The algorithm to reverse a linked list by rearranging the required p.pdf

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The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables. node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; } Solution The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables. node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; }.

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$The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables. node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; } Solution The algorithm to reverse a linked list by rearranging the required pointers is given as follows: The pseudo-code to show the working of the algorithm is given as follows: //Define the function to reverse a list. node* reverseList(node* head) { //Declare and initialize the required pointer variables.$

$node* prev_node; node* cur_node; node* next_node; prev_node = NULL; next_node = NULL; cur_node = head; //Traverse the whole list using while loop. while(cur_node != NULL) { //Rearrange the pointers to reverse the list. next_node = cur_node->next; cur_node->next = prev_node; prev_node = cur_node; cur_node = next_node; } //Make the recent previous node as head of the list. head = prev_node; //Return the head of the list. return head; }$

Similar to The algorithm to reverse a linked list by rearranging the required p.pdf

1) Create a function called reverselist that will take a simple list as a parameter and return the reversed list. (We aren’t using the word reverse, since it is also the name of a built-in function.) 2) Create a function called deleteall that will take an item and a list as parameters, and return the list with that item removed. Solution Hi, Please find my function. Please let me know in case of any issue. Let assume structure of node is: /* Link list node */ struct node { int data; struct node* next; }; a) /* Function to reverse the linked list */ struct node* reverse(struct node* head) { struct node* prev = NULL; struct node* current = head; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } return prev; } b) struct node* deleteNode(struct node *head, int item) { if(head == NULL) return NULL; // When node to be deleted is head node if(head->data == item) { return head->next; } // When not first node, follow the normal deletion process // find the previous node struct node *prev = head; while(prev->next != NULL && prev->item != item) prev = prev->next; // Check if node really exists in Linked List if(prev->next == NULL) { printf(\"\ Given node is not present in Linked List\"); }else{ // Remove node from Linked List prev->next = prev->next->next; } return head; }.

1) Create a function called reverselist that will take a simple list.pdf

ivylinvaydak64229

Use C++ Write a function to merge two doubly linked lists. The input lists have their elements in sorted order, from lowest to highest. The output list should also be sorted from lowest to highest. Your algorithm should run in linear time on the length of the output list. Provide an algorithm for your function Implement and show some samples of your running function Solution /* This is a C++ program to merge two sorted linked lists and produce a list in a Sorted order */ #include #include #include /* Link list node */ struct node { int data; struct node* next; }; /* This function is used to pull off the front node of the source and put it in destnation */ void letusMoveNode(struct node** destRef, struct node** sourceRef); /* This is a function used for performing merging of two linked lists.It takes two lists sorted in increasing order, and splices their nodes together to make one big sorted list which is returned. */ struct node* letssortlists(struct node* a, struct node* b) { /* Let us first have dummyone first node to hang the result on */ struct node dummyone; /*next the tail points to the last result node */ struct node* tail = &dummyone; /* As a result, tail->next is the place to add new nodes to the result. */ dummyone.next = NULL; while (1) { if (a == NULL) { /*we will check that if either list runs out, use the other list */ tail->next = b; break; } else if (b == NULL) { tail->next = a; break; } if (a->data <= b->data) letusMoveNode(&(tail->next), &a); else letusMoveNode(&(tail->next), &b); tail = tail->next; } return(dummyone.next); } /* letusMoveNode() function is a function which takes the node from the front of the source, and move it to the front of the dest. Before calling letusMoveNode(): source == {1, 2, 3} dest == {1, 2, 3} Affter calling letusMoveNode(): source == {3, 4} dest == {1, 2, 3, 4} */ void letusMoveNode(struct node** destReference, struct node** sourceReference) { /*This is the front source node */ struct node* newNode = *sourceReference; assert(newNode != NULL); /* now we will advance the source pointer */ *sourceReference = newNode->next; /*next we will link the old dest off the new node */ newNode->next = *destReference; /* Fineally we will move dest to point to the new node */ *destReference = newNode; } /* This IS A function which is used to insert a node at the beginning of the linked list */ void insertpush(struct node** head_reference, int new_data) { /* This is used to allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* now we will put in the data */ new_node->data = new_data; /* The next step is to link the old list off the new node */ new_node->next = (*head_reference); /*Finally we will move the head to point to the new node */ (*head_reference) = new_node; } /* This is a function to print nodes in a given linked list */ void printList(struct node *node) { while (node!=NULL) { printf(\"%d \", node->data); node = node->next; } } /*This is the driver program to test ab.

