Essay question The genomes of lots and lots of organisms (mostly ba.pdf

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Complete the identity: cot(t) (tan (t) - sin (t) cos (t)) =? sin^2 (t) sin (t) tan (t) sec (t) csc (t) tan (t) + 1 Solution cot(t)(tan(t) -sin(t)cos(t)) =(cos(t)/sin(t))((sin(t)/cos(t)) -sin(t)cos(t)) =((cos(t)/sin(t))(sin(t)/cos(t)) - (cos(t)/sin(t))sin(t)cos(t)) =1- cos2(t)..................................................................................[sin2A+cos2A =1 is an identity ] =sin2(t) therefore cot(t)(tan(t) -sin(t)cos(t)) =sin2(t).

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Essay question: The genomes of lots and lots of organisms (mostly bacteria) have been
sequenced. Is there some organism whose genome has not been sequenced that you would like to
see sequenced? Check the web site GOLD (http://www.genomesonline.org/cgi-
bin/GOLD/index.cgi?page_requested=Complete+Genome+Projects) to be sure the sequence has
not been done or is being done, and then explain why it should be done.
Solution
I would like to see the sequenced genome of Isoptera (termite). Folowing are my reasons for the
same :-

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The Food and Drug Administration (FDA) produces a quarterly report called Total Diet Study. The FDA\'s report covers more than 200 food items, each of which is analyzed for dangerous chemical compounds. One Total Diet Study reported that no pesticides at all were found in 65% of the domestically produced food samples. Consider a random sample of 800 food items analyzed for the presence of pesticides. Compute Mu and Sigma for the random variable x, the number of food items with no trace of pesticide. Is it likely that you would observe fewer then half of food items without any traces of pesticide Why or Why not Solution a) the expected value or miu will be = n*p for a binomial distribution and why is a binomial distribution? because we have a probability of success that in this case is 65% (no pesticides) miu = 0.65 * 800 = 520 sigma = srqt (n*p*q) = srqt ( 0.65*0.35*520) = 10.88 b) No it is not likely because our probability of no pesticide is 65% that means that more than half of food items are without any pesticide.

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The aqueous reaction between phenol (C6H5OH) and ammonia shown below, has initial concentrations of 0.200 M C6H5OH(aq) and 0.120 M NH3(aq). At equilibrium, the C6H5Oâ€“(aq) concentration is 0.050 M. Calculate the equilibrium constant Kc for the reaction. C6H5OH (aq) + NH3(aq) --> C6H5Oâ€“ + NH4+(aq) Answer is 0.24 - need steps - thanks! Solution Assuming it to be balanced reaction At equilibrium C6H5OH = 0.2 - x NH3 = 0.12 - x C6H5O- = 0.05 = x and NH4 + = x = 0.05 Hence Kc = (0.05 * 0.05)/(0.2 - 0.05)(.12 - 0.05) = 0.238.

