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Chapter 7
Structure and Synthesis
of Alkenes
Organic Chemistry
Chapter 7 2
Functional Group
• Pi bond is the functional group.
• More reactive than sigma bond.
• Bond dissociation energies:
C=C BDE 146 kcal/mol
C-C BDE -83 kcal/mol
Pi bond 63 kcal/mol
=>
Chapter 7 3
Orbital Description
• Sigma bonds around C are sp2
hybridized.
• Angles are approximately 120 degrees.
• No nonbonding electrons.
• Molecule is planar around the double bond.
• Pi bond is formed by the sideways overlap of
parallel p orbitals perpendicular to the plane
of the molecule.
=>
Chapter 7 4
Bond Lengths and Angles
• Hybrid orbitals have more s character.
• Pi overlap brings carbon atoms closer.
• Bond angle with pi orbitals increases.
Angle C=C-H is 121.7°
Angle H-C-H is 116. 6° =>
Chapter 7 5
Pi Bond
• Sideways overlap of parallel p orbitals.
• No rotation is possible without breaking
the pi bond (63 kcal/mole).
• Cis isomer cannot become trans
without a chemical reaction occurring.
=>
Chapter 7 6
Elements of
Unsaturation
• A saturated hydrocarbon: CnH2n+2
• Each pi bond (and each ring) decreases the
number of H’s by two.
• Each of these is an element of unsaturation.
• To calculate: find number of H’s if it were
saturated, subtract the actual number of H’s,
then divide by 2.
=>
Chapter 7 7
Propose a Structure:
• First calculate the number of elements of
unsaturation.
• Remember:
A double bond is one element of unsaturation.
A ring is one element of unsaturation.
A triple bond is two elements of unsaturation. =>
for C5H8
Chapter 7 8
Heteroatoms
• Halogens take the place of hydrogens, so add
their number to the number of H’s.
• Oxygen doesn’t change the C:H ratio, so
ignore oxygen in the formula.
• Nitrogen is trivalent, so it acts like half a
carbon.
C
H
H
C
H
H
N C
H
HH
=>
Chapter 7 9
Structure for C6H7N?
• Since nitrogen counts as half a carbon,
the number of H’s if saturated is
2(6.5) + 2 = 15.
• Number of missing H’s is 15 – 7 = 8.
• Elements of unsaturation is 8 ÷ 2 = 4.
=>
Chapter 7 10
IUPAC Nomenclature
• Parent is longest chain containing the
double bond.
• -ane changes to -ene. (or -diene, -triene)
• Number the chain so that the double
bond has the lowest possible number.
• In a ring, the double bond is assumed to
be between carbon 1 and carbon 2.
=>
Chapter 7 11
Name These Alkenes
CH2 CH CH2 CH3
CH3 C
CH3
CH CH3
CH3
CHCH2CH3
H3C
1-butene
2-methyl-2-butene
3-methylcyclopentene
2-sec-butyl-1,3-cyclohexadiene
3-n-propyl-1-heptene
=>
Chapter 7 12
Alkene Substituents
= CH2
methylene
(methylidene)
- CH = CH2
vinyl
(ethenyl)
- CH2 - CH = CH2
allyl
(2-propenyl)
Name: =>
Chapter 7 13
Common Names
• Usually used for small molecules.
• Examples:
CH2 CH2
ethylene
CH2 CH CH3
propylene
CH2 C CH3
CH3
isobutylene
=>
Chapter 7 14
Cis-trans Isomerism
• Similar groups on same side of double
bond, alkene is cis.
• Similar groups on opposite sides of
double bond, alkene is trans.
• Cycloalkenes are assumed to be cis.
• Trans cycloalkenes are not stable
unless the ring has at least 8 carbons.
=>
Chapter 7 15
Name these:
C C
CH3
H
H
CH3CH2
C C
Br
H
Br
H
trans-2-pentene cis-1,2-dibromoethene
=>
Chapter 7 16
E-Z Nomenclature
• Use the Cahn-Ingold-Prelog rules to
assign priorities to groups attached to
each carbon in the double bond.
