Trepezoidal Sarda type fall
Straight glacis fall
3/20/2014 1
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
u/s wing walls :
D/s wing walls :
D/s *bed pitching :
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
2
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
3
Radius = 5 to 6 times H
= 5 x 0.83 to 6 x 0.83
= 4.15 to 4.98 m
Say R = 4.50 m
Provide u/s wing walls having
segmental portion with radius 4.5 m
and subtending an angle of 60°, at the
centre and starting from the u/s edge
of the crest wall.
3/20/2014 4
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
3/20/2014 5
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
Length of d/s wing wall with
vertical face
= 6 H • HL
= 6-7 0.83 x 1.5
= 6.70 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
6
3/20/2014 7
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
Length of warped wing with a splay
of 1 in 3 = height * splay = 2.5 * 3
= 7.5 m
Total length of d/s wing wall = 6.70
+ 7.5 = 14.2 m.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
8
Length of d/s bed pitching
= 9 + 2Hl
= 9 + 2 x 1.5
= 12 m
Provide horizontal pitching up to
the end of masonry wing walls for a
length of 6.3 m and then sloping at 1
in 10 for length of 6 m.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
9
Wingwall
103.77
12 M
PITCHING
3/18/2014 10
PREPARED BY V.H.KHOKHANI
ASSISTANT PROFESSOR, DIET
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
11
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
12
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
13
FLUMED
FALL
UNFLUMED
FALL
METER
FALL
NONMETER
FALL
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
14
1. Crest design
2. Cistern design
3. Impervious floor
4. u/s wing walls
5. d/s wing walls
6. d/s side protection
7. Roughening devices
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
15
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
16
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
17
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
18
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
19
Length of crest = width of bed (for
unflumed fall)
L = 35.0 m
For non-meter fall, narrow crest is
provided.
Discharge Q is given by :
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
20
H = 0.85 m
R.L. of crest = u/s FSL – H
= 203.5 – 0.85
= 202.65 M
height of crest above u/s bed,
= R.L.of crest – U/S bed level
= 202.65 - 201.5 = 1.15
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
21
Crest width for non meter fall
= (2/3) H
= (2/3) 0.85
= 0.57
The d/s glacis is provided in a slope of
2 : 1
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
22
Compare it with d/s bed level
because as we know cistern is
always below d/s bed level.
Ef2 can be obtained from blench
curve from available q and Hl
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
23
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
24
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
25
d/s bed level
u/s bed level
cistern level
0.25 ef2
d/s TEL = d/s FSL + Ha =202 + 0.02
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
26
d/s bed RL is 200 m which is lower
than obtained cistern level.
So provide minimum depth of
cistern = 0.25 Ef2 = 0.25 (1.40) =
0.35 m.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
27
Length of cistern = 5 ef2 to 6 ef2
= 5(1.40) to 6 (1.40)
= 7.0 to 8.4 m
Provide length of cistern 8 .0 m
The cistern is joined to the d/s bed of
the channel with a slope of 5 : 1.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
28
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
29
d/s bed level
u/s bed level
cistern level
0. 35 m
8.0 m
5 in 1
Assuming 0.6 m additional cutoff
depth.
u/s cutoff depth = D1/3 + 0.6
D/S cutoff depth = D2/2 + 0.6
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
30
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
31
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
32
d/s bed level
u/s bed level
cistern level
0. 35 m
8.0 m
5 in 1
0.2 m
Deflector
wall
1.6 m
1.40 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
33
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
34
Provide total horizontal length of
impervious flow = 20.60 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
35
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
36
d/s bed level = 200
u/s bed level
= 201.5
cistern level =
199.65
8.0 m
1.6 m
1.40 m
crest level =
202.65
0.5 IN 1
L = b
Lu = total length – d/s glacis – u/s glacis – crest width
Provide total horizontal length of
impervious flow = 20.60 m
crest width = 0.55 m
horizontal length of u/s glacis =
(202.65 - 201.5) x 0.5 = 0.58 m
horizontal length of d/s glacis =
(202.65 - 199.65) x 2 = 6.0 m
length of cistern = 8 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
37
(a) u/s cutoff wall
d{ = 1.30 m
b = 20.60 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
38
Assume a thickness of 0.4 m at the
end of u/s floor
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
39
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
40
(b) d/s cutoff
d2 = 1.60 m
b = 20.6 m
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
41
Assume thickness of 0.5 m at the
end of d/s floor.
Neglecting effect of mutual
interference.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
42
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
43
ib) At 3 m from the toe of glacis :
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
44
(2) D/s wing walls :
Provide d/s wing walls upto the end of the
d/s floor and then join them to the return
walls.
Top level of wing wall = 202 + 0.5 = 202.5
m.
d/s Bed Protection :
No bed protection is required as a deflector
has been provided,
d/s Side Protection :
Length of side protection = 3D2 = 3 x 2= 6
m
Provide 20 cm thick brick side pitching
over 10 cm ballast for a length of
6 m at a slope of 1 : 1 beyond the d/s
impervious floor.
3/20/2014
PREPARED BY VIDHI H. KHOKHANI
ASST. PROF. DIET
45

Drop structure lecture 4

  • 1.
    Trepezoidal Sarda typefall Straight glacis fall 3/20/2014 1 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET
  • 2.
    u/s wing walls: D/s wing walls : D/s *bed pitching : 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 2
  • 3.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 3
  • 4.
