Transformer Tests
Open Circuit Test and
Short Circuit test
EECE – 203: ELECTRICAL MACHINES
The performance of a transformer can be calculated on
the basis of its four main parameters of equivalent circuit:
(i) Equivalent resistance 𝑅01 as referred to primary (or
secondary 𝑅02)
(ii) The equivalent leakage reactance 𝑋01 as referred to
primary (or secondary 𝑋02)
(iii) The core-loss conductance 𝐺0 (or resistance 𝑅0)
(iv) The magnetising susceptance 𝐵0 (or reactance 𝑋0).
These constants or parameters can be easily determined
by two tests
(i) open-circuit test and (ii) short circuit test.
Why Open Circuit Test(OCT) & Short Circuit Test (SCT) are done?
 To find out the impedance, no load current, short
circuit current and the efficiency of the transformer
 OCT is done to determine the core losses or the iron
losses of the transformer
 SCT is done to determine the Cu losses of the
transformer
 These tests are very economical and convenient,
because they furnish the required information without
actually loading the transformer
Open Circuit Test
Open Circuit Test
μ
Open Circuit Test
Admittance 𝑌0 of the transformer is given by -
conductance 𝐺0 is given by -
susceptance 𝐵0 is given by -
Example. In no-load test of single-phase transformer, the following test data were
obtained, Resistance of the primary winding = 0.6 ohm:
Primary voltage : 220 V ; Secondary voltage : 110 V ; Primary current : 0.5 A ; Power input
: 30 W.
Find the following :
(i) The turns ratio (ii) the magnetising component of no-load current (iii) its working (or
loss) component (iv) the iron loss.
Short Circuit Test
This is an economical method for determining the following :
 Equivalent impedance (𝒁 𝟎𝟏or 𝒁 𝟎𝟐), leakage reactance (𝑿 𝟎𝟏or 𝑿 𝟎𝟐) and total
resistance (𝑹 𝟎𝟏 or 𝑹 𝟎𝟐) of the transformer as referred to the winding in
which the measuring instruments are placed.
 Cu loss at full load (and at any desired load). This loss is used in calculating
the efficiency of the transformer.
 Knowing 𝒁 𝟎𝟏 or 𝒁 𝟎𝟐, the total voltage drop in the transformer as referred to
primary or secondary can be calculated and hence regulation of the
transformer determined.
Short Circuit Test
Short Circuit Test
Short Circuit Test
If Vsc is the voltage required to circulate rated load currents, then 𝑍01 =
𝑉 𝑆𝐶
𝐼1
Separation of Core losses
• The core loss of a transformer depends upon the frequency and the
maximum flux density when the volume and the thickness of the core
laminations are given.
• The core loss is made up of two parts
• hysteresis loss =
• eddy current loss =
Steinmetz’s empirical relation
• The total core-loss is given by
Transformer: Open Circuit and Short Circuit Test
Transformer: Open Circuit and Short Circuit Test

Transformer: Open Circuit and Short Circuit Test

  • 1.
    Transformer Tests Open CircuitTest and Short Circuit test EECE – 203: ELECTRICAL MACHINES
  • 2.
    The performance ofa transformer can be calculated on the basis of its four main parameters of equivalent circuit: (i) Equivalent resistance 𝑅01 as referred to primary (or secondary 𝑅02) (ii) The equivalent leakage reactance 𝑋01 as referred to primary (or secondary 𝑋02) (iii) The core-loss conductance 𝐺0 (or resistance 𝑅0) (iv) The magnetising susceptance 𝐵0 (or reactance 𝑋0). These constants or parameters can be easily determined by two tests (i) open-circuit test and (ii) short circuit test.
  • 3.
    Why Open CircuitTest(OCT) & Short Circuit Test (SCT) are done?  To find out the impedance, no load current, short circuit current and the efficiency of the transformer  OCT is done to determine the core losses or the iron losses of the transformer  SCT is done to determine the Cu losses of the transformer  These tests are very economical and convenient, because they furnish the required information without actually loading the transformer
  • 4.
  • 5.
  • 6.
    Open Circuit Test Admittance𝑌0 of the transformer is given by - conductance 𝐺0 is given by - susceptance 𝐵0 is given by -
  • 7.
    Example. In no-loadtest of single-phase transformer, the following test data were obtained, Resistance of the primary winding = 0.6 ohm: Primary voltage : 220 V ; Secondary voltage : 110 V ; Primary current : 0.5 A ; Power input : 30 W. Find the following : (i) The turns ratio (ii) the magnetising component of no-load current (iii) its working (or loss) component (iv) the iron loss.
  • 8.
    Short Circuit Test Thisis an economical method for determining the following :  Equivalent impedance (𝒁 𝟎𝟏or 𝒁 𝟎𝟐), leakage reactance (𝑿 𝟎𝟏or 𝑿 𝟎𝟐) and total resistance (𝑹 𝟎𝟏 or 𝑹 𝟎𝟐) of the transformer as referred to the winding in which the measuring instruments are placed.  Cu loss at full load (and at any desired load). This loss is used in calculating the efficiency of the transformer.  Knowing 𝒁 𝟎𝟏 or 𝒁 𝟎𝟐, the total voltage drop in the transformer as referred to primary or secondary can be calculated and hence regulation of the transformer determined.
  • 9.
  • 10.
  • 11.
    Short Circuit Test IfVsc is the voltage required to circulate rated load currents, then 𝑍01 = 𝑉 𝑆𝐶 𝐼1
  • 12.
    Separation of Corelosses • The core loss of a transformer depends upon the frequency and the maximum flux density when the volume and the thickness of the core laminations are given. • The core loss is made up of two parts • hysteresis loss = • eddy current loss = Steinmetz’s empirical relation • The total core-loss is given by