complete the proof Propost ion: If a positive intege r m is not the square of any integer, then Vm is irrational. Solution Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then there exists pand qwith no common factor (beside 1) such that n=pq Then n=p2q2 However, nn is an positive integer and p and q have no common factors beside 1. So q=1. This gives that n=p2 Contradiction since it was assumed that nm2 for any m c. c 7down voteaccepted Let nbe a positive integer such that there is no msuch that n=m2. Suppose nis rational. Then there exists pand qwith no common factor (beside 1) such that n=pq Then n=p2q2 However, nn is an positive integer and p and q have no common factors beside 1. So q=1. This gives that n=p2 Contradiction since it was assumed that nm2 for any m c. c.

1. Execute the following code and identify the errors in the program. Debug the program and
provide the correct version of the code. Note: There are two errors in the snippet below. #include
Solution
The two errors in the program are
Please find below the correct version of code
#include
int main()
{
int count = 2; //variable declaration and initialization
while (count > 0) //looping structure
{
printf("Continue "); //output
count = count - 1; //decrement
}
printf("Stop "); //output
return 0; //terminate program
}