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Based on the oxidation number considerations, the oxidation numberof molecule will increase when they react with molecular oxygen. Itis because that oxygen got the tendency to lose 2 electron to formO2- , with oxidation number of -2. This is based on redox reaction. oxidation number of N in NO = +2 oxidation number of N in N2O = +1 The highest oxidation number of N is +5, they still can react withO oxidation number of S in SO2 = +4 oxidation number of S in SO3= +6 The highest oxidation number of S is +6, SO2 still canreact with O, but SO3 dont have the tendency to reactwith O more. oxidation number of P in P4O6= +3 The highest oxidation number of P is +5, P4O6still can react with O. So, the only one wont react with O is SO3 Solution Based on the oxidation number considerations, the oxidation numberof molecule will increase when they react with molecular oxygen. Itis because that oxygen got the tendency to lose 2 electron to formO2- , with oxidation number of -2. This is based on redox reaction. oxidation number of N in NO = +2 oxidation number of N in N2O = +1 The highest oxidation number of N is +5, they still can react withO oxidation number of S in SO2 = +4 oxidation number of S in SO3= +6 The highest oxidation number of S is +6, SO2 still canreact with O, but SO3 dont have the tendency to reactwith O more. oxidation number of P in P4O6= +3 The highest oxidation number of P is +5, P4O6still can react with O. So, the only one wont react with O is SO3.

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This is an effort to make ppt of p block elements , a topic in XII, chemistry(cbse) , whom as a tutor i have often felt students are horrified due to its large text size, long descriptipns, several information to be remembered and several reasonings to keep in mind. Hope this ppt would solve thier problem of a thorough preparation of topic with all important aspects covered in the ppt. Founder Dr Mona Srivastava Masterchemclasses

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First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2 electrons (H) The only way to do this is: H-C=N: There is a C-N triple bond and a lone pair on the N. Now, the steric number is defined as the number of bonds to another atom + the number of lone pairs on the atom. For H: 1 bond = steric number of 1. For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4) For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4) Solution First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2 electrons (H) The only way to do this is: H-C=N: There is a C-N triple bond and a lone pair on the N. Now, the steric number is defined as the number of bonds to another atom + the number of lone pairs on the atom. For H: 1 bond = steric number of 1. For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4) For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4).

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// Interest.java import java.util.Scanner; public class Interest { //calculation method public static double outputAmount(double amount) { double interest = amount * 0.5; amount = amount + interest; return amount; } // method to take input public static double inputAmount() { Scanner sc = new Scanner(System.in); System.out.print(\"Enter the invested amount: \"); double amount = sc.nextDouble(); return amount; } //main method public static void main(String[] args) { double amount = inputAmount(); System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" + outputAmount(amount)); } } /* output: Enter the invested amount: 2000 5% interest earned on $2000.0 after one year is $3000.0 */ Solution // Interest.java import java.util.Scanner; public class Interest { //calculation method public static double outputAmount(double amount) { double interest = amount * 0.5; amount = amount + interest; return amount; } // method to take input public static double inputAmount() { Scanner sc = new Scanner(System.in); System.out.print(\"Enter the invested amount: \"); double amount = sc.nextDouble(); return amount; } //main method public static void main(String[] args) { double amount = inputAmount(); System.out.println(\"5% interest earned on $\" + amount + \" after one year is $\" + outputAmount(amount)); } } /* output: Enter the invested amount: 2000 5% interest earned on $2000.0 after one year is $3000.0 */.

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13. The answer is: C. 3/4 Let D be the dominant allele and d be the recessive allele. Since father and mother are both heterozygous: Dd x DdDdDDD (affected)Dd (affected)dDd (affected)dd (unaffected) Solution 13. The answer is: C. 3/4 Let D be the dominant allele and d be the recessive allele. Since father and mother are both heterozygous: Dd x DdDdDDD (affected)Dd (affected)dDd (affected)dd (unaffected).

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1) The Arrhenius Theory of acids and bases: Acids are substances which produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in solution. Neutralisation happens because hydrogen ions and hydroxide ions react to produce water. HCl(acid) + NaOH (base) = H2O + NaCl 2) The Bronsted-Lowry Theory of acids and bases An acid is a proton (hydrogen ion) donor. A base is a proton (hydrogen ion) acceptor. H2O (base) + HCl(acid) = H3O^+ + Cl^- 3) The Lewis Theory of acids and bases: An acid is an electron pair acceptor. A base is an electron pair donor. BH3(acid) + NH3(base) = H3B:NH3 (where NH3 donotes one pair of electrons to the empty orbital of BH3 to form H3BNH3 complex.) Solution 1) The Arrhenius Theory of acids and bases: Acids are substances which produce hydrogen ions in solution. Bases are substances which produce hydroxide ions in solution. Neutralisation happens because hydrogen ions and hydroxide ions react to produce water. HCl(acid) + NaOH (base) = H2O + NaCl 2) The Bronsted-Lowry Theory of acids and bases An acid is a proton (hydrogen ion) donor. A base is a proton (hydrogen ion) acceptor. H2O (base) + HCl(acid) = H3O^+ + Cl^- 3) The Lewis Theory of acids and bases: An acid is an electron pair acceptor. A base is an electron pair donor. BH3(acid) + NH3(base) = H3B:NH3 (where NH3 donotes one pair of electrons to the empty orbital of BH3 to form H3BNH3 complex.).

