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Flow measurement
Session 2
Orifice meter
Dr. Vijay G. S.
Professor
Dept. of Mech. & Ind. Engg.
MIT, Manipal
email: vijay.gs@manipal.edu
Mob.: 9980032104
• Orifice meter or Orifice plate is a device employed for measuring the
discharge of fluid through a pipe.
• It works on the same principle of the venturi meter.
• It is cheaper than a venturimeter as
it has the simplest design and occupies minimal space
2
Orifice meter
it consists of a flat circular plate with a concentric circular
sharp edge hole called orifice.
• This plate is inserted in the pipe such that the orifice
is concentric with the pipe cross section.
• The orifice diameter do
do  0.5 × d1 where, d1 = pipe diameter
Generally, 0.4d1 < do < 0.8d1
Orifice
Orifice plate
Dr. Vijay G S, Professor, MIT, Manipal
3
Orifice meter – contd…
Dr. Vijay G S, Professor, MIT, Manipal
Orifice plate
4
Orifice meter – contd… • The sudden change in the
flow area in Orifice
meters causes
considerable swirl
(eddies) and thus
significant head loss or
permanent pressure loss
occurs
• The region at which the
jet of fluid assumes
minimum cross sectional
area is known as the
“Vena contracta”
Swirl (eddies)
Pressure tapping position:
• On upstream side l1 = 1.5 to 2 times d1
• On downstream side l2 = 0.5 d1
l1 l2
d1
do
d2
Dr. Vijay G S, Professor, MIT, Manipal
5
Orifice meter – contd…
Vena Contracta
Dr. Vijay G S, Professor, MIT, Manipal
6
Orifice meter – contd…
Eddies
Dr. Vijay G S, Professor, MIT, Manipal
7
p1, V1, d1, a1 at section (1)
p2, V2, d2, a2 at section (2)
Applying Bernoulli’s equation at
sections 1 and 2 we get,
Expression for rate of flow through an Orificemeter
2 2
1 1 2 2
1 2
2 2
 
    
o o
p V p V
z z
g g g g
As pipe is horizontal, z1 = z2
2 2
1 1 2 2
2 2
 
  
o o
p V p V
g g g g
2 2
1 2 2 1
2 2
 
   
  
   
 
 
o o
p p V V
g g g g
 
1 2
o
p p
h
g



2 2
2 1
2 2
 
V V
h
g g Dr. Vijay G S, Professor, MIT, Manipal
Applying continuity equation at sections 1 and 2,
a1 V1 = a2 V2==> V1 = (a2 / a1) V2
2 2
2 1
2 2
 
V V
h
g g
2
2 1
2 2 2
1 2
1
2 2 2
1 2
2
2
a
V gh
a a
a gh
V
a a
 
  

 
 

2
2
2
2 2
1
2
2 2
2 2
2
1
2 2 2
2 1 2
2
1
2 2
1
2
2
 
 
 
 
 
 
 
 
 

   
 
a
V
a
V
h
g g
V a
a
g
V a a
h
g a
Expression for rate of flow through an Orifice meter – contd…
8
Dr. Vijay G S, Professor, MIT, Manipal
9
1
2 2 2
1 2
2
a gh
V
a a



• But a2 is the area of cross section of the fluid jet at vena contracta and
cannot be generally measured.
• So a2 should be expressed in terms of ao the area of cross section of the fluid
at orifice, which is known.
The ‘Coefficient of Contraction’ Cc is defined as:
2
c
o
a Area of cross section of fluid jet at Vena Contracta
C
a Area of cross section of fluid at Orifice
 
 a2 = Cc× ao
 
1 1
2 2 2 2
2
1 2 1
2 2
c o
a gh a gh
V
a a a C a
  
 
Expression for rate of flow through an Orifice meter – contd…
Dr. Vijay G S, Professor, MIT, Manipal
Expression for rate of flow through an Orifice meter – contd…
10
The discharge through the Vena contracta is given as
Q = a2× V2
Q = (Cc× ao) × V2
 
1
2
2
1
2
th c o
c o
a gh
Q C a
a C a
 

This is the theoretical discharge through the Orifice meter is
1
2 2 2
1
2
c o
th
c o
C a a gh
Q
a C a


