Melissa’s potw solution

Melissa’s POTW Solution

Because this is an equation both sides have to be equal
Since the x3 gotten in a(x-1)3 =a (x3-3x2+3x-1) is the only term of that degree on the right side of the equation a=1 because the X3*1 = X3.
1(x3-3x2+3x-1) = (x3-3x2+3x-1)
b(x-1)2= b(x2-2x+1) All the x2 term’s coefficients
on the left side must add up to 5 that -3+b = 5 allows you to solve for b.
b=8
Compute the value of c such that x3+5x2-8x+3= a(x-1)3+b(x-1)2+c(x-1)+d

x3-3x2+3x-1+b(x2-2x+1) After finding b plug it back
x3-3x2+3x-1+8(x2-2x+1) into the equation.
x3-3x2+3x-1 + 8x2-16x+8
x3+5x2 -13x+7
-13+c=-8 Using the x term values from the
c=5 othertwo terms and -8 you can
solve for c.
Compute the value of c such that x3+5x2-8x+3= a(x-1)3+b(x-1)2+c(x-1)+d

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Melissa’s potw solution

by Melissa Deschamps on May 08, 2011

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