The document provides an introduction and examples of using Structured Query Language (SQL) to query a student database file in FoxPro. It covers SQL fundamentals including SELECT statements, FROM and WHERE clauses, comparison operators, grouping, and aggregate functions. Fifteen examples are given that demonstrate how to list, filter, and summarize data from the student table based on various conditions.

1. Structured Query Language

2. Introduction to SQLIntroduction to SQL
What is SQL?
– When a user wants to get some information
from a database file, he can issue a query.
11
– A query is a user–request to retrieve data or
information with a certain condition.
– SQL is a query language that allows user to
specify the conditions. (instead of algorithms)

3. Introduction to SQLIntroduction to SQL
Concept of SQL
– The user specifies a certain condition.
11
– The result of the query will then be stored in
form of a table.
– Statistical information of the data.
– The program will go through all the records
in the database file and select those records
that satisfy the condition.(searching).

4. Introduction to SQLIntroduction to SQL
How to involve SQL in FoxPro
– Before using SQL, the tables should be
opened.
11
– The SQL command can be entered directly
in the Command Window
– To perform exact matching, we should
SET ANSI ON

5. Basic structure of an SQLBasic structure of an SQL
queryquery22
General
Structure
SELECT, ALL / DISTINCT, *,
AS, FROM, WHERE
Comparison IN, BETWEEN, LIKE "% _"
Grouping GROUP BY, HAVING,
COUNT( ), SUM( ), AVG( ), MAX( ), MIN( )
Display Order ORDER BY, ASC / DESC
Logical
Operators
AND, OR, NOT
Output INTO TABLE / CURSOR
TO FILE [ADDITIVE], TO PRINTER, TO SCREEN
Union UNION

6. fieldfield typetype widthwidth contentscontents
id numeric 4 student id number
name character 10 name
dob date 8 date of birth
sex character 1 sex: M / F
class character 2 class
hcode character 1 house code: R, Y, B, G
dcode character 3 district code
remission logical 1 fee remission
mtest numeric 2 Math test score
22 The Situation:
Student Particulars

7. General StructureGeneral Structure
II
SELECTSELECT [[ALL / DISTINCTALL / DISTINCT]] expr1expr1 [[ASAS col1col1],], expr2expr2 [[ASAS col2col2]] ;;
FROMFROM tablenametablename WHEREWHERE conditioncondition
SELECT ...... FROM ...... WHERE ......SELECT ...... FROM ...... WHERE ......

8. General StructureGeneral Structure
II
– The query will select rows from the source tablename
and output the result in table form.
– Expressions expr1, expr2 can be :
• (1) a column, or
• (2) an expression of functions and fields.
SELECTSELECT [[ALL / DISTINCTALL / DISTINCT]] expr1expr1 [[ASAS col1col1],], expr2expr2 [[ASAS col2col2]] ;;
FROMFROM tablenametablename WHEREWHERE conditioncondition
– And col1, col2 are their corresponding column names in the
output table.

9. General StructureGeneral Structure
II
– DISTINCT will eliminate duplication in the output while
ALL will keep all duplicated rows.
– condition can be :
• (1) an inequality, or
• (2) a string comparison
• using logical operators AND, OR, NOT.
SELECTSELECT [[ALL / DISTINCTALL / DISTINCT]] expr1expr1 [[ASAS col1col1],], expr2expr2 [[ASAS col2col2]] ;;
FROMFROM tablenametablename WHEREWHERE conditioncondition

10. General StructureGeneral Structure
II Before using SQL, open the student file:
USE studentUSE student
eg. 1eg. 1 List all the student records.List all the student records.
SELECT * FROM student
id name dob sex class mtest hcode dcode remission
9801 Peter 06/04/86 M 1A 70 R SSP .F.
9802 Mary 01/10/86 F 1A 92 Y HHM .F.
9803 Johnny 03/16/86 M 1A 91 G SSP .T.
9804 Wendy 07/09/86 F 1B 84 B YMT .F.
9805 Tobe 10/17/86 M 1B 88 R YMT .F.
: : : : : : : : :
Result

11. General StructureGeneral Structure
IIeg. 2eg. 2 List the names and house code of 1A students.List the names and house code of 1A students.
SELECT name, hcode, class FROM student ;
WHERE class="1A"
Class
1A1A
1A1A
1A1A
1B1B
1B1B
::

Class
1A1A
1A1A
1A1A
1B1B
1B1B
::




class="1A"

12. General StructureGeneral Structure
II
name hcode class
Peter R 1A
Mary Y 1A
Johnny G 1A
Luke G 1A
Bobby B 1A
Aaron R 1A
: : :
Result
eg. 2eg. 2 List the names and house code of 1A students.List the names and house code of 1A students.