Use C++ Write a function to merge two doubly linked lists. The input.pdf

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I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C. Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com. You can also call on +1 678 648 4277 for any assistance with C Homework.

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Data Structures - Lecture 7 [Linked List]

Muhammad Hammad Waseem

Below is a depiction of a doubly-linked list implementation of the bag ADT with two sentinels -one at the head and one at the tail. Strict DLink { TYPE value; strict DLink * next; struct DLink * prev;}; strict linked List { int size; struct DLink *frontSentinel; struct DLink *backSentinel;}; Write a function that at first reverses the list and then prints the values of the links in the list from front to back. Don\'t redirect to any other function. You must use assertions if necessary. Solution /* Program to reverse a doubly linked list */ #include <stdio.h> #include <stdlib.h> /* a node of the doubly linked list */ struct node { int data; struct node *n; struct node *pr; }; /* Function to reverse a Doubly Linked List */ void reverse(struct node **head_r) { struct node *t = NULL; struct node *cur = *head_r; /* swap next and prev for all nodes of doubly linked list */ while (cur != NULL) { t = cur->pr; cur->pr = cur->n; cur->n = t; cur = cur->pr; } /* Before changing head, check for the cases like empty list and list with only one node */ if(t != NULL ) *head_r = t->pr; } /* UTILITY FUNCTIONS */ /* Function to insert a node at the beginging of the Doubly Linked List */ void push(struct node** head_r, int new_data) { /* allocate node */ struct node* n_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ n_node->data = n_data; /* since we are adding at the begining, prev is always NULL */ n_node->pr = NULL; /* link the old list off the new node */ n_node->n = (*head_r); /* change prev of head node to new node */ if((*head_r) != NULL) (*head_r)->pr = n_node ; /* move the head to point to the new node */ (*head_r) = n_node; } /* Function to print nodes in a given doubly linked list This function is same as printList() of singly linked lsit */ void printList(struct node *node) { while(node!=NULL) { printf(\"%d \", node->data); node = node->next; } } /* Drier program to test above functions*/ int main() { /* Start with the empty list */ struct node* head = NULL; /* Let us create a sorted linked list to test the functions Created linked list will be 10->8->4->2 */ push(&head, 2); push(&head, 4); push(&head, 8); push(&head, 10); printf(\"\ Original Linked list \"); printList(head); /* Reverse doubly linked list */ reverse(&head); printf(\"\ Reversed Linked list \"); printList(head); getchar(); } .

