Family members with eye cataract are shown with a solid left half of .pdf

•

0 likes•1 view

Family members with eye cataract are shown with a solid left half of the symbol; those with pituitary dwarfism are indicated by a solid right half. Individual IV-1 and IV-5 decide to have a child together. What is the probability of their first child having both eye cataracts and dwarfism? Solution If I-1 (mother) is the carrier for eye cataract and 1-2 (father) is a carrier for pituitary dwarfism, we can see that the first child is unaffected (II-1). Same case we can also find in III-5 (carrier for eye cataract) and III-6 (carrier for pituitary dwarfism) are married, their first child will be uneffected (IV-4). Ans: In the same way if IV-1 (carrier for pituitary dwarfism) marries IV-5 (carrier for eye cataract), the probability of their first child having both eye cataract and pituitary dwarfism will be Zero. Note: Probability is defined as the extent / chance of an event to occur. If the probability is 0 then it indicates that the event is impossible to occur..

Education

More from wailesalekzydelore94

Write the Java source code necessary to build a solution for EITHER of the following problem: Program A (Check password) Some websites impose certain rules for passwords. Write a method that checks whether a string is a valid password. Suppose the password rules are as follows: A password must have at least eight characters. A password consists of only letters and digits. A password must contain at least two digits. Write a program that prompts the user to enter a password and displays Valid Password if the rules are followed or Invalid Password otherwise. Program B (Count the letters in a string ) Write a method that counts the number of letters in a string using the following header: public static int countLetters(String s) Write a test program that prompts the user to enter a string and displays the number of letters in the string , not counting numbers, spaces, or symbols. Solution Program A: import java.util.Scanner; class PasswordValidity { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); boolean size; boolean special; boolean digit; int count = 0; System.out.println(\"Enter password:\"); String password = scanner.nextLine(); size = false; special = false; digit = false; int length = password.length(); count=0; int digitLen=0; while (count < length) { char ch = password.charAt(count); if (length >= 8) { size = true; } if (!Character.isLetterOrDigit(ch)) { special = true; } if (Character.isDigit(ch)) { digitLen++; digit = true; } count++; } if (size && !special && digit && digitLen>=2) { System.out.println(\" Valid Password\"); } else { System.out.println(\"Invalid Password\"); } } } Program B: import java.util.Scanner; class LetterCount { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); //String str; System.out.println(\"Enter String:\"); String str= scanner.nextLine(); int res=countLetters(str); System.out.println(\"Count: \"+res); } public static int countLetters(String s) { int length=s.length(); int count=0,c=0; while(count.

Write the Java source code necessary to build a solution for EITHER .pdf

wailesalekzydelore94

Which type of protein does DNA wrap around so that it can be packaged in a cell? 1) spliceosome proteins 2)histones 3)ribosomal proteins 4)DNA polymerase 5)topoisomerase Solution Each chromosome consists of one continuous thread-like molecule of DNA coiled tightly around proteins, and contains a portion of the 6,400,000,000 basepairs (DNA building blocks) that make up your DNA. The double helix of DNA is highly negatively charged due to all the negatively charged phosphates in the backbone. All that negative charge must be counterbalanced by a positive charge, and the cell makes proteins called histones that bind DNA and aid in DNA\'s packaging. Histones are positively charged proteins that wrap up DNA through interactions between their positive charges and the negative charges of DNA. Double-stranded DNA loops around 8 histones twice, forming the nucleosome, which is the building block of chromatin packaging. Nucleosomes stack up against one another in organized arrays with multiple levels of packing. The first level of packing is thought to produce a fiber about 30 nanometers (nm) wide. These 30 nm fibers then form a series of loops, which fold back on themselves for additional compacting. The multiple levels of packing that exist within eukaryotic chromosomes not only permit a large amount of DNA to occupy a very small space, but they also serve several functional roles..

Which type of protein does DNA wrap around so that it can be package.pdf

wailesalekzydelore94

Why is the death of Socrates important? How did it underscore or undermine his theories about morality and virtue? Solution The trial and death sentence Socrates is a crucial milestone in the history of philosophy. Socrates exemplifies the person who lives in a manner consistent with their beliefs, regardless of the consequences, in order to defend their convictions, represents an idealistic character who would not mind dying so as not to give in to his principles. This event is an icon of virtue, and quecon his death and how he endured, philosophical thought going to focus on nature, to think of human beings, far from silence their ideas, they harnessed for centuries and gave a titanic epic sieve. And philosophy was still something ethereal, now is something relevant for any human being, the debate about good and evil would not only thinkers but an ethical obligation to anyone, and also a matter of public interest..

