Unit 5
Internal Sorting & Files
Dr. R. Khanchana
Assistant Professor
Department of Computer Science
Sri Ramakrishna College of Arts and Science for
Women
http://icodeguru.com/vc/10book/books/book1/chap07.htm
http://icodeguru.com/vc/10book/books/book1/chap10.htm
Tutorials :
https://www.tutorialspoint.com/data_structures_algorithms/insertion_sort_algorithm.htm
Internal Sorting
• Insertion Sort
• Quick Sort
• 2 Way Merge Sort
• Heap Sort
• Shell Sort
Insertion Sort
• Insertion sort is a simple sorting algorithm that
builds the final sorted array one item at a time.
• It is much less efficient on large lists than more
advanced algorithms such as quicksort, heapsort,
or merge sort.
• Worst complexity: n^2
• Average complexity: n^2
• Best complexity: n
• Space complexity: 1
3
Insertion Sort - Algorithm
4
Insertion Sort
• Idea: like sorting a hand of playing cards
– i with an empty left hand and the cards facing down
on the table.
– Remove one card at a time from the table, and insert
it into the correct position in the left hand
• compare it with each of the cards already in the hand, from
right to left
– The cards held in the left hand are sorted
• these cards were originally the top cards of the pile on the
table
5
Insertion Sort
6
To insert 12, we need to make
room for it by moving first 36
and then 24.STEP 1
STEP 2
STEP 3
Insertion Sort
7
5 2 4 6 1 3
input array
left sub-array right sub-array
at each iteration, the array is divided in two sub-arrays:
sorted unsorted
Insertion Sort
8
Insertion Sort
Video -
https://www.youtube.com/watch?v=QAAxd9Csu28
Insertion Sort
• Example 7.1: Assume n = 5 and the input sequence is (5,4,3,2,1) [note the
records have only one field which also happens to be the key]. Then, after
each insertion we have the following:
Note that this is an example of the worst case behavior.
• Example 7.2: n = 5 and the input sequence is (2, 3, 4, 5, 1). After each
execution of INSERT we have:
Assignment
Assignment Results
Assignment Results
Assignment Results
Quick Sort
Quick Sort
The idea (assume the list of items to be sorted is represented as an array):
1. Select a data item, called the pivot, which will be placed in its proper place
at the j of the current step. Remove it from the array.
2. Scan the array from right to left, comparing the data items with the pivot
until an item with a smaller value is found. Put this item in the pivot’s place.
3. Scan the array from left to right, comparing data items with the pivot, and
find the first item which is greater than the pivot. Place it in the position
freed by the item moved at the previous step.
4. Continue alternating steps 2-3 until no more exchanges are possible. Place
the pivot in the empty space, which is the proper place for that item.
5. Consider the sub-file to the left of the pivot, and repeat the same process.
6. Consider the sub-file to the right of the pivot, and repeat the same
process.
Video :https://www.youtube.com/watch?v=PgBzjlCcFvc
Example
We are given array of n integers to sort:
40 20 10 80 60 50 7 30 100
[0] [1] [2] [3] [4] [5] [6] [7] [8]
Pick Pivot Element
There are a number of ways to pick the pivot element. In
this example, we will use the first element in the array:
40 20 10 80 60 50 7 30 100
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
[0] [1] [2] [3] [4] [5] [6] [7] [8]
i j
1. While data[i] <= data[pivot]
++ i
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 80 60 50 7 30 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j> i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and [j]
4. While j> i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j> i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
40 20 10 30 60 50 7 80 100pivot_index = 0
i j
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++ i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
5. Swap data[j] and data[pivot_index]
40 20 10 30 7 50 60 80 100pivot_index = 0
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
1. While data[i] <= data[pivot]
++i
2. While data[j] > data[pivot]
--j
3. If i > j
swap data[i] and data[j]
4. While j > i, go to 1.
5. Swap data[j] and data[pivot_index]
7 20 10 30 40 50 60 80 100pivot_index = 4
i j
[0] [1] [2] [3] [4] [5] [6] [7] [8]
Partition Result
7 20 10 30 40 50 60 80 100
<= data[pivot] > data[pivot]
[0] [1] [2] [3] [4] [5] [6] [7] [8]
Quick Sort Algorithm
In Quick sort algorithm, partitioning of the list is performed using
following steps...
Step 1 - Consider the first element of the list as pivot (i.e., Element at
first position in the list).
Step 2 - Define two variables i and j. Set i and j to first and last elements
of the list respectively.
Step 3 - Increment i until list[i] > pivot then stop.
Step 4 - Decrement j until list[j] < pivot then stop.
Step 5 - If i > j then exchange list[i] and list[j].
Step 6 - Repeat steps 3,4 & 5 until I < j.
Step 7 - Exchange the pivot element with list[j] element.
Partitioning Array
Given a pivot, partition the elements of the array
such that the resulting array consists of:
1. One sub-array that contains elements >= pivot
2. Another sub-array that contains elements < pivot
The sub-arrays are stored in the original data array.
Partitioning loops through, swapping elements
below/above pivot.
