The document discusses generating arithmetic, geometric, and harmonic progression series. It provides examples of taking input values for the first term (A), common difference or ratio (R), and number of terms (N) and outputting the AP, GP, and HP series. Formulas are given for calculating each subsequent term in the series based on the prior term and common difference or ratio. Sample input and output examples are also provided.

1. Team Emertxe
Basic Refresher

2. Assignment 5

3. Assignment 5

4. Assignment 5
WAP to generate AP, GP, HP series.

5. Assignment 5
WAP to generate AP, GP, HP series.
Input:

6. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.

7. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms

8. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms
Output:

9. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms
Output: Print AP , GP and HP series.

10. Assignment 5
What is AP series?

11. Assignment 5
What is AP series?
A sequence of numbers in which the common difference between
two consecutive terms is constant.

12. Assignment 5
How to generate AP series?

13. Assignment 5
How to generate AP series?
Example :-
A = 3, R = 3 , N = 3

14. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3

15. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?

16. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term

17. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?

18. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?
What is the next term?
3 ?

19. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?
What is the next term?
3 6
3 + 3 = 6

20. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, 6, ?
What is the next term?
3 9
6
6 + 3 = 9

21. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
The series : 3, 6, 9

22. Assignment 5
What is GP series?

23. Assignment 5
What is GP series?
A sequence of numbers in which the common ratio between two
consecutive terms is constant.

24. Assignment 5
How to generate GP series?

25. Assignment 5
How to generate GP series?
Example :-
A = 3, R = 3 , N = 3

26. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3

27. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?

28. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term

29. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?

30. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?
What is the next term?
?
3

31. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?
What is the next term?
3 * 3 = 9
9
3

32. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, 9, ?
What is the next term?
9 * 3 = 27
27
9
3

33. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
The series : 3, 9, 27

34. Assignment 5
What is HP series?

35. Assignment 5
What is HP series?
A sequence of numbers whose reciprocals form an arithmetic
progression.

36. Assignment 5
How to generate HP series?

37. Assignment 5
How to generate HP series?
Example :-
A = 3, R = 3 , N = 3

38. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9

39. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?

40. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term

41. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?

42. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?
In float : 0.333333, ?

43. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?
In float : 0.333333, ?
What is the next term?
1/3 ?

44. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, 1/6, ?
In float : 0.333333, 0.166667, ?
What is the next term?
1/3 1/6
1 / (3+3) = 1/6

45. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, 1/6, ?
In float : 0.333333, 0.166667, 0.111111
What is the next term?
1/3 1/6
1 / (3+3) = 1/9
1/9

46. Assignment 5
For example:- A = 3, R = 3 , N = 3
Print series in float:-

47. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print series in float:-

48. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print the series in float values
Print series in float:-

49. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print the series in float values
In float : 0.333333, 0.166667, 0.111111
Print series in float:-

50. Assignment 5
Can you guess the output ?

51. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
Can you guess the output ?

52. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
Can you guess the output ?

53. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
Can you guess the output ?

54. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
It will print 1.500000
Can you guess the output ?
3 / 2 1.000000
=
int float
int
3.000000 / 2 1.500000
=
float float
int

55. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
It will print 1.500000
Can you guess the output ?
Doing int / int and storing in float.
So, decimal part(.5 of 1.5) will be
truncated and only 1.000000 will
be stored in float.
Doing float / int and storing in
float.
So, decimal part(.5 of 1.5) will not
be truncated and 1.500000 will be
stored in float. This is typecasting

56. Assignment 5
Example’s:

57. Assignment 5
Example’s:
Input:

58. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4

59. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output:

60. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11

61. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54

62. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091

63. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input:

64. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input: A = 5 , R = 5 , N = 3

65. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input: A = 5 , R = 5 , N = 3
Output:

66. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input: A = 5 , R = 5 , N = 3
Output: AP = 5,10, 15

67. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input: A = 5 , R = 5 , N = 3
Output: AP = 5,10, 15
GP = 5,25, 125

68. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.5000000, 0.2000000, 0.1250000, 0.0909091
Input: A = 5 , R = 5 , N = 3
Output: AP = 5,10, 15
GP = 5,25, 125
HP = 0.200000,0.100000, 0.066667

69. Sample execution:-
Assignment 5

70. Sample execution:-
Assignment 5

71. Sample execution:-
Assignment 5

72. Assignment 5
Pre-requisites:-

73. Assignment 5
Pre-requisites:-
Loops

74. Assignment 5
Pre-requisites:-
Loops
Operators

75. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types

76. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-

77. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping

78. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping
• If-else constructs

79. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping
• If-else constructs
• Type Casting

80. Team Emertxe
Thank you