If a ball is thrown upward with a velocity of 44 ft/s, its height (in feet) after t is given by ? = 44t - 16t^2. What is the height attained by the ball? (Round your answer to the nearest whole numbers.) 0.5 Solution We have y = 44t-16t^2 Differentiate y with respect to t y\' = 44-32t Put 44-32t = 0 t = 11/8 Put t = 11/8 in y y = 44*(11/8)-16(11/8)^2 y = 121/4 or y = 30 (nearest no) So, answer is 30.