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Gases
Chapter 5
Dr. Sa’ib Khouri
AUM- JORDAN
Chemistry
By Raymond Chang
2
Elements that exist as gases at 25 oC and 1 atmosphere
3
4
In the table
H2S and HCN are deadly poisons.
CO, NO2 , O3 , and SO2 , are somewhat less toxic.
He, Ne, and Ar are chemically inert.
Most gases are colorless. Exceptions are F2 , Cl2 , and NO2 .
O2 is essential for our survival.
5
1. Assume the volume and shape of their
containers.
All gases have the following physical
characteristics
2. Are the most compressible state of matter.
3. Will mix evenly and completely when
confined to the same container.
4. Have much lower densities than liquids and
solids.
6
Units of Pressure
1 pascal (Pa) = 1 N/m2
1 atm = 760 mmHg (= 760 torr)
1 atm = 101,325 Pa
Pressure =
Force
Area
(Force = mass x acceleration)
Pressure of a Gas
SI Units of Pressure
N/m2
The actual value of atmospheric pressure depends on location,
temperature, and weather conditions.
7
Sea level 1 atm
4 miles 0.5 atm
10 miles 0.2 atm
A column of air extending from sea level to the upper
atmosphere.
The
barometer
is the most
familiar
instrument
for
measuring
atmospheric
pressure
8
The pressure outside a jet plane flying at high altitude falls
considerably below standard atmospheric pressure.
Therefore, the air inside the cabin must be pressurized to
protect the passengers. What is the pressure in atmospheres
in the cabin if the barometer reading is 688 mmHg?
Example
9
10
Manometers Used to Measure Gas Pressures
closed-tube open-tube
A manometer is a device used to measure the pressure of
gases other than the atmosphere.
To measure pressures below
atmospheric pressure.
To measure pressures equal
to or greater than
atmospheric pressure.
11
P a 1/V
P x V = constant
P1 x V1 = P2 x V2
The Pressure-Volume Relationship: Boyle’s Law
Constant temperature
The Gas Laws
The pressure of a fixed amount of gas at a constant
temperature is inversely proportional to the volume of the gas.
Constant amount of gas
Increasing or decreasing the volume of a gas
at a constant temperature
13
A sample of chlorine gas occupies a volume of 800 mL at a
pressure of 750 mmHg. What is the pressure of the gas (in
mmHg) if the volume is reduced at constant temperature to 200
mL?
P1 x V1 = P2 x V2
P1 = 750 mmHg
V1 = 800 mL
P2 = ?
V2 = 200 mL
P2 =
P1 x V1
V2
750 mmHg x 800 mL
200 mL
= = 3000 mmHg
P x V = constant
Example
14
As T increases V increases
The Temperature-Volume Relationship:
Charles’ and Gay-Lussac’s Law
15
V a T
V = constant x T
V1/T1 = V2 /T2
T (K) = t (oC) + 273.15
Temperature must be
in Kelvin (SI-unit)
When these lines
are extrapolated,
or extended, they
all intersect at the
point representing
zero volume and
a temperature of -
273.15 oC.
16
A sample of carbon monoxide gas occupies 3.20 L at 398 K. At
what temperature will the gas occupy a volume of 1.54 L if the
pressure remains constant?
V1 = 3.20 L
T1 = 398 K
V2 = 1.54 L
T2 = ?
T2 =
V2 x T1
V1
1.54 L x 398 K
3.20 L
=
= 191.5 K
V1 /T1 = V2 /T2
Example
17
V a number of moles (n)
V = constant x n
V1 / n1 = V2 / n2
Constant temperature
Constant pressure
At constant pressure and temperature, the volume of a gas is
directly proportional to the number of moles of the gas present
The Volume-Amount Relationship:
Avogadro’s Law
18
The Ideal Gas Equation
Charles’ law: V a T (at constant n and P)
Avogadro’s law: V a n (at constant P and T)
Boyle’s law: V a (at constant n and T)1
P
V a
nT
P
V = constant x = R
nT
P
nT
P
R is the gas constant
PV = nRT
Combination of all three expressions:
ideal gas equation
19
At 0°C (273.15 K) and 1 atm pressure (standard temperature
and pressure (STP)), many real gases behave like an ideal.
