a) mean = 1.43Thus distribution is Poisson(4.2)P(X = 4) = 4.2^4.pdf
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a) mean = 1.4*3 Thus distribution is Poisson(4.2) P(X = 4) = 4.2^4 * e^{-4.2} / 4! = 0.1944 b) average number of ghosts in 90min (1.5hrs) interval = 1.4*1.5 = 2.1 c) Probability that 4th ghost will appear before 10 am = Probability that number of ghosts appearing from 8 to 10 am >= 4 As it is a 2 hr period, the distribution of number of ghosts is Poisson(1.4*2) i.e Poisson(2.8) P(X >= 4) = 1 - P(X < 4) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)] = 1 - [(2.8^0 * e^{-2.8} / 0!) + (2.8^1 * e^{-2.8} / 1!) + (2.8^2 * e^{-2.8} / 2!) + (2.8^3 * e^{- 2.8} / 3!)] = 1 - [0.0608 + 0.1703 + 0.2384 + 0.2225] = 0.692 d) When arrival distribution is Poisson(lambda), inter-arrival time distribution is Exponential(lambda) Thus, interarrival time distribution is Exponential(1.4) Expected value of time between 5th and 6th ghost = 1/1.4 = 0.7143hr e) On average time taken for 10th ghost to arrive = 10*(1/1.4) = 7.143hr Thus on an average, 10th ghost will arrive at 3:09pm f) Expected value of time between ghost appearances = 1/1.4 = 0.7143hr (see part d) g) Probability that 3rd ghost appears after 9:45 am = Probablity that number of ghosts appearing till 9:45 am < 3 Duration from 8am to 9:45 am = 1.75hr Mean number of ghosts = 1.4*1.75 = 2.45 Thus X is Poisson(2.45) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = (2.45^0 * e^{-2.45} / 0!) + (2.45^1 * e^{-2.45} / 1!) + (2.45^2 * e^{-2.45} / 2!) = 0.0863 + 0.2114 + 0.2590 = 0.5567 h) As inter-arrival time is Exponential(1.4), inter-arrival time is memoryless Thus, time for 7th ghost will be calculated from 1:00 pm and not from 12:35pm due to memorylessness property. Time duration from 1:00pm to 1:15pm = 0.25hrs Let Y be random variable denoting inter-arrival time probability that the 7th ghost will appear before 1:15 p.m. = P(Y < 0.25) = 1 - e^{-1.4 * 0.25) = 0.2953 i) Expected value of time for 7th ghost to appear after 1:00pm = 1/1.4 = 0.7143hr = 42.86 min Time from 12:35pm to 1:00pm = 25min Thus expected interarrival time = 25 + 42.86 = 67.86 min = 1hr 7.86min j) Expected duration after 1:00pm for 9th ghost to appear = 3 * (1/1.4) = 2.143hr = 2hr 8.58min Thus expected time at which 9th ghost appears = 3:09pm k) As the inter-arrival time follows memorylessness property, the future probabilities do not change with the observed value at past. Thus, 4 ghosts appearing between 7:00pm to 10:00pm does not affect ghost appearance from 11:00pm to 11:30pm Duration from 11:00pm to 11:30pm = 0.5hrs mean number of ghosts = 1.4*0.5 = 0.7 Thus it follows Poisson(0.7) distribution P(X > 2) = 1 - P(X <= 2) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)] = 1 - [(0.7^0 * e^{-0.7} / 0!) + (0.7^1 * e^{-0.7} / 1!) + (0.7^2 * e^{-0.7} / 2!)] = 1 - [0.4966 + 0.3476 + 0.1217] = 0.0341 l) Probability that 8 ghosts appear between 6pm and midnight = Probability that number of ghosts appear from 6pm to 7pm and 10pm to midnight = 4 as it is known that 4 ghosts appeared from 7pm to 10pm Let A denote number of ghost from 6pm to 7pm B denote number of ghosts .
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![a) mean = 1.4*3
Thus distribution is Poisson(4.2)
P(X = 4) = 4.2^4 * e^{-4.2} / 4! = 0.1944
b)
average number of ghosts in 90min (1.5hrs) interval = 1.4*1.5 = 2.1
c)
Probability that 4th ghost will appear before 10 am
= Probability that number of ghosts appearing from 8 to 10 am >= 4
As it is a 2 hr period, the distribution of number of ghosts is Poisson(1.4*2) i.e Poisson(2.8)
P(X >= 4)
= 1 - P(X < 4)
= 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)]
= 1 - [(2.8^0 * e^{-2.8} / 0!) + (2.8^1 * e^{-2.8} / 1!) + (2.8^2 * e^{-2.8} / 2!) + (2.8^3 * e^{-
2.8} / 3!)]
= 1 - [0.0608 + 0.1703 + 0.2384 + 0.2225]
= 0.692
d)
When arrival distribution is Poisson(lambda), inter-arrival time distribution is
Exponential(lambda)
Thus, interarrival time distribution is Exponential(1.4)
Expected value of time between 5th and 6th ghost = 1/1.4 = 0.7143hr
e)
On average time taken for 10th ghost to arrive = 10*(1/1.4) = 7.143hr
Thus on an average, 10th ghost will arrive at 3:09pm](https://image.slidesharecdn.com/amean1-230628084047-96aefb32/85/a-mean-1-43Thus-distribution-is-Poisson-4-2-P-X-4-4-2-4-pdf-1-320.jpg)
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acid, Carbonic acid is not stable in normal body temperatures, therefore, it ionizes into
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increase. Therefore, the concentration of hydronium ions increase during hypoventilation.
The stress concentration or partial pressure of CO2 during hypoventilation is significantly higher
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The breathing rate is more than normal. Therefore, as a result of heavier and faster breathing, the
CO2 concentration in the blood rapidly decreases, that is, CO2 easily leaves the blood plasma.
Decrease in the CO2 concentration slows down the rate of the forward reaction, reducing the
levels at which bicarbonate ion and H+ ion concentration were being generated. The bicarbonate
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concentration consequently lowers the pH (alkaline pH). This can lead to alkalosis.
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The concentration of H3O+ decreases during hyperventilation, since the H+ ion concentration is
lowered.
The stress levels or partial pressure of CO2 during hyperventilation is significantly lower than 40
mmHg (around 25-30 mmHg).
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carbonate would react with water and it would hydrolyse into Na+ and CO32- ions. The CO32-
combine with the hydrogen (H) present in water to form H2CO3 (carbon.
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2.
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exact opposite of each other. Thus, the two magnetic fields cancel each other out. They also
cancel out any outside magnetic fields. Twisting the wires can enhance this cancellation effect.
Using cancellation together with twisting the wires, cable designers can effectively provide self-
shielding for wire pairs within the network media.
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UTP cable relies solely on the cancellation effect produced by the twisted wire pairs to limit
signal degradation caused by electromagnetic interference (EMI) and radio frequency
interference (RFI). To further reduce crosstalk between the pairs in UTP cable, the number of
twists in the wire pairs varies. UTP cable must follow precise specifications governing how
many twists or braids are permitted per meter (3.28 feet) of cable.
UTP cable often is installed using a Registered Jack 45 (RJ-45) connector The RJ-45 is an eight-
wire connector used commonly to connect computers onto a local-area network (LAN),
especially Ethernets.
When used as a networking medium, UTP cable has four pairs of either 22- or 24-gauge copper
wire. UTP used as a networking medium has an impedance of 100 ohms; this differentiates it
from other types of twisted-pair wiring such as that used for telephone wiring, which has
impedance of 600 ohms.
UTP cable offers many advantages. Because UTP has an external diameter of approximately
0.43 cm (0.17 inches), its small size can be advantageous during installation. Because it has such
a small external diameter, UTP does not fill up wiring ducts as rapidly as other types of cable.
This can be an extremely important factor to consider, particularly when installing a network in
an older building. UTP cable is easy to install and is less expensive than other types of
networking media. In fact, UTP costs less per meter than any other type of LAN cabling. And
because UTP can be used with most of the major networking architectures, it continues to grow
in popularity.
Disadvantages also are involved in using twisted-pair cabling, howe.
A person may not choose to participate in the labour force due to La.pdf
A person may not choose to participate in the labour force due to Laziness, lack of ambition,
emotional or chemical imbalance, independent wealth, personal unavailability, or other priorities.
However, race, location, education, and marital status are irrelevant at times. They do affect the
type of job, or their availability, but not the individual\'s desire to have one. Choosing to stay
home and raise children is an example of different priorities, and a spouse\'s income, if they are
wealthy enough, may negate having to even make a choice.
(a) with low education, a job might not pay much more than unemployment benefit.
(b) with children, there is strong incentive to stay at home and take care of them.
(c) with one spouse earning a lot, another spouse can stay at home.
(d) if person belongs to a race with bad reputation, they are less likely to get hired. But at times
women are viewed as better workers than men from same race.
(e) in rural areas, there are fewer jobs, and the commute to them is longer and therefore they
prefer to do some small work nearby or choose not to work at all.
Solution
A person may not choose to participate in the labour force due to Laziness, lack of ambition,
emotional or chemical imbalance, independent wealth, personal unavailability, or other priorities.
However, race, location, education, and marital status are irrelevant at times. They do affect the
type of job, or their availability, but not the individual\'s desire to have one. Choosing to stay
home and raise children is an example of different priorities, and a spouse\'s income, if they are
wealthy enough, may negate having to even make a choice.
(a) with low education, a job might not pay much more than unemployment benefit.
(b) with children, there is strong incentive to stay at home and take care of them.
(c) with one spouse earning a lot, another spouse can stay at home.
(d) if person belongs to a race with bad reputation, they are less likely to get hired. But at times
women are viewed as better workers than men from same race.
