Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf

•

0 likes•2 views

Heterozygous FH means a person has inhrited the fsulty gene from either of his/her parents. Homozygous FH-condition where a person inherits two faulty oraltered grnes from both the parents. If the two faulty genes are identical it is refereed to as homozygous FH. By calculating the chance by Punnett square- X+-faulty gene 2 children -Normal FH by inheriting one faulty and one healthy gene-XX+ and XY+ 1Child-Homozygous by receiving faulty gene from each of the parents-X+X+ 1Child-Normal-i.e. will not inherit FH as the child will receive the norml genes from the parents.XY Therefore, in one family of four chldren the ratio of homozygous FH will be 1:4, it will bw about 1 in a million.X+YX+X+X+X+YXXX+XY Solution Heterozygous FH means a person has inhrited the fsulty gene from either of his/her parents. Homozygous FH-condition where a person inherits two faulty oraltered grnes from both the parents. If the two faulty genes are identical it is refereed to as homozygous FH. By calculating the chance by Punnett square- X+-faulty gene 2 children -Normal FH by inheriting one faulty and one healthy gene-XX+ and XY+ 1Child-Homozygous by receiving faulty gene from each of the parents-X+X+ 1Child-Normal-i.e. will not inherit FH as the child will receive the norml genes from the parents.XY Therefore, in one family of four chldren the ratio of homozygous FH will be 1:4, it will bw about 1 in a million.X+YX+X+X+X+YXXX+XY.

Education

Similar to Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf

If the characteristic followed in the pedigree is x-linked recessive allele, what is III-1\'s genotype? a. Hemizygous for a dominant allele b. Hemizygous for a recessive allele c. Definitely heterozygous d. dominant e. Either heterozygous or homozygous dominant Solution 1st generation parents 1,2 though are normal but must be heterozygotes (Pp) since their children are affected i.e. 2nd generation males 1,3. Since 1st generation male 3 is affected (pp) and 4 is normal but regardless if 4 in 1st generation is PP or Pp their children will be either 4 Pp i.e. heterozygote or 2 affected pp and 2 heterozygotes Pp. But the 2nd generation 4, 5 female are normal but heterozygotes Pp. So the cross between a 2nd generation affected male 3(pp) and a normal but heterozygote female 4(Pp) would have a normal male child only if hemizygous for a dominant allele condition exists. Hemizygous is a condition in which only one gene copy/DNA sequence exists in diploid cells. Males are hemizygous for most genes on sex chromosomes since they have only one X and one Y chromosome unlike two X for females. A recessive X-linked gene requires two mutant alleles to affect the female phenotype. Rules followed here are.

If the characteristic followed in the pedigree is x-linked recessive .pdf

aroraenterprisesmbd

Hemophilia is a recessive trait. The dominant trait is normal blood dotting A gene that can cause hemophilia is located on the X chromosome. If a homozygous normal female marries a normal male, they children might have which of the following phenotypes: Select one: a. normal females, hemophiliac females, and hemophiliac males. b. normal females, hemophiliac females, normal males, and hemophiliac males. c. normal females and hemophiliac males d. normal females and normal mates. e. normal females, normal males or hemophiliac males. Solution In X - linked recessive inheritance males are more prone to disease because they carry the disease trait. If the affected offspring’s mother has brother or father containing the same trait then the mother pass the trait to her offspring. The affected males produce unaffected daughters who can produce 50% affected sons. Hemophilia is the example of X - linked recessive trait. When a homozygous normal female marries to a normal male the offspring produced are normal females and normal males. Option d is correct..

Hemophilia is a recessive trait. The dominant trait is normal blood d.pdf

arihanthtoysandgifts

Ferdinand is affected by hemophilia, a recessive x-linked condition. He mates with an unaffected woman with no history of hemophilia in her family. Their first child is a girl with Turner Syndrome (XO sex chromosomes), who is also hemophiliac. You infer that she resulted from the following sperm and egg (answers listed in the order of sperm, egg):normal, normal Solution Answer: Because Ferdinand has hemophilia which is X-linked ressesive disease. Daughters produced by mating of ferdinand and a normal female would be carriers of hemophilia. In this case however, the daughter is having Turners\' syndrome (XO) and is heophilic as well. This implies that the X came from sperm of Ferdinand and the O is beacuse the X chromosome from the female was nondisjunct at meiosis I, as non-disjunction at meiosis II would result in two gaetes being normal, One being trisomic and one being monosomic. whereas nondysjunction at meiosis I would give rise to 50% trisomic and 50% monosomic gametes. Hence raising the possibility of turners\' syndrome after nondysjunction at meiosis I. Therefore answer is: c. Normal and non-dysjunction at meiosis I..

