Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
De Alembert’s Principle and Generalized Force, a technical discourse on Class...Manmohan Dash
A technical discourse on formal classical mechanics. This is a 12 slide introduction to the basics of how Newton's Laws are generalized into a Lagrangian Dynamics apt at the level of an advance student of Physics.
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
De Alembert’s Principle and Generalized Force, a technical discourse on Class...Manmohan Dash
A technical discourse on formal classical mechanics. This is a 12 slide introduction to the basics of how Newton's Laws are generalized into a Lagrangian Dynamics apt at the level of an advance student of Physics.
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
12. kinetics of particles impulse momentum methodEkeeda
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes.
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Ekeeda Provides Online Civil Engineering Degree Subjects Courses, Video Lectures for All Engineering Universities. Video Tutorials Covers Subjects of Mechanical Engineering Degree.
Kinetics of particles impulse momentum methodEkeeda
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11. kinetics of particles work energy methodEkeeda
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
Ekeeda Provides Online Video Lectures for Civil Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Ekeeda Provides Online Civil Engineering Degree Subjects Courses, Video Lectures for All Engineering Universities. Video Tutorials Covers Subjects of Mechanical Engineering Degree.
Mechanical Engineering is the Branch of Engineering.The mechanical engineering field requires an understanding of core areas including mechanics, dynamics, thermodynamics, materials science and structural analysis,Fluid Mechanics, Metrology and Instrumentation, Dynamics of Machinery- II, Manufacturing Processes II, Industrial Drafting and Machine Design, Engineering Graphics, Power Plant Engineering. Ekeeda offers Online Mechanical Engineering Courses for all the Subjects as per the Syllabus. Visit us: https://ekeeda.com/streamdetails/stream/mechanical-engineering
Ekeeda Provides Online Video Lectures for Mechanical Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/mechanical-engineering
Ekeeda Provides Online Video Lectures for Mechanical Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/mechanical-engineering
Civil Engineering is the Branch of Engineering.The Civil engineering field requires an understanding of core areas including Mechanics of Solids, Structural Mechanics - I, Building Construction Materials, Surveying - I, Geology and Geotechnical Engineering, Structural Mechanics, Building Construction, Water Resources and Irrigation, Environmental Engineering, Transportation Engineering, Construction and Project Management. Ekeeda offers Online Mechanical Engineering Courses for all the Subjects as per the Syllabus Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Civil Engineering is the Branch of Engineering.The Civil engineering field requires an understanding of core areas including Mechanics of Solids, Structural Mechanics - I, Building Construction Materials, Surveying - I, Geology and Geotechnical Engineering, Structural Mechanics, Building Construction, Water Resources and Irrigation, Environmental Engineering, Transportation Engineering, Construction and Project Management. Ekeeda offers Online Mechanical Engineering Courses for all the Subjects as per the Syllabus Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
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Learn Online Courses of Subject Introduction to Civil Engineering and Engineering Mechanics. Clear the Concepts of Introduction to Civil Engineering and Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/introduction-to-civil-engineering-and-engineering-mechanics
Learn Online Courses of Subject Introduction to Civil Engineering and Engineering Mechanics. Clear the Concepts of Introduction to Civil Engineering and Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/introduction-to-civil-engineering-and-engineering-mechanics
Ekeeda Provides Online Video Lectures for Civil Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Coplanar forces res & comp of forces - for mergeEkeeda
Ekeeda Provides Online Video Lectures for Civil Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Ekeeda Provides Online Video Lectures for Civil Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Ekeeda Provides Online Video Lectures for Civil Engineering Degree Subject Courses for All Engineering Universities. Visit us: https://ekeeda.com/streamdetails/stream/civil-engineering
Infomatica, as it stands today, is a manifestation of our values, toil, and dedication towards imparting knowledge to the pupils of the society. Visit us: http://www.infomaticaacademy.com/
Infomatica, as it stands today, is a manifestation of our values, toil, and dedication towards imparting knowledge to the pupils of the society. Visit us: http://www.infomaticaacademy.com/
Infomatica, as it stands today, is a manifestation of our values, toil, and dedication towards imparting knowledge to the pupils of the society. Visit us/l http://www.infomaticaacademy.com/
Infomatica, as it stands today, is a manifestation of our values, toil, and dedication towards imparting knowledge to the pupils of the society. Visit us: http://www.infomaticaacademy.com/
Infomatica, as it stands today, is a manifestation of our values, toil, and dedication towards imparting knowledge to the pupils of the society. Visit us: http://www.infomaticaacademy.com/
Ekeeda Provides Online Engineering Subjects Video Lectures and Tutorials of Mumbai University (MU) Courses. Visit us: https://ekeeda.com/streamdetails/University/Mumbai-University
Ekeeda Provides Online Engineering Subjects Video Lectures and Tutorials of Mumbai University (MU) Courses. Visit us: https://ekeeda.com/streamdetails/University/Mumbai-University
Ekeeda Provides Online Engineering Subjects Video Lectures and Tutorials of Mumbai University (MU) Courses. Visit us: https://ekeeda.com/streamdetails/University/Mumbai-University
Cosmetic shop management system project report.pdfKamal Acharya
Buying new cosmetic products is difficult. It can even be scary for those who have sensitive skin and are prone to skin trouble. The information needed to alleviate this problem is on the back of each product, but it's thought to interpret those ingredient lists unless you have a background in chemistry.
