2. C O N TE N TS
1. T h e A r e a P r o b le m
2 . The Ta ng e n t P r o b le m
3 . V e lo c it y
4 . T h e L im it of a
S e que nc e
5 . The S u m o f a S e r ie s
3. 1. THE AREA PROBLEM
The area of a polygone can be
defined by subdividing it into
F
triangles A
E
B
C D
Area (ABCDEF)=Area(ABF)+Area(BCF)+Area(CDF)+Area(DEF)
4. 1. THE AREA PROBLEM
The area of a curved figure can be defined
as limit of areas of incribed and
circonscribed polygones
A1 A2 A3 A4 A5
Area(Circle) = lim An
n →∞
8. Finally the area can be computed as the limit
of the sum of the areas of circumscribed
rectangles
This is the idea of Integral Calculus
9. 2 . TH E TA N G E N T
PROB LEM
t
P
The tangent t to the curve y=f(x) at point
P is determined by its slope m
10. We can approximate m by the slope mP Q of a
secant P Q , where Q is a nearby point
t
P (a,f(a)) Q (x,f(x))
f ( x) − f (a)
mPQ =
x−a
11. f ( x ) − f (a )
m = lim mPQ = lim
Q→P Q→P x−a
This is the idea of Differential Calculus
12. 3.
V E L O C IT Y
The distances (in feet) traveled by a car moving
along a straight road measured at 1-second
intervals are given by:
t = time elapsed 0 1 2 3 4 5
(s)
d = distance (ft) 0 2 10 25 43 78
The average velocity in the time interval 2 ≤ t ≤ 4
is:
43 − 10
v= = 16.5 ft / s
4−2
13. The average velocity in the time interval 2 ≤ t ≤ 3
is:
25 − 10
va = = 15 ft / s
3− 2
The distances traveled by the car measured at 0.1-
second intervals are given by:
t 2.0 2.1 2.2 2.3 2.4 2.5
d 10.0 11.0 12.16 13.45 14.96 16.80
0 2
The average velocity in the time interval 2 ≤ t ≤ 2.5
is:
16.80 − 10.00
va = = 13.6 ft / s
2.5 − 2
14. The average velocity computed in various interval
is:
t [2 3] [2 2.5] [2 2.4] [2 2.3] [2 2.2] [2 2.1]
va 15.0 13.6 12.4 11.5 10.8 10.2
The instantaneous velocity at t = 2 is the limit of the
average velocity over smaller and smaller interval [2
t]:
f (t ) − f (2)
v = lim
t →2 t −2
where f(t) is the distance (in feet) traveled
after t seconds
15. 4 . L IM IT O F A
S EQUENC E
The real number π is the limit of the sequence:
a1=3.1, a2=3.14, a3=3.141, a4=3.1415, a5=3.14159,
…
π = lim an
n →∞
1
lim = 0
n →∞ n
16. 5 . TH E S U M O F A
S E R IE S
The n-digit decimal representation of a rational
number 0.d1 d2 d3 … dn is the finite sum:
d1 d2 d3 dn
0.d1d 2 d 3 ...d n = + 2 + 3 +... + n
10 10 10 10
The infinite decimal representation of a real
number 0.d1 d2 d3 … dn … is the infinite sum:
d1 d2 d3
0.d1d 2 d 3 ... = + 2 + 3 +...
10 10 10
17. Therefore the infinite decimal representation 0.333 …
is:
1 3 3 3
= 0.333... = + 2 + 3 +...
3 10 10 10
Similarly we can compute the infinite
sum:
1 1 1 1
+ + + ... + n + ... As the limit of the sequence:
2 4 8 2
1 1 1 1 1 1
s1 = , s2 = + ,..., s10 = + + ... + = 0.99902344,...,
2 2 4 2 4 1024
1 1 1 1 1 1 1
s16 = + + ... + 16 = 0.99998474,..., sn = + + + ... + n ,...
2 4 10 2 4 8 2
1 1 1 1
+ + +... + n +... = lim sn =1
2 4 8 2 n→∞