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1. Coenzyme A - C. A water soluble acyl group carrier. 2. Thiamine pyrophosphate -B. A coenzyme frequently used in decarboxylation reactions. 3. Lipoate - A. The disulfide bond at its end enables it to participate in redox reactions as well as carry acyl groups. 4. Folic acid - D. A one-carbon group donor. Essential to rapidly growing tissues. Recommended for women during pregnancy. Solution 1. Coenzyme A - C. A water soluble acyl group carrier. 2. Thiamine pyrophosphate -B. A coenzyme frequently used in decarboxylation reactions. 3. Lipoate - A. The disulfide bond at its end enables it to participate in redox reactions as well as carry acyl groups. 4. Folic acid - D. A one-carbon group donor. Essential to rapidly growing tissues. Recommended for women during pregnancy..

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purines are double ringed nitrogenous bases of DNA and RNA including adenine and guanine. the three others are cytosine and thymine( uracil is present instead of thymine in RNA) are pyrimidines. So your answer should be (B) Improve Answer Solution purines are double ringed nitrogenous bases of DNA and RNA including adenine and guanine. the three others are cytosine and thymine( uracil is present instead of thymine in RNA) are pyrimidines. So your answer should be (B) Improve Answer.

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(i) Deques cannot be implemented using arrays. : false Justification: We can implement dequeue using circular array. We need to maintain two pointers rear and front. Ex : 1. Create an array of any element type like int [] dequeue. 2. Create two indexes front and rear and initialize them to 0. 3. Create an element capacity.(it should be length of an array - 1). (ii) If we require all add/remove operations to run in O(1) time, we cannot use a Deque implemented with a singly linked list. False Justification : In linklist there will be two pointers head and tail. Adding an element : tail -> next = newelement; newelement -> next = NULL; tail = newelement; These all are O(1) operation. Removing an element : head = head->next; O(1) operation (iii) A Deque can be used as a stack as well as a queue. : true Justification : Using as stack : You can use dequeue as stack by removing and inserting the element at one end. Using as queue : You can use dequeue as queue by inserting the element at front and removing at rear. (iv) Assume the Deque contains n elements and n is odd. The middle element is the e lement equidistant from either end. The middle element cannot be determined in O(1) time in any implementation : false Justification : You can achieve this in O(1) operation with the help of doubly link list. You will have to maintain a mid pointer to achieve this. You can move this pointer in either direction with previos and next pointers. Solution (i) Deques cannot be implemented using arrays. : false Justification: We can implement dequeue using circular array. We need to maintain two pointers rear and front. Ex : 1. Create an array of any element type like int [] dequeue. 2. Create two indexes front and rear and initialize them to 0. 3. Create an element capacity.(it should be length of an array - 1). (ii) If we require all add/remove operations to run in O(1) time, we cannot use a Deque implemented with a singly linked list. False Justification : In linklist there will be two pointers head and tail. Adding an element : tail -> next = newelement; newelement -> next = NULL; tail = newelement; These all are O(1) operation. Removing an element : head = head->next; O(1) operation (iii) A Deque can be used as a stack as well as a queue. : true Justification : Using as stack : You can use dequeue as stack by removing and inserting the element at one end. Using as queue : You can use dequeue as queue by inserting the element at front and removing at rear. (iv) Assume the Deque contains n elements and n is odd. The middle element is the e lement equidistant from either end. The middle element cannot be determined in O(1) time in any implementation : false Justification : You can achieve this in O(1) operation with the help of doubly link list. You will have to maintain a mid pointer to achieve this. You can move this pointer in either direction with previos and next pointers..

