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THIS IS RIGHT ANGLED TRIANGLE HAVING ONE OF ITS SIDES A RIGHT ANGLE 
Come on lets learn ‘PYTHGOREAN THEOREM’ 
푎2 + 푏2 = 푐2 
90
PYTHOGOREAN THEOREM STATEMENT 
IN A RIGHT ANGLED TRIANGLE,THE SQUARE OF THE HYPOTENUSE IS EQUAL TO THE 
SUM OF THE SQUARES ON THE OTHER TWO SIDES
THE THING WHICH SHOULD BE KNOWN TO LEARN THE THEOREM IS: 
• HYPOTENUSE : Hypotenuse means the side which is 
exactly opposite to the angle 90 degree 
here in the figure AC is the hypotenuse 
a 
b 90 c
A 
B C 
TO PROVE : We have to prove that퐴퐶2 = 퐴퐵.2 +퐵퐶.2 
DATA : In triangle ABC angle ABC =90 degree 
CONSTRUCTION : Draw BD perpendicular to AC 
D
HERE IS THE PROOF 
A 
D 
90 
B C 
To prove the theorem firstly we have to prove that 
Triangles BAD and BDC are similar to triangle ABC 
So, at the first we will take the triangle BAD and prove 
That it is similar to ABC triangle
A 
B 
D 
90 
* In triangle ABC and BAD , Angle ABC=BDA=90 DEGREE 
BECAUSE , D is perpendicular to AC , So both BDA and BDC=90 DEGREE 
• Angle BAC= Angle BAD 
because both are common angles or angle comes in both the triangles 
* Side BA =BA 
Therefore triangle ABC is similar to Triangle BAD 
Therefore AC/AB = AB/AD = BC/BD / Because of B.P.T 
HERE AC/AB CAME BECAUSE ADB IS 90 DEGREE WHICH IS IN RIGHT AND ABC IS 
AT LEFT AC/AB=.SO, AB/BY AD TURNING TRIANGLE 1 
BDA TO THE DIRECTION OF ABC , THE B.P.T 
IS APPLIED
D 
B C 
*IN triangle ABC and BDC angle ABC=BDC=90 degree 
Because AC IS PERPENDICULAR to BD 
*Angle BCA and ACD are common angles 
*THEREFORE triangle ABC is similar to BDC 
Therefore BC/AC = DC/BC 2 
90
HENCE THE TWO EQUATIONS WHICH WE GOT ARE: 
AC/AB = AB/AD 
BC/AC = DC/BC 
1 
2 
HENCE ADD THE EQUATIONS: 
BY ADDING THEM AND SIMPLIFYING THEM WE GET: 
퐴퐶2 = 퐴퐵2 + 퐵퐶2
A PRESENTATION FROM 
ABHISHEK GANDHI 
THANK YOU

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Pythogoras theorem presentation.pptx jh

  • 1. THIS IS RIGHT ANGLED TRIANGLE HAVING ONE OF ITS SIDES A RIGHT ANGLE Come on lets learn ‘PYTHGOREAN THEOREM’ 푎2 + 푏2 = 푐2 90
  • 2. PYTHOGOREAN THEOREM STATEMENT IN A RIGHT ANGLED TRIANGLE,THE SQUARE OF THE HYPOTENUSE IS EQUAL TO THE SUM OF THE SQUARES ON THE OTHER TWO SIDES
  • 3. THE THING WHICH SHOULD BE KNOWN TO LEARN THE THEOREM IS: • HYPOTENUSE : Hypotenuse means the side which is exactly opposite to the angle 90 degree here in the figure AC is the hypotenuse a b 90 c
  • 4. A B C TO PROVE : We have to prove that퐴퐶2 = 퐴퐵.2 +퐵퐶.2 DATA : In triangle ABC angle ABC =90 degree CONSTRUCTION : Draw BD perpendicular to AC D
  • 5. HERE IS THE PROOF A D 90 B C To prove the theorem firstly we have to prove that Triangles BAD and BDC are similar to triangle ABC So, at the first we will take the triangle BAD and prove That it is similar to ABC triangle
  • 6. A B D 90 * In triangle ABC and BAD , Angle ABC=BDA=90 DEGREE BECAUSE , D is perpendicular to AC , So both BDA and BDC=90 DEGREE • Angle BAC= Angle BAD because both are common angles or angle comes in both the triangles * Side BA =BA Therefore triangle ABC is similar to Triangle BAD Therefore AC/AB = AB/AD = BC/BD / Because of B.P.T HERE AC/AB CAME BECAUSE ADB IS 90 DEGREE WHICH IS IN RIGHT AND ABC IS AT LEFT AC/AB=.SO, AB/BY AD TURNING TRIANGLE 1 BDA TO THE DIRECTION OF ABC , THE B.P.T IS APPLIED
  • 7. D B C *IN triangle ABC and BDC angle ABC=BDC=90 degree Because AC IS PERPENDICULAR to BD *Angle BCA and ACD are common angles *THEREFORE triangle ABC is similar to BDC Therefore BC/AC = DC/BC 2 90
  • 8. HENCE THE TWO EQUATIONS WHICH WE GOT ARE: AC/AB = AB/AD BC/AC = DC/BC 1 2 HENCE ADD THE EQUATIONS: BY ADDING THEM AND SIMPLIFYING THEM WE GET: 퐴퐶2 = 퐴퐵2 + 퐵퐶2
  • 9. A PRESENTATION FROM ABHISHEK GANDHI THANK YOU