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4.2 Logarithmic Functions
                           Day 3


Romans 5:2-5 Through him we have also obtained access by
faith into this grace in which we stand, and we rejoice in hope
of the glory of God. More than that, we rejoice in our
sufferings, knowing that suffering produces endurance, and
endurance produces character, and character produces hope,
and hope does not put us to shame, because God’s love has
been poured into our hearts through the Holy Spirit who has
been given to us.
Graph to show that log b x and b are inverses.
                                x
Graph to show that log b x and b are inverses.
                                x



                  Let b = 2
Graph to show that log b x and b are inverses.
                                 x



                  Let b = 2
             x
    y1 = 2        y2 = log 2 x       y3 = x
Graph to show that log b x and b are inverses.
                                 x



                  Let b = 2
             x
    y1 = 2        y2 = log 2 x       y3 = x

                       log x
                  y2 =
                       log 2
Graph y1 = log(2x + 5) and discuss.
Graph y1 = log(2x + 5) and discuss.


V. Asymptote:
Graph y1 = log(2x + 5) and discuss.


V. Asymptote:    2x + 5 = 0
Graph y1 = log(2x + 5) and discuss.


V. Asymptote:    2x + 5 = 0
                        5
                  x=−
                        2
Graph y1 = log(2x + 5) and discuss.
Graph y1 = log(2x + 5) and discuss.

X Intercept:
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:    log ( 2x + 5 ) = 0
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:    log ( 2x + 5 ) = 0
                 0
               10 = 2x + 5
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:    log ( 2x + 5 ) = 0
                 0
               10 = 2x + 5
               1 = 2x + 5
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:    log ( 2x + 5 ) = 0
                 0
               10 = 2x + 5
               1 = 2x + 5
               −4 = 2x
Graph y1 = log(2x + 5) and discuss.

X Intercept:   (−2,0)
bonus math:    log ( 2x + 5 ) = 0
                 0
               10 = 2x + 5
               1 = 2x + 5
               −4 = 2x
               x = −2
Graph y1 = log(2x + 5) and discuss.
Graph y1 = log(2x + 5) and discuss.

Y Intercept:
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
               y ≈ .6990
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
               y ≈ .6990

Domain:
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
               y ≈ .6990

               ⎧          5 ⎫
Domain:        ⎨ x : x > − ⎬
               ⎩          2 ⎭
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
               y ≈ .6990

               ⎧          5 ⎫
Domain:        ⎨ x : x > − ⎬
               ⎩          2 ⎭

Range:
Graph y1 = log(2x + 5) and discuss.

Y Intercept:   y = log ( 2 g0 + 5 )
               y = log 5
               y ≈ .6990

               ⎧          5 ⎫
Domain:        ⎨ x : x > − ⎬
               ⎩          2 ⎭

Range:         {y : y ∈R}
Graph f (x) = log   3
                      ( x + 1)
Graph f (x) = log    3
                       ( x + 1)
               log ( x + 1)
        y1 =
               log   ( 3)
Properties of Natural Logs
Properties of Natural Logs
   1) ln 1 = 0
Properties of Natural Logs
   1) ln 1 = 0
         because e = 1
                   0
Properties of Natural Logs
   1) ln 1 = 0
         because e = 1
                   0


   2) ln e = 1
Properties of Natural Logs
   1) ln 1 = 0
         because e = 1
                   0


   2) ln e = 1
         because e = e
                   1
Properties of Natural Logs
   1) ln 1 = 0
         because e = 1
                   0


   2) ln e = 1
         because e = e
                   1

           x
   3) ln e = x
Properties of Natural Logs
   1) ln 1 = 0
         because e = 1
                   0


   2) ln e = 1
         because e = e
                   1

           x
   3) ln e = x
         because e = e (and we have a
                    x    x

         composite of inverse functions)
Properties of Natural Logs
   1) ln 1 = 0
           because e = 1
                      0


   2) ln e = 1
           because e = e
                      1

                 x
   3) ln e = x
           because e = e (and we have a
                      x    x

           composite of inverse functions)
          ln x
   4) e          =x
Properties of Natural Logs
   1) ln 1 = 0
           because e = 1
                      0


