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Project -1 (Cold Storage Case Study)
Saleesh Satheeshchandran
Table of Contents
Problem 1
1. Find mean cold storage temperature for Summer, Winter and Rainy
Season
2. Find overall mean for the full year
3. Find Standard Deviation for the full year
4. Assume Normal distribution, what is the probability of temperature
having fallen below 2 degree C?
5. Assume Normal distribution, what is the probability of temperature
having gone above 4 degree C?
6. What will be the penalty for the AMC Company?
Problem 2
1. State the Hypothesis, do the calculation using z test
2. State the Hypothesis, do the calculation using t test
3. Give your inference after doing both the tests
Problem 1
1. Find mean cold storage temperature for Summer, Winter and Rainy
Season
Summer – 3.15
Winter – 2.70
Rainy – 3.04
2. Find overall mean for the full year
Overall Mean – 2.96
R Studio – Screen shot
3. Find Standard Deviation for the full year
SD for full year – 0.51
R Studio screenshot
4. Assume Normal distribution, what is the probability of temperature
having fallen below 2 degree C?
Ans. 2.99%
5. Assume Normal distribution, what is the probability of temperature
having gone above 4 degree C?
Ans. 2.07%
6. What will be the penalty for the AMC Company?
Ans. The probability of temperature deviating from 2-4 interval is 5.06%.
As per the contract, if this goes above 5%, the AMC has to pay 25%
penalty.
Excel screenshot
R- screenshot
Problem - 2
1. State the Hypothesis, do the calculation using z test
Null Hypothesis (H0) : Temperature of the storage remains less than or
equal to 3.9 degree Celsius
Alternate Hypothesis (H1) : Temperature of the storage goes above 3.9
degree Celsius
Alpha = .1
n = 35
xbar = 3.974
mue0 = 3.9
sigma = 0.51
z=(xbar-mue0)/(sigma/sqrtn) = 0.858411
Pvalue=pnorm(-abs(z)) = 0.1953326
Since Pvalue is greater than Alpha, Null Hypothesis is accepted. Hence, the
temperature of the storage does not go above 3.9 degree Celsius.
R Screenshot
2. State the Hypothesis, do the calculation using t test
Null Hypothesis (H0) : Temperature of the storage remains less than or
equal to 3.9 degree Celsius
Alternate Hypothesis (H1) : Temperature of the storage goes above 3.9
degree Celsius
Alpha = .1
n = 35
xbar = 3.974
mue0 = 3.9
sd = 0.16
tstat=(xbar-mue0)/(sd/sqrtn) = 2.736187
Pvalue1=pt(tstat,34)= 0.9950957
Since Pvalue1 is greater than Alpha, Null Hypothesis is accepted. Hence, the
temperature of the storage does not go above 3.9 degree Celsius.
RStudio Screenshot
3. Give your inference after doing both the tests (10 marks)
We have done a t-test and an z-test to determine if the temperature range of
the storage facility goes above 3.9 degree Celsius in a statistically significant
manner.
In z-test we have calculated the z-value and then the Pvalue. The Pvalue is
more than the alpha (0.1). Hence, we have a 90% confidence in the result.
In t-test we have calculated the tstat value and then the Pvalue. The Pvalue is
more than the alpha (0.1). Hence, we have a 90% confidence in the result.
Since both the tests are confirming the null hypothesis, it can be safely
assumed that the storage facility does not have issue with its functioning.
There might be some issue with the procurement department and the
necessary investigations need to be done.

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Cold storage case study

  • 1. Project -1 (Cold Storage Case Study) Saleesh Satheeshchandran
  • 2. Table of Contents Problem 1 1. Find mean cold storage temperature for Summer, Winter and Rainy Season 2. Find overall mean for the full year 3. Find Standard Deviation for the full year 4. Assume Normal distribution, what is the probability of temperature having fallen below 2 degree C? 5. Assume Normal distribution, what is the probability of temperature having gone above 4 degree C? 6. What will be the penalty for the AMC Company? Problem 2 1. State the Hypothesis, do the calculation using z test 2. State the Hypothesis, do the calculation using t test 3. Give your inference after doing both the tests
  • 3. Problem 1 1. Find mean cold storage temperature for Summer, Winter and Rainy Season Summer – 3.15 Winter – 2.70 Rainy – 3.04 2. Find overall mean for the full year Overall Mean – 2.96 R Studio – Screen shot
  • 4. 3. Find Standard Deviation for the full year SD for full year – 0.51 R Studio screenshot
  • 5. 4. Assume Normal distribution, what is the probability of temperature having fallen below 2 degree C? Ans. 2.99% 5. Assume Normal distribution, what is the probability of temperature having gone above 4 degree C? Ans. 2.07% 6. What will be the penalty for the AMC Company? Ans. The probability of temperature deviating from 2-4 interval is 5.06%. As per the contract, if this goes above 5%, the AMC has to pay 25% penalty. Excel screenshot R- screenshot
  • 6. Problem - 2 1. State the Hypothesis, do the calculation using z test Null Hypothesis (H0) : Temperature of the storage remains less than or equal to 3.9 degree Celsius Alternate Hypothesis (H1) : Temperature of the storage goes above 3.9 degree Celsius Alpha = .1 n = 35 xbar = 3.974 mue0 = 3.9 sigma = 0.51 z=(xbar-mue0)/(sigma/sqrtn) = 0.858411 Pvalue=pnorm(-abs(z)) = 0.1953326 Since Pvalue is greater than Alpha, Null Hypothesis is accepted. Hence, the temperature of the storage does not go above 3.9 degree Celsius. R Screenshot
  • 7. 2. State the Hypothesis, do the calculation using t test Null Hypothesis (H0) : Temperature of the storage remains less than or equal to 3.9 degree Celsius Alternate Hypothesis (H1) : Temperature of the storage goes above 3.9 degree Celsius Alpha = .1 n = 35 xbar = 3.974 mue0 = 3.9 sd = 0.16 tstat=(xbar-mue0)/(sd/sqrtn) = 2.736187 Pvalue1=pt(tstat,34)= 0.9950957 Since Pvalue1 is greater than Alpha, Null Hypothesis is accepted. Hence, the temperature of the storage does not go above 3.9 degree Celsius. RStudio Screenshot
  • 8. 3. Give your inference after doing both the tests (10 marks) We have done a t-test and an z-test to determine if the temperature range of the storage facility goes above 3.9 degree Celsius in a statistically significant manner. In z-test we have calculated the z-value and then the Pvalue. The Pvalue is more than the alpha (0.1). Hence, we have a 90% confidence in the result. In t-test we have calculated the tstat value and then the Pvalue. The Pvalue is more than the alpha (0.1). Hence, we have a 90% confidence in the result. Since both the tests are confirming the null hypothesis, it can be safely assumed that the storage facility does not have issue with its functioning. There might be some issue with the procurement department and the necessary investigations need to be done.