Pluto and Eris best resemble a) Jovian planets b) Terrestrial planet.pdf

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It is required to remove 10 mm depth from a workpiece of dimensions 350*100 mm. An end mill cutting tool of 60 mm. diameter and 8 teeth with 30 m/min cutting speed and 0.1 mm/tooth feed is used. Find; a) The machining time (max. depth of cut = 3 mm). b) The metal remove rate. Solution GIVEN:- Depth d = 10mm, Area A = 35000mm2, End mill diameter D = 60mm, Cutting speed S = 30m/min=500mm/s Feed F = 0.1mm/tooth x 8 = 0.8mm, Max depth of cut dc = 3mm SOLUTION:- a) Time required for cutting a length of 350mm & at feed F=0.8mm at max cutting speed = 350/500=0.7s Total cuts required for cutting total area A = 35000/(350x0.8) = 125 So time required for cutting at depth of 3 mm = 125 x 0.7 = 87.5 secs Total time required for cutting depth of d = 10mm = 87.5 x 4 = 350 secs = 5 mins, 50 secs Machining time T = 5 mins,50 secs (ANSWER) (b) Metal removal rate MRR = (Length x F x dc) / Cutting time = (350 x 0.8 x 3) / 0.7 = 1200mm3/s So MRR = 1200 mm3/s (ANSWER).

Pluto and Eris best resemble a) Jovian planets b) Terrestrial planets c) Main-Belt asteroids d)
Kuiper Belt comets e) escaped moons of Neptune
Solution
Pluto and Eris best resemble Kuiper Belt comets because they are compositionally similar to
many other objects of the Kuiper belt, and they share the 2:3 orbital resonance with neptune

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The net revenue for a certain car company (in billions of dollars)between the years 2004 abd 2012 is approximated by R(X)=-0.717x^3+23.8x^2-157.6x+423.2, where x=4 correspoinds to the year 2004. Complete parts (a) and (b) (a) what is the revenue in 2009 (in billions) (b) What is the revenue in 2010 Solution The revenue is given by the formula: R(x) = -0.717 x3 + 23.8x2 - 157.6x + 423.2 where x = 4 for year 2004 So, for year 2009, x = 9 and x = 10 would correspond to year 2010 So, revenue in 2009 = R(9) = 409.907 billion dollars (just put x = 9 in the above equation of R(x) ) R (10) = 510.2 billion dollars Hope this helps,.

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Instructions write a c program to solve the following problem. Upload your source code file to Canvas. The file name must be of the form hwloop your name.c Substitute your first and last name for \"your name\" in the file name. Example: Student\'s name is Sparky Watts. The file name is hwloop sparky watts.c Problem Statement create a program that calculates twelve month\'s interest and principle loan balance. Your program will ask the user for the starting principle balance, annual interest rate, and monthly payment amount. Your program will verify the input is reasonable, as described in the Error checking section below. After obtaining reasonable the program will process 12 months of payments. The will show the accrued interest and updated loan balance after each month\'s payment. The total interest paid and total payment amounts for the 12 month period will also be calculated and displayed. Your program output should resemble the output below. AUsers williidialDesktoplhw04MbinlDebuglhw04.exe Enter loan anount: 32000.00 Enter annual interest rate 7.99 Enter monthly payment 752.84 Solution #include #include int main() { double loan_amount = 0; printf(\"Enter loan amount :\"); if (scanf(\"%lf\", &loan_amount) != 1) { printf(\"Please enter loan amount correctly\ \"); return -1; } if (loan_amount < 500) { printf(\"Loan amount should be greater than 500\ \"); return 1; } if (loan_amount > 100000) { printf(\"Loan amount should be less than 100000\ \"); return -1; } printf(\"Enter annual interest rate: \"); double interest_rate; if (scanf(\"%lf\", &interest_rate) != 1) { printf(\"Please enter interest rate correctly\ \"); return -1; } if (interest_rate < 0 || interest_rate > 8.99) { printf(\"Interest rate should be in range of 0 to 8.99\ \"); return -1; } double monthly_payments; printf(\"Enter monthly payment: \"); if (scanf(\"%lf\", &monthly_payments) != 1) { printf(\"Please monthly payment correctly\ \"); return -1; } double first_month_interest = (loan_amount * interest_rate)/(12*100); if (monthly_payments < first_month_interest) { printf(\"Monthly payment should be greater than %f\ \", first_month_interest); return -1; } double total_interest = 0; double total_paid = 0; printf(\"\ \"); printf(\"Begin \\t\\t\\t\\tMonthly\\tEnd\ \"); printf(\"Loan\\t\\tAccured\\t\\tPayment\\tLoan\ \"); printf(\"Balance\\t\\tInterest\\tAmount\\tBalance\ \"); printf(\"\ \"); int i; for(i = 0; i <= 12; i++) { printf(\"%0.2f\\t\", loan_amount); double interest = (loan_amount*interest_rate)/(1200); printf(\"%0.2f\\t\\t\", interest); printf(\"%0.2f\\t\", monthly_payments); loan_amount = loan_amount + interest; if (loan_amount < monthly_payments) { total_paid -= loan_amount; loan_amount = 0; printf(\"%0.2f\ \", loan_amount); break; } else { loan_amount -= monthly_payments; total_paid += monthly_payments; } printf(\"%0.2f\ \", loan_amount); total_interest += interest; } printf(\"\ \"); printf(\"Annual total\\t%.2f\\t\\t%.2f\ \", total_interest, total_paid); return 0; }.