Below is a depiction of a doubly-linked list implementation of the bag.docx

gilliandunce53776

in Java (ignore the last line thats hidden) Create a doubly linked list whose nodes contain Strings. Your list should include the following methods: Insert a node in the list in alphabetical order Find a node that matches a String Traverse the list forwards and print Traverse the list backwards and print Delete a node from the list Delete/destroy the list In addition to creating the class(es) for your linked list, you\'ll need to create a main method that thoroughly tests each function you build to show that it works. You should do these things in Solution / Java program to create , insert , traverse and delete a node from doubly linked list class LinkedList { static Node head = null; class Node { int data; Node next, prev; Node(int d) { data = d; next = prev = null; } } /* Let us create the doubly linked list 10<->8<->4<->2 */ list.push(head, 2); list.push(head, 4); list.push(head, 8); list.push(head, 10); System.out.println(\"Original Linked list \"); list.printList(head); /*Function to delete a node in a Doubly Linked List. head_ref --> pointer to head node pointer. del --> pointer to node to be deleted. */ void deleteNode(Node head_ref, Node del) { /* base case */ if (head == null || del == null) { return; } /* If node to be deleted is head node */ if (head == del) { head = del.next; } /* Change next only if node to be deleted is NOT the last node */ if (del.next != null) { del.next.prev = del.prev; } /* Change prev only if node to be deleted is NOT the first node */ if (del.prev != null) { del.prev.next = del.next; } /* Finally, free the memory occupied by del*/ return; } /* UTILITY FUNCTIONS */ /* Function to insert a node at the beginning of the Doubly Linked List */ void push(Node head_ref, int new_data) { /* allocate node */ Node new_node = new Node(new_data); /* since we are adding at the begining, prev is always NULL */ new_node.prev = null; /* link the old list off the new node */ new_node.next = (head); /* change prev of head node to new node */ if ((head) != null) { (head).prev = new_node; } /* move the head to point to the new node */ (head) = new_node; } /*Function to print nodes in a given doubly linked list This function is same as printList() of singly linked lsit */ void printList(Node node) { while (node != null) { System.out.print(node.data + \" \"); node = node.next; } } public static void main(String[] args) { LinkedList list = new LinkedList(); /* delete nodes from the doubly linked list */ list.deleteNode(head, head); /*delete first node*/ list.deleteNode(head, head.next); /*delete middle node*/ list.deleteNode(head, head.next); /*delete last node*/ System.out.println(\"\"); /* Modified linked list will be NULL<-8->NULL */ System.out.println(\"Modified Linked List\"); list.printList(head); } }.

in Java (ignore the last line thats hidden) Create a doubly linked l.pdf

sauravmanwanicp

Write a program in C that does the following: a) Builds a simple linked list consisting of 10 nodes each of which contains a random integer between 50 and 100 inclusive. The list is to be built in main() and must be a local variable in main(). b) Includes a user-defined function named printout(arg) that takes in the head pointer of the already-built linked list as an argument and prints out the contents of the linked list to the screen, starting from the head of the list to the tail. See the output below. Node #0 contains 53 Node #1 contains 78 Node #2 contains 95 . . . Node #20 contains 100 c) Includes a user-defined function called sum() that adds up the contents of the data members of each node in the list, and prints out the total as follows: The sum total of all nodes in this list is d) Includes a user-defined function called reverse() that takes in the head pointer of the already- built linked list as an argument and will physically reverse the order of the nodes in the list (i.e., the new head will be the old tail and the new tail will be the old head of the list). Use the function printout() to output its contents now in reverse order. This does NOT mean that it will be read backwards, but rather, the reversed list will be read from head to tail! ** PLEASE MAKE SURE THIS PROGRAM WORKS IN C LANGUAGE !! Solution #include #include /* Link list node */ struct node { int data; struct node* next; }; /* Function to reverse the linked list */ static void reverse(struct node** head_ref) { struct node* prev = NULL; struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; current->next = prev; prev = current; current = next; } *head_ref = prev; } /* Function to push a node */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref) = new_node; } /* Function to print linked list */ void printList(struct node *head) { struct node *temp = head; int i=0; while(temp != NULL) { printf(\"Node #%d contains %d\ \",i, temp->data); temp = temp->next; i++; } } void sum(struct node *head) { int sum=0; struct node *temp = head; while(temp != NULL) { //printf(\"%d \", temp->data); sum+=temp->data; temp = temp->next; } printf(\"\ The sum total of all nodes in this list is %d\ \",sum); } /* Driver program to test above function*/ int main() { /* Start with the empty list */ struct node* head = NULL; int i,t; for(i=0;i<10;i++) { // (rand() % 51) generates random number between 0 and 50 adding 50 generates random number beween 50 and 100 both inclusive t=(rand() % 51)+50; push(&head, t); } printf(\"Given linked list\ \"); printList(head); sum(head); reverse(&head); printf(\"\ Reversed Linked list \ \"); printList(head); return 0; }.