13. General StructureGeneral Structure
IIeg. 3eg. 3 List the residential district of the Red HouseList the residential district of the Red House members.members.
SELECT DISTINCT dcode FROM student ;
WHERE hcode="R"
dcode
HHM
KWC
MKK
SSP
TST
YMT
Result

14. General StructureGeneral Structure
IIeg. 4eg. 4 List the names and ages (1 d.p.) of 1B girls.List the names and ages (1 d.p.) of 1B girls.
1B Girls ?1B Girls ?

15. Condition for "1BCondition for "1B
Girls":Girls":
1)1) class =class = "1B""1B"
2)2) sex =sex = "F""F"
3)3) Both ( AND operator)Both ( AND operator)
General StructureGeneral Structure
IIeg. 4eg. 4 List the names and ages (1 d.p.) of 1B girls.List the names and ages (1 d.p.) of 1B girls.

16. General StructureGeneral Structure
IIeg. 4eg. 4 List the names and ages (1 d.p.) of 1B girls.List the names and ages (1 d.p.) of 1B girls.
What is "age"?What is "age"?

17. Functions:Functions:
# days :# days : DATE( ) – dobDATE( ) – dob
# years :(DATE( ) – dob) / 365# years :(DATE( ) – dob) / 365
1 d.p.:1 d.p.: ROUND(__ , 1)ROUND(__ , 1)
General StructureGeneral Structure
IIeg. 4eg. 4 List the names and ages (1 d.p.) of 1B girls.List the names and ages (1 d.p.) of 1B girls.

18. General StructureGeneral Structure
IIeg. 4eg. 4 List the names and ages (1 d.p.) of 1B girls.List the names and ages (1 d.p.) of 1B girls.
SELECT name, ROUND((DATE( )-dob)/365,1) AS age ;
FROM student WHERE class="1B" AND sex="F"
name age
Wendy 12.1
Kitty 11.5
Janet 12.4
Sandy 12.3
Mimi 12.2
Result

19. General StructureGeneral Structure
IIeg. 5eg. 5 List the names, id of 1A students with no feeList the names, id of 1A students with no fee remission.remission.
SELECT name, id, class FROM student ;
WHERE class="1A" AND NOT remission
name id class
Peter 9801 1A
Mary 9802 1A
Luke 9810 1A
Bobby 9811 1A
Aaron 9812 1A
Ron 9813 1A
Gigi 9824 1A
: : :
Result

20. ComparisonComparison
IIII exprexpr IN (IN ( value1value1,, value2value2,, value3value3))
exprexpr BETWEENBETWEEN value1value1 ANDAND value2value2
exprexpr LIKE "%_"LIKE "%_"

21. ComparisonComparison
IIIIeg. 6eg. 6 List the students who were born on WednesdayList the students who were born on Wednesday or Saturdays.or Saturdays.
SELECT name, class, CDOW(dob) AS bdate ;
FROM student ;
WHERE DOW(dob) IN (4,7)
name class bdate
Peter 1A Wednesday
Wendy 1B Wednesday
Kevin 1C Saturday
Luke 1A Wednesday
Aaron 1A Saturday
: : :
Result

22. ComparisonComparison
IIIIeg. 7eg. 7 List the students who were not born in January,List the students who were not born in January, March, June,March, June,
September.September.
SELECT name, class, dob FROM student ;
WHERE MONTH(dob) NOT IN (1,3,6,9)
name class dob
Wendy 1B 07/09/86
Tobe 1B 10/17/86
Eric 1C 05/05/87
Patty 1C 08/13/87
Kevin 1C 11/21/87
Bobby 1A 02/16/86
Aaron 1A 08/02/86
: : :
Result

23. ComparisonComparison
IIIIeg. 8eg. 8 List the 1A students whose Math test score isList the 1A students whose Math test score is between 80 and 90between 80 and 90
(incl.)(incl.)
SELECT name, mtest FROM student ;
WHERE class="1A" AND ;
mtest BETWEEN 80 AND 90
name mtest
Luke 86
Aaron 83
Gigi 84
Result