(e) in rural areas, there are fewer jobs, and the commute to them is longer and therefore they
prefer to do some small work nearby or choose not to work at all..
Well.. 1) Ionic bonds are almost always metal to .pdf
Well.. 1) Ionic bonds are almost always metal to non-metal. (opposing charges
attract). 2) Covalent, electron-sharing. \"co\"-valent. Valent referring to the valence electrons of
the element, that is, the electrons in outer most shell. Remember each element wants to reach a
more stable state. To achieve this it will share electrons with another element through covalent
bonds. 3) a covalent bond is said to be polar if one of the elements sharing the electrons has a
greater electronegativity. (i.e. water contains polar covalent bonds between the oxygen and the
hydrogens because oxygen is far more electronegative than hydrogen, therefore it \"hogs\" the
electrons. 4) non-polar covalent bonds have an equal sharing of the electrons, equal
electronegativity. Hope this helps!
Solution
Well.. 1) Ionic bonds are almost always metal to non-metal. (opposing charges
attract). 2) Covalent, electron-sharing. \"co\"-valent. Valent referring to the valence electrons of
the element, that is, the electrons in outer most shell. Remember each element wants to reach a
more stable state. To achieve this it will share electrons with another element through covalent
bonds. 3) a covalent bond is said to be polar if one of the elements sharing the electrons has a
greater electronegativity. (i.e. water contains polar covalent bonds between the oxygen and the
hydrogens because oxygen is far more electronegative than hydrogen, therefore it \"hogs\" the
electrons. 4) non-polar covalent bonds have an equal sharing of the electrons, equal
electronegativity. Hope this helps!.
1. The answer is d) Environmental EffectsEnvironmental effects ca.pdf
1. The answer is: d) Environmental Effects
Environmental effects can cause a single genotype to produce a range of potential Phenotypes.
2. The answer is: c) Differ in both mean and variance
The Figure represents two distributions that differ in both mean and variance.
Solution
1. The answer is: d) Environmental Effects
Environmental effects can cause a single genotype to produce a range of potential Phenotypes.
2. The answer is: c) Differ in both mean and variance
The Figure represents two distributions that differ in both mean and variance..
clear clc close all Use polyfit to solve for the phase l.pdf
clear
clc
close all
%Use polyfit to solve for the phase lines
point11=[0,15];
point12=[0,300];
line1=polyfit(point11,point12,1);
m1=line1(1);
b1=line1(2);
xpf1=linspace(min(point11),max(point11),100);
ypf1=m1*xpf1+b1;
point21=[0,15];
point22=[700,300];
line2=polyfit(point21,point22,1);
m2=line2(1);
b2=line2(2);
xpf2=linspace(min(point21),max(point21),100);
ypf2=m2*xpf2+b2;
point31=[0,50];
point32=[700,300];
line3=polyfit(point31,point32,1);
m3=line3(1);
b3=line3(2);
xpf3=linspace(min(point31),max(point31),100);
ypf3=m3*xpf3+b3;
point41=[50,100];
point42=[300,800];
line4=polyfit(point41,point42,1);
m4=line4(1);
b4=line4(2);
xpf4=linspace(min(point41),max(point41),100);
ypf4=m4*xpf4+b4;
point51=[100,85];
point52=[800,300];
line5=polyfit(point51,point52,1);
m5=line5(1);
b5=line5(2);
xpf5=linspace(min(point51),max(point51),100);
ypf5=m5*xpf5+b5;
point61=[85,100];
point62=[300,0];
line6=polyfit(point61,point62,1);
m6=line6(1);
b6=line6(2);
xpf6=linspace(min(point61),max(point61),100);
ypf6=m6*xpf6+b6;
point71=[15,85];
point72=[300,300];
%Allow the user to set the percent of B
b=input(\'Enter the mass percent of B: \');
%Return an error if the percent of B is not a valid number
if b<0 || b>100
error(\'Please enter a value between 0 and 100.\')
end
%Allow the user to set the temperature
t=input(\'Enter the temperature [deg C]: \');
%Solve for percent composition of A
a=100-b;
%Determine phase based on temperature and percent composition of B using
%the phase lines
if t<300
if b<15 && t>m1*b+b1
phase=\'alpha\';
elseif b<15 && t=15 && b<=85
phase=\'alpha + beta\';
elseif b>85 && t>m6*b+b6
phase=\'beta\';
else phase=\'alpha + beta\';
end
elseif b<15
if t=15 && b<=50
if t50 && b<=85
if t=15 && b<=85 && t==300
fprintf(\'The provided conditions fall on the eutectic line.\ \')
end
if b==50 && t==300
fprintf(\'The provided conditions fall on the eutectic point.\ \')
end
%Output a formatted statement to display the phase
fprintf(\'For the composition of %0.2f%% A, %0.2f%% B and a temperature of %0.0f degrees
Celsius, the phase is %s.\ \',a,b,t,phase)
%Create a plot of the phase lines and the user\'s set point
figure(\'color\',\'white\')
%Set axes
axis([0 100 0 1000])
%Plot the phase lines, eutectic line, eutectic point, and the user\'s point
plot(xpf1,ypf1,\'-b\')
hold on
plot(xpf2,ypf2,\'-b\')
plot(xpf3,ypf3,\'-b\')
plot(xpf4,ypf4,\'-b\')
plot(xpf5,ypf5,\'-b\')
plot(xpf6,ypf6,\'-b\')
plot(point71,point72,\'-k\')
plot(b,t,\'ro\',\'MarkerFaceColor\',\'r\')
%Assign a title and axes labels
title(\'Phase Diagram of Elements A and B\')
xlabel(\'Percent Composition of B\')
ylabel(\'Temperature (T) [deg C]\')
%Set scaling for the axes
set(gca,\'XTick\',0:10:100,\'YTick\',0:100:1000)
%Place the phase names on the graph
text(40,200,\'alpha+beta\')
text(45,600,\'Liquid\')
text(90,300,\'beta\')
text(3,300,\'alpha\')
text(15,375,\'alpha + Liquid\')
text(62,375,\'beta + Liquid\')
Solution
clear
clc
close all
%Use polyfit to solve for the phase lines
point11=[0,15];
point.
The oxygen appears in both step reactions. But, i.pdf
The oxygen appears in both step reactions. But, it would not appear in the final
reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction
is 2O3 ====> 3 O2 (No O)
Solution
The oxygen appears in both step reactions. But, it would not appear in the final
reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction
is 2O3 ====> 3 O2 (No O).
PART A The element Si belongs to IVA group. Therefore, four electro.pdf
PART A: The element Si belongs to IVA group. Therefore, four electrons present in the
outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The
s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the
number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs
to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D:
All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons.
PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present
after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is
[Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons
present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The
element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell.
Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital
and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal.
PART I: The element Ba belongs to IIA group. Therefore, two electrons present in the s-orbital.
Hence the condensed electron configuration of Ba is [Xe] 6s2. PART J: The outermost s-
electron is completely filled. Therefore, there are no unpaired electrons present in Ba metal.
PART K: The element Tl belongs to IIIA group. Therefore, the condensed electron configuration
of Tl is [Xe] 4f14 5d10 6s2 6p1. PART L: The all orbitals are filled with electrons except Tl.
Therefore, the number of unpaired electrons is 1
Solution
PART A: The element Si belongs to IVA group. Therefore, four electrons present in the
outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The
s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the
number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs
to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D:
All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons.
PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present
after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is
[Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons
present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The
element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell.
Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital
and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal.
PART I: The element Ba belongs to IIA group. Th.
The two contributions to the cohesive energy of t.pdf
The two contributions to the cohesive energy of the ionic crystal are : Vander waals
attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero-
point energy is the lowest possible energy that a quantum mechanical physical system may have;
it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in
their ground state and have an associated zero-point energy, a consequence of their wave-like
interaction.
Solution
The two contributions to the cohesive energy of the ionic crystal are : Vander waals
attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero-
point energy is the lowest possible energy that a quantum mechanical physical system may have;
it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in
their ground state and have an associated zero-point energy, a consequence of their wave-like
interaction..
If you are talking about an extraction design, th.pdf
If you are talking about an extraction design, the the water solubility has to be
greater in the aqueous base because of the greater solubility of the salts of the acids (with few
exceptions), again presuming a differential extraction aqueous to organic.
Solution
If you are talking about an extraction design, the the water solubility has to be
greater in the aqueous base because of the greater solubility of the salts of the acids (with few
exceptions), again presuming a differential extraction aqueous to organic..
Yes ,its true. Though both gibbons and rhesus monkeys belong to pr.pdf
Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens.
Solution
Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens..
When something boils, it changes states of matter. It would go from .pdf
When something boils, it changes states of matter. It would go from a liquid to a soild when it
boils, so if more heat is added, it will just change the state of matter faster.
Solution
When something boils, it changes states of matter. It would go from a liquid to a soild when it
boils, so if more heat is added, it will just change the state of matter faster..
We need to discuss why there is an importance of adding residents to.pdf
We need to discuss why there is an importance of adding residents to the budget planning, we
can go through below explaintion and can derived various conclusions from the same.
In explaining why they did or did not seek input from citizens, respondents in- dicated that the
process was guided by the desires of the leadership. Of those who said that they did seek citizen
input, the desire (as opposed to the obligation through policy) of the staff or the govern- ing
board or staff to seek public opinion seemed to provide some motivation. Almost three-quarters
of responding cities cited staff desire, and almost two-thirds, governing board desire.
The pattern for counties was similar. The most often cited reason for extra effort to involve the
public was board interest. Almost half of the counties also cited staff interest.