Ferdinand is affected by hemophilia, a recessive x-linked condition..pdf

arpitaeron555

Sex-linked inheritance by Puzon and Tope

Kathleen Faye Puzon

Law of Independent Assortment

Mae Bonto

Inbreeding and outbreeding

LekshmiJohnson

MolecularGeneticsUnit4-6.pptx

RCGaur1

4.3 theoretical genetics

cartlidge

Unit5: Biological Inheritance

aurorabiologia

1. In a given plant, the yellow seed color allele (Y) is dominant to green seed color (y). Give the genotypic and phenotypic ratios for the following crosses? a. homozygous yellow x green b. heterozygous yellow x green c. heterozygous yellow x heterozygous yellow d. green x green 2. If two animals heterozygous for a single pair of genes are mated and have 276 offspring, how many would be expected to have the dominant genotype? 3. Two long-winged fies are mated. The offspring included 90 with long wings and 32 with short wings. Which phenotype is recessive? 4. A blood test reveals that a couple both have the sickle-cell trat. What is the probability of their producing a child with sickle-cell anemia? 5. A blood type A woman has a type B child. She accuses a type O man of being the father. Knowing genetics you are asked to give an opinion; do so. 6. Assume that human eye color is controlled by a single pair of alleles. A blue-eyed man, both of whose parents were bom brown-eyed, marries a brown-eyed woman whose father was blue-eyed and whose mother was brown-eyed. They have a blue-eyed child. Which are the genotypes of all individuals mentioned? 7. A red fruit, tall tomato plant RrTt, is crossed with a yellow-fruited dwarf plant ritt. What genotypes and phenotypes would be expected in the offispring? 8. What genotype and phenotype would be expected in the offspring if the cross in the previous problem had been RrTt x RrTt ?.

1. In a given plant, the yellow seed color allele (Y) is dominant to .pdf

keshavagg1122

Presentation 02 genetics i

Ma'am Dawn

Deafness 2

mmh115

sex linked inheritance, Sex Influence inheritance and sex limited characters

Aashish Patel

agb1219-170321122125.pdf

OdaLamessa

Unit5 Biological Inheritance

aurorabiologia

sex linked inheritance

HadiAli42

Similar to Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf (16)

If the characteristic followed in the pedigree is x-linked recessive .pdf

Hemophilia is a recessive trait. The dominant trait is normal blood d.pdf

Ferdinand is affected by hemophilia, a recessive x-linked condition..pdf

Sex-linked inheritance by Puzon and Tope

Law of Independent Assortment

Inbreeding and outbreeding

MolecularGeneticsUnit4-6.pptx

4.3 theoretical genetics

Unit5: Biological Inheritance

1. In a given plant, the yellow seed color allele (Y) is dominant to .pdf

Presentation 02 genetics i

Deafness 2

sex linked inheritance, Sex Influence inheritance and sex limited characters

agb1219-170321122125.pdf

Unit5 Biological Inheritance

sex linked inheritance

More from aquazac

Answer: Every investor expects dividend from his investments.Dividend income helps investors in dealing with their routine expenses. Investors put their money to earn some positive returns and dividend is one of the way of getting returns for investors. So, It is a duty of management to satisfy dividend expectation of investors. If management do not pay dividend then it is known as retention of earnings. Retention earnings has it\'s own pro and cons, which are described as follows: Pros: Retained earnings reduces organization\'s dependence on external borrowings. It can be considered as an advantage when external borrowings are not available easily. Retained earnings indicates good business opportunities, It means organization is growing financially. It may result in better stock valuation of organization. In some situation dividend is subject to taxes (either distribution tax or income tax) in the hands of investors. So, in this case investors are not interested in dividend but they are more interested in capital gain(which may be tax exempt). So, In this situation retained earnings fulfill investor\'s objective. Cons: As explained earlier all the investors have some expectation of dividend, in case of higher retention of earnings it may become difficult to fulfill investor\'s expectations. Retention of earnings may affect investor\'s earning capacity when investors have available opportunities, which gives higher return than organization earns by retaining amount. In this case investor looses earning opportunities. In case of dividend management\'s decision is significantly influenced by media and institutional investors. Media is responsible for organization\'s image in society, such image significantly affects organization\'s financial performance. This is why management always considers media\'s point of view before making any dividend decision. Institutional investors are usually invests their money and takes part in decision making process of organization. Institutional investor\'s weight in decision making process is generally very high, so it is obvious that they influence management\'s dividend decision also. Solution Answer: Every investor expects dividend from his investments.Dividend income helps investors in dealing with their routine expenses. Investors put their money to earn some positive returns and dividend is one of the way of getting returns for investors. So, It is a duty of management to satisfy dividend expectation of investors. If management do not pay dividend then it is known as retention of earnings. Retention earnings has it\'s own pro and cons, which are described as follows: Pros: Retained earnings reduces organization\'s dependence on external borrowings. It can be considered as an advantage when external borrowings are not available easily. Retained earnings indicates good business opportunities, It means organization is growing financially. It may result in better stock valuation of organization. In some situ.