Why is the death of Socrates important How did it underscore or und.pdf

wailesalekzydelore94

Which of the following was Darwin unaware of: Question 2 options: Genetic material within cells provides evidence of species relationships Biodiversity can be explained without relying on supernatural creation Change in populations over time in response to the environment Branching relationships between groups of organisms Genetic material within cells provides evidence of species relationships Biodiversity can be explained without relying on supernatural creation Change in populations over time in response to the environment Branching relationships between groups of organisms Solution Genetic material within cells provides evidence of species relationships..... darwin worked before the era of genetics.

Which of the following was Darwin unaware ofQuestion 2 options.pdf

wailesalekzydelore94

When an eye appears bloodshot the vessels that are visible are in wh.pdf

wailesalekzydelore94

What is body fat? Solution Body fat is the total fat content in the body . Biochemically body fat is adipose tissue, coposed of adipocytes. Humans have two kinds of adipose tissues, White adipose tissue and Brown adipose tissue White adipose tissue is mainly composed of Lipids, i.e triglycerides. Brown tissue is generally negligible. and are major store houses or energy dumps, provide cushions to your internal organs, and insulation to the body from heat and cold..

What is body fatSolutionBody fat is the total fat content in .pdf

wailesalekzydelore94

What factors affect the degree of membrane fluidity? Explain in detail the Fluid Mosaic Model. Solution Degree of membrane fluidity is affected by many factors as follows: Fluid Mosaic model describes the bilayer structure of plasma membrane having various phospholipids, cholestrols, carbohydrate, and membrane proteins embedded into it. main composition of the plasma layer is Phospholipid Bilayer Hydrophobic ends of the lipid bilayer form the skeleton of the membrane whereas hydrophilic ends form hydrogen bonds with other molecules like water on both sides of the membrane. Middle part of membrane is hydrophobic in nature. Other than lipids, proteins and carbohydrate are other main constituents of the membrane. Proteins are folded and embedded into the membrane. Carbohydrates are found at the outer part of membrane and generally are found attached to proteins or lipids..

What factors affect the degree of membrane fluidity Explain in deta.pdf

wailesalekzydelore94

The probability thatapresident of the United States attends Harvard is about 18%.The odds that a president is affiliated with the Democratic Party is roughly 36%. The probability that a president both attends Harvard and is a democrat isabout 7%. (Harvard=H,Decomcratic=D) a.What percentage ofpresidents do NOT attend Harvard NOR affiliate with thedemocratic party? b.Are H and Dmutually exclusive events? Why or why not? c. Are the two events, H and D, independent? Explain, using probabilities. d.If we knowa president is affiliated with the Democraticparty, what is the probability that they attended Harvard? Solution a) P(H U D)\' = 1 - P(H U D) = 1 - [P(H) + P(D) - P(H n D)] = 1 - (0.18+0.36-0.07) = 0.53 [answer] ********************* b) As P(H n D) =/= 0 but rather is 0.07, then they are no mutually exclusive. [NO] ********************* c) If they are independent, P(H) = P(H|D) As P(H|D) = P(H n D)/P(D) = 0.07/0.36 = 0.194444444 P(H) = 0.18 As they are not equal (although close), they are not independent. ******************** d) P(H|D) = P(H|D) = P(H n D)/P(D) = 0.07/0.36 = 0.194444444 [ANSWER].

