1) The document discusses fluid static forces on plane and curved surfaces including the magnitude and direction of forces, and the location of the center of pressure.
2) Hydrostatic forces are calculated based on pressure distributions and properties of the surface area and fluid properties like density.
3) The center of pressure is found by calculating the first moment of area of the pressure distribution and does not necessarily coincide with the geometric center.
1. Fluid static forces act on surfaces exposed to fluids due to pressure distributions in the fluid. The magnitude and direction of these forces depend on factors like the surface geometry, depth of submergence, and fluid properties.
2. Hydrostatic forces can be resolved into vertical and horizontal components, with the vertical force equal to the weight of the displaced fluid. The location of the center of pressure determines the line of action of the resultant force.
3. For regular shapes, equations are provided to calculate the hydrostatic forces and location of the center of pressure based on the surface dimensions and submergence depth. Examples of applying these concepts to dams, gates, and curved surfaces are also presented.
1) The document discusses fluid static forces including hydrostatic forces on plane, inclined, vertical, and curved surfaces. It provides equations to calculate the magnitude and direction of forces.
2) The direction of force is not always through the center of gravity. On inclined surfaces, the center of pressure lies below the centroid. On curved surfaces, the resultant force passes through the center of curvature.
3) Examples are given for calculating hydrostatic forces on dams, walls, gates, and other structures exposed to fluid pressures. Diagrams illustrate free body diagrams and problem setups.
This document discusses fluid static forces and hydrostatic pressure. It begins by explaining that in a fluid at rest, pressure acts equally in all directions and where a fluid contacts a surface, the pressure gives rise to a force perpendicular to the surface. It also discusses how pressure increases with depth according to ρgh. The document then examines hydrostatic forces on various plane and curved surfaces, explaining how to calculate the magnitude and direction of forces on surfaces like inclined planes, vertical walls, and curved boundaries. It provides equations for calculating forces and locating centers of pressure on submerged objects.
1. Determine the volume of fluid above the curved surface and its weight
2. The vertical force equals the weight and acts through the volume's centroid
3. Project the curved surface onto a vertical plane and determine its height and centroid depth
4. The horizontal force magnitude equals the projected area weight and acts at the projected area centroid depth
5. The resultant force is the vector sum of the horizontal and vertical forces and acts through the surface's center of curvature.
The document discusses hydrostatic forces on submerged plane surfaces. It provides analytical and graphical (prism) methods to calculate the total hydrostatic force and location of the center of pressure. As an example, it applies both methods to calculate the force on a submerged car door located 8 meters below the water surface. The analytical method yields a force of 101.24 kN and center of pressure at 0.144 meters above the bottom of the door. The prism method gives a force of 176.94 kN and center of pressure at 2.1 meters above the bottom.
This document discusses fluid statics and hydrostatic forces. It defines key terms like resultant force, center of pressure, and explains how to calculate them for surfaces with non-uniform pressure distributions. Specific examples are given for calculating the resultant force and center of pressure on a submerged rectangular plate and for curved surfaces. Forces on a cylindrical gate hinged at one end are also analyzed.
This document discusses several key fluid mechanics concepts:
- Pressure and hydrostatic pressure calculations
- Determining the center of pressure and resultant force on submerged surfaces
- Archimedes' principle of buoyancy
- Stability of floating bodies
- The Bernoulli equation relating pressure, velocity, and elevation
- The continuity equation equating mass flow in and out of a system
The document discusses hydrostatic forces on surfaces submerged in fluids. It defines fluid statics as dealing with fluids at rest, where the only stress is normal stress due to pressure variations from fluid weight. It describes how to calculate the resultant force and center of pressure on plane and curved surfaces for non-uniform pressures. For a plane surface, the resultant force is the pressure at the centroid multiplied by the area. The center of pressure is found by equating moments. Examples are provided to demonstrate these calculations for rectangular plates and cylindrical gates submerged in water.
1. Fluid static forces act on surfaces exposed to fluids due to pressure distributions in the fluid. The magnitude and direction of these forces depend on factors like the surface geometry, depth of submergence, and fluid properties.
2. Hydrostatic forces can be resolved into vertical and horizontal components, with the vertical force equal to the weight of the displaced fluid. The location of the center of pressure determines the line of action of the resultant force.
3. For regular shapes, equations are provided to calculate the hydrostatic forces and location of the center of pressure based on the surface dimensions and submergence depth. Examples of applying these concepts to dams, gates, and curved surfaces are also presented.
1) The document discusses fluid static forces including hydrostatic forces on plane, inclined, vertical, and curved surfaces. It provides equations to calculate the magnitude and direction of forces.
2) The direction of force is not always through the center of gravity. On inclined surfaces, the center of pressure lies below the centroid. On curved surfaces, the resultant force passes through the center of curvature.
3) Examples are given for calculating hydrostatic forces on dams, walls, gates, and other structures exposed to fluid pressures. Diagrams illustrate free body diagrams and problem setups.
This document discusses fluid static forces and hydrostatic pressure. It begins by explaining that in a fluid at rest, pressure acts equally in all directions and where a fluid contacts a surface, the pressure gives rise to a force perpendicular to the surface. It also discusses how pressure increases with depth according to ρgh. The document then examines hydrostatic forces on various plane and curved surfaces, explaining how to calculate the magnitude and direction of forces on surfaces like inclined planes, vertical walls, and curved boundaries. It provides equations for calculating forces and locating centers of pressure on submerged objects.
1. Determine the volume of fluid above the curved surface and its weight
2. The vertical force equals the weight and acts through the volume's centroid
3. Project the curved surface onto a vertical plane and determine its height and centroid depth
4. The horizontal force magnitude equals the projected area weight and acts at the projected area centroid depth
5. The resultant force is the vector sum of the horizontal and vertical forces and acts through the surface's center of curvature.
The document discusses hydrostatic forces on submerged plane surfaces. It provides analytical and graphical (prism) methods to calculate the total hydrostatic force and location of the center of pressure. As an example, it applies both methods to calculate the force on a submerged car door located 8 meters below the water surface. The analytical method yields a force of 101.24 kN and center of pressure at 0.144 meters above the bottom of the door. The prism method gives a force of 176.94 kN and center of pressure at 2.1 meters above the bottom.