Write a program in C that does the followinga) Builds a simple li.pdf

kavithaarp

C++: Doubly-Linked Lists The goal of the exercise is to implement a class List of doubly- linked lists. My goal is to implement the class in a file doubly-linked.cpp. The class List implements lists using the following structures for list elements: struct Node { int val ; Node next; Node prev; }; Each Node contains a value (an integer) and two pointers: one meant to point to the next element of the list and one meant to point to the previous element in the list. The class provides the following methods that you need to implement: • A constructor and a destructor, with no arguments; • void insert(int n): insert an integer at the end of the list; • void reverse(): reverse the list; • void print(): print the list to cout in the same format as the input (i.e. integers separated by spaces); doubly-linked.h #ifndef __dll__ #define __dll__ #include using namespace std; // Basic structure to store elements of a list struct Node { int val; // contains the value Node * next; // pointer to the next element in the list Node * prev; // pointer to the previous element in the list }; // Class List class List { public: List(void); // Constructor ~List(void); // Destructor void insert(int n); // This should insert n in the list void reverse(void); // This should reverse the list void print(void); // This shoiuld print the list private: Node * first; // Pointer to the first (if any) element in the list }; #endif main.cpp #include #include \"doubly-linked.h\" using namespace std; int main(void){ List l; int n; while(cin >> n){ l.insert(n); } // Print list as read from cin l.print(); // Reverse the list and print it l.reverse(); l.print(); // Reverse again and print it l.reverse(); l.print(); return 0; } Solution #include using namespace std; /* Linked list structure */ struct list { struct list *prev; int data; struct list *next; } *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL; class linkedlist { public: /* Function for create/insert node at the beginning of Linked list */ void insrt_frnt() { list *addBeg = new list; cout << \"Enter value for the node:\" << endl; cin >> addBeg->data; if(first == NULL) { addBeg->prev = NULL; addBeg->next = NULL; first = addBeg; last = addBeg; cout << \"Linked list Created!\" << endl; } else { addBeg->prev = NULL; first->prev = addBeg; addBeg->next = first; first = addBeg; cout << \"Data Inserted at the beginning of the Linked list!\" << endl; } } /* Function for create/insert node at the end of Linked list */ void insrt_end() { list *addEnd = new list; cout << \"Enter value for the node:\" << endl; cin >> addEnd->data; if(first == NULL) { addEnd->prev = NULL; addEnd->next = NULL; first = addEnd; last = addEnd; cout << \"Linked list Created!\" << endl; } else { addEnd->next = NULL; last->next = addEnd; addEnd->prev = last; last = addEnd; cout << \"Data Inserted at the end of the Linked list!\" << endl; } } /* Function for Display Linked list */ void display() { node = first; cout << \"List of data in L.

C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdf

poblettesedanoree498

C++ problem Part 1: Recursive Print (40 pts) Please write the recursive List reverse print function, whose iterative version we wrote in class. Below are the function signatures for the functions you are going to need: public: /**Additional Operations*/ void print_reverse(); //Wrapper function that calls the reverse helper function to print a list in reverse //prints nothing if the List is empty private: void reverse(Nodeptr node); //Helper function for the public printReverse() function. //Recursively prints the data in a List in reverse. Why do we need the private helper function here? Since we are going to be reversing our list node by node, in a recursive fashion, we want to pass a one node at a time to our reverse function. However, since our nodes are private, we cannot access them if we call the function inside of main. Add these function signatures to your List.h file along with your other function prototypes inside the class definition. Make sure that you place the reverse function inside the private portion of your List class definition and the print_reverse function prototype to the public portion of your List class definition. Now, implement these two functions inside of List.h, under your section for additional operations. Important: Test each function carefully inside of your ListTest.cpp to make sure that it is working properly. Part 2: Adding an Index to Your List Nodes (20 pts) Next, you will add the following functions to your List.h /**Accessor Functions*/ int get_index(); //Indicates the index of the Node where the iterator is currently pointing //Nodes are numbered from 1 to length of the list //Pre: length != 0 //Pre: !off_end() ... int List::get_index() { //Implement the function here } /**Manipulation Procedures*/ void scroll_to_index(int index); //Moves the iterator to the node whose index is specified by the user //Pre: length != 0 ... void scroll_to_index(int index) { //Implement function here } Part 3: Implementing Search as Part of Your List (40 pts) Now, we are going to add two search functions to our List so that we can search for elements in our List. The first of these functions is going to be a simple linear search function. You will need to add the following function prototype and function definition to your List.h: /**Additional Operations*/ int linear_search(listitem item); //Searchs the list, element by element, from the start of the List to the end of the List //Returns the index of the element, if it is found in the List //Returns -1 if the element is not in the List //Pre: length != 0 ... int List::linear_search(listitem item) { //Implement the function here } You are also going to add a function to perform recursive binary search on your List. You will need to add the following function prototype and function definition to your List.h: int binary_search(int low, int high, listitem item); //Recursively searchs the list by dividing the search space in half //Returns the index of the element, if it is fo.