Answer Every investor expects dividend from his investments.Dividen.pdf

aquazac

Ans. Gene is defined as the segment of DNA that gives a functional product (protein, RNA). A functional product can be either protein (or polypeptide) or RNA. mRNA transcribes from a gene is further translated to produce polypeptides. However, all other RNAs are also transcribed from their respective genes. It includes tRNA, rRNA, snRNA and various regulatory RNAs (micro RNA, small interfering RNA), etc. tRNA acts as amino-acid carrier during translation. rRNA is the structural and functional scaffold of ribosomes. snRNA mediates splicing of immature mRNA. miRNA and siRNA have crucial roles in gene regulations. SO, polypeptides are just one class of functional product from DNA. The genomic DNA also produces various classes of RNAs with diverse functions that are crucial for cellular activates and gene regulation. Therefore, the statement “Add DNA sequences in the genome that does not encode polypeptides can be defined as junk DNA” is INCORRECT. Junk DNA is non-coding DNA that excludes all genes (including those encoding polypeptides and RNAs). Solution Ans. Gene is defined as the segment of DNA that gives a functional product (protein, RNA). A functional product can be either protein (or polypeptide) or RNA. mRNA transcribes from a gene is further translated to produce polypeptides. However, all other RNAs are also transcribed from their respective genes. It includes tRNA, rRNA, snRNA and various regulatory RNAs (micro RNA, small interfering RNA), etc. tRNA acts as amino-acid carrier during translation. rRNA is the structural and functional scaffold of ribosomes. snRNA mediates splicing of immature mRNA. miRNA and siRNA have crucial roles in gene regulations. SO, polypeptides are just one class of functional product from DNA. The genomic DNA also produces various classes of RNAs with diverse functions that are crucial for cellular activates and gene regulation. Therefore, the statement “Add DNA sequences in the genome that does not encode polypeptides can be defined as junk DNA” is INCORRECT. Junk DNA is non-coding DNA that excludes all genes (including those encoding polypeptides and RNAs)..

Ans. Gene is defined as the segment of DNA that gives a functional p.pdf

aquazac

additional optmization techniques for underlying IP network must: 1.Have bandwidth and performance to handle converged services. 2.Seprate VLAN for Voice traffic. 3.Meet the demand of high availability of voice services by providing resiliency to mitigate the effect of network outages. 4.Should be modular, hierarchical & consistent to promote consistency and manageability. 5.configure QoS on core switch. Solution additional optmization techniques for underlying IP network must: 1.Have bandwidth and performance to handle converged services. 2.Seprate VLAN for Voice traffic. 3.Meet the demand of high availability of voice services by providing resiliency to mitigate the effect of network outages. 4.Should be modular, hierarchical & consistent to promote consistency and manageability. 5.configure QoS on core switch..

additional optmization techniques for underlying IP network must1.pdf

aquazac

According to the given equation, aqueous carbon dioxide reacts with water to form carbonic acid, Carbonic acid is not stable in normal body temperatures, therefore, it ionizes into bicarbonate ion (HCO3-) and a hydrogen ion (H+) is liberated. The liberation of hydrogen ions decreases the pH. During breathing, oxygen is inhaled which is carried by the blood to the different tissues of the body. Oxygen facilitates the various metabolic reactions occurring inside our cells and helps in respiration, or the generation of energy. Carbon dioxide, formed as a by-product of these energy- generating metabolic reactions, diffuses out of the tissues and into the blood stream, which carries CO2 to the lungs, where it is exhaled out. a) In case of hypoventilation : The exchange of gases that occurs in the lungs while breathing is impaired. Therefore, the requisite amount of carbon dioxide is not being exhaled out. This leads to a build-up of carbon- dioxide in the blood plasma. As a result, the forward reaction is facilitated and more H+ ions are generated. The higher concentration of H+ ions decreases the pH (acidic pH). This can lead to acidosis. The build-up of carbon dioxide in the blood facilitates the forward reaction and therefore the equilibrium shifts to the right. The hydronium ion or H3O+ is the product of a hydrogen ion (H+) and water. Since a hydrogen ion is too small to exist freely in water, it therefore combines with a water molecule to form a hydronium ion which is more stable. In case of hypoventilation, the concentration of H+ ions increase. Therefore, the concentration of hydronium ions increase during hypoventilation. The stress concentration or partial pressure of CO2 during hypoventilation is significantly higher than 40mmHg (around 60-65 mmHg). b) In case of hyperventilation : The breathing rate is more than normal. Therefore, as a result of heavier and faster breathing, the CO2 concentration in the blood rapidly decreases, that is, CO2 easily leaves the blood plasma. Decrease in the CO2 concentration slows down the rate of the forward reaction, reducing the levels at which bicarbonate ion and H+ ion concentration were being generated. The bicarbonate and hydrogen ions recombine to yield CO2 and water. This lowering in hydrogen ion concentration consequently lowers the pH (alkaline pH). This can lead to alkalosis. As a result of the lowering of CO2 , the reverse reaction takes place. The carbonic acid changes back to CO2 and H2O, shifting the equilibrium to the left. The concentration of H3O+ decreases during hyperventilation, since the H+ ion concentration is lowered. The stress levels or partial pressure of CO2 during hyperventilation is significantly lower than 40 mmHg (around 25-30 mmHg). c) If sodium carbonate or Na2CO3 is added instead of sodium bicarbonate, then sodium carbonate would react with water and it would hydrolyse into Na+ and CO32- ions. The CO32- combine with the hydrogen (H) present in water to form H2CO3 (carbon.