Instead of buying and hoping for the best, we can use data science to help us predict which products may be good fits for us. It includes various function programs to do the above mentioned tasks.
Data file handling has been effectively used in the program.
The automated cosmetic shop management system should deal with the automation of general workflow and administration process of the shop. The main processes of the system focus on customer's request where the system is able to search the most appropriate products and deliver it to the customers. It should help the employees to quickly identify the list of cosmetic product that have reached the minimum quantity and also keep a track of expired date for each cosmetic product. It should help the employees to find the rack number in which the product is placed.It is also Faster and more efficient way.
Immunizing Image Classifiers Against Localized Adversary Attacksgerogepatton
This paper addresses the vulnerability of deep learning models, particularly convolutional neural networks
(CNN)s, to adversarial attacks and presents a proactive training technique designed to counter them. We
introduce a novel volumization algorithm, which transforms 2D images into 3D volumetric representations.
When combined with 3D convolution and deep curriculum learning optimization (CLO), itsignificantly improves
the immunity of models against localized universal attacks by up to 40%. We evaluate our proposed approach
using contemporary CNN architectures and the modified Canadian Institute for Advanced Research (CIFAR-10
and CIFAR-100) and ImageNet Large Scale Visual Recognition Challenge (ILSVRC12) datasets, showcasing
accuracy improvements over previous techniques. The results indicate that the combination of the volumetric
input and curriculum learning holds significant promise for mitigating adversarial attacks without necessitating
adversary training.
Water scarcity is the lack of fresh water resources to meet the standard water demand. There are two type of water scarcity. One is physical. The other is economic water scarcity.
Hierarchical Digital Twin of a Naval Power SystemKerry Sado
A hierarchical digital twin of a Naval DC power system has been developed and experimentally verified. Similar to other state-of-the-art digital twins, this technology creates a digital replica of the physical system executed in real-time or faster, which can modify hardware controls. However, its advantage stems from distributing computational efforts by utilizing a hierarchical structure composed of lower-level digital twin blocks and a higher-level system digital twin. Each digital twin block is associated with a physical subsystem of the hardware and communicates with a singular system digital twin, which creates a system-level response. By extracting information from each level of the hierarchy, power system controls of the hardware were reconfigured autonomously. This hierarchical digital twin development offers several advantages over other digital twins, particularly in the field of naval power systems. The hierarchical structure allows for greater computational efficiency and scalability while the ability to autonomously reconfigure hardware controls offers increased flexibility and responsiveness. The hierarchical decomposition and models utilized were well aligned with the physical twin, as indicated by the maximum deviations between the developed digital twin hierarchy and the hardware.
Overview of the fundamental roles in Hydropower generation and the components involved in wider Electrical Engineering.
This paper presents the design and construction of hydroelectric dams from the hydrologist’s survey of the valley before construction, all aspects and involved disciplines, fluid dynamics, structural engineering, generation and mains frequency regulation to the very transmission of power through the network in the United Kingdom.
Author: Robbie Edward Sayers
Collaborators and co editors: Charlie Sims and Connor Healey.
(C) 2024 Robbie E. Sayers
CFD Simulation of By-pass Flow in a HRSG module by R&R Consult.pptxR&R Consult
CFD analysis is incredibly effective at solving mysteries and improving the performance of complex systems!
