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WUC 115/05WUC 115/05
UNIVERSITY MATHEMATHICSUNIVERSITY MATHEMATHICS
BB
Rules for differentiation:
1. The derivative of a constant function is zero.
example
2. The power rule:
example
[ ] 0=c
dx
d
[ ] 030 =
dx
d
[ ] 1−
= nn
nxx
dx
d
[ ] 3144
12)4(33 xxx
dx
d
== −
Unit 5: Differentiation
5.1 Concepts and Rules of Differentiation
3. The scalar multiple rule:
If f(x) is differentiable at x and c is any real number, then
example
4. The sum rule & difference rule:
example
[ ] [ ])()( xf
dx
d
cxcf
dx
d
= [ ] [ ] 3344
12)4(333 xxx
dx
d
x
dx
d
===
[ ] [ ] [ ])()()()( xg
dx
d
xf
dx
d
xgxf
dx
d
±=±
[ ] 12)5()()(5 22
−=+−=+− x
dx
d
x
dx
d
x
dx
d
xx
dx
d
Unit 5: Differentiation
5.1 Concepts and Rules of Differentiation
Rules for differentiation:
5. The Product Rule:
Example: Differentiate
Solution:
[ ] )(')()().(')().( xgxfxgxfxgxf
dx
d
+=
)1)(13( 2
xxy +−=
[ ]
169
1366
)1)(13()6)(1(
)1()13()13()1()1)(13(
2
22
2
222
−+=
−++=
−++=
+−+−+=+−
xx
xxx
xxx
x
dx
d
xx
dx
d
xxx
dx
dy
Unit 5: Differentiation
5.1 Concepts and Rules of Differentiation
6. The Quotient Rule: If
then
Example:
Differentiate with respect to x .
,0)(,
)(
)(
)( ≠= xh
xh
xg
xf
2
)]([
)()(')()('
)('
xh
xgxhxhxg
xf
×−×
=
23
12
)(
+
−
=
x
x
xf
Unit 5: Differentiation
5.1 Concepts and Rules of Differentiation
7. The Chain Rule:
If is the composite function in which the
inside function g and the outside function f are
differentiable, then
Example:
Differentiate with respect to x .
))(( xgf
Unit 5: Differentiation
5.1 Concepts and Rules of Differentiation
)(')).(('))](([ xgxgfxgf
dx
d
=
( )22
1−+= xxy
The derivative of an Exponential Function:
Example: Determine the derivative of
Solution:
Unit 5: Differentiation
5.1 Diff. of Exp. & Log. Function
( ) xx
ee
dx
d
=
x
xexf 3)( =
)3()(3)3()(' x
dx
d
ee
dx
d
xxe
dx
d
xf xxx
+==
)1(333 +=+= xeexe xxx
The derivative of a Natural Logarithm Function:
where x > 0
And by the chain rule:
where f (x) > 0
Unit 5: Differentiation
5.1 Diff. of Exp. & Log. Function
x
x
dx
d 1
)(ln =
)(
)('
)]([ln
xf
xf
xf
dx
d
=
Example:
Find the derivative of
Solution:
Unit 5: Differentiation
5.1 Diff. of Exp. & Log. Function
)52ln()( 2
−+= xxxf
52
22
)52(
)52(
)(' 22
2
−+
+
=
−+
−+
=
xx
x
xx
xx
dx
d
xf
Marginal functions in economics
Example: The total cost, C(x) associated with the producing
and marketing x units of MP4 player is given by
Find :
(a)The actual cost incurred for producing and marketing the
11th
MP4 player.
(b) Total cost when the output is 5 units.
(c) Average cost for an output of 10 units
(d) Marginal cost the output is 4 units.
Unit 5: Differentiation
5.2 Business Application
150201.05.0)( 23
+−−= xxxxC
Marginal functions in economics
Example: Suppose the relationship between the unit price p in
RM and the quantity demanded x of the laptop model S is
given by the equation
Find :
(a) the revenue function R(x)
(b) the marginal revenue foundation R’(x)
(c) Compute R’(200) .
Unit 5: Differentiation
5.2 Business Application
30002.0)( +−= xxp
Marginal functions in economics
Example: For the above example , the revenue is function is
. Let the total cost of producing
x units of laptop model S be
Find :
(a) the profit function P(x)
(b) the marginal profit function P’(x)
(c) Compute P’(100)
Unit 5: Differentiation
5.2 Business Application
xxx 30002.0)( 2
+−=
300000200)( += xxC
Unit 5 Integration
5.3 Integration as Anti-differentiation
Definition:
A function F is called an anti-derivative or an indefinite integral
of a function f(x) if the derivative F’(x) = f(x). We write
if
Example:
Since the derivative of x2
= 2x, or
therefore, x2
is an anti-derivative of 2x, or
∫= dxxfxF )()( )()(' xfxF =
xx
dx
d
2)( 2
=
∫ = 2
2 xxdx
Unit 5 Integration
5.3 Integration as Anti-differentiation
x2
is not the only anti-derivative of 2x,
The derivative of x2
+ 5 is also 2x,
therefore x2
+ 5 is also anti-derivative of 2x.