PV = nRT R =
PV
nT
=
(1 atm)(22.414L)
(1 mol)(273.15 K)
R = 0.082057 L • atm / mol • K
Experiments show that at STP, 1 mole of an ideal gas occupies
22.414 L.
Ideal gas: a hypothetical gas whose molecules occupy negligible
space compared with the volume of the container and have no
interactions.
For most calculations:
R = 0.0821 L • atm / mol • K
20
A certain light bulb containing argon at 1.20 atm and
18 oC is heated to 85 oC at constant volume. What
is the final pressure of argon in the light bulb (in
atm)?
PV = nRT n, V and R are constant
nR
V
=
P
T
= constant
P1
T1
P2
T2
=
P1 = 1.20 atm
T1 = 291 K
P2 = ?
T2 = 358 K
P2 = P1 x
T2
T1
= 1.20 atm x 358 K
291 K
= 1.48 atm
Example
21
What is the volume (in liters) occupied by 49.8 g of HCl at STP?
PV = nRT V =
nRT
P
T = 273.15 K P = 1 atm
n = 49.8 g x
1 mol HCl
36.45 g HCl
= 1.37 mol
V =
1 atm
1.37 mol x 0.0821 x 273.15 KL•atm
mol•K
V = 30.7 L
Example
22
23
Density Calculations
d = m
V
=
PM
R T
m: the mass of the gas in g
M: the molar mass of the gas
in g/mol
dRT
P
M = d: is the density of the gas in g/L
n= m /MPV = n RT  PV = m/MRT
or PM = m / V RT
24
A 2.10 L vessel contains 4.65 g of a gas at 1.00 atm and 27.0
oC. What is the molar mass of the gas?
dRT
P
M = d = m
V
4.65 g
2.10 L
= = 2.21
g
L
M =
2.21
g
L
1 atm
x 0.0821 x 300.15 KL•atm
mol•K
M = 54.5 g/mol
Example
25
Gas Stoichiometry
Example: What is the volume of CO2 produced at 37 oC and
1.00 atm when 5.60 g of glucose are used up in the reaction:
C6H12O6 (s) + 6O2 (g) 6CO2 (g) + 6H2O (l)
g C6H12O6 mol C6H12O6 mol CO2 V CO2
5.60 g C6H12O6
1 mol C6H12O6
180 g C6H12O6
x
6 mol CO2
1 mol C6H12O6
x = 0.187 mol CO2
V =
nRT
P
0.187 mol x 0.0821 x 310.15 K
L•atm
mol•K
1.00 atm
= = 4.76 L
• According to the kinetic molecular theory, the gas
particles in a mixture behave independently, i.e.
each gas exerts a pressure independent of the
other gases in the mixture.
• All gases in the mixture have the same volume and
temperature.
• The pressure of a component gas in a mixture is
called a partial pressure.
• The sum of the partial pressures of all the gases in
a mixture equals the total pressure.
Dalton’s Law of Partial Pressures
28
At constant V and T
PA
PB Ptotal = PA + PB
29
Consider a case in which two gases, A and B, are in a
container of volume V.
PA =
nART
V
PB =
nBRT
V
nA is the number of moles of A
nB is the number of moles of B
PT = PA + PB
PA = XA PT
PB = XB PT
Pi = Xi PT mole fraction (Xi ) =
ni
nT
30
Pi = Xi PT PT = 2.00 atm
31
Collecting Gases
• Gases are often collected by having them displace
water from a container.
• The problem is that since water evaporates, there is
also water vapor in the collected gas.
• The partial pressure of the water vapor, called the
vapor pressure, depends only on the temperature. So
you can use a table to find out the partial pressure of
the water vapor in the gas you collect.
