The document discusses finding the locus of complex numbers ω or z given some condition on ω or z. It provides examples of determining the locus when:
1) ω is purely real or purely imaginary, which results in the locus being lines.
2) The argument of a linear function of z equals an angle θ, which results in the locus being an arc of a circle.
3) An example is worked through where the locus is a circle with center (1,0) and radius 1/2.
4) Another example finds the locus of z if w is purely real, which results in the locus being the x-axis where y=0.
The document discusses finding the locus of complex numbers ω or z given some condition on ω or z, where ω = f(z). It provides examples of determining the locus when:
1) ω is purely real or purely imaginary
2) The argument of a linear function of ω or z is equal to an angle θ
3) z satisfies the condition w = (z + 1)/(z - 1) and w is purely real
In the examples, it is shown that the loci are circles, lines, or the real axis depending on the specific condition given. The steps involve making the condition the subject of the equation and then solving to determine the locus.
The document discusses finding the locus of complex numbers ω or z given some condition on ω or z. It provides examples of finding the locus when:
1) ω is a linear function of z and the condition is that ω is purely real or purely imaginary. The locus is an arc of a circle.
2) The condition is that the argument of a linear function of ω equals a constant θ. The locus is an arc of a circle that can be a minor arc, major arc, or semicircle depending on the value of θ.
3) An example finds the locus is a circle when ω is a rational function of z and the condition is that z equals a constant.
4) Another
This document discusses polar form and DeMoivre's theorem for complex numbers. It begins by introducing polar form, which represents a complex number z as z = r(cosθ + i sinθ) where r is the modulus and θ is the argument. It then states DeMoivre's theorem, which says that for any positive integer n, zn = rn(cosnθ + i sinnθ). An example calculates (−1 + √3i)12 by first converting to polar form and then applying DeMoivre's theorem.
This document is Northern States Power Company's (NSP-Minnesota) annual report on Form 10-K filed with the SEC for the fiscal year ended December 31, 2007. NSP-Minnesota generates, transmits, and distributes electricity and distributes and transports natural gas. It serves approximately 1.4 million electric customers and 500,000 natural gas customers across Minnesota, North Dakota, and South Dakota. NSP-Minnesota's electric and natural gas operations are regulated by several state and federal regulatory agencies. Key issues addressed in the filing include NSP-Minnesota's rates and cost recovery, energy sources, fuel costs, environmental matters, and risk factors.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document discusses finding the locus of complex numbers ω or z given some condition on ω or z, where ω = f(z). It provides examples of determining the locus when:
1) ω is purely real or purely imaginary
2) The argument of a linear function of ω or z is equal to an angle θ
3) z satisfies the condition w = (z + 1)/(z - 1) and w is purely real
In the examples, it is shown that the loci are circles, lines, or the real axis depending on the specific condition given. The steps involve making the condition the subject of the equation and then solving to determine the locus.
The document discusses finding the locus of complex numbers ω or z given some condition on ω or z. It provides examples of finding the locus when:
1) ω is a linear function of z and the condition is that ω is purely real or purely imaginary. The locus is an arc of a circle.
2) The condition is that the argument of a linear function of ω equals a constant θ. The locus is an arc of a circle that can be a minor arc, major arc, or semicircle depending on the value of θ.
3) An example finds the locus is a circle when ω is a rational function of z and the condition is that z equals a constant.
4) Another
This document discusses polar form and DeMoivre's theorem for complex numbers. It begins by introducing polar form, which represents a complex number z as z = r(cosθ + i sinθ) where r is the modulus and θ is the argument. It then states DeMoivre's theorem, which says that for any positive integer n, zn = rn(cosnθ + i sinnθ). An example calculates (−1 + √3i)12 by first converting to polar form and then applying DeMoivre's theorem.
This document is Northern States Power Company's (NSP-Minnesota) annual report on Form 10-K filed with the SEC for the fiscal year ended December 31, 2007. NSP-Minnesota generates, transmits, and distributes electricity and distributes and transports natural gas. It serves approximately 1.4 million electric customers and 500,000 natural gas customers across Minnesota, North Dakota, and South Dakota. NSP-Minnesota's electric and natural gas operations are regulated by several state and federal regulatory agencies. Key issues addressed in the filing include NSP-Minnesota's rates and cost recovery, energy sources, fuel costs, environmental matters, and risk factors.
Slideshare is discontinuing its Slidecast feature as of February 28, 2014. Existing Slidecasts will be converted to static presentations without audio by April 30, 2014. The document informs users that new slidecasts can be found on myPlick.com or the author's blog starting in 2014. However, myPlick proved unreliable, so future slidecasts will instead be hosted on the author's YouTube channel.