• If high priority groups are on the same
side, the name is Z (for zusammen).
• If high priority groups are on opposite
sides, the name is E (for entgegen).
=>
Chapter 7 17
Example, E-Z
C C
H3C
H
Cl
CH2
C C
H
H
CH CH3
Cl1
2
1
2
2Z
2
1
1
2
5E
(2Z, 5E)-3,7-dichloro-2,5-octadiene
=>
Chapter 7 18
Commercial Uses:
Ethylene
=>
Chapter 7 19
Commercial Uses:
Propylene
=>
Chapter 7 20
Other Polymers
=>
Chapter 7 21
Stability of Alkenes
• Measured by heat of hydrogenation:
Alkene + H2 → Alkane + energy
• More heat released, higher energy alkene.
=>
30.3 kcal
27.6 kcal
Chapter 7 22
Substituent Effects
• More substituted alkenes are more stable.
H2C=CH2 < R-CH=CH2 < R-CH=CH-R < R-CH=CR2 < R2C=CR2
unsub. < monosub. < disub. < trisub. < tetra sub.
• Alkyl group stabilizes the double bond.
• Alkene less sterically hindered.
=>
Chapter 7 23
Disubstituted Isomers
• Stability: cis < geminal < trans isomer
• Less stable isomer is higher in energy, has
a more exothermic heat of hydrogenation.
27.6 kcalTrans-2-butene
28.0 kcal(CH3)2C=CH2Isobutylene
28.6 kcalCis-2-butene CH3
C C
CH3
H H
H
C C
CH3
CH3 H
=>
Chapter 7 24
Cycloalkene Stability
• Cis isomer more stable than trans.
• Small rings have additional ring strain.
• Must have at least 8 carbons to form a
stable trans double bond.
• For cyclodecene (and larger) trans
double bond is almost as stable as the
cis.
=>
Chapter 7 25
Bredt’s Rule
• A bridged bicyclic compound cannot
have a double bond at a bridgehead
position unless one of the rings
contains at least eight carbon atoms.
• Examples:
Unstable.
Violates Bredt’s rule
Stable. Double bond
in 8-membered ring.
=>
Chapter 7 26
Physical Properties
• Low boiling points, increasing with mass.
• Branched alkenes have lower boiling points.
• Less dense than water.
• Slightly polar
Pi bond is polarizable, so instantaneous dipole-
dipole interactions occur.
Alkyl groups are electron-donating toward the pi
bond, so may have a small dipole moment.
=>
Chapter 7 27
Polarity Examples
µ = 0.33 D µ = 0
=>
cis-2-butene, bp 4°C
C C
H
H3C
H
CH3
trans-2-butene, bp 1°C
C C
H
H
H3C
CH3
Chapter 7 28
Alkene Synthesis
Overview
• E2 dehydrohalogenation (-HX)
• E1 dehydrohalogenation (-HX)
• Dehalogenation of vicinal dibromides (-X2)
• Dehydration of alcohols (-H2O)
=>
Chapter 7 29
Removing HX via E2
• Strong base abstracts H+
as X-
leaves
from the adjacent carbon.
• Tertiary and hindered secondary alkyl
halides give good yields.
• Use a bulky base if the alkyl halide
usually forms substitution products.
=>
Chapter 7 30
Some Bulky Bases
C
CH3
H3C
CH3
O
_
tert-butoxide
(CH3CH2)3N :
triethylamine
=>
N
H
CH(CH3)2
CH(CH3)2
diisopropylamine
N CH3H3C
2,6-dimethylpyridine
Chapter 7 31
Hofmann Product
• Bulky bases abstract the least hindered H+
• Least substituted alkene is major product.