Here's a great example: At a large natural gas-fired power plant, where they use waste heat to generate steam and energy, they were puzzled that their boiler wasn't producing as much steam as expected.
R&R and Tetra Engineering Group Inc. were asked to solve the issue with reduced steam production.
An inspection had shown that a significant amount of hot flue gas was bypassing the boiler tubes, where the heat was supposed to be transferred.
R&R Consult conducted a CFD analysis, which revealed that 6.3% of the flue gas was bypassing the boiler tubes without transferring heat. The analysis also showed that the flue gas was instead being directed along the sides of the boiler and between the modules that were supposed to capture the heat. This was the cause of the reduced performance.
Based on our results, Tetra Engineering installed covering plates to reduce the bypass flow. This improved the boiler's performance and increased electricity production.
It is always satisfying when we can help solve complex challenges like this. Do your systems also need a check-up or optimization? Give us a call!
Work done in cooperation with James Malloy and David Moelling from Tetra Engineering.
More examples of our work https://www.r-r-consult.dk/en/cases-en/
Welcome to WIPAC Monthly the magazine brought to you by the LinkedIn Group Water Industry Process Automation & Control.
In this month's edition, along with this month's industry news to celebrate the 13 years since the group was created we have articles including
A case study of the used of Advanced Process Control at the Wastewater Treatment works at Lleida in Spain
A look back on an article on smart wastewater networks in order to see how the industry has measured up in the interim around the adoption of Digital Transformation in the Water Industry.
Final project report on grocery store management system..pdfKamal Acharya
In today’s fast-changing business environment, it’s extremely important to be able to respond to client needs in the most effective and timely manner. If your customers wish to see your business online and have instant access to your products or services.
Online Grocery Store is an e-commerce website, which retails various grocery products. This project allows viewing various products available enables registered users to purchase desired products instantly using Paytm, UPI payment processor (Instant Pay) and also can place order by using Cash on Delivery (Pay Later) option. This project provides an easy access to Administrators and Managers to view orders placed using Pay Later and Instant Pay options.
In order to develop an e-commerce website, a number of Technologies must be studied and understood. These include multi-tiered architecture, server and client-side scripting techniques, implementation technologies, programming language (such as PHP, HTML, CSS, JavaScript) and MySQL relational databases. This is a project with the objective to develop a basic website where a consumer is provided with a shopping cart website and also to know about the technologies used to develop such a website.
This document will discuss each of the underlying technologies to create and implement an e- commerce website.
NO1 Uk best vashikaran specialist in delhi vashikaran baba near me online vas...Amil Baba Dawood bangali
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Student information management system project report ii.pdfKamal Acharya
Our project explains about the student management. This project mainly explains the various actions related to student details. This project shows some ease in adding, editing and deleting the student details. It also provides a less time consuming process for viewing, adding, editing and deleting the marks of the students.
Industrial Training at Shahjalal Fertilizer Company Limited (SFCL)MdTanvirMahtab2
This presentation is about the working procedure of Shahjalal Fertilizer Company Limited (SFCL). A Govt. owned Company of Bangladesh Chemical Industries Corporation under Ministry of Industries.
Industrial Training at Shahjalal Fertilizer Company Limited (SFCL)
10. kinetics of particles newton s 2nd law
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P
INTRODUCTION
So far in the earlier chapter we did the motion analysis of moving particles
without taking into account the forces responsible for the motion. From this
chapter we begin our motion analysis involving the forces responsible for
the motion. This analysis is known as kinetics. Here we will analysis motion
of moving cars, elevators, blocks, airplanes, rockets etc. treating them as a
particle, since rotation of these bodies about their own Centre of gravity, if
any, is neglected.
In this chapter we will extensively use the Newton's Second law approach to
kinetics. As stated further, this approach involves determination of
acceleration of the moving particle by knowing the forces acting on the
particle. Having determined the acceleration, the analysis is completed-
using kinematic relations which we have studied in previous chapter.
NEWTON'S SECOND LAW OF MOTION
Newton's second law of motion states "The rate of change of momentum of a
body is directly proportional to the resultant force and takes place in the
direction of the force”.