The probability thatapresident of the United States attends Harvard .pdf

wailesalekzydelore94

The pentose phosphate cycle has an oxidative and a nonoxidative section and these are presented as both playing important metabolic roles, rather than a coupled role with a single function. How are the metabolic roles of these two parts of the pathway different from each other? Explain in terms of biochemistry Solution Answer= Function of oxidative and non-oxidative phases of pentose phosphate pathway Oxidative phase= produces NADPH = it serves as a source of electrons for the reduction of molecules during biosynthesis Nonoxidative phase=1] synthesizes 3 & 4 carbon sugars for various purposes 2] The 4 carbon sugar erythrose 4 phosphate is used to synthesize aromatic amino acids & vitamin B6 3] The pentose ribose 5-phosphate is a major component of nucleic acids, and ribulose 1,5- bisphosphate is the primary CO2 acceptor in photosynthesis. 4] Intermediates in the pentose phosphate pathway may be used to produce ATP. 5] Glyceraldehyde 3-phosphate from the pathway can enter three-carbon stage of the glycolytic pathway and be converted to ATP and pyruvate..

The pentose phosphate cycle has an oxidative and a nonoxidative sect.pdf

wailesalekzydelore94

Standpoint theory suggests that our understanding of gender-based communications acts is shaped by our standpoint in life. How does a persons standpoint as a member of one sex (male or female) shape your experiances and interactions with other? Explain how other standpoints, besides sex and gender, help you to understand your position or location within our culture. Solution Standpoint theory\'s most predominant abstraction is that an independent \'s own prospect are shaped byher or his political and social experiences. Standpoints are multifaceted rather than transitive: while Hispanic women may predominantly share some prospect, particularly with consider to ethnicity or sex, they are not explain simply by their involvement in these group. The combination of a person\'s many professional dimensions form a standpoint—a point of perspective—through which that independent sees and understands the world..

Standpoint theory suggests that our understanding of gender-based co.pdf

wailesalekzydelore94

select an engineering article/journal with ethical senerio and justify the case using NSPE CASE, not more than 500 words. Solution Under facts and circumstances of the present case , it appears that Engineer A’s actions were not under the letter or spirit of code . Act of Engineer A is a breach of trust , as he got ample opportunity to disclose his intention and his inability Some of ethical perspectives considered are (a) consequences: 4. growth and development of city could be effected . (b) Care (c) Duty He completely overlook Nolan principle of Public life i.e. Selflessness, integrity ,objectivity , accountability , openness , Honesty ,leadership (d) Virtue base thinking Following NSPE code of ethics for engineer are pertain to this case : (a)Engineers shall act in professional matters for each employer or client as faithful agents or trustees. Above code is essential for understanding between employer and employee and their future course of action would be based on faith . Engineers, when employing other engineers, shall offer a salary according to professional qualifications. Code is relevant when: Engineer hires/employs another engineer Code is violated when: Engineer offers a salary that is not commensurate with the hired engineer\'s qualifications Code is not violated when Engineer offers a salary that is commensurate with the hired engineer\'s qualifications (b) Conduct themselves honorably, responsibly, ethically, and lawfully so as to enhance the honor, reputation, and usefulness of the profession. Dignity and reputation of a person is always maintain if he follow some basic rule in his conduct i.e. reposibility , honour , ethics etc. (c) Engineers shall avoid deceptive acts. Act of engineer A , left employer in a perplexing situation as they have to wait till 23th April before outright rejection of joining by Engineer A . His act can be considered as deceptive act . (d) Engineers shall be guided in all their relations by the highest standards of honesty and integrity. According to Nolan Honesty and Integrity is basic to any public profession . Engineer A should had to maintained it . Engineers shall not falsify or permit misrepresentation of their, or their associates\', academic or professional qualifications. They shall not misrepresent or exaggerate their degree of responsibility in or for the subject matter of prior assignments. Brochures or other presentations incident to the solicitation of employment shall not misrepresent pertinent facts concerning employers, employees, associates, joint venturers, or past accomplishments with the intent and purpose of enhancing their qualifications and their work..

select an engineering articlejournal with ethical senerio and justi.pdf

wailesalekzydelore94

Que don 20 (1 point) C D You discover a heritable trait that is found in species A and B but not in species E or F which of the folowing statements about the evolution of this trait is MOST likely to be true? The trait is an example of homologous evolution EN The ancestor of E and F had the trait Solution Convergent evolution favours the selection of same structures in different ancestors. The heritable trait seen in species A or B is same as that of E or F but would be in some different form due to the convergent evolution. The convergent evolution arises independently in distantly related species..