But the actual discharge Qact will be less than the theoretical discharge Qth
Dr. Vijay G S, Professor, MIT, Manipal
• i.e., Qact < Qth  Qact = Cd × Qth , where Cd = Coefficient of discharge
• Further, the equation for discharge must also be expressed in a form that is
similar to that of the venturimeter, for comparison purpose.
• Cd must also account for the significant head losses occurring due to the
eddies.
• Cd is defined such that:
11
Expression for rate of flow through an Orifice meter – contd…
2 2
1 0
2 2 2
1
d c
c o
a a
C C
a C a



2 2 2
1
2 2
1
c o
c d
o
a C a
C C
a a

 

1
2 2
1
2
d o
act
o
C a a gh
Q
a a
 

1 1
2 2 2 2 2
1 1
2 2 2 2 2
1 1
2 2
. .,
c o d o
c o o
c d
c o o
C a a gh C a a gh
a C a a a
C C
i e
a C a a a

 

 
Dr. Vijay G S, Professor, MIT, Manipal
12
• The coefficient of discharge Cd for Orifice meter is much smaller than Cd for
a Venturi meter.
 For Venturi meter, Cd  0.95 to 0.98
 For Orifice meter, Cd  0.6 to 0.65
The actual discharge of venturi meter is
1 2
2 2
1 2
2


d
act
C a a gh
Q
a a
The actual discharge of orifice meter is
1
2 2
1
2
d o
act
o
C a a gh
Q
a a


a2 = area of c/s of throat ao = area of c/s of orifice
Expression for rate of flow through an Orifice meter – contd…
Dr. Vijay G S, Professor, MIT, Manipal
Case (i): Orifice meter is horizontal, manometer is upright, m > o
Case (ii): Orifice meter is inclined, manometer is upright, m > o
Case (iii): Orifice meter is horizontal, manometer is inverted, m < o
Case (iv): Orifice meter is inclined, manometer is inverted, m < o
1


 
 
 
 
m
o
h x
1


 
 
 
 
m
o
h x
Expression for h
13
Dr. Vijay G S, Professor, MIT, Manipal
14
Comparison between Venturi meter and Orifice meter:
Venturi meter Orifice meter
Higher cost Lower cost
Larger size Smaller size
Low head loss High head loss
High coefficient of discharge
Cd  0.95 to 0.98
Low coefficient of discharge
Cd  0.65 to 0.70
Used for measuring the flow rates of
incompressible fluids (gases with low
pressure variations, as well as liquids)
Generally used for measuring the
flow rate of liquids
Dr. Vijay G S, Professor, MIT, Manipal
PROBLEMS ON ORIFICE METER
15
Dr. Vijay G S, Professor, MIT, Manipal
Problem 1: An orifice meter with orifice diameter 10 cm is inserted in a pipe of
20 cm diameter. The pressure gauges fitted upstream and downstream of the
orifice meter gives readings of 19.62 N/cm2 and 9.81 N/cm2 respectively.
Coefficient of discharge for the orifice meter is given as 0.6. Find the discharge
of water through pipe.
o = 1000 kg/m3 (Flowing water)
d1 = 20 cm = 0.2 m (Pipe dia)
do = 10 cm = 0.1 m (Orifice dia)
p1 = 19.62 N/cm2 = 19.62×104 N/m2
p2 = 9.81 N/cm2 = 9.81×104 N/m2
Cd = 0.6
2 2
2
1
1
0.2
0.03142
4 4
d
a m
  
  
2 2
2
2 0.1
0.00785
4 4
o
d
a m
  
  
3
1
2 2 2 2
1
2 0.6 0.03142 0.00785 2 9.81 10
0.06813 /
0.03142 0.00785
d o
act
o
C a a gh
Q m s
a a
    
  
 
Qact = 68.13 lps 16
    4
1 2 19.62 9.81 10
1000 9.81
10
o
p p
h
g
m of water

  
 