According to the given equation, aqueous carbon dioxide reacts with .pdf

aquazac

a) mean = 1.4*3 Thus distribution is Poisson(4.2) P(X = 4) = 4.2^4 * e^{-4.2} / 4! = 0.1944 b) average number of ghosts in 90min (1.5hrs) interval = 1.4*1.5 = 2.1 c) Probability that 4th ghost will appear before 10 am = Probability that number of ghosts appearing from 8 to 10 am >= 4 As it is a 2 hr period, the distribution of number of ghosts is Poisson(1.4*2) i.e Poisson(2.8) P(X >= 4) = 1 - P(X < 4) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)] = 1 - [(2.8^0 * e^{-2.8} / 0!) + (2.8^1 * e^{-2.8} / 1!) + (2.8^2 * e^{-2.8} / 2!) + (2.8^3 * e^{- 2.8} / 3!)] = 1 - [0.0608 + 0.1703 + 0.2384 + 0.2225] = 0.692 d) When arrival distribution is Poisson(lambda), inter-arrival time distribution is Exponential(lambda) Thus, interarrival time distribution is Exponential(1.4) Expected value of time between 5th and 6th ghost = 1/1.4 = 0.7143hr e) On average time taken for 10th ghost to arrive = 10*(1/1.4) = 7.143hr Thus on an average, 10th ghost will arrive at 3:09pm f) Expected value of time between ghost appearances = 1/1.4 = 0.7143hr (see part d) g) Probability that 3rd ghost appears after 9:45 am = Probablity that number of ghosts appearing till 9:45 am < 3 Duration from 8am to 9:45 am = 1.75hr Mean number of ghosts = 1.4*1.75 = 2.45 Thus X is Poisson(2.45) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = (2.45^0 * e^{-2.45} / 0!) + (2.45^1 * e^{-2.45} / 1!) + (2.45^2 * e^{-2.45} / 2!) = 0.0863 + 0.2114 + 0.2590 = 0.5567 h) As inter-arrival time is Exponential(1.4), inter-arrival time is memoryless Thus, time for 7th ghost will be calculated from 1:00 pm and not from 12:35pm due to memorylessness property. Time duration from 1:00pm to 1:15pm = 0.25hrs Let Y be random variable denoting inter-arrival time probability that the 7th ghost will appear before 1:15 p.m. = P(Y < 0.25) = 1 - e^{-1.4 * 0.25) = 0.2953 i) Expected value of time for 7th ghost to appear after 1:00pm = 1/1.4 = 0.7143hr = 42.86 min Time from 12:35pm to 1:00pm = 25min Thus expected interarrival time = 25 + 42.86 = 67.86 min = 1hr 7.86min j) Expected duration after 1:00pm for 9th ghost to appear = 3 * (1/1.4) = 2.143hr = 2hr 8.58min Thus expected time at which 9th ghost appears = 3:09pm k) As the inter-arrival time follows memorylessness property, the future probabilities do not change with the observed value at past. Thus, 4 ghosts appearing between 7:00pm to 10:00pm does not affect ghost appearance from 11:00pm to 11:30pm Duration from 11:00pm to 11:30pm = 0.5hrs mean number of ghosts = 1.4*0.5 = 0.7 Thus it follows Poisson(0.7) distribution P(X > 2) = 1 - P(X <= 2) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)] = 1 - [(0.7^0 * e^{-0.7} / 0!) + (0.7^1 * e^{-0.7} / 1!) + (0.7^2 * e^{-0.7} / 2!)] = 1 - [0.4966 + 0.3476 + 0.1217] = 0.0341 l) Probability that 8 ghosts appear between 6pm and midnight = Probability that number of ghosts appear from 6pm to 7pm and 10pm to midnight = 4 as it is known that 4 ghosts appeared from 7pm to 10pm Let A denote number of ghost from 6pm to 7pm B denote number of ghosts .

a) mean = 1.43Thus distribution is Poisson(4.2)P(X = 4) = 4.2^4.pdf

aquazac

2. a. Wired Media Type and Explination: Twisted-Pair Cable Twisted-pair cable is a type of cabling that is used for telephone communications and most modern Ethernet networks. A pair of wires forms a circuit that can transmit data. The pairs are twisted to provide protection against crosstalk, the noise generated by adjacent pairs. When electrical current flows through a wire, it creates a small, circular magnetic field around the wire. When two wires in an electrical circuit are placed close together, their magnetic fields are the exact opposite of each other. Thus, the two magnetic fields cancel each other out. They also cancel out any outside magnetic fields. Twisting the wires can enhance this cancellation effect. Using cancellation together with twisting the wires, cable designers can effectively provide self- shielding for wire pairs within the network media. Two basic types of twisted-pair cable exist: unshielded twisted pair (UTP) and shielded twisted pair (STP). The following sections discuss UTP and STP cable in more detail. UTP Cable UTP cable is a medium that is composed of pairs of wires . UTP cable is used in a variety of networks. Each of the eight individual copper wires in UTP cable \\is covered by an insulating material. In addition, the wires in each pair are twisted around each other. UTP cable relies solely on the cancellation effect produced by the twisted wire pairs to limit signal degradation caused by electromagnetic interference (EMI) and radio frequency interference (RFI). To further reduce crosstalk between the pairs in UTP cable, the number of twists in the wire pairs varies. UTP cable must follow precise specifications governing how many twists or braids are permitted per meter (3.28 feet) of cable. UTP cable often is installed using a Registered Jack 45 (RJ-45) connector The RJ-45 is an eight- wire connector used commonly to connect computers onto a local-area network (LAN), especially Ethernets. When used as a networking medium, UTP cable has four pairs of either 22- or 24-gauge copper wire. UTP used as a networking medium has an impedance of 100 ohms; this differentiates it from other types of twisted-pair wiring such as that used for telephone wiring, which has impedance of 600 ohms. UTP cable offers many advantages. Because UTP has an external diameter of approximately 0.43 cm (0.17 inches), its small size can be advantageous during installation. Because it has such a small external diameter, UTP does not fill up wiring ducts as rapidly as other types of cable. This can be an extremely important factor to consider, particularly when installing a network in an older building. UTP cable is easy to install and is less expensive than other types of networking media. In fact, UTP costs less per meter than any other type of LAN cabling. And because UTP can be used with most of the major networking architectures, it continues to grow in popularity. Disadvantages also are involved in using twisted-pair cabling, howe.

