Yes ,its true. Though both gibbons and rhesus monkeys belong to pr.pdf

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Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near common ancestor of homosapiens. Solution Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near common ancestor of homosapiens..

Yes ,it's true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens.
Solution
Yes ,it's true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens.

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1. The answer is: d) Environmental Effects Environmental effects can cause a single genotype to produce a range of potential Phenotypes. 2. The answer is: c) Differ in both mean and variance The Figure represents two distributions that differ in both mean and variance. Solution 1. The answer is: d) Environmental Effects Environmental effects can cause a single genotype to produce a range of potential Phenotypes. 2. The answer is: c) Differ in both mean and variance The Figure represents two distributions that differ in both mean and variance..

1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf

1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf

1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf

clear clc close all %Use polyfit to solve for the phase lines point11=[0,15]; point12=[0,300]; line1=polyfit(point11,point12,1); m1=line1(1); b1=line1(2); xpf1=linspace(min(point11),max(point11),100); ypf1=m1*xpf1+b1; point21=[0,15]; point22=[700,300]; line2=polyfit(point21,point22,1); m2=line2(1); b2=line2(2); xpf2=linspace(min(point21),max(point21),100); ypf2=m2*xpf2+b2; point31=[0,50]; point32=[700,300]; line3=polyfit(point31,point32,1); m3=line3(1); b3=line3(2); xpf3=linspace(min(point31),max(point31),100); ypf3=m3*xpf3+b3; point41=[50,100]; point42=[300,800]; line4=polyfit(point41,point42,1); m4=line4(1); b4=line4(2); xpf4=linspace(min(point41),max(point41),100); ypf4=m4*xpf4+b4; point51=[100,85]; point52=[800,300]; line5=polyfit(point51,point52,1); m5=line5(1); b5=line5(2); xpf5=linspace(min(point51),max(point51),100); ypf5=m5*xpf5+b5; point61=[85,100]; point62=[300,0]; line6=polyfit(point61,point62,1); m6=line6(1); b6=line6(2); xpf6=linspace(min(point61),max(point61),100); ypf6=m6*xpf6+b6; point71=[15,85]; point72=[300,300]; %Allow the user to set the percent of B b=input(\'Enter the mass percent of B: \'); %Return an error if the percent of B is not a valid number if b<0 || b>100 error(\'Please enter a value between 0 and 100.\') end %Allow the user to set the temperature t=input(\'Enter the temperature [deg C]: \'); %Solve for percent composition of A a=100-b; %Determine phase based on temperature and percent composition of B using %the phase lines if t<300 if b<15 && t>m1*b+b1 phase=\'alpha\'; elseif b<15 && t=15 && b<=85 phase=\'alpha + beta\'; elseif b>85 && t>m6*b+b6 phase=\'beta\'; else phase=\'alpha + beta\'; end elseif b<15 if t=15 && b<=50 if t50 && b<=85 if t=15 && b<=85 && t==300 fprintf(\'The provided conditions fall on the eutectic line.\ \') end if b==50 && t==300 fprintf(\'The provided conditions fall on the eutectic point.\ \') end %Output a formatted statement to display the phase fprintf(\'For the composition of %0.2f%% A, %0.2f%% B and a temperature of %0.0f degrees Celsius, the phase is %s.\ \',a,b,t,phase) %Create a plot of the phase lines and the user\'s set point figure(\'color\',\'white\') %Set axes axis([0 100 0 1000]) %Plot the phase lines, eutectic line, eutectic point, and the user\'s point plot(xpf1,ypf1,\'-b\') hold on plot(xpf2,ypf2,\'-b\') plot(xpf3,ypf3,\'-b\') plot(xpf4,ypf4,\'-b\') plot(xpf5,ypf5,\'-b\') plot(xpf6,ypf6,\'-b\') plot(point71,point72,\'-k\') plot(b,t,\'ro\',\'MarkerFaceColor\',\'r\') %Assign a title and axes labels title(\'Phase Diagram of Elements A and B\') xlabel(\'Percent Composition of B\') ylabel(\'Temperature (T) [deg C]\') %Set scaling for the axes set(gca,\'XTick\',0:10:100,\'YTick\',0:100:1000) %Place the phase names on the graph text(40,200,\'alpha+beta\') text(45,600,\'Liquid\') text(90,300,\'beta\') text(3,300,\'alpha\') text(15,375,\'alpha + Liquid\') text(62,375,\'beta + Liquid\') Solution clear clc close all %Use polyfit to solve for the phase lines point11=[0,15]; point.