Dr. Vijay G S, Professor, MIT, Manipal
Problem 2: An orifice meter with orifice diameter 15 cm is inserted in a pipe of
30 cm diameter. The pressure difference measured by a mercury-oil differential
manometer on the two sides of the orifice meter gives a reading of 50 cm of
mercury. Find the rate of flow of oil of specific gravity 0.9 when the coefficient
of discharge of the orifice meter 0.64.
o = 900 kg/m3 (Flowing oil)
m = 13600 kg/m3 (Manometer fluid)
d1 = 30 cm = 0.3 m (Pipe dia)  a1 = d1
2/4 = 0.07069 m2
do = 15 cm = 0.15 m (Orifice dia)  ao = do
2/4 = 0.01767 m2
x = 50 cm = 0.5 m
Cd = 0.64 1
13600
0.5 1 7.056
900
m
o
h x
h m of oil


 
 
 
 
 
   
 
 
17
Dr. Vijay G S, Professor, MIT, Manipal
Problem 2 contd…
18
1
2 2
1
2 2
3
2
0.64 0.07069 0.01767 2 9.81 7.056
0.07069 0.01767
0.13742 /
d o
act
o
C a a gh
Q
a a
m s


    



Qact = 137.42 lps
Dr. Vijay G S, Professor, MIT, Manipal
Problem 3: An orifice meter is used to measure the air flow passing through a
pipe of 8 cm diameter. The diameter of orifice meter is 2 cm. The pipe is
horizontal. The head causing flow is measured by using a manometer containing
water. The measured head is 5.6 m of water. The density of air 1.193 kg/ m3.
Take Cd = 0.65
19
o = 1.193 kg/m3 (Flowing air)
m = 1000 kg/m3 (Manometer fluid water)
d1 = 8 cm = 0.08 m (Inlet dia)  a1 = d1
2/4 = 0.00502 m2
do = 2 cm = 0.02 m (Orifice dia)  ao = do
2/4 = 0.000314 m2
x = 5.6 m of water
Cd = 0.65 1
1000
5.6 1 4688.4
1.193
m
o
h x
h m of air


 
 
 
 
 
   
 
 
Dr. Vijay G S, Professor, MIT, Manipal
Problem 3 contd…
20
1
2 2
1
2 2
3
2
0.65 0.00502 0.000314 2 9.81 4688.4
0.00502 0.000314
0.06202 /
d o
act
o
C a a gh
Q
a a
m s


    



Qact = 62.02 lps
Dr. Vijay G S, Professor, MIT, Manipal

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007b (PPT) Orificemeter.pdf ,

