Khemendra Shukla
M.Sc. (III Sem)
Applied Physics
BBAU, Lucknow
1
Contents
i.

Rotational
spectra:
salient
features

ii. Classification
of molecules
iii. Rigid rotator:
explanation of
rotational
spectra

iv. Interaction of
radiation with
rotating molecules
v. Intensity of
spectral lines
vi. Isotope effect
vii. Non-rigid rotator

viii.Applications

2
Rotation Of Molecules
 Spectroscopy in the microwave region is concerned with
the study of rotating molecules

 Rotation of 3D body may be quite complex
 Rotational components about three mutually
perpendicular directions through the centre of gravity the principal axis of rotation.

 Three principal moments of inertia IA , IB , and IC
designated.

3
Classification of molecules
(i) Linear molecules:
 Atoms are arranged in a straight line.

 e.g. HCl or OCS
The three directions of rotation may be taken as :

(a) about the bond axis,
(b) end-over-end rotation in the plane of the paper,

(c) end-over-end rotation at right angles to the plane. Here

IA = 0 and IB = IC

4

Cont…
(ii) Symmetric top: Consider a molecule such as methyl
fluoride, three hydrogen atoms are bonded tetrahedrally
to the carbon
The moment of inertia about the C-F bond axis is now not
negligible, however, because it involves the rotation of
three comparatively massive hydrogen atoms of this axis
Symmetric tops: IB=IC≠IA IA≠0

5

Cont…
Two subdivisions of this class
 Methyl fluoride above, IB=I-C>IA, then the molecule is
called prolate symmetric top
 If IB=IC<IA, it is referred to as oblate
An example of the layer type is boron
trichloride, which, as shown, is planar and symmetrical.
IA = 2IB = 2IC
6
(iii) Spherical top: when a molecule has all three moments
of inertia identical, it is called spherical tops.

e.g, CH4

IA=IB=IC.
(iv) Asymmetric top: These molecules, to which the
majority of substance belong, have all three moments of
inertia different:

IA≠IB≠IC
Simple example are H2O and CH2=CHCl
7
8
Rotational Spectra:Molecular Requirements
 Spectroscopy in the microwave region is concerned with the study of
rotating molecules.
 Only molecules that have a permanent dipole moment can absorb or
emit electromagnetic radiation in such transitions.

 In the rotation of HCl, fluctuation seen to be exactly similar to the
fluctuating electric field of radiation.
 Thus interaction can occur, energy can be absorbed or emitted and
the rotation gives rise to a spectrum.
9
Which type of molecule doesn’t shoW
rotational spectrum and Why……???
 In homonuclear molecules like N2 & O2 , no change occur in
dipole moment during the rotation.

 Linear diatomic molecules are rotationally inactive for rotation
about the bond axis.
i.

The moment of inertia is very small (zero) about the bond axis.

ii. No change in dipole occurs when it is rotating about bond axis.
 Homonuclear molecules, however show rotational Raman spectra
(which is arises due to the polarisability of the molecules.)

10
Techniques And Instrumentation

Fig.1

The basic requirements for observing pure rotational

spectra in absorption are a source of continuous
radiation in the proper infrared region, a dispersive
device and a detector.

11

Cont
 Radiation from the source is taken, which passes through
the HCl vapour
 The transmitted beam falls on a condensing mirror
 The collimated beam passes through a rock-salt prism
and is brought to a focus at the thermal detector by
means of a focusing mirror

12
I. Source and monochromator: Klystron valve is
monochromatic source, emits radiation over only a vey

narrow freq. range.

II. Beam direction: Achieved by use of waveguides
(rectangular) inside which radiation is confined.

III.Sample and sample space
IV. Detector

13
Molecule As A Rigid Rotator:
Diatomic Molecule
The simplest model of a rotating molecule is
that of a rigid rotator
By the definition of Centre of mass, we have
M1r1 = M2r2
Also

r1 + r 2 = r

From these two equation, we have
r1

M2
r
M1 M 2

and

r1

M1
r
M1 M 2

Fig.2

14
Now, the moment of inertia of the molecule about the axis of

rotation is given by
I = M1r12 + M2r22

=

M 1M 2 2
r
M1 M 2

M 1M 2
But
is the reduced mass µ of the molecule. Then
M1 M 2

I = µr2
Thus the diatomic molecule is equivalent to a single point mass µ

at a fixed distance r from the axis of rotation. Such a system
is called a rigid rotator.