This document discusses fluid statics and hydrostatic forces. It defines key terms like resultant force, center of pressure, and explains how to calculate them for surfaces with non-uniform pressure distributions. Specific examples are given for calculating the resultant force and center of pressure on a submerged rectangular plate and for curved surfaces. Forces on a cylindrical gate hinged at one end are also analyzed.
This document discusses several key fluid mechanics concepts:
- Pressure and hydrostatic pressure calculations
- Determining the center of pressure and resultant force on submerged surfaces
- Archimedes' principle of buoyancy
- Stability of floating bodies
- The Bernoulli equation relating pressure, velocity, and elevation
- The continuity equation equating mass flow in and out of a system
The document discusses hydrostatic forces on surfaces submerged in fluids. It defines fluid statics as dealing with fluids at rest, where the only stress is normal stress due to pressure variations from fluid weight. It describes how to calculate the resultant force and center of pressure on plane and curved surfaces for non-uniform pressures. For a plane surface, the resultant force is the pressure at the centroid multiplied by the area. The center of pressure is found by equating moments. Examples are provided to demonstrate these calculations for rectangular plates and cylindrical gates submerged in water.
The document discusses hydrostatic forces on surfaces submerged in fluids. It defines fluid statics as dealing with fluids at rest, where the only stress is normal stress due to pressure variations from fluid weight. It describes how to calculate the resultant force and center of pressure on plane and curved surfaces for non-uniform pressure distributions. For a rectangular plate, the resultant force is the pressure at the centroid multiplied by the area, and the center of pressure is below the centroid. Examples are provided to demonstrate calculating these values.
hydrostatic presssure force on planer surface and curved surface.pptxNobelHassan
This document discusses hydrostatic forces on submerged bodies and plane surfaces. It defines key terms like hydrostatic force, center of pressure, and centroid. It provides formulas to calculate the total force on a submerged plane area and the location of its center of pressure. Sample problems are worked through applying these formulas to find the magnitude of force and depth/location of the center of pressure for various shapes when submerged in water.
This document discusses hydrostatic forces on surfaces, including:
1. Forces act perpendicular to surfaces submerged in fluid.
2. Forces on plane surfaces can be calculated based on pressure, area, and depth. Center of pressure is below the geometric center.
3. Forces on curved surfaces are resolved into horizontal and vertical components based on the surface orientation at each point.
Allen t chwang hydrodynamic pressures on sloping dams during earthquakesjumadilsyam
1) Von Karmán's momentum-balance method is used to analyze earthquake forces on rigid dams with inclined upstream faces of constant slope.
2) It is found that the maximum hydrodynamic pressure always occurs at the base of the dam, regardless of the inclination angle.
3) Explicit formulas are presented to evaluate the total horizontal, vertical, and normal loads on the dam based on the inclination angle and reservoir depth.
Chapter 3 static forces on surfaces [compatibility mode]imshahbaz
1) The document discusses forces on submerged surfaces due to static fluids, including calculating hydrostatic pressures and determining the resultant force and center of pressure.
2) It provides methods for calculating the resultant force on plane and curved surfaces, including using pressure diagrams which graphically represent pressure changes with depth.
3) Examples are given for determining pressures, resultant forces, and centers of pressure on surfaces like vertical walls and combinations of liquids in tanks.
This document contains instructions for 6 experiments on fluid mechanics. Experiment 1 involves measuring the center of pressure on a submerged vertical surface. Experiment 2 determines the metacentric height of a floating body under different loading conditions. Experiment 3 verifies Bernoulli's theorem by measuring pressure and velocity changes in flowing water. Experiment 4 examines the impact of a jet. Experiments 5 and 6 involve flow measurement using Venturi meters and broad-crested weirs, respectively. The experiments provide practical demonstrations of key concepts in fluid mechanics.
This document contains diagrams and equations related to fluid mechanics concepts such as:
- Pressure variations in fluids undergoing acceleration or rigid body rotation
- Free surface profiles and pressure distributions in fluids in rotating or accelerated containers
- Equations relating pressure, depth, acceleration/rotation, and density for both static and dynamic fluid situations
This document discusses hydrostatic forces on surfaces. It defines total pressure and center of pressure, and covers hydrostatic forces on three types of surfaces:
1) Plane surfaces, including horizontally immersed, vertically immersed, and inclined surfaces. The center of pressure is below the centroid for vertical surfaces.
2) Curved surfaces, where forces must be resolved into horizontal and vertical components since the direction of force varies by point.
3) Concepts of translating and rotating fluid masses are also introduced.
This document summarizes key concepts from Chapter 2 on fluid statics. It discusses static pressure and its characteristics, including that pressure is perpendicular to the surface and the same in all directions at a point. It presents the basic equation of fluid statics and hydrostatics under gravity. It also covers isobaric surfaces, units of pressure measurement, and the relationships between different pressure types such as absolute, gauge, and vacuum pressures.
Unit 4 Part 1 power point presentation ofssuserd7b2f1
This document provides an overview of open channel flow. It begins by defining open channel flow as flow with a free surface that flows due to gravity, such as in partially full pipes. It then describes the main types of open channel flows as steady or unsteady, uniform or non-uniform, laminar or turbulent, and subcritical, critical, or supercritical. The document also discusses the geometric elements of open channel sections, including depth, top width, area, perimeter, and hydraulic radius. It concludes by covering velocity distribution and common formulas used to calculate discharge in open channels, such as Chezy's and Manning's equations.
1) The document discusses various equations and concepts in hydraulics including the continuity equation, Bernoulli's equation, conservation of momentum, uniform flow in open channels, and Manning's formula.
2) The continuity equation states that the mass of fluid passing per unit time through an area is equal to the product of the flow velocity and cross-sectional area.
3) Bernoulli's equation relates the total energy of flowing water through different cross-sections in terms of pressure, elevation, and velocity.
1) Bernoulli's equation is applied to analyze flow through orifices. It relates the pressure, velocity, and elevation of a fluid flowing through an orifice.
2) For a sharp-edged orifice, the diameter of the jet is less than the diameter of the hole due to the vena contracta effect.
3) Pumps and turbines can be analyzed using Bernoulli's equation to relate input power to output power and efficiency. Head, flow rate, and losses are considered.
