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ARE YOU READY TO STUDY TODAY ??
COME ON WE SAY : “ CHEER UP “
FUNCTIONS, EQUATIONS
      AND QUADRATIC
        INEQUALITIES


DIAH   PERMATASARI
RELATION and function
1. Explanation Relation & Function

    Sequence couple & Cartesius
              product




     Relation           function
Definition
Number Pair (x, y) with x is first order and y is second order then
said Sequence couple
     Example 2.1 :
     Point A (2,3) is value absis x = 2, ordinat y = 3
     Point A (2,3) different with point B(3,2)
If A and B is two compilation a not empty, then Cartesius product
compilation A and B is all compilation sequence couple (x,y) with x ϵ A
and y ϵ B. write :
                   A x B = {(x,y) | x ϵ A and y ϵ B}
  For Example 2.2 :
  A = {4,5,6} and B= {0,2}, definite :
  a. A x B                b. B x A
  Answer : a. A x B = {(4,0),(4,2),(5,0),(5,2),(6,0),(6,2)}
          b. B x A = {(0,4), (0,5),(0,6),(2,4),(2,5),(2,6)}
Definition
For example A x B is Cartesius product compilation A and B, then
relation R from A to B is compilation of any kind part for Cartesius
product A x B.
Example 2.3 :
Back Attention example 2.2 . A = {4,5,6} and B= {0,2},
The Cartesius product A x B can be found some component
compilation for A x B is :
a. R1 = {(4,0),(5,0),(5,2),(6,2)}
b. R2 = {(4,0),(4,2),(5,0),(5,2),(6,0)}
c. R3 ={(4,0),(5,0),(6,0)}

             4
                         0
             5

             6            2
Compilation-compilation R1, R2, and R3 is part compilation for
cartesius product A x B is a familiar as relation for compilation A
to compiltion B.
From on explanation, the relation R = {(x ,y) | x ϵ A and y ϵ B}
can be matter that is
a. Compilation first ordinat ( absis) from sequence couple (x,y)
   that is origin area (domain ) relation R
b. Compilation B that is companion area (kodomain) relation
   R.
c. Part Compilation from B with x R y or y ϵ B that is output
   area (range) relation R.
Definition
Relation from compilation A to compilation B that is
function or       cartography, if each element
(component) on compilation A exact form a pair only
with a element (component ) on compilation B.
For example f is a function or cartography from
compilation A to compilation B, then function f can be
symbol with
                     f :A→B
0
                   0                                Picture 2.3. The
   0                                             function f can be write
                   0                              that is f : x → y = f (x)
   0



For example, x ϵ A, y ϵ B that (x,y) ϵ f , then y is chart or imagination from x
by function f. the chart or imagination can be said with y = f(x), you can see a
picture 2.3. So, the function f can be write that is

                                 f : x → y = f (x)
for example, f : A → B, then
a. Origin area (domain) function f is compilation A and the symbol with Df
b. Companion area (kondomain) function f is compilation B and the
    symbol with Kf , and
c. Output area (Range) function f is compilation from all chart A in B and
    the symbol with Rf.
Example
1. What is a diagram a function or not, and give reason ?
             F                                       H
     A                                     A                B
                          B
     a                                      a
                      k                                     k
     b                                     b
                      l                                         l
     c                                      c
                      m                                     m
     d                                     d
Answer :
a. Relation F is function because every component compilation
   A connection with exact one component compilation B.
b. Relation H isn’t function because be found one component
   compilation A, that c isn’t use companion in B

2. Definite domain, kodomain, and range from function f the
   indication by bow and arrow diagram ?                 F
                                                  A           B
 Answer :
 a. Compilation A = {a,b,c,d} is origin area or   a.
                                                        >
    domain from f is Df = {a,b,c,d}                           .4
                                                  b.          .5
 b. Compilation B = {4,5,6,7,8} is companion            >
                                                              .6
    area or kodomain from function f, is Kf =      c.         .7
    {4,5,6,7,8}                                               .8
                                                   d.
 c. Range or output area from function f is Rf
    = {4,5,6}
Micro teaching junior high school

