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TUTORIAL SHEET-I

                                  (CONDUCTANCE)

1. Specific conductance of a decinormal solution of KCl at 18 C is 1.12Sm-1. The resistance
    of a conductivity cell containing solution at the same temperature is 55ohm. What is the
    cell constant?
2. The specific conductance of an N/50 solution of KCl at 25C is 0.002765 cm-1Ω-1. If the
    resistance of cell containing this solution is 400Ω, what is the cell constant?
3. The specific conductance of N/5 KCl solution at 25C is 0.002780mho. The resistance of
    the cell containing this solution is 500Ω. Calculate the cell constant.
4. If the resistance of N/50 KCl solution in a cell is 100Ω, calculate the cell constant.
5. Calculate the cell constant if the dimensions of the electrodes are 0.95cm & 1.015cm and
    the two electrodes are separated by 0.45cm.
6. The resistance of a 0.01M solution of an electrolyte is 210Ω at 25C. Calculate the molar
    conductance of the solution at the same temperature. The cell constant is 0.88cm-1.
7. The resistance of 0.5M solution of an electrolyte in a cell was found to be 45Ω. Calculate
    the molar conductance of the solution if the electrodes of the cell are 2.2cm apart and
    have an area of 3.8cm2.
8. 0.5N solution of a salt placed between two platinum electrodes, 20cm apart and of area
    4cm2 has a resistance of 25Ω. Calculate equivalent conductance of the solution.
9. The specific conductance of an N/10 solution of KCl at 25C is 0.002765Ω-1. If the
    resistance of cell containing this solution is 400Ω, what is the cell constant?
10. The resistance of decinormal solution of a salt occupying a volume between two platinum
    electrodes 1.80cm apart and 5.4cm2 in area was found to be 32Ω. Calculate equivalent
    conductance of the solution.
11. 0.5N solution of a salt placed between two platinum electrodes, 20cm apart and of area
    4cm2 has a resistance of 25Ω. Calculate the equivalent conductance of the solution.
12. The resistance of 0.1N solution is 2.5x103Ω. Calculate equivalent conductance of the
    solution. Cell constant = 1.15cm-1.
13. The resistance of a 0.5N solution of an electrolyte occupying a volume between two
    platinum electrodes 1.72cm apart having an area o 4.5cm2 is 25Ω. Calculate the
    equivalent conductance of the solution.
14. 0.1N solution of CH3COONa was placed between two electrodes 0.72cm apart with an
    area of 2.25cm2. The resistance of solution was 52.40Ω. Calculate the specific and
    equivalent conductance of the solution.
15. The resistance of N/100 solution of an electrolyte was found to be 210Ω at 25C.
    Calculate the equivalent conductance of the solution. (Cell constant = 0.88).
16. Resistance of 0.01M aqueous solution of an electrolyte at room temperature is 420Ω and
    cell constant is 84m-1. Calculate the molar conductance.
17. Calculate the specific and molar conductance of a 0.0075M aqueous solution of KCl.
         Given: conductance is 1.49x10-3S and cell constant is 1.05cm-1.
     18. A conductivity cell is filled with 0.05M KCl. Its specific conductance and observed
         resistance is 6.67x10-3Ω-1cm-1 and 243Ω, respectively. When the cell is filled with 0.01M
         NaOH, observed resistance is 681Ω. Calculate specific and molar conductance of 0.01M
         NaOH.
     19. The resistance of a cell containing 0.02M KCl solution at 25C was found to be 17Ω. The
         specific conductance of this solution is 27.7x10-3Ω-1cm-1. An exactly 0.01M solution of
         another substance in the same cell had a resistance of 57Ω. Calculate the equivalent
         conductance of this substance.
     20. In a particular cell, 0.01M solution of KCl gave a resistance of 15Ω while 0.01M solution
         of HCl gave a resistance of 51.4Ω at the same temperature. If the specific conductance o
         0.01M KCl is 0.1409Sm-1, calculate cell constant, specific conductance and equivalent
         conductance of HCl solution.
     21. A conductivity cell on being filled with a 0.02M solution at 25C showed a resistance of
         165Ω. The specific conductance of KCl solution used is 2.77x10-3Ω-1cm-1. The same cell
         containing 0.01M NaCl solution gave an electrical resistance o 384Ω. Calculate the
         specific and equivalent conductance of NaCl solution.
     22. The specific conductance o water is 7.6x10-2Sm-1 and the specific conductance of 0.1M
         aqueous solution of KCl is 1.1639Sm-1. A cell has a resistance of 33.20Ω when filled
         with 0.1M KCl solution and 300Ω when filled with 0.1M CH3COOH solution. Calculate
         the molar conductance of acetic acid.
     23. A conductivity cell filled with 0.1M solution of KCl at 25C has a measured resistance of
         24.96Ω. Calculate the cell constant if the specific conductance for 0.1M solution of KCl
         is 0.011639Ω-1cm-1 and that for conductivity water is 7.5x10-8Ω-1cm-1. When the cell is
         filled with a 0.01M solution of CH3COOH, the cell resistance is 1982Ω. Calculate the
         molar conductivity of CH3COOH at this concentration.