Although citizen involvement is a hot topic in management literature these days, local
governments in North Caro- lina are generally not making extensive fforts to involve residents in
budgeting. Barely half of the cities responding to the survey and less than a third of the coun- ties
go beyond the single, mandated hearing to get citizen input In general, cities tend to seek input
more than counties do. This result might be explained by the different types of services offered
by the two forms of gov- ernment. Counties provide funding for, among other things, social
services, pub- lic health services, mental health ser- vices, and schools, and the boards over-
seeing these services may seek citizen input when they are preparing their own budget request
for the county.
Although there is informal interest in hearing from citizens, boards clearly want to remain
flexible in when and how they obtain input. Only 13 percent of the city respondents had a formal
pol- icy or requirement for citizen involve- ment beyond the single, state-mandated hearing.
Medium to large cities were more likely to have such requirements than small cities. Only one
county, a larger one, reported having such a policy or requirement.
Although citizen involvement is a hot topic in management literature these days, local
governments in North Caro- lina are generally not making extensive
efforts to involve residents in budgeting. Barely half of the cities responding to the survey and
less than a third of the coun- ties go beyond the single, mandated hearing to get citizen input
Of those that did not seek extra citizen involvement, the most common reason cited, on both the
city and the county level, was lack of governing board inter- est. The second most common
reason was poor response in the past, when at- tempts to get citizens involved did not seem very
effective. At the county level, lack of board interest was a far more important factor than
anything else, including poor past response: 71 percent of respondents cited lack of board
interest, whereas only 39 percent cited poor past response Although staff interest seemed to be a
big motivator for involving ci.
What is the largest decimal integer that can be represented with the.pdf
What is the largest decimal integer that can be represented with the following number of bits?
1. 3 bits
2. 8 bits
3. 32 bits
4. 64 bits
How do you find out the largest decimal integer?
Solution
In general, with k bits we can represent 2k values. Their range will depend on the system:
Unsigned: 0 to 2k-1
1. 3 bits
=> 2^3 - 1 => 7 => 111
2. 8 bits
=> 2^8 - 1 => 255
3. 32 bits
=> 2^32 - 1
4. 64 bits
=> 2^64 - 1.
Throwing.javaimport java.util.InputMismatchException; import jav.pdf
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer.
Solution
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer..
This electron transport is accompanied by the protons transfer into .pdf
This electron transport is accompanied by the protons transfer into intermembrane space.
Protons release potential which drives the phosphorylation of ADP to ATP.
Protons return to the matrix through a proton specific channel
Solution
This electron transport is accompanied by the protons transfer into intermembrane space.
Protons release potential which drives the phosphorylation of ADP to ATP.
Protons return to the matrix through a proton specific channel.
In linear or non cyclic electron transport of photosynthesis NADPH a.pdf
In linear or non cyclic electron transport of photosynthesis NADPH and ATP are produced.
These molecules are then used for reduction during dark reaction.
Solution
In linear or non cyclic electron transport of photosynthesis NADPH and ATP are produced.
These molecules are then used for reduction during dark reaction..
The intrusion of biases is a very important issue in decision making.pdf
The intrusion of biases is a very important issue in decision making because it introduces the
conflic of interests between parties or stakeholders, when projects are to be undertaken. Both
public and private policies have been influenced by biased positions in the past, and the concept
of conflict of interests is set when biased positions intend to domain when final decisions are
made.
When public policy is to be decided, biased positions are taken from partisans influenced by
particular interests, which is not the indend of public policy, but to benefit the people, the
citizens of a nation, or a city, or a state. In public policy, identifying these biases is very
important, specially for the ones who take the role of judges, who are responsible for driving
ecnomic resources to be invested in projects that benefit the terrirotial entity, instead of particular
interests.
For instante, for a state, building a road apparently benefted its people, but if public resources are
investo build a road that it is clear to benefit only a mining company because the road is close to
one of its mines, but away from farmers and the rest of citizens of the state, it is clear that
particular interests are domaining over the public intend of the invested resources.
So as to avoid conflicts of interests, it is very important to know parties betting on a public
project, how they try to drive it, because each party would try to benefitiate its own interests, and
the best strategy to make public resources to be invested for the good intend of everybody, these
parts have to be interacting when the project is being debated, and all of them must speak up
their minds, with no restriction, let them be companies and people, espeacially the interaction of
competing companies is desicive in making a project the less biased possible. The particular
interests of all of the parties debating on a public project, and its clearifying before the other
parties, is the best judge that could ever work by itself when public projects are to be decided.
For instance, politicians indend to benefitiate people who vote for them, but people who does not
vote should be benefitiated too, therefore, other competing politians would get this intentions
naked before the public, and therefore, oposing forces to this intend would appear so as to
balance the general benefits of public projects, making a debate less and less biased.
But inside private companies we use to find biases too. For instance, when the marketing and
sales department wants more resources, even overpassing the interests of the manufacturing
marketing, a biase is obvserved clearly. This kind of biase really is against the firm itself, for the
manufacturing department needs enough resources to guarantee good quality products, and
therefore, the market and sales department can be able to expand the company\'s market, which
would be hard to do with low quality products caused by low resources.
References:
Moore, Don et. al. (2010.
The bond issuance will got influenced by following risks a) Infla.pdf
The bond issuance will got influenced by following risks :
a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing.
b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa.
c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond.
d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease
the current market value of the bond which could result in a partial or total loss of an investment.
e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted
accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa.
f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will
come from higher coupon and/or short maturities taken by the investor. On the adverse, the
situation would be vise-versa.
g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the
investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment.
=============
Solution
The bond issuance will got influenced by following risks :
a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing.
b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa.
c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond.
d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease
the current market value of the bond which could result in a partial or total loss of an investment.
e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted
accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa.
f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will
come from higher coupon and/or short maturities taken by the investor. On the adverse, the
situation would be vise-versa.
g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the
investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment.
=============.
Sorts of SQL StatementsThe rundowns in the accompanying segments g.pdf
Sorts of SQL Statements
The rundowns in the accompanying segments give an utilitarian outline of SQL proclamations
and are isolated into these classes:
Information Definition Language (DDL) Statements
Information Manipulation Language (DML) Statements
Exchange Control Statements
Session Control Statements
Framework Control Statement
Inserted SQL Statements
Information Definition Language (DDL) Statements
Information definition dialect (DDL) articulations let you to play out these errands:
Make, change, and drop mapping objects
Give and renounce benefits and parts
Break down data on a table, file, or group
Build up examining alternatives
Add remarks to the information lexicon
The CREATE, ALTER, and DROP orders require select access to the predefined object. For
instance, an ALTER TABLE articulation comes up short if another client has an open exchange
on the predefined table.
The GRANT, REVOKE, ANALYZE, AUDIT, and COMMENT summons don\'t require elite
access to the predetermined item. For instance, you can break down a table while different
clients are redesigning the table.
Prophet Database verifiably submits the present exchange previously, then after the fact each
DDL explanation.
Numerous DDL articulations may make Oracle Database recompile or reauthorize diagram
objects. For data on how Oracle Database recompiles and reauthorizes outline objects and the
conditions under which a DDL proclamation would precipitate this, see Oracle Database
Concepts.
DDL explanations are upheld by PL/SQL with the utilization of the DBMS_SQL bundle.
See Also:
PL/SQL Packages and Types Reference
The DDL explanations are:
Adjust ... (All announcements starting with ALTER)
Examine
Partner STATISTICS
Review
Remark
Make ... (All announcements starting with CREATE)
DISASSOCIATE STATISTICS
DROP ... (All announcements starting with DROP)
FLASHBACK ... (All announcements starting with FLASHBACK)
Stipend
NOAUDIT
Cleanse
RENAME
Repudiate
TRUNCATE
Information Manipulation Language (DML) Statements
Information control dialect (DML) explanations get to and control information in existing
mapping objects. These announcements don\'t verifiably confer the present exchange. The
information control dialect articulations are:
CALL
Erase
Clarify PLAN
Embed
LOCK TABLE
Blend
SELECT
Redesign
The SELECT articulation is a constrained type of DML explanation in that it can just get to
information in the database. It can\'t control information in the database, despite the fact that it
can work on the got to information before giving back the aftereffects of the question.
The CALL and EXPLAIN PLAN proclamations are upheld in PL/SQL just when executed
progressively. All other DML articulations are completely bolstered in PL/SQL.
Exchange Control Statements
Exchange control proclamations oversee changes put forth by DML expressions. The exchange
control explanations are:
Submit
ROLLBACK
SAVEPOINT
SET TRANSACTION
All exchange control proclamations, aside from specific types of the COMMIT and.
Remediation (Clean Up) of the Bhopal Plant SiteStatus of the Forme.pdf
Remediation (Clean Up) of the Bhopal Plant Site
Status of the Former UCIL Plant Site
The Bhopal plant closed after the 1984 methylisocyanate (MIC) gas release and never resumed
normal operations. While the Bhopal gas release litigation was in progress, no steps could be
taken to remediate the site because the MIC unit was considered by the Central Bureau of
Investigation (CBI) as “evidence” in the criminal case. All activity at the site was closely
monitored and controlled by the CBI, the Indian courts and the Madhya Pradesh Pollution
Control Board (MPPCB).
UCIL was finally permitted to undertake clean-up work in the years just prior to the sale of its
stock by UCC in 1994, and spent some $2 million on that effort, which included beginning
construction of a secure landfill to hold the wastes from two on-site solar evaporation ponds. The
central and state government authorities approved, monitored and directed every step of the
clean-up work. Following the sale, it appears that UCIL, now renamed Eveready Industries India
Limited (EIIL), continued some clean-up work and completed the construction of the secure
landfill on the site. In 1998, the Madhya Pradesh State Government (MPSG), which owned and
had been leasing the property to EIIL, cancelled the lease; took over the facility; and assumed all
accountability for the site, including the completion of any additional remediation
According to media reports, court-ordered remediation efforts directed at the government entities
have proceeded slowly. Furthermore, proposals made by private companies have similarly been
questioned or rejected. For example, non-governmental organizations (NGOs) protested against
and blocked remediation attempts by those who offered to help raise funds for clean up or to
conduct pro-bono remediation. The disposal of the waste has consistently proved to be a non-
starter, and was further hindered after a Public Interest Litigation (PIL) was filed in the Madhya
Pradesh High Court in 2004. (UCC is not involved in that litigation.)