clear clc close all Use polyfit to solve for the phase l.pdf

clear clc close all Use polyfit to solve for the phase l.pdf

clear clc close all Use polyfit to solve for the phase l.pdf

The oxygen appears in both step reactions. But, it would not appear in the final reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction is 2O3 ====> 3 O2 (No O) Solution The oxygen appears in both step reactions. But, it would not appear in the final reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction is 2O3 ====> 3 O2 (No O).

The oxygen appears in both step reactions. But, i.pdf

The oxygen appears in both step reactions. But, i.pdf

The oxygen appears in both step reactions. But, i.pdf

PART A: The element Si belongs to IVA group. Therefore, four electrons present in the outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D: All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons. PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is [Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell. Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal. PART I: The element Ba belongs to IIA group. Therefore, two electrons present in the s-orbital. Hence the condensed electron configuration of Ba is [Xe] 6s2. PART J: The outermost s- electron is completely filled. Therefore, there are no unpaired electrons present in Ba metal. PART K: The element Tl belongs to IIIA group. Therefore, the condensed electron configuration of Tl is [Xe] 4f14 5d10 6s2 6p1. PART L: The all orbitals are filled with electrons except Tl. Therefore, the number of unpaired electrons is 1 Solution PART A: The element Si belongs to IVA group. Therefore, four electrons present in the outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D: All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons. PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is [Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell. Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal. PART I: The element Ba belongs to IIA group. Th.

PART A The element Si belongs to IVA group. Therefore, four electro.pdf

PART A The element Si belongs to IVA group. Therefore, four electro.pdf

PART A The element Si belongs to IVA group. Therefore, four electro.pdf

The two contributions to the cohesive energy of the ionic crystal are : Vander waals attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero- point energy is the lowest possible energy that a quantum mechanical physical system may have; it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in their ground state and have an associated zero-point energy, a consequence of their wave-like interaction. Solution The two contributions to the cohesive energy of the ionic crystal are : Vander waals attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero- point energy is the lowest possible energy that a quantum mechanical physical system may have; it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in their ground state and have an associated zero-point energy, a consequence of their wave-like interaction..

The two contributions to the cohesive energy of t.pdf

The two contributions to the cohesive energy of t.pdf

The two contributions to the cohesive energy of t.pdf

If you are talking about an extraction design, the the water solubility has to be greater in the aqueous base because of the greater solubility of the salts of the acids (with few exceptions), again presuming a differential extraction aqueous to organic. Solution If you are talking about an extraction design, the the water solubility has to be greater in the aqueous base because of the greater solubility of the salts of the acids (with few exceptions), again presuming a differential extraction aqueous to organic..