15
Schrodinger equation for a rigid rotator, which is
2

8

2

h

2

E

0

The potential energy term V has been taken zero because r is
fixed.
In spherical polar coordinate system

1
sin

sin

1
r 2 sin 2

2

2

8
2

h

2

E

(i)

0

Using separable variable method

( , )
16
On solving by separable variable method, we have two equations
d2
d

And,

1 d
sin d

M2

2

d
sin
d

(ii)

2

8

h

IE

2

M2
sin 2

(iii)

0

The solution of the Φ-equation
m

1 iM
e
2

(iv)

On solving Θ-eq.
d 2P x
1 x
dx 2
2

dP x
2x
dx

8

2

h

IE

2

M2
Px
2
1 x

0
17
This eq. is identical to the associated Legendre’s differential

equation, provided
8

2

h

Or,

IE

2

EJ

J J 1

h2
JJ 1
2
8π I

(v)

In this expression, h is Planck's constant and I is moment of

inertia, either IB or IC , since both are equal.
The quantity J, which takes integral values from zero
upwards, is called the Rotational Quantum Number.
18
Spectrum Of Rigid Rotator
In the rotational region, spectra are usually discussed in terms
of wave numbers.

EJ
hc

h
8

2

Ic

J J 1 cm

1

(J=0, 1, 2, …)

(vi)

Where c is velocity of light, Is here expressed in cm s-1 .

BJ J 1 cm

1

(vii)

Where B, the rotational constant, is given by
B

h
8

2

Ic

cm

1

19
From eq.(vii) allowed energy levels
 For J = 0, ε is zero-molecule is not
rotating

 For J=1, the rotational energy is ε1=
2B and a rotating molecule has its

lowest angular momentum
 For increasing J values, εJ may have
no limit to the rotational energy

Fig.3

20
If we imagine the molecule to be in the the
ground state, in which no radiation occurs
To raise the molecule to J= 1 state energy
absorbed will be
εJ1 – εJ0 = 2B – 0 = 2B cm-1

J 0

J 1

2Bcm

1

Further for J=1 to J=2
J 1

J 2

Fig.3.1

4Bcm

1

21
In general,

Or,

J

J 1

J

J 1

BJ 1 J

2

2 B J 1 cm

BJ J 1
1

(viii)

Thus a step wise raising of the rotational energy results in an

absorption spectrum consisting of lines at 2B, 4B, 6B, … cm-1.
we need only consider transition in which J changes by one unit –

all other transitions being spectroscopically forbidden, such a
result, it is called a selection rule,
Selection rule: ΔJ= ±1
22
Quantization Of Rotational Energy
Energy and angular momentum of
rotator

E

1
I
2

2

P

I

The energy level expression

2 EI

h2
J J 1
4 2

Or,

P

J J 1 units
23
Intensity Of Spectral Lines
 For the transition other than ΔJ= ±1 (which are
forbidden), the transition probability is zero.
And the probability of all changes with ΔJ= ±1 is
almost the same.
 This does not mean that all spectral lines will be
equally intense.

24
 In normal gas sample, there will be different numbers of

molecule in each level therefore different total numbers of
molecules will carry out transition between the various levels.
 Since the intrinsic probabilities are identical, the line

intensities will be directly proportional to the initial numbers of
molecules in each level.
 The first factor governing the population of the level is the

Boltzmann distribution.
N j N0

exp

E j kT

exp

BhcJ J 1 kT

 The second factor governing the population of the levels is the
possibility of degeneracy in the energy states.
25
 Each level J is (2J+1) degenerate
 population is greater for higher J
states.

Total relative population at energy

EJ

(2J+1) exp (-EJ / kT)

26
Effect Of Isotopic Substitution
12CO

J=6

13CO

Energy
levels

5
4
3
2
1
0

cm-1 spectrum
2B

From 12C16O
decreases (

4B

8B

12B

13C16O,

mass increases, B
1/I), so energy levels lower.
27
Comparison Of Rotational Energy
Levels Of 12CO And 13CO
 isotopic masses accurately, to within 0.02% of other methods
for atoms in gaseous molecules;
 isotopic abundances from the absorption relative intensities.
Example:
for

12CO

for

13CO

Given :

12C

J=0

J=1

at

3.84235 cm-1
3.67337 cm-1

= 12.0000 ;

O = 15.9994

amu

28
Non Rigid Rotator
 In practice, spectrum lines are not exactly equidistant;
separation decreases with increasing J.

 Molecules stretched and become non rigid with increasing
rotation.

