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# Ch 20 Electric Circuits

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### Ch 20 Electric Circuits

1. 1. Chapter 20 Electric Circuits
2. 2. Learning Objectives Electric circuits  Current, resistance, power  Students should understand the definition of electric current, so they can relate the magnitude and direction of the current to the rate of flow of positive and negative charge.  Students should understand conductivity, resistivity, and resistance, so they can:  Relate current and voltage for a resistor.  Describe how the resistance of a resistor depends upon its length and cross-sectional area, and apply this result in comparing current flow in resistors of different material or different geometry.  Apply the relationships for the rate of heat production in a resistor.
3. 3. Learning Objectives  Steady-state direct current circuits with batteries and resistors only  Students should understand the behavior of series and parallel combinations of resistors, so they can:  Identify on a circuit diagram whether resistors are in series or in parallel.  Determine the ratio of the voltages across resistors connected in series or the ratio of the currents through resistors connected in parallel.  Calculate the equivalent resistance of a network of resistors that can be broken down into series and parallel combinations.  Calculate the voltage, current, and power dissipation for any resistor in such a network of resistors connected to a single power supply.  Design a simple series-parallel circuit that produces a given current through and potential difference across one specified component, and draw a diagram for the circuit using conventional symbols.
4. 4. Learning Objectives  Steady-state direct current circuits with batteries and resistors only  Students should understand the properties of ideal and real batteries, so they can:  Calculate the terminal voltage of a battery of specified emf and internal resistance from which a known current is flowing.  Students should be able to apply Ohm’s law and Kirchhoff’s rules to direct-current circuits, in order to: determine a single unknown current, voltage, or resistance.  Students should understand the properties of voltmeters and ammeters, so they can:  State whether the resistance of each is high or low.  Identify or show correct methods of connecting meters into circuits in order to measure voltage or current.
5. 5. Learning Objectives  Capacitors in circuits  Students should understand the t = 0 and steady-state behavior of capacitors connected in series or in parallel, so they can:  Calculate the equivalent capacitance of a series or parallel combination.  Describe how stored charge is divided between capacitors connected in parallel.  Determine the ratio of voltages for capacitors connected in series.  Calculate the voltage or stored charge, under steady- state conditions, for a capacitor connected to a circuit consisting of a battery and resistors.
6. 6. Table of Contents 1. Electromotive Force and Current 2. Ohm’s Law 3. Resistance & Resistivity 4. Electric Power 5. Alternating Current (Not AP) 6. Series Wiring 7. Parallel Wiring 8. Series and Parallel Wiring 9. Internal Resistance 10. Kirchoff’s Rules 11. The Measurement of Current and Voltage 12. Capacitors in Series and Parallel Circuits 13. RC Circuits (Not AP) 14. Safety and the Physiological Effects of Current (Not AP)
7. 7. Chapter 20: Electric Circuits Section 1: Electromotive Force & Current
8. 8. Electric Circuits  In an electric circuit, an energy source and an energy consuming device are connected by conducting wires through which electric charges move.
9. 9. Electromotive Force  Within a battery, a chemical reaction occurs that transfers electrons from one terminal to another terminal.  The maximum potential difference across the terminals is called the electromotive force (emf).
10. 10.  The electric current is the amount of charge per unit time that passes through a surface that is perpendicular to the motion of the charges. t Q Iavg ∆ ∆ = One coulomb per second equals one ampere (A). Electric Current
11. 11. Types of Current  If the charges move around the circuit in the same direction at all times, the current is said to be direct current (dc).  If the charges move first one way and then the opposite way, the current is said to be alternating current (ac).
12. 12. Example 1 A Pocket Calculator The current in a 3.0 V battery of a pocket calculator is 0.17 mA. In one hour of operation, (a) how much charge flows in the circuit and (b) how much energy does the battery deliver to the calculator circuit? (a) (b) ( )tIQ ∆=∆ ( )( )V0.3C61.0= t Q Iavg ∆ ∆ = ( )( )s3600A1017.0 3− ×= C61.0= QVU = J8.1=
13. 13. Direction of Current  Conventional current is the hypothetical flow of positive charges that would have the same effect in the circuit as the movement of negative charges that actually does occur.
