Mr Huckey Case Study

Mr Huckey Case Study
Mr. Hurley has a challenge on his hands, the largest of which is that he asked me to figure this out. Ok now seriously we have to being to analyze
the problem. The first thing we want to do is identify the variables. In this case our variables will be the number of acres of corn and the amount of
wheat that is planted. We will further define them later. Next we have to identify our objective. In this case we are looking to maximize profits and
determine if participation in the government program will provide him with greater profits than not participating in the program. Finally we identify
the constraints; in our example the constraints are the rotation restrictions: must plant at least 50 acres of each crop, if he participates in the... Show
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Since the profit is the largest from corn it makes sense to plant and harvest as much corn as possible, however the requirement to have a minimum of
50 acres of wheat ensures that wheat is still in the mix. So by opting to plant only the minimum wheat (50 acres) and maximizing on the remaining
land for corn (200 acres) we can calculate the profits expected and compare the two models. MAXIMIZE 184X1 + 125X2 184(200) + 125
... Get more on HelpWriting.net ...

Essay about Mat 540 Quiz 5
Attempt Score 34 out of 40 points
Question 1
2 out of 2 points If exactly 3 projects are to be selected from a set of 5 projects, this would be written as 3 separate constraints in an integer program.
Answer
Selected Answer: False
Correct Answer: False . Question 2
2 out of 2 points Rounding non–integer solution values up to the nearest integer value will result in an infeasible solution to an integer linear
programming problem. Answer
Selected Answer: False
Correct Answer: False . Question 3
2 out of 2 points If we are solving a 0–1 integer programming problem, the constraint x1 в‰¤ x2 is a conditional constraint. Answer
Selected Answer: True
Correct Answer: ... Show more content on Helpwriting.net ...
Question 16 .2 out of 2 points The Wiethoff Company has a contract to produce 10000 garden hoses for a customer. Wiethoff has 4 different machines
that can produce this kind of hose. Because these machines are from different manufacturers and use differing technologies, their specifications are not
the same.
Write the constraint that indicates they can purchase no more than 3 machines.
Answer
Selected Answer: Y1 + Y2 + Y3+ Y4 в‰¤ 3
Correct Answer: Y1 + Y2 + Y3+ Y4 в‰¤ 3 . Question 17 .2 out of 2 points Max Z = 5x1 + 6x2
Subject to: 17x1 + 8x2 в‰¤ 136 3x1 + 4x2 в‰¤ 36 x1, x2 в‰Ґ 0 and integer
What is the optimal solution?
Answer
Selected Answer: x1 = 4, x2 = 6, Z = 56
Correct Answer: x1 = 4, x2 = 6, Z = 56 . Question 18 .2 out of 2 points The Wiethoff Company has a contract to produce 10000 garden hoses for a

customer. Wiethoff has 4 different machines that can produce this kind of hose. Because these machines are from different manufacturers and use
differing technologies, their specifications are not the same.
Write a constraint to ensure that if machine 4 is used, machine 1 will not be used.
Answer
Selected Answer: Y1 + Y4 в‰¤ 1
Correct Answer: Y1 + Y4 в‰¤ 1 . Question 19 .2 out of 2 points Max Z = 3x1 + 5x2
Subject to: 7x1 + 12x2 в‰¤ 136 3x1 + 5x2 в‰¤ 36 x1, x2 в‰Ґ 0 and

College Algebra
1. EMBED Equation.DSMT4 QUOTE = 62 Ans: x=36 2. EMBED Equation.DSMT4 ( 5x)2 = 62 5x = 36 x= 36/5 3. EMBED Equation.DSMT4 x = 4
x = 42 x=16 4. EMBED Equation.DSMT4 2 x = 24 x = 12 X = 144 5. EMBED Equation.DSMT4 X = 83 = 512 6. EMBED Equation.DSMT4 3x –1 =
36 3x = 37 X = 37/3 7. EMBED Equation.DSMT4 QUOTE x3 x = QUOTE 8. EMBED Equation.DSMT4 X3 =531441 X = 81 9. EMBED
Equation.DSMT4 3 x = 15 x = 5 X = 25 10. EMBED Equation.DSMT4 QUOTE = 3 2x 7 = 9 2x = 16 X = 8 11. EMBED Equation.DSMT4 4a2 = (x
/2) 8a2 = x 12. EMBED Equation.DSMT4 4 x = –12 x = –3 X= 9 No solution. 13. EMBED Equation.DSMT4 2R = QUOTE A = QUOTE 14. EMBED
Equation.DSMT4 R2 QUOTE H = 3V V = QUOTE 15. EMBED Equation.DSMT4 X + 4 = (y+2)2 X + 4 = y2 + 4y + 4 X = y2 + 4y 16. EMBED
Equation.DSMT4 Sum: (x) + (x–1) = 2x 1 Diff: x x 1 = –1 Prod: (x)(x–1) = x2 1 17. EMBED Equation.DSMT4 Sum: (x) + (y–1) = x+y–1 Diff: x y 1
Prod: (x)(y–1) = xy x 18. EMBED Equation.DSMT4 Sum: (x–1) + (x–2) = 2x –3 Diff: (x–1) (x–2) = 1 Prod: (x–1)(x–2) = x2 3x + 2 19. EMBED
Equation.DSMT4 Sum: x2 + x Diff: x2 – x Prod: (x2)(x) = x3 20. EMBED Equation.DSMT4 Sum: (x2–1) + (x–2) = x2 + x – 3 Diff: (x2–1) – (x–2) =
x2+x+1 Prod: (x2–1)(x–2) = x3 2x2 x +2 21. EMBED Equation.DSMT4 Sum: x2 + x2 –1 = 2x2–1 Diff: x2 (x2 –1) = 1 Prod: (x2)( x2 –1) = x4 x2 22.
EMBED Equation.DSMT4 Sum: (2x2 1) + (x3 x2 + 2x 1) = x3 + x2 + 2x –2 Diff: (2x2 1) – (x3 x2 +

Midterm Microecons
MIDTERM REVIEW ECONOMICS 100A: Intermediate Microeconomics Instructor: Prof. Ryan Oprea Prepared by: Aadil Nakhoda BUDGET
CONSTRAINT The budget constraint can be described as the following equation: m = p1 x1 + p2 x2 m = income p1 = price of good x1 p2 = price of
good x2 Solving the budget constraint: m p1 m p2 = intersect on the x1 –axis = intersect on the x2 axis p1 p2 Slope of the budget line = – Some key
points to remember: The aВ¤ordable bundle of goods lie on or below the budget line, while the unaВ¤ordable bundle of goods lie above it The budget
line is a straight line connecting two points on the two axes, but at times there can be a kink in the budget line (food stamps). 1 If income changes but
prices remain... Show more content on Helpwriting.net ...
U (x1 ; x2 ) = x2 + 2x1 x2 + x2 1 2 Answer 1: dx2 = dx1 dx2 = dx1 x1 x2 1 a 1 Answer 2: 6 CHOICE Preferred bundle vs aВ¤ordable bundle The most
preferred and aВ¤ordable bundle will always be on the budget line The slope of the budget line and the slope of the indiВ¤erence curve will always be
equal at the point the two are tangent. This will be the individual' optimal choice. s For example: Budget constraint: p1 x1 + p2 x2 = m Utility
Function: U (x1 ; x2 ) = x2 x2 1 2 U (x1 ; x2 ) = (x1 x2 )2 @U @U = 2(x1 x2 )x2 , = 2(x1 x2 )x1 @x1 @x2 M RS : 2x1 x2 2 = 2x2 x2 1 x2 x1 At the
optimal level, MRS = slope of budget line x2 = x1 x2 = p1 p2 p1 x1 p2 2p1 x1 = m x1 = m m ; x2 = 2p1 2p2 7 If the following inequality holds: M Ux
p1 > M Uy p2 How will the individual' consumption bundle be aВ¤ected? s Hint:Think about the diВ¤erences in slopes of the indiВ¤erence curve
and the budget line. Which good are you willing to consume more, and once you consume that good, how will it aВ¤ect the MRS? DEMAND
Comparative Static Analysis of demand: How x1 (p1 ; p2 ; y) and x2 (p1 ; p2 ; y) change as prices, p1 ; p2 ; and income y change. Suppose we hold
income and p2 constant, then the budget line will pivot to the left (along the x1 –axis)

