Okay, let me solve this step-by-step:
* Given: q = 10 m3/s/m, y1 = 1.25 m
* To find y2, use the sequent depth ratio: y2/y1 = 2.5√(1+8Fr1^2)
* Fr1 = q/(gy1)^0.5 = 10/(9.81*1.25)^0.5 = 4
* y2/y1 = 2.5√(1+8*16) = 2.5√33 = 5.5
* y2 = 5.5*1.25 = 6.875 m
* v2 = q/y