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Linked lists in Data Structure

Muhazzab Chouhadry

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Write a C++ function that delete nodes in a doubly linkedlist. It should delete all nodes that have that specific value. Finally, return the head of the linkedlist. node * DN(node *head, int value) { } The linkedlist structure: struct n { int value; node *next; node *previous; }; Solution #include<stdio.h> #include<stdlib.h> #include<assert.h> /* Link list node */ struct node { int data; struct node* next; }; /* Function to delete the entire linked list */ void deleteList(struct node** head_ref) { /* deref head_ref to get the real head */ struct node* current = *head_ref; struct node* next; while (current != NULL) { next = current->next; free(current); current = next; } /* deref head_ref to affect the real head back in the caller. */ *head_ref = NULL; } /* Given a reference (pointer to pointer) to the head of a list and an int, push a new node on the front of the list. */ void push(struct node** head_ref, int new_data) { /* allocate node */ struct node* new_node = (struct node*) malloc(sizeof(struct node)); /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*head_ref); /* move the head to point to the new node */ (*head_ref)Â Â Â = new_node; } /* Drier program to test count function*/ int main() { /* Start with the empty list */ struct node* head = NULL; /* Use push() to construct below list 1->12->1->4->1 */ push(&head, 1); push(&head, 4); push(&head, 1); push(&head, 12); push(&head, 1); printf(\"\ Deleting linked list\"); deleteList(&head); printf(\"\ Linked list deleted\"); } .

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noreendchesterton753

Java i have to make a method that takes a linked list and then returns a new linked list that is the reverse of the original this is the starting code /** * LinkedList lab. * @author Emma Cheney * @version 10/2/23 */ public class LinkedList { /** * Internal Node class used for the linked list. */ public class Node { String key; int value; Node next; /** * Node Constructor. * @param key The Key * @param value The Value */ public Node(String key, int value) { this.key = key; this.value = value; } } private Node head; private Node tail; /** * The default constructor. */ public LinkedList() { head = null; tail = null; } /** * Add the key, value pair to the head of the linkedlist. * @param key The Key * @param val The Value * */ public void addHead(String key, int val) { Node n = new Node(key, val); if (head == null) { head = n; tail = n; } else { n.next = head; head = n; } } /** * Add the key, val pair to the tail of the linkedlist. * @param key The Key * @param val The Value */ public void addTail(String key, int val) { Node n = new Node(key, val); if (tail == null) { head = n; tail = n; } else { tail.next = n; tail = n; } } /** * Returns the String format of the linkedlist. * @return String The String format. */ public String toString() { String ret = ""; Node curr = head; while (curr != null) { if (curr.next != null) { ret += curr.key + ":" + curr.value + ", "; } else { ret += curr.key + ":" + curr.value; } curr = curr.next; } return ret; } /** * Locate the Node in the linkedlist with the given key. * @param key The key to find in the LinkedList * @return Node Returns the Node with the given key or null if non-existent. */ private Node find(String key) { Node curr = head; while (curr != null) { if (curr.key.equals(key)) { return curr; } curr = curr.next; } return null; } A static method called reversed that takes a LinkedList as a parameter and returns a new LinkedList that is reversed. f; traverse through the input list (starting at the head). In order to reverse the ordering, you need to add the current node's key and value onto the head of the new list (addHead method). Do not change the input list or any values in it. Example (result in red) //assumelistcontainsthesekeysandvalues://ie:6,bi:48,bi:73,bi:63LinkedList.reversed(list);bi:63,bi: 73,bi:48,ie:6.