24. ComparisonComparison
IIIIeg. 9eg. 9 List the students whose names start with "T".List the students whose names start with "T".
SELECT name, class FROM student ;
WHERE name LIKE "T%"
name class
Tobe 1B
Teddy 1B
Tim 2A
Result

25. ComparisonComparison
IIIIeg. 10eg. 10 List the Red house members whose names containList the Red house members whose names contain "a" as the 2nd"a" as the 2nd
letter.letter.
SELECT name, class, hcode FROM student ;
WHERE name LIKE "_a%" AND hcode="R"
name class hcode
Aaron 1A R
Janet 1B R
Paula 2A R
Result

26. GroupingGroupingIIIIII
SELECT ...... FROM ...... WHERESELECT ...... FROM ...... WHERE conditioncondition ;;
GROUP BYGROUP BY groupexprgroupexpr [HAVING[HAVING requirementrequirement]]
Group functions:Group functions:
COUNT( ), SUM( ), AVG( ), MAX( ), MIN( )COUNT( ), SUM( ), AVG( ), MAX( ), MIN( )
– groupexpr specifies the related rows to be grouped
as one entry. Usually it is a column.
– WHERE condition specifies the condition of
individual rows before the rows are group.
HAVING requirement specifies the condition
involving the whole group.

27. GroupingGroupingIIIIII
eg. 11eg. 11 List the number of students of each class.List the number of students of each class.

28. COUNT( )COUNT( )
Group By ClassGroup By Class
1A1A
COUNT( )COUNT( )
1B1B
COUNT( )COUNT( )
1C1C
1A1A
1B1B
1C1C
StudentStudent
class
1A1A
1A1A
1A1A
1B1B
1B1B
1B1B
1B1B
1B1B
1B1B
1C1C
1C1C
1C1C

29. GroupingGroupingIIIIII
SELECT class, COUNT(*) FROM student ;
GROUP BY class
class cnt
1A 10
1B 9
1C 9
2A 8
2B 8
2C 6
eg. 11eg. 11 List the number of students of each class.List the number of students of each class.
Result

30. GroupingGroupingIIIIII
eg. 12eg. 12 List the average Math test score of each class.List the average Math test score of each class.

31. Group By ClassGroup By Class
AVG( )AVG( )
AVG( )AVG( )
AVG( )AVG( )
1A1A
1B1B
1C1C
StudentStudent
class
1A1A
1A1A
1A1A
1B1B
1B1B
1B1B
1B1B
1B1B
1B1B
1C1C
1C1C
1C1C

32. GroupingGroupingIIIIII
eg. 12eg. 12 List the average Math test score of each class.List the average Math test score of each class.
SELECT class, AVG(mtest) FROM student ;
GROUP BY class
class avg_mtest
1A 85.90
1B 70.33
1C 37.89
2A 89.38
2B 53.13
2C 32.67
Result

33. GroupingGroupingIIIIII
eg. 13eg. 13 List the number of girls of each district.List the number of girls of each district.
SELECT dcode, COUNT(*) FROM student ;
WHERE sex="F" GROUP BY dcode
dcode cnt
HHM 6
KWC 1
MKK 1
SSP 5
TST 4
YMT 8
Result

34. GroupingGroupingIIIIII
eg. 14eg. 14 List the max. and min. test score of Form 1List the max. and min. test score of Form 1 students of eachstudents of each
district.district.
SELECT MAX(mtest), MIN(mtest), dcode ;
FROM student ;
WHERE class LIKE "1_" GROUP BY dcode
max_mtest min_mtest dcode
92 36 HHM
91 19 MKK
91 31 SSP
92 36 TST
75 75 TSW
88 38 YMT
Result

35. GroupingGroupingIIIIII
eg. 15eg. 15 List the average Math test score of the boys inList the average Math test score of the boys in each class. The listeach class. The list
should not contain class withshould not contain class with less than 3 boys.less than 3 boys.
SELECT AVG(mtest), class FROM student ;
WHERE sex="M" GROUP BY class ;
HAVING COUNT(*) >= 3
avg_mtest class
86.00 1A
77.75 1B
35.60 1C
86.50 2A
56.50 2B
Result

36. Display OrderDisplay OrderIVIV
SELECT ...... FROM ...... WHERE ......SELECT ...... FROM ...... WHERE ......
GROUP BY ..... ;GROUP BY ..... ;
ORDER BYORDER BY colnamecolname ASC / DESCASC / DESC