If you are talking about an extraction design, th.pdf

If you are talking about an extraction design, th.pdf

If you are talking about an extraction design, th.pdf

When something boils, it changes states of matter. It would go from .pdf

When something boils, it changes states of matter. It would go from .pdf

When something boils, it changes states of matter. It would go from .pdf

We need to discuss why there is an importance of adding residents to the budget planning, we can go through below explaintion and can derived various conclusions from the same. In explaining why they did or did not seek input from citizens, respondents in- dicated that the process was guided by the desires of the leadership. Of those who said that they did seek citizen input, the desire (as opposed to the obligation through policy) of the staff or the governing board or staff to seek public opinion seemed to provide some motivation. Almost three-quarters of responding cities cited staff desire, and almost two-thirds, governing board desire. The pattern for counties was similar. The most often cited reason for extra effort to involve the public was board interest. Almost half of the counties also cited staff interest. Although citizen involvement is a hot topic in management literature these days, local governments in North Caro- lina are generally not making extensive fforts to involve residents in budgeting. Barely half of the cities responding to the survey and less than a third of the counties go beyond the single, mandated hearing to get citizen input In general, cities tend to seek input more than counties do. This result might be explained by the different types of services offered by the two forms of government. Counties provide funding for, among other things, social services, public health services, mental health services, and schools, and the boards over- seeing these services may seek citizen input when they are preparing their own budget request for the county. Although there is informal interest in hearing from citizens, boards clearly want to remain flexible in when and how they obtain input. Only 13 percent of the city respondents had a formal policy or requirement for citizen involvement beyond the single, state-mandated hearing. Medium to large cities were more likely to have such requirements than small cities. Only one county, a larger one, reported having such a policy or requirement. Although citizen involvement is a hot topic in management literature these days, local governments in North Caro- lina are generally not making extensive efforts to involve residents in budgeting. Barely half of the cities responding to the survey and less than a third of the counties go beyond the single, mandated hearing to get citizen input Of those that did not seek extra citizen involvement, the most common reason cited, on both the city and the county level, was lack of governing board interest. The second most common reason was poor response in the past, when attempts to get citizens involved did not seem very effective. At the county level, lack of board interest was a far more important factor than anything else, including poor past response: 71 percent of respondents cited lack of board interest, whereas only 39 percent cited poor past response Although staff interest seemed to be a big motivator for involving ci.

We need to discuss why there is an importance of adding residents to.pdf

We need to discuss why there is an importance of adding residents to.pdf

We need to discuss why there is an importance of adding residents to.pdf

What is the largest decimal integer that can be represented with the following number of bits? 1. 3 bits 2. 8 bits 3. 32 bits 4. 64 bits How do you find out the largest decimal integer? Solution In general, with k bits we can represent 2k values. Their range will depend on the system: Unsigned: 0 to 2k-1 1. 3 bits => 2^3 - 1 => 7 => 111 2. 8 bits => 2^8 - 1 => 255 3. 32 bits => 2^32 - 1 4. 64 bits => 2^64 - 1.

What is the largest decimal integer that can be represented with the.pdf

What is the largest decimal integer that can be represented with the.pdf

What is the largest decimal integer that can be represented with the.pdf

Throwing.java import java.util.InputMismatchException; import java.util.Scanner; public class Throwing { public static void main(String[] args) { try{ int n = getInt(); System.out.println(n); } catch(IllegalArgumentException e){ System.out.println(e.getMessage()); } } public static int getInt() { // your code goes here int n; try{ Scanner scan = new Scanner(System.in); System.out.println(\"Enter an integer: \"); n = scan.nextInt(); } catch(InputMismatchException e){ throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\"); } return n; } } Output: Enter an integer: s Invalid Input. Please enter an integer. Throwing.java import java.io.IOException; import java.util.InputMismatchException; import java.util.Scanner; public class Throwing { public static void main(String[] args) { try{ int n = getInt(); System.out.println(n); } catch(IOException e){ System.out.println(e.getMessage()); } } public static int getInt() throws IOException { // your code goes here int n; try{ Scanner scan = new Scanner(System.in); System.out.println(\"Enter an integer: \"); n = scan.nextInt(); } catch(InputMismatchException e){ throw new IOException(\"Invalid Input. Please enter an integer.\"); } return n; } } Output: Enter an integer: d Invalid Input. Please enter an integer. Solution Throwing.java import java.util.InputMismatchException; import java.util.Scanner; public class Throwing { public static void main(String[] args) { try{ int n = getInt(); System.out.println(n); } catch(IllegalArgumentException e){ System.out.println(e.getMessage()); } } public static int getInt() { // your code goes here int n; try{ Scanner scan = new Scanner(System.in); System.out.println(\"Enter an integer: \"); n = scan.nextInt(); } catch(InputMismatchException e){ throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\"); } return n; } } Output: Enter an integer: s Invalid Input. Please enter an integer. Throwing.java import java.io.IOException; import java.util.InputMismatchException; import java.util.Scanner; public class Throwing { public static void main(String[] args) { try{ int n = getInt(); System.out.println(n); } catch(IOException e){ System.out.println(e.getMessage()); } } public static int getInt() throws IOException { // your code goes here int n; try{ Scanner scan = new Scanner(System.in); System.out.println(\"Enter an integer: \"); n = scan.nextInt(); } catch(InputMismatchException e){ throw new IOException(\"Invalid Input. Please enter an integer.\"); } return n; } } Output: Enter an integer: d Invalid Input. Please enter an integer..

