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1
Review!
• Hypothesis Testing - the process
of hypothesis testing involves
making a decision between two
opposing hypotheses.
• Null and Alternative Hypothesis
• Either reject H0 or fail to reject
H0.
2
Review!
• The null hypothesis (denoted by H0)
is a statement saying that there is
NO significant difference between
population parameter and the value
that is being claimed.
 the starting point of the investigation.
The symbolic form of the null
hypothesis is the symbol =.
3
Review!
 The alternative hypothesis (denoted by
H1 or Ha or HA) is the statement saying
that there is significant difference
between population parameter and the
value that is being claimed.
 This is a statement that will be true once
the null hypothesis is rejected.
 The symbolic form of the alternative
hypothesis must use one of these
symbols: , <, >.
4
Decision
Accept Null Reject Null
R
E
A Null is true
L
I Null is false
T
Y
Type II Error
(β error)
Correct
decision
Type I Error
(α error)
Correct
decision
Possible outcomes of testing
5
Lesson in Life!
There is NO
ERROR/MISTAKE
when we ACCEPT the
TRUTH and REJECT
what is FALSE.
6
Identifies the
Rejection region
for a given
Level of significance
7
Two types of test
Z- test
 The z- test is used to
predict the value the
population mean when
the variance (σ) is known,
or even when it is
unknown provided that
the sample size is large
based on the Central
Limit Theorem (CLT)
 n ≥ 30.
T-test
 When the population
variance (σ) is unknown
and the sample size is
limited, i.e., n < 30, then,
the t-test is the
appropriate test statistic.
 Different sample sizes
have different
distributions determined
by its degree of freedom
(df), df = n-1.
8
Two types of test
Z- test T-test
9
LEVEL OF SIGNIFICANCE
Level of
Significance
TYPES OF TEST
One-tailed test Two-tailed test
left-tailed (<) right-tailed (>) Both right and left
tailed (≠)
-1.645 1.645 ±1.960
-2.326 2.326 ±2.575
-1.282 1.282 ±1.645
10
Level of Significance, a and the Rejection Region
H0: m  3
H1: m < 3
0
0
0
H0: m  3
H1: m > 3
H0: m = 3
H1: m  3
a
a
a/2
Critical
Value(s)
Rejection Regions
In the critical value approach, the computed statistic is
compared to the critical value of the test statistic. When the
absolute value of the computed statistic is greater than the
absolute critical value, the decision is to reject 𝐻𝑜.
11
Example 1.
A new food supplement is claimed by its
manufacturer that the weight of woman
is 1.5 kilograms per month with a
standard deviation of 0.65 kg. 35
women chosen at random have reported
gaining weight an average of 1.65
kilograms within a month. Does this data
support the claim of the manufacturer at
0.05 level of significance?
12
Solution
13
14
d. Since, the critical value -1.960 < the 𝑐𝑜𝑚𝑝
𝑢𝑡𝑒𝑑 z value 1.365 and the 𝑐𝑜𝑚𝑝𝑢𝑡𝑒𝑑 z
value 1.365 < 1.960 which falls within the
acceptance region. Therefore, the null
hypothesis is accepted.
e. There is no significant difference between
the sample mean and the population
mean. Thus, the manufacturer is correct in
claiming the weight of women is 1.5 kg per
month in using the new food supplement.
15
Example 2.
A sample of 8 measurements,
randomly selected from an
approximately normally distributed
population, resulted in the summary
statistics: 𝑋̅ =5.4, s= 1.3. Test the
null hypothesis that the mean of the
population is 6 against the
alternative hypothesis μ<6. Use
α=0.05.
16
Solution
a. 𝐻𝑜: μ = 6
𝐻A: μ < 6
a. Type of test: one-tailed test
Test Statistic: t-test
Level of significance: α=0.05
degree of freedom = n-1 =8-1 = 7
Critical values: -1.860
17
18
d. Since, t 𝑐𝑜𝑚𝑝𝑢𝑡𝑒𝑑 = -1.305 > -1.860
and falls within the acceptance
region. Therefore, the null
hypothesis is accepted
e. The sample does not provide enough
evidence to reject the null hypothesis.
Thus, there is no significant difference
between the means.
19
Example 3
According to a study done last year, the average
monthly expenses for cell phone loads of high
school students in Manila was 350.00. A statistics
students believes that this amount has increases
since January of this year. Is there a reason to
believe that this amount has really increased if a
random sample of 60 students has an average
monthly expenses for cell phone loads of 380.00?
Use a 0.05 level of significance. Assume that the
population standard deviation is 77.00.
20
Example 4
A History teacher claims that the average
height of Filipino males is 163 centimeters.
A student taking up statistics randomly
selects 20 Filipino males with a standard
deviation of 2.1cm and it is found out that
the mean is 165 cm. Use 0.05 level of
significance. Can it be concluded that the
average heights of Filipino males is different
from 163 cm?
21
Group Work(Performance Task)
The students will show the steps in solving the
following problems through a video
presentation.
1. A recent survey stated that adults spend an
average of 8 hours a day playing mobile games. A
random sample of 50 adults is selected from a
normally distributed population of adults and noted
an average of 6 hours playing mobile games a day
with a standard deviation of 3 hours. Using the
0.05 level of significance, would you conclude that
the statement given in the survey is correct?
22
How do you
relate the topic in
your life?