  • 1. Flow measurement Session 2 Orifice meter Dr. Vijay G. S. Professor Dept. of Mech. & Ind. Engg. MIT, Manipal email: vijay.gs@manipal.edu Mob.: 9980032104
  • 2. • Orifice meter or Orifice plate is a device employed for measuring the discharge of fluid through a pipe. • It works on the same principle of the venturi meter. • It is cheaper than a venturimeter as it has the simplest design and occupies minimal space 2 Orifice meter it consists of a flat circular plate with a concentric circular sharp edge hole called orifice. • This plate is inserted in the pipe such that the orifice is concentric with the pipe cross section. • The orifice diameter do do  0.5 × d1 where, d1 = pipe diameter Generally, 0.4d1 < do < 0.8d1 Orifice Orifice plate Dr. Vijay G S, Professor, MIT, Manipal
  • 3. 3 Orifice meter – contd… Dr. Vijay G S, Professor, MIT, Manipal
  • 4. Orifice plate 4 Orifice meter – contd… • The sudden change in the flow area in Orifice meters causes considerable swirl (eddies) and thus significant head loss or permanent pressure loss occurs • The region at which the jet of fluid assumes minimum cross sectional area is known as the “Vena contracta” Swirl (eddies) Pressure tapping position: • On upstream side l1 = 1.5 to 2 times d1 • On downstream side l2 = 0.5 d1 l1 l2 d1 do d2 Dr. Vijay G S, Professor, MIT, Manipal
  • 5. 5 Orifice meter – contd… Vena Contracta Dr. Vijay G S, Professor, MIT, Manipal
  • 6. 6 Orifice meter – contd… Eddies Dr. Vijay G S, Professor, MIT, Manipal
  • 7. 7 p1, V1, d1, a1 at section (1) p2, V2, d2, a2 at section (2) Applying Bernoulli’s equation at sections 1 and 2 we get, Expression for rate of flow through an Orificemeter 2 2 1 1 2 2 1 2 2 2        o o p V p V z z g g g g As pipe is horizontal, z1 = z2 2 2 1 1 2 2 2 2      o o p V p V g g g g 2 2 1 2 2 1 2 2                  o o p p V V g g g g   1 2 o p p h g    2 2 2 1 2 2   V V h g g Dr. Vijay G S, Professor, MIT, Manipal
  • 8. Applying continuity equation at sections 1 and 2, a1 V1 = a2 V2==> V1 = (a2 / a1) V2 2 2 2 1 2 2   V V h g g 2 2 1 2 2 2 1 2 1 2 2 2 1 2 2 2 a V gh a a a gh V a a            2 2 2 2 2 1 2 2 2 2 2 2 1 2 2 2 2 1 2 2 1 2 2 1 2 2                          a V a V h g g V a a g V a a h g a Expression for rate of flow through an Orifice meter – contd… 8 Dr. Vijay G S, Professor, MIT, Manipal
  • 9. 9 1 2 2 2 1 2 2 a gh V a a    • But a2 is the area of cross section of the fluid jet at vena contracta and cannot be generally measured. • So a2 should be expressed in terms of ao the area of cross section of the fluid at orifice, which is known. The ‘Coefficient of Contraction’ Cc is defined as: 2 c o a Area of cross section of fluid jet at Vena Contracta C a Area of cross section of fluid at Orifice    a2 = Cc× ao   1 1 2 2 2 2 2 1 2 1 2 2 c o a gh a gh V a a a C a      Expression for rate of flow through an Orifice meter – contd… Dr. Vijay G S, Professor, MIT, Manipal
  • 10. Expression for rate of flow through an Orifice meter – contd… 10 The discharge through the Vena contracta is given as Q = a2× V2 Q = (Cc× ao) × V2   1 2 2 1 2 th c o c o a gh Q C a a C a    This is the theoretical discharge through the Orifice meter is 1 2 2 2 1 2 c o th c o C a a gh Q a C a   But the actual discharge Qact will be less than the theoretical discharge Qth Dr. Vijay G S, Professor, MIT, Manipal
  • 11. • i.e., Qact < Qth  Qact = Cd × Qth , where Cd = Coefficient of discharge • Further, the equation for discharge must also be expressed in a form that is similar to that of the venturimeter, for comparison purpose. • Cd must also account for the significant head losses occurring due to the eddies. • Cd is defined such that: 11 Expression for rate of flow through an Orifice meter – contd… 2 2 1 0 2 2 2 1 d c c o a a C C a C a    2 2 2 1 2 2 1 c o c d o a C a C C a a     1 2 2 1 2 d o act o C a a gh Q a a    1 1 2 2 2 2 2 1 1 2 2 2 2 2 1 1 2 2 . ., c o d o c o o c d c o o C a a gh C a a gh a C a a a C C i e a C a a a       Dr. Vijay G S, Professor, MIT, Manipal