Constant term is the only difference
In general,
it is always necessary to include the constant C
when writing a general anti-derivative:
x2
+ C
Unit 5 Integration
5.3 Integration as Anti-differentiation
Integration:
If then, integrating f(x) produces
the anti-derivative F(x) + C.
We write:
[ ] )()( xfxF
dx
d
=
∫ += CxFdxxf )()(
Unit 5 Integration
5.3 Integration as Anti-differentiation
Basic Integration Rules:
Rule 1: The indefinite integral of a constant
Example:
∫ += Ckxkdx
∫ += Cxdx 99
Unit 5 Integration
5.3 Integration as Anti-differentiation
Basic Integration Rules:
Rule 2: The power rule
Example:
)( 1
1
1 1
−≠+
+
=∫
+
nCx
n
dxx nn
∫ +=+
+
= +
CxCxdxx 5144
5
1
14
1
Unit 5 Integration
5.3 Integration as Anti-differentiation
Basic Integration Rules:
Rule 3: The constant multiple rule
(h = constant)
Example:
Try Activity 5.1 (Page 8)
∫ ∫= dxxfhdxxhf )()(
∫ ∫ +





== Cxxdxxdx 2
2
1
333
Unit 5 Integration
5.3 Indefinite Integrals
Basic Integration Rules:
Rule 4: The sum rule
Example:
[ ]∫ ∫∫ ±=± dxxgdxxfdxxgxf )()()()(
( )
Cxxx
Cx
xx
dxxdxdxxdxxx
+−+=
+−





+





=
−+=−+∫ ∫ ∫ ∫
23
2
2
6
3
3
263263
23
23
22
Unit 5 Integration
5.3 Integration as Anti-differentiation
Basic Integration Rules:
Rule 5: The indefinite integral of the exponential
function
(k = constant)
Example:
∫ += Ce
k
dxe kxkx 1
∫ += −−
Cedxe xx 8585
5
1
Unit 5 Integration
5.3 Integration as Anti-differentiation
Basic Integration Rules:
Rule 6: The indefinite integral of
Example:
x
xxf
11
== −
)(
∫ ∫ ≠+==−
0
11
xCxdx
x
dxx ln
∫ ∫ ≠+==−
)(ln 05
1
55 1
xCxdx
x
dxx
Unit 5 Integration
5.3 Definite Integrals
Theorem:
Let f be continuous on [a, b]. If G is any anti-derivative
for f on [a, b], then
Example: Evaluate .
Solution: Since is an antiderivative of f(x) = x, thus
∫ −=
b
a
aGbGdxxf )()()(
∫
2
1
dxx
2
)(
2
x
xF =
2
3
)14(
2
1
2
2
1
2
2
1
=−==∫
x
dxx
Unit 5 Integration
5.3 Definite Integrals
Evaluating the definite Integral:
Let f and g be continuous function, then
( c = constant)
[ ]
( )cbadxxfdxxfdxxf
dxxgdxxfdxxgxf
dxxfcdxxcf
dxxfdxxf
dxxf
c
b
b
a
c
a
b
a
b
a
b
a
b
a
b
a
b
a
a
b
a
a
<<+=
±=±
=
−=
=
∫∫∫
∫∫∫
∫ ∫
∫ ∫
∫
)()()(.
)()()()(.
)()(.
)()(.
)(.