X-Men III: A Review Essay
From the director of Rush Hour 1, 2 and 3, Brett Ratner brings the famous fictional comic book superhero crew, X–Men, to life. When a young
mutant's extraordinary power is discovered and an unexpected visitor returns things take a change for the worse and the mutants have to battle against
time to defeat the Phoenix before it can no longer be controlled. Both teams of mutants are fighting for Jean Grey's ( the Phoenix) amazing abilities,
but which team will she join? Throughout the film many ethical issues arise about 'playing God'. A good example is when a group of scientists take
advantage of a young boy's supposedly amazing superpower, that has the ability to suppress other mutants powers. The scientists then turn it into a 'cure'
... Show more content on Helpwriting.net ...
However some of the audience may be confused if they had not seen previous X–Men films. As the film does not make it clear what is going on or
where they are. However not all the special effects are as good as that. Once again we see Storm's (Halle Berry) powers come to life in a way which
does not suit this film at all and would look more at home in a horror film. The special effects used for Storm do not look real at all and it's obvious
that they are computer generated. If Brett Ratner can't give X–Men the credit it deserves maybe he should of left it to more experienced directors.
Despite many well known names (such as Ian Mckellen) appearing in X–Men all the actors fail to make this film exciting. Hugh Jackman, who has
recently starred in the film 'Australia', returns as Wolverine again. Compared to his performance in Australia, X–Men was pretty rubbish. However in
my opinion I think Hugh Jackman puts 101% effort into this role. He brings emotion to the character and makes it believable. Especially towards the
end of the film when he is faced with a decision on whether or not he should kill Jean to save everyone. He does an outstanding job and makes the
whole scene believable. It captures the audience's attention and keeps them on their toes.
One of the main characters in the film are a bit of a disappointment, for example Woverine. For a main character

Universal Algebras Associative Ring ( R )
KEY WORDS: Fuzzy set, anti S–fuzzy subsemiring, pseudo anti S–fuzzy coset. INTRODUCTION: There are many concepts of universal algebras
generalizing an associative ring ( R ; + ; . ). Some of them in particular, nearrings and several kinds of semirings have been proven very useful.
Semirings (called also halfrings) are algebras ( R ; + ; . ) share the same properties as a ring except that ( R ; + ) is assumed to be a semigroup rather
than a commutative group. Semirings appear in a natural manner in some applications to the theory of automata and formal languages. An algebra (R ;
+, .) is said to be a semiring if (R ; +) and (R ; .) are semigroups satisfying a. ( b+c ) = a. b+a. c and (b+c) .a = b. a+c. a for all a, b and c in R. After the
introduction of fuzzy sets by L.A.Zadeh[11], several researchers explored on the generalization of the concept of fuzzy sets. The notion of anti fuzzy
left h–ideals in hemiring was introduced by Akram.M and K.H.Dar [1]. The notion of homomorphism and anti–homomorphism of fuzzy and anti–fuzzy
ideal of a ring was introduced by N.Palaniappan & K.Arjunan[6]. In this paper, we introduce the some Theorems in anti S–fuzzy subsemiring of a
semiring. 1.PRELIMINARIES: 1.1 Definition: A S–norm is a binary operation S: [0, 1]п‚ґ[0, 1] п‚® [0, 1] satisfying the following requirements; (i) 0
S x = x, 1 S x = 1 (boundary condition) (ii) x S y = y S x (commutativity) (iii) x S ( y S z) = ( x S y) S z (associativity) (iv) if x п‚Ј y and w п‚Ј z, then

Assignment 2: Linear Algebra
Task #2: Linear Algebra
Competency 209.8.4: Vector Spaces
Jennifer Moore
Western Governor's University
Part A: To show that is a vector space, Laws 3– 10 in the definition of vector space must be proven. If Laws 3–10 are proven to be true, then is a
vector space. This paper will show the proof of Laws 3 – 10.
Proof of Law 3 – The Commutative Law :
Let vectors X and Y in be represented by: where x1, x2, y1, and y2 are real numbers. by substituting coordinate form of vectors by the definition of
vector addition by commutativity of addition of real numbers by the definition of vector addition by substituting vector form of coordinates
Since by a string of equalities above, then vector addition ... Show more content on Helpwriting.net ...
Proof of Law 5 – Additive Inverse Law "For every X в€€ V there is a vector
–X such that X+(–X)=0, where –X is called the additive inverse of X":
Let vector X in be represented by where x1 and x2 are real numbers. Let 0 be the zero vector in be represented by . Let vector –X in be represented by
where –x1 and –x2 are real numbers (Vector Spaces). by substituting coordinate form of vectors by the definition of vector addition
Since x1 and –x1 are real numbers, their sum is a real number because of the closure of addition of real numbers, so the first coordinate of that vector
is real.
Since x2 and –x2 are real numbers, their sum is a real number because of the closure of addition of real numbers, so the second coordinate of that
vector is real. Thus, are real and exist in (Lay, 2015). by the inverse property of real number addition by substituting vector form for

Ge Case Analysis
, Case #1: the turbine generator industry
The default prediction that we'd make using economic theory (or common sense) in the absence of game theory is that, in the turbine generator case,
General Electric should have undercut Westinghouse because the former has lower costs.
But we start to see why it didn 't when we introduce capacity constraints into the Bertrand model. Capacity constraints can stem from two things:
decreasing returns to scale, or demand–uncertainties that create expected inventory–cost risks and induce firms to produce to order and carry backlogs.
The second condition certainly prevails in the turbine generator case.
Anti–trust regulators observed that both GE and Westinghouse were pricing higher than ... Show more content on Helpwriting.net ...
Empirical data suggests successful signaling between the firms in the Cournot aspect of their game also.
Attempts by government to discourage tacit collusion in industries like this one are worse than silly. They harm businesses and consumers, bring in no
extra public revenue, and may actually create monopolies instead of discouraging them! Such perverse competition policies are nevertheless in place in
both the European Union and South Africa.
In the United States, firms can be investigated for collusion by the anti–trust authority only if there is physical evidence of communication about
pricing strategies between competing firms. In the EU and SA, by contrast, competition authorities can investigate merely because they observe that
industry prices aren't at competitive equilibrium.
So what is supposed to happen, under the latter regime, when competitive equilibrium and Nash equilibrium don't coincide? This implies that at least
one firm must sacrifice some profits to deter the authority from investigating. It would be inefficient if all firms in the industry so sacrificed at all
times. For maximum industry profits, one firm at a time should price away from equilibrium and be compensated by the others. Thus we have it that as
a result of (badly theorized) competition policy – policy explicitly designed to deter collusion – we get incentives to

Quantitative Analysis
Linear Programming D.V.– Decision Variables O.F.– Objective Funtion S.T. or CONST – Constraints Constrained Mathematical Model – a model
with an objective and one or more constraints EXAMPLE: 50D + 30C + 6M is the total profit for a production run($50 profit for Desk, $30 profit for
Chair and $6 per pound for steel) Functional Constraints – в‰¤ в‰Ґ or = ––Restrictions that involve expressions with 1 or more variables
EXAMPLE: 7d+3c+1.5M <= 2000 (constraint on raw steel) Variable Constraints– Involve only 1 variable – Nonnegativity Constraint – Xв‰Ґ0 Lower
Bound Constraint – Xв‰ҐL(a number other than 0) Upper Bound Constraint –Xв‰¤U Interger Constraint – X=integer Binary Constraint – X=0 or 1
EXAMPLE FROM HOMEWORK 1 of Constraints... Show more content on Helpwriting.net ...
Slope: the amount X2 increases given one unit increase of X1 Intercept: the point where the line intersects with X2 axis. Use above for Slope – great
formula Redundant Constraints – if removed will not affect the feasible region Feasible Region – The set of all points that satisfy all constraints of the
model HW EXAMPLE Apply Graphical analysis on the Golden Electronics

Lab Report
In chlorambucil treated rats for 5 days (Group III), congested dilated central veins and portal tract were observed. Vacuolated hepatocytes were also
detected. Most hepatocytes were noticed with dense pyknotic nuclei . (Figs. 3,4 ). In chlorambucil treated rats for 10 days (Group IV), hepatocytes
with cytoplasmic vacuolations and congested central veins were frequently noticed. Hepatocytes with abnormal pyknotic nuclei were also detected.
(Figs. 5,6 ) While in chlorambucil treated rats for 15 days (Group V), extensive vacuolated hepatocytes with pyknotic nuclei were seen in most hepatic
lobules. Dilated congested central veins, hepatic sinusoids and portal tracts were also detected. Areas of mononuclear cellular infiltration were also...
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(Fig 16 ) In rat group treated with chlorambucil for 5 days (GroupIII ), vacuolations of some renal tubules were noticed. Some tubular cells showed
pyknotic nuclei(Fig. 17).While those treated for 10 days (Group IV ), vacoulations of renal tubular cells, pyknotic nuclei and loss of normal
architecture of renal tubules could also be observed(Fig. 18) and chlorambucil treated rats for 15 days(Group V ), congestion of peritubular capillaries,
and loss of normal tubular architecture with dilatation of tubular lumen were frequently found(Figs. 19,20) The percentage of the pathological changes
observed in groups III,IV and V showed significat difference from group I.(Table 8) In rats given L–ascorbic acid concomitantly with chlorambucil for
5 days (Group VI ), few tubular cells were appeared with pyknotic nuclei(Fig. 21). In rats given L–ascorbic acid concomitantly with chlorambucil for
10 days (GroupVII ), vacuolations of some renal tubular cells were observed(Fig. 22). While in rats given L–ascorbic acid concomitantly with
chlorambucil for 15 days (GroupVIII ), congestion of peritubular capillaries could be detected (Fig.23). The percentage of pathological changes
observed in groups VI,VII and VIII showed insignificant difference from group I . (Table 8) Table 1 ANOVA, One Way Statistical Analysis of serum
AST ,ALT, and total serm bilirubin in studied groups.(20 rats/group) GroupI