37. Display OrderDisplay OrderIVIV
SELECT name, id FROM student ;
WHERE sex="M" AND class="1A" ORDER BY name
eg. 16eg. 16 List the boys of class 1A, order by their names.List the boys of class 1A, order by their names.
name id
Peter 9801
Johnny 9803
Luke 9810
Bobby 9811
Aaron 9812
Ron 9813
ORDER BY
dcode
name id
Aaron 9812
Bobby 9811
Johnny 9803
Luke 9810
Peter 9801
Ron 9813
Result

38. Display OrderDisplay OrderIVIV
SELECT name, id, class, dcode FROM student ;
WHERE class="2A" ORDER BY dcode
eg. 17eg. 17 List the 2A students by their residential district.List the 2A students by their residential district.
name id class dcode
Jimmy 9712 2A HHM
Tim 9713 2A HHM
Samual 9714 2A SHT
Rosa 9703 2A SSP
Helen 9702 2A TST
Joseph 9715 2A TSW
Paula 9701 2A YMT
Susan 9704 2A YMT
Result

39. Display OrderDisplay OrderIVIV
SELECT COUNT(*) AS cnt, dcode FROM student ;
GROUP BY dcode ORDER BY cnt DESC
eg. 18eg. 18 List the number of students of each districtList the number of students of each district
(in desc. order).(in desc. order).
cnt docode
11 YMT
10 HHM
10 SSP
9 MKK
5 TST
2 TSW
1 KWC
1 MMK
1 SHT
Result

40. Display OrderDisplay OrderIVIV
SELECT name, class, hcode FROM student ;
WHERE sex="M" ORDER BY hcode, class
eg. 19eg. 19 List the boys of each house order by theList the boys of each house order by the classes. (2-levelclasses. (2-level
ordering)ordering)

41. Display OrderDisplay OrderIVIV
name hcode class
Bobby B 1A
Teddy B 1B
Joseph B 2A
Zion B 2B
Leslie B 2C
Johnny G 1A
Luke G 1A
Kevin G 1C
George G 1C
: : :
Result
Order
by
class
Blue
House
Green
House
:
:
Order
by
hcode

42. OutputOutput
VV
INTO TABLE tablename the output table is saved as a
database file in the disk.
INTO CURSOR temp the output is stored in the
working memory temporarily.
TO FILE filename [ADDITIVE] output to a text file.
(additive = append)
TO PRINTER send to printer.
TO SCREEN display on screen.

43. OutputOutput
VVeg. 20eg. 20 List the students in desc. order of their names andList the students in desc. order of their names and save the resultsave the result
as a database file name.dbf.as a database file name.dbf.
SELECT * FROM student ;
ORDER BY name DESC INTO TABLE name.dbf
id name dob sex class mtest hcode dcode remission
9707 Zion 07/29/85 M 2B 51 B MKK .F.
9709 Yvonne 08/24/85 F 2C 10 R TST .F.
9804 Wendy 07/09/86 F 1B 84 B YMT .F.
9819 Vincent 03/15/85 M 1C 29 Y MKK .F.
9805 Tobe 10/17/86 M 1B 88 R YMT .F.
9713 Tim 06/19/85 M 2A 91 R HHM .T.
9816 Teddy 01/30/86 M 1B 64 B SSP .F.
: : : : : : : : :
Result

44. OutputOutput
VVeg. 21eg. 21 Print the Red House members by their classes, sexPrint the Red House members by their classes, sex and name.and name.
SELECT class, name, sex FROM student ;
WHERE hcode="R" ;
ORDER BY class, sex DESC, name TO PRINTER
class name sex
1A Aaron M
1A Peter M
1A Ron M
1B Tobe M
1B Janet F
1B Kitty F
1B Mimi F
: : :
Result

45. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
A B
The union of A and B (A∪B)
A table containing all the rows from A and B.

46. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
The intersection of A and B (A∩B)
A table containing only rows that appear in both A and B.
A B

47. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
The difference of A and B (A–B)
A table containing rows that appear in A but not in B.
A B

48. 33
Consider the members of the Bridge Club andConsider the members of the Bridge Club and
the Chess Club. The two database files havethe Chess Club. The two database files have
the same structure:the same structure:
The Situation:
Bridge Club & Chess Club
field type width contents
id numeric 4 student id number
name character 10 name
sex character 1 sex: M / F
class character 2 class

49. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
Before using SQL, open the two tables:Before using SQL, open the two tables:
Bridge [A] Chess [B]
id name sex class id name sex class
1 9812 Aaron M 1A 1 9802 Mary F 1A
2 9801 Peter M 1A 2 9801 Peter M 1A
3 9814 Kenny M 1B 3 9815 Eddy M 1B
4 9806 Kitty F 1B 4 9814 Kenny M 1B
5 9818 Edmond M 1C 5 9817 George M 1C
: : : : : : : :
SELECT ASELECT A
USE bridgeUSE bridge
SELECT BSELECT B
USE chessUSE chess

50. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
SELECT * FROM bridge ;
UNION ;
SELECT * FROM chess ;
ORDER BY class, name INTO TABLE party
eg. 22eg. 22 The two clubs want to hold a joint party.The two clubs want to hold a joint party. Make a list of allMake a list of all
students. (Union)students. (Union)
SELECT ...... FROM ...... WHERE ...... ;SELECT ...... FROM ...... WHERE ...... ;
UNION ;UNION ;
SELECT ...... FROM ...... WHERE ......SELECT ...... FROM ...... WHERE ......
Result

51. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
SELECT * FROM bridge ;
WHERE id IN ( SELECT id FROM chess ) ;
TO PRINTER
eg. 23eg. 23 Print a list of students who are members of bothPrint a list of students who are members of both clubs.clubs.
(Intersection)(Intersection)
SELECT ...... FROMSELECT ...... FROM table1table1 ;;
WHEREWHERE colcol IN ( SELECTIN ( SELECT colcol FROMFROM table2table2 ))
Result

52. Union, Intersection andUnion, Intersection and
Difference of TablesDifference of Tables33
SELECT * FROM bridge ;
WHERE id NOT IN ( SELECT id FROM chess ) ;
INTO TABLE diff
eg. 24eg. 24 Make a list of students who are members of theMake a list of students who are members of the Bridge Club butBridge Club but
not Chess Club. (Difference)not Chess Club. (Difference)
SELECT ...... FROMSELECT ...... FROM table1table1 ;;
WHEREWHERE colcol NOT IN ( SELECTNOT IN ( SELECT colcol FROMFROM table2table2 ))
Result

53. Multiple Tables:Multiple Tables:44
• SQL provides a convenient operation toSQL provides a convenient operation to
retrieve information from multiple tables.retrieve information from multiple tables.
• This operation is calledThis operation is called joinjoin..
• The join operation willThe join operation will combinecombine the tables intothe tables into
one large table with all possible combinationsone large table with all possible combinations
(Math: Cartesian Product), and then it will(Math: Cartesian Product), and then it will
filterfilter the rows of this combined table to yieldthe rows of this combined table to yield
usefuluseful information.information.

54. Multiple Tables:Multiple Tables:44
field1
A
B
field2
1
2
3
field1 field2
A
A
A
1
2
3
B
B
B
1
2
3

55. 44
Each student should learn a musical instrument.Each student should learn a musical instrument.
Two database files:Two database files: student.dbfstudent.dbf && music.dbfmusic.dbf
The common field:The common field: student idstudent id
fieldfield typetype widthwidth contentscontents
idid numericnumeric 44 student id numberstudent id number
typetype charactercharacter 1010 type of the music instrumenttype of the music instrument
The Situation:
Music Lesson
SELECT ASELECT A
USE studentUSE student
SELECT BSELECT B
USE musicUSE music

56. Natural JoinNatural Join44
AA Natural JoinNatural Join is a join operation that joins twois a join operation that joins two
tables bytables by their common column. This operationtheir common column. This operation
is similar to the setting relation of two tables.is similar to the setting relation of two tables.
SELECT a.comcol, a.SELECT a.comcol, a.col1col1, b., b.col2col2,, expr1expr1,, expr2expr2 ;;
FROMFROM table1table1 a,a, table2table2 b ;b ;
WHERE a.WHERE a.comcolcomcol = b.= b.comcolcomcol

57. Natural JoinNatural Join44
MusicMusic
idid
98019801
typetype
StudentStudent
98019801
idid namename classclass
98019801
ProductProduct
idid namename classclass typetype
Same idSame id
JoinJoin
eg. 25eg. 25 Make a list of students and the instruments theyMake a list of students and the instruments they
learn. (Natural Join)learn. (Natural Join)

