since both are strong acids we can add up their individual contributions towards H+ concentration [H+]=(4.4+5.3)*10-2=(9.7)*10-2 pH=2-log(9.7)=1.013 Solution since both are strong acids we can add up their individual contributions towards H+ concentration [H+]=(4.4+5.3)*10-2=(9.7)*10-2 pH=2-log(9.7)=1.013.