Consider a particle acted upon by several forces as shown in Fig. 10.1. Let
F be the resultant force. Because of the resultant force, the particle would
move in the direction of the resultant force. If u is the initial velocity, v is
final velocity and this change takes place in t sec, we have from Newton’s
second law:
Rate of change of Momentum = Resultant Force
i.e.
Finalmomentum - Initial momentum
Time
F
( )
mv mu
F
t
v u
F m
t
or F m a …………10.1
Kinetics of Particles-Newton's 2nd Law
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Equation 10.1 is the mathematical expression of Newton's Second Law and
this gives rise to another statement of Newton's Second Law, which is "If
the resultant force acting on a particle is not zero, the particle will have an
acceleration proportional to the magnitude of the resultant and in the
direction o' the resultant force'.
Equation 10.1 is a vector relation since both the force and acceleration are
vector quantities. The scalar relations from 10.1 can be developed as,
x x
m aF …… [10.2 (a)]
y y
m aF …… [10.2 (b)]
z z
m aF …… [10.2 (c)]
Since we will normally restrict our analysis to coplanar forces, the
equations 10.2 (a) and 10.2 (b) will be mainly used.
D'ALEMBERT'S PRINCIPLE
Referring to equation 10.1 we have
F m a
This is Newton's Second Law equation and relates the particle's
acceleration to the resultant of the external forces acting on the particle.
The equation is vector a equation where the resultant force vector is
equated to the ma vector.
Transposing the R.H.S. of the equation 10.1 we get,
0F ma …… [10.3]
The above equation is a dynamic equilibrium equation put forth by
D'Alembert. The ma vector is treated as an inertia force and when added
with a negative sign to all other forces, results in equilibrium state of
particle.
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Figure shows the dynamic equilibrium state of
1) A block sliding down a rough inclined plane
2) A sphere tied to a string, swinging as a pendulum to a lower position.
Particle's acceleration can be found out by D'Alembert's principle, by
developing the figure representing a dynamic state and using the
equilibrium equations used in static viz.,
0 and 0F Fx y
Newton's Second Law approach to kinetics is more realistic than the
D’Alembert's principle since it does not involve inertia forces and does not
refer to an equilibrium state of a moving particle. We would therefore solve
the problems in kinetics involving forces and acceleration using Newton's
Second Law equation.
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N S L EQUATIONS APPLIED TO RECTILINEAR MOTION
Application of Newton's equations to determine the acceleration of
rectilinear moving particles should be carried out by a systematic approach
as explained below.
step (1) Draw the FBD showing all the forces acting on the moving
particle. I more than one particle is involved, the particles may be
isolated and separate FBD may be drawn.
step (2) By the side of FBD, draw the Kinetic Diagram (KD) which shows
the particle with a ma vector acting on it. The magnitude of ma
vector is the product of particle's mass and its acceleration. ma
vector acts in the direction of particle's acceleration.
step (3) Equations of Newton's second law viz 10.2 (a) and I0.2 (b) are now
used, taking help of the FBD and KD drawn earlier. The particle's
acceleration is thus obtained.
To understand the above outlined x steps, let us find out the
acceleration of a block of mass m which is being pulled up an
inclined plane by force P applied parallel to the plane. Let k N
be the kinetic coefficient of friction between the block and
plane. As the block moves up, the rough inclined surface
develops a frictional force k N down the plane.
The FBD of the block showing the forces and the corresponding
Kinetic Diagram showing the ma vector is drawn as shown in
figure. Taking the x and y axes as shown and using equation
10.2 (a) of the Newton's Second Law we have,
k Substituting the value of N from equation (2) in (1)
sin cos
sin cos
k
k
P mg mg ma
P mg
a
m
Thus knowing the forces acting on the particle, its acceleration
can be found out.
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EXERCISE 1
1. A 100 kg crate is projected on a horizontal floor
with an initial speed of 10 m/s. If tr1" = 0.4 and
p1 = 0.3, calculate the distance traveled and the
time taken by create to come to rest.
2. A block of mass 30 kg is placed on a plane. k Between the block and
plane is 0.3. If a force of 250 N is acting on the block, find its acceleration
for the two cases shown.
3. Find force P required to accelerate the block shown in
figure at 2.5 m/s2. Take p = 0.3.
4. Two blocks A and B are placed 15 m apart and are released simultaneously
from rest. Calculate the time taken and the distance traveled by each block
before they collide.