• If you collect a gas sample with a total pressure of
758 mmHg at 25 °C, the partial pressure of the
water vapor will be 23.8 mmHg, so the partial
pressure of the dry gas will be 734 mmHg
(Dalton’s law )
32
Vapor of Water and Temperature
33
2KClO3 (s) 2KCl (s) + 3O2 (g) PT = PO2
+ PH2O
Example
35
The Kinetic Molecular Theory of Gases
Assumptions
1. A gas is composed of molecules (or atoms) that are separated
from each other by distances far greater than their own
dimensions. The molecules can be considered to be “points”; that
is, they possess mass but have negligible volume.
2. Gas molecules are in constant motion in random directions,
and they frequently collide with one another. Collisions among
molecules are perfectly elastic. In other words, energy can be
transferred from one molecule to another as a result of a
collision. Nevertheless, the total energy of all the molecules in a
system remains the same.
3. Gas molecules exert neither attractive nor repulsive forces on
one another.
36
4.The average kinetic energy of the molecules is
proportional to the temperature of the gas in kelvins. Any
two gases at the same temperature will have the same
average kinetic energy. The average kinetic energy of a
molecule is given by
KE = ½ mu2
where m is the mass of the molecule and u is its speed
According to the kinetic molecular theory, gas pressure is
the result of collisions between molecules and the walls of
their container.
37
Application to the Gas Laws
• Compressibility of Gases: gases can be compressed
easily to occupy less volume.
• Boyle’s Law
P a collision rate with wall
Collision rate a number density (per unit volume)
Number density a 1/V
P a 1/V
• Charles’ Law
P a collision rate with wall, which comes from raising T.
Collision rate a average kinetic energy of gas molecules
Average kinetic energy a T
P a T
38
• Avogadro’s Law
P a collision rate with wall
Collision rate a number density
Number density a n
P a n
• Dalton’s Law of Partial Pressures
Molecules do not attract or repel one another
P exerted by one type of molecule is unaffected by the
presence of another gas
Ptotal = SPi
39
The distribution of speeds
for nitrogen gas molecules
at three different temperatures
The distribution of speeds
of three different gases
at the same temperature
Distribution of Molecular Speeds
40
41
Gas diffusion:
The gradual mixing of molecules of one gas with molecules of
another by virtue of their kinetic properties.
NH3
17 g/mol
HCl
36 g/mol
NH4Cl
r1
r2
M2
M1=
molecular path
42
Gas effusion:
The process by which gas under pressure escapes from one
compartment of a container to another by passing through a
small opening.
=
r1
r2
t2
t1
M2
M1=
Nickel forms a gaseous compound of the formula Ni(CO)x. What
is the value of x given that under the same conditions methane
(CH4) effuses 3.3 times faster than the compound?
r1 = 3.3 x r2
M1 = 16 g/mol
M2 =
r1
r2
( )
2
x M1 = (3.3)2 x 16 = 174.2
58.7 + x • 28 = 174.2 x = 4.1 ~ 4
43
Deviation from Ideal Behavior
Plot of PV/RT
versus P of 1
mole of a gas
at 0°C
For 1 mole of an ideal gas, PV/RT is equal to 1, no matter what
the pressure of the gas is.
For real gases, we observe various deviations from ideality at
high pressures.
At very low pressures, all gases exhibit ideal behavior; that is,
their PV/RT values all converge to 1 as P approaches zero.
44
Van der Waals equation
nonideal gas
P + (V – nb) = nRTan2
V2( )
}
corrected
pressure
}corrected
volume
H.W.
Using the van der Waals equation, calculate the pressure exerted
by 15.0 mol of carbon dioxide confined to a 3.0 L vessel at 329 K.
Note: Values for a and b in the van der Waals equation:
a = 3.59 L
2
.atm/mol
2
, b = 0.0427 L/mol.