5
4
3
2
01
Unit 5 Integration
5.3 Definite Integrals
Example: Given that and
Find: (a) (b)
Solution:
(a) (b)
5)(
7
4
−=∫ dxxf 8)(
7
4
=∫ dxxg
∫ +
7
4
)]()([ dxxgxf ∫ +−
7
4
]3)()([ dxxgxf
3
85
)()(
)]()([
7
4
7
4
7
4
=
+−=
+=
+
∫∫
∫
dxxgdxxf
dxxgxf
4
)47(385
3)()(
]3)()([
7
4
7
4
7
4
7
4
−=
−+−−=
+−=
+−
∫∫∫
∫
dxdxxgdxxf
dxxgxf
Unit 5 Integration
5.3 Definite Integrals
Example: Given that and
Find
Solution:
8)(
5
0
=∫ dxxf 3)(
2
0
=∫ dxxf
∫
5
2
)( dxxf
∫
∫
∫ ∫∫
=−=
=+
=+
5
2
5
2
5
2
5
0
2
0
538)(
8)(3
)()()(
dxxf
dxxf
dxxfdxxfdxxf
Example: Evaluate
Solution:
Unit 5 Integration
5.3 Definite Integrals
( ) .4
3
0
2
dxx∫ −
( )
3
)00()912(
3
44
3
0
3
3
0
2
=
−−−=






−=−∫
x
xdxx

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Calculus

  • 1. WUC 115/05WUC 115/05 UNIVERSITY MATHEMATHICSUNIVERSITY MATHEMATHICS BB
  • 2. Rules for differentiation: 1. The derivative of a constant function is zero. example 2. The power rule: example [ ] 0=c dx d [ ] 030 = dx d [ ] 1− = nn nxx dx d [ ] 3144 12)4(33 xxx dx d == − Unit 5: Differentiation 5.1 Concepts and Rules of Differentiation
  • 3. 3. The scalar multiple rule: If f(x) is differentiable at x and c is any real number, then example 4. The sum rule & difference rule: example [ ] [ ])()( xf dx d cxcf dx d = [ ] [ ] 3344 12)4(333 xxx dx d x dx d === [ ] [ ] [ ])()()()( xg dx d xf dx d xgxf dx d ±=± [ ] 12)5()()(5 22 −=+−=+− x dx d x dx d x dx d xx dx d Unit 5: Differentiation 5.1 Concepts and Rules of Differentiation
  • 4. Rules for differentiation: 5. The Product Rule: Example: Differentiate Solution: [ ] )(')()().(')().( xgxfxgxfxgxf dx d += )1)(13( 2 xxy +−= [ ] 169 1366 )1)(13()6)(1( )1()13()13()1()1)(13( 2 22 2 222 −+= −++= −++= +−+−+=+− xx xxx xxx x dx d xx dx d xxx dx dy Unit 5: Differentiation 5.1 Concepts and Rules of Differentiation
  • 5. 6. The Quotient Rule: If then Example: Differentiate with respect to x . ,0)(, )( )( )( ≠= xh xh xg xf 2 )]([ )()(')()(' )(' xh xgxhxhxg xf ×−× = 23 12 )( + − = x x xf Unit 5: Differentiation 5.1 Concepts and Rules of Differentiation
  • 6. 7. The Chain Rule: If is the composite function in which the inside function g and the outside function f are differentiable, then Example: Differentiate with respect to x . ))(( xgf Unit 5: Differentiation 5.1 Concepts and Rules of Differentiation )(')).(('))](([ xgxgfxgf dx d = ( )22 1−+= xxy
  • 7. The derivative of an Exponential Function: Example: Determine the derivative of Solution: Unit 5: Differentiation 5.1 Diff. of Exp. & Log. Function ( ) xx ee dx d = x xexf 3)( = )3()(3)3()(' x dx d ee dx d xxe dx d xf xxx +== )1(333 +=+= xeexe xxx
  • 8. The derivative of a Natural Logarithm Function: where x > 0 And by the chain rule: where f (x) > 0 Unit 5: Differentiation 5.1 Diff. of Exp. & Log. Function x x dx d 1 )(ln = )( )(' )]([ln xf xf xf dx d =
  • 9. Example: Find the derivative of Solution: Unit 5: Differentiation 5.1 Diff. of Exp. & Log. Function )52ln()( 2 −+= xxxf 52 22 )52( )52( )(' 22 2 −+ + = −+ −+ = xx x xx xx dx d xf
  • 10. Marginal functions in economics Example: The total cost, C(x) associated with the producing and marketing x units of MP4 player is given by Find : (a)The actual cost incurred for producing and marketing the 11th MP4 player. (b) Total cost when the output is 5 units. (c) Average cost for an output of 10 units (d) Marginal cost the output is 4 units. Unit 5: Differentiation 5.2 Business Application 150201.05.0)( 23 +−−= xxxxC
  • 11. Marginal functions in economics Example: Suppose the relationship between the unit price p in RM and the quantity demanded x of the laptop model S is given by the equation Find : (a) the revenue function R(x) (b) the marginal revenue foundation R’(x) (c) Compute R’(200) . Unit 5: Differentiation 5.2 Business Application 30002.0)( +−= xxp