Quick Sort
40 20 10 80 60 50 7 30 100
[0] [1] [2] [3] [4] [5] [6] [7] [8]
m n
K = Pivot
Ki
Kj
i
j
m nj-1
j
j+1
CHAPTER 7 48
Time and Space Complexity for
Quick Sort
 Space complexity:
– Average case and best case: O(log n)
– Worst case: O(n)
 Time complexity:
– Average case and best case: O(n logn)
– Worst case: O(n )2
Merge Sort
• Apply divide-and-conquer to sorting problem
• Problem: Given n elements, sort elements into non-
decreasing order
• Divide-and-Conquer:
– If n=1 terminate (every one-element list is already sorted)
– If n>1, partition elements into two or more sub-
collections; sort each; combine into a single sorted list
CHAPTER 7 49
Merge-Sort
• An execution of merge-sort is depicted by a binary
tree
– each node represents a recursive call of merge-sort and
stores
– the root is the initial call
– the leaves are calls on subsequences of size 0 or 1
• Given two sorted lists
(list[i], …, list[m])
(list[m+1], …, list[n])
generate a single sorted list
(sorted[i], …, sorted[n])
• O(n) space vs. O(1) space
Merge Sort 50
Merge-Sort Tree
Merge Sort 51
Merge-Sort Tree
Merge Sort 52
7 2  9 4  2 4 7 9
7  2  2 7 9  4  4 9
7  7 2  2 9  9 4  4
Execution Example
• Partition
Merge Sort 53
7 2 9 4  2 4 7 9 3 8 6 1  1 3 8 6
7 2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, partition
Merge Sort 54
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7 2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, partition
Merge Sort 55
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, base case
Merge Sort 56
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, base case
Merge Sort 57
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Merge
Merge Sort 58
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, …, base case, merge
Merge Sort 59
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
9  9 4  4
Execution Example (cont.)
• Merge
Merge Sort 60
7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Recursive call, …, merge, merge
Merge Sort 61
7 2  9 4  2 4 7 9 3 8 6 1  1 3 6 8
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Execution Example (cont.)
• Merge
Merge Sort 62
7 2  9 4  2 4 7 9 3 8 6 1  1 3 6 8
7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6
7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1
7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
Example -2
• Partition into lists of size n/2
[10, 4, 6, 3]
[10, 4, 6, 3, 8, 2, 5, 7]
[8, 2, 5, 7]
[10, 4] [6, 3] [8, 2] [5, 7]
[10] [4] [6] [3] [8] [2] [5] [7]
Example- 2 Cont’d
• Merge
[3, 4, 6, 10]
[2, 3, 4, 5, 6, 7, 8, 10 ]
[2, 5, 7, 8]
[4, 10] [3, 6] [2, 8] [5, 7]
[10] [4] [6] [3] [8] [2] [5] [7]
Merge Sort
[3, 4, 6, 10]
[2, 3, 4, 5, 6, 7, 8, 10 ]
[2, 5, 7, 8]
[10, 4, 6, 3, 8, 2, 5, 7]Input Array
Output Array (Sorted)
X X
K
Xi Xj
Zk
Analysis
• array vs. linked list representation
– array: O(M(n-i+1)) where M: record length
for copy
– linked list representation: O(n-i+1)
(n-i+1) linked fields
CHAPTER 7 66
Heap Sort
Heap sort may be regarded as a two stage method.
First the tree representing the file is converted into a heap(max heap).
-max-heap property: the value of each node is less than or equal to the
value of its parent, with the maximum-value element at the root.
A heap is defined to be a complete binary tree with the property that the value
of each node is at least as large as the value of its children nodes (if they
exist) (i.e., Kj/2 Kj for 1 j/2 < j n).
Min Heap Vs Max Heap
Heap Sort
50 10 23 1 7 -4
Initial
Array
[0] [1] [2] [3] [4] [5]
Heap Sort
Heap Sort
-4 1 7 10 23 50
Sorted
Array
[0] [1] [2] [3] [4] [5]
Procedure -Heap
15 5 20 1 17 10 30
[1] [2] [3] [4] [5] [6] [7]
Procedure -Heap
Shell Sort
• Shellsort is an extension of insertion sort, which gains
speed by allowing exchanges of elements that are far apart.
• Shellsort is also known as diminishing increment sort.
• It is an advanced Sorting Method
• Shell sort is an algorithm that first sorts the elements far
apart from each other and successively reduces the interval
between the elements to be sorted. It is a generalized version
of insertion sort.
• In shell sort, elements at a specific interval are sorted. The
interval between the elements is gradually decreased based
on the sequence used. The performance of the shell sort
depicts on the type of sequence used for a given input array.
Shellsort
• Invented by Donald Shell in 1959.
• 1st algorithm to break the quadratic time
barrier but few years later, a sub quadratic
time bound was proven
• Shellsort works by comparing elements
that are distant rather than adjacent
elements in an array.
Shellsort
• Shellsort makes multiple passes through a list
and sorts a number of equally sized sets using the
insertion sort.
• The distance between comparisons decreases as
the sorting algorithm runs until the last phase in
which adjacent elements are compared
• Shellsort improves on the efficiency of insertion
sort by quickly shifting values to their destination
Empirical Analysis of Shellsort (Advantage)
• Advantage of Shellsort is that its only efficient
for medium size lists. For bigger lists, the
algorithm is not the best choice. Fastest of all
O(N^2) sorting algorithms.
• 5 times faster than the bubble sort and a little
over twice as fast as the insertion sort, its
closest competitor.
Empirical Analysis of Shellsort (Disadvantage)
• Disadvantage of Shellsort is that it is a complex
algorithm and its not nearly as efficient as the merge,
heap, and quick sorts.
• The shell sort is still significantly slower than the
merge, heap, and quick sorts, but its relatively simple
algorithm makes it a good choice for sorting lists of
less than 5000 items unless speed important. It's also
an excellent choice for repetitive sorting of smaller
lists.
Shellsort Examples –Pass 1
Interval 1
Sort: 18 32 12 5 38 33 16 2
8 Numbers to be sorted, Shell’s increment will be floor(n/2)
* floor(8/2)  floor(4) = 4
increment 4: 1 2 3 4
18 32 12 5 38 33 16 2
(visualize underlining)
Step 1) Only look at 18 and 38 and sort in order ;
18 and 38 stays at its current position because they are in order.
Step 2) Only look at 32 and 33 and sort in order ;
32 and 33 stays at its current position because they are in order.
Shellsort Examples – Pass 1
Interval 1
Sort: 18 32 12 5 38 33 16 2
8 Numbers to be sorted, Shell’s increment will be floor(n/2) * floor(8/2)  floor(4) = 4
increment 4: 1 2 3 4
18 32 12 5 38 33 16 2
(visualize underlining)
Step 3) Only look at 12 and 16 and sort in order ;
12 and 16 stays at its current position because they are in order.