A) 23.2 atm
B) 2.16 atm
C) 81.9 atm
D) 96.4 atm

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Ch5 Gases

  • 1. 1 Gases Chapter 5 Dr. Sa’ib Khouri AUM- JORDAN Chemistry By Raymond Chang
  • 2. 2 Elements that exist as gases at 25 oC and 1 atmosphere
  • 3. 3
  • 4. 4 In the table H2S and HCN are deadly poisons. CO, NO2 , O3 , and SO2 , are somewhat less toxic. He, Ne, and Ar are chemically inert. Most gases are colorless. Exceptions are F2 , Cl2 , and NO2 . O2 is essential for our survival.
  • 5. 5 1. Assume the volume and shape of their containers. All gases have the following physical characteristics 2. Are the most compressible state of matter. 3. Will mix evenly and completely when confined to the same container. 4. Have much lower densities than liquids and solids.
  • 6. 6 Units of Pressure 1 pascal (Pa) = 1 N/m2 1 atm = 760 mmHg (= 760 torr) 1 atm = 101,325 Pa Pressure = Force Area (Force = mass x acceleration) Pressure of a Gas SI Units of Pressure N/m2 The actual value of atmospheric pressure depends on location, temperature, and weather conditions.
  • 7. 7 Sea level 1 atm 4 miles 0.5 atm 10 miles 0.2 atm A column of air extending from sea level to the upper atmosphere. The barometer is the most familiar instrument for measuring atmospheric pressure
  • 8. 8 The pressure outside a jet plane flying at high altitude falls considerably below standard atmospheric pressure. Therefore, the air inside the cabin must be pressurized to protect the passengers. What is the pressure in atmospheres in the cabin if the barometer reading is 688 mmHg? Example
  • 9. 9
  • 10. 10 Manometers Used to Measure Gas Pressures closed-tube open-tube A manometer is a device used to measure the pressure of gases other than the atmosphere. To measure pressures below atmospheric pressure. To measure pressures equal to or greater than atmospheric pressure.
  • 11. 11 P a 1/V P x V = constant P1 x V1 = P2 x V2 The Pressure-Volume Relationship: Boyle’s Law Constant temperature The Gas Laws The pressure of a fixed amount of gas at a constant temperature is inversely proportional to the volume of the gas. Constant amount of gas
  • 12. Increasing or decreasing the volume of a gas at a constant temperature
  • 13. 13 A sample of chlorine gas occupies a volume of 800 mL at a pressure of 750 mmHg. What is the pressure of the gas (in mmHg) if the volume is reduced at constant temperature to 200 mL? P1 x V1 = P2 x V2 P1 = 750 mmHg V1 = 800 mL P2 = ? V2 = 200 mL P2 = P1 x V1 V2 750 mmHg x 800 mL 200 mL = = 3000 mmHg P x V = constant Example
  • 14. 14 As T increases V increases The Temperature-Volume Relationship: Charles’ and Gay-Lussac’s Law
  • 15. 15 V a T V = constant x T V1/T1 = V2 /T2 T (K) = t (oC) + 273.15 Temperature must be in Kelvin (SI-unit) When these lines are extrapolated, or extended, they all intersect at the point representing zero volume and a temperature of - 273.15 oC.
