OBJECTIVES:
During the period, the students are
expected to:
1. identify the different Measures of
Variability;
2. give the formula to compute each
Measure of Variability;
3. solve problems involving Measures of
Variability ( ungrouped data ).
Boys Girls
Frederick 70 Grace 82
Russel 95 Irish 80
Murphy 60 Abigail 83
Jerome 80 Sherry 81
Tom 100 Kristine 79
Mean: 81 Mean: 81
Scores of 5 Boys and 5 Girls in
Mathematics
Boys
60 70 80 90 100
Girls
60 70 80 90 100
Measures of
Variability or
Dispersion
RANGE:
The difference between the highest and the
lowest observation
R = H – L
Boys: R = 100 – 60
R = 40
Girls: R = 83 – 79
R = 4
Therefore the
girls are more
homogeneous
than the boys in
their math
ability
Mean Deviation:
The average of the summation of the
absolute deviation of each observation
from the mean.
MD = Σ Xi - X
n
BOYS Xi Xi – X
Frederick 70 11
Russel 95 14
Murphy 60 21
Jerome 80 1
Tom 100 19
Mean: 81 Σ = 405 Σ = 66
M.D = 66 / 5
= 13.2
GIRLS Xi Xi – X
Grace 82 1
Irish 80 1
Abigail 83 2
Sherry 81 0
Kristine 79 2
Mean: 81 Σ = 405 Σ = 6
M.D = 6 / 5
= 1.2
MD ( boys ) = 13.2
MD ( girls ) = 1.2
- based from the computed Mean
Deviation, the girls are more
homogeneous than the boys.
VARIANCE:
The average of the squared deviation
from the mean.
Population Variance
σ 2
= Σ ( Xi – X ) 2
n
Sample Variance
s 2
= Σ ( Xi – X ) 2
n - 1
BOYS Xi Xi – X ( Xi – X ) 2
Frederick 70 -11 121
Russel 95 14 196
Murphy 60 -21 441
Jerome 80 -1 1
Tom 100 19 361
Mean: 81 Σ = 405 Σ = 1,120
σ2
= 1,120 / 5 s2
= 1,120 / 4
= 224 = 280
GIRLS Xi Xi – X ( Xi – X ) 2
Grace 82 1 1
Irish 80 1 1
Abigail 83 2 4
Sherry 81 0 0
Kristine 79 2 4
Mean: 81 Σ = 405 Σ = 10
σ2
= 10 / 5 s2
= 10 / 4
= 2 = 2.5
BOYS
σ2
= 1,120 / 5 s2
= 1,120 / 4
= 224 = 280
GIRLS
σ2
= 10 / 5 s2
= 10 / 4
= 2 = 2.5
The values of
the Variance
also reveals that
the score of
boys are more
spread out than
that of the girls.
STANDARD DEVIATION:
The square root of the Variance
BOYS
σ 2
= 224 s 2
= 280
σ = 14.97 s = 16.73
GIRLS
σ 2
= 2 s 2
= 2.5
σ = 1.41 s = 1.58
Question:
Why do you think the
RANGE is considered an
unreliable Measure of
Variability?
Answer:
The RANGE is considered
unreliable because we will only
use two values, the highest and the
lowest which is not a complete
representation of all the
observations.
Think about this:
Why do we need to work
harmoniously with
everyone?
Recap:
 What are the different
Measures of Variability?
 How do we compute for each
measure?
SEATWORK:
Given the table below, compute for R,
MD, s, and s2
Xi l Xi – X l ( Xi – X ) 2
17
15
22
19
18
Σ = Σ = Σ =
Xi l Xi – X l ( Xi – X ) 2
17 1.2 1.44
15 3.2 10.24
22 3.8 14.44
19 0.8 0.64
18 0.2 0.04
Σ = 91 Σ = 9.2 Σ = 26.8
1. Range = 7
2. MD = 1.84
3. s = 2.59
σ = 2.32
4. s 2
= 6.7
σ 2
= 5.36
Measures of variability

Measures of variability

  • 1.
