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Course: Quantum Electronics
Arpan Deyasi
Calculation of
Transmission Coefficient using PMM
1
Arpan Deyasi, RCCIIT
1/17/2021
1/17/2021 Arpan Deyasi, RCCIIT 2
Graphical representation of Transmission Coefficient
E0
E
T(E)
E1 E2 E3
Drawbacks of Transfer Matrix Technique
1/17/2021 3Arpan Deyasi, RCCIIT
Step potential well: Ideal case
Real quantum well can’t have step potential profile,
in fact, different complex potential profiles are
considered for application purpose
1/17/2021 4Arpan Deyasi, RCCIIT
Solution
We have to consider a mathematical technique
where variation of potential at each point of
both barrier and well layers can be incorporated
V = 0
V = V0
1/17/2021 5Arpan Deyasi, RCCIIT
Change required in Mathematical Formulation
*
2 2
2 ( )wm z E
κ =

*
0
1 2
2 ( )( )bm z E V
κ
−
=

for well for barrier
1/17/2021 6Arpan Deyasi, RCCIIT
We have to make a generalized wave-vector
for both barrier and well
Change required in Mathematical Formulation
Why?
Then we will be able to incorporate simultaneous
variation of barrier and well potentials
1/17/2021 7Arpan Deyasi, RCCIIT
Generalized wave-vector
*
2
2 ( )( )j j
j
m z E V
κ
−
=

calculated at jth point
1/17/2021 8Arpan Deyasi, RCCIIT
Z
DQWTB structure
j j+1
1/17/2021 9Arpan Deyasi, RCCIIT
Generalized wave equations
exp( ) exp( )j j j j jA i z B i zψ κ κ= + −
1 1 1 1 1exp( ) exp( )j j j j jC i z D i zψ κ κ+ + + + += + −
1/17/2021 10Arpan Deyasi, RCCIIT
Generalized boundary conditions
1j j+Ψ =Ψ
1j jd d
dz dz
+Ψ Ψ
=
1/17/2021 11Arpan Deyasi, RCCIIT
At interface
1j j+Ψ =Ψ
1 1 1 1
exp( ) exp( )
exp( ) exp( )
j j j j
j j j j
A i z B i z
C i z D i z
κ κ
κ κ+ + + +
+ −
= + −
1/17/2021 12Arpan Deyasi, RCCIIT
At interface
1' 'j j+Ψ =Ψ
1 1 1 1 1 1
exp( ) exp( )
exp( ) exp( )
j j j j j j
j j j j j j
i A i z i B i z
i C i z i D i z
κ κ κ κ
κ κ κ κ+ + + + + +
− −
= − −
1 1 1 1 1 1
exp( ) exp( )
exp( ) exp( )
j j j j j j
j j j j j j
A i z B i z
C i z D i z
κ κ κ κ
κ κ κ κ+ + + + + +
− −
= − −
1/17/2021 13Arpan Deyasi, RCCIIT
At interface
1
1 1
1
1 1
exp( ) exp( )
exp( )
exp( )
j j j j
j
j j
j
j
j j
j
A i z B i z
C i z
D i z
κ κ
κ
κ
κ
κ
κ
κ
+
+ +
+
+ +
− −
 
=   
 
 
− −  
 
1/17/2021 14Arpan Deyasi, RCCIIT
At interface
1 1
1 1 1 1
exp( ) exp( )
exp( ) exp( )
j j j j
j j
j j j j
j j
A i z B i z
C i z D i z
κ κ
κ κ
κ κ
κ κ
+ +
+ + + +
− −
   
= − −      
   
1 1 1 1
exp( ) exp( )
exp( ) exp( )
j j j j
j j j j
A i z B i z
C i z D i z
κ κ
κ κ+ + + +
+ −
= + −
In matrix
notation
1
1 1
1
1 1
1 1
1 1
j j
j j
j j
j j
A C
B D
κ κ
κ κ
+
+ +
+
 
      
=      −−      
1/17/2021 15Arpan Deyasi, RCCIIT
1
1 1
1
1 1
1 1
1 1
j j
j j
j j
j j
A C
B D
κ κ
κ κ
+
+ +
+
 