Que don 20 (1 point) C D You discover a heritable trait that is found.pdf

wailesalekzydelore94

Parthenogenesis has been documented in most vertebrate Classes (e.g. birds, fish) but never in mammals. Genomic imprinting provides one explanation for this observation. Why? Solution Parthrnogenesis is the process of reproduction from ovum without fertilization. It has been documented in most vertebrates but never in mammals because of polyploidy and hybridisation. On the cellular level, the distinction between parthenogens and sexuals is that, meiosis is accompanied by fusion of a male and female gamete. In parthenogenesis, meiosis is changed so that only one unique set of chromosomes is transferred in a non-random fashion. Germ cell doesn’t have centrioles (they’re lost throughout gametogenesis), the lack of centrioles is not a restrict to the egg cellular. The genomic imprinting, i.e. that sure genes will no longer activate unless paternal genes are lacking. That is an trouble with mammals and no longer with the parthenogenic vertebrates because mammals have an overabundance of a protein referred to as mos. when absent, automixis occurs (it normally blocks cleavage formation inside the oocyte, therefore, the oocyte can’t undergo automixis)..

Parthenogenesis has been documented in most vertebrate Classes (e.g. .pdf

wailesalekzydelore94

organisms in this domain first produce oxygenSolutionThe three.pdf

wailesalekzydelore94

In the cae below identify the subject matter of the controversy, whether the common law or the UCC (Artlce 2) would cover the contractual issues, and explain the reasons for your conclusions. Also, discuss when, in general, the UCC (Article 2) governs contracts and when the common law governs. Kurt N. Aslakson, et al., Appellants, v. Home Savings Association, Respondent, Upper Northwest Payment Plans Co., Respondent No. C6-87-1497 Court of Appeals of Minnesota 416 N.W.2d 786; 1987 Minn. App. LEXIS 5110; 6 U.C.C. Rep. Serv. 2d (Callaghan) 35 December 3, 1987, Decided December 15, 1987, Filed PRIOR HISTORY: [**1] Appeal from Hennepin County, District Court, Hon. Ann Montgomery, Judge. DISPOSITION: Affirmed. CASE SUMMARY: PROCEDURAL POSTURE: Appellant homeowners sought review of the decision from the Hennepin County, District Court (Minnesota), which granted summary judgment in favor of respondents, savings association and payment plan, on the homeowners\' claim of tortious interference with contract. OVERVIEW: The homeowners entered into a conditional sales contract to purchase a mobile home. Subsequently the contract was assigned to the savings associationThe homeowners argued that thetrial court erred in determining, as a matter of law, that their claims of wrongful interference with contracts were invalid. The court determined that the trial court had correctly determined that a contract between the homeowners and a subsequent buyer could not arise absent performance of a condition precedent, which was the approval of the subsequent buyer\'s assumption of the loan. Even if this court were to determine that valid contracts existed between the homeowners and prospective buyers, the issue of justification would have to be addressed and the savings association and payment plan would have prevailed. Credit checks and equity interests were commercially reasonable assurances and could not be met by the prospective buyers. The savings association and payment plan were within their right to refuse the assignment. OUTCOME: The court affirmed the decision from the trial court. CORE TERMS: mobile home, materially, prospective buyer, breach of contract, assignee, buyer\'s, purchase agreement, assignor, summary judgment, down payment, substantial interest, conditional, assurances, assigned, inducing, delegate, condition precedent, contractual, contingent, delegation, tortious interference, credit check, right to refuse, wrongful interference, contractual duties, equity interest, delegating, purchaser, happening, default LexisNexis(R) Headnotes 1 of 7 4/4/12 5:11 PM http://www.lexisnexis.com/lnacui2api/delivery/PrintDoc.do?jo... Torts > Business Torts > Commercial Interference > Contracts > General Overview [HN1] \"Interference with contract\" is somewhat broader than \"inducing breach of contract\" in that the former includes any act injuring or destroying persons or property which retards, makes more difficult, or prevents performance, or makes performan.