    OBJECTIVES: During the period,the students are expected to: 1. identify the different Measures of Variability; 2. give the formula to compute each Measure of Variability; 3. solve problems involving Measures of Variability ( ungrouped data ).
  • 2.
    Boys Girls Frederick 70Grace 82 Russel 95 Irish 80 Murphy 60 Abigail 83 Jerome 80 Sherry 81 Tom 100 Kristine 79 Mean: 81 Mean: 81 Scores of 5 Boys and 5 Girls in Mathematics
  • 3.
    Boys 60 70 8090 100 Girls 60 70 80 90 100
  • 4.
  • 5.
    RANGE: The difference betweenthe highest and the lowest observation R = H – L Boys: R = 100 – 60 R = 40 Girls: R = 83 – 79 R = 4 Therefore the girls are more homogeneous than the boys in their math ability
  • 6.
    Mean Deviation: The averageof the summation of the absolute deviation of each observation from the mean. MD = Σ Xi - X n
  • 7.
    BOYS Xi Xi– X Frederick 70 11 Russel 95 14 Murphy 60 21 Jerome 80 1 Tom 100 19 Mean: 81 Σ = 405 Σ = 66 M.D = 66 / 5 = 13.2
  • 8.
    GIRLS Xi Xi– X Grace 82 1 Irish 80 1 Abigail 83 2 Sherry 81 0 Kristine 79 2 Mean: 81 Σ = 405 Σ = 6 M.D = 6 / 5 = 1.2
  • 9.
    MD ( boys) = 13.2 MD ( girls ) = 1.2 - based from the computed Mean Deviation, the girls are more homogeneous than the boys.
  • 10.
    VARIANCE: The average ofthe squared deviation from the mean. Population Variance σ 2 = Σ ( Xi – X ) 2 n Sample Variance s 2 = Σ ( Xi – X ) 2 n - 1
  • 11.
    BOYS Xi Xi– X ( Xi – X ) 2 Frederick 70 -11 121 Russel 95 14 196 Murphy 60 -21 441 Jerome 80 -1 1 Tom 100 19 361 Mean: 81 Σ = 405 Σ = 1,120 σ2 = 1,120 / 5 s2 = 1,120 / 4 = 224 = 280
  • 12.
    GIRLS Xi Xi– X ( Xi – X ) 2 Grace 82 1 1 Irish 80 1 1 Abigail 83 2 4 Sherry 81 0 0 Kristine 79 2 4 Mean: 81 Σ = 405 Σ = 10 σ2 = 10 / 5 s2 = 10 / 4 = 2 = 2.5
  • 13.
    BOYS σ2 = 1,120 /5 s2 = 1,120 / 4 = 224 = 280 GIRLS σ2 = 10 / 5 s2 = 10 / 4 = 2 = 2.5 The values of the Variance also reveals that the score of boys are more spread out than that of the girls.
  • 14.
    STANDARD DEVIATION: The squareroot of the Variance BOYS σ 2 = 224 s 2 = 280 σ = 14.97 s = 16.73 GIRLS σ 2 = 2 s 2 = 2.5 σ = 1.41 s = 1.58
  • 15.
    Question: Why do youthink the RANGE is considered an unreliable Measure of Variability?
  • 16.
    Answer: The RANGE isconsidered unreliable because we will only use two values, the highest and the lowest which is not a complete representation of all the observations.
  • 17.
    Think about this: Whydo we need to work harmoniously with everyone?
  • 18.
    Recap:  What arethe different Measures of Variability?  How do we compute for each measure?
  • 19.
    SEATWORK: Given the tablebelow, compute for R, MD, s, and s2 Xi l Xi – X l ( Xi – X ) 2 17 15 22 19 18 Σ = Σ = Σ =
  • 20.
    Xi l Xi– X l ( Xi – X ) 2 17 1.2 1.44 15 3.2 10.24 22 3.8 14.44 19 0.8 0.64 18 0.2 0.04 Σ = 91 Σ = 9.2 Σ = 26.8
  • 21.
    1. Range =7 2. MD = 1.84 3. s = 2.59 σ = 2.32 4. s 2 = 6.7 σ 2 = 5.36