The probability thatapresident of the United States attends Harvard .pdf

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The probability thatapresident of the United States attends Harvard is about 18%.The odds that a president is affiliated with the Democratic Party is roughly 36%. The probability that a president both attends Harvard and is a democrat isabout 7%. (Harvard=H,Decomcratic=D) a.What percentage ofpresidents do NOT attend Harvard NOR affiliate with thedemocratic party? b.Are H and Dmutually exclusive events? Why or why not? c. Are the two events, H and D, independent? Explain, using probabilities. d.If we knowa president is affiliated with the Democraticparty, what is the probability that they attended Harvard? Solution a) P(H U D)\' = 1 - P(H U D) = 1 - [P(H) + P(D) - P(H n D)] = 1 - (0.18+0.36-0.07) = 0.53 [answer] ********************* b) As P(H n D) =/= 0 but rather is 0.07, then they are no mutually exclusive. [NO] ********************* c) If they are independent, P(H) = P(H|D) As P(H|D) = P(H n D)/P(D) = 0.07/0.36 = 0.194444444 P(H) = 0.18 As they are not equal (although close), they are not independent. ******************** d) P(H|D) = P(H|D) = P(H n D)/P(D) = 0.07/0.36 = 0.194444444 [ANSWER].

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The pentose phosphate cycle has an oxidative and a nonoxidative section and these are presented as both playing important metabolic roles, rather than a coupled role with a single function. How are the metabolic roles of these two parts of the pathway different from each other? Explain in terms of biochemistry Solution Answer= Function of oxidative and non-oxidative phases of pentose phosphate pathway Oxidative phase= produces NADPH = it serves as a source of electrons for the reduction of molecules during biosynthesis Nonoxidative phase=1] synthesizes 3 & 4 carbon sugars for various purposes 2] The 4 carbon sugar erythrose 4 phosphate is used to synthesize aromatic amino acids & vitamin B6 3] The pentose ribose 5-phosphate is a major component of nucleic acids, and ribulose 1,5- bisphosphate is the primary CO2 acceptor in photosynthesis. 4] Intermediates in the pentose phosphate pathway may be used to produce ATP. 5] Glyceraldehyde 3-phosphate from the pathway can enter three-carbon stage of the glycolytic pathway and be converted to ATP and pyruvate..

The pentose phosphate cycle has an oxidative and a nonoxidative sect.pdf

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Standpoint theory suggests that our understanding of gender-based communications acts is shaped by our standpoint in life. How does a persons standpoint as a member of one sex (male or female) shape your experiances and interactions with other? Explain how other standpoints, besides sex and gender, help you to understand your position or location within our culture. Solution Standpoint theory\'s most predominant abstraction is that an independent \'s own prospect are shaped byher or his political and social experiences. Standpoints are multifaceted rather than transitive: while Hispanic women may predominantly share some prospect, particularly with consider to ethnicity or sex, they are not explain simply by their involvement in these group. The combination of a person\'s many professional dimensions form a standpoint—a point of perspective—through which that independent sees and understands the world..

Standpoint theory suggests that our understanding of gender-based co.pdf

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select an engineering article/journal with ethical senerio and justify the case using NSPE CASE, not more than 500 words. Solution Under facts and circumstances of the present case , it appears that Engineer A’s actions were not under the letter or spirit of code . Act of Engineer A is a breach of trust , as he got ample opportunity to disclose his intention and his inability Some of ethical perspectives considered are (a) consequences: 4. growth and development of city could be effected . (b) Care (c) Duty He completely overlook Nolan principle of Public life i.e. Selflessness, integrity ,objectivity , accountability , openness , Honesty ,leadership (d) Virtue base thinking Following NSPE code of ethics for engineer are pertain to this case : (a)Engineers shall act in professional matters for each employer or client as faithful agents or trustees. Above code is essential for understanding between employer and employee and their future course of action would be based on faith . Engineers, when employing other engineers, shall offer a salary according to professional qualifications. Code is relevant when: Engineer hires/employs another engineer Code is violated when: Engineer offers a salary that is not commensurate with the hired engineer\'s qualifications Code is not violated when Engineer offers a salary that is commensurate with the hired engineer\'s qualifications (b) Conduct themselves honorably, responsibly, ethically, and lawfully so as to enhance the honor, reputation, and usefulness of the profession. Dignity and reputation of a person is always maintain if he follow some basic rule in his conduct i.e. reposibility , honour , ethics etc. (c) Engineers shall avoid deceptive acts. Act of engineer A , left employer in a perplexing situation as they have to wait till 23th April before outright rejection of joining by Engineer A . His act can be considered as deceptive act . (d) Engineers shall be guided in all their relations by the highest standards of honesty and integrity. According to Nolan Honesty and Integrity is basic to any public profession . Engineer A should had to maintained it . Engineers shall not falsify or permit misrepresentation of their, or their associates\', academic or professional qualifications. They shall not misrepresent or exaggerate their degree of responsibility in or for the subject matter of prior assignments. Brochures or other presentations incident to the solicitation of employment shall not misrepresent pertinent facts concerning employers, employees, associates, joint venturers, or past accomplishments with the intent and purpose of enhancing their qualifications and their work..