2.a. Wired Media Type and ExplinationTwisted-Pair CableTwiste.pdf

aquazac

A person may not choose to participate in the labour force due to Laziness, lack of ambition, emotional or chemical imbalance, independent wealth, personal unavailability, or other priorities. However, race, location, education, and marital status are irrelevant at times. They do affect the type of job, or their availability, but not the individual\'s desire to have one. Choosing to stay home and raise children is an example of different priorities, and a spouse\'s income, if they are wealthy enough, may negate having to even make a choice. (a) with low education, a job might not pay much more than unemployment benefit. (b) with children, there is strong incentive to stay at home and take care of them. (c) with one spouse earning a lot, another spouse can stay at home. (d) if person belongs to a race with bad reputation, they are less likely to get hired. But at times women are viewed as better workers than men from same race. (e) in rural areas, there are fewer jobs, and the commute to them is longer and therefore they prefer to do some small work nearby or choose not to work at all. Solution A person may not choose to participate in the labour force due to Laziness, lack of ambition, emotional or chemical imbalance, independent wealth, personal unavailability, or other priorities. However, race, location, education, and marital status are irrelevant at times. They do affect the type of job, or their availability, but not the individual\'s desire to have one. Choosing to stay home and raise children is an example of different priorities, and a spouse\'s income, if they are wealthy enough, may negate having to even make a choice. (a) with low education, a job might not pay much more than unemployment benefit. (b) with children, there is strong incentive to stay at home and take care of them. (c) with one spouse earning a lot, another spouse can stay at home. (d) if person belongs to a race with bad reputation, they are less likely to get hired. But at times women are viewed as better workers than men from same race. (e) in rural areas, there are fewer jobs, and the commute to them is longer and therefore they prefer to do some small work nearby or choose not to work at all..

A person may not choose to participate in the labour force due to La.pdf

aquazac

Well.. 1) Ionic bonds are almost always metal to non-metal. (opposing charges attract). 2) Covalent, electron-sharing. \"co\"-valent. Valent referring to the valence electrons of the element, that is, the electrons in outer most shell. Remember each element wants to reach a more stable state. To achieve this it will share electrons with another element through covalent bonds. 3) a covalent bond is said to be polar if one of the elements sharing the electrons has a greater electronegativity. (i.e. water contains polar covalent bonds between the oxygen and the hydrogens because oxygen is far more electronegative than hydrogen, therefore it \"hogs\" the electrons. 4) non-polar covalent bonds have an equal sharing of the electrons, equal electronegativity. Hope this helps! Solution Well.. 1) Ionic bonds are almost always metal to non-metal. (opposing charges attract). 2) Covalent, electron-sharing. \"co\"-valent. Valent referring to the valence electrons of the element, that is, the electrons in outer most shell. Remember each element wants to reach a more stable state. To achieve this it will share electrons with another element through covalent bonds. 3) a covalent bond is said to be polar if one of the elements sharing the electrons has a greater electronegativity. (i.e. water contains polar covalent bonds between the oxygen and the hydrogens because oxygen is far more electronegative than hydrogen, therefore it \"hogs\" the electrons. 4) non-polar covalent bonds have an equal sharing of the electrons, equal electronegativity. Hope this helps!.

Well.. 1) Ionic bonds are almost always metal to .pdf

aquazac

1. The answer is: d) Environmental Effects Environmental effects can cause a single genotype to produce a range of potential Phenotypes. 2. The answer is: c) Differ in both mean and variance The Figure represents two distributions that differ in both mean and variance. Solution 1. The answer is: d) Environmental Effects Environmental effects can cause a single genotype to produce a range of potential Phenotypes. 2. The answer is: c) Differ in both mean and variance The Figure represents two distributions that differ in both mean and variance..