    Radius = 5to 6 times H = 5 x 0.83 to 6 x 0.83 = 4.15 to 4.98 m Say R = 4.50 m Provide u/s wing walls having segmental portion with radius 4.5 m and subtending an angle of 60°, at the centre and starting from the u/s edge of the crest wall. 3/20/2014 4 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET
  • 5.
    3/20/2014 5 PREPARED BYVIDHI H. KHOKHANI ASST. PROF. DIET
  • 6.
    Length of d/swing wall with vertical face = 6 H • HL = 6-7 0.83 x 1.5 = 6.70 m 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 6
  • 7.
    3/20/2014 7 PREPARED BYVIDHI H. KHOKHANI ASST. PROF. DIET
  • 8.
    Length of warpedwing with a splay of 1 in 3 = height * splay = 2.5 * 3 = 7.5 m Total length of d/s wing wall = 6.70 + 7.5 = 14.2 m. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 8
  • 9.
    Length of d/sbed pitching = 9 + 2Hl = 9 + 2 x 1.5 = 12 m Provide horizontal pitching up to the end of masonry wing walls for a length of 6.3 m and then sloping at 1 in 10 for length of 6 m. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 9
  • 10.
    Wingwall 103.77 12 M PITCHING 3/18/2014 10 PREPAREDBY V.H.KHOKHANI ASSISTANT PROFESSOR, DIET
  • 11.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 11
  • 12.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 12
  • 13.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 13
  • 14.
  • 15.
    1. Crest design 2.Cistern design 3. Impervious floor 4. u/s wing walls 5. d/s wing walls 6. d/s side protection 7. Roughening devices 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 15
  • 16.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 16
  • 17.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 17
  • 18.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 18
  • 19.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 19
  • 20.
    Length of crest= width of bed (for unflumed fall) L = 35.0 m For non-meter fall, narrow crest is provided. Discharge Q is given by : 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 20
  • 21.
    H = 0.85m R.L. of crest = u/s FSL – H = 203.5 – 0.85 = 202.65 M height of crest above u/s bed, = R.L.of crest – U/S bed level = 202.65 - 201.5 = 1.15 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 21
  • 22.
    Crest width fornon meter fall = (2/3) H = (2/3) 0.85 = 0.57 The d/s glacis is provided in a slope of 2 : 1 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 22
  • 23.
    Compare it withd/s bed level because as we know cistern is always below d/s bed level. Ef2 can be obtained from blench curve from available q and Hl 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 23
  • 24.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 24
  • 25.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 25 d/s bed level u/s bed level cistern level 0.25 ef2
  • 26.
    d/s TEL =d/s FSL + Ha =202 + 0.02 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 26
  • 27.
    d/s bed RLis 200 m which is lower than obtained cistern level. So provide minimum depth of cistern = 0.25 Ef2 = 0.25 (1.40) = 0.35 m. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 27
  • 28.
    Length of cistern= 5 ef2 to 6 ef2 = 5(1.40) to 6 (1.40) = 7.0 to 8.4 m Provide length of cistern 8 .0 m The cistern is joined to the d/s bed of the channel with a slope of 5 : 1. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 28
  • 29.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 29 d/s bed level u/s bed level cistern level 0. 35 m 8.0 m 5 in 1
  • 30.
    Assuming 0.6 madditional cutoff depth. u/s cutoff depth = D1/3 + 0.6 D/S cutoff depth = D2/2 + 0.6 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 30
  • 31.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 31
  • 32.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 32 d/s bed level u/s bed level cistern level 0. 35 m 8.0 m 5 in 1 0.2 m Deflector wall 1.6 m 1.40 m
  • 33.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 33
  • 34.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 34
  • 35.
    Provide total horizontallength of impervious flow = 20.60 m 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 35
  • 36.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 36 d/s bed level = 200 u/s bed level = 201.5 cistern level = 199.65 8.0 m 1.6 m 1.40 m crest level = 202.65 0.5 IN 1 L = b Lu = total length – d/s glacis – u/s glacis – crest width
  • 37.
    Provide total horizontallength of impervious flow = 20.60 m crest width = 0.55 m horizontal length of u/s glacis = (202.65 - 201.5) x 0.5 = 0.58 m horizontal length of d/s glacis = (202.65 - 199.65) x 2 = 6.0 m length of cistern = 8 m 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 37
  • 38.
    (a) u/s cutoffwall d{ = 1.30 m b = 20.60 m 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 38
  • 39.
    Assume a thicknessof 0.4 m at the end of u/s floor 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 39
  • 40.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 40
  • 41.
    (b) d/s cutoff d2= 1.60 m b = 20.6 m 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 41
  • 42.
    Assume thickness of0.5 m at the end of d/s floor. Neglecting effect of mutual interference. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 42
  • 43.
    3/20/2014 PREPARED BY VIDHIH. KHOKHANI ASST. PROF. DIET 43
  • 44.
    ib) At 3m from the toe of glacis : 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 44
  • 45.
    (2) D/s wingwalls : Provide d/s wing walls upto the end of the d/s floor and then join them to the return walls. Top level of wing wall = 202 + 0.5 = 202.5 m. d/s Bed Protection : No bed protection is required as a deflector has been provided, d/s Side Protection : Length of side protection = 3D2 = 3 x 2= 6 m Provide 20 cm thick brick side pitching over 10 cm ballast for a length of 6 m at a slope of 1 : 1 beyond the d/s impervious floor. 3/20/2014 PREPARED BY VIDHI H. KHOKHANI ASST. PROF. DIET 45