Answers

1            0.56 cm-1                            2                        1.106 cm-1
3            1.39 cm-1                            4                        0.2765 cm-1
5            0.4668 cm-1                          6                        419.04 Ω-1cm2mol-1
7            25.73 Ω-1cm2mol-1                    8                        400 Ω-1cm2eq-1
9            1.106 cm-1                           10                       104.16 Ω-1cm2eq-1
11           400 Ω-1cm2eq-1                       12                       4.6 Ω-1cm2eq-1
13           30.57 Ω-1cm2eq-1                     14                       61.069 Ω-1cm2eq-1
15           419.047 Ω-1cm2eq-1                   16                       200 Ω-1cm2eq-1
17           0.0015645 Ω-cm-1                     18                       0.00238 Ω-1cm-1
             208.6 Ω-1cm2mol-1                                             238 Ω-1cm2mol-1
19           0.0082614 Ω-1cm-1                    20                       0.0021135 cm-1
             826.14 Ω-1cm2mol-1                                            4.112 x 10-4 Ω-1cm-1
41.12 Ω-1cm2eq-1
21   1.1902 x 10-3 Ω-1cm-1   22   0.528 Scm2mol-1
     119.02 Ω-1cm2eq-1
23   14.652 Ω-1cm2mol-1

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Conductance tutorial

  • 1. TUTORIAL SHEET-I (CONDUCTANCE) 1. Specific conductance of a decinormal solution of KCl at 18 C is 1.12Sm-1. The resistance of a conductivity cell containing solution at the same temperature is 55ohm. What is the cell constant? 2. The specific conductance of an N/50 solution of KCl at 25C is 0.002765 cm-1Ω-1. If the resistance of cell containing this solution is 400Ω, what is the cell constant? 3. The specific conductance of N/5 KCl solution at 25C is 0.002780mho. The resistance of the cell containing this solution is 500Ω. Calculate the cell constant. 4. If the resistance of N/50 KCl solution in a cell is 100Ω, calculate the cell constant. 5. Calculate the cell constant if the dimensions of the electrodes are 0.95cm & 1.015cm and the two electrodes are separated by 0.45cm. 6. The resistance of a 0.01M solution of an electrolyte is 210Ω at 25C. Calculate the molar conductance of the solution at the same temperature. The cell constant is 0.88cm-1. 7. The resistance of 0.5M solution of an electrolyte in a cell was found to be 45Ω. Calculate the molar conductance of the solution if the electrodes of the cell are 2.2cm apart and have an area of 3.8cm2. 8. 0.5N solution of a salt placed between two platinum electrodes, 20cm apart and of area 4cm2 has a resistance of 25Ω. Calculate equivalent conductance of the solution. 9. The specific conductance of an N/10 solution of KCl at 25C is 0.002765Ω-1. If the resistance of cell containing this solution is 400Ω, what is the cell constant? 10. The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80cm apart and 5.4cm2 in area was found to be 32Ω. Calculate equivalent conductance of the solution. 11. 0.5N solution of a salt placed between two platinum electrodes, 20cm apart and of area 4cm2 has a resistance of 25Ω. Calculate the equivalent conductance of the solution. 12. The resistance of 0.1N solution is 2.5x103Ω. Calculate equivalent conductance of the solution. Cell constant = 1.15cm-1. 