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Micro teaching junior high school

  • 1. ARE YOU READY TO STUDY TODAY ?? COME ON WE SAY : “ CHEER UP “
  • 2. FUNCTIONS, EQUATIONS AND QUADRATIC INEQUALITIES DIAH PERMATASARI
  • 4. 1. Explanation Relation & Function Sequence couple & Cartesius product Relation function
  • 5. Definition Number Pair (x, y) with x is first order and y is second order then said Sequence couple Example 2.1 : Point A (2,3) is value absis x = 2, ordinat y = 3 Point A (2,3) different with point B(3,2) If A and B is two compilation a not empty, then Cartesius product compilation A and B is all compilation sequence couple (x,y) with x ϵ A and y ϵ B. write : A x B = {(x,y) | x ϵ A and y ϵ B} For Example 2.2 : A = {4,5,6} and B= {0,2}, definite : a. A x B b. B x A Answer : a. A x B = {(4,0),(4,2),(5,0),(5,2),(6,0),(6,2)} b. B x A = {(0,4), (0,5),(0,6),(2,4),(2,5),(2,6)}
  • 6. Definition For example A x B is Cartesius product compilation A and B, then relation R from A to B is compilation of any kind part for Cartesius product A x B. Example 2.3 : Back Attention example 2.2 . A = {4,5,6} and B= {0,2}, The Cartesius product A x B can be found some component compilation for A x B is : a. R1 = {(4,0),(5,0),(5,2),(6,2)} b. R2 = {(4,0),(4,2),(5,0),(5,2),(6,0)} c. R3 ={(4,0),(5,0),(6,0)} 4 0 5 6 2
  • 7. Compilation-compilation R1, R2, and R3 is part compilation for cartesius product A x B is a familiar as relation for compilation A to compiltion B. From on explanation, the relation R = {(x ,y) | x ϵ A and y ϵ B} can be matter that is a. Compilation first ordinat ( absis) from sequence couple (x,y) that is origin area (domain ) relation R b. Compilation B that is companion area (kodomain) relation R. c. Part Compilation from B with x R y or y ϵ B that is output area (range) relation R.
  • 8. Definition Relation from compilation A to compilation B that is function or cartography, if each element (component) on compilation A exact form a pair only with a element (component ) on compilation B. For example f is a function or cartography from compilation A to compilation B, then function f can be symbol with f :A→B
  • 9. 0 0 Picture 2.3. The 0 function f can be write 0 that is f : x → y = f (x) 0 For example, x ϵ A, y ϵ B that (x,y) ϵ f , then y is chart or imagination from x by function f. the chart or imagination can be said with y = f(x), you can see a picture 2.3. So, the function f can be write that is f : x → y = f (x) for example, f : A → B, then a. Origin area (domain) function f is compilation A and the symbol with Df b. Companion area (kondomain) function f is compilation B and the symbol with Kf , and c. Output area (Range) function f is compilation from all chart A in B and the symbol with Rf.
  • 10. Example 1. What is a diagram a function or not, and give reason ? F H A A B B a a k k b b l l c c m m d d
  • 11. Answer : a. Relation F is function because every component compilation A connection with exact one component compilation B. b. Relation H isn’t function because be found one component compilation A, that c isn’t use companion in B 2. Definite domain, kodomain, and range from function f the indication by bow and arrow diagram ? F A B Answer : a. Compilation A = {a,b,c,d} is origin area or a. > domain from f is Df = {a,b,c,d} .4 b. .5 b. Compilation B = {4,5,6,7,8} is companion > .6 area or kodomain from function f, is Kf = c. .7 {4,5,6,7,8} .8 d. c. Range or output area from function f is Rf = {4,5,6}

Editor's Notes

  1. B