CH3 C
H
H
C
CH3
Br
CH2
H
CH3CH2O
CH3CH2OH
_
C C
CH3
CH3H
H3C
C C
H
HH3C
CH3CH2
71% 29%
72%28%
C C
H
HH3C
CH3CH2
C C
CH3
CH3H
H3C_
CH3CH2OH
CH3 C
H
H
C
CH3
Br
CH2
H
(CH3)3CO
=>
Chapter 7 32
E2: Diastereomers
Stereospecific reaction: (S, R) produces only
trans product, (R, R) produces only cis.
Ph
Br H
H CH3
Ph
≡
H
Ph CH3
Br
PhH
H
Ph
CH3
Ph
H
Br
CH3Ph
PhH
=>
Chapter 7 33
E2: Cyclohexanes
Leaving groups must be trans diaxial. =>
Chapter 7 34
E2: Vicinal Dibromides
• Remove Br2 from adjacent carbons.
• Bromines must be anti-coplanar (E2).
• Use NaI in acetone, or Zn in acetic acid.
I
-
Br
CH3
H
Br
CH3H
C C
CH3
H
H
H3C
=>
Chapter 7 35
Removing HX via E1
• Secondary or tertiary halides
• Formation of carbocation intermediate
• Weak nucleophile
• Usually have substitution products too
=>
Chapter 7 36
Dehydration of
Alcohols
• Reversible reaction
• Use concentrated sulfuric or phosphoric
acid, remove low-boiling alkene as it
forms.
• Protonation of OH converts it to a good
leaving group, HOH
• Carbocation intermediate, like E1
• Protic solvent removes adjacent H+
=>
Chapter 7 37
Dehydration
Mechanism
C
H
C
O H
S
O
O
O HOH C
H
C
O H
H
HSO4
_
C
H
C
O H
H
C
H
C
H2O:
C C H3O
+
=>
Chapter 7 38
Industrial Methods
• Catalytic cracking of petroleum
Long-chain alkane is heated with a catalyst to
produce an alkene and shorter alkane.
Complex mixtures are produced.
• Dehydrogenation of alkanes
Hydrogen (H2) is removed with heat, catalyst.
Reaction is endothermic, but entropy-favored.
• Neither method is suitable for lab synthesis
=>
Chapter 7 39
End of Chapter 7

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Alkene

  • 1. Chapter 7 Structure and Synthesis of Alkenes Organic Chemistry
  • 2. Chapter 7 2 Functional Group • Pi bond is the functional group. • More reactive than sigma bond. • Bond dissociation energies: C=C BDE 146 kcal/mol C-C BDE -83 kcal/mol Pi bond 63 kcal/mol =>
  • 3. Chapter 7 3 Orbital Description • Sigma bonds around C are sp2 hybridized. • Angles are approximately 120 degrees. • No nonbonding electrons. • Molecule is planar around the double bond. • Pi bond is formed by the sideways overlap of parallel p orbitals perpendicular to the plane of the molecule. =>
  • 4. Chapter 7 4 Bond Lengths and Angles • Hybrid orbitals have more s character. • Pi overlap brings carbon atoms closer. • Bond angle with pi orbitals increases. Angle C=C-H is 121.7° Angle H-C-H is 116. 6° =>
  • 5. Chapter 7 5 Pi Bond • Sideways overlap of parallel p orbitals. • No rotation is possible without breaking the pi bond (63 kcal/mole). • Cis isomer cannot become trans without a chemical reaction occurring. =>
  • 6. Chapter 7 6 Elements of Unsaturation • A saturated hydrocarbon: CnH2n+2 • Each pi bond (and each ring) decreases the number of H’s by two. • Each of these is an element of unsaturation. • To calculate: find number of H’s if it were saturated, subtract the actual number of H’s, then divide by 2. =>
  • 7. Chapter 7 7 Propose a Structure: • First calculate the number of elements of unsaturation. • Remember: A double bond is one element of unsaturation. A ring is one element of unsaturation. A triple bond is two elements of unsaturation. => for C5H8