  • 16. 16 A sample of carbon monoxide gas occupies 3.20 L at 398 K. At what temperature will the gas occupy a volume of 1.54 L if the pressure remains constant? V1 = 3.20 L T1 = 398 K V2 = 1.54 L T2 = ? T2 = V2 x T1 V1 1.54 L x 398 K 3.20 L = = 191.5 K V1 /T1 = V2 /T2 Example
  • 17. 17 V a number of moles (n) V = constant x n V1 / n1 = V2 / n2 Constant temperature Constant pressure At constant pressure and temperature, the volume of a gas is directly proportional to the number of moles of the gas present The Volume-Amount Relationship: Avogadro’s Law
  • 18. 18 The Ideal Gas Equation Charles’ law: V a T (at constant n and P) Avogadro’s law: V a n (at constant P and T) Boyle’s law: V a (at constant n and T)1 P V a nT P V = constant x = R nT P nT P R is the gas constant PV = nRT Combination of all three expressions: ideal gas equation
  • 19. 19 At 0°C (273.15 K) and 1 atm pressure (standard temperature and pressure (STP)), many real gases behave like an ideal. PV = nRT R = PV nT = (1 atm)(22.414L) (1 mol)(273.15 K) R = 0.082057 L • atm / mol • K Experiments show that at STP, 1 mole of an ideal gas occupies 22.414 L. Ideal gas: a hypothetical gas whose molecules occupy negligible space compared with the volume of the container and have no interactions. For most calculations: R = 0.0821 L • atm / mol • K
  • 20. 20 A certain light bulb containing argon at 1.20 atm and 18 oC is heated to 85 oC at constant volume. What is the final pressure of argon in the light bulb (in atm)? PV = nRT n, V and R are constant nR V = P T = constant P1 T1 P2 T2 = P1 = 1.20 atm T1 = 291 K P2 = ? T2 = 358 K P2 = P1 x T2 T1 = 1.20 atm x 358 K 291 K = 1.48 atm Example
  • 21. 21 What is the volume (in liters) occupied by 49.8 g of HCl at STP? PV = nRT V = nRT P T = 273.15 K P = 1 atm n = 49.8 g x 1 mol HCl 36.45 g HCl = 1.37 mol V = 1 atm 1.37 mol x 0.0821 x 273.15 KL•atm mol•K V = 30.7 L Example
  • 22. 22
  • 23. 23 Density Calculations d = m V = PM R T m: the mass of the gas in g M: the molar mass of the gas in g/mol dRT P M = d: is the density of the gas in g/L n= m /MPV = n RT  PV = m/MRT or PM = m / V RT
  • 24. 24 A 2.10 L vessel contains 4.65 g of a gas at 1.00 atm and 27.0 oC. What is the molar mass of the gas? dRT P M = d = m V 4.65 g 2.10 L = = 2.21 g L M = 2.21 g L 1 atm x 0.0821 x 300.15 KL•atm mol•K M = 54.5 g/mol Example
  • 25. 25 Gas Stoichiometry Example: What is the volume of CO2 produced at 37 oC and 1.00 atm when 5.60 g of glucose are used up in the reaction: C6H12O6 (s) + 6O2 (g) 6CO2 (g) + 6H2O (l) g C6H12O6 mol C6H12O6 mol CO2 V CO2 5.60 g C6H12O6 1 mol C6H12O6 180 g C6H12O6 x 6 mol CO2 1 mol C6H12O6 x = 0.187 mol CO2 V = nRT P 0.187 mol x 0.0821 x 310.15 K L•atm mol•K 1.00 atm = = 4.76 L
  • 26.
  • 27. • According to the kinetic molecular theory, the gas particles in a mixture behave independently, i.e. each gas exerts a pressure independent of the other gases in the mixture. • All gases in the mixture have the same volume and temperature. • The pressure of a component gas in a mixture is called a partial pressure. • The sum of the partial pressures of all the gases in a mixture equals the total pressure. Dalton’s Law of Partial Pressures
  • 28. 28 At constant V and T PA PB Ptotal = PA + PB
  • 29. 29 Consider a case in which two gases, A and B, are in a container of volume V. PA = nART V PB = nBRT V nA is the number of moles of A nB is the number of moles of B PT = PA + PB PA = XA PT PB = XB PT Pi = Xi PT mole fraction (Xi ) = ni nT
  • 30. 30 Pi = Xi PT PT = 2.00 atm
  • 31. 31 Collecting Gases • Gases are often collected by having them displace water from a container. • The problem is that since water evaporates, there is also water vapor in the collected gas. • The partial pressure of the water vapor, called the vapor pressure, depends only on the temperature. So you can use a table to find out the partial pressure of the water vapor in the gas you collect. • If you collect a gas sample with a total pressure of 758 mmHg at 25 °C, the partial pressure of the water vapor will be 23.8 mmHg, so the partial pressure of the dry gas will be 734 mmHg (Dalton’s law )
  • 32. 32 Vapor of Water and Temperature
  • 33. 33 2KClO3 (s) 2KCl (s) + 3O2 (g) PT = PO2 + PH2O Example
  • 34.