Investment Strategy Linear Programming Essay
INVESTMENT STRATEGY REPORT Submitted to J. D. Williams, Inc. By Mizar Gonzalez Industrial Engineering Department Southern Polytechnic
State university 404–519–2792 February 20, 2008 EXECUTIVE SUMMARY This report is our recommendation for an optimal investment strategy
that would allow J. D. Williams, Inc. to maximize the annual yield of an investment of $800,000 in a diversified portfolio of funds. To find the
investment that would result in the greatest annual yield we have formulated a linear program that takes into account the requirements for the client of
J. D. Williams, Inc. The requirements for the investment portfolio can be found on the section titled "Problem Description" The greatest annual... Show
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The client will realize an annual yield on the $800,000 investment of $94,133.33 if it is allocated in the following manner. The amount to be
invested in the growth fund must be $ 248,889. The income fund must have an investment of $ 160,000 and the money market fund must have an
investment of $ 391, 112. The solution is not surprising given the requirements for the investments. The amount invested in the growth fund yields
the greatest revenue but has to be less than 50% of the total investment and is also limited by its high risk index. The amount is greatest when
invested in the money market fund because it balances the greater risk the other funds are subjected to. Problem answers If the client's risk index
was increased to.055 the investment would be affected in the following manner. The optimal solution becomes $ 98, 800 and the funds would be
allocated in the following manner: Growth fund $ 293, 334, Income fund $ 160, 000, and Money Market fund $ 346, 667. If the original problem is
consulted and the annual yield of growth fund is downgraded to 16% the optimal solution would change to $92, 934 with the funds invested in the
following manner. Growth fund $ 293, 334, Income fund $ 160, 000, and Money Market fund $ 346, 667. The yield of the growth fund still justifies
having a large amount of the portfolio

Julia's Food Booth Case Problem
Julia's Food Booth Case Problem Assignment 3 Max Z =Profit1x1+ Profit2x2+ Profit3x3 A– Formulation of the LP model x1 – number of pizza slice
x2 – number of hot dogs x3 – number of barbecue sandwiches Constraints Cost Maximum fund available for food = $1500 Cost per pizza $6 Г·08
(slices) = $0.75 Cost for a hot dog = $0.45 Cost for a barbecue sandwich = $0.90 Constraint: 0.75x1+0.45x2+0.90x3 в‰¤1500 Oven space Space
available 16.3.4.2 = 384ft^2 384.144=55296 in ^2 Space required for pizza: 14.14 = 196 ^2 inches Space for slice of pizza; 196 Г·8 = 24.50 in ^2
Space for hot dog: 16 in ^2 Space for barbecue = 25 in ^2 Constraint 24.50x1+16x2+25x3 в‰¤55296 Julia can sell at least as many... Show more
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If her estimation does not happen the way she expects, she would be out of $1500, cost of the warmer and the booth rent (each game). In A, she
can earn a profit of $150, so she does not want her lose to be below $150. Second, she should consider some other costs not mentioned in her
analyses, such as hygiene and cleaning products, and some other products like ketchup, mustard, and this kind of products are essential in the type
of business she is considering to be in. Third, if there is a problem with the warmer during the game, she will not be able to recuperate her money
from the people she is leasing the warmer from. Lastly, once she is counting on a friend to help her because she might not be able to attend demand
alone, if the cost of her friend is higher than she can afford, it may be hard for her to find somebody that meets her budge. My advice would be that
Julia should give a try for the first game and calculate how it goes, based on the results obtained in the first game, she could make decisions to adapt
her business once she knows her competitors, customers demand and expectations, because one product can sell more than the other she

Essay about Cheat sheet OMIS 355
In a decision–making problem, anchoring effects occur whenвЂЁa seemingly trivial factor serves as a starting point for estimations
In the following expression, which is (are) the dependent variable(s)? PROFIT = REVENUE – EXPENSES. Profit
The categories of modeling techniques presented in this book include all of the following except: preventive models.
Which of the following categories of modeling techniques includes optimization techniques? Prescriptive models
What is the goal in optimization? Find the decision variable values that result in the best objective function and вЂЁsatisfy all constraints.
The following linear programming problem has been written to plan the production of two products. The company wants to maximize its ... Show more
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Inflow в€’ Outflow в‰¤ Supply or Demand
An oil company wants to create lube oil, gasoline and diesel fuel at two refineries. There are two sources of crude oil. Consider arc 2–4. The per unit
shipping cost of crude B from source 2 (node 2) to refinery 2 (node 4) is $11 and the yield is 85 percent. The following flowchart depicts this problem.
What is the balance of flow constraint for node 7 (Diesel)? .90 X37 + .95 X47 = 75
The objective function value for the ILP problem can never be better than the optimal solution to its LP relaxation.
If a company produces Product 1, then it must produce at least 150 units of Product 1. Which of the following constraints enforces this condition? X1
в€’150Y1 в‰
Ґ0
If a company selects Project 1 then it must also select either Project 2 or Project 3. Which of the following constraints enforces this condition?
X1в€’X2в€’X3в‰¤0
Which of the following is a goal of decision analysis? Help individuals make good decisions
The decision with the smallest expected opportunity loss (EOL) will also have largest EMV
Expected regret is also called EOL.
The minimum EOL in a decision problem will always equal the EVPI. вЂЁ
The Byte computer company produces two models of computers, Plain and Fancy. It wants to plan how many computers to produce next month to
maximize

Thug Life
Mendelian Genetics in Drosophila Melanogaster: Fruit Fly Inheritance
Results
Total count for section & course data: Cross| Phenotype| Section 6 Total| Course Total| ap/ap x +/+| wt| 211| 2604| | Apterous| 58| 824| | | | |
| | | | X(w)X(w) x X(+)Y| wt females| 15| 707| | white females| 9| 597| | wt males| 13| 633| | White males| 13| 614| Totals| 760| 11,754|
Table 1: Total counts for section and course data. Four crosses were experimented to determine F2 generation pooled data: a monohybrid cross,
two–dihybrid crosses, and a sex–linked cross.
X2 calculations for section data:
ap/ap x +/+| Phenotype| Observed| Expected| (O–E)| (O–E)2| (O–E)2/E| wt| ... Show more content on Helpwriting.net ...
X(w)X(w) x X(+)Y| Phenotype| Observed| Expected| (O–E)| (O–E)2| (O–E)2/E| wt females| 707| 638| 69| 4,761| 7.46| White females| 597| 638| –41|
1,681| 2.63| wt males| 633| 638| –5| 25| 0.04| White males| 614| 637| –23| 529| 0.83| Totals:| 2,551| 2,551| | 10.96|
Table 9: Course total results and X2 calculations for the sex–linked F2 X(w)X(w) x X(+)Y cross. The expected phenotypic frequency was 1:1:1:1 and
the observed phenotypic frequency was also approximately 1:1:1:1. The calculated X2 value was 10.96.
The total counts of all four crosses for both the section totals and course totals were recorded in Table 1. The phenotypic ratios and X2 vales, and
614 white males (Table 9). Expected values were calculated by multiplying the totals by 1/4 (0.25) for each phenotype. The X2 values for the section
and course results were 1.50 and 10.96, respectively.
Discussion The X2 value for each cross was calculated to determine that the observed and expected ratios according to Mendelian inheritance were
close in agreement (Garey et. al 2013). In order to determine if the observed deviations for each cross were within the limits expected by chance,10%
and 25% of similar trials. The monohybrid autosomal ap/ap x +/+ cross results were the most similar in comparison of results and probability of all
the crosses. The chi–square results were extremely similar as expected and both accept the hypothesis that deviations

Rate of Return and Non-negativity Constraints
LINEAR PROGRAMMING FORMULATION PROBLEMS AND SOLUTIONS
7–14 The Electrocomp Corporation manufactures two electrical products: air conditioners and large fans. The assembly process for each is
similar in that both require a certain amount of wiring and drilling. Each air conditioner takes 3 hours of wiring and 2 hours of drilling. Each fan
must go through 2 hours of wiring and 1 hour of drilling. During the next production period, 240 hours of wiring time are available and up to 140
hours of drilling time maybe used. Each air conditioner sold yields a profit of $25. Each fan assembled may be sold for a $15 profit. Formulate and
solve this LP production mix situation to find the best combination of air conditioners and fans that yields ... Show more content on Helpwriting.net ...
The firm employs five technicians, working 160 hours each per month, on its assembly line. Management insists that full employment (i.e., all 160
hours of time) be maintained for each worker during next month's operations. It requires 20 labor hours to assemble each Alpha 4 computer and 25
labor hours to assemble each Beta 5 model. MSA wants to see at least 10 Alpha 4s and at least 15 Beta 5s produced during the production period.
Alpha 4s generate $1,200 profit per unit, and Beta 5s yield $1,800 each. Determine the most profitable number of each model of minicomputer to
produce during the coming month. Let X1 = the number of Alpha 4 computers scheduled for production next month X2 = the number of Beta 5
computers scheduled for production next month
Maximize| 1,200X1| +| 1,800X2| | | (maximize profit)| Subject to:| 20X1| +| 25X2| =| 800| (full employment, 5 workers x 160 hours)| | X1| | | в‰Ґ| 10|
(make at least 10 Alpha 4 computers)| | | | X2| в‰Ґ| 15| (make at least 15 Beta 5 computers)| | | | X1, X2| в‰Ґ| 0| (non–negativity constraints)|
Optimal Solution: X1 = 10 X2 = 24 Profit = $55,200 7–20 A winner of the Texas