Step 4) Only look at 5 and 2 and sort in order ;
2 and 5 need to be switched to be in order.
Sort: 18 32 12 5 38 33 16 2
Resulting numbers after increment 4 steps in pass1 :
18 32 12 2 38 33 16 5
Shellsort Examples – Pass 2
Interval 2
8 Numbers to be sorted, Shell’s increment will be floor(n/4) or (interval1/2)
* floor(4/2)  floor(2) = 2
increment 2: 1 2
18 32 12 2 38 33 16 5
Step 1) Look at 18, 12, 38, 16 and sort them in their appropriate location:
12 32 16 2 18 33 38 5
Step 2) Look at 32, 2, 33, 5 and sort them in their appropriate location:
12 2 16 5 18 32 38 33
Sort: 18 32 12 5 38 33 16 2
Resulting numbers after increment 2 steps in pass2 :
12 2 16 5 18 32 38 33
Shellsort Examples- Pass 3
Interval 3
Sort: 18 32 12 5 38 33 16 2
* floor(2/2)  floor(1) = 1
increment 1: 1
12 2 16 5 18 32 38 33
2 5 12 16 18 32 33 38
The last increment or phase of Shellsort is basically an Insertion Sort algorithm.
8 Numbers to be sorted, Shell’s increment will be floor(n/8) or (interval2/2)
Shell Sort Algorithm
1.shellsort(int arr[], int num)
2.{
3.int i, j, k;
4.for (i = num / 2; i > 0; i = i / 2)
5.{
6.for (j = i; j < num; j++)
7.{
8.for(k = j - i; k >= 0; k = k - i)
9.{
10.if (arr[k+i] >= arr[k])
11.break;
12.else
13.{
14.Swap arr[k] =
arr[k+i];}
15.}
16.}
17.}
18.}
Additional Online References
• Spark Notes (From Barnes & Noble):
– http://www.sparknotes.com/cs/
Chapter -10
* Files
* Queries
* Sequential
Organization
FILES
 A file is a collection of records which contain
data about individual entities.
 The data is subdivided into records.
 Each record contains a number of fields.
 The primary key is a field, or a composite of
several fields which uniquely distinguishes a
record from all others.
 All the remaining fields are the secondary
fields.
FILES
File Organization
A file organization refers to the way records are
arranged on a storage devices such as magnetic
tapes, disks, etc...
• Sequential File
• Direct File
• Indexed Sequential File
Objective of file organization
 The primary objective of file organization
is to provide a means for record retrieval
and update.
 The update of a record could involve its
deletion, changes in some of its fields or the
insertion of an entirely new record.
 Records may be retrieved by specifying
values for some or using all of the keys.
How data can be organized on external
storage devices?
Depends on the following factors
 Kind of external storage devices
available
 Type of Queries allowed
 Number of keys
 Mode of retrieval
 Mode of update
Storage Device Types - DASD
A direct access storage device is a
secondary storage device in which
“each physical record has a discrete
location and a unique address”.
Direct access storage devices allow
the host computer to access data
directly from wherever it is stored
within the storage device because each
data chunk is saved in a discrete and
separate location from other chunks
Query Types
A combination of key values specified for
retrieve will be termed a query.
The four query types are:
Simple query – The value of a single key is
specified.
Range query – A range of values for a
single key is specified.
Functional query – Some function of key
values in the file is specified (e.g. average or
median).
 Boolean Query – A Boolean combination of all above queries
using logical operators and, or, not.
Q1: Dept = Security
Q2: Salary > 25,000
Q3: Salary>average salary of all employees
Q4: (Dept = security and salary > 25,000) or (Employee number =
367 and designation = manager)
Number of Keys
The chief distinction here will be between files having only one
key and files with more than one key.
Query Types
The mode of retrieval may be either real time
or batched.
* In real time retrieval the response time for
any query should be minimal.
Example: In an airline reservation
system we are able to determine the
status of a flight (number of seats
vacant) in a matter of few seconds.
Mode of Retrieval
• In the batched mode of retrieval, the response time is
not very significant.
• Requests for retrieval are batched together on a
“transaction file” until either enough requests have
been received or a suitable amount of time has passed.
• Then all queries on the transaction file are processed.
Mode of Retrieval
Mode of update – Real time
 The function that keeps files current is known
as updating. The mode of update may again be either
real time or batched.
 Real time involves a large number of users performing
transactions to change data.
 The steps in real time involve sending the data to an
online database in a master file.
 Data is accessed via direct access, which occurs when
data is accessed without accessing previous data items.
 Uses an algorithm to calculate the location of data.
 If the data is not there it continues to search through
successive locations until it is found.
Technology in real time requires secondary
storage to store large quantities of data for
quick access, magnetic disk storage.
Example: In an airline reservation system,
as soon as a seat on the flight is reserved,
the file must be changed to indicate the
new status.
Mode of update – Real time
Batch Update
A batch update is a set of multiple update
statements that is submitted to the database for
processing as a batch.
Sending multiple update statements to the
database together as a unit can, in some
situations, be much more efficient than sending
each update statement separately.
No user interaction is required.
Common examples of where batch processing
occurs include the processing of bank
statements, utility bills and credit card
transactions.
In case of batched update two files are
considered : Master file and Transaction file.
The permanent data file, called the master
file contains the most current file data.
The transaction file contains changes to be
applied to the master file.
Batch Update
How the required functions are
carried out efficiently on a tape?
* The records in the file are ordered by the key field.
* Requests for retrieval and update are batched onto a
transaction tape.
* When it is time to process the transactions, the
transactions are sorted into order by the key field and
update process is carried out creating a new master file.
* All records in the old master file are examined, changed
if necessary and then written out onto a new master file.
* The time required for the whole process is essentially
O(n + m log m) where n and m are the number of
records in the master and transaction files respectively.