This document provides an overview of hydrostatics and the concepts of total pressure, center of pressure, and hydrostatic force on immersed surfaces. It discusses the total pressure on horizontally, vertically, and inclined immersed surfaces. It describes how to calculate the center of pressure on vertically and inclined immersed surfaces. The document also discusses hydrostatic force on curved surfaces and some applications of hydrostatics, such as water pressure on sluice gates.
This presentation introduces concepts of hydrostatics including total pressure on immersed surfaces, center of pressure, and applications. Total pressure on a surface depends on its orientation (horizontal, vertical, inclined) and is calculated by integrating pressure over small elements. The center of pressure is the point where the total pressure force acts and can be found using the theorem of parallel axis. Examples of hydrostatics applications discussed are water pressure on structures like sluice gates, lock gates, and masonry walls. Conditions for stability of dams are also outlined.
This document provides a 3-paragraph summary of a course on hydraulics:
The course is titled "Hydraulics II" with course number CEng2152. It is a 5 ECTS credit degree program course focusing on open channel flow. Open channel flow occurs when water flows with a free surface exposed to the atmosphere, such as in rivers, culverts and spillways. Engineering structures for open channel flow are designed and analyzed using open channel hydraulics.
The document covers different types of open channel flow including steady and unsteady, uniform and non-uniform flow. It also discusses the geometric elements of open channel cross-sections including depth, width, area and hydraulic radius. Uniform flow
This document reports on an experiment conducted to determine hydrostatic force and center of pressure. The objectives were to determine the hydrostatic force on a partially or fully submerged surface and to determine experimentally and theoretically the center of pressure. The method involved increasing water depth in a tank and reaching equilibrium between moments on a balance arm, with forces from a weight and hydrostatic force on a vertical surface. Results from increasing water depth in 5 increments are presented in a table.
This document discusses the equations of motion for rigid fluids subjected to different types of acceleration.
1) The general equation of motion for a rigid fluid is derived from applying Newton's second law to a small fluid element. This relates the fluid acceleration to the pressure gradient and gravitational force.
2) For specific cases of a fluid at rest, in free fall, and linearly accelerating, the pressure gradient terms in the equation are simplified.
3) For a rotating fluid contained in a cylindrical tank, the equation is derived in cylindrical coordinates and relates the radial pressure gradient to the centripetal acceleration from rotation.
This document discusses the equations of motion for rigid bodies subjected to various accelerations in fluids. It begins by deriving the general equation of motion for a rigid fluid body subjected to any acceleration. It then applies this equation to several examples:
1) A fluid at rest, where pressure is constant horizontally and varies with depth.
2) A freely falling fluid body, where pressure is constant.
3) A linearly accelerating fluid body, where lines of constant pressure slope according to the acceleration components.
4) A fluid body rotating rigidly in a cylinder, where pressure increases radially outward due to centripetal acceleration.
This document provides an overview of various branches of civil engineering including structural engineering, transportation engineering, geotechnical engineering, environmental engineering, construction management, quantity surveying, irrigation engineering, and earthquake engineering. It also discusses related topics like surveying, roads, railways, soil mechanics, fluid mechanics, and the roles of civil engineers in different construction projects. The key branches covered are structural design of buildings and bridges, transportation infrastructure like roads and railways, foundation design and geotechnical soil testing, water and wastewater management, construction planning and management, and disaster mitigation.
This document discusses fluid mechanics and hydraulics concepts including:
1. Definitions of density, specific gravity, atmospheric pressure, absolute and gauge pressure.
2. Descriptions of viscosity, laminar flow, turbulent flow, continuity equation, and steady vs unsteady flow.
3. Explanations of surface tension, capillarity, hydrostatic pressure, buoyancy, and center of pressure.
4. Discussions of manometers, energy equations, forces on submerged surfaces, and fluid static forces.
The document discusses hydrostatic forces on surfaces submerged in fluids. It defines fluid statics as dealing with fluids at rest, where the only stress is normal stress due to pressure variations from fluid weight. It describes how to calculate the resultant force and center of pressure on plane and curved surfaces for non-uniform pressure distributions. For a rectangular plate, the resultant force is the pressure at the centroid multiplied by the area, and the center of pressure is below the centroid. Examples are provided to demonstrate calculating these values.
hydrostatic presssure force on planer surface and curved surface.pptxNobelHassan
This document discusses hydrostatic forces on submerged bodies and plane surfaces. It defines key terms like hydrostatic force, center of pressure, and centroid. It provides formulas to calculate the total force on a submerged plane area and the location of its center of pressure. Sample problems are worked through applying these formulas to find the magnitude of force and depth/location of the center of pressure for various shapes when submerged in water.
This document discusses hydrostatic forces on surfaces, including:
1. Forces act perpendicular to surfaces submerged in fluid.
2. Forces on plane surfaces can be calculated based on pressure, area, and depth. Center of pressure is below the geometric center.
3. Forces on curved surfaces are resolved into horizontal and vertical components based on the surface orientation at each point.
Allen t chwang hydrodynamic pressures on sloping dams during earthquakesjumadilsyam
1) Von Karmán's momentum-balance method is used to analyze earthquake forces on rigid dams with inclined upstream faces of constant slope.
2) It is found that the maximum hydrodynamic pressure always occurs at the base of the dam, regardless of the inclination angle.
3) Explicit formulas are presented to evaluate the total horizontal, vertical, and normal loads on the dam based on the inclination angle and reservoir depth.
Chapter 3 static forces on surfaces [compatibility mode]imshahbaz
1) The document discusses forces on submerged surfaces due to static fluids, including calculating hydrostatic pressures and determining the resultant force and center of pressure.
2) It provides methods for calculating the resultant force on plane and curved surfaces, including using pressure diagrams which graphically represent pressure changes with depth.
3) Examples are given for determining pressures, resultant forces, and centers of pressure on surfaces like vertical walls and combinations of liquids in tanks.
This document contains instructions for 6 experiments on fluid mechanics. Experiment 1 involves measuring the center of pressure on a submerged vertical surface. Experiment 2 determines the metacentric height of a floating body under different loading conditions. Experiment 3 verifies Bernoulli's theorem by measuring pressure and velocity changes in flowing water. Experiment 4 examines the impact of a jet. Experiments 5 and 6 involve flow measurement using Venturi meters and broad-crested weirs, respectively. The experiments provide practical demonstrations of key concepts in fluid mechanics.