The media reported in 2007 that the Supreme Court of India had directed the central and state
governments to pay for collection of waste on the site and to have it landfilled or incinerated, as
appropriate. While some of the waste had been landfilled, public interest groups again
challenged the Court\'s incineration directive, as did the states where waste incineration facilities
were located.
However, in 2012, the Supreme Court selected the Pithampur waste treatment storage and
disposal facility (TSDF) in Madhya Pradesh’s Dhar district as the most suitable facility for
incinerating the waste. Though environmental NGOs claimed the facility failed to meet desired
safety parameters, the Central Pollution Control Board (CPCB) submitted an affidavit in 2014
verifying the suitability of the facility to carry out the incineration.
According to The Indian Express, 10 tons of trial waste were transferred to the site in July 2015
and the trial incinera.
Rb, Na, As, Li here. Lithium only has 3 electrons...cant have .pdf
Rb, Na, As, Li
here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct.
the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct.
now, Arsenic has the highest 1st ionization of all.
So the answer is As.
Solution
Rb, Na, As, Li
here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct.
the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct.
now, Arsenic has the highest 1st ionization of all.
So the answer is As..
operating system Linux,ubuntu,Mac#include stdio.h #include .pdf
//operating system Linux,ubuntu,Mac
#include
#include
#include
#include
/*Sum function implementation*/
int sum(int number1,int number2){
return number1+number2;
}
/*sub function implementation*/
int sub(int number1,int number2){
return number1-number2;
}
/*mul function implementation*/
int mul(int number1,int number2){
return number1*number2;
}
/*divide function implementation*/
float divide(int number1,int number2){
if(number2==0){
printf(\"We can not divide by 0 \ \");
return 0.0f;
}
return (float)(number1/number2);
}
char *substring(char *string, int position, int length)
{
char *pointer;
int c;
pointer = malloc(length+1);
if (pointer == NULL)
{
printf(\"Unable to allocate memory.\ \");
exit(1);
}
for (c = 0 ; c < length ; c++)
{
*(pointer+c) = *(string+position-1);
string++;
}
*(pointer+c) = \'\\0\';
return pointer;
}
/*Main Function start*/
int main(int argc, char *argv[]){
/*Variable declarations*/
int number1,number2;
char *operator,*str1,*str2;
char line[50];
char s[2] = \" \";
int errorFlag=0;// checking if user entered more then one operands
while(1){
/*User input*/
printf(\"Please Enter the command \");
gets(line);
int len=0;
for(int i=0; line[i]!=\'\\0\'; ++i){len++;}
if(len==0){
return 1;
}
/*Spliting into Tokens*/
operator = strtok(line, \" \");
if(strcmp(operator,\"bye\")==0){
break;
}
/*String to integer --- token1*/
number1=atoi(strtok(NULL, s));
/*Removing ( and ) from String*/
str2=strtok(NULL, s);
char *content;int length=0;
for(int i=0; str2[i]!=\'\\0\'; ++i){length++;}
if(str2[0]==\'(\'){
content=substring(str2,2,length-1);
char *opr=content;
int n1=atoi(strtok(NULL, s));
int n2=atoi(strtok(NULL, s));
/*If user entered more then two operands then it will return some token otherwise it will
return NULL pointer*/
if(strtok(NULL, s)!=NULL){
printf(\"You need to enter operator operand1 operand2 \ \");
errorFlag=1;
}else{
if(strcmp(opr,\"sum\")==0){
number2=sum(n1,n2);
}else if(strcmp(opr,\"sub\")==0){
number2=sub(n1,n2);
}else if(strcmp(opr,\"mul\")==0){
number2=mul(n1,n2);
} else if(strcmp(opr,\"div\")==0){
number2=divide(n1,n2);
}
}
}else{
number2=atoi(str2);
/*If user entered more then two operands then it will return some token otherwise it will return
NULL pointer*/
if(strtok(NULL, s)!=NULL){
printf(\"You need to enter operator operand1 operand2 \ \");
errorFlag=1;
}
}
if(errorFlag!=1){
/*Checking operator by strcmp function*/
if(strcmp(operator,\"sum\")==0){
printf(\"Result %d \ \",sum(number1,number2));
}else if(strcmp(operator,\"sub\")==0){
printf(\"Result %d \ \",sub(number1,number2));
}else if(strcmp(operator,\"mul\")==0){
printf(\"Result %d \ \",mul(number1,number2));
} else if(strcmp(operator,\"div\")==0){
printf(\"Result %.2f \ \",divide(number1,number2));
}
}
}
return 0;
}
/********************output************************/
gopal@gopal:~/Desktop/chegg$ gcc Calculator.c
Calculator.c: In function ‘main’:
Calculator.c:67:3: warning: implicit declaration of function ‘gets’ [-Wimplicit-function-
declaration]
gets(.
Network security architecture is the planning and design of the camp.pdf
Network security architecture is the planning and design of the campus network to reduce
security risks in accordance with the institution’s risk analysis and security policies. It focuses on
reduc-ing security risks and enforcing policy through the design and con-figuration of firewalls,
routers, and other network equipment.
Network security is important because it is one of the means to enforce the policies and
procedures developed by the institution to protect information. It is often referred to as the “front
door” in broader discussions of IT security. To the extent that you can block network access to a
computer, you “lock” the door and provide bet-ter protection for that computer and its contents.
Traditional network design has focused on creating a secure net-work perimeter around the
organization and strategically placing a firewall at the point where the network is connected to
the Inter-net. For higher education, this traditional design is problematic; our constituents need
access from off campus to a large number of machines and services on campus. In addition,
because we have many computers on our campus that we cannot implicitly trust, we also must be
concerned about security threats from inside the perimeter protected by a traditional firewall.
These design issues require a different approach to network security. Although it is impossible to
do justice to the topic of network design in a few pages, there are some best practices that I feel
universities should focus on in terms of network design.
Step 1: Eliminate Network Components That Still UseShared Ethernet
Shared Ethernet switches (or hubs) were developed more than a decade ago to interconnect
multiple computers and networks. These hubs retransmit all network traffic to all computers
connected to that hub. The security implication is that if one computer has its security
compromised it can be used to monitor network traffic com-ing from any other computer that
shares the same hub. This could expose passwords and other sensitive information. Today,
switched Ethernet, which isolates traffic intended for one computer from the view of others on
the same switch, is very inexpensive and, hence, it is worth the cost of replacing older hubs.
Step 2: Embrace and Implement the Concept of Defense and Use Multiple Firewalls Within
Your Network
Commercial and Linux-based firewalls are inexpensive enough that you can deploy these in
multiple locations as needed. It is still bene-ficial to have a firewall separating your institutional
network from the connection to the Internet. This firewall, called a border firewall, will provide a
minimal level of protection for all computers on your net-work. The major benefit of this firewall
is that it allows your network and security staff to quickly block external access should a threat
arise, such as when the “SQL worm” was launched in January 2003 In addition to the border
firewall, consider adding internal firewalls to protect areas that requi.
Lipids can be more formally defined as substances such as a fat, oil.pdf
Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in
alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen
proportionally than carbohydrates
Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these
essential components, certain other elements like phosphorus and nitrogen may be present.
Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy
ketones, or change to such substances on simple chemical transformations, as hydrolysis,
oxidation, or reduction, and that form the supporting tissues of plants and are important food for
animals and people.
All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many
hydrogen atoms as oxygen atoms
Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA,
whose molecules consist of many nucleotides linked in a long chain. It is composed of a
nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid.
Solution
Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in
alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen
proportionally than carbohydrates
Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these
essential components, certain other elements like phosphorus and nitrogen may be present.
Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy
ketones, or change to such substances on simple chemical transformations, as hydrolysis,
oxidation, or reduction, and that form the supporting tissues of plants and are important food for
animals and people.
All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many
hydrogen atoms as oxygen atoms
Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA,
whose molecules consist of many nucleotides linked in a long chain. It is composed of a
nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid..
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...
Letter from the Congress of the United States regarding Anti-Semitism sent June 3rd to MIT President Sally Kornbluth, MIT Corp Chair, Mark Gorenberg
Dear Dr. Kornbluth and Mr. Gorenberg,
The US House of Representatives is deeply concerned by ongoing and pervasive acts of antisemitic
harassment and intimidation at the Massachusetts Institute of Technology (MIT). Failing to act decisively to ensure a safe learning environment for all students would be a grave dereliction of your responsibilities as President of MIT and Chair of the MIT Corporation.
This Congress will not stand idly by and allow an environment hostile to Jewish students to persist. The House believes that your institution is in violation of Title VI of the Civil Rights Act, and the inability or
unwillingness to rectify this violation through action requires accountability.
Postsecondary education is a unique opportunity for students to learn and have their ideas and beliefs challenged. However, universities receiving hundreds of millions of federal funds annually have denied
students that opportunity and have been hijacked to become venues for the promotion of terrorism, antisemitic harassment and intimidation, unlawful encampments, and in some cases, assaults and riots.