* If m=1 and n=106 then clearly it is very wasteful to process the entire
master file.
* As the files in tape are sequentially ordered it is not possible to alter a
record in the middle of a tape without destroying information in an
adjacent record.
* For batched retrieval and update, ordered sequential files are
preferred over unordered sequential files since they are easier to
process.
- (contd)
How the required functions are
carried out efficiently on a disk?
 Batched retrieval and update can be carried out essentially
in the same way as for a sequentially ordered tape file by
setting up input and output buffers and reading in perhaps,
one track of the master and transaction files at a time.
 The transaction file should be sorted on the primary key
before beginning the master file processing.
 The sequential interpretation is particularly efficient for
batched update and retrieval as the tracks are to be accessed
in the order.
 The read/write heads are moved one cylinder at a time and
this movement is necessitated only once for every s tracks
read (s = number of surfaces).
Pictorial Representation of Magnetic
Disk
If the records are of a fixed size then it
is possible to use binary search to
obtain the record with the desired key
value.
Example : For a file with 105 records
of length 300 characters this would
mean a maximum of 17 accesses
Binary Search
Index File Access
To access a record in a file randomly, we need to
know the address of the record.
An index is just a collection of key values and
address pairs.
The index itself is a very small file with only two
fields.
The key of the sequential file and the address
of the corresponding record on the disk.
The index is sorted based on the key values of the
data files.
An index which contains one entry for
every record in the file will be referred
to as a dense index.
 Time is consumed in this access.
Index File Access
Index Techniques
• Indexing is a data structure technique to
efficiently retrieve records from the database
files based on some attributes on which
the indexing has been done. ...
Clustering Index − Clustering index is defined
on an ordered data file. The data file is
ordered on a non-key field.
Cylinder-surface indexing
• Simplest type of index organization. It is useful
only for the primary key index of a
sequentially ordered file. It assumes that
records are stored sequentially in increasing
order of primary key. The index consists of a
cylinder index and several surface indexes. If
the file requires c cylinders for storage then
the cylinder index contains c entries.
Hashed indexes
• Hash functions and overflow handling techniques are
used for hashing. Since the index is to be maintained
on disk and disk access times are generally several
orders of magnitude larger than internal memory
access times, much consideration is given to hash table
design and the choice of an overflow handling
technique.
• Overflow handling techniques:
• rehashing
• open addressing (random[f(i)=random()], quadratic,
linear)
• chaining
Tree indexing-B Trees
• Using m-way search tree can minimize the
search time, rather than using avl trees.
• B trees are used for indexing
•
Trie indexing
• An index structure that is particularly useful
when key values are of varying size is trie.
• A trie is a tree of degree m>=2 in which the
branching at any level is determined not by
the entire key value but by only a portion of it.
• The trie contains two types of nodes. First
type called the branch node and second
information node.
Video
• https://www.youtube.com/watch?v=E2tPBAN
5JHs
File Organization
• File organization refers to the way data is
stored in a file. File organization is very
important because it determines the methods
of access, efficiency, flexibility and storage
devices to use. There are four methods
of organizing files on a storage media.
• What is File?
• File is a collection of records related to each
other. The file size is limited by the size of
memory and storage medium.
• There are two important features of file:
1. File Activity
2. File Volatility
File Organization
• File activity specifies percent of actual records which proceed in a
single run.
File volatility addresses the properties of record changes. It helps to
increase the efficiency of disk design than tape.
• File Organization
File organization ensures that records are available for processing. It
is used to determine an efficient file organization for each base
relation.
For example, if we want to retrieve employee records in
alphabetical order of name. Sorting the file by employee name is a
good file organization. However, if we want to retrieve all
employees whose marks are in a certain range, a file is ordered by
employee name would not be a good file organization.
File Organization
Types of File Organizations are
• Sequential Organizations
• Random Organization
• Linked Organization
• Inverted Files
• Cellular partitions
Sequential Organizations
• Storing and sorting in contiguous block within files on
tape or disk is called as sequential access file
organization.
• In sequential access file organization, all records are
stored in a sequential order. The records are arranged
in the ascending or descending order of a key field.
• Sequential file search starts from the beginning of the
file and the records can be added at the end of the file.
• In sequential file, it is not possible to add a record in
the middle of the file without rewriting the file.
• Advantages of sequential file
It is simple to program and easy to design.
• Sequential file is best use if storage space.
• Disadvantages of sequential file
Sequential file is time consuming process.
• It has high data redundancy.
• Random searching is not possible.
Sequential Organization
Random Organization
• Records are stored randomly but accessed
directly. To access a file stored randomly, a
record key is used to determine where a
record is stored on the storage media.
Magnetic and optical disks allow data to be
stored and accessed randomly.
Linked Organization
• A linked data structure is a data
structure which consists of a set
of data records (nodes) linked together and
organized by references (links or pointers).
... Linked data structures include linked lists,
search trees, expression trees, and many
other widely used data structures.
Inverted Files
• An Inverted file is an index data structure that
maps content to its location within a
database file, in a document or in a set of
documents. ... The inverted file is the most
popular data structure used in document
retrieval systems to support full text search.
Cellular partitions
• To reduce the file search times, the storage
media may be divided into cells. A cell may be
an entire disk pack or it may simply be a
cylinder. Lists are localized to lie within a cell.
video
• https://www.youtube.com/watch?v=2Dz7H-
eMyJg
Quiz
• https://quizizz.com/admin/quiz/5fa9f2c993bd
1b001c5dcf1b

Unit 5 internal sorting &amp; files

  • 1.
    Unit 5 Internal Sorting& Files Dr. R. Khanchana Assistant Professor Department of Computer Science Sri Ramakrishna College of Arts and Science for Women http://icodeguru.com/vc/10book/books/book1/chap07.htm http://icodeguru.com/vc/10book/books/book1/chap10.htm Tutorials : https://www.tutorialspoint.com/data_structures_algorithms/insertion_sort_algorithm.htm
  • 2.