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The correlation coefficient of two input sequences is given by r = n sigma x_i y_i - sigma x_i sigma y_i/Squareroot [n sigma x_i^2 - (sigma x_i)^2][n sigma y_i^2 - (sigma y_i)^2] Adapt Example 4.11 to compute the correlation coefficient from a sequence of pairs of input values from an input file. Solution #include using namespace std; //Class for standard deviation class stdDev { private: int max; double value[100]; double mean; public: double CalMean() { double sum = 0; for(int i = 0; i < max; i++) sum += value[i]; return (sum / max); } double CalVariane() { mean = CalMean(); double temp = 0; for(int i = 0; i < max; i++) { temp += (value[i] - mean) * (value[i] - mean) ; } return temp / max; } double CalSampleVar() { mean = CalMean(); //get mean double temp = 0; for(int i = 0; i < max; i++) { temp += (value[i] - mean) * (value[i] - mean) ; //apply formula } return temp / (max - 1); //returns sample variance } int SetValues(double *p, int count) { if(count > 100) return -1; max = count; for(int i = 0; i < count; i++) value[i] = p[i]; return 0; } double CalStdDev()//returns Standard deviation { return sqrt(CalVariane()); } double SampleStdDev()//returns sample deviation { return sqrt(CalSampleVar()); } }; class Calculate { private: double XTerms[100]; double YTerms[100]; int max; stdDev x; // Standard deviation for x stdDev y;// Standard deviation for y public: //set x and y series values to class members void SetValues(double *xval, double *yval, int count) { for(int i = 0; i < count; i++) { XTerms[i] = xval[i]; YTerms[i] = yval[i]; } x.SetValues(xval, count); y.SetValues(yval, count); max = count; } double Calculate_Covariance() { double xmean = x.CalMean();//Get X meam double ymean = y.CalMean();//get y mean double total = 0; for(int i = 0; i < max; i++) { total += (XTerms[i] - xmean) * (YTerms[i] - ymean); } return total / max;//return Covariance } double Calculate_Correlation()//Find correlation { double cov = Calculate_Covariance(); double correlation = cov / (x.CalStdDev() * y.CalStdDev()); return correlation; } }; int main() { Calculate calc; //create object of class double xarr[] = { 0, 2, 4, 6, 8 }; // x series double yarr[] = { 6, 13, 15, 16, 20 };// y series calc.SetValues(xarr,yarr,sizeof(xarr) / sizeof(xarr[0]));//set series values cout<<\"X series ={ 0, 2, 4, 6, 8 }\ Y series={ 6, 13, 15, 16, 20 }\ \"; cout<<\"Correlation \"<< calc.Calculate_Correlation(); } ===================================================================== ======== Output: akshay@akshay-Inspiron-3537:~/Chegg$ g++ coeffici.cpp akshay@akshay-Inspiron-3537:~/Chegg$ ./a.out X series ={ 0, 2, 4, 6, 8 } Y series={ 6, 13, 15, 16, 20 } Correlation 0.952157.

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The answer has to be original. For this week’s discussion, complete the following two scenario questions below in detail. Please discuss thoroughly and substantivelyin your post. 1.)You are a digital forensic examiner and have been asked to examine a hard drive for potential evidence. Give examples of how the hard drive (or the data on it) could be used as (or lead to the presentation of) all four types of evidence in court; testimonial, real, documentary, and demonstrative. If you do not believe one or more of the types of evidence would be included, explain why not. 2.) You have been asked to assist a law enforcement team serving a search warrant related to a child pornography investigation. You are the digital forensic expert for the team, and, as such, have been assigned the task of identifying and collecting the digital evidence at the search location. Answer the following questions about your assignment. What steps should you take before the search to serve the search warrant? What types of evidence should you be on the alert for, when searching the residence? What types of items would you seize? Solution.

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Take the problem 4284 divided by 14 using the standard division algorithm. the answer is 306. (a) when we write the 3 in the quoitent, and then mulitply 3 by 14 to get 42, what does the 42 represent? (b) explain the mathmatical reason why you have to \" move to the right\" as you do the algorithm. (c) is may be confusing for children to understand why the answer is 306 instead of 36. explain clearly why a 0 must be put into the answer. Solution a) it is actually 4200. Not 42. It is the way of writing. Because we actually subtract 4200 from 4284. b) we move to right because we are going towards units place. Like 1000x+100y+10z+a this is the format. C)we must understand we are taking all places one by one. Here hundred\'s place is 3.so 300. Tens place is 0. So 0. Units place is 6. Therfore 300+0+6=306.

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Problem 12-5A Bramble Corp.\'s income statement contained the condensed information below. Bramble Corp. Income Statement For the Year Ended December 31, 2017 $3,171,900 Service revenue Operating expenses, excluding depreciation 2,007,780 Depreciation expense Loss on disposal of plant assets Income before income taxes Income tax expense Net income 179,850 52,320 2,239,950 931,950 183,120 $748,830 Bramble Corp.\'s balance sheet contained the compartive data at December 31 2017 2016 Accounts receivable Accounts payable Income taxes payable $228,900 134,070 42,510 $196,200 104,640 22,890 Accounts payable pertain to operating expenses. Prepare the operating activities section of the statement of cash flows using the indirect parenthesis e.g. (15,000).) Solution Prepare operating activities indirect method :Net income748830Adjustment to reconcile net incomeDepreciation expense179850Loss on disposal of plant assets52320Increase account receivable-32700Increase account payable29430Increase income tax payable19620248520Net cash flow from operating activities997350.

