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EJERCICIOS DE
CONVERSIÓN DE
UNIDADES
(S.I.)
CRISTHIAN Y. HILASACA ZEA
Para resolver: La distancia que hay del home al jardín central de un campo de béisbol es
de 400 pies (ft), convierta esta cantidad a metros.
Solución
1. Identificamos la unidad de partida y la unidad
de destino (donde debemos llegar).
El ejemplo nos indica que debemos expresar
ft (pies) en m (metros).
2. Identificamos la equivalencia
1 m = 3,28 ft
3. Escribimos el valor que nos piden convertir,
multiplicado por su respectiva equivalencia
400 𝑓𝑡 ×
1 𝑚
3,28 𝑓𝑡
= 121,95 𝑚
Respuesta
Para practicar:
❖ Convertir 6 Km a pies
❖ Convertir 7 galones a centímetros cúbicos
❖ Convertir 100 millas a Km
Para resolver: Un automóvil se desplaza a una velocidad de 20 m/s. Expresar dicha velocidad
en Km/h
Solución
1. Identificamos la unidad de partida y la unidad
de destino (donde debemos llegar).
El ejemplo nos indica que debemos expresar m/s
(metros por segundo) en Km/h (kilómetros por
hora)
2. Identificamos la equivalencia
3. Escribimos el valor que nos piden convertir,
multiplicado por su respectiva equivalencia
Respuesta
Para practicar:
❖ Convertir 2500 L/s a m3/h
❖ Convertir 50 mL/min a L/s
❖ Convertir 800 g/cm3 a Kg/m3
1 Km = 1000 m
1 h = 60 min
1 min = 60 s
20
𝑚
𝑠
×
1 𝐾𝑚
1 000 𝑚
×
60 𝑠
1 𝑚𝑖𝑚
×
60 𝑚𝑖𝑛
1 ℎ
= 79,2 𝐾𝑚/ℎ
PREFIJOS
S.I.
ESCALAS DE
TEMPERATURA
𝑪
𝟓
=
𝑭 − 𝟑𝟐
𝟗
=
𝑲 − 𝟐𝟕𝟑
𝟓
=
𝑹 − 𝟒𝟗𝟐
𝟗
EJERCICIOS
PROPUESTOS
❑ Convertir 5 dm/min a hm/cs
SOLUCIÓN 5
𝑑𝑚
𝑚𝑖𝑛
×
10−1𝑚
1 𝑑𝑚
×
1 ℎ𝑚
102𝑚
×
1 𝑚𝑖𝑛
60 𝑠
×
10−2 𝑠
1 𝑐𝑠
= 0,0000008333333 ℎ𝑚/𝑐𝑠
= 8,3 × 10−7 ℎ𝑚/𝑐𝑠
❑ Convertir 160 m/h a Km/ns
SOLUCIÓN 160
𝑚
ℎ
×
10−6𝑚
1 𝑚
×
1 𝐾𝑚
1000 𝑚
×
1 ℎ
3600 𝑠
×
10−9 𝑠
1 𝑛𝑠
= 0,0000000000000000000444 𝐾𝑚/𝑛𝑠
= 4,44 × 10−20 𝐾𝑚/𝑛𝑠
❑ Convertir 2456x10-2 mg/ms a Ton/h
SOLUCIÓN 24,56
𝑚𝑔
𝑚𝑠
×
10−3𝑔
1 𝑚𝑔
×
1 𝐾𝑔
1000 𝑔
×
1 𝑇𝑜𝑛
1000 𝐾𝑔
×
1 𝑚𝑠
10−3 𝑠
×
3600 𝑠
1 ℎ
= 0,088416 𝑇𝑜𝑛/ℎ
= 8,8416 × 10−2 𝑇𝑜𝑛/ℎ
▪ Convertir 280°F a R
▪ Convertir 0,0002 x107 °C a K
▪ Convertir 0,05 x104 R a °C
𝐹 − 32
9
=
𝑅 − 492
9
SOLUCIÓN
𝐹 = 280
𝑅 = ?
280 − 32
9
=
𝑅 − 492
9
280 − 32 = 𝑅 − 492 248 = 𝑅 − 492 𝑅 = 740
𝐶
5
=
𝐾 − 273
5
SOLUCIÓN
𝐶 = 2000
𝐾 = ?
2000
5
=
𝐾 − 273
5
2000 = 𝐾 − 273 2000 + 273 = 𝐾 𝐾 = 2273
𝑅 − 492
9
=
𝐶
5
SOLUCIÓN
𝑅 = 500
C = ?