This document contains diagrams and equations related to fluid mechanics concepts such as:
- Pressure variations in fluids undergoing acceleration or rigid body rotation
- Free surface profiles and pressure distributions in fluids in rotating or accelerated containers
- Equations relating pressure, depth, acceleration/rotation, and density for both static and dynamic fluid situations
This document discusses hydrostatic forces on surfaces. It defines total pressure and center of pressure, and covers hydrostatic forces on three types of surfaces:
1) Plane surfaces, including horizontally immersed, vertically immersed, and inclined surfaces. The center of pressure is below the centroid for vertical surfaces.
2) Curved surfaces, where forces must be resolved into horizontal and vertical components since the direction of force varies by point.
3) Concepts of translating and rotating fluid masses are also introduced.
This document summarizes key concepts from Chapter 2 on fluid statics. It discusses static pressure and its characteristics, including that pressure is perpendicular to the surface and the same in all directions at a point. It presents the basic equation of fluid statics and hydrostatics under gravity. It also covers isobaric surfaces, units of pressure measurement, and the relationships between different pressure types such as absolute, gauge, and vacuum pressures.
Unit 4 Part 1 power point presentation ofssuserd7b2f1
This document provides an overview of open channel flow. It begins by defining open channel flow as flow with a free surface that flows due to gravity, such as in partially full pipes. It then describes the main types of open channel flows as steady or unsteady, uniform or non-uniform, laminar or turbulent, and subcritical, critical, or supercritical. The document also discusses the geometric elements of open channel sections, including depth, top width, area, perimeter, and hydraulic radius. It concludes by covering velocity distribution and common formulas used to calculate discharge in open channels, such as Chezy's and Manning's equations.
1) The document discusses various equations and concepts in hydraulics including the continuity equation, Bernoulli's equation, conservation of momentum, uniform flow in open channels, and Manning's formula.
2) The continuity equation states that the mass of fluid passing per unit time through an area is equal to the product of the flow velocity and cross-sectional area.
3) Bernoulli's equation relates the total energy of flowing water through different cross-sections in terms of pressure, elevation, and velocity.
1) Bernoulli's equation is applied to analyze flow through orifices. It relates the pressure, velocity, and elevation of a fluid flowing through an orifice.
2) For a sharp-edged orifice, the diameter of the jet is less than the diameter of the hole due to the vena contracta effect.
3) Pumps and turbines can be analyzed using Bernoulli's equation to relate input power to output power and efficiency. Head, flow rate, and losses are considered.
This document provides an overview of hydrostatics and the concepts of total pressure, center of pressure, and hydrostatic force on immersed surfaces. It discusses the total pressure on horizontally, vertically, and inclined immersed surfaces. It describes how to calculate the center of pressure on vertically and inclined immersed surfaces. The document also discusses hydrostatic force on curved surfaces and some applications of hydrostatics, such as water pressure on sluice gates.
This presentation introduces concepts of hydrostatics including total pressure on immersed surfaces, center of pressure, and applications. Total pressure on a surface depends on its orientation (horizontal, vertical, inclined) and is calculated by integrating pressure over small elements. The center of pressure is the point where the total pressure force acts and can be found using the theorem of parallel axis. Examples of hydrostatics applications discussed are water pressure on structures like sluice gates, lock gates, and masonry walls. Conditions for stability of dams are also outlined.
This document provides a 3-paragraph summary of a course on hydraulics:
The course is titled "Hydraulics II" with course number CEng2152. It is a 5 ECTS credit degree program course focusing on open channel flow. Open channel flow occurs when water flows with a free surface exposed to the atmosphere, such as in rivers, culverts and spillways. Engineering structures for open channel flow are designed and analyzed using open channel hydraulics.
The document covers different types of open channel flow including steady and unsteady, uniform and non-uniform flow. It also discusses the geometric elements of open channel cross-sections including depth, width, area and hydraulic radius. Uniform flow
This document reports on an experiment conducted to determine hydrostatic force and center of pressure. The objectives were to determine the hydrostatic force on a partially or fully submerged surface and to determine experimentally and theoretically the center of pressure. The method involved increasing water depth in a tank and reaching equilibrium between moments on a balance arm, with forces from a weight and hydrostatic force on a vertical surface. Results from increasing water depth in 5 increments are presented in a table.
This document discusses the equations of motion for rigid fluids subjected to different types of acceleration.
1) The general equation of motion for a rigid fluid is derived from applying Newton's second law to a small fluid element. This relates the fluid acceleration to the pressure gradient and gravitational force.
2) For specific cases of a fluid at rest, in free fall, and linearly accelerating, the pressure gradient terms in the equation are simplified.
3) For a rotating fluid contained in a cylindrical tank, the equation is derived in cylindrical coordinates and relates the radial pressure gradient to the centripetal acceleration from rotation.
This document discusses the equations of motion for rigid bodies subjected to various accelerations in fluids. It begins by deriving the general equation of motion for a rigid fluid body subjected to any acceleration. It then applies this equation to several examples:
1) A fluid at rest, where pressure is constant horizontally and varies with depth.
2) A freely falling fluid body, where pressure is constant.
3) A linearly accelerating fluid body, where lines of constant pressure slope according to the acceleration components.
4) A fluid body rotating rigidly in a cylinder, where pressure increases radially outward due to centripetal acceleration.
This document provides an overview of various branches of civil engineering including structural engineering, transportation engineering, geotechnical engineering, environmental engineering, construction management, quantity surveying, irrigation engineering, and earthquake engineering. It also discusses related topics like surveying, roads, railways, soil mechanics, fluid mechanics, and the roles of civil engineers in different construction projects. The key branches covered are structural design of buildings and bridges, transportation infrastructure like roads and railways, foundation design and geotechnical soil testing, water and wastewater management, construction planning and management, and disaster mitigation.
