CAPACITOR
Dr. Nadeem Khalid
AL-AQSA ACADEMY, LAHORE
• Definition
• The device which is used to store electric charge is called capacitor
CAPACITOR
• A simple capacitor consist of two parallel conducting plates separated
by air, or some insulating medium is called parallel plate capacitor
• The insulating medium is known as dielectric
PARALLEL PLATE CAPACITOR
• If the plates are connected to a battery of voltage V the one of the
plate has + Q charge and the other plate have – Q charge. These
charges remain on the inner surface of the plates due to attraction
between the opposite charges
• It is observed that if the amount of charge stored increased the
potential difference between plates also increase
• Q∝ 𝑉
• Q = CV
• C =
𝑄
𝑉
• Here C is the constant of proportionality called capacitance of capacitor
CHARGING OF CAPACITOR
• Definition
• The capacity of a capacitor to store charges is known as Capacitance
• Formula
• C =
𝑄
𝑉
• Dependence
• Area of plate
• Distance between plates
• Medium present between plates
• Units
• Farad(F)
• Farad
• if one coulomb charge store on capacitor plates produce a potential difference of
one volt then capacitance of this capacitor will be one farad
• 1 farad =
1 𝑐𝑜𝑢𝑙𝑜𝑚𝑏
1 𝑣𝑜𝑙𝑡
CAPACITANCE
• Consider a parallel plate capacitor. Let
• A = area of each plate
• d = distance between the plates
• Q = charge store on each plate
• V = potential difference between plates
• E = electric field
• 𝜎 = surface charge density
CAPACITANCE OF A PARALEL PLATE
CAPACITOR
• Capacitance when air or vacuum between plates
• Cvac =
𝑄
𝑉
…….(1)
• Cvac =
𝜎𝐴
𝜎𝑑
ϵ0
• Cvac =
𝐴ϵ0
d
CAPACITANCE OF A PARALEL PLATE
CAPACITOR
E=
𝑽
𝒅
V = Ed
E =
𝝈
𝛜 𝟎
V = =
𝝈𝒅
𝛜 𝟎
𝝈=
𝑸
𝑨
Q = 𝝈𝑨
• Capacitance with dielectric as medium
• If an insulating material of relative permittivity ϵr is placed between plates the
capacitance of capacitor is increased by the factor ϵr called as dielectric
constant
• Cmed =
𝐴ϵ0 ϵr
d
CAPACITANCE OF A PARALEL PLATE
CAPACITOR
• How capacitance increase
• C =
𝑄
𝑉
• by placing dielectric voltage decrease so capacitance increase
• Dielectric constant
• Ratio of capacitance of a parallel plate capacitor with a dielecric to its
capacitance with vacuum or air as a medium
• ϵr =
Cmed
Cvac
CAPACITANCE OF A PARALEL PLATE
CAPACITOR
PRACTICE TEST
Answer: A
C =
𝑄
𝑉
PRACTICE TEST
Answer: A
Cmed =
𝐴ϵ0 ϵr
d
PRACTICE TEST
Answer: C
Cvac =
𝑨𝛜 𝟎
𝒅
Capacitor

Capacitor

  • 1.
  • 2.
    • Definition • Thedevice which is used to store electric charge is called capacitor CAPACITOR
  • 4.
    • A simplecapacitor consist of two parallel conducting plates separated by air, or some insulating medium is called parallel plate capacitor • The insulating medium is known as dielectric PARALLEL PLATE CAPACITOR
  • 5.
    • If theplates are connected to a battery of voltage V the one of the plate has + Q charge and the other plate have – Q charge. These charges remain on the inner surface of the plates due to attraction between the opposite charges • It is observed that if the amount of charge stored increased the potential difference between plates also increase • Q∝ 𝑉 • Q = CV • C = 𝑄 𝑉 • Here C is the constant of proportionality called capacitance of capacitor CHARGING OF CAPACITOR
  • 6.
    • Definition • Thecapacity of a capacitor to store charges is known as Capacitance • Formula • C = 𝑄 𝑉 • Dependence • Area of plate • Distance between plates • Medium present between plates • Units • Farad(F) • Farad • if one coulomb charge store on capacitor plates produce a potential difference of one volt then capacitance of this capacitor will be one farad • 1 farad = 1 𝑐𝑜𝑢𝑙𝑜𝑚𝑏 1 𝑣𝑜𝑙𝑡 CAPACITANCE
  • 7.
    • Consider aparallel plate capacitor. Let • A = area of each plate • d = distance between the plates • Q = charge store on each plate • V = potential difference between plates • E = electric field • 𝜎 = surface charge density CAPACITANCE OF A PARALEL PLATE CAPACITOR
  • 8.
    • Capacitance whenair or vacuum between plates • Cvac = 𝑄 𝑉 …….(1) • Cvac = 𝜎𝐴 𝜎𝑑 ϵ0 • Cvac = 𝐴ϵ0 d CAPACITANCE OF A PARALEL PLATE CAPACITOR E= 𝑽 𝒅 V = Ed E = 𝝈 𝛜 𝟎 V = = 𝝈𝒅 𝛜 𝟎 𝝈= 𝑸 𝑨 Q = 𝝈𝑨
  • 9.
    • Capacitance withdielectric as medium • If an insulating material of relative permittivity ϵr is placed between plates the capacitance of capacitor is increased by the factor ϵr called as dielectric constant • Cmed = 𝐴ϵ0 ϵr d CAPACITANCE OF A PARALEL PLATE CAPACITOR
  • 10.
    • How capacitanceincrease • C = 𝑄 𝑉 • by placing dielectric voltage decrease so capacitance increase • Dielectric constant • Ratio of capacitance of a parallel plate capacitor with a dielecric to its capacitance with vacuum or air as a medium • ϵr = Cmed Cvac CAPACITANCE OF A PARALEL PLATE CAPACITOR
  • 12.
  • 13.
  • 14.
    PRACTICE TEST Answer: C Cvac= 𝑨𝛜 𝟎 𝒅