1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf

aquazac

clear clc close all %Use polyfit to solve for the phase lines point11=[0,15]; point12=[0,300]; line1=polyfit(point11,point12,1); m1=line1(1); b1=line1(2); xpf1=linspace(min(point11),max(point11),100); ypf1=m1*xpf1+b1; point21=[0,15]; point22=[700,300]; line2=polyfit(point21,point22,1); m2=line2(1); b2=line2(2); xpf2=linspace(min(point21),max(point21),100); ypf2=m2*xpf2+b2; point31=[0,50]; point32=[700,300]; line3=polyfit(point31,point32,1); m3=line3(1); b3=line3(2); xpf3=linspace(min(point31),max(point31),100); ypf3=m3*xpf3+b3; point41=[50,100]; point42=[300,800]; line4=polyfit(point41,point42,1); m4=line4(1); b4=line4(2); xpf4=linspace(min(point41),max(point41),100); ypf4=m4*xpf4+b4; point51=[100,85]; point52=[800,300]; line5=polyfit(point51,point52,1); m5=line5(1); b5=line5(2); xpf5=linspace(min(point51),max(point51),100); ypf5=m5*xpf5+b5; point61=[85,100]; point62=[300,0]; line6=polyfit(point61,point62,1); m6=line6(1); b6=line6(2); xpf6=linspace(min(point61),max(point61),100); ypf6=m6*xpf6+b6; point71=[15,85]; point72=[300,300]; %Allow the user to set the percent of B b=input(\'Enter the mass percent of B: \'); %Return an error if the percent of B is not a valid number if b<0 || b>100 error(\'Please enter a value between 0 and 100.\') end %Allow the user to set the temperature t=input(\'Enter the temperature [deg C]: \'); %Solve for percent composition of A a=100-b; %Determine phase based on temperature and percent composition of B using %the phase lines if t<300 if b<15 && t>m1*b+b1 phase=\'alpha\'; elseif b<15 && t=15 && b<=85 phase=\'alpha + beta\'; elseif b>85 && t>m6*b+b6 phase=\'beta\'; else phase=\'alpha + beta\'; end elseif b<15 if t=15 && b<=50 if t50 && b<=85 if t=15 && b<=85 && t==300 fprintf(\'The provided conditions fall on the eutectic line.\ \') end if b==50 && t==300 fprintf(\'The provided conditions fall on the eutectic point.\ \') end %Output a formatted statement to display the phase fprintf(\'For the composition of %0.2f%% A, %0.2f%% B and a temperature of %0.0f degrees Celsius, the phase is %s.\ \',a,b,t,phase) %Create a plot of the phase lines and the user\'s set point figure(\'color\',\'white\') %Set axes axis([0 100 0 1000]) %Plot the phase lines, eutectic line, eutectic point, and the user\'s point plot(xpf1,ypf1,\'-b\') hold on plot(xpf2,ypf2,\'-b\') plot(xpf3,ypf3,\'-b\') plot(xpf4,ypf4,\'-b\') plot(xpf5,ypf5,\'-b\') plot(xpf6,ypf6,\'-b\') plot(point71,point72,\'-k\') plot(b,t,\'ro\',\'MarkerFaceColor\',\'r\') %Assign a title and axes labels title(\'Phase Diagram of Elements A and B\') xlabel(\'Percent Composition of B\') ylabel(\'Temperature (T) [deg C]\') %Set scaling for the axes set(gca,\'XTick\',0:10:100,\'YTick\',0:100:1000) %Place the phase names on the graph text(40,200,\'alpha+beta\') text(45,600,\'Liquid\') text(90,300,\'beta\') text(3,300,\'alpha\') text(15,375,\'alpha + Liquid\') text(62,375,\'beta + Liquid\') Solution clear clc close all %Use polyfit to solve for the phase lines point11=[0,15]; point.

clear clc close all Use polyfit to solve for the phase l.pdf

aquazac

The oxygen appears in both step reactions. But, it would not appear in the final reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction is 2O3 ====> 3 O2 (No O) Solution The oxygen appears in both step reactions. But, it would not appear in the final reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction is 2O3 ====> 3 O2 (No O).

The oxygen appears in both step reactions. But, i.pdf

aquazac

PART A The element Si belongs to IVA group. Therefore, four electro.pdf

aquazac

The two contributions to the cohesive energy of the ionic crystal are : Vander waals attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero- point energy is the lowest possible energy that a quantum mechanical physical system may have; it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in their ground state and have an associated zero-point energy, a consequence of their wave-like interaction. Solution The two contributions to the cohesive energy of the ionic crystal are : Vander waals attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero- point energy is the lowest possible energy that a quantum mechanical physical system may have; it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in their ground state and have an associated zero-point energy, a consequence of their wave-like interaction..

The two contributions to the cohesive energy of t.pdf

aquazac

If you are talking about an extraction design, the the water solubility has to be greater in the aqueous base because of the greater solubility of the salts of the acids (with few exceptions), again presuming a differential extraction aqueous to organic. Solution If you are talking about an extraction design, the the water solubility has to be greater in the aqueous base because of the greater solubility of the salts of the acids (with few exceptions), again presuming a differential extraction aqueous to organic..

If you are talking about an extraction design, th.pdf

aquazac

Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near common ancestor of homosapiens. Solution Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near common ancestor of homosapiens..