      
=      −−      
At interface
1
1
1 1
1
1 1
1 1
1 1
j j
j j
j j
j j
A C
B D
κ κ
κ κ
−
+
+ +
+
 
      
=      −−      
1/17/2021 Arpan Deyasi, RCCIIT 16
At interface
1
1 1
1
1 1
1 11
1 12
j j
j j
j j
j j
A C
B D
κ κ
κ κ
+
+ +
+
 
      
=      −−      
1 1
1
11 1
1 1
1
2
1 1
j j
j jj j
j jj j
j j
A C
B D
κ κ
κ κ
κ κ
κ κ
+ +
+
++ +
    
+ −              
=    
       
− +       
     
1/17/2021 Arpan Deyasi, RCCIIT 17
1 1
1 1
1 1
1
2
1 1
j j
j j
j
j j
j j
P
κ κ
κ κ
κ κ
κ κ
+ +
+ +
    
+ −           
=  
    
− +       
     
At interface
Let
Pj : junction matrix
1/17/2021 18Arpan Deyasi, RCCIIT
Z
DQWTB structure
j j+1Lj
1/17/2021 Arpan Deyasi, RCCIIT 19
Significance of Lj
travelling from ‘j’ to ‘j+1’ with a distance ‘Lj’
matches the positive coefficients as well as
negative coefficients
1/17/2021 Arpan Deyasi, RCCIIT 20
1exp( )j j j jA i L Cκ +=
For Lj
1exp( )j j j jB i L Dκ +− =
In matrix
notation
1
1
exp( ) 0
0 exp( )
j j j j
j j j j
i L A C
i L B D
κ
κ
+
+
    
=    −    
1/17/2021 Arpan Deyasi, RCCIIT 21
For Lj
1
1
exp( ) 0
0 exp( )
j j j j
j j j j
A i L C
B i L D
κ
κ
+
+
−    
=    
    
exp( ) 0
0 exp( )
j j
L
j j
i L
P
i L
κ
κ
− 
=  
 
Let
PL : step matrix
1/17/2021 Arpan Deyasi, RCCIIT 22
Q: How to calculate propagation matrix?
It is the Cartesian product of
Junction matrix with Step matrix
1/17/2021 Arpan Deyasi, RCCIIT 23
Propagation Matrix calculation
1 1
1 1
1 1
1
2
1 1
j j
j j
j
j j
j j
P
κ κ
κ κ
κ κ
κ κ
+ +
+ +
    
+ −           
=  
    
− +       
     
exp( ) 0
0 exp( )
j j
L
j j
i L
P
i L
κ
κ
− 
=  
 
1/17/2021 Arpan Deyasi, RCCIIT 24
Propagation Matrix calculation
j LP P P= ×
1 1
1 1
1 1
1
2
1 1
exp( ) 0
0 exp( )
j j
j j
j j
j j
j j
j j
P
i L
i L
κ κ
κ κ
κ κ
κ κ
κ
κ
+ +
+ +
    
+ −           
=  
    
− +       
     
− 
× 
 
1/17/2021 Arpan Deyasi, RCCIIT 25
Propagation Matrix calculation
1 1
1 1
exp( ) 1 exp( ) 1
1
2
exp( ) 1 exp( ) 1
j j
j j j j
j j
j j
j j j j
j j
i L i L
P
i L i L
κ κ
κ κ
κ κ
κ κ
κ κ
κ κ
+ +
+ +
    
− + − −           
=  
    
− +       
     
11 12
21 22
P P
P
P P
 
=  
 
1/17/2021 Arpan Deyasi, RCCIIT 26
Propagation Matrix calculation
1
1
j j
j j
A C
P
B D
+
+
   
=   
   
111 12
121 22
j j
j j
A CP P
B DP P
+
+
    
=    
    
1/17/2021 Arpan Deyasi, RCCIIT 27
Propagation Matrix calculation
11 1 12 1j j jA P C P D+ += +
21 1 22 1j j jB P C P D+ += +
111 12
121 22
j j
j j
A CP P
B DP P
+
+
    