13. The resistance of a 0.5N solution of an electrolyte occupying a volume between two platinum electrodes 1.72cm apart having an area o 4.5cm2 is 25Ω. Calculate the equivalent conductance of the solution. 14. 0.1N solution of CH3COONa was placed between two electrodes 0.72cm apart with an area of 2.25cm2. The resistance of solution was 52.40Ω. Calculate the specific and equivalent conductance of the solution. 15. The resistance of N/100 solution of an electrolyte was found to be 210Ω at 25C. Calculate the equivalent conductance of the solution. (Cell constant = 0.88). 16. Resistance of 0.01M aqueous solution of an electrolyte at room temperature is 420Ω and cell constant is 84m-1. Calculate the molar conductance.
  • 2. 17. Calculate the specific and molar conductance of a 0.0075M aqueous solution of KCl. Given: conductance is 1.49x10-3S and cell constant is 1.05cm-1. 18. A conductivity cell is filled with 0.05M KCl. Its specific conductance and observed resistance is 6.67x10-3Ω-1cm-1 and 243Ω, respectively. When the cell is filled with 0.01M NaOH, observed resistance is 681Ω. Calculate specific and molar conductance of 0.01M NaOH. 19. The resistance of a cell containing 0.02M KCl solution at 25C was found to be 17Ω. The specific conductance of this solution is 27.7x10-3Ω-1cm-1. An exactly 0.01M solution of another substance in the same cell had a resistance of 57Ω. Calculate the equivalent conductance of this substance. 20. In a particular cell, 0.01M solution of KCl gave a resistance of 15Ω while 0.01M solution of HCl gave a resistance of 51.4Ω at the same temperature. If the specific conductance o 0.01M KCl is 0.1409Sm-1, calculate cell constant, specific conductance and equivalent conductance of HCl solution. 21. A conductivity cell on being filled with a 0.02M solution at 25C showed a resistance of 165Ω. The specific conductance of KCl solution used is 2.77x10-3Ω-1cm-1. The same cell containing 0.01M NaCl solution gave an electrical resistance o 384Ω. Calculate the specific and equivalent conductance of NaCl solution. 22. The specific conductance o water is 7.6x10-2Sm-1 and the specific conductance of 0.1M aqueous solution of KCl is 1.1639Sm-1. A cell has a resistance of 33.20Ω when filled with 0.1M KCl solution and 300Ω when filled with 0.1M CH3COOH solution. Calculate the molar conductance of acetic acid. 23. A conductivity cell filled with 0.1M solution of KCl at 25C has a measured resistance of 24.96Ω. Calculate the cell constant if the specific conductance for 0.1M solution of KCl is 0.011639Ω-1cm-1 and that for conductivity water is 7.5x10-8Ω-1cm-1. When the cell is filled with a 0.01M solution of CH3COOH, the cell resistance is 1982Ω. Calculate the molar conductivity of CH3COOH at this concentration. Answers 1 0.56 cm-1 2 1.106 cm-1 3 1.39 cm-1 4 0.2765 cm-1 5 0.4668 cm-1 6 419.04 Ω-1cm2mol-1 7 25.73 Ω-1cm2mol-1 8 400 Ω-1cm2eq-1 9 1.106 cm-1 10 104.16 Ω-1cm2eq-1 11 400 Ω-1cm2eq-1 12 4.6 Ω-1cm2eq-1 13 30.57 Ω-1cm2eq-1 14 61.069 Ω-1cm2eq-1 15 419.047 Ω-1cm2eq-1 16 200 Ω-1cm2eq-1 17 0.0015645 Ω-cm-1 18 0.00238 Ω-1cm-1 208.6 Ω-1cm2mol-1 238 Ω-1cm2mol-1 19 0.0082614 Ω-1cm-1 20 0.0021135 cm-1 826.14 Ω-1cm2mol-1 4.112 x 10-4 Ω-1cm-1
  • 3. 41.12 Ω-1cm2eq-1 21 1.1902 x 10-3 Ω-1cm-1 22 0.528 Scm2mol-1 119.02 Ω-1cm2eq-1 23 14.652 Ω-1cm2mol-1