14. 14. 20.1.1. In which one of the following situations does a conventional electric current flow due north? a) Protons in a beam are moving due south. b) A water molecule is moving due north. c) Electrons in a beam are moving due south. d) Electrons in a wire connected to a battery are moving from south to north.
15. 15. 20.1.2. The battery capacity of a lithium ion battery in a digital music player is 750 mA-h. The manufacturer claims that the player can operate for eight hours if the battery is initially fully charged. Given this information, determine the number of electrons that flow through the player as you listen to your favorite songs for three hours. a) 6.2 × 1018 electrons b) 1.0 × 103 electrons c) 2.4 × 109 electrons d) 6.3 × 1021 electrons e) 8.1 × 1028 electrons
16. 16. Chapter 20: Electric Circuits Section 2: Ohm’s Law
17. 17. Resistance  The resistance (R) is defined as the ratio of the voltage V applied across a piece of material to the current I through the material.  To the extent that a wire or an electrical device offers resistance to electrical flow, it is called a resistor.
18. 18. SI Unit of Resistance: volt/ampere (V/A) = ohm (Ω) I∝V Ohm’s Law  The V is proportional to I, where V is the voltage applied across a piece of material and I is the current through the material: IRV =
19. 19. Example 2 A Flashlight The filament in a light bulb is a resistor in the form of a thin piece of wire. The wire becomes hot enough to emit light because of the current in it. The flashlight uses two 1.5-V batteries to provide a current of 0.40 A in the filament. Determine the resistance of the glowing filament. I V R = IRV = A0.40 V0.3 = Ω= 5.7
20. 20. 20.2.1. In a certain circuit containing a battery and a resistor, Ohm’s law is obeyed. An instrument to measure the current in the circuit, an ammeter, is connected in between one of the terminals of the battery and one end of the resistor. The ammeter indicates that the current in the circuit is I. The battery is then removed and replaced with another battery. This time, the ammeter indicates the current is 2I. Which one of the following statements concerning the resistor is true? a) When the second battery was placed in the circuit, the resistance increased to twice its initial value. b) When the second battery was placed in the circuit, the resistance decreased to one half its initial value. c) When the second battery was placed in the circuit, the resistance increased to four times its initial value. d) When the second battery was placed in the circuit, the resistance increased to one fourth its initial value. e) When the second battery was placed in the circuit, the resistance did not change.
21. 21. 20.2.2. Consider the circuit containing a battery and a resistor shown. For which one of the following combinations of current and voltage does R have the smallest value? a) V = 9 V and I = 0.002 A b) V = 12 V and I = 0.5 A c) V = 1.5 V and I = 0.075 A d) V = 6 V and I = 0.1 A e) V = 4.5 V and I = 0.009 A
22. 22. 20.2.3. A certain circuit contains a battery and a resistor. An instrument to measure the current in the circuit, an ammeter, is connected in between one of the terminals of the battery and one end of the resistor. The graph shows the current in the circuit as the voltage is increased. Which one of the following statements best describes the resistor in this circuit? a) The resistor does not obey Ohm’s law. b) The resistor obeys Ohm’s law for voltages between zero and twenty-five volts. c) The resistor obeys Ohm’s law for voltages between zero and thirty-five volts. d) The resistor obeys Ohm’s law for voltages between zero and forty volts. e) The resistor obeys Ohm’s law for voltages between thirty and forty volts.