This document discusses fluid mechanics and hydraulics concepts including:
1. Definitions of density, specific gravity, atmospheric pressure, absolute and gauge pressure.
2. Descriptions of viscosity, laminar flow, turbulent flow, continuity equation, and steady vs unsteady flow.
3. Explanations of surface tension, capillarity, hydrostatic pressure, buoyancy, and center of pressure.
4. Discussions of manometers, energy equations, forces on submerged surfaces, and fluid static forces.
The document contains 7 practice problems for applying Bernoulli's equation to fluid mechanics situations:
1) Determining the diameter of a jet of water flowing from a tank if the water level remains constant
2) Determining if the water level in a tank with inflows and an outflow weir is rising or falling
3) Calculating pressures and drawing hydraulic grade lines for a pipe system with and without a nozzle
4) Analyzing forces on a vertical gate from upstream water with varying depths
5) Calculating flow rates and pressures at several points in a branched pipeline system
This document provides conversion factors between British gravitational (BG) units and International System of Units (SI) units for various quantities in fluid mechanics and heat transfer. It lists units for length, area, mass, density, force, pressure, temperature, velocity, power, viscosity, volume, and flow rate. For each quantity, it specifies the conversion factor to multiply the BG unit by to obtain the equivalent SI unit. The list of conversion factors is extensive and covers many common units needed for engineering calculations involving fluid properties, forces, heat transfer, and fluid flow behaviors.
Manometers and Pitot tubes are devices used to measure fluid pressure and velocity. A manometer uses a liquid column to measure pressure differences, while a Pitot tube uses a pressure tap to measure flow velocity based on Bernoulli's equation. A manometer can be a simple U-tube or inclined design, while orifices are openings that can be classified by size, shape, and flow characteristics. A Pitot tube has a open end facing flow and static pressure taps, allowing velocity measurement. These devices are essential tools for analyzing fluid systems.
This document contains 5 questions regarding fluid mechanics. Question 1 involves calculating the torque and power required to overcome viscous resistance in a rotating shaft. Question 2 involves calculating pressure drop, head loss, and power required for a given water flow rate through a pipe and orifice system. Question 3 determines the necessary counterweight to balance a water gate. Question 4 calculates the water level in a tank given pump specifications and a triangular weir. Question 5 determines if a hydraulic machine is a pump or turbine and calculates its power output or input.
This document provides information and examples for calculating surface areas and volumes of rectangular and round tanks, as well as clarifier loading calculations. It includes formulas and step-by-step worked examples for determining surface area of rectangles and circles, and volume of rectangular and cylindrical tanks, including those with conical bottoms. Clarifier detention time is defined as the time it takes for water to travel from inlet to outlet.
1) The document presents the solution to calculating the force in a strut connecting two points on a small dam given information about the dam geometry and hydrostatic forces.
2) It also provides examples of calculating forces on structures like gates and stops subjected to hydrostatic forces from water, including determining the minimum volume of concrete needed to balance these forces.
3) The solutions involve applying principles of equilibrium, calculating hydrostatic force components, and summing moments. Analytical expressions for determining forces are developed.
The document contains questions related to open channel flow, pipe flow, and hydraulic structures. It asks the reader to calculate parameters like normal depth, critical depth, flow depth, head loss, forces on structures, and more for channels, pipes and hydraulic elements based on given flow rates, dimensions, slopes and roughness. The reader is asked to show working and assumptions for multi-part questions involving concepts like specific energy, critical flow, flow transitions, weirs and sluice gates.
The document describes a calculation to determine the height (H) of oil in a rectangular tank at which a hinged gate will just begin to rotate counterclockwise. The gate is subjected to an upward force from the oil (F1) and a leftward force from the air pressure (F2). F1 is calculated based on the oil density, area of the gate, and height of the oil column. F2 is given as the air pressure times the gate area. Setting F1 equal to F2 and solving for H gives the critical height at which rotation will occur.
The document discusses several fluid mechanics problems involving pipes, valves, pumps, and Venturi meters. It provides the relevant equations, diagrams, and step-by-step workings to calculate pressure, velocity, discharge, and other flow parameters for each problem.
The document also contains an Arabic passage discussing philosophical concepts like thinking outside the box and challenging preconceived notions.
The document contains questions related to open channel flow, pipe flow, and hydraulic structures. It asks the reader to calculate parameters like normal depth, critical depth, flow depth, head loss, force on structures, and more for channels, pipes and hydraulic elements based on given cross-sections, slopes, roughness and discharge. It also contains multiple choice questions testing understanding of concepts like Darcy-Weisbach equation, Chezy's formula, relationship between EGL, HGL and velocity head.
The document appears to be a 14-page final exam for a Hydraulic I course taught by Dr. Ezzat El-sayed G. SALEH in January 2017. It contains multiple pages of questions related to hydraulics for students taking the CVE 215 Hydraulic I course final.
The document contains lecture notes on hydraulics from Minia University in Egypt. It defines key terms related to fluid mechanics such as density, viscosity, laminar and turbulent flow, compressibility, and surface tension. It also provides the continuity equation and defines different types of fluid flow such as steady, uniform, rotational, and one, two, and three-dimensional flow. The notes conclude by listing the Bernoulli equation and its assumptions.
The document is a study sheet on Bernoulli's equation and its applications. It contains 7 practice problems applying Bernoulli's equation to calculate things like water flow rates, pressures at different points, and forces on gates. Diagrams illustrate the hydraulic systems and students are asked to calculate values, sketch graphs, and determine if water levels are rising or falling. The problems involve nozzles, pipes, weirs, and cylinders to demonstrate applications of Bernoulli's equation in hydraulics.
This document provides an overview of various topics in civil engineering, including the different branches and their applications. It discusses surveying, structural engineering, transportation engineering, geotechnical engineering, construction management, irrigation engineering, earthquake engineering, and the roles of civil engineers in construction projects like buildings and dams. The key information presented includes the different types of structures, loads, soils, roads, and the purposes and methods of each civil engineering specialty.
This document discusses Pelton wheel turbines. It begins with an overview of Pelton wheels and their components. It then provides explanations of key concepts such as impulse turbines, velocity diagrams, effective head, maximum power output, and hydraulic efficiency. Practical considerations for Pelton wheel design like optimal bucket angles are also covered. Finally, it discusses turbine selection and the typical range of specific speeds for different turbine types.
This document defines and describes different types of fluid flows. It discusses ideal and real fluids, Newtonian and non-Newtonian fluids, laminar and turbulent flow, steady and unsteady flow, uniform and non-uniform flow, compressible and incompressible flow, rotational and irrotational flow, and viscous and non-viscous flow. Key fluid properties like viscosity, density, and compressibility are covered. Examples are provided to illustrate different fluid types and flows.
This document contains diagrams and questions related to fluid mechanics:
1) It shows diagrams of different devices moving in fluid and asks whether each will move in the positive or negative x-direction assuming equal pressure at the entrance and exit.
