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Chapter# 21
LLBiochemistr1
Chapter o1 : Stoichiometry
Introduction t
Stoichiometry
Syllabus Review
Al-Chemist Channel You Tube
Learning Outcomes
 Students be able to
 Understand and explain applications of
Stoichiometry and Mole concept
Al-Chemist Channel You Tube
What is Stoichio-metry?
The branch of Chemistry that deals with the study of:
The quantitative relationship between reactants and products in a
balanced chemical equation.
It is an application of law of conservation mass to calculate the relative
amounts of reactants and products.
Following relationship is studied in Stoichiometry
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How does biochemistry
impact you?
Al-Chemist Channel You Tube
Balanced Chemical Equation
N2 + 3H2 2NH3
Al-Chemist Channel You Tube
1 mole of
N2
3 moles of
H2
2 moles of
Ammonia Gas
1N2 + 3H2 2NH3
Al-Chemist Channel You Tube
N2 H2
1 3
N2 NH3
1 3
H2 NH3
3 2
 What is mole?
 Mole is just a number
Like
 1 dozen Apples= 12 apples
 1 mole Apples=6022000000000000000000 Apples
 In Exponential form 6.022x1023
 1 mole carbon atoms= 6.022x1023 moles carbon atoms
 5 moles carbon atoms= 5x6.022x1023 moles carbon atoms
Al-Chemist Channel You Tube
What is a mole (Gram atom)
 When the atomic mass of an elements is expressed in
grams is called gram atom or moles of that substance
 Mathematically,
 Moles= Mass of an element in gram/Molar mass element
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Mole
Al-Chemist Channel You Tube
Gram molecules/Formula units or Moles
Al-Chemist Channel You Tube
Gram Formulas
Al-Chemist Channel You Tube
Moles
 So, the atomic mass, molecular mass, formula mass or ionic mass of the
substance expressed
in gram is called moles of the substance.
Al-Chemist Channel You Tube
Example: Calculate moles in
Al-Chemist Channel You Tube
Avogadro's number 6.022x1023
 Avogadro's number is the number of atoms, molecules and
ions in one gram atom of an element,
one gram molecule of a compound and one gram ion of a
substance, respectively.
 To understand Avogadro's number let us consider the
following quantities of substances.
Al-Chemist Channel You Tube
Avogadro's number
 1.008 g of hydrogen = 1 mole of hydrogen = 6.02 x 1023
atoms of H
23 g of sodium = 1 mole of Na = 6.02 x1O23 atoms of Na
238 g of uranium = 1 mole of U = 6.02 x 1023atoms of U
This number, 6.02 x 1023is the number of atoms in one
mole of the element. It is interesting to know that
different masses of elements have the same number of
atoms.
Al-Chemist Channel You Tube
Calculation for particles
Al-Chemist Channel You Tube
Calculation of particles
 Number of particles = Moles x NA
Calculate number Water molecules in 9 grams of H2O
 1st we calculate number of moles of H2O
 Moles= mass in gram/molar mass
 Moles ofH2O= 9g/18
 o.5 Moles
 Number of water molecules= 0.5 x 6.022x1023
Al-Chemist Channel You Tube
Al-Chemist Channel You Tube
Al-Chemist Channel You Tube
Chapter# 21
LLBiochemistr1
Lecture 02
Limiting
Reactant
And yield
Syllabus Review
Al-Chemist Channel You Tube
Percentage Composition
Al-Chemist Channel You Tube
Solved Example
Al-Chemist Channel You Tube
Pecentage per mole
Al-Chemist Channel You Tube
Limiting and Excess reactant
Al-Chemist Channel You Tube
 Limiting Reactant
 limiting reactant is a reactant that controls the
amount of the product formed in a chemical reaction
due to its smaller amount.
2H2(g) + O2(g) 2H2O(l)
When we take 2 moles of hydrogen (4g) and allow it to
react with 2 moles of oxygen (64g), then we

2H2(g) + O2(g) 2H2O(l)
 will get only 2 moles (36 g) of water. Actually, we will get 2 moles (36g) of water
because 2 moles

(4g) of hydrogen react with 1 mole (32 g) of oxygen according to the balanced
equation. Since less hydrogen is present as compared to oxygen, so hydrogen is
a limiting reactant. If we would have reacted 4 moles (8g) of hydrogen with 2
moles (64 g) of oxygen, we would have obtained 4 moles (72 g) of water.
Al-Chemist Channel You Tube
Identification of Limiting Reactant
Following steps are involved:
Al-Chemist Channel You Tube
Solved Example
Al-Chemist Channel You Tube
 NH3 gas can be prepared by heating together two solids
NH4Cl and Ca(OH)2. If a mixture containing 100 g of each
solid is heated then
 (a) Calculate the number of grams of NH3 produced.