5. Two blocks A of weight 500 N and B of weight 300 N
are 10 m apart on an inclined plane as shown in
figure. = O.2 for block A and 0.3 for block B. If the
blocks begin to slide down simultaneously calculate
the time and the distance travelled by each block
when block A touches block B.
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6. Two blocks A and B rest on an inclined plane as shown. Find their
acceleration on being released from rest. Also find the contact force between
the blocks.
7. Three blocks m1 and m2 and m3 of masses 1.5 kg, 2 kg and 1 kg
respectively are placed on a rough surface with = O.2O as shown. If a
force F is applied to accelerate the blocks at 3 m/s2 what will be the force
that 1.5 kg block exerts on 2 kg block.
8. A package of total weight 4OO0 N is being pulled up a slope by a steel cable
exerting a force F = (50 t2 + 25OO) N. Knowing that the velocity of the
package was 5 m/s at t = 0, find the acceleration and velocity of the
package at t=8 sec.
9. An airplane of mass 30,000 kg starts from rest and runs on the runway for
1500 m before it takes off. If the airplane engines developed a constant
thrust of 50 kN and the air resistance force acting on the plane is F = 3 v2
(where F is in Newton and v is in m/s), find the takeoff velocity of the
airplane.
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10. A particle of mass 3 kg initially at rest at the origin is set in rectilinear
motion by a force varying with time as per the graph shown. Find
a) The velocity and position of the particle at t =1O sec.
b) The time and position at which the particle comes to rest
c) The time at which the particle comes again to its original position.
11. A locomotive train weighing 5OOO kN exerts a constant pull of 120 kN. The
train starts from rest on a level track and attains a speed of 9O kmph, after
which steam is suddenly shut off, slowly bringing it to a halt. If the tractive
resistance is 15 N/kN of the eight of the train, find the total distance
covered by the train and the total time to cover this distance. What is the
maximum power developed by the engine?
12. A vertical lift of total mass 750 kg acquires an upward velocity of 3 m/s
over a distance of 4m moving with constant acceleration starting from rest.
Calculate the tension in the cable.
13. A 400 kg lift-carrying a 60 kg person travels vertically up starting from rest
and acquires a velocity of 4m/s in a distance of 3m of motion. Find the
tension in the cable supporting the lift and the force transmitted by the
person on the lift floor. Does the person feel normal or heavy or light.
a) The lift is now brought to a halt from the speed of 4 mf s, in 2 sec time.
What is the force exerted by the man on the floor of the lift and how does
he feel now.
14. Two blocks A and B are connected by a rope and move on a rough
horizontal plane under a pull of 60 N as shown. If p is 0.2 between the
blocks and the surface, find the acceleration of the blocks and the tension
in the rope.
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15. Two masses l.4kg and 7kg connected by a flexible
inextensible cord rest on a plane inclined at 45 with the
horizontal as shown in figure. When the masses are
released what will be the tension T in the cord?
Assume the coefficient of friction between the plane
and the 14 kg mass as 0.25 and between the plane
and the 7kg mass as 0.375.
16. Two particles of masses mA = 5 kg and m= 10 kg
are supported as shown. acceleration of the
blocks
a) if the horizontal surface is smooth
b) if the horizontal surface is rough coefficient of kinetic friction k = Q.4
17. Calculate the vertical acceleration of the 10O kg block and the tension in
the connecting string. Neglect friction.
18. Determine the tension in the string and the velocity of 1500N block shown
in the figure 5 sec after starting from rest.
19. Determine the weight WA of block A required to
bring the system to stop in 6 sec, if at the instant
shown, the block C is moving down at 5 m/s.
Given WB = 2OO N, Wc = 600 N. Take the pulley to
be smooth.
a) Find weight WA to bring the system to stop in 5
sec., If at the instant shown, vc = 3 m/s , WB
=150N and WC=500N.
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20. At a given instant 5O N block A is moving downwards with a speed of 1.8
m/sec. determine its speed 2 sec. later. Block 'B' has a weight 2O N, and
the coefficient of kinetic friction between it and the horizontal plane is k =
0.2. Neglect the mass of pulleys and chord. Use D’Alembert’s principle.
21. Two blocks A and B are connected by an inextensible string as shown.
Neglecting the effect of friction, determine the acceleration of each block
and tension in the cable.