The document discusses different methods for factorising expressions:
1) Looking for a common factor and dividing it out of all terms
2) Using the difference of two squares formula (a2 - b2 = (a - b)(a + b))
3) Factorising quadratic trinomials into two binomial factors by identifying the values that multiply to give the constant term and sum to give the coefficient of the linear term.
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
0
The document discusses the relationship between integration and calculating the area under a curve. It shows that the area under a curve from x=a to x=b can be calculated as the integral from a to b of the function f(x) dx. This is equal to the antiderivative F(x) evaluated from b to a. The area under a curve can also be estimated using rectangles, and as the width of the rectangles approaches 0, the estimate becomes the exact area. The derivative of the area function A(x) gives the equation of the curve f(x). Examples are given to calculate the exact area under curves.
The document discusses nth roots of unity. It states that the solutions to equations of the form zn = ±1 are the nth roots of unity. These solutions form a regular n-sided polygon with vertices on the unit circle when placed on an Argand diagram. As an example, it shows that the solutions to z5 = 1 are the fifth roots of unity located at angles that are integer multiples of 2π/5 around the unit circle. It then proves that if ω is a root of z5 - 1 = 0, then ω2, ω3, ω4 and ω5 are also roots. Finally, it proves that 1 + ω + ω2 + ω3 + ω4 = 0.
हिंदी वर्णमाला पीपीटी, hindi alphabet PPT presentation, hindi varnamala PPT, Hindi Varnamala pdf, हिंदी स्वर, हिंदी व्यंजन, sikhiye hindi varnmala, dr. mulla adam ali, hindi language and literature, hindi alphabet with drawing, hindi alphabet pdf, hindi varnamala for childrens, hindi language, hindi varnamala practice for kids, https://www.drmullaadamali.com
The document provides information on index laws and the meaning of indices in algebra:
- Index laws state that am × an = am+n, am ÷ an = am-n, and (am)n = amn. Exponents can be added or subtracted when multiplying or dividing terms with the same base.
- Positive exponents indicate a term is raised to a power. Negative exponents indicate a root is being taken. Terms with exponents are evaluated from left to right.
- Examples demonstrate how to simplify expressions using index laws and interpret different types of indices.
12 x1 t01 03 integrating derivative on function (2013)Nigel Simmons
The document discusses integrating derivatives of functions. It states that the integral of the derivative of a function f(x) is equal to the natural log of f(x) plus a constant. It then provides examples of integrating several derivatives: (i) ∫(1/(7-3x)) dx = -1/3 log(7-3x) + c, (ii) ∫(1/(8x+5)) dx = 1/8 log(8x+5) + c, and (iii) ∫(x5/(x-2)) dx = 1/6 log(x6-2) + c. It also discusses techniques for integrating fractions by polynomial long division and finds
The document discusses logarithms and their properties. Logarithms are defined as the inverse of exponentials. If y = ax, then x = loga y. The natural logarithm is log base e, written as ln. Properties of logarithms include: loga m + loga n = loga mn; loga m - loga n = loga(m/n); loga mn = n loga m; loga 1 = 0; loga a = 1. Examples of evaluating logarithmic expressions are provided.
The document discusses relationships between the coefficients and roots of polynomials. It states that for a polynomial P(x) = axn + bxn-1 + cxn-2 + ..., the sum of the roots equals -b/a, the sum of the roots taken two at a time equals c/a, and so on for higher order terms. It also provides examples of using these relationships to find the sums of roots for a given polynomial.
P
4
3
2
The document discusses properties of polynomials with multiple roots. It first proves that if a polynomial P(x) has a root x = a of multiplicity m, then the derivative of P(x), P'(x), will have a root x = a of multiplicity m-1. It then provides an example of solving a cubic equation given it has a double root. Finally, it examines a quartic polynomial and shows that its root α cannot be 0, 1, or -1, and that 1/
The document discusses factorizing complex expressions. The main points are:
- If a polynomial's coefficients are real, its roots will appear in complex conjugate pairs.
- Any polynomial of degree n can be factorized into a mixture of quadratic and linear factors over real numbers, or into n linear factors over complex numbers.
- Odd degree polynomials must have at least one real root.
- Examples of factorizing polynomials over both real and complex numbers are provided.
The document describes the Trapezoidal Rule for approximating the area under a curve between two points. It shows that the area A is estimated by dividing the region into trapezoids with height equal to the function values at the interval endpoints and bases equal to the intervals. In general, the area is approximated as the sum of the areas of each trapezoid, which is equal to the average of the endpoint function values multiplied by the interval length.