Throwing.javaimport java.util.InputMismatchException; import jav.pdf

Throwing.javaimport java.util.InputMismatchException; import jav.pdf

Throwing.javaimport java.util.InputMismatchException; import jav.pdf

This electron transport is accompanied by the protons transfer into intermembrane space. Protons release potential which drives the phosphorylation of ADP to ATP. Protons return to the matrix through a proton specific channel Solution This electron transport is accompanied by the protons transfer into intermembrane space. Protons release potential which drives the phosphorylation of ADP to ATP. Protons return to the matrix through a proton specific channel.

This electron transport is accompanied by the protons transfer into .pdf

This electron transport is accompanied by the protons transfer into .pdf

This electron transport is accompanied by the protons transfer into .pdf

In linear or non cyclic electron transport of photosynthesis NADPH a.pdf

In linear or non cyclic electron transport of photosynthesis NADPH a.pdf

In linear or non cyclic electron transport of photosynthesis NADPH a.pdf

The intrusion of biases is a very important issue in decision making because it introduces the conflic of interests between parties or stakeholders, when projects are to be undertaken. Both public and private policies have been influenced by biased positions in the past, and the concept of conflict of interests is set when biased positions intend to domain when final decisions are made. When public policy is to be decided, biased positions are taken from partisans influenced by particular interests, which is not the indend of public policy, but to benefit the people, the citizens of a nation, or a city, or a state. In public policy, identifying these biases is very important, specially for the ones who take the role of judges, who are responsible for driving ecnomic resources to be invested in projects that benefit the terrirotial entity, instead of particular interests. For instante, for a state, building a road apparently benefted its people, but if public resources are investo build a road that it is clear to benefit only a mining company because the road is close to one of its mines, but away from farmers and the rest of citizens of the state, it is clear that particular interests are domaining over the public intend of the invested resources. So as to avoid conflicts of interests, it is very important to know parties betting on a public project, how they try to drive it, because each party would try to benefitiate its own interests, and the best strategy to make public resources to be invested for the good intend of everybody, these parts have to be interacting when the project is being debated, and all of them must speak up their minds, with no restriction, let them be companies and people, espeacially the interaction of competing companies is desicive in making a project the less biased possible. The particular interests of all of the parties debating on a public project, and its clearifying before the other parties, is the best judge that could ever work by itself when public projects are to be decided. For instance, politicians indend to benefitiate people who vote for them, but people who does not vote should be benefitiated too, therefore, other competing politians would get this intentions naked before the public, and therefore, oposing forces to this intend would appear so as to balance the general benefits of public projects, making a debate less and less biased. But inside private companies we use to find biases too. For instance, when the marketing and sales department wants more resources, even overpassing the interests of the manufacturing marketing, a biase is obvserved clearly. This kind of biase really is against the firm itself, for the manufacturing department needs enough resources to guarantee good quality products, and therefore, the market and sales department can be able to expand the company\'s market, which would be hard to do with low quality products caused by low resources. References: Moore, Don et. al. (2010.

The intrusion of biases is a very important issue in decision making.pdf

The intrusion of biases is a very important issue in decision making.pdf

The intrusion of biases is a very important issue in decision making.pdf

The bond issuance will got influenced by following risks : a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing. b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa. c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond. d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease the current market value of the bond which could result in a partial or total loss of an investment. e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa. f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will come from higher coupon and/or short maturities taken by the investor. On the adverse, the situation would be vise-versa. g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment. ============= Solution The bond issuance will got influenced by following risks : a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing. b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa. c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond. d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease the current market value of the bond which could result in a partial or total loss of an investment. e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa. f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will come from higher coupon and/or short maturities taken by the investor. On the adverse, the situation would be vise-versa. g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment. =============.