(b) Calculate the excess amount of reagent left unreacted.
 2NH4Cl (s) + Ca (OH)2 (s) CaCl2(s) + 2NH3 (g) + 2H2O(l)
Al-Chemist Channel You Tube
Oligosacharides
Al-Chemist Channel You Tube
NH4Cl vs Ca (OH)2
NH4Cl : Ca (OH)2
2 : 1
1 : 1/2
1.87 : 0.935
Al-Chemist Channel You Tube
Hence the number of moles of Ca(OH)2 which completely
react with 1.87 moles of NH4Cl is 0.935moles.
No. of moles of Ca(OH)2 taken =1.35
No. of moles of Ca(OH)2 used = = 0.935
No. of moles of Ca(OH)2 left behind = 1.35 - 0.935 = 0.415
Mass of Ca(OH)2 left unreacted (excess) = 0.415x74 = 30.71 g
Answer
It means that we should have mixed 100 g of NH4Cl with 69.3
g (100 - 30.71) of Ca(OH)2 to get 1.87moles of NH3.
Al-Chemist Channel You Tube
YIELD (Product)
Al-Chemist Channel You Tube
Actual yield
The amount of the products obtained in a chemical
reaction is called the actual yield of that reaction.
 Theoretical yield
The amount of the products calculated from the balanced
chemical equation represents the
theoretical yield.
Theoretical yield is maximum
Al-Chemist Channel You Tube
 The theoretical yield is the maximum amount of the
product that can be produced
by a given amount of a reactant, according to balanced
chemical equation.
In most chemical reactions the amount of the product
obtained is less than the theoretical yield.
Percent yield
Percent yield=
.
•
Al-Chemist Channel You Tube
Percent Yield
Al-Chemist Channel You Tube