2) It shows a diagram of a sprinkler and asks to determine the torque required to prevent its rotation given the fluid velocity and distance from the point of rotation.
3) It shows a diagram of a vane moving through fluid and asks to determine the force on the vane given its angle, velocity through the fluid, and the fluid velocity striking it.
4) It asks which factors the pressure at the summit of a siphon depends on out of liquid density
artificial intelligence and data science contents.pptxGauravCar
What is artificial intelligence? Artificial intelligence is the ability of a computer or computer-controlled robot to perform tasks that are commonly associated with the intellectual processes characteristic of humans, such as the ability to reason.
› ...
Artificial intelligence (AI) | Definitio
Use PyCharm for remote debugging of WSL on a Windo cf5c162d672e4e58b4dde5d797...shadow0702a
This document serves as a comprehensive step-by-step guide on how to effectively use PyCharm for remote debugging of the Windows Subsystem for Linux (WSL) on a local Windows machine. It meticulously outlines several critical steps in the process, starting with the crucial task of enabling permissions, followed by the installation and configuration of WSL.
The guide then proceeds to explain how to set up the SSH service within the WSL environment, an integral part of the process. Alongside this, it also provides detailed instructions on how to modify the inbound rules of the Windows firewall to facilitate the process, ensuring that there are no connectivity issues that could potentially hinder the debugging process.
The document further emphasizes on the importance of checking the connection between the Windows and WSL environments, providing instructions on how to ensure that the connection is optimal and ready for remote debugging.
It also offers an in-depth guide on how to configure the WSL interpreter and files within the PyCharm environment. This is essential for ensuring that the debugging process is set up correctly and that the program can be run effectively within the WSL terminal.
Additionally, the document provides guidance on how to set up breakpoints for debugging, a fundamental aspect of the debugging process which allows the developer to stop the execution of their code at certain points and inspect their program at those stages.
Finally, the document concludes by providing a link to a reference blog. This blog offers additional information and guidance on configuring the remote Python interpreter in PyCharm, providing the reader with a well-rounded understanding of the process.
Software Engineering and Project Management - Introduction, Modeling Concepts...Prakhyath Rai
Introduction, Modeling Concepts and Class Modeling: What is Object orientation? What is OO development? OO Themes; Evidence for usefulness of OO development; OO modeling history. Modeling
as Design technique: Modeling, abstraction, The Three models. Class Modeling: Object and Class Concept, Link and associations concepts, Generalization and Inheritance, A sample class model, Navigation of class models, and UML diagrams
Building the Analysis Models: Requirement Analysis, Analysis Model Approaches, Data modeling Concepts, Object Oriented Analysis, Scenario-Based Modeling, Flow-Oriented Modeling, class Based Modeling, Creating a Behavioral Model.
Applications of artificial Intelligence in Mechanical Engineering.pdfAtif Razi
Historically, mechanical engineering has relied heavily on human expertise and empirical methods to solve complex problems. With the introduction of computer-aided design (CAD) and finite element analysis (FEA), the field took its first steps towards digitization. These tools allowed engineers to simulate and analyze mechanical systems with greater accuracy and efficiency. However, the sheer volume of data generated by modern engineering systems and the increasing complexity of these systems have necessitated more advanced analytical tools, paving the way for AI.
AI offers the capability to process vast amounts of data, identify patterns, and make predictions with a level of speed and accuracy unattainable by traditional methods. This has profound implications for mechanical engineering, enabling more efficient design processes, predictive maintenance strategies, and optimized manufacturing operations. AI-driven tools can learn from historical data, adapt to new information, and continuously improve their performance, making them invaluable in tackling the multifaceted challenges of modern mechanical engineering.
Introduction- e - waste – definition - sources of e-waste– hazardous substances in e-waste - effects of e-waste on environment and human health- need for e-waste management– e-waste handling rules - waste minimization techniques for managing e-waste – recycling of e-waste - disposal treatment methods of e- waste – mechanism of extraction of precious metal from leaching solution-global Scenario of E-waste – E-waste in India- case studies.
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3. 3
Hydraulic I (3) Fluid Static Forces
Hydrostatic Forces on Plane Surfaces
- Magnitude,
- Direction, it is the easiest!
Why?
- Line of action
To define the force, we need:
5. 5
Hydraulic I (5) Fluid Static Forces
Hydrostatic Force on an Inclined Plane Surfaces
- Magnitude,
- Location
6. 6
X
dA
Hydraulic I (6) Fluid Static Forces
Center of Pressure CP
Center of Gravity CG
y
ỳ
ycp
F
P = g y sin
Free Surface
A
A
dA
y
g
dA
P
F
sin
Hydrostatic Force on Plane Inclined Surfaces
7. 7
Hydraulic I (7) Fluid Static Forces
A
y
sin
g
dA
sin
y
g
dA
P
F
A
A
A
Surfaces exposed to fluids experience a force due to the distribution
in the fluid
From solid mechanics the location of the center of gravity (centroid of
the area) measured from the surface is
A
y
A
1
y
A
..(1)
- Magnitude
Hydrostatic Force on Plane Inclined Surfaces
8. 8
Hydraulic I (8) Fluid Static Forces
A
P
A
h
g
A
)
sin
y
(
g
F
Substituting into Eq. (1) gives:
y
h
sin
y
h
- Magnitude
Hydrostatic Force on Plane Inclined Surfaces
9. 9
Hydraulic I (9) Fluid Static Forces
A
P
A
h
g
A
P
A
h
g
A
P
F atm
atm
)
R
(
The net pressure force on the
plane, submerged surface is:
- Note
Hydrostatic Force on Plane Surfaces
𝐻 = 𝑦 sin 𝜃
10. 10
Hydraulic I (10) Fluid Static Forces
Center of Pressure on an Inclined Plane Surface
- Line of Action of F
Does the resultant force pass thought the center of gravity
?