Hw Solutions
TUTORIAL 2 Linear Programming –Minimisation Special cases Simplex maximisation 1.Innis Investments manages funds for a number of companies
and wealthy clients. The investment strategy is tailored to each client's needs. For a new client, Innis has been authorised to invest up to $1.2 million in
two investment funds: a stock fund and a money market fund. Each unit of the stock fund costs $50 and provides an annual rate of return of 10%; each
unit of the money market fund costs $100 and provides an annual rate of return of 4%. The client wants to minimise risk subject to the requirement that
the annual income from the investment be at least $60,000. According to Innis's risk measurement system, each unit... Show more content on
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Explain. b.If there are no feasible solutions, explain what is needed to produce 30 tons of fuel additive and 15 tons of solvent base. (ASW : Ch 2,
Qn 48) 7.Reconsider the Kelson Sporting Equipment Inc example. Discuss the concepts of infeasibility, unbounded solution, and alternative
optimal solutions as they occur in each of the following situations: a.Management has requested that the production of baseball gloves (regular
model plus catcher's model) be such that the total number of gloves produced is at least 750. That is, 1x1 + 1x2 > 750 b.The original problem has
to be solved again because the profit contribution for the regular model is adjusted downward to $4 per glove. c.What would have to happen for this
problem to be unbounded? (ASW : Ch 2, Qn 49) 8.Recall the Innis Investments problem. Letting x1 = units purchased in the stock fund x2 = units
purchased in the money market fund leads to the following formulation: Min8x1 + 3x2 s.t. 50x1 + 100x2 < 1,200,000Funds available 5x1 + 4x2 >
60,000Annual income x2 > 3,000Units in money market x1, x2 > 0 Obtain and use the computer solution to answer the following: a.What is the
optimal solution, and what is the minimum total risk? b.Specify the range of optimality for the objective function coefficients. c.How much annual
income will be earned by the portfolio? d.What is the rate

I.PrisonerвЂ™S Dilemma As A 2 X 2 Matrix. (X1, X1)(X2, X3).
I.Prisoner's Dilemma as a 2 x 2 Matrix
(x1, x1)(x2, x3)
(x3, x2)(x4, x4)
A1 (C)
A2 (D) B1 (C) B2 (D)
Figure 1. Prisoner 1's Dilemma as a 2 x 2 Matrix, Figure 1 shows the Prisoner 's Dilemma as a 2 x 2 Matrix subject to the following conditions:
a)2 (x1) is greater than x2 + x3 is greater than 2 (x4)
b)x3 is greater than x1
c)x3 is greater than x2
d)x4 is greater than x2.
"C" and "D" represent strategies in which players would "cooperate" or "defect".
What this means is that for both players, strategy 2 dominates strategy 1 (A2 dominates A1 for the row player and B2 dominates 31 for the column
player). However, the choice (A2, B2) results in a payoff (x4) to each player smaller than ... Show more content on Helpwriting.net ...
South Korea 's order of preference among the choices are:
1. unification under a democratic system,
2. "peaceful" unification
3. the status quo,
4. unification under a communist system.
What can be said about these four outcomes as they apply to the Prisoner 's Dilemma? First, neither North nor South Korea sees the status quo as the
worst choice. Second, each side sees the opponents most desired outcome as its worst possible outcome. Third, each side prefers a "peaceful
unification" to the status quo. And lastly, neither side prefers a "peaceful unification" to its own best choice. The result of this is, as in the matrix in
Figure 1 the preferred choice is the dominating strategy for both North (B2 dominating B1) and South (A2 dominating A1). Specifically,North Korea
prefers a communist settlement of unification to either the status quo or a "peaceful" unification. South Korea prefers a democratic settlement to either
the status que or a "peaceful" unification. Thus, the dilemma that faces both sides is: since neither side can have its own best choice, they settle for the
status quo. This is done in spite of the fact that the possibility of a peaceful settlement to unification is exists (a "peaceful" unification) that might be
better for both sides than their own optimal choice. Neither side can choose collective interest over self–interest because they are forced to assume that
the other will follow the

Adjusting Entries
Adjusting Entries – Examples Let's work with some examples. We are working with a one year accounting period that ends on 12/31/X2. Let's use a
three step process. Step 1 – Analyze the transaction. Step 2 – Record in the journal. Step 3 – Post to the ledger. Example 1: On 12/31/X2 (before the
adjusting process), Supplies, an asset, has a balance of $2,500. Employees take a physical account of the supplies on hand. That physical count reveals
that $1,200 of supplies remains. Step 1 вЂђвЂђ The balance of Supplies before the adjusting entry is $2,500. Subtract the amount determined during
the physical count ($1,200). The result ($1,300) represents the amount of supplies that have been used up – Supplies Expense. Assets – Supplies is...
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Example 4: On 7/25/X2, a law firm and its client sign a contract and the client pays $8,400 cash. The contract states the law firm will provide monthly
legal services for 12 months, beginning on 8/1/X2. A regular journal entry is needed on 7/25/X2– debit Cash and credit Unearned Revenue for $8,400.
On 12/31/X2, an adjusting journal entry is needed to record the amount of revenue that has been earned. The entry also results in the correct balance of
the liability account as of 12/31/X2. Computation: $8,400 divided by 12 months equals $700 per month. $700 times 5 months (Aug – Dec) equals
$3,500. $3,500 has now been earned. This complies with the revenue recognition principle – record revenue when it is earned. The liability is reduced
because the services have been provided for 5 months. Liabilities – Unearned Revenue is decreased. Stockholders' Equity – Legal Fees Earned is
increased. The journal entry includes a debit to Unearned Revenue and a credit to Legal Fees Earned for $3,500 When the debit of $3,500 is posted
to Unearned Revenue, the ending balance will be correct ($8,400 less $3,500). Legal Fees Earned goes to the Income Statement. Example 5: On 12
/31/X2, the accountant questions the managers and discovers that revenue of $12,500 has been earned (the services have been provided) but the
clients have not yet been billed. This is an accrual of revenue. Revenue has been earned and must be recorded

Solving Math Equations
MAT101 Case 4 Revised March 2014 (Dr. Rensvold) INSTRUCTIONS: Read the references found on the Background Info page. Study the
examples there, and the ones given below. Work out the problems, showing all the computational steps. This is particularly important for those
problems for which the answers are given. On those problems, the correct procedure is the only thing that counts toward the assignment grade.
SOLVING QUADRATIC EQUATIONS BY FACTORING. References: Waner, 2007 Examples: E1: x 4 0.(x 2)(x 2) 0.The two factors are (x+2) and
(x–2). If EITHER is equal to zero, the corresponding value of x is a root.Solving the two factors for x:(x+2)=0 x=–2(x–2)=0 x 2The two roots
(solutio22ns) are x=2 and x=–2.ANS: x= 2Checking:(2) 4 4 4 0(–2) 4 4 4 0 E2: x 6.x x 6 0. (Must be in this form.)(x+2)(x–3)=0The two factors are
(x+2) and (x–3). Checking:(x+2)(x–3)=x 3x 2x 6 x x 6.If EITHER is equal to zero, the corresponding value of x is a root.Solv222ing the two factors
for x:(x+2)=0 x=–2(x–3)=0 x 3The two roots (solutions) are x=–2 and x=3ANS: x=–2 or +3.Checking:(x) x 6(–2) ( 2) 4 2 6(3) (3) 9 3 6 Problems 1
through 5: Find the roots (values of x when the expression is equal to zero) using factoring. Prove your answers are correct by checking, or showing
that the values of x you computed satisfy the original equation. 1. X(4x 25) = 0 X = 0