  • 8. Chapter 7 8 Heteroatoms • Halogens take the place of hydrogens, so add their number to the number of H’s. • Oxygen doesn’t change the C:H ratio, so ignore oxygen in the formula. • Nitrogen is trivalent, so it acts like half a carbon. C H H C H H N C H HH =>
  • 9. Chapter 7 9 Structure for C6H7N? • Since nitrogen counts as half a carbon, the number of H’s if saturated is 2(6.5) + 2 = 15. • Number of missing H’s is 15 – 7 = 8. • Elements of unsaturation is 8 ÷ 2 = 4. =>
  • 10. Chapter 7 10 IUPAC Nomenclature • Parent is longest chain containing the double bond. • -ane changes to -ene. (or -diene, -triene) • Number the chain so that the double bond has the lowest possible number. • In a ring, the double bond is assumed to be between carbon 1 and carbon 2. =>
  • 11. Chapter 7 11 Name These Alkenes CH2 CH CH2 CH3 CH3 C CH3 CH CH3 CH3 CHCH2CH3 H3C 1-butene 2-methyl-2-butene 3-methylcyclopentene 2-sec-butyl-1,3-cyclohexadiene 3-n-propyl-1-heptene =>
  • 12. Chapter 7 12 Alkene Substituents = CH2 methylene (methylidene) - CH = CH2 vinyl (ethenyl) - CH2 - CH = CH2 allyl (2-propenyl) Name: =>
  • 13. Chapter 7 13 Common Names • Usually used for small molecules. • Examples: CH2 CH2 ethylene CH2 CH CH3 propylene CH2 C CH3 CH3 isobutylene =>
  • 14. Chapter 7 14 Cis-trans Isomerism • Similar groups on same side of double bond, alkene is cis. • Similar groups on opposite sides of double bond, alkene is trans. • Cycloalkenes are assumed to be cis. • Trans cycloalkenes are not stable unless the ring has at least 8 carbons. =>
  • 15. Chapter 7 15 Name these: C C CH3 H H CH3CH2 C C Br H Br H trans-2-pentene cis-1,2-dibromoethene =>
  • 16. Chapter 7 16 E-Z Nomenclature • Use the Cahn-Ingold-Prelog rules to assign priorities to groups attached to each carbon in the double bond. • If high priority groups are on the same side, the name is Z (for zusammen). • If high priority groups are on opposite sides, the name is E (for entgegen). =>
  • 17. Chapter 7 17 Example, E-Z C C H3C H Cl CH2 C C H H CH CH3 Cl1 2 1 2 2Z 2 1 1 2 5E (2Z, 5E)-3,7-dichloro-2,5-octadiene =>
  • 18. Chapter 7 18 Commercial Uses: Ethylene =>
  • 19. Chapter 7 19 Commercial Uses: Propylene =>
  • 20. Chapter 7 20 Other Polymers =>
  • 21. Chapter 7 21 Stability of Alkenes • Measured by heat of hydrogenation: Alkene + H2 → Alkane + energy • More heat released, higher energy alkene. => 30.3 kcal 27.6 kcal
  • 22. Chapter 7 22 Substituent Effects • More substituted alkenes are more stable. H2C=CH2 < R-CH=CH2 < R-CH=CH-R < R-CH=CR2 < R2C=CR2 unsub. < monosub. < disub. < trisub. < tetra sub. • Alkyl group stabilizes the double bond. • Alkene less sterically hindered. =>
  • 23. Chapter 7 23 Disubstituted Isomers • Stability: cis < geminal < trans isomer • Less stable isomer is higher in energy, has a more exothermic heat of hydrogenation. 27.6 kcalTrans-2-butene 28.0 kcal(CH3)2C=CH2Isobutylene 28.6 kcalCis-2-butene CH3 C C CH3 H H H C C CH3 CH3 H =>
  • 24. Chapter 7 24 Cycloalkene Stability • Cis isomer more stable than trans. • Small rings have additional ring strain. • Must have at least 8 carbons to form a stable trans double bond. • For cyclodecene (and larger) trans double bond is almost as stable as the cis. =>