The House of Representatives will not countenance the use of federal funds to indoctrinate students into hateful, antisemitic, anti-American supporters of terrorism. Investigations into campus antisemitism by the Committee on Education and the Workforce and the Committee on Ways and Means have been expanded into a Congress-wide probe across all relevant jurisdictions to address this national crisis. The undersigned Committees will conduct oversight into the use of federal funds at MIT and its learning environment under authorities granted to each Committee.
• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
• The Committee on Oversight and Accountability is investigating the sources of funding and other support flowing to groups espousing pro-Hamas propaganda and engaged in antisemitic harassment and intimidation of students. The Committee on Oversight and Accountability is the principal oversight committee of the US House of Representatives and has broad authority to investigate “any matter” at “any time” under House Rule X.
• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
Honest Reviews of Tim Han LMA Course Program.pptx
Personal development courses are widely available today, with each one promising life-changing outcomes. Tim Han’s Life Mastery Achievers (LMA) Course has drawn a lot of interest. In addition to offering my frank assessment of Success Insider’s LMA Course, this piece examines the course’s effects via a variety of Tim Han LMA course reviews and Success Insider comments.
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clear clc close all Use polyfit to solve for the phase l.pdf
clear
clc
close all
%Use polyfit to solve for the phase lines
point11=[0,15];
point12=[0,300];
line1=polyfit(point11,point12,1);
m1=line1(1);
b1=line1(2);
xpf1=linspace(min(point11),max(point11),100);
ypf1=m1*xpf1+b1;
point21=[0,15];
point22=[700,300];
line2=polyfit(point21,point22,1);
m2=line2(1);
b2=line2(2);
xpf2=linspace(min(point21),max(point21),100);
ypf2=m2*xpf2+b2;
point31=[0,50];
point32=[700,300];
line3=polyfit(point31,point32,1);
m3=line3(1);
b3=line3(2);
xpf3=linspace(min(point31),max(point31),100);
ypf3=m3*xpf3+b3;
point41=[50,100];
point42=[300,800];
line4=polyfit(point41,point42,1);
m4=line4(1);
b4=line4(2);
xpf4=linspace(min(point41),max(point41),100);
ypf4=m4*xpf4+b4;
point51=[100,85];
point52=[800,300];
line5=polyfit(point51,point52,1);
m5=line5(1);
b5=line5(2);
xpf5=linspace(min(point51),max(point51),100);
ypf5=m5*xpf5+b5;
point61=[85,100];
point62=[300,0];
line6=polyfit(point61,point62,1);
m6=line6(1);
b6=line6(2);
xpf6=linspace(min(point61),max(point61),100);
ypf6=m6*xpf6+b6;
point71=[15,85];
point72=[300,300];
%Allow the user to set the percent of B
b=input(\'Enter the mass percent of B: \');
%Return an error if the percent of B is not a valid number
if b<0 || b>100
error(\'Please enter a value between 0 and 100.\')
end
%Allow the user to set the temperature
t=input(\'Enter the temperature [deg C]: \');
%Solve for percent composition of A
a=100-b;
%Determine phase based on temperature and percent composition of B using
%the phase lines
if t<300
if b<15 && t>m1*b+b1
phase=\'alpha\';
elseif b<15 && t=15 && b<=85
phase=\'alpha + beta\';
elseif b>85 && t>m6*b+b6
phase=\'beta\';
else phase=\'alpha + beta\';
end
elseif b<15
if t=15 && b<=50
if t50 && b<=85
if t=15 && b<=85 && t==300
fprintf(\'The provided conditions fall on the eutectic line.\ \')
end
if b==50 && t==300
fprintf(\'The provided conditions fall on the eutectic point.\ \')
end
%Output a formatted statement to display the phase
fprintf(\'For the composition of %0.2f%% A, %0.2f%% B and a temperature of %0.0f degrees
Celsius, the phase is %s.\ \',a,b,t,phase)
%Create a plot of the phase lines and the user\'s set point
figure(\'color\',\'white\')
%Set axes
axis([0 100 0 1000])
%Plot the phase lines, eutectic line, eutectic point, and the user\'s point
plot(xpf1,ypf1,\'-b\')
hold on
plot(xpf2,ypf2,\'-b\')
plot(xpf3,ypf3,\'-b\')
plot(xpf4,ypf4,\'-b\')
plot(xpf5,ypf5,\'-b\')
plot(xpf6,ypf6,\'-b\')
plot(point71,point72,\'-k\')
plot(b,t,\'ro\',\'MarkerFaceColor\',\'r\')
%Assign a title and axes labels
title(\'Phase Diagram of Elements A and B\')
xlabel(\'Percent Composition of B\')
ylabel(\'Temperature (T) [deg C]\')
%Set scaling for the axes
set(gca,\'XTick\',0:10:100,\'YTick\',0:100:1000)
%Place the phase names on the graph
text(40,200,\'alpha+beta\')
text(45,600,\'Liquid\')
text(90,300,\'beta\')
text(3,300,\'alpha\')
text(15,375,\'alpha + Liquid\')
text(62,375,\'beta + Liquid\')
Solution
clear
clc
close all
%Use polyfit to solve for the phase lines
point11=[0,15];
point.
The oxygen appears in both step reactions. But, i.pdf
The oxygen appears in both step reactions. But, it would not appear in the final
reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction
is 2O3 ====> 3 O2 (No O)
Solution
The oxygen appears in both step reactions. But, it would not appear in the final
reaction. Therefore it is a reaction intermediate. It is sort of in the \"middle\" The final reaction
is 2O3 ====> 3 O2 (No O).
PART A The element Si belongs to IVA group. Therefore, four electro.pdf
PART A: The element Si belongs to IVA group. Therefore, four electrons present in the
outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The
s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the
number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs
to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D:
All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons.
PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present
after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is
[Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons
present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The
element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell.
Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital
and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal.
PART I: The element Ba belongs to IIA group. Therefore, two electrons present in the s-orbital.
Hence the condensed electron configuration of Ba is [Xe] 6s2. PART J: The outermost s-
electron is completely filled. Therefore, there are no unpaired electrons present in Ba metal.
PART K: The element Tl belongs to IIIA group. Therefore, the condensed electron configuration
of Tl is [Xe] 4f14 5d10 6s2 6p1. PART L: The all orbitals are filled with electrons except Tl.
Therefore, the number of unpaired electrons is 1
Solution
PART A: The element Si belongs to IVA group. Therefore, four electrons present in the
outermost shell. Hence the condensed electron configuration of Si is [Ne] 3s23p2. PART B: The
s orbital is completely filled and there are two electrons present in p-orbital. Therefore, the
number of unpaired electrons of Si is 2 PART C: The atomic number of Zn is 30 and it belongs
to IIB group. Therefore, the condensed electron configuration of Zn is [Ar] 4s23d10. PART D:
All orbitals of Zn completely filled with electrons. Therefore, there are no unpaired electrons.
PART E: The atomic number of Zr is 40 and it belongs to IVB group. This element is present
after third element of Kr in periodic table. Hence the condensed electron configuration of Zr is
[Kr] 5s24d2. PART F: The s orbital is completely with electrons and there are two electrons
present in the d orbital. Therefore, the number of unpaired electrons of Zr is 2 PART G: The
element Sn belongs to IVA group. Therefore, four electrons present in the outermost shell.
Hence the condensed electron configuration of Sn is [Kr] 5s24d10 5p2. PART H: The s orbital
and p orbital is completely filled. Therefore, there are two unpaired electrons in the Sn metal.
PART I: The element Ba belongs to IIA group. Th.
The two contributions to the cohesive energy of t.pdf
The two contributions to the cohesive energy of the ionic crystal are : Vander waals
attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero-
point energy is the lowest possible energy that a quantum mechanical physical system may have;
it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in
their ground state and have an associated zero-point energy, a consequence of their wave-like
interaction.
Solution
The two contributions to the cohesive energy of the ionic crystal are : Vander waals
attraction between the adjacent ions Zero point oscillations of their equilibrium position. Zero-
point energy is the lowest possible energy that a quantum mechanical physical system may have;
it is the energy of its ground state. All quantum mechanical systems undergo fluctuations even in
their ground state and have an associated zero-point energy, a consequence of their wave-like
interaction..
If you are talking about an extraction design, th.pdf
If you are talking about an extraction design, the the water solubility has to be
greater in the aqueous base because of the greater solubility of the salts of the acids (with few
exceptions), again presuming a differential extraction aqueous to organic.
Solution
If you are talking about an extraction design, the the water solubility has to be
greater in the aqueous base because of the greater solubility of the salts of the acids (with few
exceptions), again presuming a differential extraction aqueous to organic..
Yes ,its true. Though both gibbons and rhesus monkeys belong to pr.pdf
Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens.
Solution
Yes ,it\'s true. Though both gibbons and rhesus monkeys belong to primates, but gibbons are
under a group apes, and rhesus monkeys belongs to old world monkey group. Apes are near
common ancestor of homosapiens..
When something boils, it changes states of matter. It would go from .pdf
When something boils, it changes states of matter. It would go from a liquid to a soild when it
boils, so if more heat is added, it will just change the state of matter faster.
Solution
When something boils, it changes states of matter. It would go from a liquid to a soild when it
boils, so if more heat is added, it will just change the state of matter faster..
We need to discuss why there is an importance of adding residents to.pdf
We need to discuss why there is an importance of adding residents to the budget planning, we
can go through below explaintion and can derived various conclusions from the same.
In explaining why they did or did not seek input from citizens, respondents in- dicated that the
process was guided by the desires of the leadership. Of those who said that they did seek citizen
input, the desire (as opposed to the obligation through policy) of the staff or the govern- ing
board or staff to seek public opinion seemed to provide some motivation. Almost three-quarters
of responding cities cited staff desire, and almost two-thirds, governing board desire.
The pattern for counties was similar. The most often cited reason for extra effort to involve the
public was board interest. Almost half of the counties also cited staff interest.