Essay on Infinite Surds
| INFINITE SURDS | Ria Garg| | The purpose of my investigation is to find the general statement that represents all values of k in an infinite surd for
which the expression is an integer. I was able to achieve this goal through the process of going through various infinite surds and trying to find a
relationship between each sequence. In the beginning stages of my investigation I came across the sequence of `a1= 1+1 a2= 1+1+1 a3 =
1+1+1+1 While looking at the sequence I came to the realization that there is a very obvious pattern between each n value. The answer to each n
value was plugged into the next n value. For example if you look at this sequence a1= 1+1 = 1.414213562 a2= 1+1+1 =... Show more content on
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Also since the sequence is a square root and, the graph shows no evidence of a root value I can disregard the negative answer to the infinite surd.
x=–bВ±b2–4ac2a X=1+1–41–121 x=1+52 Now, I would like to carry on my investigation and look at another sequence of infinite surds where the first
term of the sequence is 2+2. In the beginning steps of my investigation I came up with the formula an+1 = 1+an, which I will be using to further my
investigation and find the first 10 terms of my new sequence. A1 = 2+2 a6 = 2+a5 = 1.847759065 = 1.999962351 a2 = 2+a1 a7 = 2+a6 =
1.961570561 = 1.999990588 a3 = 2+a2 a8 = 2+a7 = 1.990369453 = 1.999997647 a4 = 2+a3 a9 = 2+a8 = 1.997590912 = 1.999999412 a5 = 2+a4 a10 =
2+a9 = 1.999849404 = 1.999999853 Repeating the same process I completed with the previous sequence of infinite surds, for the next step I will
consider the value of an – an+1

Busn312 Hw3A Essay
Homework 3A
Multiple Choice
Identify the choice that best completes the statement or answers the question.
__B__1.What are the three common elements of an optimization problem?
a.|objectives, resources, goals.|
b.|decisions, constraints, an objective.|
c.|decision variables, profit levels, costs.|
d.|decisions, resource requirements, a profit function.|
___A_2.What is the goal in optimization?
a.|Find the best decision variable values that satisfy all constraints.|
b.|Find the values of the decision variables that use all available resources.|
c.|Find the values of the decision variables that satisfy all constraints.|
d.|None of the above.|
____B3.Limited resources are modeled in optimization problems as
a.|an objective ... Show more content on Helpwriting.net ...
The following linear programming problem has been written to plan the production of two products. The company wants to maximize its profits.
X1 = number of product 1 produced in each batch
X2 = number of product 2 produced in each batch
MAX:|150 X1 + 250 X2|
Subject to:|2 X1 + 5 X2 ВЈ 200|
|3 X1 + 7 X2 ВЈ 175|

|X1, X2 Ві 0|
How much profit is earned per each unit of product 2 produced?
a.|150|
b.|175|
c.|200|
d.|250|
__B__10.A company uses 4 pounds of resource 1 to make each unit of X1 and 3 pounds of resource 1 to make each unit of X2. There are only 150
pounds of resource 1 available. Which of the following constraints reflects the relationship between X1, X2 and resource 1?
a.|4 X1 + 3 X2 Ві 150|
b.|4 X1 + 3 X2 ВЈ 150|
c.|4 X1 + 3 X2 = 150|
d.|4 X1 ВЈ 150|
___D_11.The objective function for a LP model is 3 X1 + 2 X2. If X1 = 20 and X2 = 30, what is the value of the objective function?
a.|0|
b.|50|
c.|60|
d.|120|
___B_12.Why do we study the graphical method of solving LP problems?
a.|Lines are easy to draw on paper.|
b.|To develop an understanding of the linear programming strategy.|
c.|It is faster than computerized methods.|
d.|It

Decisions For Innovate Rather Than Replace. Carter, T. Cis...
Decisions to Innovate Rather than Replace
Carter, T.
CIS–486
Instructor: Dr. Barry Cumbie
12/10/16
University of North Alabama
INTRODUCTION
Finding new and innovative ways of handling existing problems has never been easier or more frequent than today. New technological concepts
seem to be coming to light on what seems a daily basis. With this being said, sometimes it is easier to solve existing problems with existing solutions
rather than finding new ones. When is it acceptable for companies, or even governments, to innovate to find a solution rather than replace with
existing technologies? For example, if a company is increasing its LAN infrastructure would it be best to invest in new or less expensive technologies
even if they are untested, or to replace with more expensive but reliable technologies. This is a question that could be asked by someone deciding on a
home computer, to NASA deciding the best way to launch rockets into space.
Research Background
1
Fiber optic cable is not a new form of technology. It allows for larger amounts of data to be transferred at a rate much higher than traditional copper
cable. This is the main appeal to fiber optic technologies. This being said, it is very expensive to replace current mediums with fiber optic
infrastructure. In the Bloomberg article, "Will Not–Quite–Fiber Make the Grade?", BT has realized that there is a sector of the United Kingdom's
market that wants the ability to transfer larger amounts of

M14056009 Key Questions
1. 7.5/8
The height in metres of a ball dropped from the top of the CN Tower is given by h(t)= –4.9t2+450, where t is time elapsed in seconds.
(a) Draw the graph of h with respect to time
(b) Find the average velocity for the first 2 seconds after the ball was dropped h(0)=(0,450), h(2)=(2,430.4)
= (430.4–450)/(2–0)
= –9.8m/s в€
љ
(c) Find the average velocity for the following time intervals
(1) 1 в‰¤ t в‰¤ 4 h(1)=(1,445.1) h(4)=(4,371.6)
= (371.6–445.1)/(4–1)
= –24.5m/s в€
љ
(2) 1 в‰¤ t в‰¤ 2 h(1)=(1,445.1) h(2)=(2,430.4)
= (430.4–445.1)/(2–1)
= –14.7m/s в€
љ
(3) 1 в‰¤ t в‰¤ 1.5 h(1)=(1,445.1) h(1.5)=(1.5, 438.98)
= (438.98–445.1)/(1.5–1)
= –12.25m/s в€
љ
(d) Use the secant method to approximate the instantaneous velocity at t=1 h(0.5) = (0.5, 448.78) ... Show more content on Helpwriting.net ...
H(2)= –5(2)2+20(2)+1 = –20+40+1 =21 H(2+h)= –5(2+h)2 + 20(2+h) +1 = –5(4+4h+h2) + 40+20h+1 = –20–20h–5h2+40+20h+1= –5h2+21
lim(h–>0) H(2+h)–H(2)/h = –5h2+21–21/h = –5h = –5(0) = 0 в€
љ
(b) A particle's motion is described by the equation d=t2–8t+15 where d and t are measured in metres and seconds. Show that the particle is at rest
when t = 4.
D(4)= (4)2–8(4)+15 =16–32+15= –1D(4+h)= (4+h)2–8(4+h)+15= 16+8h+h2–32–8h+15= h2–1limD(4+h)–D(4)/h = h2–1+1/h = h =0 в€
љ
6. 4/4
For the following graph

(a) Determine the intervals between which the rate of change is positive and negative.The function is increasing at x<–1 and x>1, hence its rate of
change is positive. The function is decreasing at –1<x<1, hence its rate of change is negative. в€
љ
(b) State where the rate of change is zero. The instantaneous rate of change is zero at x=–1 and x=1 в€
љ
(c) List the local maximums and minimums of the function.F(–1) is a local maximum and F(1) is a local minimum. в€
љ
7. 10/10
For the function f(x) =2x3–7x2+4x+1(a) Find the instantaneous rate of change at x=0 and x=1(1) F(0+h) = 2(h)3 – 7(h)2+4(h)+1 =2h3–7h2+4h+1F(0)
= 1lim(h–>0) (F(0+h)–F(0))/h = (2h3–7h2+4h+1–1)/h = (2h3–7h2+4h)/h = 2h2–7h+4 = 4 в€
ґthe instantaneous rate of change at x=0 is 4 в€
љ

Advantages And Disadvantages Of Noble Fir
Introduction Abies magnifica and Abies procera, often referred to as red fir and noble fir, are two closely related evergreen coniferous tree species
residing in moist soils at mid and high elevations of western North America (Zavarin et al. 1978). Ranging from 10–20 centimeters in sizes, these two
firs are distinguished by their "hockey–stick" structured needles among their genus (Parker 1963). Red fir, in particular, has the subgroups California
red firs and intermediate Shasta red fir (Mathiasen and Daugherty 2008). Controversies on whether red fir and noble fir hybridize have long been
debated in the scientific world (Critchfield 1988; Silen et al. 1965).
Morphologically, red firs consist of cones larger than 15 centimeters, chained barks, more diamond–shaped needles that exclude a groove, as well as
basal bud scales pubescent throughout (Parker 1963; Hunt 1993). Noble firs tend to be smaller than 15 centimeters and include narrow ridged
barks, grooved needles, and central basal bud scales (Parker 1963; Hunt 1993). Based on his research of thirteen separated sites, Parker reasoned that
most of the fir at higher altitudes in southern Oregon as well as north western California were noble fir (Parker 1963). Nevertheless, classification of
the morphological affiliations of red fir, noble fir, and Shasta red fir are disputable due to their variations. Mathiasen and Daugherty analyzed the
characteristic of different degrees of mistletoe infection of host–specific mountain

