Logika Dasar

[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object], x  R  x + 2 = 5 (pernyataan benar)  x  R  x 2 > 0 (pernyataan salah)

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],p ~p B S S B

[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],~ [(  x) P (x)] = (  x)[ ~P (x)]

[object Object],[object Object],[object Object],[object Object],[object Object]

[object Object],‘ p  q ’ bernilai benar hanya apabila p dan q sama-sama bernilai benar. Contoh : p : Hari ini hujan q : Murid-murid diliburkan dari sekolah p  q : Hari ini hujan dan murid-murid diliburkan dari sekolah p q p  q B B B B S S S B S S S S

[object Object],[object Object],p q p  q B B B B S B S B B S S S p q p  q B B S B S B S B B S S S

[object Object],[object Object],[object Object],[object Object]

p q p  q B B B B S S S B B S S B

[object Object],[object Object],[object Object],p q ~p ~q Implikasi p  q Konvers q  p Invers ~p  ~q Kontraposisi ~q  ~p B B S S B S B S S S B B S B S B B S B B B B S B B B S B B S B B

p q p ⇔ q B B B B S S S B B S S B

[object Object],[object Object]

[object Object],p q p  q ~ ( p  q) p  ~ ( p  q ) B B B S B B S S B B S B S B B S S S B B

[object Object],p q p  q p  q ~ ( p  q ) ( p  q )  ~ ( p  q ) B B B S B S B S S B B S S B S B B S S S S B B S

p q ~ p ~ q p  q ~ ( p  q ) ~ p  ~ q B B S S B S B S S S B B S B S B B B B S S S S B S S S B

p q ~ p ~ q p  q ~ ( p  q ) ~ p  ~ q B B S S B S B S S S B B S B S B B S S S S B B B S B B B

p q ~ p ~ q p  q ~ ( p  q ) ( p  ~ q ) B B S S B S B S S S B B S B S B B S B B S B S S S B S S

p q ~ p ~ q p ⇔ q ( p  ~q ) ( q  ~ p ) ~ ( p ⇔ q ) A  B B B S S B S B S S S B B S B S B B S S B S B S S S S B S S B B S S B B S

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