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abestion Tu 10 points Save Acower p Company purchased a 90% interest in Company on an ay 2 2013 it accounts for its investment n s company ng the cost the d P Co b Company because s Company was its primary supplier of merchandise for resale. During 2011. P Company bought merchandise from S Company. The selling price to P Company was S300.000, S Company uses a 25% markup on cost. At the end of 2013, P Company still had in its books 2S percent of the inventory purchased from S Company. In 2014, the intercompany sia profit in ending inventory at the end of 2014? OA 544,800 les totalled $280.000 with 20 percent left in inventory at the end of the year. What is the unrealized O B. $10.400 OC.$11.200 O D.$56.000 Solution ANSWER IS C($ 11200) DETAIL WORKING IS GIVEN AS UNDER: INTER COMPANY SALE S= $ 280000 INVENTORY LEFT AT THE END =$280000X20%=$56000 UNREALISED PROFIT = $56000X25/125 = $11200 _S COMPANY USES A 25% MARKUP ON COST: AS SUCH IF COSY TO S COMPANY IS $100 THAN BY ADDING 25% ON COST(I.E.,$25) SELLING PRICE OF S COMPANY TO P COMPANY WILL BE $125 THAN UNREALISED PROFIT WILL BE 25/125.

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please help with this question. 3. Write a counterexample for each property the relation does not possess. (1,1), (1,2), (2,1), (2,2) (b) apy z Solution (a) Here let us consider the three properties. They are: Reflexive: For every element 1 in A, (1,1) is in R. Symmetric: If an ordered pair (1,2) in R, (2,1) is in R. Transitive: If ordered pairs (1,2) and (2,1) in R, (1,1) in is R. Here R is reflexive and symmetric and we have to prove that it is not transitive..

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1 Describe the advanced features and operation of network switches. 2. Discuss the advantages and disadvantages of these features. 1 Explain basic and advanced wireless access point features. 2. Describe a real world scenario where you would use advanced wireless access point features, including how and why you would choose to set them a certain way. Solution 1. A normal Switch has a function of connecting two networks, or 2 devices connected to 2 different networks. But now a day this function is not sufficient in large organizations, the advanced features of Switches Which Include Traffic flow Monitoring helps the organization by analyzing the data to how much extent the traffic on the network of their organization has increased, or decreased, this helps the organization to help grow their network. 2.The Advantages are: - Disadvantages: - 3. Wireless Access Point refers to a hardware device, which helps a WIFI compatible device to get connected to a Wired Network, now a days Wireless Access points are a part of Router Itself. Basic Features of Wireless Access point are: Advanced Features of Wireless Access point are: 4. In an Office Network, I would prefer to use the Advances Wireless access point feature, as in an office the devices will be more, the speed required will be more, and as a office in a large area, the device will be able to cover a large area. Thank You for using Chegg...

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Lab Exercise — 2-D Arrays in C++ In this lab exercise, you are required to write a C++ program to add two 4 * 5 matrices and then output the results to the screen. Prompt the user to enter the name of two files with matrices Compute the sum of the two matrices and output the results A sample run is as follows: Further requirements: Create three functions: readArray with void return and one 2D array argument and one string argument printArray with void return and one 2D array argument sumArray with void return and three 2D array arguments Separate your code into three files as described in the lab: main.cpp myFunction.cpp myFunction.h If you can correct this and then saparete it to three files #include #include #include using namespace std; const unsigned int R_SIZE=4; const unsigned int C_SIZE=5; void readArray(int p_Array[][C_SIZE], string fName); // function prototype int main() { int i, j; int Nums1[R_SIZE][C_SIZE]; string filename; cout << \"Please enter the name of the file containing data for Array 1: \"; cin >>filename; readArray(Nums1, filename); for ( i=0; i < R_SIZE; i++) { for ( j=0; j< C_SIZE; j++) { cout<< Nums1[i][j] << \" \"; } cout << endl; } } // Function: readArray // Purpose: To read values into an array. // Parameters: Base address of an array. // Returns: void // -------------------------------------------------------- void readArray(int p_Array[R_SIZE][C_SIZE], string fName) { ifstream inF; int i, j; inF.open(fName.c_str()); if(inF.fail()) { cout << fName << \"does not enist\" << endl; } else { cout << fName << \"exists\" << endl; } while(!inF.eof()) { for ( i=0; i < R_SIZE; i++) { for ( j=0; j< C_SIZE; i++) { inF >> p_Array[i][j]; } } } } // end InitArray function Someone help me with this and I modified it a little bit but still can\'t read from the file!!! This is the code /*..............myFunction.h ...........*/ #include #include using namespace std; const unsigned int R_SIZE=4; const unsigned int C_SIZE=5; void readArray(int p_Array[][C_SIZE], string fName); // function read prototype void printArray(int p_Array[][C_SIZE]); // function print prototype void sumArray (int p_Array1[][C_SIZE],int p_Array2[][C_SIZE],int p_Array3[][C_SIZE]); /*..............myFunction.cpp ...........*/ #include \"myfunction.h\" // Function: printArray // Purpose: To print values of an array. // Parameters: Base address of an array. // Returns: void // -------------------------------------------------------- void printArray(int p_Array[R_SIZE][C_SIZE]){ for (int i=0; i < R_SIZE; i++) { for (int j=0; j< C_SIZE; j++) { cout<< p_Array[i][j] << \" \"; } cout << endl; } } // Function: readArray // Purpose: To read values into an array. // Parameters: Base address of an array. // Returns: void // -------------------------------------------------------- void readArray(int p_Array[R_SIZE][C_SIZE], string fName) { ifstream inF; int i, j; inF.open(fName.c_str()); if(inF.fail()) { cout << fName << \"does not enist\" << endl; } else { cout << fName .