   2) ln e = 1
           because e = e
                      1

                 x
   3) ln e = x
           because e = e (and we have a
                      x    x

           composite of inverse functions)
          ln x
   4) e          =x
           composite of inverse functions again
HW #5

There are no secrets to success. It is the result of
preparation, hard work, and learning from failure.
                                 Colin Powell

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0405 ch 4 day 5

  • 1. 4.2 Logarithmic Functions Day 3 Romans 5:2-5 Through him we have also obtained access by faith into this grace in which we stand, and we rejoice in hope of the glory of God. More than that, we rejoice in our sufferings, knowing that suffering produces endurance, and endurance produces character, and character produces hope, and hope does not put us to shame, because God’s love has been poured into our hearts through the Holy Spirit who has been given to us.
  • 2. Graph to show that log b x and b are inverses. x
  • 3. Graph to show that log b x and b are inverses. x Let b = 2
  • 4. Graph to show that log b x and b are inverses. x Let b = 2 x y1 = 2 y2 = log 2 x y3 = x
  • 5. Graph to show that log b x and b are inverses. x Let b = 2 x y1 = 2 y2 = log 2 x y3 = x log x y2 = log 2
  • 6. Graph y1 = log(2x + 5) and discuss.
  • 7. Graph y1 = log(2x + 5) and discuss. V. Asymptote:
  • 8. Graph y1 = log(2x + 5) and discuss. V. Asymptote: 2x + 5 = 0
  • 9. Graph y1 = log(2x + 5) and discuss. V. Asymptote: 2x + 5 = 0 5 x=− 2
  • 10. Graph y1 = log(2x + 5) and discuss.
  • 11. Graph y1 = log(2x + 5) and discuss. X Intercept:
  • 12. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0)
  • 13. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math:
  • 14. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math: log ( 2x + 5 ) = 0
  • 15. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math: log ( 2x + 5 ) = 0 0 10 = 2x + 5
  • 16. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math: log ( 2x + 5 ) = 0 0 10 = 2x + 5 1 = 2x + 5
  • 17. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math: log ( 2x + 5 ) = 0 0 10 = 2x + 5 1 = 2x + 5 −4 = 2x
  • 18. Graph y1 = log(2x + 5) and discuss. X Intercept: (−2,0) bonus math: log ( 2x + 5 ) = 0 0 10 = 2x + 5 1 = 2x + 5 −4 = 2x x = −2
  • 19. Graph y1 = log(2x + 5) and discuss.
  • 20. Graph y1 = log(2x + 5) and discuss. Y Intercept:
  • 21. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 )
  • 22. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5
  • 23. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5 y ≈ .6990
  • 24. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5 y ≈ .6990 Domain:
  • 25. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5 y ≈ .6990 ⎧ 5 ⎫ Domain: ⎨ x : x > − ⎬ ⎩ 2 ⎭
  • 26. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5 y ≈ .6990 ⎧ 5 ⎫ Domain: ⎨ x : x > − ⎬ ⎩ 2 ⎭ Range:
  • 27. Graph y1 = log(2x + 5) and discuss. Y Intercept: y = log ( 2 g0 + 5 ) y = log 5 y ≈ .6990 ⎧ 5 ⎫ Domain: ⎨ x : x > − ⎬ ⎩ 2 ⎭ Range: {y : y ∈R}
  • 28. Graph f (x) = log 3 ( x + 1)
  • 29. Graph f (x) = log 3 ( x + 1) log ( x + 1) y1 = log ( 3)
  • 31. Properties of Natural Logs 1) ln 1 = 0
  • 32. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0
  • 33. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1
  • 34. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1 because e = e 1
  • 35. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1 because e = e 1 x 3) ln e = x
  • 36. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1 because e = e 1 x 3) ln e = x because e = e (and we have a x x composite of inverse functions)
  • 37. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1 because e = e 1 x 3) ln e = x because e = e (and we have a x x composite of inverse functions) ln x 4) e =x
  • 38. Properties of Natural Logs 1) ln 1 = 0 because e = 1 0 2) ln e = 1 because e = e 1 x 3) ln e = x because e = e (and we have a x x composite of inverse functions) ln x 4) e =x composite of inverse functions again
  • 39. HW #5 There are no secrets to success. It is the result of preparation, hard work, and learning from failure. Colin Powell

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