23. 23. Chapter 20: Electric Circuits Section 3: Resistance and Resitivity
24. 24. A L R ρ = resistivity in units of ohm·meter Resistance in Materials  For a wide range of materials, the resistance of a piece of material of length L and cross-sectional area A is:
25. 25. Example 3 Longer Extension Cords The instructions for an electric lawn mower suggest that a 20-gauge extension cord can be used for distances up to 35 m, but a thicker 16-gauge cord should be used for longer distances. The cross sectional area of a 20-gauge wire is 5.2x10-7 Ω·m, while that of a 16-gauge wire is 13x10-7 Ω·m. Determine the resistance of (a) 35 m of 20-gauge copper wire and (b) 75 m of 16-gauge copper wire. A L R ρ = (a) (b) ( )( ) 27- 8 m1013 m75m1072.1 × ⋅Ω× = − ( )( ) 27- 8 m105.2 m35m1072.1 × ⋅Ω× = − Ω= 2.1 A L R ρ = Ω= 99.0
26. 26. ( )[ ]oo TT −+= αρρ 1 temperature coefficient of resistivity ( )[ ]oo TTRR −+= α1 Temperature Effects
27. 27. 20.3.1. For which combination for the length L and radius R of a wire will the resistance have the smallest value? a) L = 0.50 m and R = 0.03 m b) L = 0.25 m and R = 0.08 m c) L = 0.40 m and R = 0.2 m d) L = 0.80 m and R = 0.1 m e) L = 0.10 m and R = 0.05 m
28. 28. 20.3.2. The ends of a wire are connected to the terminals of a battery. For which of the following changes will the resulting current in the circuit have the largest value? a) Replace the wire with one that has a larger resistivity. b) Replace the wire with one that has a larger radius. c) Replace the wire with one that has a longer length.
29. 29. Chapter 20: Electric Circuits Section 4: Electric Power
30. 30. t U P ∆ = energy power time Electric Power  Suppose some charge emerges from a battery and the potential difference between the battery terminals is V. ( ) t Vq ∆ ∆ = V t q ∆ ∆ = IV=
31. 31. IVP = SI Unit of Power: watt (W) ( ) RIIRIP 2 == R V V R V P 2 =      = Electric Power  When there is current in a circuit as a result of a voltage, the electric power delivered to the circuit is:
32. 32. Example 5 The Power and Energy Used in a Flashlight In the flashlight, the current is 0.40A and the voltage is 3.0 V. Find (a) the power delivered to the bulb and (b) the energy dissipated in the bulb in 5.5 minutes of operation. (a) (b) IVP = PtE = ( )( )V0.3A40.0= W2.1= ( )( )s330W2.1= J100.4 2 ×=
33. 33. 20.4.1. An automatic coffee maker uses a resistive heating element to boil the 2.4 kg of water that was poured into it at 21 °C. The current delivered to the coffee pot is 8.5 A when it is plugged into a 120 V electrical outlet. If the specific heat capacity of water is 4186 J/kgC°, approximately how long does it take to boil all of the water? a) 5 minutes b) 8 minutes c) 10 minutes d) 13 minutes e) 15 minutes
34. 34. 20.4.2. The insulated wiring in a house can safely carry a maximum current of 18 A. The electrical outlets in the house provide an alternating voltage of 120 V. A space heater when plugged into the outlet operates at an average power of 1500 W. How many space heaters can safely be plugged into a single electrical outlet and turned on for an extended period of time? a) zero b) one c) two d) three e) four
35. 35. 20.4.3. A portable CD player was recently introduced that has a “special power saving technology.” The manufacturer claims that with only two standard AA batteries (together: 3.0 V, 20 kJ energy storage) that the player can be played for about 25 hours. What is the approximate resistance in the CD player’s electrical circuitry? a) 41 Ω b) 0.010 Ω c) 300 Ω d) 1.5 Ω e) 15 Ω
36. 36. 20.4.4. A wire is used as a heating element that has a resistance that is fairly independent of its temperature within its operating range. When a current I is applied to the wire, the energy delivered by the heater each minute is E. For what amount of current will the energy delivered by the heater each minute be 4E? a) 2I b) 4I c) 0.5I d) 0.25I e) 8I
37. 37. Chapter 20: Electric Circuits Section 5: Alternating Current
38. 38. In an AC circuit, the charge flow reverses direction periodically.
