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10.3 Hyperbolas




John 17:3 "And this is eternal life, that they know you the
only true God, and Jesus Christ whom you have sent."
Another way to define
the hyperbola is this:

A Hyperbola is the set
of points in the plane,
the difference of whose
distances from two
fixed points (the Foci),
is a constant.



                  use K on keyboard to Pause/Play
Another way to define
the hyperbola is this:

A Hyperbola is the set
of points in the plane,
the difference of whose
distances from two
fixed points (the Foci),
is a constant.



                  use K on keyboard to Pause/Play
F2   F1
Vertex   Vertex


 F2       F1
Central Box



Vertex                 Vertex


 F2                     F1
Central Box



Vertex                 Vertex


 F2                     F1


         Asymptotes
Central Box



              Vertex                 Vertex


               F2                     F1


                       Asymptotes




The segment joining V1 and V2 is the Transverse Axis.
To derive the equation for a hyperbola ... start with
               PF2 − PF1 = 2a
To derive the equation for a hyperbola ... start with
               PF2 − PF1 = 2a

It is very similar to what we did with the ellipse, so we
won’t go through all of that again. The equation is:
To derive the equation for a hyperbola ... start with
               PF2 − PF1 = 2a

It is very similar to what we did with the ellipse, so we
won’t go through all of that again. The equation is:
                  2   2
                x    y
                  2
                    − 2 =1
                a b
A bit more detail ...
A bit more detail ...




                        V1V2 :Transverse Axis
                        B1 B2 :Conjugate Axis
A bit more detail ...




                                 V1V2 :Transverse Axis
                                 B1 B2 :Conjugate Axis




  2   2
x    y
  2
    − 2 = 1 opens left − right
a b
A bit more detail ...




                                          V1V2 :Transverse Axis
                                          B1 B2 :Conjugate Axis




  2   2                           2   2
x    y                           y    x
  2
    − 2 = 1 opens left − right     2
                                     − 2 = 1 opens up − down
a b                              a b
To sketch a hyperbola:
To sketch a hyperbola:

  1. Draw the central box
To sketch a hyperbola:

  1. Draw the central box
  2. Draw in the asymptotes
To sketch a hyperbola:

  1. Draw the central box
  2. Draw in the asymptotes
  3. Plot the vertices and foci
To sketch a hyperbola:

  1. Draw the central box
  2. Draw in the asymptotes
  3. Plot the vertices and foci
  4. Draw the hyperbola
2   2
1. Discuss and graph:   x   y
                          −   =1
                        16 25
2       2
1. Discuss and graph:       x   y
                              −   =1
                            16 25
                        2   2    2
      a=4    b=5    c = a +b
                    c = 41 ≈ 6.4
2        2
1. Discuss and graph:             x   y
                                    −   =1
                                  16 25
                              2   2     2
      a=4      b=5           c = a +b
                             c = 41 ≈ 6.4

     Vert. :   ( ± 4,0 )
     Foci :    ( ± 6.4,0 )
     TA : 8
     CA : 10
                  5
      Asy. : y = ± x
                  4
2. Discuss and graph:     2   2
                        4x − y + 4 = 0
2. Discuss and graph:         2   2
                            4x − y + 4 = 0
                 2      2
               4x − y = −4
2. Discuss and graph:         2   2
                            4x − y + 4 = 0
                 2      2
               4x − y = −4
                 2      2
                y  x
                  − =1
                4 1
2. Discuss and graph:            2       2
                            4x − y + 4 = 0
                 2      2
               4x − y = −4
                 2      2
                y  x
                  − =1
                4 1
                             2       2       2
        a=2    b =1         c = a +b
                            c = 5 ≈ 2.2
2. Discuss and graph:                     2       2
                                     4x − y + 4 = 0
                       2     2
                   4x − y = −4
                       2         2
                     y  x
                       − =1
                     4 1
                                      2       2       2
        a=2        b =1              c = a +b
                                     c = 5 ≈ 2.2
        Vert. :   ( 0, ± 2 )
        Foci :    ( 0, ± 2.2 )
        TA : 4
        CA : 2
                     x
        Asy. : y = ±
                     2
HW #6