Yes ,its true. Though both gibbons and rhesus monkeys belong to pr.pdf

aquazac

When something boils, it changes states of matter. It would go from .pdf

aquazac

We need to discuss why there is an importance of adding residents to the budget planning, we can go through below explaintion and can derived various conclusions from the same. In explaining why they did or did not seek input from citizens, respondents in- dicated that the process was guided by the desires of the leadership. Of those who said that they did seek citizen input, the desire (as opposed to the obligation through policy) of the staff or the governing board or staff to seek public opinion seemed to provide some motivation. Almost three-quarters of responding cities cited staff desire, and almost two-thirds, governing board desire. The pattern for counties was similar. The most often cited reason for extra effort to involve the public was board interest. Almost half of the counties also cited staff interest. Although citizen involvement is a hot topic in management literature these days, local governments in North Caro- lina are generally not making extensive fforts to involve residents in budgeting. Barely half of the cities responding to the survey and less than a third of the counties go beyond the single, mandated hearing to get citizen input In general, cities tend to seek input more than counties do. This result might be explained by the different types of services offered by the two forms of gov- ernment. Counties provide funding for, among other things, social services, public health services, mental health services, and schools, and the boards over- seeing these services may seek citizen input when they are preparing their own budget request for the county. Although there is informal interest in hearing from citizens, boards clearly want to remain flexible in when and how they obtain input. Only 13 percent of the city respondents had a formal policy or requirement for citizen involvement beyond the single, state-mandated hearing. Medium to large cities were more likely to have such requirements than small cities. Only one county, a larger one, reported having such a policy or requirement. Although citizen involvement is a hot topic in management literature these days, local governments in North Caro- lina are generally not making extensive efforts to involve residents in budgeting. Barely half of the cities responding to the survey and less than a third of the counties go beyond the single, mandated hearing to get citizen input Of those that did not seek extra citizen involvement, the most common reason cited, on both the city and the county level, was lack of governing board interest. The second most common reason was poor response in the past, when at- tempts to get citizens involved did not seem very effective. At the county level, lack of board interest was a far more important factor than anything else, including poor past response: 71 percent of respondents cited lack of board interest, whereas only 39 percent cited poor past response Although staff interest seemed to be a big motivator for involving ci.

We need to discuss why there is an importance of adding residents to.pdf

aquazac

What is the largest decimal integer that can be represented with the following number of bits? 1. 3 bits 2. 8 bits 3. 32 bits 4. 64 bits How do you find out the largest decimal integer? Solution In general, with k bits we can represent 2k values. Their range will depend on the system: Unsigned: 0 to 2k-1 1. 3 bits => 2^3 - 1 => 7 => 111 2. 8 bits => 2^8 - 1 => 255 3. 32 bits => 2^32 - 1 4. 64 bits => 2^64 - 1.

What is the largest decimal integer that can be represented with the.pdf

aquazac

Throwing.javaimport java.util.InputMismatchException; import jav.pdf

aquazac

This electron transport is accompanied by the protons transfer into intermembrane space. Protons release potential which drives the phosphorylation of ADP to ATP. Protons return to the matrix through a proton specific channel Solution This electron transport is accompanied by the protons transfer into intermembrane space. Protons release potential which drives the phosphorylation of ADP to ATP. Protons return to the matrix through a proton specific channel.

This electron transport is accompanied by the protons transfer into .pdf

aquazac

More from aquazac (20)

Answer Every investor expects dividend from his investments.Dividen.pdf

Ans. Gene is defined as the segment of DNA that gives a functional p.pdf

additional optmization techniques for underlying IP network must1.pdf

According to the given equation, aqueous carbon dioxide reacts with .pdf

a) mean = 1.43Thus distribution is Poisson(4.2)P(X = 4) = 4.2^4.pdf

2.a. Wired Media Type and ExplinationTwisted-Pair CableTwiste.pdf

A person may not choose to participate in the labour force due to La.pdf

Well.. 1) Ionic bonds are almost always metal to .pdf

1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf

clear clc close all Use polyfit to solve for the phase l.pdf

The oxygen appears in both step reactions. But, i.pdf

PART A The element Si belongs to IVA group. Therefore, four electro.pdf

The two contributions to the cohesive energy of t.pdf

If you are talking about an extraction design, th.pdf

Yes ,its true. Though both gibbons and rhesus monkeys belong to pr.pdf

When something boils, it changes states of matter. It would go from .pdf

We need to discuss why there is an importance of adding residents to.pdf

What is the largest decimal integer that can be represented with the.pdf

Throwing.javaimport java.util.InputMismatchException; import jav.pdf

This electron transport is accompanied by the protons transfer into .pdf

Recently uploaded

The Department of Emergency Medicine at Carolinas Medical Center is passionate about education! Dr. Michael Gibbs is a world-renowned clinician and educator and has helped guide numerous young clinicians on the long path of Mastery of Emergency Medical Care. With his oversight, the EMGuideWire team aim to help augment our understanding of emergent imaging. You can follow along with the EMGuideWire.com team as they post these educational, self-guided radiology slides or you can also use this section to learn more in-depth about specific conditions and diseases. This Radiology Reading Room pertains to Sternal Fractures and Dislocations and is brought to you by Carrie Bissell, MD, Aaron Fox, MD, Kendrick Lim, MD, Stephanie Jensen, MD, and Olivia Rice, MD. It is has special guest editor: Sean Dieffenbaugher, MD and Laurence Kempton, MD

Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room

Sean M. Fox

ANTI PARKISON DRUGS.pptx

PoojaSen20

Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

EADTU

DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM

ELOISARIVERA8

Improved Approval Flow in Odoo 17 Studio App

Celine George

Andreas Schleicher presents at the launch of What does child empowerment mean...