    Internal Sorting • InsertionSort • Quick Sort • 2 Way Merge Sort • Heap Sort • Shell Sort
  • 3.
    Insertion Sort • Insertionsort is a simple sorting algorithm that builds the final sorted array one item at a time. • It is much less efficient on large lists than more advanced algorithms such as quicksort, heapsort, or merge sort. • Worst complexity: n^2 • Average complexity: n^2 • Best complexity: n • Space complexity: 1 3
  • 4.
    Insertion Sort -Algorithm 4
  • 5.
    Insertion Sort • Idea:like sorting a hand of playing cards – i with an empty left hand and the cards facing down on the table. – Remove one card at a time from the table, and insert it into the correct position in the left hand • compare it with each of the cards already in the hand, from right to left – The cards held in the left hand are sorted • these cards were originally the top cards of the pile on the table 5
  • 6.
    Insertion Sort 6 To insert12, we need to make room for it by moving first 36 and then 24.STEP 1 STEP 2 STEP 3
  • 7.
    Insertion Sort 7 5 24 6 1 3 input array left sub-array right sub-array at each iteration, the array is divided in two sub-arrays: sorted unsorted
  • 8.
  • 9.
  • 10.
    Insertion Sort • Example7.1: Assume n = 5 and the input sequence is (5,4,3,2,1) [note the records have only one field which also happens to be the key]. Then, after each insertion we have the following: Note that this is an example of the worst case behavior. • Example 7.2: n = 5 and the input sequence is (2, 3, 4, 5, 1). After each execution of INSERT we have:
  • 11.
  • 12.
  • 13.
  • 14.
  • 15.
  • 16.
    Quick Sort The idea(assume the list of items to be sorted is represented as an array): 1. Select a data item, called the pivot, which will be placed in its proper place at the j of the current step. Remove it from the array. 2. Scan the array from right to left, comparing the data items with the pivot until an item with a smaller value is found. Put this item in the pivot’s place. 3. Scan the array from left to right, comparing data items with the pivot, and find the first item which is greater than the pivot. Place it in the position freed by the item moved at the previous step. 4. Continue alternating steps 2-3 until no more exchanges are possible. Place the pivot in the empty space, which is the proper place for that item. 5. Consider the sub-file to the left of the pivot, and repeat the same process. 6. Consider the sub-file to the right of the pivot, and repeat the same process. Video :https://www.youtube.com/watch?v=PgBzjlCcFvc
  • 17.
    Example We are givenarray of n integers to sort: 40 20 10 80 60 50 7 30 100 [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 18.
    Pick Pivot Element Thereare a number of ways to pick the pivot element. In this example, we will use the first element in the array: 40 20 10 80 60 50 7 30 100 [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 19.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 20.
    40 20 1080 60 50 7 30 100pivot_index = 0 [0] [1] [2] [3] [4] [5] [6] [7] [8] i j 1. While data[i] <= data[pivot] ++ i
  • 21.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 22.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 23.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 24.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 25.
    40 20 1080 60 50 7 30 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 26.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 27.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 28.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j> i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 29.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and [j] 4. While j> i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 30.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j> i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 31.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 32.
    40 20 1030 60 50 7 80 100pivot_index = 0 i j 1. While data[i] <= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 33.
    1. While data[i]<= data[pivot] ++ i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 34.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 35.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 36.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 37.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 38.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 39.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 40.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 41.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 42.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 5. Swap data[j] and data[pivot_index] 40 20 10 30 7 50 60 80 100pivot_index = 0 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 43.
    1. While data[i]<= data[pivot] ++i 2. While data[j] > data[pivot] --j 3. If i > j swap data[i] and data[j] 4. While j > i, go to 1. 5. Swap data[j] and data[pivot_index] 7 20 10 30 40 50 60 80 100pivot_index = 4 i j [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 44.
    Partition Result 7 2010 30 40 50 60 80 100 <= data[pivot] > data[pivot] [0] [1] [2] [3] [4] [5] [6] [7] [8]
  • 45.
    Quick Sort Algorithm InQuick sort algorithm, partitioning of the list is performed using following steps... Step 1 - Consider the first element of the list as pivot (i.e., Element at first position in the list). Step 2 - Define two variables i and j. Set i and j to first and last elements of the list respectively. Step 3 - Increment i until list[i] > pivot then stop. Step 4 - Decrement j until list[j] < pivot then stop. Step 5 - If i > j then exchange list[i] and list[j]. Step 6 - Repeat steps 3,4 & 5 until I < j. Step 7 - Exchange the pivot element with list[j] element.
  • 46.
    Partitioning Array Given apivot, partition the elements of the array such that the resulting array consists of: 1. One sub-array that contains elements >= pivot 2. Another sub-array that contains elements < pivot The sub-arrays are stored in the original data array. Partitioning loops through, swapping elements below/above pivot.
  • 47.
    Quick Sort 40 2010 80 60 50 7 30 100 [0] [1] [2] [3] [4] [5] [6] [7] [8] m n K = Pivot Ki Kj i j m nj-1 j j+1
  • 48.
    CHAPTER 7 48 Timeand Space Complexity for Quick Sort  Space complexity: – Average case and best case: O(log n) – Worst case: O(n)  Time complexity: – Average case and best case: O(n logn) – Worst case: O(n )2
  • 49.
    Merge Sort • Applydivide-and-conquer to sorting problem • Problem: Given n elements, sort elements into non- decreasing order • Divide-and-Conquer: – If n=1 terminate (every one-element list is already sorted) – If n>1, partition elements into two or more sub- collections; sort each; combine into a single sorted list CHAPTER 7 49
  • 50.