Aaron Hernandez Murder Trial
Results The mean attitudinal sore of all 25 respondents towards the Aaron Hernandez murder trial was 71. As can be seen in Table 2 below, this
mean falls in the undecided category. The sample standard deviation of the scores was 11.74. The distribution of the 25 scores is seen as well. The
two most frequently scored categories are undecided and unfavorable. The category with the fewest respondent is favorable. TABLE 2: Distribution of
Scores Attitude CategoriesScore RangeFrequency Very Favorable117
–140Favorable93–1162 Undecided69–9213 Unfavorable45–688 Very
Unfavorable20–44The 13 hypotheses listed in the Literature Review section were statistically tested. Each hypothesis is again listed below along with
the... Show more content on Helpwriting.net ...
The mean attitudinal score for FPU students who did not know of the Aaron Hernandez murder trial was 7.38. The calculated t–value was 9.64. Using
the one–tailed T table and an N of 25, it was determined that the table t value was 2.485 at .01 level of significance. Thus, H6B is accepted. FPU
students who know of the Aaron Hernandez murder trial had a statistically significant less favorable attitude towards the Aaron Hernandez murder
trial than those who don't know of the Aaron Hernandez murder trial. H7: There will be a statistically significant difference between the attitudes of
Franklin Pierce University Students who are unwilling to be a juror and who are willing to be a juror in the Aaron Hernandez murder trial
(Spearman's rank order correlation) H8: There will be a statistically significant difference between the attitudes of a conservative, a moderate, and a
liberal towards the Aaron Hernandez murder trial (Tested with analysis variance) H9: There will be a statistically significant difference between the
attitudes of a independent, a republican, and a democrat towards the Aaron Hernandez murder trial (Tested with analysis variance) H10: There will be
a statistically significant direct positive or negative correlation between the Franklin Pierce University Students who have been to Patriots games
(tested with Pearson's r) H11: There will be a statistically significant difference between the attitudes of Franklin

Fruit Flies : A Genetic Analysis Of Inheritance Essay
Fruit Flies: A Genetic Analysis of Inheritance in Drosophila melanogaster
Introduction
Mendelian Genetics Gregor Mendel, the father of genetics, discovered principles of inheritance through breeding peas of different color and texture. He
crossed several types of peas to investigate dominance relationships, variability, and genetic probability. Through his experiments, he laid down the
foundation of inheritance that geneticists use to this day (Griffiths, 2015). From these crosses, Mendel pioneered modern genetics by developing seven
laws of inheritance. The first and second law are investigated in this experiment. Mendel's first law of inheritance is also known as the law of equal
segregation. This law states that the two members of a gene pair segregate equally into gamete cells. In other words, each sex cell contains only one
copy of a gene. Mendel discovered the second law–now known as the law of independent assortment–while studying dihybrid crosses. This law states
that genes assort independently during gamete formation. This explains how there are different combinations of different phenotypes. In peas, for
example, yellow color is not always associated with a round shape. There can be different combinations of round and wrinkled shape with yellow and
green color (Griffiths, 2015). Though there are some exceptions to this rule, such as linked genes and sex–linked genes, the traits investigated in this
experiment strictly follow Mendelian inheritance.
A monohybrid

X2: X-Men United Essay
X2: X–Men United
The ultimate test of a good sequel is its ability to stand alone. X2: X–Men United passes this test with flying colors. Though the story line follows the
classic good versus evil paradigm, it is not dependent on the original X–Men movie to tell its story. X2's plotline twists keep the viewer wondering
about the loyalties of characters that appear at one moment to switch to the good side, and then just as easily revert to their roles as bad guys. Requiring
the viewer to ask, "How do we know who we can trust?"
Equally, the film's visual effects are stunning without being overwhelming or redundant. We do not see action sequences repeated from the first movie
but fresh new twists that appear as visual candy. Many ... Show more content on Helpwriting.net ...
In this society fear motivates an otherwise just government to enact a mutant registration act. This act hauntingly reminds viewers of how atrocities
began against the Jews, a people considered different in another era of hostility and fear.
It is easy for the viewer to temporarily suspend disbelief because they feel as if they have entered into the comic book world of the X–Men. Director,
Bryan Singer, has gone to great lengths to create an environment that appears plausibly realistic thus, drawing the audience even deeper into the
plotline. Costumes are dazzling with vivid color and sets are as gritty as they are realistic. Through this filmmaking magic even the most unrealistic
comic book characters seem completely credible. Combine this with editor/composer John Ottman's romantic style and sweeping score and the viewer
finds themselves thoroughly entrenched in the complexities of this comic book world.
All the original characters, plus a few new ones, return in X2 only this time with more depth and soul. The conflict between Charles Xaiver's
(Patrick Stewart) idealistic view and Eric Lensherr's (Ian McKellen) fatalistic outlook takes on more prominence as Xaiver's (Stewart) powers are used
by William Stryker (Brian Cox) as a force of evil against Xaiver's will. At this point only his

why i want to take and complee the lpn program at stone...
Elementary Algebra problems you can use for practice. Remember, you may not use a calculator when you take the assessment test. Use these
problems to help you get up to speed. _____________________________________________________________________________________
Perform the indicated operation. Write in lowest terms if necessary. 4 1 1)– 5 4 A) C) 2) 9 20 B) 21 20 21 20 B) 1040 D) –280 A) –87 1 42 B) 1 11)
4(9a + 10b) – (10a – 7b) 3 D) 14 B) –6 C) 6 D) –6859 Simplify the algebraic expression. 5 14 A) 26a + 33b D) –5 4) 19 – (–19) + 14 + (–14) B) 26a +
47b C) 26a + 17b 13 3 A) –7 B) 17,576 C) –24,389 5 C) 14 3) 26 Г· – A) 80 10)... Show more content on Helpwriting.net ...
Simplify if possible. 21x4 7x3 44) 9x2 28x5 A) 3x4 28 B) 28x4 3 C) 28x8 3 D) 189x2 196 49) –8 s–t B) 0 C) Simplify the rational expression. m 2 –
5m – 50 43) 40 – 4m A) – x2 10x – 16 2 – 64 x x2 – 64 –16 s–t D) 8 s–t 3 6 + x x–7 A) 3(3x – 7) x(x – 7) B) 3(3x + 7) x(x – 7) C) 9 x(x – 7) D) 9 2x
– 7 Simplify the complex rational expression. 1 1 4 x2 50) 1 1 + 2 x A) x–2 2x B) x+2 2x C) 2x x+2 D) 2x x–2 Solve the equation. 1 20 51) 1 + = x
x2 Solve. 56) If 5 apples cost $2.50, how much would 20 apples cost? A) 5, –4 C) 5, 4 D) – A) $0.03 1 1 , 5 4 Solve the rational equation. Check your
answer. 7 3 3x + 21 + = 52) x + 21 x – 7 x2 + 14x – 147 A) {1} B) { } C) {0} D) {–1} a–c ac B) b = a+c C) b = ac D) $10.00 Solve the problem. 57)
Determine whether the ordered pair (–4, 3) satisfies the equation 4x – 6y = –34. A) Yes B) No 58) If m varies directly as p, and m = 15 when p = 3, find
m when p is 9. A) m = 3 ac a–c ac D) b = a+c B) m = 81 C) m = 25 Solve the equation for the indicated variable. 1 1 1 53) + = for b a b c A) b = B)
$40.00 C) $0.50 B) –5, 4 D) m = 45 Solve the equation. 59) 5x2 = 4x + 9 5 ,0 A) 9 C) Solve the proportion. 5

Parabola Y X2 Change
The shape of the basis parabola y=x2 changes for different forms of the parabolic function causing it to translate, reflect or dilate. Dilation
(widening or narrowing) of the parabola occurs when the basis parabola y=x2 is multiplied or divided (m) therefore changing the equation to
either y=mx2 or y=x^2/m. For instance, if the parabola is multiplied by two the parabola becomes narrower whereas if the parabola is divided by two
the parabola becomes wider. This is evident in the graph in question 1b as when the basis parabola is multiplied by fourteen the parabola becomes
narrower however when the basis parabola is divided by fourteen it becomes wider. Reflection of the parabola occurs when the basis parabola y=x2 is
changed to y=–x2. For example,... Show more content on Helpwriting.net ...
Vertical (upwards or downwards) translation of the parabola occurs when the basis parabola y=x2, y–value of each point is increased or decreased
therefore changing the equation to either to y=x2+h or y=x2–h. For instance, in order to translate the parabola upwards by 5 units it shifts the general
point (a, a2) to (a, a2+5) therefore making the equation, y= x2+5. The vertex of this parabola is now (0,5) but it still has the same axis of symmetry.
Likewise, when the basis parabola becomes y=x2–5 the parabola is translated 5 units down with the vertex (0,–5). This can be seen through the graph
in question 1a as the parabolas are vertically translated upwards or downwards by using the addition or subtraction of fourteen. Conversely,
horizontal translation of the parabola occurs when the translation parabola equation y=x2В±h is changed to y=(xВ±h)2. Therefore, the horizontal
translation for the parabola is changed by the value of the variable h, that is subtracted from x before the squaring operation. For example, in order to
translate the parabola to the left by 4 units it shifts the general point (a, a2) to (a, (a+2)2) therefore making the equation, y= (x+2)2. The vertex of this
parabola is now (0,4). Likewise, when the basis parabola becomes y=(x–2)2 the parabola is translated 2 units to the right with the vertex (0,–4). This
can be seen through the graph in