Please i need help on following program using C++ Language.Add the.pdf

Please i need help on following program using C++ Language.Add the.pdf

Please i need help on following program using C++ Language.Add the.pdf

If you buy a new car, the entire purchase is counted as consumption in the year in which you make the transaction. Explain briefly why this is in one sense an “error” in national income accounting. (Hint: How is the purchase of a car different from the purchase of a pizza?) How might you correct this error? How is housing treated in the National Income and Product Accounts? Specifically how does owner- occupied housing enter into the accounts? (Hint: Do some Web searching on “imputed rent on owner-occupied housing.”) Solution This is in one sense error because purchasing car may be considered also investment that leds to production of services particularly when it is used for commercial use also. We can correct it by listing it as investment The owner occupied houses are treated by I\'m putting Rents to them.

One for the first steps towards a successful cloud migration is obta.pdf

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In an ancient land, the beautiful princess Eve had many suitors She decided on the following procedure to determine which suitor she would marry First, all of the suitors would be lined up on after the other and assigned numbers The first suitor would be number 1, the second number 2, and so on up to the last suitor, number n starting at the first suitor she would then count three suitors down the line (because of the three letters in her name) and the third suitor would be eliminated from winning her hand and removed from the line Eve would then continue, counting three more suitors, and eliminating every third suitor When she reached the end of the line she would continue counting from the beginning. For example, if there were six suitors then the elimination process would proceed as follows: Write a program that creates a circular linked list of nodes to determine which position you should stand in to marry the princess if there are n suitors Your program should simulate the elimination process by deleting the node that corresponds to the suitor that is eliminated for each step in the process. Solution import java.util.Scanner; import java.util.Stack; public class CircularLinkedListImpl { private Node node = null; private Node head = null; private Node tail = null; private static int listCount = 0; public CircularLinkedListImpl() { } /* Function to delete element at position */ public void deleteAtPos(int pos) { if (this.listCount == 1 && pos == 1) { head = null; tail = null; this.listCount = 0; return; } if (pos == 1) { head = this.head.next; tail.next = head; listCount--; return; } if (pos == listCount) { Node s = head; Node t = head; while (s != tail) { t = s; s = s.next; } tail = t; tail.next = head; listCount--; return; } Stack> stack = new Stack>(); Node ptr = head.next; pos = pos - 1; for (int i = 1; i < listCount - 1; i++) { if (i == pos) { System.out.println(\"kfdsf\" + ptr.item); Node tmp = ptr.next; tmp = tmp.next; ptr.next = tmp; break; } stack.push(ptr); } listCount--; } public boolean add(E element) { boolean isItemAdded = false; Node tempNode = new Node(element); Node node = this.node; if (node == null) { this.node = tempNode; this.head = this.node; this.tail = this.node; CircularLinkedListImpl.listCount++; isItemAdded = true; } else { while (node.next != null) { System.out.println(node.next.item); node = node.next; } tempNode.next = node.next; node.next = tempNode; this.tail = tempNode; CircularLinkedListImpl.listCount++; isItemAdded = true; } return isItemAdded; } public int size() { return CircularLinkedListImpl.listCount++; } public String toString() { String output = \"\"; if (this.node != null) { Node crunchifyCurrent = this.node; while (crunchifyCurrent != null) { output += \"[\" + crunchifyCurrent.item.toString() + \"]\"; crunchifyCurrent = crunchifyCurrent.next; } } return output; } public static void main(String[] args) { CircularLinkedListImpl c = new CircularLinkedListImpl(); Scanner scan = new Scanner(System.in).

Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf

Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf

Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf

If a ball is thrown upward with a velocity of 44 ft/s, its height (in feet) after t is given by ? = 44t - 16t^2. What is the height attained by the ball? (Round your answer to the nearest whole numbers.) 0.5 Solution We have y = 44t-16t^2 Differentiate y with respect to t y\' = 44-32t Put 44-32t = 0 t = 11/8 Put t = 11/8 in y y = 44*(11/8)-16(11/8)^2 y = 121/4 or y = 30 (nearest no) So, answer is 30.

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