The bond issuance will got influenced by following risks a) Infla.pdf

The bond issuance will got influenced by following risks a) Infla.pdf

The bond issuance will got influenced by following risks a) Infla.pdf

Sorts of SQL Statements The rundowns in the accompanying segments give an utilitarian outline of SQL proclamations and are isolated into these classes: Information Definition Language (DDL) Statements Information Manipulation Language (DML) Statements Exchange Control Statements Session Control Statements Framework Control Statement Inserted SQL Statements Information Definition Language (DDL) Statements Information definition dialect (DDL) articulations let you to play out these errands: Make, change, and drop mapping objects Give and renounce benefits and parts Break down data on a table, file, or group Build up examining alternatives Add remarks to the information lexicon The CREATE, ALTER, and DROP orders require select access to the predefined object. For instance, an ALTER TABLE articulation comes up short if another client has an open exchange on the predefined table. The GRANT, REVOKE, ANALYZE, AUDIT, and COMMENT summons don\'t require elite access to the predetermined item. For instance, you can break down a table while different clients are redesigning the table. Prophet Database verifiably submits the present exchange previously, then after the fact each DDL explanation. Numerous DDL articulations may make Oracle Database recompile or reauthorize diagram objects. For data on how Oracle Database recompiles and reauthorizes outline objects and the conditions under which a DDL proclamation would precipitate this, see Oracle Database Concepts. DDL explanations are upheld by PL/SQL with the utilization of the DBMS_SQL bundle. See Also: PL/SQL Packages and Types Reference The DDL explanations are: Adjust ... (All announcements starting with ALTER) Examine Partner STATISTICS Review Remark Make ... (All announcements starting with CREATE) DISASSOCIATE STATISTICS DROP ... (All announcements starting with DROP) FLASHBACK ... (All announcements starting with FLASHBACK) Stipend NOAUDIT Cleanse RENAME Repudiate TRUNCATE Information Manipulation Language (DML) Statements Information control dialect (DML) explanations get to and control information in existing mapping objects. These announcements don\'t verifiably confer the present exchange. The information control dialect articulations are: CALL Erase Clarify PLAN Embed LOCK TABLE Blend SELECT Redesign The SELECT articulation is a constrained type of DML explanation in that it can just get to information in the database. It can\'t control information in the database, despite the fact that it can work on the got to information before giving back the aftereffects of the question. The CALL and EXPLAIN PLAN proclamations are upheld in PL/SQL just when executed progressively. All other DML articulations are completely bolstered in PL/SQL. Exchange Control Statements Exchange control proclamations oversee changes put forth by DML expressions. The exchange control explanations are: Submit ROLLBACK SAVEPOINT SET TRANSACTION All exchange control proclamations, aside from specific types of the COMMIT and.

Sorts of SQL StatementsThe rundowns in the accompanying segments g.pdf

Sorts of SQL StatementsThe rundowns in the accompanying segments g.pdf

Sorts of SQL StatementsThe rundowns in the accompanying segments g.pdf

Remediation (Clean Up) of the Bhopal Plant Site Status of the Former UCIL Plant Site The Bhopal plant closed after the 1984 methylisocyanate (MIC) gas release and never resumed normal operations. While the Bhopal gas release litigation was in progress, no steps could be taken to remediate the site because the MIC unit was considered by the Central Bureau of Investigation (CBI) as “evidence” in the criminal case. All activity at the site was closely monitored and controlled by the CBI, the Indian courts and the Madhya Pradesh Pollution Control Board (MPPCB). UCIL was finally permitted to undertake clean-up work in the years just prior to the sale of its stock by UCC in 1994, and spent some $2 million on that effort, which included beginning construction of a secure landfill to hold the wastes from two on-site solar evaporation ponds. The central and state government authorities approved, monitored and directed every step of the clean-up work. Following the sale, it appears that UCIL, now renamed Eveready Industries India Limited (EIIL), continued some clean-up work and completed the construction of the secure landfill on the site. In 1998, the Madhya Pradesh State Government (MPSG), which owned and had been leasing the property to EIIL, cancelled the lease; took over the facility; and assumed all accountability for the site, including the completion of any additional remediation According to media reports, court-ordered remediation efforts directed at the government entities have proceeded slowly. Furthermore, proposals made by private companies have similarly been questioned or rejected. For example, non-governmental organizations (NGOs) protested against and blocked remediation attempts by those who offered to help raise funds for clean up or to conduct pro-bono remediation. The disposal of the waste has consistently proved to be a non- starter, and was further hindered after a Public Interest Litigation (PIL) was filed in the Madhya Pradesh High Court in 2004. (UCC is not involved in that litigation.) The media reported in 2007 that the Supreme Court of India had directed the central and state governments to pay for collection of waste on the site and to have it landfilled or incinerated, as appropriate. While some of the waste had been landfilled, public interest groups again challenged the Court\'s incineration directive, as did the states where waste incineration facilities were located. However, in 2012, the Supreme Court selected the Pithampur waste treatment storage and disposal facility (TSDF) in Madhya Pradesh’s Dhar district as the most suitable facility for incinerating the waste. Though environmental NGOs claimed the facility failed to meet desired safety parameters, the Central Pollution Control Board (CPCB) submitted an affidavit in 2014 verifying the suitability of the facility to carry out the incineration. According to The Indian Express, 10 tons of trial waste were transferred to the site in July 2015 and the trial incinera.