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We all know humans are good at removing the competition and it is difficult for any other species to dominate or even evolve to super intelligent like us. With large brains evolved and we had taught ourselves how to control other animals as they tends to have not so evolved brains like humans. There can be seen in zoo, circus dancing on the tunes of human’s orders. Since humans are self-centred, each and everything is designed or developed is based on the same feeling human is only species which is important, others are just to serve for its pleasure, food, and etc. we believe we can do anything we want with animals and their habitats. Due to industrialization and continue growth of big cities, there is war like condition between animals and cities. And history has teaches us in number of times, the strong one who has more number wins the war. Same is the case we can see in NYC, we humans has tendency to get threaten by whole species even an individual attacks one single person, which itself is rare case. In this regard there tends to forget these lands was initially dominated by animals, later humans have conquered and started ruling it. Solution We all know humans are good at removing the competition and it is difficult for any other species to dominate or even evolve to super intelligent like us. With large brains evolved and we had taught ourselves how to control other animals as they tends to have not so evolved brains like humans. There can be seen in zoo, circus dancing on the tunes of human’s orders. Since humans are self-centred, each and everything is designed or developed is based on the same feeling human is only species which is important, others are just to serve for its pleasure, food, and etc. we believe we can do anything we want with animals and their habitats. Due to industrialization and continue growth of big cities, there is war like condition between animals and cities. And history has teaches us in number of times, the strong one who has more number wins the war. Same is the case we can see in NYC, we humans has tendency to get threaten by whole species even an individual attacks one single person, which itself is rare case. In this regard there tends to forget these lands was initially dominated by animals, later humans have conquered and started ruling it..

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Theories devised by keynes and Minsky are similar in concept since Minsky himself was a post- Keynesian. He supported quite much of Keynes\' theories and rather contributed to the economics of financial markets by providing theories on why such markets fail and how they recover. So they are a more advanced extension of Keynes\' theory to explain the behaviour of financial markets and how they influence the overall economy. For understanding the similarities between the two theories, we need to look at some of their main points in brief, without going into detail and then compare them on where they stood unique shared the same concept. Since nearly very business cycle theory explains through some common points, their mode can be different, for Keynes\' theory explained business cycle on a macro economic scale while Minsky\'s was more market related. Some of the main key points for Keynes\' and Minsky\'s theories are listed down below. Keynes\' theory of business cycles Minsky, as I already told, was a Keynesian himself and all his theories have been always been an extension of Keynesian concepts to explain the economics of today. His most valuable thesis on the workings of financial markets why they fail becasue of fluctuations is a Kynesian modifed concept. Minsky proposed his theory in pure financial terminology. His point was that during propserity when cash flows are maximum to pay off the debts, the resulting euphoria that develops into society results in a debt crises that the borrowers are unable to pay. This leads to banks restructing money supply which in the end contracts the whole economy. Solution Theories devised by keynes and Minsky are similar in concept since Minsky himself was a post- Keynesian. He supported quite much of Keynes\' theories and rather contributed to the economics of financial markets by providing theories on why such markets fail and how they recover. So they are a more advanced extension of Keynes\' theory to explain the behaviour of financial markets and how they influence the overall economy. For understanding the similarities between the two theories, we need to look at some of their main points in brief, without going into detail and then compare them on where they stood unique shared the same concept. Since nearly very business cycle theory explains through some common points, their mode can be different, for Keynes\' theory explained business cycle on a macro economic scale while Minsky\'s was more market related. Some of the main key points for Keynes\' and Minsky\'s theories are listed down below. Keynes\' theory of business cycles Minsky, as I already told, was a Keynesian himself and all his theories have been always been an extension of Keynesian concepts to explain the economics of today. His most valuable thesis on the workings of financial markets why they fail becasue of fluctuations is a Kynesian modifed concept. Minsky proposed his theory in pure financial terminology. His point was that durin.

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They might have consumed cyanide. The pit of Apricot contains cyanide. Cyanide acts by inhibiting the enzyme cytochrome c oxidase of the electron transport chain which prevents the cell from producing ATP which is important for aerobic respiration of cells. Hydroxocobalamin, Sodium thiosulfate, Sodium nitrite are the common antedotes used in cyanide poisoning Solution They might have consumed cyanide. The pit of Apricot contains cyanide. Cyanide acts by inhibiting the enzyme cytochrome c oxidase of the electron transport chain which prevents the cell from producing ATP which is important for aerobic respiration of cells. Hydroxocobalamin, Sodium thiosulfate, Sodium nitrite are the common antedotes used in cyanide poisoning.

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The attacking of the nucleophile formed in the reactionof acetone and benzaldehyde on most preferntially on the carbonylcarbon of the benzaldehyde but not on the acetaldehyde. This isbecause the electrophilic cheractor of the carbonyl carbon of thebenzaldehyde is increases due to the presence of the electron withdrawing benzene. Hence it readily participate in the reactioncompare with the acetaldehyde. Ethanol is polar solvent. When washes a compound withthis solvent remove the impurities has the polar nature. Solution The attacking of the nucleophile formed in the reactionof acetone and benzaldehyde on most preferntially on the carbonylcarbon of the benzaldehyde but not on the acetaldehyde. This isbecause the electrophilic cheractor of the carbonyl carbon of thebenzaldehyde is increases due to the presence of the electron withdrawing benzene. Hence it readily participate in the reactioncompare with the acetaldehyde. Ethanol is polar solvent. When washes a compound withthis solvent remove the impurities has the polar nature..