500 − 492
9
=
𝐶
5
8
9
=
𝐶
5
(8)(5)
9
= 𝐶
40
9
= 𝐶 𝐶 = 4,44
PARA PRACTICAR EN CASA …
❑ Convertir 500 mm/s a Km/min
❑ Convertir 1200 m3/cs a cL/h
❑ Convertir 0,0055 x105 g/mL a Kg/m3
❑ Convertir 5x103 g/cL a Mg/nL
❑ Convertir 0,0256 x104 °C a R
❑ Convertir 15000 x10-3 °F a °C
❑ Convertir 12,3 x104 dg/s a lb/día
❑ Convertir 0,540 x104 °F a R
❑ Convertir 25 m3/min a mL/ms
❑ Convertir 5x103 pg/dL a hg/L
PARA PRACTICAR …
Determinar el número de cifras significativas en las siguientes cantidades:
❑ 2804 m
❑ -2,84 Km
❑ 0,0029 mL
❑ 0,003068 g
❑ 8,1x104 s
❑ 12345 m
❑ 70x10-5 h
❑ 1999,0 cm
❑ 20200 mm
4 cifras
3 cifras
2 cifras
4 cifras
2 cifras
5 cifras
1 cifra
5 cifras
3 cifras
S.I. (ejercicios propuestos)

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S.I. (ejercicios propuestos)

  • 2. Para resolver: La distancia que hay del home al jardín central de un campo de béisbol es de 400 pies (ft), convierta esta cantidad a metros. Solución 1. Identificamos la unidad de partida y la unidad de destino (donde debemos llegar). El ejemplo nos indica que debemos expresar ft (pies) en m (metros). 2. Identificamos la equivalencia 1 m = 3,28 ft 3. Escribimos el valor que nos piden convertir, multiplicado por su respectiva equivalencia 400 𝑓𝑡 × 1 𝑚 3,28 𝑓𝑡 = 121,95 𝑚 Respuesta Para practicar: ❖ Convertir 6 Km a pies ❖ Convertir 7 galones a centímetros cúbicos ❖ Convertir 100 millas a Km
  • 3. Para resolver: Un automóvil se desplaza a una velocidad de 20 m/s. Expresar dicha velocidad en Km/h Solución 1. Identificamos la unidad de partida y la unidad de destino (donde debemos llegar). El ejemplo nos indica que debemos expresar m/s (metros por segundo) en Km/h (kilómetros por hora) 2. Identificamos la equivalencia 3. Escribimos el valor que nos piden convertir, multiplicado por su respectiva equivalencia Respuesta Para practicar: ❖ Convertir 2500 L/s a m3/h ❖ Convertir 50 mL/min a L/s ❖ Convertir 800 g/cm3 a Kg/m3 1 Km = 1000 m 1 h = 60 min 1 min = 60 s 20 𝑚 𝑠 × 1 𝐾𝑚 1 000 𝑚 × 60 𝑠 1 𝑚𝑖𝑚 × 60 𝑚𝑖𝑛 1 ℎ = 79,2 𝐾𝑚/ℎ
  • 4.
  • 5.
  • 6.
  • 9. 𝑪 𝟓 = 𝑭 − 𝟑𝟐 𝟗 = 𝑲 − 𝟐𝟕𝟑 𝟓 = 𝑹 − 𝟒𝟗𝟐 𝟗
  • 11. ❑ Convertir 5 dm/min a hm/cs SOLUCIÓN 5 𝑑𝑚 𝑚𝑖𝑛 × 10−1𝑚 1 𝑑𝑚 × 1 ℎ𝑚 102𝑚 × 1 𝑚𝑖𝑛 60 𝑠 × 10−2 𝑠 1 𝑐𝑠 = 0,0000008333333 ℎ𝑚/𝑐𝑠 = 8,3 × 10−7 ℎ𝑚/𝑐𝑠 ❑ Convertir 160 m/h a Km/ns SOLUCIÓN 160 𝑚 ℎ × 10−6𝑚 1 𝑚 × 1 𝐾𝑚 1000 𝑚 × 1 ℎ 3600 𝑠 × 10−9 𝑠 1 𝑛𝑠 = 0,0000000000000000000444 𝐾𝑚/𝑛𝑠 = 4,44 × 10−20 𝐾𝑚/𝑛𝑠 ❑ Convertir 2456x10-2 mg/ms a Ton/h SOLUCIÓN 24,56 𝑚𝑔 𝑚𝑠 × 10−3𝑔 1 𝑚𝑔 × 1 𝐾𝑔 1000 𝑔 × 1 𝑇𝑜𝑛 1000 𝐾𝑔 × 1 𝑚𝑠 10−3 𝑠 × 3600 𝑠 1 ℎ = 0,088416 𝑇𝑜𝑛/ℎ = 8,8416 × 10−2 𝑇𝑜𝑛/ℎ
  • 12. ▪ Convertir 280°F a R ▪ Convertir 0,0002 x107 °C a K ▪ Convertir 0,05 x104 R a °C 𝐹 − 32 9 = 𝑅 − 492 9 SOLUCIÓN 𝐹 = 280 𝑅 = ? 280 − 32 9 = 𝑅 − 492 9 280 − 32 = 𝑅 − 492 248 = 𝑅 − 492 𝑅 = 740 𝐶 5 = 𝐾 − 273 5 SOLUCIÓN 𝐶 = 2000 𝐾 = ? 2000 5 = 𝐾 − 273 5 2000 = 𝐾 − 273 2000 + 273 = 𝐾 𝐾 = 2273 𝑅 − 492 9 = 𝐶 5 SOLUCIÓN 𝑅 = 500 C = ? 500 − 492 9 = 𝐶 5 8 9 = 𝐶 5 (8)(5) 9 = 𝐶 40 9 = 𝐶 𝐶 = 4,44
  • 13. PARA PRACTICAR EN CASA … ❑ Convertir 500 mm/s a Km/min ❑ Convertir 1200 m3/cs a cL/h ❑ Convertir 0,0055 x105 g/mL a Kg/m3 ❑ Convertir 5x103 g/cL a Mg/nL ❑ Convertir 0,0256 x104 °C a R ❑ Convertir 15000 x10-3 °F a °C ❑ Convertir 12,3 x104 dg/s a lb/día ❑ Convertir 0,540 x104 °F a R ❑ Convertir 25 m3/min a mL/ms ❑ Convertir 5x103 pg/dL a hg/L
  • 14. PARA PRACTICAR … Determinar el número de cifras significativas en las siguientes cantidades: ❑ 2804 m ❑ -2,84 Km ❑ 0,0029 mL ❑ 0,003068 g ❑ 8,1x104 s ❑ 12345 m ❑ 70x10-5 h ❑ 1999,0 cm ❑ 20200 mm 4 cifras 3 cifras 2 cifras 4 cifras 2 cifras 5 cifras 1 cifra 5 cifras 3 cifras