Although citizen involvement is a hot topic in management literature these days, local
governments in North Caro- lina are generally not making extensive fforts to involve residents in
budgeting. Barely half of the cities responding to the survey and less than a third of the coun- ties
go beyond the single, mandated hearing to get citizen input In general, cities tend to seek input
more than counties do. This result might be explained by the different types of services offered
by the two forms of gov- ernment. Counties provide funding for, among other things, social
services, pub- lic health services, mental health ser- vices, and schools, and the boards over-
seeing these services may seek citizen input when they are preparing their own budget request
for the county.
Although there is informal interest in hearing from citizens, boards clearly want to remain
flexible in when and how they obtain input. Only 13 percent of the city respondents had a formal
pol- icy or requirement for citizen involve- ment beyond the single, state-mandated hearing.
Medium to large cities were more likely to have such requirements than small cities. Only one
county, a larger one, reported having such a policy or requirement.
Although citizen involvement is a hot topic in management literature these days, local
governments in North Caro- lina are generally not making extensive
efforts to involve residents in budgeting. Barely half of the cities responding to the survey and
less than a third of the coun- ties go beyond the single, mandated hearing to get citizen input
Of those that did not seek extra citizen involvement, the most common reason cited, on both the
city and the county level, was lack of governing board inter- est. The second most common
reason was poor response in the past, when at- tempts to get citizens involved did not seem very
effective. At the county level, lack of board interest was a far more important factor than
anything else, including poor past response: 71 percent of respondents cited lack of board
interest, whereas only 39 percent cited poor past response Although staff interest seemed to be a
big motivator for involving ci.
What is the largest decimal integer that can be represented with the.pdf
What is the largest decimal integer that can be represented with the following number of bits?
1. 3 bits
2. 8 bits
3. 32 bits
4. 64 bits
How do you find out the largest decimal integer?
Solution
In general, with k bits we can represent 2k values. Their range will depend on the system:
Unsigned: 0 to 2k-1
1. 3 bits
=> 2^3 - 1 => 7 => 111
2. 8 bits
=> 2^8 - 1 => 255
3. 32 bits
=> 2^32 - 1
4. 64 bits
=> 2^64 - 1.
Throwing.javaimport java.util.InputMismatchException; import jav.pdf
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer.
Solution
Throwing.java
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IllegalArgumentException e){
System.out.println(e.getMessage());
}
}
public static int getInt()
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IllegalArgumentException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
s
Invalid Input. Please enter an integer.
Throwing.java
import java.io.IOException;
import java.util.InputMismatchException;
import java.util.Scanner;
public class Throwing
{
public static void main(String[] args)
{
try{
int n = getInt();
System.out.println(n);
}
catch(IOException e){
System.out.println(e.getMessage());
}
}
public static int getInt() throws IOException
{
// your code goes here
int n;
try{
Scanner scan = new Scanner(System.in);
System.out.println(\"Enter an integer: \");
n = scan.nextInt();
}
catch(InputMismatchException e){
throw new IOException(\"Invalid Input. Please enter an integer.\");
}
return n;
}
}
Output:
Enter an integer:
d
Invalid Input. Please enter an integer..
This electron transport is accompanied by the protons transfer into .pdf
This electron transport is accompanied by the protons transfer into intermembrane space.
Protons release potential which drives the phosphorylation of ADP to ATP.
Protons return to the matrix through a proton specific channel
Solution
This electron transport is accompanied by the protons transfer into intermembrane space.
Protons release potential which drives the phosphorylation of ADP to ATP.
Protons return to the matrix through a proton specific channel.
In linear or non cyclic electron transport of photosynthesis NADPH a.pdf
In linear or non cyclic electron transport of photosynthesis NADPH and ATP are produced.
These molecules are then used for reduction during dark reaction.
Solution
In linear or non cyclic electron transport of photosynthesis NADPH and ATP are produced.
These molecules are then used for reduction during dark reaction..
The intrusion of biases is a very important issue in decision making.pdf
The intrusion of biases is a very important issue in decision making because it introduces the
conflic of interests between parties or stakeholders, when projects are to be undertaken. Both
public and private policies have been influenced by biased positions in the past, and the concept
of conflict of interests is set when biased positions intend to domain when final decisions are
made.
When public policy is to be decided, biased positions are taken from partisans influenced by
particular interests, which is not the indend of public policy, but to benefit the people, the
citizens of a nation, or a city, or a state. In public policy, identifying these biases is very
important, specially for the ones who take the role of judges, who are responsible for driving
ecnomic resources to be invested in projects that benefit the terrirotial entity, instead of particular
interests.
For instante, for a state, building a road apparently benefted its people, but if public resources are
investo build a road that it is clear to benefit only a mining company because the road is close to
one of its mines, but away from farmers and the rest of citizens of the state, it is clear that
particular interests are domaining over the public intend of the invested resources.
So as to avoid conflicts of interests, it is very important to know parties betting on a public
project, how they try to drive it, because each party would try to benefitiate its own interests, and
the best strategy to make public resources to be invested for the good intend of everybody, these
parts have to be interacting when the project is being debated, and all of them must speak up
their minds, with no restriction, let them be companies and people, espeacially the interaction of
competing companies is desicive in making a project the less biased possible. The particular
interests of all of the parties debating on a public project, and its clearifying before the other
parties, is the best judge that could ever work by itself when public projects are to be decided.
For instance, politicians indend to benefitiate people who vote for them, but people who does not
vote should be benefitiated too, therefore, other competing politians would get this intentions
naked before the public, and therefore, oposing forces to this intend would appear so as to
balance the general benefits of public projects, making a debate less and less biased.
But inside private companies we use to find biases too. For instance, when the marketing and
sales department wants more resources, even overpassing the interests of the manufacturing
marketing, a biase is obvserved clearly. This kind of biase really is against the firm itself, for the
manufacturing department needs enough resources to guarantee good quality products, and
therefore, the market and sales department can be able to expand the company\'s market, which
would be hard to do with low quality products caused by low resources.
References:
Moore, Don et. al. (2010.
The bond issuance will got influenced by following risks a) Infla.pdf
The bond issuance will got influenced by following risks :
a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing.
b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa.
c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond.
d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease
the current market value of the bond which could result in a partial or total loss of an investment.
e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted
accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa.
f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will
come from higher coupon and/or short maturities taken by the investor. On the adverse, the
situation would be vise-versa.
g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the
investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment.
=============
Solution
The bond issuance will got influenced by following risks :
a) Inflation risk : During the inflacinary period, the effect return on the bond keeps on reducing.
b) currency risk : Reduction in the currency value reduces the return on the bonds and vice-versa.
c) liquidity risk: Price changes and supply and demand will alter the liquidity of a bond.
d) default risk : Adversely changes in the creditworthiness of the issuer and rating can decrease
the current market value of the bond which could result in a partial or total loss of an investment.
e) interest rate risk : As interest rates fluctuates, the yield on the bond will be adjusted
accordingly, ie. if interest rates rise, the price of a bond will fall and vise-versa.
f) reinvestment rate risk : The reinvestment rate and taking advantage of rising interest rates will
come from higher coupon and/or short maturities taken by the investor. On the adverse, the
situation would be vise-versa.
g) maturity risk : If the bond is maturing on the longer period, it will provide higher yield to the
investor. The maturity will bring the liquidity to the investor and the risk of the reinvestment.
=============.
Sorts of SQL StatementsThe rundowns in the accompanying segments g.pdf
Sorts of SQL Statements
The rundowns in the accompanying segments give an utilitarian outline of SQL proclamations
and are isolated into these classes:
Information Definition Language (DDL) Statements
Information Manipulation Language (DML) Statements
Exchange Control Statements
Session Control Statements
Framework Control Statement
Inserted SQL Statements
Information Definition Language (DDL) Statements
Information definition dialect (DDL) articulations let you to play out these errands:
Make, change, and drop mapping objects
Give and renounce benefits and parts
Break down data on a table, file, or group
Build up examining alternatives
Add remarks to the information lexicon
The CREATE, ALTER, and DROP orders require select access to the predefined object. For
instance, an ALTER TABLE articulation comes up short if another client has an open exchange
on the predefined table.
The GRANT, REVOKE, ANALYZE, AUDIT, and COMMENT summons don\'t require elite
access to the predetermined item. For instance, you can break down a table while different
clients are redesigning the table.
Prophet Database verifiably submits the present exchange previously, then after the fact each
DDL explanation.
Numerous DDL articulations may make Oracle Database recompile or reauthorize diagram
objects. For data on how Oracle Database recompiles and reauthorizes outline objects and the
conditions under which a DDL proclamation would precipitate this, see Oracle Database
Concepts.
DDL explanations are upheld by PL/SQL with the utilization of the DBMS_SQL bundle.
See Also:
PL/SQL Packages and Types Reference
The DDL explanations are:
Adjust ... (All announcements starting with ALTER)
Examine
Partner STATISTICS
Review
Remark
Make ... (All announcements starting with CREATE)
DISASSOCIATE STATISTICS
DROP ... (All announcements starting with DROP)
FLASHBACK ... (All announcements starting with FLASHBACK)
Stipend
NOAUDIT
Cleanse
RENAME
Repudiate
TRUNCATE
Information Manipulation Language (DML) Statements
Information control dialect (DML) explanations get to and control information in existing
mapping objects. These announcements don\'t verifiably confer the present exchange. The
information control dialect articulations are:
CALL
Erase
Clarify PLAN
Embed
LOCK TABLE
Blend
SELECT
Redesign
The SELECT articulation is a constrained type of DML explanation in that it can just get to
information in the database. It can\'t control information in the database, despite the fact that it
can work on the got to information before giving back the aftereffects of the question.