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JAVA Information Security: Principles ad Practices. Write a program to help an analyst decrypt a simple substitution cipher. Your program should take the ciphertext as input, compute letter frequency counts, and display these for the analyst. The program should then allow the analyst to guess a key and display the results of the corresponding \"decryption\" with the putative key. BELOW IS WHAT I GOT SO FAR. ANALYST IS NOT GUESSING A KEY OR PUTATIVE KEY IS NOT COMING OUT. IF YOU HAVE BETTER PROGRAM, PLEASE IGNORE THE SOURCE BELOW. THANKS. import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.HashMap; import java.util.LinkedHashMap; import java.util.Map; publicclass SubstitutionCipher { Map letterFrequencyMap; Map key; String ciphertext; String plaintext; BufferedReader br; privatevoid getCiphertext() // get cipher text as input from analyst { System.out.println(\"----- Substitution Cipher ----\"); System.out.println(\" Enter the cipher text: \"); br = new BufferedReader(new InputStreamReader(System.in)); try { ciphertext = br.readLine(); } catch(Exception e) { System.err.println(\"Exception in cipher text reading \" + e ); e.printStackTrace(); } ciphertext = ciphertext.toUpperCase(); System.out.println(\"The ciphertext Entered is - \" + ciphertext); } privatevoid displayLetterFrequency() { letterFrequencyMap = new LinkedHashMap(); for (int i = 0; i < ciphertext.length(); i++) { Character ch = ciphertext.charAt(i); if (!( ch >= \'A\' && ch <=\'Z\')) continue; // check if letter is not in between A to Z Integer cnt = (Integer) letterFrequencyMap.get(ch); if(cnt == null) { letterFrequencyMap.put(ch,1); } else { letterFrequencyMap.put(ch,cnt + 1); } } System.out.println(letterFrequencyMap); } privatevoid keyGuess() { System.out.println(\"Hey Analyst , Guess a key from a to z\"); String putativeKey = null; try { putativeKey = br.readLine(); } catch(Exception e) { System.out.println(\"Excpetion in reading the putative key\"); e.printStackTrace(); } createKeyMap(putativeKey); } privatevoid createKeyMap(String putativeKey) { if(putativeKey.length() < 26) { System.out.println(\"putative key length is less then 26 letters. Invalid Entry. \"); return; } key = new HashMap(); putativeKey = putativeKey.toUpperCase(); for(int j = 0;j Solution import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.HashMap; import java.util.LinkedHashMap; import java.util.Map; class SubstitutionCipher { Map letterFrequencyMap; Map key; String ciphertext; String plaintext; BufferedReader br; private void getCiphertext() // get cipher text as input from analyst { System.out.println(\"----- Substitution Cipher ----\"); System.out.println(\" Enter the cipher text: \"); br = new BufferedReader(new InputStreamReader(System.in)); try { ciphertext = br.readLine(); } catch(Exception e) { System.err.println(\"Exception in cipher text reading \" + e ); e.printStackTrace(); } ciphertext = ciphertext.toUpperCase(); System.out.println(\.