A correction term, containing the centrifugal distortion
constant, D, which corrects for the fact that the bond is

not rigid.
29
Spectrum Of Non-rigid Rotator
The Schrodinger eq. may set up for
non rigid rotator
EJ

h2
8

2

I

J J 1

h4
2
J2 J 1 J
32 2 I 2 r 2 k

Or,
j

EJ hc

BJ J 1

2

DJ 2 J 1 cm

1

Where D is centrifugal distortion
constant, given by,
D

h3
cm
4 2 2
32 I r kc

1

30
Applications Of Microwave Spectroscopy
Chemical analysis by microwave spectroscopy
 The rotational spectrum of a substance at room temperature

can examined accurately.
Molecular identification in space
 Electronic spectroscopy has been able to detect the presence of
various atoms, ions and few radicals in the light of stars but

recently simple stable molecules in space detected by using
microwave spectroscopy.
 130 molecules / ions have been identified in interstellar space by
their rotational emission spectra(rf‐astronomy).

31

Cont
32
Microwave oven
Do you know what is the basic principle of cooking in
microwave oven????

 Its mode of operation depends entirely upon the
absorption by the food of microwave radiation.

33
34

Rotational Spectra : Microwave Spectroscopy

  • 1.
    Khemendra Shukla M.Sc. (IIISem) Applied Physics BBAU, Lucknow 1
  • 2.
    Contents i. Rotational spectra: salient features ii. Classification of molecules iii.Rigid rotator: explanation of rotational spectra iv. Interaction of radiation with rotating molecules v. Intensity of spectral lines vi. Isotope effect vii. Non-rigid rotator viii.Applications 2
  • 3.
    Rotation Of Molecules Spectroscopy in the microwave region is concerned with the study of rotating molecules  Rotation of 3D body may be quite complex  Rotational components about three mutually perpendicular directions through the centre of gravity the principal axis of rotation.  Three principal moments of inertia IA , IB , and IC designated. 3
  • 4.
    Classification of molecules (i)Linear molecules:  Atoms are arranged in a straight line.  e.g. HCl or OCS The three directions of rotation may be taken as : (a) about the bond axis, (b) end-over-end rotation in the plane of the paper, (c) end-over-end rotation at right angles to the plane. Here IA = 0 and IB = IC 4 Cont…
  • 5.
    (ii) Symmetric top:Consider a molecule such as methyl fluoride, three hydrogen atoms are bonded tetrahedrally to the carbon The moment of inertia about the C-F bond axis is now not negligible, however, because it involves the rotation of three comparatively massive hydrogen atoms of this axis Symmetric tops: IB=IC≠IA IA≠0 5 Cont…
  • 6.
    Two subdivisions ofthis class  Methyl fluoride above, IB=I-C>IA, then the molecule is called prolate symmetric top  If IB=IC<IA, it is referred to as oblate An example of the layer type is boron trichloride, which, as shown, is planar and symmetrical. IA = 2IB = 2IC 6
  • 7.
    (iii) Spherical top:when a molecule has all three moments of inertia identical, it is called spherical tops. e.g, CH4 IA=IB=IC. (iv) Asymmetric top: These molecules, to which the majority of substance belong, have all three moments of inertia different: IA≠IB≠IC Simple example are H2O and CH2=CHCl 7
  • 8.
  • 9.
    Rotational Spectra:Molecular Requirements Spectroscopy in the microwave region is concerned with the study of rotating molecules.  Only molecules that have a permanent dipole moment can absorb or emit electromagnetic radiation in such transitions.  In the rotation of HCl, fluctuation seen to be exactly similar to the fluctuating electric field of radiation.  Thus interaction can occur, energy can be absorbed or emitted and the rotation gives rise to a spectrum. 9
  • 10.
    Which type ofmolecule doesn’t shoW rotational spectrum and Why……???  In homonuclear molecules like N2 & O2 , no change occur in dipole moment during the rotation.  Linear diatomic molecules are rotationally inactive for rotation about the bond axis. i. The moment of inertia is very small (zero) about the bond axis. ii. No change in dipole occurs when it is rotating about bond axis.  Homonuclear molecules, however show rotational Raman spectra (which is arises due to the polarisability of the molecules.) 10