The document discusses methods for calculating the volumes of solids of revolution. It provides formulas for finding volumes when an area is revolved around either the x-axis or y-axis. Examples are given for finding volumes of common solids like cones, spheres, and others. Steps are shown for using the formulas to calculate volumes based on given functions and limits of revolution.
The document discusses different methods for calculating the area under a curve or between curves.
(1) The area below the x-axis is given by the integral of the function between the bounds, which can be positive or negative depending on whether the area is above or below the x-axis.
(2) To calculate the area on the y-axis, the function is solved for x in terms of y, then the bounds are substituted into the integral of this new function with respect to y.
(3) The area between two curves is calculated by taking the integral of the upper curve minus the integral of the lower curve, both between the same bounds on the x-axis.
The document discusses 8 properties of definite integrals:
1) Integrating polynomials results in a fraction.
2) Constants can be factored out of integrals.
3) Integrals of sums are equal to the sum of integrals.
4) Splitting an integral range results in the sum of the integrals.
5) Integrals of positive functions over a range are positive, and negative if the function is negative.
6) Integrals can be compared based on the relative values of the integrands.
7) Changing the limits of integration flips the sign of the integral.
8) Integrals of odd functions over a symmetric range are zero, and integrals of even functions are twice the integral over
0
The document discusses the relationship between integration and calculating the area under a curve. It shows that the area under a curve from x=a to x=b can be calculated as the integral from a to b of the function f(x) dx. This is equal to the antiderivative F(x) evaluated from b to a. The area under a curve can also be estimated using rectangles, and as the width of the rectangles approaches 0, the estimate becomes the exact area. The derivative of the area function A(x) gives the equation of the curve f(x). Examples are given to calculate the exact area under curves.
The document discusses nth roots of unity. It states that the solutions to equations of the form zn = ±1 are the nth roots of unity. These solutions form a regular n-sided polygon with vertices on the unit circle when placed on an Argand diagram. As an example, it shows that the solutions to z5 = 1 are the fifth roots of unity located at angles that are integer multiples of 2π/5 around the unit circle. It then proves that if ω is a root of z5 - 1 = 0, then ω2, ω3, ω4 and ω5 are also roots. Finally, it proves that 1 + ω + ω2 + ω3 + ω4 = 0.
हिंदी वर्णमाला पीपीटी, hindi alphabet PPT presentation, hindi varnamala PPT, Hindi Varnamala pdf, हिंदी स्वर, हिंदी व्यंजन, sikhiye hindi varnmala, dr. mulla adam ali, hindi language and literature, hindi alphabet with drawing, hindi alphabet pdf, hindi varnamala for childrens, hindi language, hindi varnamala practice for kids, https://www.drmullaadamali.com
Walmart Business+ and Spark Good for Nonprofits.pdfTechSoup
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analytics” feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...PECB
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
-------------------------------------------------------------------------------
Find out more about ISO training and certification services
Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
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For more information about PECB:
Website: https://pecb.com/
LinkedIn: https://www.linkedin.com/company/pecb/
Facebook: https://www.facebook.com/PECBInternational/
Slideshare: http://www.slideshare.net/PECBCERTIFICATION
This presentation includes basic of PCOS their pathology and treatment and also Ayurveda correlation of PCOS and Ayurvedic line of treatment mentioned in classics.
Strategies for Effective Upskilling is a presentation by Chinwendu Peace in a Your Skill Boost Masterclass organisation by the Excellence Foundation for South Sudan on 08th and 09th June 2024 from 1 PM to 3 PM on each day.
Main Java[All of the Base Concepts}.docxadhitya5119
This is part 1 of my Java Learning Journey. This Contains Custom methods, classes, constructors, packages, multithreading , try- catch block, finally block and more.
How to Make a Field Mandatory in Odoo 17Celine George
In Odoo, making a field required can be done through both Python code and XML views. When you set the required attribute to True in Python code, it makes the field required across all views where it's used. Conversely, when you set the required attribute in XML views, it makes the field required only in the context of that particular view.