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Que don 20 (1 point) C D You discover a heritable trait that is found in species A and B but not in species E or F which of the folowing statements about the evolution of this trait is MOST likely to be true? The trait is an example of homologous evolution EN The ancestor of E and F had the trait Solution Convergent evolution favours the selection of same structures in different ancestors. The heritable trait seen in species A or B is same as that of E or F but would be in some different form due to the convergent evolution. The convergent evolution arises independently in distantly related species..

Que don 20 (1 point) C D You discover a heritable trait that is found.pdf

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Parthenogenesis has been documented in most vertebrate Classes (e.g. birds, fish) but never in mammals. Genomic imprinting provides one explanation for this observation. Why? Solution Parthrnogenesis is the process of reproduction from ovum without fertilization. It has been documented in most vertebrates but never in mammals because of polyploidy and hybridisation. On the cellular level, the distinction between parthenogens and sexuals is that, meiosis is accompanied by fusion of a male and female gamete. In parthenogenesis, meiosis is changed so that only one unique set of chromosomes is transferred in a non-random fashion. Germ cell doesn’t have centrioles (they’re lost throughout gametogenesis), the lack of centrioles is not a restrict to the egg cellular. The genomic imprinting, i.e. that sure genes will no longer activate unless paternal genes are lacking. That is an trouble with mammals and no longer with the parthenogenic vertebrates because mammals have an overabundance of a protein referred to as mos. when absent, automixis occurs (it normally blocks cleavage formation inside the oocyte, therefore, the oocyte can’t undergo automixis)..

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organisms in this domain first produce oxygenSolutionThe three.pdf

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In the cae below identify the subject matter of the controversy, whether the common law or the UCC (Artlce 2) would cover the contractual issues, and explain the reasons for your conclusions. Also, discuss when, in general, the UCC (Article 2) governs contracts and when the common law governs. Kurt N. Aslakson, et al., Appellants, v. Home Savings Association, Respondent, Upper Northwest Payment Plans Co., Respondent No. C6-87-1497 Court of Appeals of Minnesota 416 N.W.2d 786; 1987 Minn. App. LEXIS 5110; 6 U.C.C. Rep. Serv. 2d (Callaghan) 35 December 3, 1987, Decided December 15, 1987, Filed PRIOR HISTORY: [**1] Appeal from Hennepin County, District Court, Hon. Ann Montgomery, Judge. DISPOSITION: Affirmed. CASE SUMMARY: PROCEDURAL POSTURE: Appellant homeowners sought review of the decision from the Hennepin County, District Court (Minnesota), which granted summary judgment in favor of respondents, savings association and payment plan, on the homeowners\' claim of tortious interference with contract. OVERVIEW: The homeowners entered into a conditional sales contract to purchase a mobile home. Subsequently the contract was assigned to the savings associationThe homeowners argued that thetrial court erred in determining, as a matter of law, that their claims of wrongful interference with contracts were invalid. The court determined that the trial court had correctly determined that a contract between the homeowners and a subsequent buyer could not arise absent performance of a condition precedent, which was the approval of the subsequent buyer\'s assumption of the loan. Even if this court were to determine that valid contracts existed between the homeowners and prospective buyers, the issue of justification would have to be addressed and the savings association and payment plan would have prevailed. Credit checks and equity interests were commercially reasonable assurances and could not be met by the prospective buyers. The savings association and payment plan were within their right to refuse the assignment. OUTCOME: The court affirmed the decision from the trial court. CORE TERMS: mobile home, materially, prospective buyer, breach of contract, assignee, buyer\'s, purchase agreement, assignor, summary judgment, down payment, substantial interest, conditional, assurances, assigned, inducing, delegate, condition precedent, contractual, contingent, delegation, tortious interference, credit check, right to refuse, wrongful interference, contractual duties, equity interest, delegating, purchaser, happening, default LexisNexis(R) Headnotes 1 of 7 4/4/12 5:11 PM http://www.lexisnexis.com/lnacui2api/delivery/PrintDoc.do?jo... Torts > Business Torts > Commercial Interference > Contracts > General Overview [HN1] \"Interference with contract\" is somewhat broader than \"inducing breach of contract\" in that the former includes any act injuring or destroying persons or property which retards, makes more difficult, or prevents performance, or makes performan.