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Stoichiometry

  • 1. Al-Chemist Channel You Tube Chapter# 21 LLBiochemistr1 Chapter o1 : Stoichiometry Introduction t Stoichiometry
  • 3. Learning Outcomes  Students be able to  Understand and explain applications of Stoichiometry and Mole concept Al-Chemist Channel You Tube
  • 4. What is Stoichio-metry? The branch of Chemistry that deals with the study of: The quantitative relationship between reactants and products in a balanced chemical equation. It is an application of law of conservation mass to calculate the relative amounts of reactants and products. Following relationship is studied in Stoichiometry Al-Chemist Channel You Tube
  • 5. How does biochemistry impact you? Al-Chemist Channel You Tube
  • 6. Balanced Chemical Equation N2 + 3H2 2NH3 Al-Chemist Channel You Tube 1 mole of N2 3 moles of H2 2 moles of Ammonia Gas
  • 7. 1N2 + 3H2 2NH3 Al-Chemist Channel You Tube N2 H2 1 3 N2 NH3 1 3 H2 NH3 3 2
  • 8.  What is mole?  Mole is just a number Like  1 dozen Apples= 12 apples  1 mole Apples=6022000000000000000000 Apples  In Exponential form 6.022x1023  1 mole carbon atoms= 6.022x1023 moles carbon atoms  5 moles carbon atoms= 5x6.022x1023 moles carbon atoms Al-Chemist Channel You Tube
  • 9. What is a mole (Gram atom)  When the atomic mass of an elements is expressed in grams is called gram atom or moles of that substance  Mathematically,  Moles= Mass of an element in gram/Molar mass element Al-Chemist Channel You Tube
  • 11. Gram molecules/Formula units or Moles Al-Chemist Channel You Tube
  • 13. Moles  So, the atomic mass, molecular mass, formula mass or ionic mass of the substance expressed in gram is called moles of the substance. Al-Chemist Channel You Tube
  • 14. Example: Calculate moles in Al-Chemist Channel You Tube
  • 15. Avogadro's number 6.022x1023  Avogadro's number is the number of atoms, molecules and ions in one gram atom of an element, one gram molecule of a compound and one gram ion of a substance, respectively.  To understand Avogadro's number let us consider the following quantities of substances. Al-Chemist Channel You Tube
  • 16. Avogadro's number  1.008 g of hydrogen = 1 mole of hydrogen = 6.02 x 1023 atoms of H 23 g of sodium = 1 mole of Na = 6.02 x1O23 atoms of Na 238 g of uranium = 1 mole of U = 6.02 x 1023atoms of U This number, 6.02 x 1023is the number of atoms in one mole of the element. It is interesting to know that different masses of elements have the same number of atoms. Al-Chemist Channel You Tube
  • 18. Calculation of particles  Number of particles = Moles x NA Calculate number Water molecules in 9 grams of H2O  1st we calculate number of moles of H2O  Moles= mass in gram/molar mass  Moles ofH2O= 9g/18  o.5 Moles  Number of water molecules= 0.5 x 6.022x1023 Al-Chemist Channel You Tube
  • 20. Al-Chemist Channel You Tube Chapter# 21 LLBiochemistr1 Lecture 02 Limiting Reactant And yield
  • 24. Pecentage per mole Al-Chemist Channel You Tube
  • 25. Limiting and Excess reactant Al-Chemist Channel You Tube  Limiting Reactant  limiting reactant is a reactant that controls the amount of the product formed in a chemical reaction due to its smaller amount. 2H2(g) + O2(g) 2H2O(l) When we take 2 moles of hydrogen (4g) and allow it to react with 2 moles of oxygen (64g), then we 
  • 26. 2H2(g) + O2(g) 2H2O(l)  will get only 2 moles (36 g) of water. Actually, we will get 2 moles (36g) of water because 2 moles  (4g) of hydrogen react with 1 mole (32 g) of oxygen according to the balanced equation. Since less hydrogen is present as compared to oxygen, so hydrogen is a limiting reactant. If we would have reacted 4 moles (8g) of hydrogen with 2 moles (64 g) of oxygen, we would have obtained 4 moles (72 g) of water. Al-Chemist Channel You Tube
  • 27. Identification of Limiting Reactant Following steps are involved: Al-Chemist Channel You Tube
  • 28. Solved Example Al-Chemist Channel You Tube  NH3 gas can be prepared by heating together two solids NH4Cl and Ca(OH)2. If a mixture containing 100 g of each solid is heated then  (a) Calculate the number of grams of NH3 produced.  (b) Calculate the excess amount of reagent left unreacted.  2NH4Cl (s) + Ca (OH)2 (s) CaCl2(s) + 2NH3 (g) + 2H2O(l)
  • 31. NH4Cl vs Ca (OH)2 NH4Cl : Ca (OH)2 2 : 1 1 : 1/2 1.87 : 0.935 Al-Chemist Channel You Tube
  • 32. Hence the number of moles of Ca(OH)2 which completely react with 1.87 moles of NH4Cl is 0.935moles. No. of moles of Ca(OH)2 taken =1.35 No. of moles of Ca(OH)2 used = = 0.935 No. of moles of Ca(OH)2 left behind = 1.35 - 0.935 = 0.415 Mass of Ca(OH)2 left unreacted (excess) = 0.415x74 = 30.71 g Answer It means that we should have mixed 100 g of NH4Cl with 69.3 g (100 - 30.71) of Ca(OH)2 to get 1.87moles of NH3. Al-Chemist Channel You Tube
  • 33. YIELD (Product) Al-Chemist Channel You Tube Actual yield The amount of the products obtained in a chemical reaction is called the actual yield of that reaction.  Theoretical yield The amount of the products calculated from the balanced chemical equation represents the theoretical yield.
  • 34. Theoretical yield is maximum Al-Chemist Channel You Tube  The theoretical yield is the maximum amount of the product that can be produced by a given amount of a reactant, according to balanced chemical equation. In most chemical reactions the amount of the product obtained is less than the theoretical yield.
  • 35. Percent yield Percent yield= . • Al-Chemist Channel You Tube Percent Yield