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vishalateen

This assignment and the next (#5) involve design and development of a sequential non contiguous and dynamic datastructure called LinkedList. A linked list object is a container consisting of connected ListNode objects. As before, we are not going to use pre-fabricated classes from the c++ library, but construct the LinkedList ADT from scratch. The first step is construction and testing of the ListNode class. A ListNode object contains a data field and a pointer to the next ListNode object (note the recursive definition). #This assignment requires you to 1. Read the Assignment 4 Notes 2. Watch the Assignment 4 Support video 3. Implement the following methods of the ListNode class -custom constructor -setters for next pointer and data 4. Implement the insert and remove method in the main program 5. Scan the given template to find the above //TODO and implement the code needed //TODO in ListNodecpp.h file public: ListNode(T idata, ListNode<T> * newNext); public: void setNext(ListNode<T> * newNext); public: void setData(T newData); // TODO in main program void remove(ListNode<int> * &front,int value) void insert(ListNode<int> * &front,int value) # The driver is given ListNodeMain.cpp is given to you that does the following tests 1. Declares a pointer called front to point to a ListNode of datatype integer 2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked list. 3. Inserts ListNode with data 3 to the list 4. Removes node 1 and adds it back to test removing and adding the first element 5. Removes node 3 to test removing a middle node 6. Removes node 4 to test removing the last node 7. Attempt to remove a non existent node 8. Remove all existing nodes to empty the list 9. Insert node 4 and then node 1 to test if insertions preserve order 10.Print the list Main.cpp #include <iostream> #include "ListNodecpp.h" // REMEMBER each ListNode has two parts : a data field // and an address field. The address is either null or points to the next node //in the chain //Requires: integer value for searching, address of front //Effects: traverses the list node chain starting from front until the end comparing search value with listnode getData. Returns the original search value if found, if not adds +1 to indicate not found //Modifies: Nothing int search(ListNode<int> * front, int value); //Requires: integer value for inserting, address of front //Effects: creates a new ListNode with value and inserts in proper position (increasing order)in the chain. If chain is empty, adds to the beginning //Modifies: front, if node is added at the beginning. //Also changes the next pointer of the previous node to point to the //newly inserted list node. the next pointer of the newly inserted pointer //points to what was the next of the previous node. //This way both previous and current links are adjusted //******** NOTE the use of & in passing pointer to front as parameter - // Why do you think this is needed ?********** void insert(ListNode<int> * &fr.

This assignment and the next (#5) involve design and development of a.pdf

EricvtJFraserr

Implement the following specification of UnsortedType using circular linked list as the implementation structure. *** I have seen this question answered here before but it is not a good answer. Can someone please give me a original answer.*** // Deliverables: // - A listing of the specification and implementation files for UnsortedType // - A listing of the driver program for your test plan // - A listing of the test plan as input to the driver. // - A listing of the output from the driver. template struct NodeType; /* Assumption: ItemType is a type for which the operators \"<\" and \"==\" are defined-either an appropriate built-in type or a class that overloads these operators. */ template class UnsortedType { public: // Class constructor, destructor, and copy constructor UnsortedType(); ~UnsortedType(); UnsortedType(const UnsortedType&); void operator=(UnsortedType); bool IsFull() const; // Determines whether list is full. //Post: Function value = (list is full) int GetLength() const; // Determines the number of elements in list. // Post: Function value = number of elements in list. void RetrieveItem(ItemType& item, bool& found); // Retrieves list element whose key matches item\'s key // (if present). // Pre: Key member of item is initialized. // Post: If there is an element someItem whose key matches // item\'s key, then found = true and item is a copy of // someItem; otherwise found = false and item is unchanged. // List is unchanged. void InsertItem(ItemType item); // Adds item to list. // Pre: List is not full. // Item is not in list. // Post: item is in list. void DeleteItem(ItemType item); // Deletes the element whose key matches item\'s key // Pre: Key member of item is initialized. // One and only one element in list has a key matching // item\'s key. // Post: No element in list has a key matching item\'s key. void ResetList(); // Initializes current position for an iteration through the list. // Post: Current position is prior to list. void GetNextItem(ItemType&); // Gets the next element in list. // Pre: Current position is defined. // Element at current position is not last in list. // Post: Current position is updated to next position. // item is a copy of element at current position. private: NodeType* listData; int length; NodeType* currentPos; }; Solution #include #include /* structure for a node */ struct node { int data; struct node *next; }; /* function to insert a new_node in a list in sorted way. Note that this function expects a pointer to head node as this can modify the head of the input linked list */ void sortedInsert(struct node** head_ref, struct node* new_node) { struct node* current = *head_ref; // Case 1 of the above algo if (current == NULL) { new_node->next = new_node; *head_ref = new_node; } // Case 2 of the above algo else if (current->data >= new_node->data) { /* If value is smaller than head\'s value then we need to change next of last node */ while(current->next != *head_ref) current = current->next; cur.