In the cae below identify the subject matter of the controversy, whe.pdf

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Listed below are the major steps in protein synthesis and some events that do not occur during protein synthesis. From the list select those events that do occur in protein synthesis and place the letters of these steps in the correct chronological order. A) DNA attaches to ribosomes B) Amino acids bond to mRNA C) mRNA processed (introns removed) D) amino acids carried by tRNA joined together E) mRNA leaves nucleus F) DNA replicates itself G) mRNA replicates itself H) mRNA attaches to ribosomes I) mRNA produced using DNA as template J) tRNA and mRNA become part of finished protein K) tRNA anticodons bond to mRNA codons Solution Translation is the process where synthesis of appropriate amino acid and polypeptide chain takes place taking mRNA synthesized from the target DNA sequence as a reference. Translation takes place in the cytoplasm over the ribosomes of rough endoplasmic reticulum by a comprehensive action of mRNA, tRNA and other accessory ingredients by utilization of energy in the form of ATP. The sequential process of translation can be found as below: F) DNA replicates itself I) mRNA produced using DNA as template G) mRNA replicates itself E) mRNA leaves nucleus C) mRNA processed (introns removed) H) mRNA attaches to ribosomes D) amino acids carried by tRNA joined together K) tRNA anticodons bond to mRNA codons B) Amino acids bond to mRNA From the sequence above, it can be seen that the point A, i.e. DNA binds to ribosomes, is not included. This is because DNA does not bind directly to the ribosomes during any part of translation. Conversly, DNA is transcribed into mRNA which is translated into amino acid polypeptide on the ribosomes. Also, the point J) tRNA and mRNA become part of finished protein, is not included because tRNA and mRNA are never the part of finished protein. The protein is translated from the mRNA sequence by utilizing tRNA function..

Listed below are the major steps in protein synthesis and some event.pdf

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1.What are 2nd messengers? Give specific examples. How are they used un signal transduction? 2.Signal transduction by RTK signaling pathways 3.Explainhow RTK are activated and inactivated 4.Explainhow signaling pathway mutants are used to dissect the functions of signaling molecul Solution 1). Receptors are the protienious structures that act as “signal transducing molecules.” There are three kinds of membrane receptors namely, ligand gated receptors, G-protein coupled receptors and kinase linked receptors. Primary messengers receive the stimulus information from the external environment and passes into the cell. If the primary messenger cannot pass through the cell membrane, receptors use second messenger for communication between the receptor and intracellular environment. Secondary messengers relay the signal information from the receptor-ligand complex, to the interior of the cell. G-protein coupled receptors are also known as heptahelical (seven transmembrane-spanning) receptors. They are connected to the intracellular system through G-protein molecules that activate secondary messengers. The three important secondary messengers are cAMP (cyclic adenosine monophosphate), IP3 (ionositol 1,4,5-triphosphate), and DAG (diacyl glycerol). Adenylate cyclase is an enzyme that converts ATP (adenosine tri phosphate) into cAMP. cAMP is one of the important secondary messengers of G-protein receptors. Phopholipase C is an enzyme that hydrolyses phosphatidylinositol bisphosphate (PIP2) into two second messengers namely, ionositol 1,4,5-triphosphate (IP3) and diacylglycerol (DAG). Adenylate cyclase is an enzyme that converts ATP (adenosine tri phosphate) into cAMP. cAMP is one of the important secondary messengers of G-protein receptors. Phospholipase C is an enzyme that hydrolyzes phosphatidylinositol bisphosphate (PIP2) into two-second messengers namely, inositol 1,4,5-triphosphate (IP3) and diacylglycerol (DAG). IP3 increases the calcium release from endoplasmic reticulum by acting through IP3 receptors. DAG diffuses through the plasma membrane and activates protein kinase C. PKC is present in many isoforms, which is activated by raised intracellular calcium levels . Calcium activates calmodulin protein by allosteric binding and thus activates calcium- calmodulin dependent kinases. The calcium-calmodulin complex activates the myosin light chain kinases by phosphorylation, which causes muscle contraction. In contrast, the cAMP acts through Gs type of GPCRs, IP3 acts through Gq type of GPCRs. The secondary effector in cAMP pathway is PKA (protein kinase A), the secondary effector in IP3 and Calcium-mediated pathways is PKC and calmodulin (calcium directly acts on calmodulin)..