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
2. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
3. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
4. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
5. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
is purely imaginary Re 0, arg
2
6. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
is purely imaginary Re 0, arg
2
linear function
arg locus is an arc of a circle
linear function
7. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
is purely imaginary Re 0, arg
2
linear function
arg locus is an arc of a circle
linear function
* minor arc if
2
8. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
is purely imaginary Re 0, arg
2
linear function
arg locus is an arc of a circle
linear function
* minor arc if
2
* major arc if
2
9. Locus and Complex Numbers
f z , find the locus of or z
given some condition for or z
(Make the condition the subject)
is purely real Im 0, arg 0 or
is purely imaginary Re 0, arg
2
linear function
arg locus is an arc of a circle
linear function
* minor arc if
2
* major arc if
2
* semicircle if
2
11. z2
e.g .i Find the locus of w if w ,z 4
2
z2
w
z
12. z2
e.g .i Find the locus of w if w ,z 4
2
z2
w
z
zw z 2
13. z2
e.g .i Find the locus of w if w ,z 4
2
z2
w
z
zw z 2
z w 1 2
14. z2
e.g .i Find the locus of w if w ,z 4
2
z2
w
z
zw z 2
z w 1 2
2
z
w 1
15. z2
e.g .i Find the locus of w if w ,z 4
2
z2 2
w 4
z w 1
zw z 2
z w 1 2
2
z
w 1
16. z2
e.g .i Find the locus of w if w ,z 4
2
z2 2
w 4
z w 1
zw z 2 2
z w 1 2 4
w 1
2
z
w 1
17. z2
e.g .i Find the locus of w if w ,z 4
2
z2 2
w 4
z w 1
zw z 2 2
z w 1 2 4
w 1
2
z w 1
1
w 1 2
18. z2
e.g .i Find the locus of w if w ,z 4
2
z2 2
w 4
z w 1
zw z 2 2
z w 1 2 4
w 1
2
z w 1
1
w 1 2
1
locus is a circle, centre 1,0 and radius
2
1
i.e. x 1 y
2 2
4
19. z 1
ii Find the locus of z if w and w is purely real
z 1
20. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
21. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
22. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
23. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
24. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
xy y xy y 0
25. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0
26. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
27. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2
1 i x 1 y i x 1 y y 2
x 12 y 2
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
28. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
29. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
30. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 -1 1 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
31. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 -1 1 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
32. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 -1 1 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
33. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 -1 1 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
locus is y 0, excluding 1,0
34. z 1
ii Find the locus of z if w and w is purely real
z 1
x 1 iy x 1 iy OR If w is purely real then arg w 0 or
w
x 1 iy x 1 iy
x 2 1 i x 1 y i x 1 y y 2 z 1 0 or
i.e. arg
x 1 y 2
2 z 1
If w is purely real then Imw 0 arg z 1 arg z 1 0 or
y
i.e. x 1 y x 1 y 0
xy y xy y 0
2y 0
y0 -1 1 x
locus is y 0, excluding 1,0
z 1 0, bottom of fraction 0
locus is y 0, excluding 1,0
Note : locus is y 0, excluding 1,0 only
i.e. answer the original question
35. z
iii Find the locus of z if arg
z 4 6
36. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
37. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
38. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
x
39. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
4x
6
40. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
4x
6
NOTE: arg z arg z-4
below axis
41. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
2
4x
6
NOTE: arg z arg z-4
below axis
42. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
2
r 4x
(2,y)
6
NOTE: arg z arg z-4
below axis
43. z
iii Find the locus of z if arg
z 4 6
arg z
z 4 6
arg z arg z 4
6
y
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
44. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60
z 4 6 2
arg z arg z 4
6
y
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
45. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60
z 4 6 2
y 2 tan 60
arg z arg z 4
6
y 2 3
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
46. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60
z 4 6 2
y 2 tan 60
arg z arg z 4
6
y 2 3
centre is 2,2 3
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
47. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60 r 2 2 2 2 3
2
z 4 6 2
y 2 tan 60
arg z arg z 4
6
y 2 3
centre is 2,2 3
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
48. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60 r 2 2 2 2 3
2
z 4 6 2
r 2 16
arg z arg z 4 y 2 tan 60
6 r4
y 2 3
centre is 2,2 3
2
r 4x
(2,y)
30
6
NOTE: arg z arg z-4
below axis
49. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60 r 2 2 2 2 3
2
z 4 6 2
r 2 16
arg z arg z 4 y 2 tan 60
6 r4
y 2 3
centre is 2,2 3
locus is the major arc of the circle
2
x 2 y 2 3 16 formed by the
2 2
r 4x
chord joining 0,0 and 4,0 but not
(2,y)
30 including these points.
6
NOTE: arg z arg z-4
below axis
50. z
iii Find the locus of z if arg
z 4 6
arg z y
tan 60 r 2 2 2 2 3
2
z 4 6 2
r 2 16
arg z arg z 4 y 2 tan 60
6 r4
y 2 3
centre is 2,2 3
locus is the major arc of the circle
2
x 2 y 2 3 16 formed by the
2 2
r 4x
chord joining 0,0 and 4,0 but not
(2,y)
30 including these points.
6 Exercise 4N; 5, 6
Exercise 4O; 3 to 10, 12, 13a, 14, 17,
NOTE: arg z arg z-4 20b, 21a, 22, 25, 26
below axis HSC Geometrical Complex Numbers Questions