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Rejection Region.ppt.ppt

  • 1. 1 Review! • Hypothesis Testing - the process of hypothesis testing involves making a decision between two opposing hypotheses. • Null and Alternative Hypothesis • Either reject H0 or fail to reject H0.
  • 2. 2 Review! • The null hypothesis (denoted by H0) is a statement saying that there is NO significant difference between population parameter and the value that is being claimed.  the starting point of the investigation. The symbolic form of the null hypothesis is the symbol =.
  • 3. 3 Review!  The alternative hypothesis (denoted by H1 or Ha or HA) is the statement saying that there is significant difference between population parameter and the value that is being claimed.  This is a statement that will be true once the null hypothesis is rejected.  The symbolic form of the alternative hypothesis must use one of these symbols: , <, >.
  • 4. 4 Decision Accept Null Reject Null R E A Null is true L I Null is false T Y Type II Error (β error) Correct decision Type I Error (α error) Correct decision Possible outcomes of testing
  • 5. 5 Lesson in Life! There is NO ERROR/MISTAKE when we ACCEPT the TRUTH and REJECT what is FALSE.
  • 6. 6 Identifies the Rejection region for a given Level of significance
  • 7. 7 Two types of test Z- test  The z- test is used to predict the value the population mean when the variance (σ) is known, or even when it is unknown provided that the sample size is large based on the Central Limit Theorem (CLT)  n ≥ 30. T-test  When the population variance (σ) is unknown and the sample size is limited, i.e., n < 30, then, the t-test is the appropriate test statistic.  Different sample sizes have different distributions determined by its degree of freedom (df), df = n-1.
  • 8. 8 Two types of test Z- test T-test
  • 9. 9 LEVEL OF SIGNIFICANCE Level of Significance TYPES OF TEST One-tailed test Two-tailed test left-tailed (<) right-tailed (>) Both right and left tailed (≠) -1.645 1.645 ±1.960 -2.326 2.326 ±2.575 -1.282 1.282 ±1.645
  • 10. 10 Level of Significance, a and the Rejection Region H0: m  3 H1: m < 3 0 0 0 H0: m  3 H1: m > 3 H0: m = 3 H1: m  3 a a a/2 Critical Value(s) Rejection Regions In the critical value approach, the computed statistic is compared to the critical value of the test statistic. When the absolute value of the computed statistic is greater than the absolute critical value, the decision is to reject 𝐻𝑜.
  • 11. 11 Example 1. A new food supplement is claimed by its manufacturer that the weight of woman is 1.5 kilograms per month with a standard deviation of 0.65 kg. 35 women chosen at random have reported gaining weight an average of 1.65 kilograms within a month. Does this data support the claim of the manufacturer at 0.05 level of significance?
  • 13. 13
  • 14. 14 d. Since, the critical value -1.960 < the 𝑐𝑜𝑚𝑝 𝑢𝑡𝑒𝑑 z value 1.365 and the 𝑐𝑜𝑚𝑝𝑢𝑡𝑒𝑑 z value 1.365 < 1.960 which falls within the acceptance region. Therefore, the null hypothesis is accepted. e. There is no significant difference between the sample mean and the population mean. Thus, the manufacturer is correct in claiming the weight of women is 1.5 kg per month in using the new food supplement.
  • 15. 15 Example 2. A sample of 8 measurements, randomly selected from an approximately normally distributed population, resulted in the summary statistics: 𝑋̅ =5.4, s= 1.3. Test the null hypothesis that the mean of the population is 6 against the alternative hypothesis μ<6. Use α=0.05.
  • 16. 16 Solution a. 𝐻𝑜: μ = 6 𝐻A: μ < 6 a. Type of test: one-tailed test Test Statistic: t-test Level of significance: α=0.05 degree of freedom = n-1 =8-1 = 7 Critical values: -1.860
  • 17. 17
  • 18. 18 d. Since, t 𝑐𝑜𝑚𝑝𝑢𝑡𝑒𝑑 = -1.305 > -1.860 and falls within the acceptance region. Therefore, the null hypothesis is accepted e. The sample does not provide enough evidence to reject the null hypothesis. Thus, there is no significant difference between the means.
  • 19. 19 Example 3 According to a study done last year, the average monthly expenses for cell phone loads of high school students in Manila was 350.00. A statistics students believes that this amount has increases since January of this year. Is there a reason to believe that this amount has really increased if a random sample of 60 students has an average monthly expenses for cell phone loads of 380.00? Use a 0.05 level of significance. Assume that the population standard deviation is 77.00.
  • 20. 20 Example 4 A History teacher claims that the average height of Filipino males is 163 centimeters. A student taking up statistics randomly selects 20 Filipino males with a standard deviation of 2.1cm and it is found out that the mean is 165 cm. Use 0.05 level of significance. Can it be concluded that the average heights of Filipino males is different from 163 cm?
  • 21. 21 Group Work(Performance Task) The students will show the steps in solving the following problems through a video presentation. 1. A recent survey stated that adults spend an average of 8 hours a day playing mobile games. A random sample of 50 adults is selected from a normally distributed population of adults and noted an average of 6 hours playing mobile games a day with a standard deviation of 3 hours. Using the 0.05 level of significance, would you conclude that the statement given in the survey is correct?
  • 22. 22 How do you relate the topic in your life?

Editor's Notes

  1. Type 1 - the probability to reject Ho when it is true/reject the true Ho. (False positive) Type 2- the probability of accepting Ho when it is false/accept a false Ho. (False Negative)