1.What are 2nd messengers Give specific examples. How are they used.pdf

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In a Pp heterozygous organisms, one of the chromosomes carrying the P locus is moving towards the pole at anaphase I of meiosis. In the absense of crossing overs, the P locus on this chromosome is represented by _____ dsDNA molecules with genotype ______. (name every complete allelic copy) (2, either PP or pp) I have included the answers in the parenthesis after the question. Please explain how to get the answers in details please :) Solution The organism is Pp. It will enter Meiosis I after completion of interphase. So, the genome will be ‘4n’, when entering Meiosis I, i.e. “PPpp”. Crossing over will result in formation of “PpPp”. But there is no crossing- over in Prophase I. So, “PPpp” will go into metaphase I and subsequently into Anaphase I. At anaphase I, \'PP\' will go towards one end and \'pp\' will go towards another end. So, genotypes of the two dsDNA molecules should be either \'PP\' or \'pp\'. Both will be homozygous..

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How do vesicles carrying proteins destined for secretion move to the plasma membrane? by diffusion They swim with flagella. a long microtubules They swim with cilia a long actin The diagram to the right shows a cell and many sucrose molecules. If the cell membrane is permeable to sucrose, in which direction will the sucrose move? Into the cell Out of the cell There isn\'t enough information to let Both into rod out of the cell. The success worst move If you wanted to separated cells from a plant tissue into individual cell you would need to ? adherens junctions Primary cell walls plasmodesmata hemidemosomes middle lamella The fluid material located outside of nucleus is the nucleoplasm cytosol vacuole endoplasm protoplasm Solution 1. Vesicles carrying proteins molecules destined for secretion move along with microtubules and reach to the plasma membrane. Vesicles are carried by two motor proteins, namely kinesin and dynein. Hence, the correct answer is (c) along microtubules..

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Hi everyone I need to help me in this case study I want summary introduction and solving problems in case and conclusion and answer the questions in case Case 1-2 Kim Fuller* In the early fall of 2010, Kim Fuller was employed as a of this material was available. All that was needed was an district sales engineer for a large chemical firm. During organization to tap that bottle supply, grind the bottles, a routine discussion with plant chemists, Fuller learned and deliver the pulverized plastic to the chemical comp- that the company had developed a use for the recycled any. It was an opportunity Fuller had long awaited-a material, in pulverized form, made from plastic soft chance to start a business. drink bottles. Because the state had mandatory deposits on all beverage bottles, Fuller realized that a ready supply costs involved in setting up a plastic bottle grinding In November 2010, Fuller began checking into the business. A used truck and three trailers were acquired to pick up the empty bottles. Fuller purchased one © Professor Robert N. Anthony. Solution Fuller would require accounting information regarding the incomes and expenses done for the operations of his business. And also Fuller would be required to keep proper check and recording of the assets and liabilities held by the business and the flow of funds and cash through the business day in day out. Non-accounting information will include making cost analysis. Keeping a check on the expenses and arriving at proper alternatives to minimize the overall cost. Technology information to be competitive as new players may enter the market with technological advantage. Searching for new opportunities to grab and increase the sales and the overall market and total revenue. Fuller purchased one used truck and three trailers and one used grinding machine and a new one. He also purchased the maintenance equipment and a personal computer with software for accounting and financial information storage. All this sums up the assets of Fuller’s business with the warehouse purchased being the last one. The $75000 invested by Fuller and the $90000 invested by his brothers and sisters and the mortgage for warehouse are all his Liabilities. Fuller must value the assets on cost and decide on a depreciation method to be implemented for depreciating the fixed assets purchased over the time. The company’s opening owner’s equity is $75000 invested by Fuller and $90000 invested by his brothers and sisters. Information regarding all the expenses incurred for sales and other expenses relating to business should be recorded and reported accurately and on a timely basis. Fuller should also keep a track of the taxation policies governing the business. Subtracting the expenses total from the Income total will give fuller his profit or loss and even the break-even point from where he will start making profits. Fuller should analyze the profit and loss statement on a weekly or half monthly basis, as he is new in th.

