Gauss's law states that the electric flux through any closed surface is equal to 1/ε0 times the total charge enclosed by the surface. The document then explains Gauss's law and the Gaussian surface method for calculating electric field intensity. It provides an example of using Gauss's law to find that the electric field intensity inside a hollow charged sphere is zero since there is no enclosed charge.

2.  Gauss's Law
• Statement
• Explanation and derivation
 Gaussian surface
• Definition
• Steps to find E
 Intensity of field inside Hollow Charged Sphere
OVERVIEW

3. •Statement
• The electric flux through any close surface is 1/ϵ0 times the total charge
enclosed in it.
• Mathematical form
• 𝜑e=1/ϵ0(Q)
Gauss’s Law

4. •Explanation
• Consider an irregular closed surface having n points charges q1,q2,q3,…qn as
shown in figure. The total electric flux passing through the closed surface is
Gauss’s Law

5. •Definition
• An imaginary closed surface of arbitrary shape which passes through the
point where we find to calculate the Electric intensity.
•Steps to Calculate Electric intensity
1. Consider a Gaussian surface
2. Charged enclosed by Gaussian surface
3. calculate the flux through that area
4. Apply Gauss’s law to calculate Electric Intensity
Gaussian Surface

6. •Step 1
• Gaussian Surface
Intensity of field inside a
Hollow Charged Sphere

7. •Step 2
• Charged enclosed
• q = 0
Intensity of field inside a
Hollow Charged Sphere

8. •Step 3
• Calculation of flux
• 𝝋e = E . A
•Step 4
• Calculation of electric intensity
• 𝝋e =
𝒒
𝛜 𝟎
• E . A =
𝒒
𝛜 𝟎
• E . A = 0
• Since area can never be zero so, E=0
Intensity of field inside a
Hollow Charged Sphere

10. PRACTICE TEST
ANSWER : D

11. PRACTICE TEST
ANSWER : B