No! lies below the centroid, since pressure increases with
depth
Moment of the resultant force must equal the moment of
the distributed pressure force
dA
y
sin
g
y
dF
y
F
A
2
A
cp
12. 12
Hydraulic I (12) Fluid Static Forces
- Line of Action of F (center of pressure)
The location of the center of pressure is independent of
the angle ,
The center of pressure is always below the centroid,
As the depth of immersion increase, the depth of the
center of pressure approaches the centroid.
y
A
I
y
y
g
.
c
cp
15. 15
Hydraulic I (15) Fluid Static Forces
- Moment of Inertia for Common Shapes
16. 16
C.G
C.P
Free Surface
A Completely SubmergedTilted Rectangular Plate
)
b
a
(
sin
2
/
a
S
g
A
h
g
F
)
b
a
(
2
/
a
S
)
12
/
a
b
(
2
/
a
S
y
3
cp
sin
2
/
a
S
h
h
y
cp
y
S
F
a
17. 17
C.G
C.P
Free Surface
sin
)
2
/
a
(
h y
a
cp
y
F
)
b
a
(
sin
2
/
a
g
A
h
g
F
h
a
3
2
)
b
a
(
2
/
a
)
12
/
a
b
(
2
/
a
y
3
cp
When the Upper Edge of the SubmergedTilted Rectangular Plate is at the
Free Surface and thus (S = 0)
h
18. 18
=90o
C.G
C.P
Free Surface
A Completely SubmergedVertical Rectangular and thus ( = 0)
a
S
1
90
sin
:
where
)
2
/
a
S
(
h
o
cp
cp h
y
h
y
F
)
b
a
(
2
/
a
S
g
A
h
g
F
)
b
a
(
2
/
a
S
)
12
/
a
b
(
2
/
a
S
y
3
cp
19. 19
=90o
C.G
C.P
Free Surface
h
y
cp
cp h
y
0
S
,
1
90
sin
:
where
2
/
a
h
o
a
F
When the Upper Edge of the SubmergedVertical Rectangular
Plate is at the Free Surface and thus (S = 0 & = 90o)
)
b
a
(
2
/
a
g
A
h
g
F
a
3
2
)
b
a
(
2
/
a
)
12
/
a
b
(
2
/
a
y
3
cp
20. 20
F increases as H increases ?
decreases as H increases?
is constant as H increases?
T increases as H increases?
T is constant as H increases?
y
ycp
y
ycp
True or False???
21. 21
Hydraulic I (21) Fluid Static Forces
Hydrostatic Force on a Curved Surface
D C
E B
A
FH
W1
W2
Assume Patm=0 (gage) at the free
surface,
The hydrostatic force on the surface EA
: is Fx
The net vertical force on the curve
surface AB is: FV=W1+W2
To find the line of action of the resultant
force, balance the momentum about
some convenient point
22. 22
A
Hydraulic I (22) Fluid Static Forces
Pressure on Curved Surface (free body)
D
B
C
yCp
FV(1)
FH
FV(2)
E
w
EA
2
EA
DE
g
Fx
A
w
ABE
area
BCDE
area
g
FV
S
B
23. 23
Hydraulic I (23) Fluid Static Forces
Pressure on Curved Surface (free body)
Determine the volume of fluid above the curved surface,
Compute the weight of the volume above it,
The magnitude of the vertical component of the resultant
force is equal to the weight of the determined volume. It
acts in line with the centroid of the volume,
Draw a projection of the curved surface onto a vertical
plane and determine its height called “S”,
24. 24
Hydraulic I (24) Fluid Static Forces
Pressure on Curved Surface (free body)
Determine the depth to the centroid of the projected area
=DE+(S/2), where DE is the depth to the top of the projected area
Compute the magnitude of the horizontal component of
the resultant force, FH = g h- A = g (DE+S/2)x(Sx w)
Compute the depth to the line of action of the horizontal
force,
h
A
I
h
h
cg
cp
25. 25
Hydraulic I (25) Fluid Static Forces
Pressure on Curved Surface (free body)
For regular rectangular cross-section,
Thus,
Compute the resultant force,
h
A
I
h
h
cg
cp
w
S
h
12
S
DA
g
A
h
g
F
2
H
2
V
2
H
R F
F
F
26. 26
Hydraulic I (26) Fluid Static Forces
Pressure on Curved Surface (free body)
Compute the angle of inclination of the resultant force
relative to the horizontal.
Thus,
11- Show the resultant force acting on the curved surface
in such a direction that its line of action passes through
the center of curvature of the surface.
H
V
1
F
F
tan
27. 27
Hydraulic I (27) Fluid Static Forces
2.50 m
2.80 m
2. 0 m
water Oil s.g = 0.90
Support
Gate, 0.60 m wide
Hinge
Pressure on Plane Surface (free body)
28. 28
Hydraulic I (28) Fluid Static Forces
The figure shows a gate hinged at its bottom hinged at its
bottom and held by a simple support at its top. The gate
separates two fluids. Compute
the net force on the gate due to the fluid on each side,
and
Compute the force on the hinge and on the support.
Pressure on Plane Surface (free body)
29. 29
Hydraulic I (29) Fluid Static Forces
2.50 m
2.80 m
2. 0 m
water Oil Sg = 0.90
Support
Gate, 0.60 m wide
Hinge “o”
F1
F2
Hcp (1)
Hcp (1)
2.50 m
Pressure on Plane Surface (free body)
32. 32
What are the magnitude and direction of the force on
the vertical rectangular dam (the shown figure) of
height H and width, w, due to hydrostatic loads, and
At what elevation is the center of pressure?
34. 34
Because the area is (H x w), the magnitude of the force,
2
H
w
g
2
1
A
h
g
F
The center of pressure is found using
,
)
h
A
/(
I
h
y cg
p
.
c
12
/
H
w
I 3
cg
Thus, 6
/
H
)
2
/
wH
(
)
12
/
H
w
(
h
y 2
3
p
.
c
The hydrostatic pressure is , where is the depth at
which the centroid of the dam is located.
h
g
P
2
H
h
35. 35
The direction of the force is normal and compressive to the dam face as
shown .
The center of pressure is therefore located at a distance H/6 directly below
the centroid of the dam, or a distance 2H / 3 of below the water surface.
36. 36
What is the net horizontal force acting on a constant
radius arch-dam face due to hydrostatic forces?