Hi everyoneI need to help me in this case studyI want summary in.pdf

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Explain why a gallstone located in the bile duct at a point distal to the entry of the pancreatic duct might result in elevations of serum amylase and serum lipase (perhaps as high as three times the normal values) and abdominal pain. Neuroendocrine tumors (NETs), also known as “islet cell tumors” are relatively rare cancers for which the majority (85%) function to produce hormones. NETs include Insulinomas, Gastrinomas, and Glucagonomas. In fact Zollinger-Ellison Syndrome (ZES) is the cause of a form of peptic ulcer disease (PUD) resulting from neoplastic duodenal or pancreatic G cells. Describe how a gastrinoma causing ZES might cause PUD and discuss the extent to which H2-receptor antagonists or proton pump inhibitors would be effective in reducing the symptoms associated with ZES. Solution Ques-1: Explain why a gallstone located in the bile duct at a point distal to the entry of the pancreatic duct might result in elevations of serum amylase and serum lipase (perhaps as high as three times the normal values) and abdominal pain. Answer: The bile duct is a vessel, which drains the bile juices into the digestive tract. These bile juices help in emulsifying fats and enhance their breakdown in body. A gallstone located in the bile duct at a point distal to the entry of the pancreatic duct might result in elevations of serum amylase and serum lipase because acute pancreatitis in which \"lower acinar cell mass\" may be observed along with macroamylasemia and under severe conditions, it leads to Jaundice (due to block of pancreatic duct) Ques-2: Neuroendocrine tumors also referred as islet cell tumors are relatively rare cancers for which the majority (85%) functions to produce hormones. These tumors are also a precursor for generation of Zollinger-Ellison syndrome or peptic ulcer disease. The major gastrinoma causing zollinger- ellison syndrome is due to chronic carcinoma developed from peptic ulcer. This peptic ulcer formation is due to either stress or due to Helicobacterium pylori. Gastrinoma is mainly associated with gastric parietal cell apoptosis and leading to caspase mediated gastric cell necrosis & apoptosis through extrinsic and intrinsic apoptotic mechanisms. This apoptosis is leading to gastrinoma with peptic ulcer disease due to severe acid secretion through histamine- mediated activity. This is also due to the following infection inside gastric area. Bacteria, Helicobacterium pylori produces, catalase, urease positive tests and showing up biofilm formation on gastric mucosal layers with several colonies (coccoid forms) on his stomach biopsy slides. It can be visualized using scanning electron microscopy & confocal microscopy. These are flagellated & phospholipids and lipopolysaccharide. Helicobacterium pylori feeds on mucosal cells finally due to the rupture of mucosal layer, the gastric juices secreted directly attack the abdominal wall. This causes severe pain in the mid of the abdomen or upper abdominal region. Proton pump inhib.

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Family members with eye cataract are shown with a solid left half of the symbol; those with pituitary dwarfism are indicated by a solid right half. Individual IV-1 and IV-5 decide to have a child together. What is the probability of their first child having both eye cataracts and dwarfism? Solution If I-1 (mother) is the carrier for eye cataract and 1-2 (father) is a carrier for pituitary dwarfism, we can see that the first child is unaffected (II-1). Same case we can also find in III-5 (carrier for eye cataract) and III-6 (carrier for pituitary dwarfism) are married, their first child will be uneffected (IV-4). Ans: In the same way if IV-1 (carrier for pituitary dwarfism) marries IV-5 (carrier for eye cataract), the probability of their first child having both eye cataract and pituitary dwarfism will be Zero. Note: Probability is defined as the extent / chance of an event to occur. If the probability is 0 then it indicates that the event is impossible to occur..