  • 25. Chapter 7 25 Bredt’s Rule • A bridged bicyclic compound cannot have a double bond at a bridgehead position unless one of the rings contains at least eight carbon atoms. • Examples: Unstable. Violates Bredt’s rule Stable. Double bond in 8-membered ring. =>
  • 26. Chapter 7 26 Physical Properties • Low boiling points, increasing with mass. • Branched alkenes have lower boiling points. • Less dense than water. • Slightly polar Pi bond is polarizable, so instantaneous dipole- dipole interactions occur. Alkyl groups are electron-donating toward the pi bond, so may have a small dipole moment. =>
  • 27. Chapter 7 27 Polarity Examples µ = 0.33 D µ = 0 => cis-2-butene, bp 4°C C C H H3C H CH3 trans-2-butene, bp 1°C C C H H H3C CH3
  • 28. Chapter 7 28 Alkene Synthesis Overview • E2 dehydrohalogenation (-HX) • E1 dehydrohalogenation (-HX) • Dehalogenation of vicinal dibromides (-X2) • Dehydration of alcohols (-H2O) =>
  • 29. Chapter 7 29 Removing HX via E2 • Strong base abstracts H+ as X- leaves from the adjacent carbon. • Tertiary and hindered secondary alkyl halides give good yields. • Use a bulky base if the alkyl halide usually forms substitution products. =>
  • 30. Chapter 7 30 Some Bulky Bases C CH3 H3C CH3 O _ tert-butoxide (CH3CH2)3N : triethylamine => N H CH(CH3)2 CH(CH3)2 diisopropylamine N CH3H3C 2,6-dimethylpyridine
  • 31. Chapter 7 31 Hofmann Product • Bulky bases abstract the least hindered H+ • Least substituted alkene is major product. CH3 C H H C CH3 Br CH2 H CH3CH2O CH3CH2OH _ C C CH3 CH3H H3C C C H HH3C CH3CH2 71% 29% 72%28% C C H HH3C CH3CH2 C C CH3 CH3H H3C_ CH3CH2OH CH3 C H H C CH3 Br CH2 H (CH3)3CO =>
  • 32. Chapter 7 32 E2: Diastereomers Stereospecific reaction: (S, R) produces only trans product, (R, R) produces only cis. Ph Br H H CH3 Ph ≡ H Ph CH3 Br PhH H Ph CH3 Ph H Br CH3Ph PhH =>
  • 33. Chapter 7 33 E2: Cyclohexanes Leaving groups must be trans diaxial. =>
  • 34. Chapter 7 34 E2: Vicinal Dibromides • Remove Br2 from adjacent carbons. • Bromines must be anti-coplanar (E2). • Use NaI in acetone, or Zn in acetic acid. I - Br CH3 H Br CH3H C C CH3 H H H3C =>
  • 35. Chapter 7 35 Removing HX via E1 • Secondary or tertiary halides • Formation of carbocation intermediate • Weak nucleophile • Usually have substitution products too =>
  • 36. Chapter 7 36 Dehydration of Alcohols • Reversible reaction • Use concentrated sulfuric or phosphoric acid, remove low-boiling alkene as it forms. • Protonation of OH converts it to a good leaving group, HOH • Carbocation intermediate, like E1 • Protic solvent removes adjacent H+ =>
  • 37. Chapter 7 37 Dehydration Mechanism C H C O H S O O O HOH C H C O H H HSO4 _ C H C O H H C H C H2O: C C H3O + =>
  • 38. Chapter 7 38 Industrial Methods • Catalytic cracking of petroleum Long-chain alkane is heated with a catalyst to produce an alkene and shorter alkane. Complex mixtures are produced. • Dehydrogenation of alkanes Hydrogen (H2) is removed with heat, catalyst. Reaction is endothermic, but entropy-favored. • Neither method is suitable for lab synthesis =>
  • 39. Chapter 7 39 End of Chapter 7