USA Today (\"Hybrid Car Sales Rose 81% Last Year,\" April 25, 2005) reported the top five states for sales of hybrid cars in 2004 as California, Virginia, Washington, Florida, and Maryland. Suppose that each car in a sample of 2004 hybrid car sales is classified by state where the sale took place. Sales from states other than the top five were excluded from the sample, resulting in the accompanying table. (The given observed counts are artificial, but they are consistent with hybrid sales figures given in the article.) The 2004 population estimates from the Census Bureau web site are given in the accompanying table. The population proportion for each state was computed by dividing each state population by the total population for all five states. Use the 2goodness-of-fit test and a significance level of = 0.01 to test the hypothesis that hybrid sales for these five states are proportional to the 2004 population for these states. Let p1, p2, p3, p4, and p5 be the actual population proportions of 2004 for the five states in the following order: California, Virginia, Washington, Florida, Maryland. State the null and alternative hypotheses. Calculate the test statistic. (Round your answer to two decimal places.) 2 = What is the P-value for the test? (Round your answer to four decimal places.) P-value = StateObserved Frequency California 254Virginia 53 Washington 37Florida 34Maryland 34Total 412 Solution A) OPTION B: H0: p1 = 0.495, p2 = 0.103, p3 = 0.085, p4 = 0.240, p5 = 0.077 Ha: H0 is not true. [ANSWER] ******************** b) Doing an observed/expected value table, O E (O - E)^2/E 254 203.94 12.28794547 53 42.436 2.629797719 37 35.02 0.111947459 34 98.88 42.57093851 34 31.724 0.163288866 Using chi^2 = Sum[(O - E)^2/E], chi^2 = 57.76391803 [ANSWER, TEST STATISTIC] ******************* c) As df = a - 1, a = 5 df = a - 1 = 4 Thus, the p value is p = 8.5533*10^-12 = 0.0000 [ANSWER].