Family members with eye cataract are shown with a solid left half of .pdf

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Do routers have IP addresses? If so, how many? Please explain answer Solution Answer: Yes , a router can have as many IPs as you assign to it , but there is only one IP address per interface. You might be well aware of the routers functionalities. It creates a routing table for IP addresses. Routing table consists of many ips , with subnet masks. So routers can have as many ip addresses as you can give to it. It stores the ip addresses into the routing table and forwards them into different networks they belong to..

Do routers have IP addresses If so, how many Please explain answer.pdf

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discuss the importance of The Age discrimination in employment act (ADEA) and its applicability in healthcare. Solution The Age Discrimination in Employment Act provides the rights to an employee so that the employer cannot refuse to hire or does not allow the discrimination if the employee is 40 or older. Through ADEA, the employee will get all the pay benefits and it will not allow the employer to classify the workers based on their age and to deprive them of their opportunities or declining them from getting promoted. The Age Discrimination in Employment Act functioning will be found similar to other federal discrimination laws and through this law who are covering can be known. In healthcare system also this ADEA law is playing an important role, in understanding the role of physicians and nurses, and how aged health care workers can provide high-quality health services in many chronic conditions. In many cases the ADEA law will protect the rights of the patients, he cannot be denied to offer any type of treatment by showing his age, and all elderly patients should get similar type of treatment..

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Cocaine sometimes produces extreme alertness and an exaggerated awareness of environmental stimuli. This is because one of its effects is to enhance the activity of the neurotransmitter that helps prepare the body for stressful situations, namely: A. serotonin B.endorphins C.acetylcholine D.Norepinephrine Solution D) NOREPINEPHRINE.....it is the stressful situation harmone ...cocaine blocks neurotransmiter transportersinthe brain hence increasing the concentration of norepinephrinein the synapse ....

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Catalysts are molecules that lower the activation energy for a given reaction. Cells produce their own catalysts called proteins enzymes cofactors complexes Solution Answer : The correct answer is B (Enzymes) Explanation : Enzymes are the biocatalysts - the catalysts of life. A catalyst is defined as the as the substance that increases the velocity or rate of the chemical reaction without itself undergoing any change in the overall process..

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(Match grouping symbols) A Java program contains various pairs of grouping symbols, such as: Parentheses: ( and ) Braces: { and } Brackets: [ and ] Note that the grouping symbols cannot overlap. For example, (a{b)} is illegal. Write a program to check whether a Java source-code file has correct pairs of grouping symbols. Pass the source- code file name as a command-line argument. Solution // GroupingSymbols.java import java.io.*; import java.util.*; public class GroupingSymbols { public static void main(String[] args) { if (args.length != 1) { System.out.println(\"Usage: filename\"); System.exit(0); } File inputFile = new File(args[0]); // Check if file exists if (!inputFile.exists()) { System.out.println(\"File does not exist!\"); System.exit(1); } // Create a stack Stack charstack = new Stack<>(); // arraylist ArrayList symbolarray = new ArrayList<>(); // addinng all symbols to collection Collections.addAll(symbolarray, \"(\", \")\", \"{\", \"}\", \"[\", \"]\"); try(BufferedReader bf = new BufferedReader(new InputStreamReader(new FileInputStream(inputFile)))) { String str; while ((str = bf.readLine()) != null) { for (char character : str.toCharArray()) { String s = character + \"\"; int sIndex = symbolarray.indexOf(s); if (sIndex == -1) continue; if (charstack.size() == 0) { charstack.push(s); } else { int lIndex = symbolarray.indexOf(charstack.peek()); if (sIndex - 1 == lIndex) { charstack.pop(); } else { if ((lIndex & 1) == 1) { System.out.println(\"ERROR at:\" + str); } charstack.push(s); } } } } } catch (FileNotFoundException exception) { System.out.println(\"File not found.\"); exception.printStackTrace(); } catch (IOException exception) { System.out.println(\"IO error.\"); exception.printStackTrace(); } } }.

(Match grouping symbols) A Java program contains various pairs of gr.pdf

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