  • 35. 35 The Kinetic Molecular Theory of Gases Assumptions 1. A gas is composed of molecules (or atoms) that are separated from each other by distances far greater than their own dimensions. The molecules can be considered to be “points”; that is, they possess mass but have negligible volume. 2. Gas molecules are in constant motion in random directions, and they frequently collide with one another. Collisions among molecules are perfectly elastic. In other words, energy can be transferred from one molecule to another as a result of a collision. Nevertheless, the total energy of all the molecules in a system remains the same. 3. Gas molecules exert neither attractive nor repulsive forces on one another.
  • 36. 36 4.The average kinetic energy of the molecules is proportional to the temperature of the gas in kelvins. Any two gases at the same temperature will have the same average kinetic energy. The average kinetic energy of a molecule is given by KE = ½ mu2 where m is the mass of the molecule and u is its speed According to the kinetic molecular theory, gas pressure is the result of collisions between molecules and the walls of their container.
  • 37. 37 Application to the Gas Laws • Compressibility of Gases: gases can be compressed easily to occupy less volume. • Boyle’s Law P a collision rate with wall Collision rate a number density (per unit volume) Number density a 1/V P a 1/V • Charles’ Law P a collision rate with wall, which comes from raising T. Collision rate a average kinetic energy of gas molecules Average kinetic energy a T P a T
  • 38. 38 • Avogadro’s Law P a collision rate with wall Collision rate a number density Number density a n P a n • Dalton’s Law of Partial Pressures Molecules do not attract or repel one another P exerted by one type of molecule is unaffected by the presence of another gas Ptotal = SPi
  • 39. 39 The distribution of speeds for nitrogen gas molecules at three different temperatures The distribution of speeds of three different gases at the same temperature Distribution of Molecular Speeds
  • 40. 40
  • 41. 41 Gas diffusion: The gradual mixing of molecules of one gas with molecules of another by virtue of their kinetic properties. NH3 17 g/mol HCl 36 g/mol NH4Cl r1 r2 M2 M1= molecular path
  • 42. 42 Gas effusion: The process by which gas under pressure escapes from one compartment of a container to another by passing through a small opening. = r1 r2 t2 t1 M2 M1= Nickel forms a gaseous compound of the formula Ni(CO)x. What is the value of x given that under the same conditions methane (CH4) effuses 3.3 times faster than the compound? r1 = 3.3 x r2 M1 = 16 g/mol M2 = r1 r2 ( ) 2 x M1 = (3.3)2 x 16 = 174.2 58.7 + x • 28 = 174.2 x = 4.1 ~ 4
  • 43. 43 Deviation from Ideal Behavior Plot of PV/RT versus P of 1 mole of a gas at 0°C For 1 mole of an ideal gas, PV/RT is equal to 1, no matter what the pressure of the gas is. For real gases, we observe various deviations from ideality at high pressures. At very low pressures, all gases exhibit ideal behavior; that is, their PV/RT values all converge to 1 as P approaches zero.
  • 44. 44 Van der Waals equation nonideal gas P + (V – nb) = nRTan2 V2( ) } corrected pressure }corrected volume
  • 45.
  • 46.
  • 47. H.W. Using the van der Waals equation, calculate the pressure exerted by 15.0 mol of carbon dioxide confined to a 3.0 L vessel at 329 K. Note: Values for a and b in the van der Waals equation: a = 3.59 L 2 .atm/mol 2 , b = 0.0427 L/mol. A) 23.2 atm B) 2.16 atm C) 81.9 atm D) 96.4 atm