22. Masses A (5 kg), B (10 kg), (2O kg) are connected as shown in the figure by
inextensible cord passing over massless and frictionless pulleys. The
coefficient of friction for masses A and B with ground is 0.2. If the system is
released from rest, find acceleration of the blocks and tension in the cords.
23. The two blocks starts from rest. The horizontal plane and the pulley are
frictionless. Determine the acceleration of each blocks and tension in the
cord.
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24. Block A (7 kg), B (12 kg), - (30 kg) are connected by an inextensible string
as shown. If the system is released from rest find the accelerations of each
block and tension in the cord. Assume smooth surfaces.
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N S L EQUATIONS APPLIED TO CURVILINEAR MOTION
For curvilinear moving particles, the kinetic diagram shows the components
of ma vector viz, man, and mat. The man component acts towards the
centre of path while the mat component acts tangent to the path. Both the
components lie in the plane of curvilinear motion.
EXERCISE 2
1. A steel bob of mass 5 kg tied to a string of 3 m length is whirled with a
constant speed, such that the bob moves in a circle in the horizontal plane.
If the string makes an angle of 30" with the vertical, find the speed of the
bob and tension in the string.
2. A car weighing 12 kN goes round a flat curve of 90 m radius. Determine the
uniform limiting speed of the car in order to avoid outward skidding. Take µ
= 0.35
3. Figure shows two vehicles moving at 90 kmph on a road. Knowing that µ=
0.5 between road and the tyres. Determine total acceleration of each vehicle
when the brakes are suddenly applied and the wheels skid.
4. A vehicle of weight 8OO0 N travels with a constant speed of 72 kmph over a
vertical parabolic curve as shown. Find the pressure exerted by the tyres on
the road at the peak B.
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5. In a roller coaster ride, the coaster traveling around the loop ABC needs to
have a certain minimum velocity at the peak B. If the loop diameter is 10
m, find this velocity.
6. A pendulum of mass 600 gms, has a speed of 3.6 m/s at the position
shown. Find the tension in the string and the total acceleration at this
instant.
EXERCISE 3
Theory Questions
Q.1 State Newton's Second Law of Motion.
Q.2 Derive the mathematical expression of Newton's Second Law. Explain
D'Alembert's Principle.
UNIVERSITY QUESTIONS
1. A ball thrown down the incline strike the incline at a distance of 75 m
along. If the ball rises 20 m above the point of projection. Complete the
initial velocity and angle of projection with horizontal. (10 Marks)
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2. The system shown in figure is
released from rest. What is the height
lost by bodies A, B and C in 2
seconds? Take coefficient of kinetic
friction at rubbing surfaces as o.4.
Find also the tension in wires.
(10 Marks)
3. A 50 kg block kept on a 150 inclined plane is pushed down the plane with
an initial velocity of 20 m/s. If kμ =0.4, determine the distance travelled by
the block and the time it will take as it comes to rest. (4 Marks)
4. Two block mA = 10 kg and mB = 5 kg connected with cord and pulley
system as shown in fig. Determine the velocity of each block when system
is started from rest and block B gets displacement by 2 m. Take kμ =0.2
between block A and Horizontal surface. (6 Marks)
5. A body of mass 25 kg resting on a horizontal
table is connected by string passing over a
smooth pulley at the edge of the table to another
body of mass 3.75 kg and hanging vertically as
shown. Initially, the friction between the mass A
and the table is just sufficient to prevent the motion. If an additional 1.25
kg is added to the 3.75 kg mass, find the acceleration of the masse
(4 Marks)
6. State D’ Alembert’s principle with two examples. (4 Marks)
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7. Find out min. value of P to start the motion. (8 Marks)
8. Sphere A is supported by two writes AB, AC. Find
out tensions in wire AC:-
(i) before AB is cut
(ii) just after AB is cut. (4 Marks)
9. A block of mass 5kg is released from rest along a 40 degree inclined plane.
Determine the acceleration of the block when it travels a distance of 3m
using D’ Alemberts principle. Take coefficient of friction as 0.2. (4 Marks)
10. The mass of A is 23kg and mass of B is 36kg.
The coefficient are 0.4 between A and B, and 0.2
between ground and block B. Assume smooth
drum. Determine the maximum mass of M at
impending motion. (8 Marks)