Remediation (Clean Up) of the Bhopal Plant SiteStatus of the Forme.pdf

Remediation (Clean Up) of the Bhopal Plant SiteStatus of the Forme.pdf

Remediation (Clean Up) of the Bhopal Plant SiteStatus of the Forme.pdf

Rb, Na, As, Li here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct. the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct. now, Arsenic has the highest 1st ionization of all. So the answer is As. Solution Rb, Na, As, Li here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct. the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct. now, Arsenic has the highest 1st ionization of all. So the answer is As..

Rb, Na, As, Li here. Lithium only has 3 electrons...cant have .pdf

Rb, Na, As, Li here. Lithium only has 3 electrons...cant have .pdf

Rb, Na, As, Li here. Lithium only has 3 electrons...cant have .pdf

//operating system Linux,ubuntu,Mac #include #include #include #include /*Sum function implementation*/ int sum(int number1,int number2){ return number1+number2; } /*sub function implementation*/ int sub(int number1,int number2){ return number1-number2; } /*mul function implementation*/ int mul(int number1,int number2){ return number1*number2; } /*divide function implementation*/ float divide(int number1,int number2){ if(number2==0){ printf(\"We can not divide by 0 \ \"); return 0.0f; } return (float)(number1/number2); } char *substring(char *string, int position, int length) { char *pointer; int c; pointer = malloc(length+1); if (pointer == NULL) { printf(\"Unable to allocate memory.\ \"); exit(1); } for (c = 0 ; c < length ; c++) { *(pointer+c) = *(string+position-1); string++; } *(pointer+c) = \'\\0\'; return pointer; } /*Main Function start*/ int main(int argc, char *argv[]){ /*Variable declarations*/ int number1,number2; char *operator,*str1,*str2; char line[50]; char s[2] = \" \"; int errorFlag=0;// checking if user entered more then one operands while(1){ /*User input*/ printf(\"Please Enter the command \"); gets(line); int len=0; for(int i=0; line[i]!=\'\\0\'; ++i){len++;} if(len==0){ return 1; } /*Spliting into Tokens*/ operator = strtok(line, \" \"); if(strcmp(operator,\"bye\")==0){ break; } /*String to integer --- token1*/ number1=atoi(strtok(NULL, s)); /*Removing ( and ) from String*/ str2=strtok(NULL, s); char *content;int length=0; for(int i=0; str2[i]!=\'\\0\'; ++i){length++;} if(str2[0]==\'(\'){ content=substring(str2,2,length-1); char *opr=content; int n1=atoi(strtok(NULL, s)); int n2=atoi(strtok(NULL, s)); /*If user entered more then two operands then it will return some token otherwise it will return NULL pointer*/ if(strtok(NULL, s)!=NULL){ printf(\"You need to enter operator operand1 operand2 \ \"); errorFlag=1; }else{ if(strcmp(opr,\"sum\")==0){ number2=sum(n1,n2); }else if(strcmp(opr,\"sub\")==0){ number2=sub(n1,n2); }else if(strcmp(opr,\"mul\")==0){ number2=mul(n1,n2); } else if(strcmp(opr,\"div\")==0){ number2=divide(n1,n2); } } }else{ number2=atoi(str2); /*If user entered more then two operands then it will return some token otherwise it will return NULL pointer*/ if(strtok(NULL, s)!=NULL){ printf(\"You need to enter operator operand1 operand2 \ \"); errorFlag=1; } } if(errorFlag!=1){ /*Checking operator by strcmp function*/ if(strcmp(operator,\"sum\")==0){ printf(\"Result %d \ \",sum(number1,number2)); }else if(strcmp(operator,\"sub\")==0){ printf(\"Result %d \ \",sub(number1,number2)); }else if(strcmp(operator,\"mul\")==0){ printf(\"Result %d \ \",mul(number1,number2)); } else if(strcmp(operator,\"div\")==0){ printf(\"Result %.2f \ \",divide(number1,number2)); } } } return 0; } /********************output************************/ gopal@gopal:~/Desktop/chegg$ gcc Calculator.c Calculator.c: In function ‘main’: Calculator.c:67:3: warning: implicit declaration of function ‘gets’ [-Wimplicit-function- declaration] gets(.