In the cae below identify the subject matter of the controversy, whe.pdf

wailesalekzydelore94

Listed below are the major steps in protein synthesis and some events that do not occur during protein synthesis. From the list select those events that do occur in protein synthesis and place the letters of these steps in the correct chronological order. A) DNA attaches to ribosomes B) Amino acids bond to mRNA C) mRNA processed (introns removed) D) amino acids carried by tRNA joined together E) mRNA leaves nucleus F) DNA replicates itself G) mRNA replicates itself H) mRNA attaches to ribosomes I) mRNA produced using DNA as template J) tRNA and mRNA become part of finished protein K) tRNA anticodons bond to mRNA codons Solution Translation is the process where synthesis of appropriate amino acid and polypeptide chain takes place taking mRNA synthesized from the target DNA sequence as a reference. Translation takes place in the cytoplasm over the ribosomes of rough endoplasmic reticulum by a comprehensive action of mRNA, tRNA and other accessory ingredients by utilization of energy in the form of ATP. The sequential process of translation can be found as below: F) DNA replicates itself I) mRNA produced using DNA as template G) mRNA replicates itself E) mRNA leaves nucleus C) mRNA processed (introns removed) H) mRNA attaches to ribosomes D) amino acids carried by tRNA joined together K) tRNA anticodons bond to mRNA codons B) Amino acids bond to mRNA From the sequence above, it can be seen that the point A, i.e. DNA binds to ribosomes, is not included. This is because DNA does not bind directly to the ribosomes during any part of translation. Conversly, DNA is transcribed into mRNA which is translated into amino acid polypeptide on the ribosomes. Also, the point J) tRNA and mRNA become part of finished protein, is not included because tRNA and mRNA are never the part of finished protein. The protein is translated from the mRNA sequence by utilizing tRNA function..

Listed below are the major steps in protein synthesis and some event.pdf

wailesalekzydelore94

1.What are 2nd messengers? Give specific examples. How are they used un signal transduction? 2.Signal transduction by RTK signaling pathways 3.Explainhow RTK are activated and inactivated 4.Explainhow signaling pathway mutants are used to dissect the functions of signaling molecul Solution 1). Receptors are the protienious structures that act as “signal transducing molecules.” There are three kinds of membrane receptors namely, ligand gated receptors, G-protein coupled receptors and kinase linked receptors. Primary messengers receive the stimulus information from the external environment and passes into the cell. If the primary messenger cannot pass through the cell membrane, receptors use second messenger for communication between the receptor and intracellular environment. Secondary messengers relay the signal information from the receptor-ligand complex, to the interior of the cell. G-protein coupled receptors are also known as heptahelical (seven transmembrane-spanning) receptors. They are connected to the intracellular system through G-protein molecules that activate secondary messengers. The three important secondary messengers are cAMP (cyclic adenosine monophosphate), IP3 (ionositol 1,4,5-triphosphate), and DAG (diacyl glycerol). Adenylate cyclase is an enzyme that converts ATP (adenosine tri phosphate) into cAMP. cAMP is one of the important secondary messengers of G-protein receptors. Phopholipase C is an enzyme that hydrolyses phosphatidylinositol bisphosphate (PIP2) into two second messengers namely, ionositol 1,4,5-triphosphate (IP3) and diacylglycerol (DAG). Adenylate cyclase is an enzyme that converts ATP (adenosine tri phosphate) into cAMP. cAMP is one of the important secondary messengers of G-protein receptors. Phospholipase C is an enzyme that hydrolyzes phosphatidylinositol bisphosphate (PIP2) into two-second messengers namely, inositol 1,4,5-triphosphate (IP3) and diacylglycerol (DAG). IP3 increases the calcium release from endoplasmic reticulum by acting through IP3 receptors. DAG diffuses through the plasma membrane and activates protein kinase C. PKC is present in many isoforms, which is activated by raised intracellular calcium levels . Calcium activates calmodulin protein by allosteric binding and thus activates calcium- calmodulin dependent kinases. The calcium-calmodulin complex activates the myosin light chain kinases by phosphorylation, which causes muscle contraction. In contrast, the cAMP acts through Gs type of GPCRs, IP3 acts through Gq type of GPCRs. The secondary effector in cAMP pathway is PKA (protein kinase A), the secondary effector in IP3 and Calcium-mediated pathways is PKC and calmodulin (calcium directly acts on calmodulin)..