Theme Of Repetition In Lord Of The Flies
Imagine being trapped on an island with a group of power hungry boys controlled by savagery and fear. Lord of the Flies is a story about a group
of boys who crashed on an island while flying to safety away from the war. The main leaders of the boys are Ralph and Jack. Jack leads a group
called the savages who hunt to prove themselves powerful, whereas Ralph's group is focused on being rescued. They live in fear of a beast who
Jack and his group insist on hunting and killing. In chapter nine, a boy named Simon goes to where the beast supposedly is and finds that is is just
a pilot with a parachute who landed on the island after his plane exploded. He goes to tell the others, but they are so encaged in their fear of the
beast and the storm that they believe he is the beast and rip him apart. Simon dies and most boys don't fully realize the extent of what they have done
until later because of that same fear. Fear can overtake your mind and body causing you to do terrible things that can hurt you and others. In chapter 9
of Lord of the Flies, William Golding employs repetition, symbolism, and foreshadowing to convey the theme that... Show more content on
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When Golding really wants things to be noticed, he repeats them and makes them stand out. One of the main things They repeat is "Kill the beast!
Cut his throat! Spill his blood! Do him in!" (Golding 175). The boys chanting this over and over as they rip simon apart show how the fear and
savagery can take over. Jack wants to be big and bad and in charge. He took a small, normal fear, and turned it to something terrible. He wants to
hunt and to kill to prove his worth, and they say this to egg each other on. To remind them that this is okay because it is 'the beast' and 'the beast' is
bad, but the savagery they created is so much worse than any beast could ever be. This shows how hard it really is to go back and fix civilization,
especially when someone was murdered because of the

Goodrich Rabobank Interest Rate Swap Essay example
1.How large should the discount (X) be to make this an attractive deal for Rabobank?
2.How large must the annual fee (F) be to make this an attractive deal for Morgan Guaranty?
3.How small must the combination of F and X be to make this an attractive deal for B.F. Goodrich?
4.Is this an attractive deal for the savings banks?
5.Is this a deal where everyone wins? If not, who loses?
Introduction:
Players: Morgan Bank, Rabobank, and B.F. Goodrich, Salomon Brothers, Thrift Institutions and Saving Banks
Goodrich:
In early 1983, Goodrich needed $50 million to fund its ongoing financial needs. However, Goodrich was reluctant to borrow (short term debt) from its
committed bank lines because of the following reasons:
1.It ... Show more content on Helpwriting.net ...
Invest in short term treasury bills, large CD's of commercial banks.
Floating rate notes of major US banks whose yields were tied to the Treasury bill notes.
Buy Goodrich floating rate notes with a yield tied to the LIBOR.
Structuring of the Swap:
In the swap depicted above the following can be calculated:
1.Goodrich receives the following amount semi annually:
–(LIBOR+0.5%)+(LIBOR–x1)–10.7% = x1+11.2%
2.Morgan receives the following amount as fees: –(LIBOR–x1)+(LIBOR–x2)+10.7%–10.7% = x1–x2.

Note: As stated in the case (footnote #2 on page 362) this fee can be anywhere between 8 basis points and 37.5 basis points.
3.Rabobank receives following amount semi annually: –(LIBOR–x2)+10.7%–10.7% = x2–LIBOR i.e. it will give out LIBOR – x2.
From exhibit 3 the following is also given:
4.Since Goodrich has BBB– credit rating it could raise capital at a fixed rate probably at 12.5% for 7–10 years.
5.Also, Rabobank could raise floating rate debt at LIBOR – 1/8% (LIBOR + Вј% – 3/8%) since it is an AAA rated bank.
Therefore,
6.From (1), and 4, Goodrich saves the following amount in semiannual interest payments : 12.5% – (x1+11.2%) = 1.3%–x1.
7.From (2), and (5) Rabobank saves the following amount in semiannual interest payments: LIBOR – 1/8% – (LIBOR –x2) = x2 – 1/8%.
8.For this deal to occur,

Nash Arbitration Methods: Game Theory For Students Without
Nash Arbitration Methods: Game Theory for students without calculus
William P. Fox
Naval Postgraduate School
Abstract
We illustrate a method to obtain the solution to Nash arbitration using only methods involving college algebra. A necessary component of the Nash
arbitration is the status quo point which is usually the security levels found from the Prudential Strategies. We use linear programming to find these
security levels using the SimplexLP of the Solver. We show how golden section search, used as an iterative numerical method with Excel, is used to
find the solution value for the x coordinate of the Nash arbitration scheme. Then we show how we find the y coordinate using the equation developed
from the Pareto optimal line. Having ... Show more content on Helpwriting.net ...
His interests include applied mathematics, optimization (linear and nonlinear), mathematical modeling, statistical models for medical research, game
theory, and simulation models. He is currently the Past–President of the Military Application Society of INFORMS.
Introduction
We teach a course in decision making titled modeling in conflict. Our main topics in this course are applications and algorithms in decision theory and
game theory. In our game theory course, we cover such main topics as utility theory, zero sum games & constant sum with their methods of solutions,
non–zero sum games with Nash equilibriums and strategic moves, three person zero sum and non–zero sum games, and Nash arbitration scheme for
bargaining. To somewhat complicate our teaching is that the course requirement is college algebra, not calculus. Our other main issue is that we are
limited to the technology that we use. Currently that technology is Excel since Excel is the software that our students will have after graduation in the
careers.
Our colleague, Frank Giordano, developed a geometric approach to Nash arbitration involving triangles, mid–points, and similar triangles to obtain both
the arbitration point and how strategically to play the arbitration game. We found that often geometry is harder to extract from our students memories
than the basic algebra concepts. We also wanted to give the students some technology using Excel to assist them in their efforts also

Applying A Notation Involving Subscripts Essay
To allow for generalizations of the simple regression analysis to large numbers of variables, it is convenient to adopt a notation involving
subscripts. It will be assumed that X1, X2, X3, . . . denote the variables under consideration. Accordingly X11, X12, X13, . . . will denote the values
assumed by the variable X1, and X21, X22, X23, . . . will denote the values assumed by the variable X2, and so on. With this notation, a sum such as
X21 + X22 +вЂЏ X23 вЂЏ+... +вЂЏX2N could be written в€‘_(j=1)^Nв
–’X_2j , в€‘_jв
–’X_2j , or simply в€‘в
–’X_2 . When no ambiguity can
result, we use the last notation.
Just like simple regression model, a multivariate regression equation is an equation for estimating a dependent variable, say X1, from the
independent variables X2, X3, . . . and is called a regression equation of X1 on X2, X3, . . . etc. In functional notation this is sometimes written
briefly as E[X1] = F(X2, X3, . . .) (where E[.] refers to statistical expectation).
For the case of three variables, the simplest linear regression equation of X1 on X2 and X3 has the form
X_1=b_1.23+b_12.3 X_2+b_13.2 X_3(2.14) where b1.23, b12.3, and b13.2 are constants. The double subscript in for example b12.3В¬ indicates
the coefficient of the model relating variable 1 to 2 keeping variable 3 constant. If we keep X3 constant in this equation, the graph of X1 versus X2
is a straight line with slope b12.3. If we keep X2 constant, the graph of X1 versus X3 is a straight line with slope b13.2. Due to the fact

Math 221 Week 5 Assignment Essay
Buried Treasure
Ashford University MAT 221
Buried Treasure
For this week's Assignment we are given a word problem involving buried treasure and the use of the Pythagorean Theorem. We will use many
different ways to attempt to factor down the three quadratic expressions which is in this problem. The problem is as, ""Ahmed has half of a treasure
map, which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. Vanessa has the other half of the map. Her half
indicates that to find the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x + 4 paces to the east. If they share their
information, then they can find x and save a lot of digging. ... Show more content on Helpwriting.net ...
Running with this information can now write out the equation AB2 + BC2 = AC2. One important thing is that we must note that AB is equal to "X"
and the line segment of BC is equal to that of 2x+4, and that AC will be equal to that of 2x+6. So we will now input this information to create (x)2 +
(2x + 4)2 = (2x + 6)2 and begin factoring each term into two sections. These two sections will be as x*x + (2x + 4)(2x + 4) = (2x + 6)(2x + 6). x times
x is x2. An important tool to use now would be the FOIL method, so we will take (2x + 4)(2x + 4) and create 4x2 + 16x + 16. Right off the bat we
notice that we have like terms. So we will add x2 to 4x2 to get 5x2. This will create 5x2 + 16x + 16 = 4x2 + 24x+ 36. Now we will use the subtraction
property to get 5x2 – 4x2 + 16x – 24x + 16 – 36 = 0, however we still have like terms, so because 5x2 is a like term with –4x2 we will add them
together to get x2. We will also combine 16x and –24x and also 16 and –36 which are also like terms and create –8x and –20, our equation should now
look like x2 – 8x –– 20 = 0.We will now factor the equation from left to right, first factoring x2 which has 1 coefficient so the fact will be 1 and –1.
The other term will be 20 which have no coefficient so we will do 5x4 and then 4 still can be divided so 2x2. This will create 20=225.
We will now take a look using the Prime Factorization formula which will aid us in finding the number