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Network security architecture is the planning and design of the campus network to reduce security risks in accordance with the institution’s risk analysis and security policies. It focuses on reduc-ing security risks and enforcing policy through the design and con-figuration of firewalls, routers, and other network equipment. Network security is important because it is one of the means to enforce the policies and procedures developed by the institution to protect information. It is often referred to as the “front door” in broader discussions of IT security. To the extent that you can block network access to a computer, you “lock” the door and provide bet-ter protection for that computer and its contents. Traditional network design has focused on creating a secure net-work perimeter around the organization and strategically placing a firewall at the point where the network is connected to the Inter-net. For higher education, this traditional design is problematic; our constituents need access from off campus to a large number of machines and services on campus. In addition, because we have many computers on our campus that we cannot implicitly trust, we also must be concerned about security threats from inside the perimeter protected by a traditional firewall. These design issues require a different approach to network security. Although it is impossible to do justice to the topic of network design in a few pages, there are some best practices that I feel universities should focus on in terms of network design. Step 1: Eliminate Network Components That Still UseShared Ethernet Shared Ethernet switches (or hubs) were developed more than a decade ago to interconnect multiple computers and networks. These hubs retransmit all network traffic to all computers connected to that hub. The security implication is that if one computer has its security compromised it can be used to monitor network traffic com-ing from any other computer that shares the same hub. This could expose passwords and other sensitive information. Today, switched Ethernet, which isolates traffic intended for one computer from the view of others on the same switch, is very inexpensive and, hence, it is worth the cost of replacing older hubs. Step 2: Embrace and Implement the Concept of Defense and Use Multiple Firewalls Within Your Network Commercial and Linux-based firewalls are inexpensive enough that you can deploy these in multiple locations as needed. It is still bene-ficial to have a firewall separating your institutional network from the connection to the Internet. This firewall, called a border firewall, will provide a minimal level of protection for all computers on your net-work. The major benefit of this firewall is that it allows your network and security staff to quickly block external access should a threat arise, such as when the “SQL worm” was launched in January 2003 In addition to the border firewall, consider adding internal firewalls to protect areas that requi.

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Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen proportionally than carbohydrates Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these essential components, certain other elements like phosphorus and nitrogen may be present. Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy ketones, or change to such substances on simple chemical transformations, as hydrolysis, oxidation, or reduction, and that form the supporting tissues of plants and are important food for animals and people. All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many hydrogen atoms as oxygen atoms Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA, whose molecules consist of many nucleotides linked in a long chain. It is composed of a nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid. Solution Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen proportionally than carbohydrates Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these essential components, certain other elements like phosphorus and nitrogen may be present. Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy ketones, or change to such substances on simple chemical transformations, as hydrolysis, oxidation, or reduction, and that form the supporting tissues of plants and are important food for animals and people. All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many hydrogen atoms as oxygen atoms Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA, whose molecules consist of many nucleotides linked in a long chain. It is composed of a nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid..

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