 570.375𝑘𝑖𝑝𝑠 > 554𝑘𝑖𝑝𝑠 ⟹ 𝑂𝑘 Slenderness Ratio Check: 𝐿 𝑟 = 25.23 ∗ 12 1.92 = 157.69 < 300 ⟹ 𝑂𝑘 Weight Check: 𝑊𝑒𝑖𝑔ℎ𝑡 = 53 𝑘𝑖𝑝𝑠 1000𝑓𝑡 ∗ 3.28 𝑓𝑡 𝑚 ∗ 4.448 𝑘𝑁 𝑘𝑖𝑝𝑠 = 0.773 𝑘𝑁 𝑚 < 1.12 𝑘𝑁 𝑚 ⟹ 𝑂𝑘 Use 𝑊14 × 53
  • 20. Connection Procedure • There are, in general, two types of connections, one is bearing type connection and the second is slip critical connection. • The design of a connection means both, to determine the number of bolts in that connection and to determine the spacing between those bolts (bolt-to-bolt spacing and edge spacing). • To determine the number of bolts, one must first assume the diameter and the type of bolts to be used. • Based on the diameter and the type of bolts, the capacity of each bolt can be determined in each shear, tension, and slipping. • After that, number of bolts can be determined by dividing the maximum applied force on the least capacity of the bolt i.e. shear, tension, and slipping capacities.
  • 21. Connection Procedure • When the number of the bolts is determined, the spacing can be determined based on bearing capacity i.e. by choosing edge and bolt-to-bolt spacing to be between the minimum and maximum spacing, then checking if those spacing will give the required capacity to support the entire maximum applied load. Minimum edge spacing Le-min (table J3-4 AISC code). Maximum edge spacing Le-max = 12t or 6 inches whichever is less. Minimum bolt-bolt spacing Smin = 2.667d but 3d is preferable Maximum bolt-bolt spacing Smax = 24t or 12 inches whichever is less. (For protective bolts) • Bearing capacity /bolt -------- 𝜙𝑅 𝑛 = 𝜙1.2𝐿 𝑐 𝑡𝐹𝑢 or ϕ2.4dtF_u whichever is less.
  • 22. Done By: Ahmed Hammad Hamzeh Al-Khalailah Qusai Al-Qudah Mohammad Al-Ghzawi