39. 39. ( )ftVV o π2sin=
40. 40. In circuits that contain only resistance, the current reverses direction each time the polarity of the generator reverses. ( ) ( )ftIft R V R V I o o ππ 2sin2sin === peak current
41. 41. ( )ftVIIVP oo π2sin2 == ( )ftII o π2sin= ( )ftVV o π2sin=
42. 42. rmsrms 222 VI VIVI P oooo =            ==
43. 43. RIV rmsrms = rmsrmsIVP = RIP 2 rms= R V P 2 rms =
44. 44. Example 6 Electrical Power Sent to a Loudspeaker A stereo receiver applies a peak voltage of 34 V to a speaker. The speaker behaves approximately as if it had a resistance of 8.0 Ω. Determine (a) the rms voltage, (b) the rms current, and (c) the average power for this circuit.
45. 45. (a) (b) (c) V24 2 V34 2 rms === oV V A3.0 0.8 V24rms rms = Ω == R V I ( )( ) W72V24A3.0rmsrms === VIP
46. 46. Conceptual Example 7 Extension Cords and a Potential Fire Hazard During the winter, many people use portable electric space heaters to keep warm. Sometimes, however, the heater must be located far from a 120-V wall receptacle, so an extension cord must be used. However, manufacturers often warn against using an extension cord. If one must be used, they recommend a certain wire gauge, or smaller. Why the warning, and why are smaller-gauge wires better then larger-gauge wires?
47. 47. 20.5.1. The graph shows the current as a function of time for an electrical device plugged into a outlet with an rms voltage of 120 V. What is the resistance of the device? a) 24 Ω b) 21 Ω c) 17 Ω d) 14Ω e) 12 Ω
48. 48. 20.5.2. Consider the circuits shown in parts A and B in the picture. In part A, a light bulb is plugged into a wall outlet that has an rms voltage of 120 volts. A current I passes through the circuit and the bulb turns on. In part B, a second, identical light bulb is connected in series in the circuit. How does the current in circuit B compare with that in circuit A? a) The current is the same, I, as in part A. b) The current is twice as much, 2I, as in part A. c) The current in part B is zero amperes. d) The current is one fourth as much, 0.25I, as in part A. e) The current is one half as much, 0.5I, as in part A.
49. 49. Chapter 20: Electric Circuits Section 6: Series Wiring
50. 50. Series Wiring  There are many circuits in which more than one device is connected to a voltage source.  Series wiring means that the devices are connected in such a way that there is the same electric current through each device. (One Path)
51. 51. 21 VVV += +++= 321 RRRRSSeries resistors Resistance in a series Circuit  As we will discuss later, the sum of all voltage in a circuit must equal zero.  Voltage supplied by battery is lost by resistors 21 IRIR += ( )21 RRI += SIR= ∑= i iS RR
52. 52. Example 8 Resistors in a Series Circuit A 6.00 Ω resistor and a 3.00 Ω resistor are connected in series with a 12.0 V battery. Assuming the battery contributes no resistance to the circuit, find (a) the current, (b) the power dissipated in each resistor, and (c) the total power delivered to the resistors by the battery. (a) (b) (c) Ω=Ω+Ω= 00.900.300.6SR SR V I = RIP 2 = RIP 2 = W31.5W6.10 +=P Ω = 00.9 V0.12 A33.1= ( ) ( )Ω= 00.6A33.1 2 W6.10= ( ) ( )Ω= 00.3A33.1 2 W31.5= W9.15=
53. 53. 20.6.1. Consider the circuit shown in the drawing. Two identical light bulbs, labeled A and B, are connected in series with a battery and are illuminated equally. There is a switch in the circuit that is initially open. Which one of the following statements concerning the two bulbs is true after the switch is closed? a) Bulbs A and B will be off. b) Bulbs A and B will be equally illuminated. c) Bulb A will be brighter and bulb B will be off. d) Bulb A will be off and bulb B will be brighter. e) Both bulbs will be dimmer than before the switch was closed.