    Merge-Sort • An executionof merge-sort is depicted by a binary tree – each node represents a recursive call of merge-sort and stores – the root is the initial call – the leaves are calls on subsequences of size 0 or 1 • Given two sorted lists (list[i], …, list[m]) (list[m+1], …, list[n]) generate a single sorted list (sorted[i], …, sorted[n]) • O(n) space vs. O(1) space Merge Sort 50
  • 51.
  • 52.
    Merge-Sort Tree Merge Sort52 7 2  9 4  2 4 7 9 7  2  2 7 9  4  4 9 7  7 2  2 9  9 4  4
  • 53.
    Execution Example • Partition MergeSort 53 7 2 9 4  2 4 7 9 3 8 6 1  1 3 8 6 7 2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 54.
    Execution Example (cont.) •Recursive call, partition Merge Sort 54 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7 2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 55.
    Execution Example (cont.) •Recursive call, partition Merge Sort 55 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 56.
    Execution Example (cont.) •Recursive call, base case Merge Sort 56 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 57.
    Execution Example (cont.) •Recursive call, base case Merge Sort 57 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 58.
    Execution Example (cont.) •Merge Merge Sort 58 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 59.
    Execution Example (cont.) •Recursive call, …, base case, merge Merge Sort 59 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9 9  9 4  4
  • 60.
    Execution Example (cont.) •Merge Merge Sort 60 7 2  9 4  2 4 7 9 3 8 6 1  1 3 8 6 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 61.
    Execution Example (cont.) •Recursive call, …, merge, merge Merge Sort 61 7 2  9 4  2 4 7 9 3 8 6 1  1 3 6 8 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 62.
    Execution Example (cont.) •Merge Merge Sort 62 7 2  9 4  2 4 7 9 3 8 6 1  1 3 6 8 7  2  2 7 9 4  4 9 3 8  3 8 6 1  1 6 7  7 2  2 9  9 4  4 3  3 8  8 6  6 1  1 7 2 9 4  3 8 6 1  1 2 3 4 6 7 8 9
  • 63.
    Example -2 • Partitioninto lists of size n/2 [10, 4, 6, 3] [10, 4, 6, 3, 8, 2, 5, 7] [8, 2, 5, 7] [10, 4] [6, 3] [8, 2] [5, 7] [10] [4] [6] [3] [8] [2] [5] [7]
  • 64.
    Example- 2 Cont’d •Merge [3, 4, 6, 10] [2, 3, 4, 5, 6, 7, 8, 10 ] [2, 5, 7, 8] [4, 10] [3, 6] [2, 8] [5, 7] [10] [4] [6] [3] [8] [2] [5] [7]
  • 65.
    Merge Sort [3, 4,6, 10] [2, 3, 4, 5, 6, 7, 8, 10 ] [2, 5, 7, 8] [10, 4, 6, 3, 8, 2, 5, 7]Input Array Output Array (Sorted) X X K Xi Xj Zk
  • 66.
    Analysis • array vs.linked list representation – array: O(M(n-i+1)) where M: record length for copy – linked list representation: O(n-i+1) (n-i+1) linked fields CHAPTER 7 66
  • 67.
    Heap Sort Heap sortmay be regarded as a two stage method. First the tree representing the file is converted into a heap(max heap). -max-heap property: the value of each node is less than or equal to the value of its parent, with the maximum-value element at the root. A heap is defined to be a complete binary tree with the property that the value of each node is at least as large as the value of its children nodes (if they exist) (i.e., Kj/2 Kj for 1 j/2 < j n).
  • 68.
    Min Heap VsMax Heap
  • 69.
    Heap Sort 50 1023 1 7 -4 Initial Array [0] [1] [2] [3] [4] [5]
  • 70.
  • 71.
    Heap Sort -4 17 10 23 50 Sorted Array [0] [1] [2] [3] [4] [5]
  • 72.
    Procedure -Heap 15 520 1 17 10 30 [1] [2] [3] [4] [5] [6] [7]
  • 73.
  • 74.
    Shell Sort • Shellsortis an extension of insertion sort, which gains speed by allowing exchanges of elements that are far apart. • Shellsort is also known as diminishing increment sort. • It is an advanced Sorting Method • Shell sort is an algorithm that first sorts the elements far apart from each other and successively reduces the interval between the elements to be sorted. It is a generalized version of insertion sort. • In shell sort, elements at a specific interval are sorted. The interval between the elements is gradually decreased based on the sequence used. The performance of the shell sort depicts on the type of sequence used for a given input array.
  • 75.
    Shellsort • Invented byDonald Shell in 1959. • 1st algorithm to break the quadratic time barrier but few years later, a sub quadratic time bound was proven • Shellsort works by comparing elements that are distant rather than adjacent elements in an array.
  • 76.
    Shellsort • Shellsort makesmultiple passes through a list and sorts a number of equally sized sets using the insertion sort. • The distance between comparisons decreases as the sorting algorithm runs until the last phase in which adjacent elements are compared • Shellsort improves on the efficiency of insertion sort by quickly shifting values to their destination
  • 77.
    Empirical Analysis ofShellsort (Advantage) • Advantage of Shellsort is that its only efficient for medium size lists. For bigger lists, the algorithm is not the best choice. Fastest of all O(N^2) sorting algorithms. • 5 times faster than the bubble sort and a little over twice as fast as the insertion sort, its closest competitor.
  • 78.
    Empirical Analysis ofShellsort (Disadvantage) • Disadvantage of Shellsort is that it is a complex algorithm and its not nearly as efficient as the merge, heap, and quick sorts. • The shell sort is still significantly slower than the merge, heap, and quick sorts, but its relatively simple algorithm makes it a good choice for sorting lists of less than 5000 items unless speed important. It's also an excellent choice for repetitive sorting of smaller lists.
  • 79.
    Shellsort Examples –Pass1 Interval 1 Sort: 18 32 12 5 38 33 16 2 8 Numbers to be sorted, Shell’s increment will be floor(n/2) * floor(8/2)  floor(4) = 4 increment 4: 1 2 3 4 18 32 12 5 38 33 16 2 (visualize underlining) Step 1) Only look at 18 and 38 and sort in order ; 18 and 38 stays at its current position because they are in order. Step 2) Only look at 32 and 33 and sort in order ; 32 and 33 stays at its current position because they are in order.