“The difference between the possible and the impossible
lies in a man’s determination.”
                     Tommy Lasorda

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1006 ch 10 day 6

  • 1. 10.3 Hyperbolas John 17:3 "And this is eternal life, that they know you the only true God, and Jesus Christ whom you have sent."
  • 2. Another way to define the hyperbola is this: A Hyperbola is the set of points in the plane, the difference of whose distances from two fixed points (the Foci), is a constant. use K on keyboard to Pause/Play
  • 3. Another way to define the hyperbola is this: A Hyperbola is the set of points in the plane, the difference of whose distances from two fixed points (the Foci), is a constant. use K on keyboard to Pause/Play
  • 4.
  • 5. F2 F1
  • 6. Vertex Vertex F2 F1
  • 7. Central Box Vertex Vertex F2 F1
  • 8. Central Box Vertex Vertex F2 F1 Asymptotes
  • 9. Central Box Vertex Vertex F2 F1 Asymptotes The segment joining V1 and V2 is the Transverse Axis.
  • 10.
  • 11. To derive the equation for a hyperbola ... start with PF2 − PF1 = 2a
  • 12. To derive the equation for a hyperbola ... start with PF2 − PF1 = 2a It is very similar to what we did with the ellipse, so we won’t go through all of that again. The equation is:
  • 13. To derive the equation for a hyperbola ... start with PF2 − PF1 = 2a It is very similar to what we did with the ellipse, so we won’t go through all of that again. The equation is: 2 2 x y 2 − 2 =1 a b
  • 14. A bit more detail ...
  • 15. A bit more detail ... V1V2 :Transverse Axis B1 B2 :Conjugate Axis
  • 16. A bit more detail ... V1V2 :Transverse Axis B1 B2 :Conjugate Axis 2 2 x y 2 − 2 = 1 opens left − right a b
  • 17. A bit more detail ... V1V2 :Transverse Axis B1 B2 :Conjugate Axis 2 2 2 2 x y y x 2 − 2 = 1 opens left − right 2 − 2 = 1 opens up − down a b a b
  • 18. To sketch a hyperbola:
  • 19. To sketch a hyperbola: 1. Draw the central box
  • 20. To sketch a hyperbola: 1. Draw the central box 2. Draw in the asymptotes
  • 21. To sketch a hyperbola: 1. Draw the central box 2. Draw in the asymptotes 3. Plot the vertices and foci
  • 22. To sketch a hyperbola: 1. Draw the central box 2. Draw in the asymptotes 3. Plot the vertices and foci 4. Draw the hyperbola
  • 23. 2 2 1. Discuss and graph: x y − =1 16 25
  • 24. 2 2 1. Discuss and graph: x y − =1 16 25 2 2 2 a=4 b=5 c = a +b c = 41 ≈ 6.4
  • 25. 2 2 1. Discuss and graph: x y − =1 16 25 2 2 2 a=4 b=5 c = a +b c = 41 ≈ 6.4 Vert. : ( ± 4,0 ) Foci : ( ± 6.4,0 ) TA : 8 CA : 10 5 Asy. : y = ± x 4
  • 26. 2. Discuss and graph: 2 2 4x − y + 4 = 0
  • 27. 2. Discuss and graph: 2 2 4x − y + 4 = 0 2 2 4x − y = −4
  • 28. 2. Discuss and graph: 2 2 4x − y + 4 = 0 2 2 4x − y = −4 2 2 y x − =1 4 1
  • 29. 2. Discuss and graph: 2 2 4x − y + 4 = 0 2 2 4x − y = −4 2 2 y x − =1 4 1 2 2 2 a=2 b =1 c = a +b c = 5 ≈ 2.2
  • 30. 2. Discuss and graph: 2 2 4x − y + 4 = 0 2 2 4x − y = −4 2 2 y x − =1 4 1 2 2 2 a=2 b =1 c = a +b c = 5 ≈ 2.2 Vert. : ( 0, ± 2 ) Foci : ( 0, ± 2.2 ) TA : 4 CA : 2 x Asy. : y = ± 2
  • 31. HW #6 “The difference between the possible and the impossible lies in a man’s determination.” Tommy Lasorda

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