54. 54. Chapter 20: Electric Circuits Section 7: Parallel Wiring
55. 55. Parallel Wiring  Parallel wiring means that the devices are connected in such a way that the same voltage is applied across each device.  Multiple paths are present.  When two resistors are connected in parallel, each receives current from the battery as if the other was not present.  Therefore the two resistors connected in parallel draw more current than does either resistor alone.
56. 56. Wiring in your home
57. 57. parallel resistors… +++= 321 1111 RRRRP Parallel Wiring  As we will discuss later, the total current flowing into any point must equal the total current flowing out. 21 III += 21 R V R V +=       += 21 11 RR V       = PR V 1 ∑= i iP RR 11
58. 58. Simplifying Circuits ∑= i iP RR 11 R1 = 5 Ω R2 = 3 Ω 21 11 RR += 21 21 RR RR R + = 21 121 RR RR R + = ( )( ) Ω+Ω ΩΩ = 35 35 Ω= 89.1R 0 5 RTotal OR
59. 59. Example 10 Main and Remote Stereo Speakers Most receivers allow the user to connect to “remote” speakers in addition to the main speakers. At the instant represented in the picture, the voltage across the speakers is 6.00 V. Determine (a) the equivalent resistance of the two speakers, (b) the total current supplied by the receiver, (c) the current in each speaker, and (d) the power dissipated in each speaker.
60. 60. (a) Ω + Ω = 00.4 1 00.8 11 PR Ω= 67.2 (b) PR V I rms rms = R V I rms rms =(c) R V I rms rms = (d) rmsrmsVIP = rmsrmsVIP = ∑= i iP RR 11 Ω = 00.8 3 Ω = 67.2 V00.6 A25.2= Ω = 00.8 V00.6 A750.0= A 00.4 V00.6 Ω = A50.1= ( )( )V00.6A750.0= W50.4= ( )( )V00.6A50.1= W00.9=
61. 61. Conceptual Example 11 A Three-Way Light Bulb and Parallel Wiring Within the bulb there are two separate filaments. When one burns out, the bulb can produce only one level of illumination, but not the highest. Are the filaments connected in series or parallel? How can two filaments be used to produce three different illumination levels?
62. 62. 20.7.1. Consider the three resistors and the battery in the circuit shown. Which resistors, if any, are connected in parallel? a) R1 and R2 b) R1 and R3 c) R2 and R3 d) R1 and R2 and R3 e) No resistors are connected in parallel.
63. 63. 20.7.2. Consider the circuits shown in parts A and B in the picture. In part A, a light bulb is plugged into a wall outlet that has an rms voltage of 120 volts. A current I passes through the circuit and the bulb turns on. In part B, a second, identical light bulb is connected in parallel in the circuit. How does the total current in circuit B compare with that in circuit A? a) The current is the same, I, as in part A. b) The current is twice as much, 2I, as in part A. c) The current in part B is zero amperes. d) The current is one fourth as much, 0.25I, as in part A. e) The current is one half as much, 0.5I, as in part A.
64. 64. 20.7.3. Two light bulbs, one “50 W” bulb and one “100 W” bulb, are connected in parallel with a standard 120 volt ac electrical outlet. The brightness of a light bulb is directly related to the power it dissipates. Therefore, the 100 W bulb appears brighter. How does the brightness of the two bulbs compare when these same bulbs are connected in series with the same outlet? a) Both bulbs will be equally bright. b) The “100 W” bulb will be brighter. c) The “50 W” bulb will be brighter.
65. 65. Chapter 20: Electric Circuits Section 8: Series and Parallel Wiring
66. 66. Compound Circuits
67. 67. 20.8.1. Consider the three identical light bulbs shown in the circuit. Bulbs B and C are wired in series with each other and are wired in parallel with bulb A. When the bulbs are connected to the battery as shown, how does the brightness of each bulb compare to the others? a) Bulbs B and C are equally bright, but bulb A is less bright. b) Bulbs B and C are equally bright, but less bright than bulb A. c) All three bulbs are equally bright. d) Bulbs A and B are equally bright, but bulb C is less bright. e) Only bulb A is illuminated.