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It is required to remove 10 mm depth from a workpiece of dimensions 350*100 mm. An end mill cutting tool of 60 mm. diameter and 8 teeth with 30 m/min cutting speed and 0.1 mm/tooth feed is used. Find; a) The machining time (max. depth of cut = 3 mm). b) The metal remove rate. Solution GIVEN:- Depth d = 10mm, Area A = 35000mm2, End mill diameter D = 60mm, Cutting speed S = 30m/min=500mm/s Feed F = 0.1mm/tooth x 8 = 0.8mm, Max depth of cut dc = 3mm SOLUTION:- a) Time required for cutting a length of 350mm & at feed F=0.8mm at max cutting speed = 350/500=0.7s Total cuts required for cutting total area A = 35000/(350x0.8) = 125 So time required for cutting at depth of 3 mm = 125 x 0.7 = 87.5 secs Total time required for cutting depth of d = 10mm = 87.5 x 4 = 350 secs = 5 mins, 50 secs Machining time T = 5 mins,50 secs (ANSWER) (b) Metal removal rate MRR = (Length x F x dc) / Cutting time = (350 x 0.8 x 3) / 0.7 = 1200mm3/s So MRR = 1200 mm3/s (ANSWER).

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Instructions write a c program to solve the following problem. Upload your source code file to Canvas. The file name must be of the form hwloop your name.c Substitute your first and last name for \"your name\" in the file name. Example: Student\'s name is Sparky Watts. The file name is hwloop sparky watts.c Problem Statement create a program that calculates twelve month\'s interest and principle loan balance. Your program will ask the user for the starting principle balance, annual interest rate, and monthly payment amount. Your program will verify the input is reasonable, as described in the Error checking section below. After obtaining reasonable the program will process 12 months of payments. The will show the accrued interest and updated loan balance after each month\'s payment. The total interest paid and total payment amounts for the 12 month period will also be calculated and displayed. Your program output should resemble the output below. AUsers williidialDesktoplhw04MbinlDebuglhw04.exe Enter loan anount: 32000.00 Enter annual interest rate 7.99 Enter monthly payment 752.84 Solution #include #include int main() { double loan_amount = 0; printf(\"Enter loan amount :\"); if (scanf(\"%lf\", &loan_amount) != 1) { printf(\"Please enter loan amount correctly\ \"); return -1; } if (loan_amount < 500) { printf(\"Loan amount should be greater than 500\ \"); return 1; } if (loan_amount > 100000) { printf(\"Loan amount should be less than 100000\ \"); return -1; } printf(\"Enter annual interest rate: \"); double interest_rate; if (scanf(\"%lf\", &interest_rate) != 1) { printf(\"Please enter interest rate correctly\ \"); return -1; } if (interest_rate < 0 || interest_rate > 8.99) { printf(\"Interest rate should be in range of 0 to 8.99\ \"); return -1; } double monthly_payments; printf(\"Enter monthly payment: \"); if (scanf(\"%lf\", &monthly_payments) != 1) { printf(\"Please monthly payment correctly\ \"); return -1; } double first_month_interest = (loan_amount * interest_rate)/(12*100); if (monthly_payments < first_month_interest) { printf(\"Monthly payment should be greater than %f\ \", first_month_interest); return -1; } double total_interest = 0; double total_paid = 0; printf(\"\ \"); printf(\"Begin \\t\\t\\t\\tMonthly\\tEnd\ \"); printf(\"Loan\\t\\tAccured\\t\\tPayment\\tLoan\ \"); printf(\"Balance\\t\\tInterest\\tAmount\\tBalance\ \"); printf(\"\ \"); int i; for(i = 0; i <= 12; i++) { printf(\"%0.2f\\t\", loan_amount); double interest = (loan_amount*interest_rate)/(1200); printf(\"%0.2f\\t\\t\", interest); printf(\"%0.2f\\t\", monthly_payments); loan_amount = loan_amount + interest; if (loan_amount < monthly_payments) { total_paid -= loan_amount; loan_amount = 0; printf(\"%0.2f\ \", loan_amount); break; } else { loan_amount -= monthly_payments; total_paid += monthly_payments; } printf(\"%0.2f\ \", loan_amount); total_interest += interest; } printf(\"\ \"); printf(\"Annual total\\t%.2f\\t\\t%.2f\ \", total_interest, total_paid); return 0; }.