EduSkills OECD

How to Send Pro Forma Invoice to Your Customers in Odoo 17

Celine George

VAMOS CUIDAR DO NOSSO PLANETA! .

Colégio Santa Teresinha

How To Create Editable Tree View in Odoo 17

Celine George

An Overview of the Odoo 17 Knowledge App

Celine George

The Story of Village Palampur Class 9 Free Study Material PDF

Vivekanand Anglo Vedic Academy

male presentation...pdf.................

MirzaAbrarBaig5

會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽

中央社

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Limon Prince

Transport (British English) or Transportation (American English) ransportation has developed along three basic Mode (Media):- 1. Land Transportation (way)– (a) Road Transportation (b) Rail Transportation 2. Water Transportation 3. Air Transportation Tramway Inland water transport Ocean transport These may be classified as under: (a). Liners (b). Tramps Liners Vs Tramps Figure- Layout airport runway design TRAFFIC SIGNS

Basic Civil Engineering notes on Transportation Engineering & Modes of Transport

Denish Jangid

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

Pondicherry University

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

Nguyen Thanh Tu Collection

When Quality Assurance Meets Innovation in Higher Education - Report launch w...

Gary Wood

ESSENTIAL of (CS/IT/IS) class 07 (Networks)

Dr. Mazin Mohamed alkathiri

Mattingly "AI & Prompt Design: Named Entity Recognition"

National Information Standards Organization (NISO)

Recently uploaded (20)

Sternal Fractures & Dislocations - EMGuidewire Radiology Reading Room

ANTI PARKISON DRUGS.pptx

Transparency, Recognition and the role of eSealing - Ildiko Mazar and Koen No...

DEMONSTRATION LESSON IN ENGLISH 4 MATATAG CURRICULUM

Improved Approval Flow in Odoo 17 Studio App

Andreas Schleicher presents at the launch of What does child empowerment mean...

How to Send Pro Forma Invoice to Your Customers in Odoo 17

VAMOS CUIDAR DO NOSSO PLANETA! .

How To Create Editable Tree View in Odoo 17

An Overview of the Odoo 17 Knowledge App

The Story of Village Palampur Class 9 Free Study Material PDF

male presentation...pdf.................

會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽會考英聽

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Basic Civil Engineering notes on Transportation Engineering & Modes of Transport

FICTIONAL SALESMAN/SALESMAN SNSW 2024.pdf

TỔNG HỢP HƠN 100 ĐỀ THI THỬ TỐT NGHIỆP THPT TOÁN 2024 - TỪ CÁC TRƯỜNG, TRƯỜNG...

When Quality Assurance Meets Innovation in Higher Education - Report launch w...

ESSENTIAL of (CS/IT/IS) class 07 (Networks)

Mattingly "AI & Prompt Design: Named Entity Recognition"

Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf

1. Heterozygous FH means a person has inhrited the fsulty gene from either of his/her parents. Homozygous FH-condition where a person inherits two faulty oraltered grnes from both the parents. If the two faulty genes are identical it is refereed to as homozygous FH. By calculating the chance by Punnett square- X+-faulty gene 2 children -Normal FH by inheriting one faulty and one healthy gene-XX+ and XY+ 1Child-Homozygous by receiving faulty gene from each of the parents-X+X+ 1Child-Normal-i.e. will not inherit FH as the child will receive the norml genes from the parents.XY Therefore, in one family of four chldren the ratio of homozygous FH will be 1:4, it will bw about 1 in a million.X+YX+X+X+X+YXXX+XY Solution Heterozygous FH means a person has inhrited the fsulty gene from either of his/her parents. Homozygous FH-condition where a person inherits two faulty oraltered grnes from both the parents. If the two faulty genes are identical it is refereed to as homozygous FH. By calculating the chance by Punnett square- X+-faulty gene 2 children -Normal FH by inheriting one faulty and one healthy gene-XX+ and XY+ 1Child-Homozygous by receiving faulty gene from each of the parents-X+X+ 1Child-Normal-i.e. will not inherit FH as the child will receive the norml genes from the parents.XY Therefore, in one family of four chldren the ratio of homozygous FH will be 1:4, it will bw about 1 in a million.X+YX+X+X+X+YXXX+XY

Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf

Recommended

Recommended

More Related Content

Similar to Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf

Similar to Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf (16)

More from aquazac

More from aquazac (20)

Recently uploaded

Recently uploaded (20)

Heterozygous FH means a person has inhrited the fsulty gene from eit.pdf