Mathematical Modeling and Applications
IE 456 MATHEMATICAL MODELING AND APPLICATIONS Homework 1 1. [15 points] Consider the following linear programming problem:
Min z = 3x12x23x3 Subject to x1+2x2 +x3 14 x1+2x2+4x3 12 x1 x2 +x3 = 2 x3 3 x1; x2 unrestricted (a) [6 points] Reformulate the problem so it
is in standard format. (b) [6 points] Reformulate the problem so it is in canonical format. (c) [3 points] Convert the problem into a maximization
problem. 2. [20 points] A lathe is used to reduce the diameter of a steel shaft whose length is 36 inches (in.) from 14 in. to 12 in. The speed x1 (in
revolutions per minute), the depth feed x2 (in inches per minute), and the length feed x3 (in inches per minute) must be determined. The duration of the
cut is given... Show more content on Helpwriting.net ...
(1: tanks, 2: planes, 3: missile batteries). (a) [12 points] Max x1+ 3x2+ 2x3 (22) s.t. 600; 000x1+2; 000; 000x2+800; 000x3 900; 000; 000 (23) x1 200
(24) x2 200 (25) x2 300 (26) x2 4x3 0 (27) x2+ 2x3 0 (28) x1; x2; x3 0: (29) (22) gives the total utility obtained from the military logistics items to
maximize. (23) is the budget constraint that restricts the money to spend on the items. (24) { (26) give the limits on the quantity of tanks and planes to
acquire. (27) and (28) ensure the ratio of the tanks and missile batteries are within the given limits. Finally, (29) ensure non–negativity of the quantity
of items to buy. (b) [3 points] (23) can be rewritten as: 0:6x1 + 2x2 + 0:8x3

Drosophila Ausomal and Sex-Linked Cross Essay
Drosophila Autosomal and Sex–Linked Cross The idea of the project was to experiment breeding Drosophila Melanogaster (fruit fly) to figure out if
certain genes of that species were sex linked or not (autosomal). A mono–hybrid cross and di–hybrid cross was performed. For the mono–hybrid cross,
white eyed female and red eyed male were placed in one vial for them to reproduce. For the di–hybrid cross, red eyed and normal winged flies and
sepia eyed and vestigial winged flies were placed in their vial to reproduce. In the mono–hybrid cross the results expected were within a 1:1:1:1 ratio.
Expected results similar to the expected desired null hypothesis proposed with what the F1 parental generation breeds. The potential results would have
had... Show more content on Helpwriting.net ...
His second theory was the law of independent assortment which occurs in metaphase I. This theory was construed based on the fact that a new
phenotypic ratio occurred in the F2 generation with a di–hybrid cross (9:3:3:1). Here, alleles (genes) are expected to segregate independently from each
other (Cain, Urry, & Reece, 2010). Thomas Hunt Morgan continued Mendel's work and in 1911, decided to experiment onDrosophila melanogaster,
also known as fruit fly. His study on them was due to the fact that they had only 4 chromosomes which 3 were autosomal and 1 was a sex
chromosome. His study proved that eye color was sex linked (Cain, Urry, & Reece, 2010). Other traits were not linked. Any mutation can change the
result of a mutated gene which would give variations. Such is the case in the eyes of the fruit flies. The purpose of this experiment is to see if
Mendel and Morgan both had valid points. Examining the fruit flies all the way to the F2 generation would give way to prove or disprove Mendel's
expected results and Morgan's visual results.
Method and Materials
A three week experiment was proposed. On week 1, the preparation of vials was the beginning of the experiment. An equal amount of food and water
was measured and then mixed. This mixture was to be the food for the larvae. The mixture was placed in the vile with a height of 2–3 cm. The mixture
had to be placed inside and made sure by pressure that no air pockets were

Change In Film
Film, being both visual and audible, has become a power source of art throughout its development. In many cases, films are used as a way to promote
social change. The 2000 X–Men film can be seen as a cry for equality. A supernatural film about mutants versus humans sends an underlying message
about how people may not feel accepted or like they fit in just because they don't conform to society. During the mid–1950s and early 1960s movies
were used to express the desire to break free, as a people, from the ideals of perfection and gender norms as America underwent a huge social change
that quickly became known as The Sexual Revolution. (Escoffier, Sexual Revolution). Films such as Douglas Sirk's All That Heaven Allows (1955),
Nicholas Ray's Rebel Without a ... Show more content on Helpwriting.net ...
Then the pressures of society weigh down on her and cause her to go back on her feelings, which on it's own conveys that if you want to be happy,
you need to be your own person. Rebel Without a Cause (1955) is about a troubled teenage boy that wants to find a purpose in life despite being
neglected by his parents and feeling as if he didn't belong in his society. This ultimately leads to a tragic end for him and it sends the message that not
being accepted isn't okay. Some Like It Hot (1959) is about men who dress as women to escape thugs and the women they meet who march to the beat
of their own drum. This movie was heavily considered against the norm but was made despite Americanfilm censorship's contempt. Men in women's
clothing was extremely looked down upon, which made this movie bold and inspirational to anyone who felt like they wanted to do or be something
or someone although it might be heavily frowned upon ("Some Like It Hot (1959) Analysis"). In Mulvey's "Visual Pleasure and the Narrative
Cinema," she talks about the already preconceived notions we have already formed about gender and how that plays into movie making and

Statistics Paper
Case Study: Condo Sales Case A. Brief introduction to the case This case involves an investigation of the factors that affect the sale price of oceanside
condominium units. The sales data were obtained for a new oceanside condominium complex consisting of two adjacent and connecting eight–floor
buildings. The complex contains 200 units of equal size (approximately 500 square feet each). Variables Dependent variable 1. Sale price: Y
Independent variables 1. Floor height: x1 2. Distance from elevator: x2 3. View of the ocean: x3 4. End unit: x4 5. Furniture: x5 Issues identified To
build a regression model that accurately predicts the sale price of a condominium unit sold at... Show more content on Helpwriting.net ...
iii) The hypotheses of interest concern the interaction parameter ОІ10. Specifically, H0: ОІ10 = 0 Ha: ОІ10 < 0 Test statistic: t = 1.378, p–value =
0.170, respectively. The lower–tailed p–value, obtained by dividing the two–tailed p–value in half, is 0.170/2 = 0.085. Since we are testing using О± =
0.1, О± exceeds the p–value, thus we can reject H0 and conclude that the rate of change of the sale price of the condos with distance from the
elevator(x2) decreases when the view(x3) decreases ; that is x2 and x3 interact positively. Thus, it appears that the interaction term should be included
in the model. Therefore the new multiple regression model is: E(y) = 198.934 – 6.474 x1 – 5.746 x2 + 58.666 x3 – 21.678 x4 + 0.872 x12 + 0.533x22
– 0.264 x1x2 – 5.93 x1x3 + 0.92 x2x3 C. Insight for business decision making Regression models are very useful in determination of important
statistics in the corporate world. For instance, multiple regression models can be used to determine whether advertising, product loyalty, or price is the
most important determinant of business growth. With this information, businesses are able to focus their resources into the channels which will help
them achieve their targets effectively. It can also be used to calculate the predicted mileage for a vehicle with respect to different possible variables
such as weight of vehicle, age of vehicle, and climate of country. Car manufacturers can capitalize on

Unit 4 Case Problem 2 Denim
We have the given details like the objectives of making profit of $2.25 per yard for denim and $3.10 for yard of Corduroy and constraints of
processing time of 3.2 hour for Corduroy and 3 for Denim, 6500 pounds of total cotton and 3000 hours of processing time and the demand is
unlimited for Denim and 510 maximum for corduroy. By table above details, CategoryX1X2в‰Ґ0 Z2.253.1Maximum Cotton57.5в‰¤6500 Processing
Time33.2в‰¤3000 Demand01в‰¤510 InterceptsX1X2Cotton0866.66676500 130006500 Processing Time0937.53000 100003000
Demand0510510 Now plot the line for cotton using scatter plot for 0, 1300 and 866.6, 0, processing time of 0, 1000 and 0, 510, and Demand of 0,510.
The variable X1 can be calculated using simple formula = =MMULT (MINVERSE (B5:C6), E5:E6) which gives X1=456 and X2 =510. We profit
under optimum production in the area represented by 4 points represented as * in the graph. We have 4 corner points and excluding 0, 0, we have
456, 510 (B in the graph), 0, 510 (A in the graph) and 1000, 0 (C in the graph).... Show more content on Helpwriting.net ...
This result is same as the Solver output. Below is Excel calculation of the co–ordinates used for plotting the graphics. Below graph is plotted using line
for cotton using points 0, 1300 and 866.66, 0, line for processing time using 0,1000 and 937.5, 0 and demand line 0, 510 with infinite for Denim. A,
B, C are area of the corner point where maximum production can be achieved and at point B (X1=456, X2= 510) the production is maximum.
Conclusion: The output of the graphic method and solver came up with required denim and corduroy cloth in yards as 456 and 510 to produce
maximize profit of

Mr Huckey Case Study

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