The CALL and EXPLAIN PLAN proclamations are upheld in PL/SQL just when executed
progressively. All other DML articulations are completely bolstered in PL/SQL.
Exchange Control Statements
Exchange control proclamations oversee changes put forth by DML expressions. The exchange
control explanations are:
Submit
ROLLBACK
SAVEPOINT
SET TRANSACTION
All exchange control proclamations, aside from specific types of the COMMIT and.
Remediation (Clean Up) of the Bhopal Plant SiteStatus of the Forme.pdf
Remediation (Clean Up) of the Bhopal Plant Site
Status of the Former UCIL Plant Site
The Bhopal plant closed after the 1984 methylisocyanate (MIC) gas release and never resumed
normal operations. While the Bhopal gas release litigation was in progress, no steps could be
taken to remediate the site because the MIC unit was considered by the Central Bureau of
Investigation (CBI) as “evidence” in the criminal case. All activity at the site was closely
monitored and controlled by the CBI, the Indian courts and the Madhya Pradesh Pollution
Control Board (MPPCB).
UCIL was finally permitted to undertake clean-up work in the years just prior to the sale of its
stock by UCC in 1994, and spent some $2 million on that effort, which included beginning
construction of a secure landfill to hold the wastes from two on-site solar evaporation ponds. The
central and state government authorities approved, monitored and directed every step of the
clean-up work. Following the sale, it appears that UCIL, now renamed Eveready Industries India
Limited (EIIL), continued some clean-up work and completed the construction of the secure
landfill on the site. In 1998, the Madhya Pradesh State Government (MPSG), which owned and
had been leasing the property to EIIL, cancelled the lease; took over the facility; and assumed all
accountability for the site, including the completion of any additional remediation
According to media reports, court-ordered remediation efforts directed at the government entities
have proceeded slowly. Furthermore, proposals made by private companies have similarly been
questioned or rejected. For example, non-governmental organizations (NGOs) protested against
and blocked remediation attempts by those who offered to help raise funds for clean up or to
conduct pro-bono remediation. The disposal of the waste has consistently proved to be a non-
starter, and was further hindered after a Public Interest Litigation (PIL) was filed in the Madhya
Pradesh High Court in 2004. (UCC is not involved in that litigation.)
The media reported in 2007 that the Supreme Court of India had directed the central and state
governments to pay for collection of waste on the site and to have it landfilled or incinerated, as
appropriate. While some of the waste had been landfilled, public interest groups again
challenged the Court\'s incineration directive, as did the states where waste incineration facilities
were located.
However, in 2012, the Supreme Court selected the Pithampur waste treatment storage and
disposal facility (TSDF) in Madhya Pradesh’s Dhar district as the most suitable facility for
incinerating the waste. Though environmental NGOs claimed the facility failed to meet desired
safety parameters, the Central Pollution Control Board (CPCB) submitted an affidavit in 2014
verifying the suitability of the facility to carry out the incineration.
According to The Indian Express, 10 tons of trial waste were transferred to the site in July 2015
and the trial incinera.
Rb, Na, As, Li here. Lithium only has 3 electrons...cant have .pdf
Rb, Na, As, Li
here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct.
the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct.
now, Arsenic has the highest 1st ionization of all.
So the answer is As.
Solution
Rb, Na, As, Li
here. Lithium only has 3 electrons...can\'t have a 6th ionizationenergy, it is correct.
the 1st ionization of Rb < Na , therefore the6th would be less as well. it is also correct.
now, Arsenic has the highest 1st ionization of all.
So the answer is As..
operating system Linux,ubuntu,Mac#include stdio.h #include .pdf
//operating system Linux,ubuntu,Mac
#include
#include
#include
#include
/*Sum function implementation*/
int sum(int number1,int number2){
return number1+number2;
}
/*sub function implementation*/
int sub(int number1,int number2){
return number1-number2;
}
/*mul function implementation*/
int mul(int number1,int number2){
return number1*number2;
}
/*divide function implementation*/
float divide(int number1,int number2){
if(number2==0){
printf(\"We can not divide by 0 \ \");
return 0.0f;
}
return (float)(number1/number2);
}
char *substring(char *string, int position, int length)
{
char *pointer;
int c;
pointer = malloc(length+1);
if (pointer == NULL)
{
printf(\"Unable to allocate memory.\ \");
exit(1);
}
for (c = 0 ; c < length ; c++)
{
*(pointer+c) = *(string+position-1);
string++;
}
*(pointer+c) = \'\\0\';
return pointer;
}
/*Main Function start*/
int main(int argc, char *argv[]){
/*Variable declarations*/
int number1,number2;
char *operator,*str1,*str2;
char line[50];
char s[2] = \" \";
int errorFlag=0;// checking if user entered more then one operands
while(1){
/*User input*/
printf(\"Please Enter the command \");
gets(line);
int len=0;
for(int i=0; line[i]!=\'\\0\'; ++i){len++;}
if(len==0){
return 1;
}
/*Spliting into Tokens*/
operator = strtok(line, \" \");
if(strcmp(operator,\"bye\")==0){
break;
}
/*String to integer --- token1*/
number1=atoi(strtok(NULL, s));
/*Removing ( and ) from String*/
str2=strtok(NULL, s);
char *content;int length=0;
for(int i=0; str2[i]!=\'\\0\'; ++i){length++;}
if(str2[0]==\'(\'){
content=substring(str2,2,length-1);
char *opr=content;
int n1=atoi(strtok(NULL, s));
int n2=atoi(strtok(NULL, s));
/*If user entered more then two operands then it will return some token otherwise it will
return NULL pointer*/
if(strtok(NULL, s)!=NULL){
printf(\"You need to enter operator operand1 operand2 \ \");
errorFlag=1;
}else{
if(strcmp(opr,\"sum\")==0){
number2=sum(n1,n2);
}else if(strcmp(opr,\"sub\")==0){
number2=sub(n1,n2);
}else if(strcmp(opr,\"mul\")==0){
number2=mul(n1,n2);
} else if(strcmp(opr,\"div\")==0){
number2=divide(n1,n2);
}
}
}else{
number2=atoi(str2);
/*If user entered more then two operands then it will return some token otherwise it will return
NULL pointer*/
if(strtok(NULL, s)!=NULL){
printf(\"You need to enter operator operand1 operand2 \ \");
errorFlag=1;
}
}
if(errorFlag!=1){
/*Checking operator by strcmp function*/
if(strcmp(operator,\"sum\")==0){
printf(\"Result %d \ \",sum(number1,number2));
}else if(strcmp(operator,\"sub\")==0){
printf(\"Result %d \ \",sub(number1,number2));
}else if(strcmp(operator,\"mul\")==0){
printf(\"Result %d \ \",mul(number1,number2));
} else if(strcmp(operator,\"div\")==0){
printf(\"Result %.2f \ \",divide(number1,number2));
}
}
}
return 0;
}
/********************output************************/
gopal@gopal:~/Desktop/chegg$ gcc Calculator.c
Calculator.c: In function ‘main’:
Calculator.c:67:3: warning: implicit declaration of function ‘gets’ [-Wimplicit-function-
declaration]
gets(.
Network security architecture is the planning and design of the camp.pdf
Network security architecture is the planning and design of the campus network to reduce
security risks in accordance with the institution’s risk analysis and security policies. It focuses on
reduc-ing security risks and enforcing policy through the design and con-figuration of firewalls,
routers, and other network equipment.
Network security is important because it is one of the means to enforce the policies and
procedures developed by the institution to protect information. It is often referred to as the “front
door” in broader discussions of IT security. To the extent that you can block network access to a
computer, you “lock” the door and provide bet-ter protection for that computer and its contents.
Traditional network design has focused on creating a secure net-work perimeter around the
organization and strategically placing a firewall at the point where the network is connected to
the Inter-net. For higher education, this traditional design is problematic; our constituents need
access from off campus to a large number of machines and services on campus. In addition,
because we have many computers on our campus that we cannot implicitly trust, we also must be
concerned about security threats from inside the perimeter protected by a traditional firewall.
These design issues require a different approach to network security. Although it is impossible to
do justice to the topic of network design in a few pages, there are some best practices that I feel
universities should focus on in terms of network design.
Step 1: Eliminate Network Components That Still UseShared Ethernet
Shared Ethernet switches (or hubs) were developed more than a decade ago to interconnect
multiple computers and networks. These hubs retransmit all network traffic to all computers
connected to that hub. The security implication is that if one computer has its security
compromised it can be used to monitor network traffic com-ing from any other computer that
shares the same hub. This could expose passwords and other sensitive information. Today,
switched Ethernet, which isolates traffic intended for one computer from the view of others on
the same switch, is very inexpensive and, hence, it is worth the cost of replacing older hubs.
Step 2: Embrace and Implement the Concept of Defense and Use Multiple Firewalls Within
Your Network
Commercial and Linux-based firewalls are inexpensive enough that you can deploy these in
multiple locations as needed. It is still bene-ficial to have a firewall separating your institutional
network from the connection to the Internet. This firewall, called a border firewall, will provide a
minimal level of protection for all computers on your net-work. The major benefit of this firewall
is that it allows your network and security staff to quickly block external access should a threat
arise, such as when the “SQL worm” was launched in January 2003 In addition to the border
firewall, consider adding internal firewalls to protect areas that requi.
Lipids can be more formally defined as substances such as a fat, oil.pdf
Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in
alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen
proportionally than carbohydrates
Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these
essential components, certain other elements like phosphorus and nitrogen may be present.
Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy
ketones, or change to such substances on simple chemical transformations, as hydrolysis,
oxidation, or reduction, and that form the supporting tissues of plants and are important food for
animals and people.