  • 80.
    Shellsort Examples –Pass 1 Interval 1 Sort: 18 32 12 5 38 33 16 2 8 Numbers to be sorted, Shell’s increment will be floor(n/2) * floor(8/2)  floor(4) = 4 increment 4: 1 2 3 4 18 32 12 5 38 33 16 2 (visualize underlining) Step 3) Only look at 12 and 16 and sort in order ; 12 and 16 stays at its current position because they are in order. Step 4) Only look at 5 and 2 and sort in order ; 2 and 5 need to be switched to be in order. Sort: 18 32 12 5 38 33 16 2 Resulting numbers after increment 4 steps in pass1 : 18 32 12 2 38 33 16 5
  • 81.
    Shellsort Examples –Pass 2 Interval 2 8 Numbers to be sorted, Shell’s increment will be floor(n/4) or (interval1/2) * floor(4/2)  floor(2) = 2 increment 2: 1 2 18 32 12 2 38 33 16 5 Step 1) Look at 18, 12, 38, 16 and sort them in their appropriate location: 12 32 16 2 18 33 38 5 Step 2) Look at 32, 2, 33, 5 and sort them in their appropriate location: 12 2 16 5 18 32 38 33 Sort: 18 32 12 5 38 33 16 2 Resulting numbers after increment 2 steps in pass2 : 12 2 16 5 18 32 38 33
  • 82.
    Shellsort Examples- Pass3 Interval 3 Sort: 18 32 12 5 38 33 16 2 * floor(2/2)  floor(1) = 1 increment 1: 1 12 2 16 5 18 32 38 33 2 5 12 16 18 32 33 38 The last increment or phase of Shellsort is basically an Insertion Sort algorithm. 8 Numbers to be sorted, Shell’s increment will be floor(n/8) or (interval2/2)
  • 83.
    Shell Sort Algorithm 1.shellsort(intarr[], int num) 2.{ 3.int i, j, k; 4.for (i = num / 2; i > 0; i = i / 2) 5.{ 6.for (j = i; j < num; j++) 7.{ 8.for(k = j - i; k >= 0; k = k - i) 9.{ 10.if (arr[k+i] >= arr[k]) 11.break; 12.else 13.{ 14.Swap arr[k] = arr[k+i];} 15.} 16.} 17.} 18.}
  • 84.
    Additional Online References •Spark Notes (From Barnes & Noble): – http://www.sparknotes.com/cs/
  • 85.
    Chapter -10 * Files *Queries * Sequential Organization
  • 86.
    FILES  A fileis a collection of records which contain data about individual entities.  The data is subdivided into records.  Each record contains a number of fields.  The primary key is a field, or a composite of several fields which uniquely distinguishes a record from all others.  All the remaining fields are the secondary fields.
  • 87.
  • 88.
    File Organization A fileorganization refers to the way records are arranged on a storage devices such as magnetic tapes, disks, etc... • Sequential File • Direct File • Indexed Sequential File
  • 89.
    Objective of fileorganization  The primary objective of file organization is to provide a means for record retrieval and update.  The update of a record could involve its deletion, changes in some of its fields or the insertion of an entirely new record.  Records may be retrieved by specifying values for some or using all of the keys.
  • 90.
    How data canbe organized on external storage devices? Depends on the following factors  Kind of external storage devices available  Type of Queries allowed  Number of keys  Mode of retrieval  Mode of update
  • 91.
    Storage Device Types- DASD A direct access storage device is a secondary storage device in which “each physical record has a discrete location and a unique address”. Direct access storage devices allow the host computer to access data directly from wherever it is stored within the storage device because each data chunk is saved in a discrete and separate location from other chunks
  • 92.
    Query Types A combinationof key values specified for retrieve will be termed a query. The four query types are: Simple query – The value of a single key is specified. Range query – A range of values for a single key is specified. Functional query – Some function of key values in the file is specified (e.g. average or median).
  • 93.
     Boolean Query– A Boolean combination of all above queries using logical operators and, or, not. Q1: Dept = Security Q2: Salary > 25,000 Q3: Salary>average salary of all employees Q4: (Dept = security and salary > 25,000) or (Employee number = 367 and designation = manager) Number of Keys The chief distinction here will be between files having only one key and files with more than one key. Query Types
  • 94.
    The mode ofretrieval may be either real time or batched. * In real time retrieval the response time for any query should be minimal. Example: In an airline reservation system we are able to determine the status of a flight (number of seats vacant) in a matter of few seconds. Mode of Retrieval
  • 95.
    • In thebatched mode of retrieval, the response time is not very significant. • Requests for retrieval are batched together on a “transaction file” until either enough requests have been received or a suitable amount of time has passed. • Then all queries on the transaction file are processed. Mode of Retrieval
  • 96.
    Mode of update– Real time  The function that keeps files current is known as updating. The mode of update may again be either real time or batched.  Real time involves a large number of users performing transactions to change data.  The steps in real time involve sending the data to an online database in a master file.  Data is accessed via direct access, which occurs when data is accessed without accessing previous data items.  Uses an algorithm to calculate the location of data.  If the data is not there it continues to search through successive locations until it is found.
  • 97.
    Technology in realtime requires secondary storage to store large quantities of data for quick access, magnetic disk storage. Example: In an airline reservation system, as soon as a seat on the flight is reserved, the file must be changed to indicate the new status. Mode of update – Real time
  • 98.
    Batch Update A batchupdate is a set of multiple update statements that is submitted to the database for processing as a batch. Sending multiple update statements to the database together as a unit can, in some situations, be much more efficient than sending each update statement separately. No user interaction is required. Common examples of where batch processing occurs include the processing of bank statements, utility bills and credit card transactions.