1.What are 2nd messengers Give specific examples. How are they used.pdf

wailesalekzydelore94

In a Pp heterozygous organisms, one of the chromosomes carrying the P locus is moving towards the pole at anaphase I of meiosis. In the absense of crossing overs, the P locus on this chromosome is represented by _____ dsDNA molecules with genotype ______. (name every complete allelic copy) (2, either PP or pp) I have included the answers in the parenthesis after the question. Please explain how to get the answers in details please :) Solution The organism is Pp. It will enter Meiosis I after completion of interphase. So, the genome will be ‘4n’, when entering Meiosis I, i.e. “PPpp”. Crossing over will result in formation of “PpPp”. But there is no crossing- over in Prophase I. So, “PPpp” will go into metaphase I and subsequently into Anaphase I. At anaphase I, \'PP\' will go towards one end and \'pp\' will go towards another end. So, genotypes of the two dsDNA molecules should be either \'PP\' or \'pp\'. Both will be homozygous..

In a Pp heterozygous organisms, one of the chromosomes carrying the .pdf

wailesalekzydelore94

How do vesicles carrying proteins destined for secretion move to the plasma membrane? by diffusion They swim with flagella. a long microtubules They swim with cilia a long actin The diagram to the right shows a cell and many sucrose molecules. If the cell membrane is permeable to sucrose, in which direction will the sucrose move? Into the cell Out of the cell There isn\'t enough information to let Both into rod out of the cell. The success worst move If you wanted to separated cells from a plant tissue into individual cell you would need to ? adherens junctions Primary cell walls plasmodesmata hemidemosomes middle lamella The fluid material located outside of nucleus is the nucleoplasm cytosol vacuole endoplasm protoplasm Solution 1. Vesicles carrying proteins molecules destined for secretion move along with microtubules and reach to the plasma membrane. Vesicles are carried by two motor proteins, namely kinesin and dynein. Hence, the correct answer is (c) along microtubules..

How do vesicles carrying proteins destined for secretion move to the .pdf

wailesalekzydelore94

Hi everyone I need to help me in this case study I want summary introduction and solving problems in case and conclusion and answer the questions in case Case 1-2 Kim Fuller* In the early fall of 2010, Kim Fuller was employed as a of this material was available. All that was needed was an district sales engineer for a large chemical firm. During organization to tap that bottle supply, grind the bottles, a routine discussion with plant chemists, Fuller learned and deliver the pulverized plastic to the chemical comp- that the company had developed a use for the recycled any. It was an opportunity Fuller had long awaited-a material, in pulverized form, made from plastic soft chance to start a business. drink bottles. Because the state had mandatory deposits on all beverage bottles, Fuller realized that a ready supply costs involved in setting up a plastic bottle grinding In November 2010, Fuller began checking into the business. A used truck and three trailers were acquired to pick up the empty bottles. Fuller purchased one © Professor Robert N. Anthony. Solution Fuller would require accounting information regarding the incomes and expenses done for the operations of his business. And also Fuller would be required to keep proper check and recording of the assets and liabilities held by the business and the flow of funds and cash through the business day in day out. Non-accounting information will include making cost analysis. Keeping a check on the expenses and arriving at proper alternatives to minimize the overall cost. Technology information to be competitive as new players may enter the market with technological advantage. Searching for new opportunities to grab and increase the sales and the overall market and total revenue. Fuller purchased one used truck and three trailers and one used grinding machine and a new one. He also purchased the maintenance equipment and a personal computer with software for accounting and financial information storage. All this sums up the assets of Fuller’s business with the warehouse purchased being the last one. The $75000 invested by Fuller and the $90000 invested by his brothers and sisters and the mortgage for warehouse are all his Liabilities. Fuller must value the assets on cost and decide on a depreciation method to be implemented for depreciating the fixed assets purchased over the time. The company’s opening owner’s equity is $75000 invested by Fuller and $90000 invested by his brothers and sisters. Information regarding all the expenses incurred for sales and other expenses relating to business should be recorded and reported accurately and on a timely basis. Fuller should also keep a track of the taxation policies governing the business. Subtracting the expenses total from the Income total will give fuller his profit or loss and even the break-even point from where he will start making profits. Fuller should analyze the profit and loss statement on a weekly or half monthly basis, as he is new in th.

Hi everyoneI need to help me in this case studyI want summary in.pdf

wailesalekzydelore94

More from wailesalekzydelore94 (20)