38. 38
The projected area is , while
H
sin
R
2
A projected
The pressure at the centroid of the projected surface is h
g
P
The magnitude of the horizontal force is thus ,
and the center of pressure lies below the water surface on the
line of symmetry of the dam face.
sin
R
H
g
A
h
g
F 2
3
2 /
H
Because the face is assumed vertical, the vertical force on the dam is zero
42. 42
A
B
C
FH, U
D
FH, U
FH, D
FV, U FV, D
O
E
)
W
"
AD
("
"
AD
"
g
F U
,
H
)
W
"
OA
("
"
OA
"
g
F D
,
H
W
BCD
area
ABCD
area
g
F U
,
V
W
AOE
area
g
F D
,
V
3
/
r
4
Curved Surfaces
46. 46
Fluid of s. g =
P =
)
g
g
.
s
/(
P
h w
.
equi
B
B
A
h
B
h
The tank shown in the figure contains a
fluid of s.g = and is pressurized to P =
How to calculate the forces (horizontal
& vertical on the quarter circle gate
AB????
Convert the pressure to an equivalent head “h” equiv.
)
g
g
.
s
/(
P
h w
.
equi
and solve it as before
48. 48
9.0 m
45 m
Water
Water Surface
9.0 m
A semicircular 9.0 m diameter tunnel is to be built under a 45 m
deep, 240 m long lake, as shown. Determine the total hydrostatic
force acting on the roof of the tunnel.
Tunnel
Worked Example
49. 49
9.0 m
45 m
Water
W
ater Surface
9.0 m
Tunnel
A
B C
D
E
Fx
Fy
Fx
Fy
The hydrostaticforce actingon the roof of the tunnel
The hydrostatic force acting on the roof of the tunnel
50. 50
It acts vertically downward (see the shown figure
below).
0
Fx
w
AED
area
ABCD
area
g
Fy
kN
10
64
.
874
240
9
8
9
45
81
.
9
1000 3
2
The vertical force can be computed as
51. 51
R
1
If this weightless quarter-cylindrical gate is in static equilibrium, what is
the ratio between 1 and 1 ?
2
Worked Example “Static Forces on Curved Surfaces”
Pivot
52. 52
3
/
R
4
R
U
,
H
F D
,
H
F
U
,
V
F
1
2
U
,
H
D
,
H
H F
F
F
W
)
ABC
volume
(
g
FV
3
/
R 3
/
R
)
1
R
(
2
R
F 1
U
,
H
)
1
R
(
2
R
F 2
D
,
H
Both of the horizontal
forces, FH,U and FH,D
act at a vertical
distance of R/3 above
the pivot.
A
B C
For a unite wide of the gate
U
,
H
F
Cont.
53. 53
3
R
4
F
3
R
F U
,
V
H
Taking the moment about the pivot “o” and equating it to zero gives,
or
3
R
4
0
.
1
4
R
3
R
)
0
.
1
R
(
2
R
)
(
2
1
1
2
H
F U
,
V
F
1
1
2 2
)
(
the ratio between 1 and 1
3
/
1
2
1
Cont.
54. 54
Worked Example “Static Forces on Curved Surfaces”
The homogeneous gate shown in the figure consists of one quarter of a
circular and is used to maintain a water depth of 4.0 m. That is, when
the water depth exceeds 4.0 m, the gate opens slightly and lets the
water flow under it. Determine the weight of the gate per meter of length.
Water
Worked Example “Static Forces on Curved Surfaces”
Pivot
1.0 m
4.0 m
55. 55
Cont.
Water
Worked Example “Static Forces on Curved Surfaces”
Pivot
1.0 m
4.0 m
0.5 m
1- 4R/3
FV,2
FV,1
FH
C.p
3
2
/
1
h
C.G
O
A
B
C D
W
In the shown figure, FH and FV are the
horizontal and vertical components of
the total force on the one quarter of a
circular immersed homogenous gate.
56. 56
Cont.
0.5 m
1- 4R/3
FV,2
FV,1
FH
C.p
O
A
B
C D
W
For the Horizontal Force:
g
5
.
3
)
1
1
(
)
2
/
1
3
(
g
A
h
g
FH
It acts towards left at a distance hcp from the free surface,
which can be calculate as
m
52
.
3
5
.
3
)
1
1
(
)
12
/
1
1
(
5
.
3
h
A
I
h
h
3
cg
p
.
c
For the Vertical Force:
The horizontal force FH= Resultant force on the projection
of “OA” on a vertical plane:
The vertical force FV = Weight of the
volume of the water which would lie
vertically above “OA”.
0
.
1
AODCDA
area
g
width
unit
per
,
FV
57. 57
Cont.
0.5 m
1- 4R/3
FV,2
FV,1
O
A
B
C D
W
0
.
1
ODCB
area
AOB
area
g
width
unit
per
,
FV
2
,
V
1
,
V F
and
F
g
785
.
0
0
.
1
)
4
/
1
(
g
0
.
1
AOB
area
g
F 2
1
,
V
g
3
0
.
1
)
3
1
(
g
0
.
1
ADCB
area
g
F 2
,
V
The force acts upward, through the centroid of the gate at a
distance of (1- 4R/ 3) = 1- (4x1/ 3 ) = 1- 0.424 =0.576 m (left
to “O”)
The force acts upward, through the centroid of the rectangular
“ODCB” at a distance of 0.50 m (left to “O”)
58. 58
Cont.
0.5 m
1- 4R/3
FV,2
FV,1
O
A
B
C D
W
Since the gate is homogenous, it weight acts downward,
through the centroid at a distance of (1- 4R/ 3) = 1- (4x1/ 3 ) =
1- 0.424 =0.576 m (left to “O”).
FH
3.52 - 3.0 = 0.52m
Taking the moments about pivot “O”
576
.
0
W
50
.
0
F
576
.
0
F
52
.
0
F
0
M 2
,
V
1
,
V
H
"
O
"
about
576
.
0
50
.
0
F
576
.
0
F
52
.
0
F
W
2
,
V
1
,
V
H
Substituting the compute values gives,
kN
25
.
64
1000
81
.
9
1000
55
.
6
g
55
.
6
576
.
0
50
.
0
3
576
.
0
g
785
.
0
52
.
0
g
5
.
3
W
W = the weight of the
gate per meter of length
59. 59
1.20 m
1.80
m
2.40 m
P
S.G = 0.95
Air
Air
A
Worked Example “Static Forces on
Plane Surfaces”
•What is the pressure at “A”?
• Draw a free body diagram of the
gate (5.0 m) showing all forces and
the locations of their lines of action.
• Calculate the minimum force “P”
necessary to keep the gate close.