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If you buy a new car, the entire purchase is counted as consumption in the year in which you make the transaction. Explain briefly why this is in one sense an “error” in national income accounting. (Hint: How is the purchase of a car different from the purchase of a pizza?) How might you correct this error? How is housing treated in the National Income and Product Accounts? Specifically how does owner- occupied housing enter into the accounts? (Hint: Do some Web searching on “imputed rent on owner-occupied housing.”) Solution This is in one sense error because purchasing car may be considered also investment that leds to production of services particularly when it is used for commercial use also. We can correct it by listing it as investment The owner occupied houses are treated by I\'m putting Rents to them.

One for the first steps towards a successful cloud migration is obta.pdf

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In an ancient land, the beautiful princess Eve had many suitors She decided on the following procedure to determine which suitor she would marry First, all of the suitors would be lined up on after the other and assigned numbers The first suitor would be number 1, the second number 2, and so on up to the last suitor, number n starting at the first suitor she would then count three suitors down the line (because of the three letters in her name) and the third suitor would be eliminated from winning her hand and removed from the line Eve would then continue, counting three more suitors, and eliminating every third suitor When she reached the end of the line she would continue counting from the beginning. For example, if there were six suitors then the elimination process would proceed as follows: Write a program that creates a circular linked list of nodes to determine which position you should stand in to marry the princess if there are n suitors Your program should simulate the elimination process by deleting the node that corresponds to the suitor that is eliminated for each step in the process. Solution import java.util.Scanner; import java.util.Stack; public class CircularLinkedListImpl { private Node node = null; private Node head = null; private Node tail = null; private static int listCount = 0; public CircularLinkedListImpl() { } /* Function to delete element at position */ public void deleteAtPos(int pos) { if (this.listCount == 1 && pos == 1) { head = null; tail = null; this.listCount = 0; return; } if (pos == 1) { head = this.head.next; tail.next = head; listCount--; return; } if (pos == listCount) { Node s = head; Node t = head; while (s != tail) { t = s; s = s.next; } tail = t; tail.next = head; listCount--; return; } Stack> stack = new Stack>(); Node ptr = head.next; pos = pos - 1; for (int i = 1; i < listCount - 1; i++) { if (i == pos) { System.out.println(\"kfdsf\" + ptr.item); Node tmp = ptr.next; tmp = tmp.next; ptr.next = tmp; break; } stack.push(ptr); } listCount--; } public boolean add(E element) { boolean isItemAdded = false; Node tempNode = new Node(element); Node node = this.node; if (node == null) { this.node = tempNode; this.head = this.node; this.tail = this.node; CircularLinkedListImpl.listCount++; isItemAdded = true; } else { while (node.next != null) { System.out.println(node.next.item); node = node.next; } tempNode.next = node.next; node.next = tempNode; this.tail = tempNode; CircularLinkedListImpl.listCount++; isItemAdded = true; } return isItemAdded; } public int size() { return CircularLinkedListImpl.listCount++; } public String toString() { String output = \"\"; if (this.node != null) { Node crunchifyCurrent = this.node; while (crunchifyCurrent != null) { output += \"[\" + crunchifyCurrent.item.toString() + \"]\"; crunchifyCurrent = crunchifyCurrent.next; } } return output; } public static void main(String[] args) { CircularLinkedListImpl c = new CircularLinkedListImpl(); Scanner scan = new Scanner(System.in).

Part C What is the conjugate acid of HPOs27 Express your answer as a.pdf

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If a ball is thrown upward with a velocity of 44 ft/s, its height (in feet) after t is given by ? = 44t - 16t^2. What is the height attained by the ball? (Round your answer to the nearest whole numbers.) 0.5 Solution We have y = 44t-16t^2 Differentiate y with respect to t y\' = 44-32t Put 44-32t = 0 t = 11/8 Put t = 11/8 in y y = 44*(11/8)-16(11/8)^2 y = 121/4 or y = 30 (nearest no) So, answer is 30.

OBJECTIVE-CHow do you get a thumbnail image from an article and pl.pdf

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