=    
    
1/17/2021 Arpan Deyasi, RCCIIT 28
P11 P12
P21 P22
Aj
Bj
Cj+1
Dj+1
P12 is the transmission coefficient
when the wave is traversing from port 2 to port 1
and port 1 is terminated by matched load
1/17/2021 Arpan Deyasi, RCCIIT 29
P12 = 0 for practical device
11
1
j
j
A
P
C +
=
( )
2
1
*
11 11
1j
j
C
T E
A P P
+
 
= =  
 
11 1 12 1j j jA P C P D+ += +
1/17/2021 Arpan Deyasi, RCCIIT 30
Graphical representation of Transmission Coefficient
E0
E
T(E)
E1 E2 E3

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Calculation of transmission coefficient using Propagation Matrix Method

  • 1. Course: Quantum Electronics Arpan Deyasi Calculation of Transmission Coefficient using PMM 1 Arpan Deyasi, RCCIIT 1/17/2021
  • 2. 1/17/2021 Arpan Deyasi, RCCIIT 2 Graphical representation of Transmission Coefficient E0 E T(E) E1 E2 E3
  • 3. Drawbacks of Transfer Matrix Technique 1/17/2021 3Arpan Deyasi, RCCIIT Step potential well: Ideal case Real quantum well can’t have step potential profile, in fact, different complex potential profiles are considered for application purpose
  • 4. 1/17/2021 4Arpan Deyasi, RCCIIT Solution We have to consider a mathematical technique where variation of potential at each point of both barrier and well layers can be incorporated V = 0 V = V0
  • 5. 1/17/2021 5Arpan Deyasi, RCCIIT Change required in Mathematical Formulation * 2 2 2 ( )wm z E κ =  * 0 1 2 2 ( )( )bm z E V κ − =  for well for barrier
  • 6. 1/17/2021 6Arpan Deyasi, RCCIIT We have to make a generalized wave-vector for both barrier and well Change required in Mathematical Formulation Why? Then we will be able to incorporate simultaneous variation of barrier and well potentials
  • 7. 1/17/2021 7Arpan Deyasi, RCCIIT Generalized wave-vector * 2 2 ( )( )j j j m z E V κ − =  calculated at jth point
  • 8. 1/17/2021 8Arpan Deyasi, RCCIIT Z DQWTB structure j j+1
  • 9. 1/17/2021 9Arpan Deyasi, RCCIIT Generalized wave equations exp( ) exp( )j j j j jA i z B i zψ κ κ= + − 1 1 1 1 1exp( ) exp( )j j j j jC i z D i zψ κ κ+ + + + += + −
  • 10. 1/17/2021 10Arpan Deyasi, RCCIIT Generalized boundary conditions 1j j+Ψ =Ψ 1j jd d dz dz +Ψ Ψ =
  • 11. 1/17/2021 11Arpan Deyasi, RCCIIT At interface 1j j+Ψ =Ψ 1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j A i z B i z C i z D i z κ κ κ κ+ + + + + − = + −
  • 12. 1/17/2021 12Arpan Deyasi, RCCIIT At interface 1' 'j j+Ψ =Ψ 1 1 1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j j j j j i A i z i B i z i C i z i D i z κ κ κ κ κ κ κ κ+ + + + + + − − = − − 1 1 1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j j j j j A i z B i z C i z D i z κ κ κ κ κ κ κ κ+ + + + + + − − = − −
  • 13. 1/17/2021 13Arpan Deyasi, RCCIIT At interface 1 1 1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j j j j j A i z B i z C i z D i z κ κ κ κ κ κ κ κ + + + + + + − −   =        − −    
  • 14. 1/17/2021 14Arpan Deyasi, RCCIIT At interface 1 1 1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j j j j j A i z B i z C i z D i z κ κ κ κ κ κ κ κ + + + + + + − −     = − −           1 1 1 1 exp( ) exp( ) exp( ) exp( ) j j j j j j j j A i z B i z C i z D i z κ κ κ κ+ + + + + − = + − In matrix notation 1 1 1 1 1 1 1 1 1 1 j j j j j j j j A C B D κ κ κ κ + + + +          =      −−      