68. 68. 20.8.2. A circuit is formed using a battery, three identical resistors, and connecting wires as shown. How does the current passing through R3 compare with that passing through R1? a) I3 < I1 b) I3 = I1 c) I3 > I1 d) This cannot be determined without knowing the amount of current passing through R2.
69. 69. 20.8.3. What is the approximate equivalent resistance of the five resistors shown in the circuit? a) 21 Ω b) 7 Ω c) 11 Ω d) 14 Ω e) 19 Ω
70. 70. R RR Resistance = 3 R What is the resistance between x and y? x y
71. 71. R RR Resistance = R What is the resistance between x and y? x y a
72. 72. R RR Resistance = R What is the resistance between x and y? x yb
73. 73. R RR What is the resistance between x and y? x y a b
74. 74. R x R R y ab R RR x y a b Redraw the circuit
75. 75. R R R What is the resistance between x and y? x y ab 3 R Resistance =
76. 76. Chapter 20: Electric Circuits Section 9: Internal Resistance
77. 77. Internal Resistance  Batteries and generators add some resistance to a circuit. This resistance is called internal resistance.  The actual voltage between the terminals of a battery is known as the terminal voltage.
78. 78. Example 12 The Terminal Voltage of a Battery The car battery has an emf of 12.0 V and an internal resistance of 0.0100 Ω. What is the terminal voltage when the current drawn from the battery is (a) 10.0 A and (b) 100.0 A? (a) IrV = V10.0V0.12 − (b) IrV = V0.1V0.12 − ( )( )Ω= 010.0A0.10 V10.0= 11.9V= ( )( )Ω= 010.0A0.100 V0.1= 11.0V=
79. 79. 20.9.1. In physics lab, two students measured the potential difference between the terminals of a battery and the current in a circuit connected to the battery. The students then made a graph of the two parameters as shown. They then drew a best fit line through the data. From their results, determine the approximate internal resistance of the battery. a) 0.002 Ω b) 0.08 Ω c) 0.1 Ω d) 0.3 Ω e) 0.6 Ω
80. 80. Chapter 20: Electric Circuits Section 10: Kirchoff’s Rules
81. 81. Loop Rule  The loop rule expresses conservation of energy in terms of the electric potential.  States that for a closed circuit loop, the total of all potential rises is the same as the total of all potential drops.
82. 82. Junction Rule  Conservation of mass  Electrons entering must equal the electrons leaving  The junction rule states that the total current directed into a junction must equal the total current directed out of the junction.
83. 83. Example 14 Using Kirchhoff’s Loop Rule Determine the current in the circuit.  ( ) ( )   dropspotentialrisespotential 0.8V0.612V24 Ω++Ω= II A90.0=I ∑ = i iV 0 ( )321 VVVVbattery ++=
84. 84. Reasoning Strategy Applying Kirchhoff’s Rules 1. Draw the current in each branch of the circuit. Choose any direction. If your choice is incorrect, the value obtained for the current will turn out to be a negative number. 2. Mark each resistor with a + at one end and a – at the other end in a way that is consistent with your choice for current direction in step 1. Outside a battery, conventional current is always directed from a higher potential (the end marked +) to a lower potential (the end marked -). 3. Apply the junction rule and the loop rule to the circuit, obtaining in the process as many independent equations as there are unknown variables. 4. Solve these equations simultaneously for the unknown variables.