58. SELECT s.class, s.name, s.id, m.type ;
FROM student s, music m ;
WHERE s.id=m.id ORDER BY class, name
Natural JoinNatural Join44
class name id type
1A Aaron 9812 Piano
1A Bobby 9811 Flute
1A Gigi 9824 Recorder
1A Jill 9820 Piano
1A Johnny 9803 Violin
1A Luke 9810 Piano
1A Mary 9802 Flute
: : : :
Result
eg. 25eg. 25 Make a list of students and the instruments theyMake a list of students and the instruments they learn.learn.
(Natural Join)(Natural Join)

59. eg. 26eg. 26 Find the number of students learning piano inFind the number of students learning piano in each class.each class.
Natural JoinNatural Join44
Three Parts :Three Parts :
(1)(1) Natural Join.Natural Join.
(2)(2) Condition:Condition: m.type="Piano"m.type="Piano"
(3)(3) GROUP BY classGROUP BY class

60. Natural JoinNatural Join44
MusicMusic
StudentStudent
ProductProduct
JoinJoin
ConditionCondition
m.type= "Piano"m.type= "Piano"
Group ByGroup By
classclass
eg. 26eg. 26

61. eg. 26eg. 26 Find the number of students learning piano inFind the number of students learning piano in each class.each class.
SELECT s.class, COUNT(*) ;
FROM student s, music m ;
WHERE s.id=m.id AND m.type="Piano" ;
GROUP BY class ORDER BY class
Natural JoinNatural Join44
class cnt
1A 4
1B 2
1C 1
Result

62. AnAn Outer JoinOuter Join is a join operation that includesis a join operation that includes
rows that have a match, plus rows that do notrows that have a match, plus rows that do not
have a match in the other table.have a match in the other table.
Outer JoinOuter Join44

63. eg. 27eg. 27 List the students who have not yet chosen anList the students who have not yet chosen an instrument. (Noinstrument. (No
match)match)
Outer JoinOuter Join44
No matchNo match
MusicMusic
idid typetype
StudentStudent
98019801
idid namename classclass

64. eg. 27eg. 27 List the students who have not yet chosen anList the students who have not yet chosen an instrument. (Noinstrument. (No
match)match)
SELECT class, name, id FROM student ;
WHERE id NOT IN ( SELECT id FROM music ) ;
ORDER BY class, name
Outer JoinOuter Join44
Result
class name id
1A Mandy 9821
1B Kenny 9814
1B Tobe 9805
1C Edmond 9818
1C George 9817
: : :

65. eg. 28eg. 28 Make a checking list of students and theMake a checking list of students and the instruments they learn. The listinstruments they learn. The list
should alsoshould also contain the students without an instrument.contain the students without an instrument.
(Outer Join)(Outer Join)
Outer JoinOuter Join44

66. Outer JoinOuter Join44
Natural JoinNatural Join
No MatchNo Match
Outer JoinOuter Join
eg. 28eg. 28

67. SELECT s.class, s.name, s.id, m.type ;
FROM student s, music m ;
WHERE s.id=m.id ;
Outer JoinOuter Join44
UNION ;
SELECT class, name, id, "" ;
FROM student ;
WHERE id NOT IN ( SELECT id FROM music ) ;
ORDER BY 1, 2
eg. 28eg. 28

68. Outer JoinOuter Join44
emptyclass name id
1A Mandy 9821
1B Kenny 9814
1B Tobe 9805
1C Edmond 9818
1C George 9817
: : :
No Match
class name id type
1A Aaron 9812 Piano
1A Bobby 9811 Flute
1A Gigi 9824 Recorder
1A Jill 9820 Piano
1A Johnny 9803 Violin
1A Luke 9810 Piano
1A Mary 9802 Flute
: : : :
Natural Join
class name id type
1A Aaron 9812 Piano
1A Bobby 9811 Flute
1A Gigi 9824 Recorder
1A Jill 9820 Piano
1A Johnny 9803 Violin
1A Luke 9810 Piano
1A Mandy 9821
1A Mary 9802 Flute
1A Peter 9801 Piano
1A Ron 9813 Guitar
1B Eddy 9815 Piano
1B Janet 9822 Guitar
1B Kenny 9814
1B Kitty 9806 Recorder
: : : :
Outer Join