  • 12. 12 • The coefficient of discharge Cd for Orifice meter is much smaller than Cd for a Venturi meter.  For Venturi meter, Cd  0.95 to 0.98  For Orifice meter, Cd  0.6 to 0.65 The actual discharge of venturi meter is 1 2 2 2 1 2 2   d act C a a gh Q a a The actual discharge of orifice meter is 1 2 2 1 2 d o act o C a a gh Q a a   a2 = area of c/s of throat ao = area of c/s of orifice Expression for rate of flow through an Orifice meter – contd… Dr. Vijay G S, Professor, MIT, Manipal
  • 13. Case (i): Orifice meter is horizontal, manometer is upright, m > o Case (ii): Orifice meter is inclined, manometer is upright, m > o Case (iii): Orifice meter is horizontal, manometer is inverted, m < o Case (iv): Orifice meter is inclined, manometer is inverted, m < o 1           m o h x 1           m o h x Expression for h 13 Dr. Vijay G S, Professor, MIT, Manipal
  • 14. 14 Comparison between Venturi meter and Orifice meter: Venturi meter Orifice meter Higher cost Lower cost Larger size Smaller size Low head loss High head loss High coefficient of discharge Cd  0.95 to 0.98 Low coefficient of discharge Cd  0.65 to 0.70 Used for measuring the flow rates of incompressible fluids (gases with low pressure variations, as well as liquids) Generally used for measuring the flow rate of liquids Dr. Vijay G S, Professor, MIT, Manipal
  • 15. PROBLEMS ON ORIFICE METER 15 Dr. Vijay G S, Professor, MIT, Manipal
  • 16. Problem 1: An orifice meter with orifice diameter 10 cm is inserted in a pipe of 20 cm diameter. The pressure gauges fitted upstream and downstream of the orifice meter gives readings of 19.62 N/cm2 and 9.81 N/cm2 respectively. Coefficient of discharge for the orifice meter is given as 0.6. Find the discharge of water through pipe. o = 1000 kg/m3 (Flowing water) d1 = 20 cm = 0.2 m (Pipe dia) do = 10 cm = 0.1 m (Orifice dia) p1 = 19.62 N/cm2 = 19.62×104 N/m2 p2 = 9.81 N/cm2 = 9.81×104 N/m2 Cd = 0.6 2 2 2 1 1 0.2 0.03142 4 4 d a m       2 2 2 2 0.1 0.00785 4 4 o d a m       3 1 2 2 2 2 1 2 0.6 0.03142 0.00785 2 9.81 10 0.06813 / 0.03142 0.00785 d o act o C a a gh Q m s a a           Qact = 68.13 lps 16     4 1 2 19.62 9.81 10 1000 9.81 10 o p p h g m of water         Dr. Vijay G S, Professor, MIT, Manipal
  • 17. Problem 2: An orifice meter with orifice diameter 15 cm is inserted in a pipe of 30 cm diameter. The pressure difference measured by a mercury-oil differential manometer on the two sides of the orifice meter gives a reading of 50 cm of mercury. Find the rate of flow of oil of specific gravity 0.9 when the coefficient of discharge of the orifice meter 0.64. o = 900 kg/m3 (Flowing oil) m = 13600 kg/m3 (Manometer fluid) d1 = 30 cm = 0.3 m (Pipe dia)  a1 = d1 2/4 = 0.07069 m2 do = 15 cm = 0.15 m (Orifice dia)  ao = do 2/4 = 0.01767 m2 x = 50 cm = 0.5 m Cd = 0.64 1 13600 0.5 1 7.056 900 m o h x h m of oil                     17 Dr. Vijay G S, Professor, MIT, Manipal
  • 18. Problem 2 contd… 18 1 2 2 1 2 2 3 2 0.64 0.07069 0.01767 2 9.81 7.056 0.07069 0.01767 0.13742 / d o act o C a a gh Q a a m s           Qact = 137.42 lps Dr. Vijay G S, Professor, MIT, Manipal
  • 19. Problem 3: An orifice meter is used to measure the air flow passing through a pipe of 8 cm diameter. The diameter of orifice meter is 2 cm. The pipe is horizontal. The head causing flow is measured by using a manometer containing water. The measured head is 5.6 m of water. The density of air 1.193 kg/ m3. Take Cd = 0.65 19 o = 1.193 kg/m3 (Flowing air) m = 1000 kg/m3 (Manometer fluid water) d1 = 8 cm = 0.08 m (Inlet dia)  a1 = d1 2/4 = 0.00502 m2 do = 2 cm = 0.02 m (Orifice dia)  ao = do 2/4 = 0.000314 m2 x = 5.6 m of water Cd = 0.65 1 1000 5.6 1 4688.4 1.193 m o h x h m of air                     Dr. Vijay G S, Professor, MIT, Manipal
  • 20. Problem 3 contd… 20 1 2 2 1 2 2 3 2 0.65 0.00502 0.000314 2 9.81 4688.4 0.00502 0.000314 0.06202 / d o act o C a a gh Q a a m s           Qact = 62.02 lps Dr. Vijay G S, Professor, MIT, Manipal