  • 12. Marginal functions in economics Example: For the above example , the revenue is function is . Let the total cost of producing x units of laptop model S be Find : (a) the profit function P(x) (b) the marginal profit function P’(x) (c) Compute P’(100) Unit 5: Differentiation 5.2 Business Application xxx 30002.0)( 2 +−= 300000200)( += xxC
  • 13. Unit 5 Integration 5.3 Integration as Anti-differentiation Definition: A function F is called an anti-derivative or an indefinite integral of a function f(x) if the derivative F’(x) = f(x). We write if Example: Since the derivative of x2 = 2x, or therefore, x2 is an anti-derivative of 2x, or ∫= dxxfxF )()( )()(' xfxF = xx dx d 2)( 2 = ∫ = 2 2 xxdx
  • 14. Unit 5 Integration 5.3 Integration as Anti-differentiation x2 is not the only anti-derivative of 2x, The derivative of x2 + 5 is also 2x, therefore x2 + 5 is also anti-derivative of 2x. Constant term is the only difference In general, it is always necessary to include the constant C when writing a general anti-derivative: x2 + C
  • 15. Unit 5 Integration 5.3 Integration as Anti-differentiation Integration: If then, integrating f(x) produces the anti-derivative F(x) + C. We write: [ ] )()( xfxF dx d = ∫ += CxFdxxf )()(
  • 16. Unit 5 Integration 5.3 Integration as Anti-differentiation Basic Integration Rules: Rule 1: The indefinite integral of a constant Example: ∫ += Ckxkdx ∫ += Cxdx 99
  • 17. Unit 5 Integration 5.3 Integration as Anti-differentiation Basic Integration Rules: Rule 2: The power rule Example: )( 1 1 1 1 −≠+ + =∫ + nCx n dxx nn ∫ +=+ + = + CxCxdxx 5144 5 1 14 1
  • 18. Unit 5 Integration 5.3 Integration as Anti-differentiation Basic Integration Rules: Rule 3: The constant multiple rule (h = constant) Example: Try Activity 5.1 (Page 8) ∫ ∫= dxxfhdxxhf )()( ∫ ∫ +      == Cxxdxxdx 2 2 1 333
  • 19. Unit 5 Integration 5.3 Indefinite Integrals Basic Integration Rules: Rule 4: The sum rule Example: [ ]∫ ∫∫ ±=± dxxgdxxfdxxgxf )()()()( ( ) Cxxx Cx xx dxxdxdxxdxxx +−+= +−      +      = −+=−+∫ ∫ ∫ ∫ 23 2 2 6 3 3 263263 23 23 22
  • 20. Unit 5 Integration 5.3 Integration as Anti-differentiation Basic Integration Rules: Rule 5: The indefinite integral of the exponential function (k = constant) Example: ∫ += Ce k dxe kxkx 1 ∫ += −− Cedxe xx 8585 5 1
  • 21. Unit 5 Integration 5.3 Integration as Anti-differentiation Basic Integration Rules: Rule 6: The indefinite integral of Example: x xxf 11 == − )( ∫ ∫ ≠+==− 0 11 xCxdx x dxx ln ∫ ∫ ≠+==− )(ln 05 1 55 1 xCxdx x dxx
  • 22. Unit 5 Integration 5.3 Definite Integrals Theorem: Let f be continuous on [a, b]. If G is any anti-derivative for f on [a, b], then Example: Evaluate . Solution: Since is an antiderivative of f(x) = x, thus ∫ −= b a aGbGdxxf )()()( ∫ 2 1 dxx 2 )( 2 x xF = 2 3 )14( 2 1 2 2 1 2 2 1 =−==∫ x dxx
  • 23. Unit 5 Integration 5.3 Definite Integrals Evaluating the definite Integral: Let f and g be continuous function, then ( c = constant) [ ] ( )cbadxxfdxxfdxxf dxxgdxxfdxxgxf dxxfcdxxcf dxxfdxxf dxxf c b b a c a b a b a b a b a b a b a a b a a <<+= ±=± = −= = ∫∫∫ ∫∫∫ ∫ ∫ ∫ ∫ ∫ )()()(. )()()()(. )()(. )()(. )(. 5 4 3 2 01
  • 24. Unit 5 Integration 5.3 Definite Integrals Example: Given that and Find: (a) (b) Solution: (a) (b) 5)( 7 4 −=∫ dxxf 8)( 7 4 =∫ dxxg ∫ + 7 4 )]()([ dxxgxf ∫ +− 7 4 ]3)()([ dxxgxf 3 85 )()( )]()([ 7 4 7 4 7 4 = +−= += + ∫∫ ∫ dxxgdxxf dxxgxf 4 )47(385 3)()( ]3)()([ 7 4 7 4 7 4 7 4 −= −+−−= +−= +− ∫∫∫ ∫ dxdxxgdxxf dxxgxf
  • 25. Unit 5 Integration 5.3 Definite Integrals Example: Given that and Find Solution: 8)( 5 0 =∫ dxxf 3)( 2 0 =∫ dxxf ∫ 5 2 )( dxxf ∫ ∫ ∫ ∫∫ =−= =+ =+ 5 2 5 2 5 2 5 0 2 0 538)( 8)(3 )()()( dxxf dxxf dxxfdxxfdxxf
  • 26. Example: Evaluate Solution: Unit 5 Integration 5.3 Definite Integrals ( ) .4 3 0 2 dxx∫ − ( ) 3 )00()912( 3 44 3 0 3 3 0 2 = −−−=       −=−∫ x xdxx