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Terry And Hill can develop a method of profit sharing on below factors Unequal capital contribution Compensate by paying interest on capital - Compensate for the uneven contributions towards capital by paying interest on their capital contributions. Greater the Capital contributed, greater the interest earned. This would set right the difference in contributions in the form of capital. Profit equal to the total \"Interest on Capital\" on all the capital of the firm is set aside and is distributed to the partners in the ratio of their capitals.Rest of the profits can be shared equally if all other contributions are equal. Unequal time and efforts - Compensate by paying Salary to Partner. - Compensate for the uneven contributions of time and efforts towards the firm by paying salary to partner. The salary paid to Hill would be compensation for his greater contribution. Profit equal to the total \"Salary to Partners\" to all the partners who have made a contribution in this respect is set aside and is distributed to them in proportion to the value of their contributions as agreed upon between partners. Rest of the profits can be shared equally if all other contributions are equal. and if terry and hill are not interested in compensating by above methods then profit sharing by effort in running the partnership is more preferable as its helping in generating income of partnership. Solution Terry And Hill can develop a method of profit sharing on below factors Unequal capital contribution Compensate by paying interest on capital - Compensate for the uneven contributions towards capital by paying interest on their capital contributions. Greater the Capital contributed, greater the interest earned. This would set right the difference in contributions in the form of capital. Profit equal to the total \"Interest on Capital\" on all the capital of the firm is set aside and is distributed to the partners in the ratio of their capitals.Rest of the profits can be shared equally if all other contributions are equal. Unequal time and efforts - Compensate by paying Salary to Partner. - Compensate for the uneven contributions of time and efforts towards the firm by paying salary to partner. The salary paid to Hill would be compensation for his greater contribution. Profit equal to the total \"Salary to Partners\" to all the partners who have made a contribution in this respect is set aside and is distributed to them in proportion to the value of their contributions as agreed upon between partners. Rest of the profits can be shared equally if all other contributions are equal. and if terry and hill are not interested in compensating by above methods then profit sharing by effort in running the partnership is more preferable as its helping in generating income of partnership..

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The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables. node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; } Solution The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables. node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; }.

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Splicing mechanism Small nuclear ribonucleic acid (snRNA): It is also known as U-RNA as it contains many uridine contents in its complex structure. This is composed of 150 nucleotides nearly to produce spliceosomes and to act along with snRNP. This snRNA has a predominant role in splicing. The roles of U1snRNA is different to that of U4snRNA and U1snRNA is mainly going to mediate splicing by binding to 5\'-splice site when snRNP (small nuclear ribonucleoprotein particles) to remove latriant introns but the U4snRNA is going to Peptidyl transferase rRNA is different in their function to U1snRNA,U4snRNA in RNP as ribozymes and these ribozymes are enzymatic RNA molecules & they are going to mediate RNA splicing. The peptidyl transferase activity is possessed by 5S and 23S rRNA of ribosomes. The role of U4snRNA is going to form a complex to form as U1/U2/U4/U5 on pre-mRNA as spliceosome to remove introns. However, U4snRNA is specifically has specific role in 3 prime end of hnRNA Solution Splicing mechanism Small nuclear ribonucleic acid (snRNA): It is also known as U-RNA as it contains many uridine contents in its complex structure. This is composed of 150 nucleotides nearly to produce spliceosomes and to act along with snRNP. This snRNA has a predominant role in splicing. The roles of U1snRNA is different to that of U4snRNA and U1snRNA is mainly going to mediate splicing by binding to 5\'-splice site when snRNP (small nuclear ribonucleoprotein particles) to remove latriant introns but the U4snRNA is going to Peptidyl transferase rRNA is different in their function to U1snRNA,U4snRNA in RNP as ribozymes and these ribozymes are enzymatic RNA molecules & they are going to mediate RNA splicing. The peptidyl transferase activity is possessed by 5S and 23S rRNA of ribosomes. The role of U4snRNA is going to form a complex to form as U1/U2/U4/U5 on pre-mRNA as spliceosome to remove introns. However, U4snRNA is specifically has specific role in 3 prime end of hnRNA.

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since both are strong acids we can add up their individual contribut.pdf

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public int getPosition(T anObject) { int result = null; // result to return int lastIndex = length - 1; for(int index=0; index < lastIndex;index++){ if(anObject.equals(list[index])) { result = index; } } return result; } // end getPosition Solution public int getPosition(T anObject) { int result = null; // result to return int lastIndex = length - 1; for(int index=0; index < lastIndex;index++){ if(anObject.equals(list[index])) { result = index; } } return result; } // end getPosition.

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