  • 99.
    In case ofbatched update two files are considered : Master file and Transaction file. The permanent data file, called the master file contains the most current file data. The transaction file contains changes to be applied to the master file. Batch Update
  • 100.
    How the requiredfunctions are carried out efficiently on a tape? * The records in the file are ordered by the key field. * Requests for retrieval and update are batched onto a transaction tape. * When it is time to process the transactions, the transactions are sorted into order by the key field and update process is carried out creating a new master file. * All records in the old master file are examined, changed if necessary and then written out onto a new master file. * The time required for the whole process is essentially O(n + m log m) where n and m are the number of records in the master and transaction files respectively.
  • 101.
    * If m=1and n=106 then clearly it is very wasteful to process the entire master file. * As the files in tape are sequentially ordered it is not possible to alter a record in the middle of a tape without destroying information in an adjacent record. * For batched retrieval and update, ordered sequential files are preferred over unordered sequential files since they are easier to process. - (contd)
  • 102.
    How the requiredfunctions are carried out efficiently on a disk?  Batched retrieval and update can be carried out essentially in the same way as for a sequentially ordered tape file by setting up input and output buffers and reading in perhaps, one track of the master and transaction files at a time.  The transaction file should be sorted on the primary key before beginning the master file processing.  The sequential interpretation is particularly efficient for batched update and retrieval as the tracks are to be accessed in the order.  The read/write heads are moved one cylinder at a time and this movement is necessitated only once for every s tracks read (s = number of surfaces).
  • 103.
  • 104.
    If the recordsare of a fixed size then it is possible to use binary search to obtain the record with the desired key value. Example : For a file with 105 records of length 300 characters this would mean a maximum of 17 accesses Binary Search
  • 105.
    Index File Access Toaccess a record in a file randomly, we need to know the address of the record. An index is just a collection of key values and address pairs. The index itself is a very small file with only two fields. The key of the sequential file and the address of the corresponding record on the disk. The index is sorted based on the key values of the data files.
  • 106.
    An index whichcontains one entry for every record in the file will be referred to as a dense index.  Time is consumed in this access. Index File Access
  • 107.
    Index Techniques • Indexingis a data structure technique to efficiently retrieve records from the database files based on some attributes on which the indexing has been done. ... Clustering Index − Clustering index is defined on an ordered data file. The data file is ordered on a non-key field.
  • 108.
    Cylinder-surface indexing • Simplesttype of index organization. It is useful only for the primary key index of a sequentially ordered file. It assumes that records are stored sequentially in increasing order of primary key. The index consists of a cylinder index and several surface indexes. If the file requires c cylinders for storage then the cylinder index contains c entries.
  • 109.
    Hashed indexes • Hashfunctions and overflow handling techniques are used for hashing. Since the index is to be maintained on disk and disk access times are generally several orders of magnitude larger than internal memory access times, much consideration is given to hash table design and the choice of an overflow handling technique. • Overflow handling techniques: • rehashing • open addressing (random[f(i)=random()], quadratic, linear) • chaining
  • 110.
    Tree indexing-B Trees •Using m-way search tree can minimize the search time, rather than using avl trees. • B trees are used for indexing •
  • 111.
    Trie indexing • Anindex structure that is particularly useful when key values are of varying size is trie. • A trie is a tree of degree m>=2 in which the branching at any level is determined not by the entire key value but by only a portion of it. • The trie contains two types of nodes. First type called the branch node and second information node.
  • 112.
  • 113.
    File Organization • Fileorganization refers to the way data is stored in a file. File organization is very important because it determines the methods of access, efficiency, flexibility and storage devices to use. There are four methods of organizing files on a storage media.
  • 114.
    • What isFile? • File is a collection of records related to each other. The file size is limited by the size of memory and storage medium. • There are two important features of file: 1. File Activity 2. File Volatility File Organization
  • 115.
    • File activityspecifies percent of actual records which proceed in a single run. File volatility addresses the properties of record changes. It helps to increase the efficiency of disk design than tape. • File Organization File organization ensures that records are available for processing. It is used to determine an efficient file organization for each base relation. For example, if we want to retrieve employee records in alphabetical order of name. Sorting the file by employee name is a good file organization. However, if we want to retrieve all employees whose marks are in a certain range, a file is ordered by employee name would not be a good file organization. File Organization
  • 116.
    Types of FileOrganizations are • Sequential Organizations • Random Organization • Linked Organization • Inverted Files • Cellular partitions
  • 117.
    Sequential Organizations • Storingand sorting in contiguous block within files on tape or disk is called as sequential access file organization. • In sequential access file organization, all records are stored in a sequential order. The records are arranged in the ascending or descending order of a key field. • Sequential file search starts from the beginning of the file and the records can be added at the end of the file. • In sequential file, it is not possible to add a record in the middle of the file without rewriting the file.
  • 118.
    • Advantages ofsequential file It is simple to program and easy to design. • Sequential file is best use if storage space. • Disadvantages of sequential file Sequential file is time consuming process. • It has high data redundancy. • Random searching is not possible. Sequential Organization
  • 119.
    Random Organization • Recordsare stored randomly but accessed directly. To access a file stored randomly, a record key is used to determine where a record is stored on the storage media. Magnetic and optical disks allow data to be stored and accessed randomly.
  • 120.
    Linked Organization • Alinked data structure is a data structure which consists of a set of data records (nodes) linked together and organized by references (links or pointers). ... Linked data structures include linked lists, search trees, expression trees, and many other widely used data structures.
  • 121.
    Inverted Files • AnInverted file is an index data structure that maps content to its location within a database file, in a document or in a set of documents. ... The inverted file is the most popular data structure used in document retrieval systems to support full text search.
  • 122.
    Cellular partitions • Toreduce the file search times, the storage media may be divided into cells. A cell may be an entire disk pack or it may simply be a cylinder. Lists are localized to lie within a cell.
  • 123.
  • 124.