  • 11.
    Techniques And Instrumentation Fig.1 Thebasic requirements for observing pure rotational spectra in absorption are a source of continuous radiation in the proper infrared region, a dispersive device and a detector. 11 Cont
  • 12.
     Radiation fromthe source is taken, which passes through the HCl vapour  The transmitted beam falls on a condensing mirror  The collimated beam passes through a rock-salt prism and is brought to a focus at the thermal detector by means of a focusing mirror 12
  • 13.
    I. Source andmonochromator: Klystron valve is monochromatic source, emits radiation over only a vey narrow freq. range. II. Beam direction: Achieved by use of waveguides (rectangular) inside which radiation is confined. III.Sample and sample space IV. Detector 13
  • 14.
    Molecule As ARigid Rotator: Diatomic Molecule The simplest model of a rotating molecule is that of a rigid rotator By the definition of Centre of mass, we have M1r1 = M2r2 Also r1 + r 2 = r From these two equation, we have r1 M2 r M1 M 2 and r1 M1 r M1 M 2 Fig.2 14
  • 15.
    Now, the momentof inertia of the molecule about the axis of rotation is given by I = M1r12 + M2r22 = M 1M 2 2 r M1 M 2 M 1M 2 But is the reduced mass µ of the molecule. Then M1 M 2 I = µr2 Thus the diatomic molecule is equivalent to a single point mass µ at a fixed distance r from the axis of rotation. Such a system is called a rigid rotator. 15
  • 16.
    Schrodinger equation fora rigid rotator, which is 2 8 2 h 2 E 0 The potential energy term V has been taken zero because r is fixed. In spherical polar coordinate system 1 sin sin 1 r 2 sin 2 2 2 8 2 h 2 E (i) 0 Using separable variable method ( , ) 16
  • 17.
    On solving byseparable variable method, we have two equations d2 d And, 1 d sin d M2 2 d sin d (ii) 2 8 h IE 2 M2 sin 2 (iii) 0 The solution of the Φ-equation m 1 iM e 2 (iv) On solving Θ-eq. d 2P x 1 x dx 2 2 dP x 2x dx 8 2 h IE 2 M2 Px 2 1 x 0 17
  • 18.
    This eq. isidentical to the associated Legendre’s differential equation, provided 8 2 h Or, IE 2 EJ J J 1 h2 JJ 1 2 8π I (v) In this expression, h is Planck's constant and I is moment of inertia, either IB or IC , since both are equal. The quantity J, which takes integral values from zero upwards, is called the Rotational Quantum Number. 18
  • 19.
    Spectrum Of RigidRotator In the rotational region, spectra are usually discussed in terms of wave numbers. EJ hc h 8 2 Ic J J 1 cm 1 (J=0, 1, 2, …) (vi) Where c is velocity of light, Is here expressed in cm s-1 . BJ J 1 cm 1 (vii) Where B, the rotational constant, is given by B h 8 2 Ic cm 1 19
  • 20.
    From eq.(vii) allowedenergy levels  For J = 0, ε is zero-molecule is not rotating  For J=1, the rotational energy is ε1= 2B and a rotating molecule has its lowest angular momentum  For increasing J values, εJ may have no limit to the rotational energy Fig.3 20
  • 21.
    If we imaginethe molecule to be in the the ground state, in which no radiation occurs To raise the molecule to J= 1 state energy absorbed will be εJ1 – εJ0 = 2B – 0 = 2B cm-1 J 0 J 1 2Bcm 1 Further for J=1 to J=2 J 1 J 2 Fig.3.1 4Bcm 1 21
  • 22.
    In general, Or, J J 1 J J1 BJ 1 J 2 2 B J 1 cm BJ J 1 1 (viii) Thus a step wise raising of the rotational energy results in an absorption spectrum consisting of lines at 2B, 4B, 6B, … cm-1. we need only consider transition in which J changes by one unit – all other transitions being spectroscopically forbidden, such a result, it is called a selection rule, Selection rule: ΔJ= ±1 22
  • 23.
    Quantization Of RotationalEnergy Energy and angular momentum of rotator E 1 I 2 2 P I The energy level expression 2 EI h2 J J 1 4 2 Or, P J J 1 units 23
  • 24.
