Methyl Orange is a good indicator for pH\'s ranging from 3 to 5,with 3 being more acidic than 5. When methyl orange is added to distilled water (pH 6.5-7), theindicator turns yellow because the concentration of H+ ions indistilled water is low enough that the methyl orange candisassociate it\'s H+ ions. When 6M HCl is added, H+ ions are added to the system, disturbingthe equilibrium of methyl orange and making the solution moreacidic. Since H+ ions are the product of the reaction, the methylorange will shift it\'s equilibrium to the left, therefore makingmore of the reactant , HMO which turns the solution red. When 6M NAOH is added after the HCl, the -OH ions react with the H+ions to create water (reaction 3 in your discussion section), whichremoves H+ and -OH ions from the solution. The equilibrium ofmethyl orange is disturbed again, and the equilibrium will shift tothe right to make more of the product. The solution turns back toyellow as more reactants are turned into products, so HMO isconsumed and H+ ions are created again. I think this covered all of your questions, I hope this helps! Steve Solution Methyl Orange is a good indicator for pH\'s ranging from 3 to 5,with 3 being more acidic than 5. When methyl orange is added to distilled water (pH 6.5-7), theindicator turns yellow because the concentration of H+ ions indistilled water is low enough that the methyl orange candisassociate it\'s H+ ions. When 6M HCl is added, H+ ions are added to the system, disturbingthe equilibrium of methyl orange and making the solution moreacidic. Since H+ ions are the product of the reaction, the methylorange will shift it\'s equilibrium to the left, therefore makingmore of the reactant , HMO which turns the solution red. When 6M NAOH is added after the HCl, the -OH ions react with the H+ions to create water (reaction 3 in your discussion section), whichremoves H+ and -OH ions from the solution. The equilibrium ofmethyl orange is disturbed again, and the equilibrium will shift tothe right to make more of the product. The solution turns back toyellow as more reactants are turned into products, so HMO isconsumed and H+ ions are created again. I think this covered all of your questions, I hope this helps! Steve.

1. Methyl Orange is a good indicator for pH's ranging from 3 to 5,with 3 being more
acidic than 5. When methyl orange is added to distilled water (pH 6.5-7), theindicator turns
yellow because the concentration of H+ ions indistilled water is low enough that the methyl
orange candisassociate it's H+ ions. When 6M HCl is added, H+ ions are added to the system,
disturbingthe equilibrium of methyl orange and making the solution moreacidic. Since H+ ions
are the product of the reaction, the methylorange will shift it's equilibrium to the left, therefore
makingmore of the reactant , HMO which turns the solution red. When 6M NAOH is added
after the HCl, the -OH ions react with the H+ions to create water (reaction 3 in your discussion
section), whichremoves H+ and -OH ions from the solution. The equilibrium ofmethyl orange is
disturbed again, and the equilibrium will shift tothe right to make more of the product. The
solution turns back toyellow as more reactants are turned into products, so HMO isconsumed and
H+ ions are created again. I think this covered all of your questions, I hope this helps! Steve
Solution
Methyl Orange is a good indicator for pH's ranging from 3 to 5,with 3 being more
acidic than 5. When methyl orange is added to distilled water (pH 6.5-7), theindicator turns
yellow because the concentration of H+ ions indistilled water is low enough that the methyl
orange candisassociate it's H+ ions. When 6M HCl is added, H+ ions are added to the system,
disturbingthe equilibrium of methyl orange and making the solution moreacidic. Since H+ ions
are the product of the reaction, the methylorange will shift it's equilibrium to the left, therefore
makingmore of the reactant , HMO which turns the solution red. When 6M NAOH is added
after the HCl, the -OH ions react with the H+ions to create water (reaction 3 in your discussion
section), whichremoves H+ and -OH ions from the solution. The equilibrium ofmethyl orange is
disturbed again, and the equilibrium will shift tothe right to make more of the product. The
solution turns back toyellow as more reactants are turned into products, so HMO isconsumed and
H+ ions are created again. I think this covered all of your questions, I hope this helps! Steve