  • 15. 1/17/2021 15Arpan Deyasi, RCCIIT 1 1 1 1 1 1 1 1 1 1 j j j j j j j j A C B D κ κ κ κ + + + +          =      −−       At interface 1 1 1 1 1 1 1 1 1 1 1 j j j j j j j j A C B D κ κ κ κ − + + + +          =      −−      
  • 16. 1/17/2021 Arpan Deyasi, RCCIIT 16 At interface 1 1 1 1 1 1 1 11 1 12 j j j j j j j j A C B D κ κ κ κ + + + +          =      −−       1 1 1 11 1 1 1 1 2 1 1 j j j jj j j jj j j j A C B D κ κ κ κ κ κ κ κ + + + ++ +      + −               =             − +             
  • 17. 1/17/2021 Arpan Deyasi, RCCIIT 17 1 1 1 1 1 1 1 2 1 1 j j j j j j j j j P κ κ κ κ κ κ κ κ + + + +      + −            =        − +              At interface Let Pj : junction matrix
  • 18. 1/17/2021 18Arpan Deyasi, RCCIIT Z DQWTB structure j j+1Lj
  • 19. 1/17/2021 Arpan Deyasi, RCCIIT 19 Significance of Lj travelling from ‘j’ to ‘j+1’ with a distance ‘Lj’ matches the positive coefficients as well as negative coefficients
  • 20. 1/17/2021 Arpan Deyasi, RCCIIT 20 1exp( )j j j jA i L Cκ += For Lj 1exp( )j j j jB i L Dκ +− = In matrix notation 1 1 exp( ) 0 0 exp( ) j j j j j j j j i L A C i L B D κ κ + +      =    −    
  • 21. 1/17/2021 Arpan Deyasi, RCCIIT 21 For Lj 1 1 exp( ) 0 0 exp( ) j j j j j j j j A i L C B i L D κ κ + + −     =          exp( ) 0 0 exp( ) j j L j j i L P i L κ κ −  =     Let PL : step matrix
  • 22. 1/17/2021 Arpan Deyasi, RCCIIT 22 Q: How to calculate propagation matrix? It is the Cartesian product of Junction matrix with Step matrix
  • 23. 1/17/2021 Arpan Deyasi, RCCIIT 23 Propagation Matrix calculation 1 1 1 1 1 1 1 2 1 1 j j j j j j j j j P κ κ κ κ κ κ κ κ + + + +      + −            =        − +              exp( ) 0 0 exp( ) j j L j j i L P i L κ κ −  =    
  • 24. 1/17/2021 Arpan Deyasi, RCCIIT 24 Propagation Matrix calculation j LP P P= × 1 1 1 1 1 1 1 2 1 1 exp( ) 0 0 exp( ) j j j j j j j j j j j j P i L i L κ κ κ κ κ κ κ κ κ κ + + + +      + −            =        − +              −  ×   
  • 25. 1/17/2021 Arpan Deyasi, RCCIIT 25 Propagation Matrix calculation 1 1 1 1 exp( ) 1 exp( ) 1 1 2 exp( ) 1 exp( ) 1 j j j j j j j j j j j j j j j j i L i L P i L i L κ κ κ κ κ κ κ κ κ κ κ κ + + + +      − + − −            =        − +              11 12 21 22 P P P P P   =    
  • 26. 1/17/2021 Arpan Deyasi, RCCIIT 26 Propagation Matrix calculation 1 1 j j j j A C P B D + +     =        111 12 121 22 j j j j A CP P B DP P + +      =         
  • 27. 1/17/2021 Arpan Deyasi, RCCIIT 27 Propagation Matrix calculation 11 1 12 1j j jA P C P D+ += + 21 1 22 1j j jB P C P D+ += + 111 12 121 22 j j j j A CP P B DP P + +      =         
  • 28. 1/17/2021 Arpan Deyasi, RCCIIT 28 P11 P12 P21 P22 Aj Bj Cj+1 Dj+1 P12 is the transmission coefficient when the wave is traversing from port 2 to port 1 and port 1 is terminated by matched load
  • 29. 1/17/2021 Arpan Deyasi, RCCIIT 29 P12 = 0 for practical device 11 1 j j A P C + = ( ) 2 1 * 11 11 1j j C T E A P P +   = =     11 1 12 1j j jA P C P D+ += +
  • 30. 1/17/2021 Arpan Deyasi, RCCIIT 30 Graphical representation of Transmission Coefficient E0 E T(E) E1 E2 E3