85. 85. 20.10.1. What is the current through the 4-Ω resistor in this circuit? a) 0.67 A b) 0.75 A c) 1.0 A d) 1.3 A e) 1.5 A
86. 86. 20.10.2. What is the current through the 1-Ω resistor in this circuit? a) 2.8 A b) 3.0 A c) 3.4 A d) 4.3 A e) 4.8 A
87. 87. 20.10.3. Which one of the following equations is not correct relative to the other four equations determined by applying Kirchoff’s Rules to the circuit shown? a) I2 = I1 + I4 b) I2 = I3 + I5 c) 6 V − (8 Ω) I1 − (5 Ω) I2 − (4 Ω) I3 = 0 d) 6 V − (6 Ω) I4 − (5 Ω) I2 − (2 Ω) I5 = 0 e) 6 V − (8 Ω) I1 − (6 Ω) I4 − 6 V − (2 Ω) I5 − (4 Ω) I3 = 0
88. 88. Chapter 20: Electric Circuits Section 11: The Measurement of Current and Voltage
89. 89. A dc galvanometer. The coil of wire and pointer rotate when there is a current in the wire.
90. 90. An ammeter must be inserted into a circuit so that the current passes directly through it.
91. 91. If a galvanometer with a full-scale limit of 0.100 mA is to be used to measure the current of 60.0 mA, a shunt resistance must be used so that the excess current of 59.9 mA can detour around the galvanometer coil.
92. 92. To measure the voltage between two points in a circuit, a voltmeter is connected between the points.
93. 93. Chapter 20: Electric Circuits Section 12: Capacitors in series and in parallel
94. 94. Parallel capacitors ∑= i iP CC 21 qqq += Capacitors in Parallel  Voltage is the same on each side of the circuit  Charges on each capacitor directly add VCVC 21 += ( )VCC 21 +=
95. 95. 21 VVV += Series capacitors ∑= i iS CC 11 Capacitors in Series  Since there is only one path, charge is the same in all capacitors regardless of capacitance  Voltage drop of each capacitor directly add 21 C q C q +=       += 21 11 CC q
96. 96. 20.12.1. A parallel plate capacitor is connected to a battery and becomes fully charged. A voltmeter is used to measure the potential difference across the plates of the capacitor. Then, an uncharged thin metal plate is inserted into the gap between the parallel plates without touching either plate. What affect, if any, does the insertion of the plate have on the potential difference across the plates? a) The potential difference will not change. b) The potential difference will increase to twice its initial value. c) The potential difference will decrease to one half its initial value. d) The potential difference will increase to a value that cannot be determined without having more information. e) The potential difference will decrease to a value that cannot be determined without having more information.
97. 97. 20.12.2. Three parallel plate capacitors, each having a capacitance of 1.0 µF are connected in series. The potential difference across the combination is 100 V. What is the charge on any one of the capacitors? a) 30 µC b) 300 µC c) 3000 µC d) 100 µC e) 1000 µC
98. 98. Chapter 20: Electric Circuits Section 13: RC Circuits
99. 99. Capacitor charging [ ]RCt o eqq − −= 1 RC=τ time constant RC Circuits
100. 100. Capacitor discharging RCt oeqq − = RC=τ time constant RC Circuits
101. 101. 20.13.1. In physics lab, Rebecca measured the voltage across an unknown capacitor in an RC circuit, every ten seconds after a switch in the circuit that allows the capacitor to discharge is closed. The capacitor was initially fully charged. Using the graph, estimate the time constant. a) 7.5 s b) 15 s c) 30 s d) 45 s e) 60 s
102. 102. 20.13.2. An RC circuit contains a battery, a switch, a resistor, and a capacitor – all connected in series. Initially, the switch is open and the capacitor is uncharged. Which one of the following statements correctly describes the current in the circuit during the time the capacitor is charging? a) The current is increasing with increasing time. b) The current is constant with increasing time. c) The current is decreasing with increasing time. d) The current increases for the first half of the time until the capacitor is fully discharged, and then decreases during the second half of the time. e) The current can either increase or decrease with increasing time depending on the value of the time constant.
103. 103. Chapter 20: Electric Circuits Section 14: Safety and the Physiological Effects of Current
104. 104. 20.14 Safety and the Physiological Effects of Current To reduce the danger inherent in using circuits, proper electrical grounding is necessary.