The document discusses generating arithmetic, geometric, and harmonic progression series. It explains that arithmetic series have a constant difference between terms, geometric series have a constant ratio, and harmonic series have reciprocals that form an arithmetic progression. Examples are provided of inputting initial values and generating the corresponding series output for each progression type. Pre-requisites of loops, operators, and data types are also listed.

1. Team Emertxe
Basic Refresher

2. Assignment 5

3. Assignment 5

4. Assignment 5
WAP to generate AP, GP, HP series.

5. Assignment 5
WAP to generate AP, GP, HP series.
Input:

6. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.

7. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms

8. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms
Output:

9. Assignment 5
WAP to generate AP, GP, HP series.
Input: Read integer ‘A’, ‘R’ and ‘N’.
where:
A = First number
R = Common difference(AP & HP), Common ratio(GP)
N = number of terms
Output: Print AP , GP and HP series.

10. Assignment 5
What is AP series?

11. Assignment 5
What is AP series?
A sequence of numbers in which the common difference between
two consecutive terms is constant.

12. Assignment 5
How to generate AP series?

13. Assignment 5
How to generate AP series?
Example :-
A = 3, R = 3 , N = 3

14. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3

15. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?

16. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term

17. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?

18. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?
What is the next term?
3 ?

19. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, ?
What is the next term?
3 6
3 + 3 = 6

20. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Sum of previous term and common difference(R) -> next term
The series : 3, 6, ?
What is the next term?
3 9
6
6 + 3 = 9

21. Assignment 5
How to generate AP series?
First term ‘A’ = 3, Common difference ‘R’ = 3 and ‘N’ = 3
The series : 3, 6, 9

22. Assignment 5
What is GP series?

23. Assignment 5
What is GP series?
A sequence of numbers in which the common ratio between two
consecutive terms is constant.

24. Assignment 5
How to generate GP series?

25. Assignment 5
How to generate GP series?
Example :-
A = 3, R = 3 , N = 3

26. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3

27. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?

28. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term

29. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?

30. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?
What is the next term?
?
3

31. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, ?
What is the next term?
3 * 3 = 9
9
3

32. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
How to find the next term ?
Product of previous term and common ratio (R) -> next term
The series : 3, 9, ?
What is the next term?
9 * 3 = 27
27
9
3

33. Assignment 5
How to generate GP series?
First term ‘A’ = 3, Common ratio ‘R’ = 3 and ‘N’ = 3
The series : 3, 9, 27

34. Assignment 5
What is HP series?

35. Assignment 5
What is HP series?
A sequence of numbers whose reciprocals form an arithmetic
progression.

36. Assignment 5
How to generate HP series?

37. Assignment 5
How to generate HP series?
Example :-
A = 3, R = 3 , N = 3

38. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9

39. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?

40. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term

41. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?

42. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?
In float : 0.333333, ?

43. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, ?
In float : 0.333333, ?
What is the next term?
1/3 ?

44. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, 1/6, ?
In float : 0.333333, 0.166667, ?
What is the next term?
1/3 1/6
1 / (3+3) = 1/6

45. Assignment 5
How to generate HP series?
First term is –> 1/A (A = 3) and the AP series : 3, 6, 9
How to find the next term ?
Reciprocal of next term in AP series-> next term
The series : 1/3, 1/6, ?
In float : 0.333333, 0.166667, 0.111111
What is the next term?
1/3 1/6
1 / (3+3) = 1/9
1/9

46. Assignment 5
For example:- A = 3, R = 3 , N = 3
Print series in float:-

47. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print series in float:-

48. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print the series in float values
Print series in float:-

49. Assignment 5
For example:- A = 3, R = 3 , N = 3
The HP series is :- 1/3, 1/6, 1/9
Print the series in float values
In float : 0.333333, 0.166667, 0.111111
Print series in float:-

50. Assignment 5
Can you guess the output ?

51. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
Can you guess the output ?

52. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
Can you guess the output ?

53. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
Can you guess the output ?

54. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
It will print 1.500000
Can you guess the output ?
3 / 2 1.000000
=
int float
int
3.000000 / 2 1.500000
=
float float
int

55. Assignment 5
 int num1 = 3 , num2 = 2;
float res = num1 / num2;
It will print 1.000000
 int num1 = 3 , num2 = 2;
float res = (float) num1 / num2;
It will print 1.500000
Can you guess the output ?
Doing int / int and storing in float.
So, decimal part(.5 of 1.5) will be
truncated and only 1.000000 will
be stored in float.
Doing float / int and storing in
float.
So, decimal part(.5 of 1.5) will not
be truncated and 1.500000 will be
stored in float. This is typecasting

56. Assignment 5
Example’s:

57. Assignment 5
Example’s:
Input:

58. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4

59. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output:

60. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11

61. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54

62. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909

63. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input:

64. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input: A = 5 , R = 5 , N = 3

65. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input: A = 5 , R = 5 , N = 3
Output:

66. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input: A = 5 , R = 5 , N = 3
Output: AP = 5, 10, 15

67. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input: A = 5 , R = 5 , N = 3
Output: AP = 5, 10, 15
GP = 5, 25, 125

68. Assignment 5
Example’s:
Input: A = 2 , R = 3 , N = 4
Output: AP = 2, 5, 8, 11
GP = 2, 6, 18, 54
HP = 0.500000, 0.200000, 0.125000, 0.090909
Input: A = 5 , R = 5 , N = 3
Output: AP = 5, 10, 15
GP = 5, 25, 125
HP = 0.200000,0.100000, 0.066667

69. Sample execution:-
Assignment 5

70. Sample execution:-
Assignment 5

71. Sample execution:-
Assignment 5

72. Assignment 5
Pre-requisites:-

73. Assignment 5
Pre-requisites:-
Loops

74. Assignment 5
Pre-requisites:-
Loops
Operators

75. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types

76. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-

77. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping

78. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping
• If-else constructs

79. Assignment 5
Pre-requisites:-
Loops
Operators
Data Types
Objective:-
To understand the concept of
• Continuous looping
• If-else constructs
• Type Casting

80. Team Emertxe
Thank you