    Intensity Of SpectralLines  For the transition other than ΔJ= ±1 (which are forbidden), the transition probability is zero. And the probability of all changes with ΔJ= ±1 is almost the same.  This does not mean that all spectral lines will be equally intense. 24
  • 25.
     In normalgas sample, there will be different numbers of molecule in each level therefore different total numbers of molecules will carry out transition between the various levels.  Since the intrinsic probabilities are identical, the line intensities will be directly proportional to the initial numbers of molecules in each level.  The first factor governing the population of the level is the Boltzmann distribution. N j N0 exp E j kT exp BhcJ J 1 kT  The second factor governing the population of the levels is the possibility of degeneracy in the energy states. 25
  • 26.
     Each levelJ is (2J+1) degenerate  population is greater for higher J states. Total relative population at energy EJ (2J+1) exp (-EJ / kT) 26
  • 27.
    Effect Of IsotopicSubstitution 12CO J=6 13CO Energy levels 5 4 3 2 1 0 cm-1 spectrum 2B From 12C16O decreases ( 4B 8B 12B 13C16O, mass increases, B 1/I), so energy levels lower. 27
  • 28.
    Comparison Of RotationalEnergy Levels Of 12CO And 13CO  isotopic masses accurately, to within 0.02% of other methods for atoms in gaseous molecules;  isotopic abundances from the absorption relative intensities. Example: for 12CO for 13CO Given : 12C J=0 J=1 at 3.84235 cm-1 3.67337 cm-1 = 12.0000 ; O = 15.9994 amu 28
  • 29.
    Non Rigid Rotator In practice, spectrum lines are not exactly equidistant; separation decreases with increasing J.  Molecules stretched and become non rigid with increasing rotation. A correction term, containing the centrifugal distortion constant, D, which corrects for the fact that the bond is not rigid. 29
  • 30.
    Spectrum Of Non-rigidRotator The Schrodinger eq. may set up for non rigid rotator EJ h2 8 2 I J J 1 h4 2 J2 J 1 J 32 2 I 2 r 2 k Or, j EJ hc BJ J 1 2 DJ 2 J 1 cm 1 Where D is centrifugal distortion constant, given by, D h3 cm 4 2 2 32 I r kc 1 30
  • 31.
    Applications Of MicrowaveSpectroscopy Chemical analysis by microwave spectroscopy  The rotational spectrum of a substance at room temperature can examined accurately. Molecular identification in space  Electronic spectroscopy has been able to detect the presence of various atoms, ions and few radicals in the light of stars but recently simple stable molecules in space detected by using microwave spectroscopy.  130 molecules / ions have been identified in interstellar space by their rotational emission spectra(rf‐astronomy). 31 Cont
  • 32.
  • 33.
    Microwave oven Do youknow what is the basic principle of cooking in microwave oven????  Its mode of operation depends entirely upon the absorption by the food of microwave radiation. 33
  • 34.

Editor's Notes

  • #4 Thus a body has three principal moments of inertia, one about each axis, usually designated IA, IB, and IC
  • #5 Molecules may be classified into groups according to the relative values of their three principal moments of inertia.
  • #6 As in the case of linear molecules, the end-over-end rotation in, and out of the plane of paper are still identical and we have IB=IC. The moment of inertia about the C-F bond axis is now not negligible, however, because it involves the rotation of three comparatively massive hydrogen atoms of this axis. Such a molecule spinning about this axis can be imagined as a top, and hence the name of the class.We have thenSymmetric tops: IB=IC≠IA IA≠0There are two subdivisions of this class which we may mention: if, as in methyl fluoride above, IB=I­C&gt;IA, then the molecule is called prolate symmetric top; whereas if IB=IC&lt;IA, it is referred to as oblate.
  • #19 its restriction to integral values arises directly out of solution to the Schrodinger equation and is by no means arbitrary, and it is restriction which effectively allows only certain discrete rotational energy levels to the molecule.