Implement the following specification of UnsortedType using circular.pdf

udit652068

could you implement this function please, im having issues with it. void makeList (const ListNode::value_type [],const size_t& count) class ListNode { public: typedef int value_type; ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum () const { return datum; } ListNode const* getNext () const { return next; } //Mutator void setDatum (const value_type& d) {datum = d; } ListNode* getNext () { return next; } void setNext (ListNode* new_link) {next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList (); virtual ~LinkedList (); void insertItem (ListNode::value_type); void makeList (const ListNode::value_type [],const size_t& count); void deleteList (); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; This is the pseudocode, but i still have a hard time undertanding it. Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head node, index n will be the last node. First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next node. While more nodes to add { Create a new node initialized with the data value and a NULL pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to point to the new node. Get a data value for the next node. } Thanks. Solution //linkedList.h #ifndef LINKEDLIST_H #define LINKEDLIST_H #include #include class ListNode { public: typedef int value_type; ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; } //Assessor value_type getDatum() const { return datum; } ListNode const* getNext() const { return next; } //Mutator void setDatum(const value_type& d) { datum = d; } ListNode* getNext() { return next; } void setNext(ListNode* new_link) { next = new_link; } private: value_type datum; ListNode* next; }; class LinkedList { public: LinkedList(); virtual ~LinkedList(); void insertItem(ListNode::value_type); void makeList(const ListNode::value_type[], const size_t& count); void deleteList(); //The following friend function is implemented in lablinklist.cpp friend std::ostream& operator<<(std::ostream&, const LinkedList&); private: ListNode* head; }; #endif ------------------------------------------------------------- //linkedList.cpp #include \"linkedlist.h\" LinkedList::LinkedList() { head = NULL; } LinkedList::~LinkedList() { ListNode *tmp = head; while (tmp != NULL) { head = head->getNext(); delete tmp; tmp = head; } } void LinkedList::insertItem(ListNode::value_type item) { ListNode *newNode,*cur = head; newNode = new ListNode; newNode->setDatum(item); newNode->setNext(NULL);.

could you implement this function please, im having issues with it..pdf

feroz544

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First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2 electrons (H) The only way to do this is: H-C=N: There is a C-N triple bond and a lone pair on the N. Now, the steric number is defined as the number of bonds to another atom + the number of lone pairs on the atom. For H: 1 bond = steric number of 1. For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4) For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4) Solution First let\'s draw out the Lewis structure such that each atom has either an octet (C and N), or 2 electrons (H) The only way to do this is: H-C=N: There is a C-N triple bond and a lone pair on the N. Now, the steric number is defined as the number of bonds to another atom + the number of lone pairs on the atom. For H: 1 bond = steric number of 1. For C: 4 bonds (1 single + 1 triple) = steric number of 4 (carbon almost always has SN = 4) For N: 3 bonds (1 triple) + 1 lone pair = steric number of 4 (nitrogen also often has SN = 4).

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