1) By equating like terms, a=1 since the coefficients of x3 must be equal.
2) Equating the coefficients of x2 gives -3+b=5, so b=8.
3) Equating the coefficients of x gives -13+c=-8, so c=5.
Q1 week 1 (common monomial,sum & diffrence of two cubes,difference of tw...Walden Macabuhay
It consists of ten units in which the first unit focuses on the special products and factors. Its deals with the study of rational algebraic expressions. It aims to empower students with life – long learning and helps them to attain functional literacy. The call of the K to 12 curriculum allow the students to have an active involvement in learning through demonstration of skills, manifestations of communication skills, development of analytical and creative thinking and understanding of mathematical applications and connections.
Q1 week 1 (common monomial,sum & diffrence of two cubes,difference of tw...Walden Macabuhay
It consists of ten units in which the first unit focuses on the special products and factors. Its deals with the study of rational algebraic expressions. It aims to empower students with life – long learning and helps them to attain functional literacy. The call of the K to 12 curriculum allow the students to have an active involvement in learning through demonstration of skills, manifestations of communication skills, development of analytical and creative thinking and understanding of mathematical applications and connections.
Algebra Presentation on Topic Modulus Function and PolynomialsAnzaLubis
Algebra Presentation on Topic Modulus Function and Polynomials
Created by: Anza Sahel Lubis and Jonathan Briant Wijaya 12 A
Performance Task Binus School Bekasi
This will help you in factoring sum and difference of two cubes.
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Algebra Presentation on Topic Modulus Function and PolynomialsAnzaLubis
Algebra Presentation on Topic Modulus Function and Polynomials
Created by: Anza Sahel Lubis and Jonathan Briant Wijaya 12 A
Performance Task Binus School Bekasi
This will help you in factoring sum and difference of two cubes.
For more instructional resources, CLICK me here!
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LIKE and FOLLOW me here!
https://tinyurl.com/ycjp8r7u
https://tinyurl.com/ybo27k2u
For more instructional resources, CLICK me here!
https://tinyurl.com/y9muob6q
LIKE and FOLLOW me here!
https://tinyurl.com/ycjp8r7u
https://tinyurl.com/ybo27k2u
Giftblooms presents top valentine day gift ideas for him. It has flowers,chocolates,cake,stuffed animals and many more for the valentine gifts delivery
NIMCET Previous Year Solved Paper 2022
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2. Because this is an equation both sides have to be equal Since the x3 gotten in a(x-1)3 =a (x3-3x2+3x-1) is the only term of that degree on the right side of the equation a=1 because the X3*1 = X3. 1(x3-3x2+3x-1) = (x3-3x2+3x-1) b(x-1)2= b(x2-2x+1) All the x2 term’s coefficients on the left side must add up to 5 that -3+b = 5 allows you to solve for b. b=8 Compute the value of c such that x3+5x2-8x+3= a(x-1)3+b(x-1)2+c(x-1)+d
3. x3-3x2+3x-1+b(x2-2x+1) After finding b plug it back x3-3x2+3x-1+8(x2-2x+1) into the equation. x3-3x2+3x-1 + 8x2-16x+8 x3+5x2 -13x+7 -13+c=-8 Using the x term values from the c=5 othertwo terms and -8 you can solve for c. Compute the value of c such that x3+5x2-8x+3= a(x-1)3+b(x-1)2+c(x-1)+d