All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many
hydrogen atoms as oxygen atoms
Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA,
whose molecules consist of many nucleotides linked in a long chain. It is composed of a
nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid.
Solution
Lipids can be more formally defined as substances such as a fat, oil or wax that dissolves in
alcohol but not in water. Lipids contain carbon, hydrogen and oxygen but have far less oxygen
proportionally than carbohydrates
Lipids are organic compounds which are made of carbon, hydrogen and oxygen. Besides these
essential components, certain other elements like phosphorus and nitrogen may be present.
Carbohydrates are a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy
ketones, or change to such substances on simple chemical transformations, as hydrolysis,
oxidation, or reduction, and that form the supporting tissues of plants and are important food for
animals and people.
All carbohydrates are made from carbon, hydrogen and oxygen. They have twice as many
hydrogen atoms as oxygen atoms
Nucleic acid is a complex organic substance present in living cells, especially DNA or RNA,
whose molecules consist of many nucleotides linked in a long chain. It is composed of a
nitrogenous base (either a purine or pyrimidine), a pentose and Phosphoric acid..
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a) mean = 1.43Thus distribution is Poisson(4.2)P(X = 4) = 4.2^4.pdf
- 1. a) mean = 1.4*3 Thus distribution is Poisson(4.2) P(X = 4) = 4.2^4 * e^{-4.2} / 4! = 0.1944 b) average number of ghosts in 90min (1.5hrs) interval = 1.4*1.5 = 2.1 c) Probability that 4th ghost will appear before 10 am = Probability that number of ghosts appearing from 8 to 10 am >= 4 As it is a 2 hr period, the distribution of number of ghosts is Poisson(1.4*2) i.e Poisson(2.8) P(X >= 4) = 1 - P(X < 4) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)] = 1 - [(2.8^0 * e^{-2.8} / 0!) + (2.8^1 * e^{-2.8} / 1!) + (2.8^2 * e^{-2.8} / 2!) + (2.8^3 * e^{- 2.8} / 3!)] = 1 - [0.0608 + 0.1703 + 0.2384 + 0.2225] = 0.692 d) When arrival distribution is Poisson(lambda), inter-arrival time distribution is Exponential(lambda) Thus, interarrival time distribution is Exponential(1.4) Expected value of time between 5th and 6th ghost = 1/1.4 = 0.7143hr e) On average time taken for 10th ghost to arrive = 10*(1/1.4) = 7.143hr Thus on an average, 10th ghost will arrive at 3:09pm
- 2. f) Expected value of time between ghost appearances = 1/1.4 = 0.7143hr (see part d) g) Probability that 3rd ghost appears after 9:45 am = Probablity that number of ghosts appearing till 9:45 am < 3 Duration from 8am to 9:45 am = 1.75hr Mean number of ghosts = 1.4*1.75 = 2.45 Thus X is Poisson(2.45) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = (2.45^0 * e^{-2.45} / 0!) + (2.45^1 * e^{-2.45} / 1!) + (2.45^2 * e^{-2.45} / 2!) = 0.0863 + 0.2114 + 0.2590 = 0.5567 h) As inter-arrival time is Exponential(1.4), inter-arrival time is memoryless Thus, time for 7th ghost will be calculated from 1:00 pm and not from 12:35pm due to memorylessness property. Time duration from 1:00pm to 1:15pm = 0.25hrs Let Y be random variable denoting inter-arrival time probability that the 7th ghost will appear before 1:15 p.m. = P(Y < 0.25) = 1 - e^{-1.4 * 0.25) = 0.2953
- 3. i) Expected value of time for 7th ghost to appear after 1:00pm = 1/1.4 = 0.7143hr = 42.86 min Time from 12:35pm to 1:00pm = 25min Thus expected interarrival time = 25 + 42.86 = 67.86 min = 1hr 7.86min j) Expected duration after 1:00pm for 9th ghost to appear = 3 * (1/1.4) = 2.143hr = 2hr 8.58min Thus expected time at which 9th ghost appears = 3:09pm k) As the inter-arrival time follows memorylessness property, the future probabilities do not change with the observed value at past. Thus, 4 ghosts appearing between 7:00pm to 10:00pm does not affect ghost appearance from 11:00pm to 11:30pm Duration from 11:00pm to 11:30pm = 0.5hrs mean number of ghosts = 1.4*0.5 = 0.7 Thus it follows Poisson(0.7) distribution P(X > 2) = 1 - P(X <= 2) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)] = 1 - [(0.7^0 * e^{-0.7} / 0!) + (0.7^1 * e^{-0.7} / 1!) + (0.7^2 * e^{-0.7} / 2!)] = 1 - [0.4966 + 0.3476 + 0.1217] = 0.0341 l) Probability that 8 ghosts appear between 6pm and midnight = Probability that number of ghosts appear from 6pm to 7pm and 10pm to midnight = 4 as it is
- 4. known that 4 ghosts appeared from 7pm to 10pm Let A denote number of ghost from 6pm to 7pm B denote number of ghosts from 10pm to midnight A is Poisson(1.4) B is Poisson(1.4*2) i.e Poisson(2.8) Probability that 8 ghosts appear between 6pm and midnight = P(A=0)P(B=4) + P(A=1)P(B=3) + P(A=2)P(B=2) + P(A=3)P(B=1) + P(A=4)P(B=0) = 0.2466*0.1557 + 0.3452*0.2225 + 0.2417*0.2384 + 0.1123*0.1703 + 0.0395*0.0608 = 0.1944 Solution a) mean = 1.4*3 Thus distribution is Poisson(4.2) P(X = 4) = 4.2^4 * e^{-4.2} / 4! = 0.1944 b) average number of ghosts in 90min (1.5hrs) interval = 1.4*1.5 = 2.1 c) Probability that 4th ghost will appear before 10 am = Probability that number of ghosts appearing from 8 to 10 am >= 4 As it is a 2 hr period, the distribution of number of ghosts is Poisson(1.4*2) i.e Poisson(2.8) P(X >= 4) = 1 - P(X < 4) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)] = 1 - [(2.8^0 * e^{-2.8} / 0!) + (2.8^1 * e^{-2.8} / 1!) + (2.8^2 * e^{-2.8} / 2!) + (2.8^3 * e^{- 2.8} / 3!)]
- 5. = 1 - [0.0608 + 0.1703 + 0.2384 + 0.2225] = 0.692 d) When arrival distribution is Poisson(lambda), inter-arrival time distribution is Exponential(lambda) Thus, interarrival time distribution is Exponential(1.4) Expected value of time between 5th and 6th ghost = 1/1.4 = 0.7143hr e) On average time taken for 10th ghost to arrive = 10*(1/1.4) = 7.143hr Thus on an average, 10th ghost will arrive at 3:09pm f) Expected value of time between ghost appearances = 1/1.4 = 0.7143hr (see part d) g) Probability that 3rd ghost appears after 9:45 am = Probablity that number of ghosts appearing till 9:45 am < 3 Duration from 8am to 9:45 am = 1.75hr Mean number of ghosts = 1.4*1.75 = 2.45 Thus X is Poisson(2.45) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = (2.45^0 * e^{-2.45} / 0!) + (2.45^1 * e^{-2.45} / 1!) + (2.45^2 * e^{-2.45} / 2!) = 0.0863 + 0.2114 + 0.2590
- 6. = 0.5567 h) As inter-arrival time is Exponential(1.4), inter-arrival time is memoryless Thus, time for 7th ghost will be calculated from 1:00 pm and not from 12:35pm due to memorylessness property. Time duration from 1:00pm to 1:15pm = 0.25hrs Let Y be random variable denoting inter-arrival time probability that the 7th ghost will appear before 1:15 p.m. = P(Y < 0.25) = 1 - e^{-1.4 * 0.25) = 0.2953 i) Expected value of time for 7th ghost to appear after 1:00pm = 1/1.4 = 0.7143hr = 42.86 min Time from 12:35pm to 1:00pm = 25min Thus expected interarrival time = 25 + 42.86 = 67.86 min = 1hr 7.86min j) Expected duration after 1:00pm for 9th ghost to appear = 3 * (1/1.4) = 2.143hr = 2hr 8.58min Thus expected time at which 9th ghost appears = 3:09pm k) As the inter-arrival time follows memorylessness property, the future probabilities do not change with the observed value at past. Thus, 4 ghosts appearing between 7:00pm to 10:00pm does not affect ghost appearance from 11:00pm to 11:30pm Duration from 11:00pm to 11:30pm = 0.5hrs
- 7. mean number of ghosts = 1.4*0.5 = 0.7 Thus it follows Poisson(0.7) distribution P(X > 2) = 1 - P(X <= 2) = 1 - [P(X = 0) + P(X = 1) + P(X = 2)] = 1 - [(0.7^0 * e^{-0.7} / 0!) + (0.7^1 * e^{-0.7} / 1!) + (0.7^2 * e^{-0.7} / 2!)] = 1 - [0.4966 + 0.3476 + 0.1217] = 0.0341 l) Probability that 8 ghosts appear between 6pm and midnight = Probability that number of ghosts appear from 6pm to 7pm and 10pm to midnight = 4 as it is known that 4 ghosts appeared from 7pm to 10pm Let A denote number of ghost from 6pm to 7pm B denote number of ghosts from 10pm to midnight A is Poisson(1.4) B is Poisson(1.4*2) i.e Poisson(2.8) Probability that 8 ghosts appear between 6pm and midnight = P(A=0)P(B=4) + P(A=1)P(B=3) + P(A=2)P(B=2) + P(A=3)P(B=1) + P(A=4)P(B=0) = 0.2466*0.1557 + 0.3452*0.2225 + 0.2417*0.2384 + 0.1123*0.1703 + 0.0395*0.0608 = 0.1944